200. newton·meters of work is put into a machine over a distance of 20. meters. The machine does 150. newton·meters of work as it lifts a load 10. meters high. What is the mechanical advantage of the machine?

Answer:8.0 m/s^2

Explanation: The ball is traveling in uniform circular motion at the speed of 2 m/s in a path of the radius that is 0.50 meters.

v^2/r

2.0 m/s^2/ 0.50 m= 8.0 m/s^2

The magnitude of the ball's centripetal  acceleration is [tex]\rm 8 \;m/sec^2[/tex] and this can be determined by using the formula of the centripetal  acceleration.

Given :

A ball attached to a string is whirled at a constant speed of 2.0 meters per second in a horizontal circle of a radius of 0.50 meters.

The following steps can be used in order to determine the magnitude of the ball's centripetal  acceleration:

Step 1 - The formula of the centripetal acceleration can be used in order to determine the magnitude of the ball's centripetal  acceleration.

Step 2 - The formula of the centripetal acceleration is given below:

[tex]\rm a_c=\dfrac{v^2}{r}[/tex]

Step 3 - Substitute the values of the known terms in the above formula.

[tex]\rm a_c=\dfrac{2^2}{0.5}[/tex]

Step 4 - Simplify the above expression.

[tex]\rm a_c = 8\;m/sec^2[/tex]

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Answer:

A producer needs the sun to make its own food, because producers use photosynthesis. In photosynthesis you use the sun to turn the air people breathe out and water into glucose and oxygen.

Explanation:

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Answer:

v= 14.85 m/s

Explanation:

       [tex]F_{cent} = F_{n} - F_{g} (1)[/tex]

       [tex]F_{n} = m*\frac{v^{2} }{r} + m*g (3)[/tex]

      [tex]F_{n} = 1.15*F_{g} = m*\frac{v^{2}}{r} +F_{g} (4)[/tex]

       [tex]v = \sqrt{0.15*g*r} = \sqrt{9.8 m/s2*0.15*150m} = 14.85 m/s (5)[/tex]

Answer:

1.87 ms-2

Explanation:

We need to convert the velocity from km/hr to m/s as follows;

100 × 1000/3600 = 27.7 m/s

Also

120 × 1000/3600 = 33.3 m/s

From;

v= u + at

v= 33.3 m/s

u= 27.7 m/s

t= 3 secs

v= u + at

a = v- u/t

a = 33.3 - 27.7/3

a= 1.87 ms-2

Answer:

-16i kgm/s

Explanation:

Impulse I = m(v - u) where m = mass of ball = 2.0 kg, u = initial velocity of ball = (4i + 3j) m/s  and v = final velocity of ball = (-4i + 3j) m/s.

So, the impulse is thus

I = m(v - u)

= 2.0 kg[(-4i + 3j) m/s - (4i + 3j) m/s]

= 2.0 kg[(-4i - 4i) + (3j - 3j) m/s]

= 2.0kg[-8i + 0j] m/s

= -16i kgm/s

The impulse on a 2.0-kg ball with an initial velocity of (4i + 3j) m/s collides with a wall and rebounds with a velocity of (–4i + 3j) m/s = 16i

Impulse: This can be defined as change in momentum of a body. The s.i unit of impulse is kgm/s²

The formula of impulse is

I = m(v-u)................ Equation 1

Where, I = impulse exerted on the ball by the wall, m = mass of the ball, v = final velocity of the ball, u = initial velocity of the ball

From the question,

Given: m = 2.0 kg, v = (-4i+3j) m/s, u = (4i+3j)  m/s

Substitute these values into equation 1

I = 2.0[(-4i+3j)-(4i+3j)

I = 2.0(-4i-4i+3j-3j)

I  = 2.0(-8i+0j)

I = -16i.

Hence the impulse exerted by the wall on the ball is -16i

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Answer:

Decrease the distance between the two objects.

Explanation:

The force (F) of attraction between two masses (M₁ and M₂) separated by a distance (r) is given by:

F = GM₁M₂ / r²

NOTE: G is the gravitational force constant.

From the equation:

F = GM₁M₂ / r²

We can say that the force is directly proportional to the masses of the object and inversely proportional to the square of the distance between them. This implies that an increase in any of the masses will increase the force of attraction and likewise, a decrease in any of the masses will lead to a decrease in the force of attraction.

Also, an increase in the distance between the masses will result in a decrease in the force of attraction and a decrease in the distance between the masses, will result in an increase in the force of attraction.

Considering the question given above,

To increase the gravitational force between the two objects, we must decrease the distance between the two objects as explained above.

Answer:

Decrease the distance between the two objects.

Explanation:

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Ground-level ozone is the most common pollutant that is often referred to as "smog".

Smog is a type of air pollution that is characterized by a mixture of smoke and fog.

It typically forms in urban areas with high levels of vehicle and industrial emissions, as well as natural factors such as temperature inversions.

Smog is composed of a complex mixture of pollutants, including ground-level ozone, nitrogen oxides, sulfur oxides, particulate matter, and volatile organic compounds (VOCs).

Exposure to smog can cause a range of health problems, including respiratory issues, heart disease, and cancer. It can also have negative impacts on the environment, including damage to crops, forests, and bodies of water. Efforts to reduce smog often involve reducing emissions from vehicles and industrial sources and promoting cleaner forms of transportation and energy production.

Therefore, The Ground-level ozone is the most common pollutant that is often referred to as "smog".

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Answer:

Explanation:

I just need points

This question is incomplete, the complete question is;

A 30-kilogram child moving at 4.0 meters per second jumps onto a 50-kilogram sled that is initially at rest on a long, frictionless, horizontal sheet of ice.

a. Determine the speed of the child-sled system after the child jumps onto the sled.

b. After coasting at constant speed for a short time, the child jumps off the sled in such a way that she is at rest with respect to the ice. Determine the speed of the sled after the child jumps off

Answer:

a) the speed of the child-sled system after the child jumps onto the sled is 1.5 m/s

b) the speed of the sled after the child jumps off is 2.4 m/s

Explanation:

Given that;

Weight of the child m_c = 30 kg

u = 4 m/s

M = 50 kg

a) the speed of the child-sled system after the child jumps onto the sled.

Using conservation of momentum;

P_i = P_f

30 × 4 = 50(v) + 30(v)

120 = 80(v)

v = 120 / 80

v = 1.5 m/s

therefore, the speed of the child-sled system after the child jumps onto the sled is 1.5 m/s

b) the speed of the sled after the child jumps off .

Also using conservation of momentum;

mv1 = mv2

(30+50) × 1.5 = (30 × 0) + (50 × v2 )

80 × 1.5 = 50v2

v2 = 120 / 50

v2 = 2.4 m/s

Therefore the speed of the sled after the child jumps off is 2.4 m/s

Answer:

The number of revolutions is 10.68 rev/min.

Explanation:

Given that,

Radius = 8 m

Suppose,  centripetal acceleration equal to the gravity

[tex]a_{c}=g=9.8[/tex]

We need to calculate the velocity

Using formula of centripetal acceleration

[tex]a_{c}=\dfrac{v^2}{r}[/tex]

[tex]v^2=a_{c}\times r[/tex]

Put the value into the formula

[tex]v=\sqrt{9.8\times8}[/tex]

[tex]v=8.85\ m/s[/tex]

We need to calculate the value of [tex]\omega[/tex]

Using formula of velocity

[tex]v=r\omega[/tex]

[tex]\omega=\dfrac{v}{r}[/tex]

Put the value into the formula

[tex]\omega=\dfrac{8.85}{8}[/tex]

[tex]\omega=1.12\rad/s[/tex]

We need to calculate the number of revolutions

Using formula of angular frequency

[tex]\omega=\dfrac{2\pi}{T}[/tex]

[tex]\omega=2\pi N[/tex]

[tex]N=\dfrac{\omega}{2\pi}[/tex]

Put the value into the formula

[tex]N=\dfrac{1.12}{2\pi}[/tex]

[tex]N=0.178\ rev/s[/tex]

Using conversion rev/s to rev/min

[tex]N=0.178\times 60[/tex]

[tex]N=10.68\ rev/min[/tex]

Hence,  The number of revolutions is 10.68 rev/min.

Answer:

Physicists use a hand mnemonic known as the right-hand rule to help remember the direction of magnetic forces. To form the mnemonic, first make an L-shape with the thumb and first two fingers of your right hand. Then, point your middle finger perpendicular to your thumb and index finger.

Answer:

If you point your pointer finger in the direction the positive charge is moving, and then your middle finger in the direction of the magnetic field, your thumb points in the direction of the magnetic force pushing on the moving charge.

Explanation:

Got it right

Answer:

Mass of the man = 100 kg

Explanation:

Given that,

Mass of the Earth, M = 6×10²⁴ kg

The radius of the Earth, r = 6400 km

Force on man, F = 977 N

We need to find the mass of the man. Let the mass of the man be m. The gravitational force acting between two objects is given by :

[tex]F=G\dfrac{mM}{r^2}\\\\m=\dfrac{Fr^2}{GM}\\\\m=\dfrac{977\times (6400\times 10^3)^2}{6.67\times 10^{-11}\times 6\times 10^{24}}\\\\m=99.99\ kg[/tex]

or

m = 100 kg

So, the mass of the man is 100 kg.

Answer:

3 hours

Explanation:

180 divided by 60 (mph means miles per hours by the way)

Answer:1.1x10^3N upward

Explanation:

Answer:

300 m  

Explanation:

using constant acceleration equations:

v = vi + a * t, v = final velocity = 0m/s , vi =  initial velocity = 60m/s,

a = acceleration = -6m/s², t = time

solve t

t = 10s

x = vi * t + .5 * a * t²

plug

x = 300 m

Answer:

Kinetic energy is the energy of motion. An object that has motion - whether it is vertical or horizontal motion - has kinetic energy. There are many forms of kinetic energy - vibrational (the energy due to vibrational motion), rotational (the energy due to rotational motion), and translational (the energy due to motion from one location to another). To keep matters simple, we will focus upon translational kinetic energy. The amount of translational kinetic energy (from here on, the phrase kinetic energy will refer to translational kinetic energy) that an object has depends upon two variables: the mass (m) of the object and the speed (v) of the object. The following equation is used to represent the kinetic energy (KE) of an object.

KE = 0.5 • m • v2

where m = mass of object

v = speed of object

This equation reveals that the kinetic energy of an object is directly proportional to the square of its speed. That means that for a twofold increase in speed, the kinetic energy will increase by a factor of four. For a threefold increase in speed, the kinetic energy will increase by a factor of nine. And for a fourfold increase in speed, the kinetic energy will increase by a factor of sixteen. The kinetic energy is dependent upon the square of the speed. As it is often said, an equation is not merely a recipe for algebraic problem solving, but also a guide to thinking about the relationship between quantities.

Kinetic energy is a scalar quantity; it does not have a direction. Unlike velocity, acceleration, force, and momentum, the kinetic energy of an object is completely described by magnitude alone. Like work and potential energy, the standard metric unit of measurement for kinetic energy is the Joule. As might be implied by the above equation, 1 Joule is equivalent to 1 kg*(m/s)^2.

1 Joule = 1 kg • m2/s2

Explanation:

Answer:

If it has balanced forces, then it is completely still.

Balanced forces do not cause a change in motion. So, the object that has balanced forces acting on it either moves with constant speed at a constant direction or remains rest.

Two forces are said to be balanced when their strengths are equal but their directions of action are opposing. Once more, tug-of-war is a prime illustration. The forces are balanced if the pullers are exerting equal force but going in the opposite direction on either side of the rope. There is hence no motion.

Forces that are balanced can cancel one another out. The thing stays in place whenever there is a balanced force.

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Answer:

the correct one is b,  Decrease the launch speed and Low the launch height

Explanation:

Let's find the solution to the problem in order to answer the questions.

The bullet is fired horizontally with a velocity vo, let's find the time or it takes to reach the ground

      y = y₀ + [tex]v_{oy}[/tex] t - ½ g t²

as it shoots horizontally v_{oy} = 0 and when I reach the floor y = 0

       0 = y₀ - ½ g t2

       t = [tex]\sqrt{\frac{2y_{o} }{g} }[/tex]

where y₀ is the height of the cliff

at this time the bullet recreates a distance of

       x = v₀ t

we substitute

       x = v₀ \sqrt{\frac{2y_{o} }{g} }

There, to reduce the range of the bullet, we must decrease its speed. This is the magnitude that most affects the distance and to a lesser degree we can decrease the height.

When checking the answers, the correct one is b

Answer:

v = 22.58[m/s]  

Explanation:

To solve this problem we will use the principle of energy conservation, which tells us that potential energy is transformed into kinetic energy or vice versa.

[tex]E_{kin}=E_{pot}[/tex]

We must remember that potential energy is defined as the product of mass by gravity by height.

[tex]E_{pot}=m*g*h[/tex]

And the kinetic energy can be calculated by means of the following expression.

[tex]E_{kin}=0.5*m*v^{2}\\[/tex]

Now equalizing the two equations we can determine the initial velocity.

[tex]m*9.81*26=0.5*m*v^{2}\\255.06=0.5*v^{2}\\v=\sqrt{255.06/0.5}\\v=22.58[m/s][/tex]

Answer:

GRAVITYYYYY

HOPE THIS HELPS

Answer: There is a net force acting on which is a force of gravity

Explanation:

Answer:

there is no net force onthe car

Explanation:

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Answer:

Images that are not aligned are laterally inverted

Explanation:

When a plane mirror reverses an image so that it becomes upside down and downside up or the other way round, we say that the image is laterally inverted.

Hence the effect produced when a plane mirror reverses an image is called lateral inversion

A good example of lateral inversion ins the lettering of an ambulance

Answer:

Speed at bottom of the hill (v) = 11.74 m/s

Explanation:

Given:

Combined mass = 48.8 kg

Height h = 7.05 m

Find:

Speed at bottom of the hill (v)

Computation:

v² = 2gh

v = √2 x 9.8 x 7.05

v = √138.18

v = 11.74 m/s

Speed at bottom of the hill (v) = 11.74 m/s

Answer:

The mass of the dog is 15 kg

Explanation:

We use the formula for the kinetic energy of the dog:

[tex]KE=\frac{1}{2} m\,v^2[/tex]

Then, in our case:

[tex]KE=\frac{1}{2} m\,v^2\\1080 \,=\,\frac{1}{2} m\,(12)^2\\m = \frac{2*1080}{144} \\m=15 \,\,kg[/tex]

Answer:

The Total Mechanical Energy

As already mentioned, the mechanical energy of an object can be the result of its motion (i.e., kinetic energy) and/or the result of its stored energy of position (i.e., potential energy). The total amount of mechanical energy is merely the sum of the potential energy and the kinetic energy.

Explanation: