1/4 plus 1/5 plus 11/12

Answer:

=sqrt of 30

Step-by-step explanation:

=sqrt of 3×2×5

=sqrt 30

The measure of segment DF from the given question is 21

In line geometry, a line is the distance between two points while an angle is the point where two lines intersect.

Given the following parameters

DE = 4x + 10, EF = 2x-1, and DF = 9x-15,

Required

DF

Using the addition postulate

DE + EF = DF

Substitute

4x+10 + 2x -1= 9x - 15

6x + 11 = 9x - 1

6x - 9x =  -1 - 1

-3x = -12

x = 12/3

x = 4

For DF

DF =  9(4) - 15

DF = 21

Hence the measure of segment DF from the given question is 21

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The value of x associated with the point P on a number line is 0.5.

In accordance with the statement, the condition SP = PT means that the locations of points S, T and P on the number line are 0, 1, x, so that S < P < T and that point P is equidistant of points S and T. Then, the location of the missing point is determined by the midpoint formula:

P = 0.5 · S + 0.5 · T

P = 0.5 · 0 + 0.5 · 1

P = x = 0.5

The value of x associated with the point P on a number line is 0.5.

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Answer:

$1

Step-by-step explanation:

If you have x dimes, you have 8x nickels.

So, this means x + 8x = 18.

This means you have 2 dimes and 16 nickels, which have a combined value of 2(0.10)+16(0.05)=$1.

Answer:

[tex]\sf y =\dfrac{-11}{8}x +\dfrac{13}{8}[/tex]

Step-by-step explanation:

Here, m is the slope and b is the y-intercept.

( -1, 3) ;  x₁ = -1  & y₁ = 3

(7, -8) ; x₂ = 7 & y₂ = -8

Slope can be obtained by the formula:

    [tex]\sf \boxed{\bf Slope = \dfrac{y_2-y_1}{x_2-x_1}}[/tex]

                [tex]\sf =\dfrac{-8-3}{7-[-1]}\\\\\\=\dfrac{-8-3}{7+1}\\\\\\=\dfrac{-11}{8}[/tex]

Now, we can find the y-intercept,

[tex]\sf y = \dfrac{-11}{8}x + b\\\\Substitute \ any \ one \ of \ the \ point \ in \ the \ above \ equation.\\\\\text{Here, we are substituting (-1 ,3)}\\\\3 = \dfrac{-11}{8}*(-1) + b\\\\3 = \dfrac{11}{8}+b\\\\b = 3 - \dfrac{11}{8}\\\\b = \dfrac{3*8}{1*8}-\dfrac{11}{8}\\\\b= \dfrac{24-11}{8}\\\\b= \dfrac{13}{8}[/tex]

Slope-intercept form:

          [tex]\sf y =\dfrac{-11}{8}x +\dfrac{13}{8}[/tex]

From rectangle F to G translation is -4 units to the x- direction and -3 units to the y- direction.

From rectangle G to H translation is 6 units to the x- direction and -1 units to the y- direction.

From rectangle F to H translation is 2 units to the x- direction and -4 units to the y- direction.

Given that,

In the picture we have a graph with 3 rectangles that is F, G, and H.

We have to find the translation of the rectangles.

We know that,

The transformation, i.e., f: X X, is a function, f, that maps to itself. Following the transformation, the pre-image X changes into the image X. Any operation, including translation, rotation, reflection, and dilation, may be used to create this transformation. A function can be moved in one direction or another by translation, rotated around a point by rotation, reflected in its mirror image by reflection, and scaled by dilation.

So,

From rectangle F to G translation is -4 units to the x- direction and -3 units to the y- direction.

From rectangle G to H translation is 6 units to the x- direction and -1 units to the y- direction.

From rectangle F to H translation is 2 units to the x- direction and -4 units to the y- direction.

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The number of hours Hector worked this week is 32 hours.

444 = 15(4) + 12(x)

444 = 60 + 12x

444 - 60 = 12x

384 = 12x

x = 384/12

x = 32 hours

check:

444 = 60 + 12x

444 = 60 + 12(32)

444 = 60 + 384

444 = 444

Therefore, the number of hours Hector worked this week is 32 hours.

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Answer:

  5.2 g/cm³

Step-by-step explanation:

Given a sculpture consisting of 2 cm³ at 4 g/cm³, 7 cm³ at 5 g/cm³, and 5 cm³ at 6 g/cm³, you want its average density.

The total mass of the sculpture is the sum of the masses of the components. Each of those is the product of its volume and density.

  red sand: (2 cm³)(4 g/cm³) = 8 g

  yellow sand: (7 cm³)(5 g/cm³) = 35 g

  brown sand: (5 cm³)(6 g/cm³) = 30 g

The total mass of the sculpture is ...

  total mass = 8 g + 35 g + 30 g = 73 g

The total volume of the sculpture is the sum of the volumes of its parts:

  total volume = 2 cm³ +7 cm³ +5 cm³ = 14 cm³

The density is the ratio of mass to volume:

  ρ = (total mass)/(total volume) = (73 g)/(14 cm³) = 73/14 g/cm³

  = 5 3/14 g/cm³ ≈ 5.2 g/cm³

The average density of the sculpture is about 5.2 g/cm³.

The value of x and y is y=29, X=21.

180-60=120

4y+4=120 get y by itself and remember that what ever you do to one side you do to the other.

Alternate interior angles are congruent so 3x-3=60

What is an angle ?

Angle is the figure formed by two rays, called the sides of the angle, sharing a common endpoint, called the vertex of the angle. Angles formed by two rays lie in the plane that contains the rays. Angles are also formed by the intersection of two planes. These are called dihedral angles.

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Answer:

6(5)3(5)² + (3)³

Step-by-step explanation:

Put this into your calculator just like this

The equation of circle is [tex]x^2+y^2=100[/tex]

The standard equation of a circle with center (h, k) and radius r is given by:

[tex](x-h)^2+(y-k)^2=r^2[/tex] ........(1)

This is the equation needed for the circle with a center at A(h, k) and a radius equal to r since it describes the relationship between the coordinates of any point on the circumference.

Now according to the question, it is given that the circle has the center at origin and length of its radius is 10.

Center = (h, k)=(0, 0)

Radius(r) = 10 units

Now, substituting the given values in (1) we get;

⇒[tex]x^2+y^2=100[/tex]

Therefore, the equation of circle centered at origin with radius 10 is [tex]x^2+y^2=100[/tex]

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Answer:

So what you have to do is go back to you lesson and read till you find an answer just like this one and read how to do it when u do that go back and to the quick check and find an answer that is similar. the reason why I'm telling you this is cause I cant calculate it right. or what you can do is calculate it right on here.

Step-by-step explanation:

https://www.inchcalculator.com/cubic-footage-calculator/

Abby should write her equation as k = 1.61m.

The correct option is B.

A pair of algebraic equations with the equal symbol (=) in the center and the same value are referred to as an equation.

Given:

Abby knows that 1 mile is about 1.61 kilometers.

To write an equation, which she can use to convert any given distance in miles (m) to kilometers (k):

Let m be the total number of miles and k be the kilometers.

So, the equation is,

k = 1.61m

Where 1.61 is multiplied by m.

Therefore, the equation is k = 1.61m.

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2(6k+2)=64

12k+4=64

12k=60

k=5

Answer: The car was not speeding. It went 27.6 mi/h.

Step-by-step explanation: The equation v=2/5L is given where v is measured in mi/h. L is measured in ft. Since we have the value 69 for L, we sub it into the equation. We end up getting 27.6 mi/h after evaluating.

The sequence starting with 0 but each number is two times three less than the previous number is as follows:

0, -6, -12, -18, -22

A sequence is defined as an arrangement of numbers in a particular order.

The most common sequence are the arithmetic and the geometric sequence.

The sequence starts with 0 but each number is two times three less than the previous number.

This means the first term of the sequence is 3.

Hence,

2 times 3 less than the previous number means:

Aₙ = Aₙ₋₁ - 2(3)

where,

Let's use the formula to find the other numbers in the sequence,

A₂ = A₂₋₁ - 2(3) = 0 - 6 = -6

A₃ = A₃₋₁ - 2(3) = -6 - 6 = -12

A₄ = A₄₋₁ - 2(3) = -12 - 6 = - 18

A₅ = A₅₋₁ - 2(3) = -18 - 6 = - 22

Therefore, the sequence starting with 0 but each number is two times three less than the previous number is as follows:

0, -6, -12, -18, -22

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Step-by-step explanation:

[tex](3 \sqrt{3 - 2 \sqrt{2)(3 \sqrt{3 - 2 \sqrt{2)} } } } [/tex]

Answer:

Step-by-step explanation:

33575357853222467

ufee

Answer:

(−∞, 31/5) or x <31/5 (the graph will start a little bit past 6 and will be a open circle and head to the left)

Answer:

x< 6[tex]\frac{1}{5}[/tex]

Step-by-step explanation:

7<-5(x -8) - 2  Distribute the 5

7<-5x + 40 - 2

7<-5x +38  Subtract 38 from both sides

-31<-5x  Divide both sides by -5

[tex]\frac{31}{5}[/tex] >x  When you divide both sides by a negative number, you must flip the sign.

or

x < 6 [tex]\frac{1}{5}[/tex]

answer:

1,120,504

Step-by-step explanation:

I don't really have one but I'm sure

Answer:

120

Step-by-step explanation:

the difference = 24×41-864=120

The possible values of x will belong to the set A = [9, ∞).

We have the following inequality -

1 - 2x/3 ≤ -3

We have to determine all values of x.

An inequality is a relation which makes a non-equal comparison between two numbers or other mathematical expressions.

According to the question, we have the following inequality -

1 - 2x/3 ≤ -3

Subtract 1 from both sides -

-2x/3 ≤ -4

Multiply by -1 on both sides -

2x/3 ≥ 4

Multiply by 3/2 on both sides -

x ≥ 9

Hence, the possible values of x will belong to the set A = [9, ∞).

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To get to 1 we have to divide 60 by 60, and to get 25 we have to multiply 60 with 5/12 or 0.41.

Given that we have to get 1 by dividing 60 by something and multiply 60 by something to get 25.

We are required to find those numbers.

Take first result:

Suppose the number which divides 60 be x.

So,

60/x=1

x=60

Number will be 60.

Take second result:

Suppose the number which multiplied with 60 to get 25 be y.

So,

60*y=25

y=25/60

y=0.41

Number will be 0.41.

Hence to get to 1 we have to divide 60 by 60, and to get 25 we have to multiply 60 with 5/12 or 0.41.

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The larger integer number is 18 and the smaller integer number is -14.

Integers are the subset of Rational numbers which contains all numbers except fraction and decimals

Numbers are the building blocks of mathematics. Numbers are used to count ,measure or label quantities.

The different types of numbers are:

Let the smaller number be x. The sum of the numbers is 4 .

So the larger number is 4 - x

Again given that sum of three times the larger number and 2 times the smaller number is 26.

∴3 ( 4-x )+ 2x = 26

or, 12 -3x +2 x = 26

or, -x = 26-12

or, x = -14

Therefore the larger number is 4-(-14)= 18

Hence the larger integer number is 18 and the smaller number is -14 .

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Part (a)

The middle values were nitially 266 and 269, but now they are 255 and 266. Thus, the median changes from 267.5 to 260.5, meaning it decreases by 7.

Part (b)

The sum before the change is 2264, but after, it is 2120. This means the sum decreased by 144, and thus the mean decreased by 16.

Using the Pythagorean Theorem and implicit differentiation, it is found that the distance between them is increasing at a rate of 2050 km/h when they are 0.5 hours away from the harbor.

The Pythagorean Theorem relates the length of the legs [tex]l_1[/tex] and [tex]l_2[/tex] of a right triangle with the length of the hypotenuse h, according to the following equation:

[tex]h^2 = l_1^2 + l_2^2[/tex]

For this problem, we have that since the ships are moving west and north, the distance between them as a function of the time will be given by the hypotenuse of a right triangle, as follows:

d² = x² + y².

In which;

Applying implicit differentiation, the rate of change of the position is given as follows:

[tex]2\frac{dd}{dt} = 2x\frac{dx}{dt} + 2y\frac{dy}{dt}[/tex]

[tex]\frac{dd}{dt} = x\frac{dx}{dt} + y\frac{dy}{dt}[/tex]

From the velocities, we have that:

[tex]\frac{dx}{dt} = 40, \frac{dy}{dt} = 50[/tex]

From the velocities, and the time of half an hour, the positions are given as follows:

x = 0.5 x 40 = 20, y = 0.5 x 50 = 25.

Hence:

[tex]\frac{dd}{dt} = x\frac{dx}{dt} + y\frac{dy}{dt}[/tex]

[tex]\frac{dd}{dt} = 20(40) + 25(50)[/tex]

dd/dt = 2050.

The distance between them is increasing at a rate of 2050 km/h when they are 0.5 hours away from the harbor.

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Using proportional relationships, we have that:

A. The function does not show a direct linear relationship.

B. The function shows a direct linear relationship.

C. The function does not show a direct linear relationship.

A proportional relationship is a function in which the output variable is given by the multiplication of the input variable and the constant of proportionality k, in the case of a direct relationship, as follows:

y = kx

In the case of an inverse relationship, we have that:

y = k/x.

From the format of these equations, we have that:

A function is classified as linear if the exponent of x is of 1, hence item c does not show a linear function.

The functions A, B, C are missing, and are given as follows.

A. 9/x.

B. x/11.

C. x²/8.

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Answer: 1. {a, b, c, d, e}

2. {a, b, d}

3. {c, f, g, h}

4. {a, c}

Step-by-step explanation:

1. AUC ==> Means take all parameters from A and C.

A+C=

{a, b, c, d}+{a, e}={a, b, c, d, e}

2. B∩A ==> Means take the common parameters from B and A

B: {b, e, a, d}

A: {a, b, c, d}

Both B and A have a, b, and d.

So answer is {a, b, d}.

3. B' is every parameter that isn't in B

Reminder: B={b, e, a, d}.

All parameters: {a, b, c, d, e, f, g, h}

Remaining Parameters(B'): {c, f, g, h}

4. A-B∩C'

First, let's find C'.

C' is every parameter that isn't in C.

Reminder: C={a, e}

All parameters: {a, b, c, d, e, f, g, h}

Remaining Parameters(C'): {b, c, d, f, g, h}

Then lets find B∩C'

B: {b, e, a, d}

C': {b, c, d, f, g, h}

Both B and C' have b and d, so B∩C' is {b, d}

A-{b, d}=

{a, b, c, d}-{b, d}={a, c} ==> Answer for 4

Answer:

[tex]\sf 1) \quad \sf A \cup C = \{a, b, c, d, e\}[/tex]

[tex]\sf 2) \quad B \cap A = \{a, b, d\}[/tex]

[tex]\sf 3) \quad B' = \{c, f, g, h \}[/tex]

[tex]\sf 4) \quad A -(B \cap C') = \{a, c \}[/tex]

Step-by-step explanation:

Set Notation

[tex]\begin{array}{|c|c|l|} \cline{1-3} \sf Symbol & \sf N\:\!ame & \sf Meaning \\\cline{1-3} \{ \: \} & \sf Set & \sf A\:collection\:of\:elements\\\cline{1-3} \cup & \sf Union & \sf A \cup B=elements\:in\:A\:or\:B\:(or\:both)}\\\cline{1-3} \cap & \sf Intersection & \sf A \cap B=elements\: in \:both\: A \:and \:B} \\\cline{1-3} \sf ' \:or\: ^c & \sf Complement & \sf A'=elements\: not\: in\: A \\\cline{1-3} \sf - & \sf Difference & \sf A-B=elements \:in \:A \:but\: not\: in \:B}\\\cline{1-3} \end{array}[/tex]

Given sets:

Therefore:

Question 1

[tex]\begin{aligned}\sf A \cup C & = \sf \{a, b, c, d\} \cup \{a,e\}\\& = \sf \{a, b, c, d, e\}\end{aligned}[/tex]

Question 2

[tex]\begin{aligned}\sf B \cap A & = \sf \{b, e, a, d\} \cap \{a, b, c, d\}\\& = \sf \{a, b, d\}\end{aligned}[/tex]

Question 3

[tex]\begin{aligned}\sf B' & = \rm U - \sf B\\& = \sf \{a, b, c, d, e, f, g, h \}-\{b, e, a, d\}\\& = \sf \{c, f, g, h \}\end{aligned}[/tex]

Question 4

[tex]\begin{aligned}\sf A -(B \cap C') & = \sf \{a, b, c, d \}- \left( \{b, e, a, d \} \cap \{b, c, d, f, g, h \} \right)\\& = \sf \{a, b, c, d \}- \{b, d \} \\& = \sf \{a, c \}\end{aligned}[/tex]

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