1/6(6+18)-2 to the 2nd power

Answer:

slope = 0

Step-by-step explanation:

calculate the slope m using the slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = (8, 2 ) and (x₂, y₂ ) = (10, 2 )

m = [tex]\frac{2-2}{10-8}[/tex] = [tex]\frac{0}{2}[/tex] = 0

Answer:

the answer is A

Answer:

Step-by-step explanation:

b is the aswswer

David travelled 32 kilometres of the entire trip by foot

David travelled 4/5 of his trip by bicycle and the rese was done by foot

The whole trip was 160 km

The first step is to calculate the distance travelled with the bicycle

4/5 × 160

= 128

Therefore the distance travelled by foot can be calculated as follows

= 160-128

= 32

Hence David travelled 32km by foot

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Answer:32

Step-by-step explanation:32

The inverse of the function x^7 is x^-7 and it is also a function.

An inverse function or an anti function is defined as a function, which can reverse into another function.

A standard method to find inverse of a function is to set y=f(x)

let y= f(x)=x^7

thus

[tex]\sqrt[7]{y}[/tex]=x

thus [tex]f^{-1}[/tex](y)=[tex]\sqrt[7]{y}[/tex]

thus [tex]f^{-1} (x)=\sqrt[7]{x}[/tex]

(To verify this if a function is inverse or not we are required to check for the identity)

f([tex]f^{-1}[/tex](x))=[tex]f^{-1}[/tex](f(x))=x

Therefore, The inverse of the function x^7 is x^-7 and it is also a function.

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keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation above

[tex]6x-7y=-4\implies 6x=7y-4\implies 6x+4=7y \\\\\\ \cfrac{6x+4}{7}=y\implies \qquad \stackrel{\stackrel{m}{\downarrow }}{\cfrac{6}{7}} x+\cfrac{4}{7}=y\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}[/tex]

now, since we know that slope, let's check for a perpendicular line to it

[tex]\stackrel{~\hspace{5em}\textit{perpendicular lines have \underline{negative reciprocal} slopes}~\hspace{5em}} {\stackrel{slope}{\cfrac{6}{7}} ~\hfill \stackrel{reciprocal}{\cfrac{7}{6}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{7}{6}}}[/tex]

so we're really looking for the equation of aline whose slope is -7/6 and that it passes through (-6 , 5)

[tex](\stackrel{x_1}{-6}~,~\stackrel{y_1}{5})\hspace{10em} \stackrel{slope}{m} ~=~ - \cfrac{7}{6} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{5}=\stackrel{m}{- \cfrac{7}{6}}(x-\stackrel{x_1}{(-6)}) \implies y -5= -\cfrac{7}{6} (x +6) \\\\\\ y-5=-\cfrac{7}{6}x-7\implies {\LARGE \begin{array}{llll} y=-\cfrac{7}{6}x-2 \end{array}}[/tex]

Answer:

Please read and try to understand it :>

Step-by-step explanation:

[tex]6x-7y=-4[/tex] is not the standard format for a straight line so you have to rearrange it:

[tex]y=\frac{6}{7} x +\frac{4}{7}[/tex]

To find the equation of a perpendicular line to the given equation, you have to first find the negative reciprocal of the gradient:

[tex]-\frac{7}{6}[/tex]

Since you want to find the equation of a perpendicular line that passes a certain point, you have to substitute the coordinates to the equation to find the y-intercept:

[tex]5=-\frac{7}{6} (-6)+c[/tex]

Solving:

[tex]5=-\frac{7}{6} (-6) +c\\ \\ 5=\frac{42}{6} +c\\ \\-\frac{42}{6} +5=c\\ \\-7+5=c\\\\ -2=c[/tex]

Final equation: [tex]y=-\frac{7}{6} x -2[/tex]

The probability that exactly two of selected are 75W is 0.2967 , probability that exactly two of the selected bulbs are rated 75W is 0.2637 , probability that one bulb of each type is selected is 0.0747  .

Probability of an event E denoted by P(E) is defined as number of favorable outcomes divided by total number of outcomes.

In the given question

40W bulbs = 4

60W bulbs = 5

75W bulbs = 6

Total number of bulbs = 4+5+6=15.

Part(a)

probability that exactly two of the selected bulbs are rated 75-w

Selection of 3 bulbs from 15 bulbs can be done in C(15,3) ways.

[tex]=\frac{15!}{3!*12!}[/tex]

[tex]=\frac{15*14*13*12!}{12!*3!} \\ \\ =\frac{15*14*13}{3*2*1}[/tex]

=455 ways

Total number of ways = 455      ...(i)

Now,

Number of ways of selecting 2 ,75W bulbs and 1 bulb from the remaining is C(6,2)*C(9,1).    

= C(6,2)*C(9,1)

[tex]=\frac{6!}{2!*4!} *\frac{9!}{1!*8!} \\ \\ =\frac{6*5*4!}{2*4!} *\frac{9*8!}{8!}[/tex]

[tex]=\frac{6*5}{2} *9\\ \\ =15*9\\ \\ =135[/tex]

the probability that exactly two selected bulbs are rated 75W = 135/455 =0.2967

Part(b)

probability that one bulb of each type is selected .

Number of ways of selecting one bulb from each type = selecting 1 bulb from four 40W bulbs + 1 bulb from 60W bulbs + 1 bulb from 75W bulbs.

Number of ways of selecting one bulb from each type=C(4,1)*C(5,1)*C(6,1)

[tex]=C(4,1)*C(5,1)*C(6,1)\\ \\ =\frac{4!}{3!*1!} *\frac{5!}{4!*1!} *\frac{6!}{5!*1!}[/tex]

[tex]=\frac{4*3!}{3!} *\frac{5*4!}{4!} *\frac{6*5!}{5!}[/tex]   ...( as 1!=1)

[tex]=4*5*6\\ \\ =120[/tex]

Number of ways of selecting one bulb from each type = 120

Total number of ways = 455     ...from equation (i)

Probability that exactly two bulbs selected are rated 75W =120/455

=0.2637

Part(c)

probability that all three of the selected bulbs have the same rating

Number of ways three bulbs of same rating are selected = (all 3 from 40W bulbs )+(all 3 are from 60W bulbs )+( all 3 are from 75 W bulbs)

[tex]=C(4,3)+C(5,3)+C(6,3)[/tex]

[tex]=\frac{4!}{1!*3!} +\frac{5!}{2!*3!} +\frac{6!}{3!*3!} \\ \\ =\frac{4*3!}{3!} +\frac{5*4*3!}{2!*3!} +\frac{6*5*4*3!}{3*2*3!}[/tex]...( as1!=1)

[tex]=4+10+20[/tex]

[tex]=34[/tex]

Number of ways three bulbs of same rating are selected = 34

Total number of ways = 455     ...from equation (i)

Probability that all three of the selected bulbs have the same rating=34/455 = 0.0747

Therefore ,(a) the probability that exactly two of selected are 75W is 0.2967 , (b) probability that exactly two of the selected bulbs are rated 75W is 0.2637 (c)  probability that one bulb of each type is selected is 0.0747  .

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Using the Pythagorean Theorem, the length of the third sides in a triangle that satisfy this criteria is given by:

[tex]l_2^2 = 49 - 2l_1^2[/tex]

The Pythagorean Theorem relates the length of the legs [tex]l_1[/tex] and [tex]l_2[/tex] of a right triangle with the length of the hypotenuse h, stating that the hypotenuse squared is the sum of the legs squared, according to the following equation:

[tex]h^2 = l_1^2 + l_2^2[/tex]

For this problem, considering the description of a Pythagorean triple, we have that:

Hence the length of the third side can be given as follows:

[tex]49 - l_1^2 = l_1^2 + l_2^2[/tex]

[tex]2l_1^2 + l_2^2 = 49[/tex]

[tex]l_2^2 = 49 - 2l_1^2[/tex]

Hence the length of the third sides in a triangle that satisfy this criteria is given by:

[tex]l_2^2 = 49 - 2l_1^2[/tex]

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Answer:

trust me a shoe box or a board game box or a small container

Answer:

a. zero point zero zero 5

b. eleven point zero three seven

c. four hundred and three point six zero eight.

I really hope this helps you!!! Have a great day :).

The distance of the earth from the star is mathematically given as

2.537 x 10¹⁵ miles

Generally, the Coefficients for the problem are mathematically given a

Coefficients =4.6 x 5.9

Coefficients =27.14

For Exponents

Exponents  10² x 10¹² = 10⁽²⁺¹²⁾

Exponents =10¹⁴

In conclusion, After that, we put them together once again to produce a scientific notation:

25.37 x 10¹⁴

2.537 x 10¹⁵ miles

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Answer:

Step-by-step explanation:-12+4x-7x=12-3x.

UR MOM IS GONNA BE SO PROUD OF YOU!!!!!!!!!!!!!

log x-log y = log ( x/y) we  use this properties Quotient in the equation.

A logarithm is defined simply?

How does exponential growth utilise e?

You use this properties Quotient in the equation -

log x-log y = log ( x/y)

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The missing value of direct variation is 56/3

The direct variation property states that , whenever the division of values of two quantities is a constant value then there is same variation between these two corresponding values. Or we can also say that if the divisible nature of two corresponding values is constant, then one quantity is directly varies with second quantity. That mean if one quantity increase other will also increase and vice versa.

Let say if x and y are two values and k is a constant value, then

According to direct variation

k = y/x or y = k x

In the given question,

Take the order pair (3,7)

As it is an direct variation, we can substitute it

y=k x  

7=k (3)

K=7 / 3

Now find the direct variation equation

y=k x

Also, k=7/3

Solve this equation for the second pair (8,y)

As, y=7/3 x

   y= 7/3 (8) = 56/3

Therefore, missing value is 56/3

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The next fraction in this sequence 4/5, 13/20, 1/2, 7/20,.... is; 1/5

Arithmetic sequence are sequence that are separated by a common difference.

We are given the sequence as;

4/5, 13/20, 1/2, 7/20,....

The fractions expressed as percentage is given as:

80%, 65%, 50%, 35%...

The general formula for the nth term of the sequence is;

Tₙ = a + (n - 1)d

where;

a is first term

d is common difference

n is position of term

Thus, the fifth term is;

T₅  =  80 + (5 - 1)(-15)

T₅ = 80 + (4)(-15)

T₅ = 80 - 60

T₅ = 20

Expressing 20% as a fraction gives us;

20% = 20/100 = 1/5

Thus the next fraction in the given sequence is 1/5

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It is more unusual to have a day with a high temperature of 55 F. A high temerature of 55 F in July is 2.2 std deviation below the mean and a high temperature of 55 F in January is only 1.889 std deviation above the mean.

Which month is more unusual to have a day with a high temperature?

Here z score =(X-mean)/std deviation

Therefore for temperature 55 F ; zscore for January =(55-38)/9=1.889

And for temperature 55 F ; zscore for July =(55-77)/10=-2.2

As z score reflect that 55 F is farthest from the mean of July in terms of std deviation

It is more unusual to have a day with a high temperature of 55 F. A high temperature of 55 F in July is a 2.2 std deviation below the mean, and a high temperature of 55 F in January is only a 1.889 std deviation above the mean.

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The taxi ride was 11.2 miles

Fabian took a ride from his house to the airport

The taxi company charged 4.80 and 4 per miles

The total fare amount was 44.80, the fee was not inclusive

The number of miles can be calculated as follows

= 44.80/4

= 11.2

Hence the taxi ride was 11.2 miles

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Answer:

151 cm² (i don't know what unit you were given so im going to use cm)

Step-by-step explanation:

Part One: finding the missing side (h)

h = a² = b² + c²

13² = 12² + c²

169 = 144 + c²

169 - 145 = c²

= 25

square root of 25 = c

5 = c

area of top triangular area = ½ b × h

= ½ × 12 × 5

= 30 cm²

Part Two

area of rectangle = l × b

= 12 × 8

= 96 cm²

Part Three

area of square = l × l

= 5 × 5

= 25 cm²

total surface area = (30 + 96 + 25) cm²

= 151 cm²

Expression as a single natural logarithm is 0.01234567901.

Given in the question an expression

ln 3 + 5 ln 3

ln 3 +  ln [tex]3^{5}[/tex]

Apply multiplication rule

ln (3/[tex]3^{5}[/tex])

[tex]3^{5}[/tex] = 243

so

expression as a single natural logarithm is 0.01234567901.

The inverse of an exponential function, the natural log is the logarithm to the base of the number e. Natural logarithms are unique varieties of logarithms that are employed in the treatment of time and growth-related issues.

The distinction between log and ln is that log is expressed in terms of base 10, while ln is expressed in terms of base e. As an illustration, log of base 2 is denoted by log2 and log of base e by loge = ln (natural log).

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Answer: i got no clue

Step-by-step explanation:

Answer:

ecdqwef

Step-by-step explanation:

Answer:

x= 0 (B)

Step-by-step explanation:

hope this helps

I think B.9 is correct

1*3*5=15

1+3+5=9

log ( 3x + 1 ) = 2 => x = 33, by properties of logarithm.

Given: log (3x + 1) = 2

Raising both the sides by 10, in order to remove the logarithm:

=> [tex]10^{log_{10}(3x+1)} = 10^{2}[/tex]

=> 3x + 1 = 100 (as [tex]a^{log_a(x)} = x[/tex])

=> 3x = 99

=> x = 33

Hence, log ( 3x + 1 ) = 2 => x = 33, by properties of logarithm.

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Answer:

The answer is 12.

Step-by-step explanation:

Let the smallest number = x and the largest number = x+2(since the three numbers are consecutive, we would have to use x+2. If we wanted the second largest number, it would be x+1)

We would write the statement "four times the smallest integer is equal to six more than more than three times the largest" as:

4x = 3(x+2) + 6

Now just solve.

4x = 3x+6+6     distributive property

4x = 3x+12        simplify

x  = 12               subtraction property

And since x is the smallest number, we have our answer.

Therefore, the answer is 12.

[Mathematical Solutions]

1.) [tex]\frac{2}{7} + \frac{1}{4} = \frac{15}{28}[/tex]

2.) [tex]\frac{5}{9} +\frac{3}{8} = \frac{67}{72}[/tex]

3.) [tex]3\frac{5}{6} - 2\frac{7}{15} =\frac{41}{30}[/tex] as the Exact Form, or [tex]1\frac{11}{30}[/tex] as the Mixed Number Form.

Hope this helps!

Using logarithmic quotient rule, we expand each logarithm function log√2x/y as 1/2 log (2x) - log (y).

According to the question, we need to expand  we expand logarithm function log√2x/y .In Logarithms, the power is raised to some numbers (usually, base number) to get some other number. It is an inverse function of exponential function.

Quotient rule for logarithm: log (a/b) = log (a) - log(b).

⇒ log√2x/y

Applying quotient rule to the above logarithm function, we get

log√2x/y = log (√2x) - log (y)

= log (2x)^1/2 - log (y)  →(1)

Power rule for logarithm: log (a)ˣ = x log (a)

Applying power rule to the equation (1), we get

log (2x)^1/2 - log (y) = 1/2 log (2x) - log (y)

Hence, using logarithmic quotient rule, we expand each logarithm function log√2x/y as 1/2 log (2x) - log (y).

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Answer:

y=-42 or f(x)=-42

Step-by-step explanation:

1. Substitute x for -6. Equation: f(x)=6(-6) + -6

2. Turn f(x) into y. Equation: y=6(-6) + -6

3. Multiply 6 and -6. Equation: y=-36 + -6

4. Add -36 and -6. Equation: y=-42 or f(x)=-42

Answer:

Can I see a diagram?

Step-by-step explanation:

Answer: 8 and a half vehicles (if no halves are allowed just 8)

Step-by-step explanation:

We divide 68 vehicles by 8 hours bringing us to 8 and a half vehicles an hour