3. An object is dropped from 600m, If it is initially at rest, how fast will it go as it
Hits the ground?

Answers

Answer 1

The velocity of the object as it hits the ground, given the data from the question is 108.486 m/s

How to determine the final velocity

We'll begin by obtaining the time take to reach the ground. this is illustrated below:

Height (h) = 600 mAcceleration due to gravity (g) = 9.8 m/s²Time (t) =?

h = ½gt²

600 = ½ × 9.8 × t²

600 = 4.9 × t²

Divide both side by 4.9

t² = 600 / 4.9

Take the square root of both side

t = √(600 / 4.9)

t = 11.07 s

Finally, we can obtain the final velocity as follow:

Time (t) = 11.07 sInitial velocity (u) = 0 m/sAcceleration due to gravity (g) = 9.8 m/s²Final velocity (v) =?

v = u + gt

v = 0 + (9.8 × 11.07)

v = 0 + 25.088

v = 108.486 m/s

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Related Questions

what happens to the sh
ape of water when we pour the same volume of water in different containers of different shape​

Answers

Answer:

It shapes into the form of the container because water is a liquid.

Explanation:

You are driving through town at 12.0 m/s when suddenly a ball rolls out in front of you. You apply the brakes and begin decelerating at 3.5 m/s^2
(a) How far do you travel before stopping?
(b) When you have traveled only half the distance in part (a), is your speed 6.0 m/s, greater than 6.0 m/s, or less than 6.0 m/s?
(c) Find the speed of your car when you have traveled half the distance in part (a).

Answers

(a) The distance traveled by the driver before stopping is 20.57 m.

(b) When you have traveled only half the distance in part (a), your speed is greater than 6.0 m/s.

(c) The speed of your car when you have traveled half the distance in part (a) is 8.49 m/s.

Distance traveled by the driver before stopping

The distance traveled by the driver before stopping is calculated as follows;

v² = u² + 2as

when the car stops, the final velocity, v = 0

0 = u² + 2as

0 = 12² + 2(-3.5)s

0 = 144 - 7s

7s = 144

s = 144/7

s = 20.57 m

when you travel half of 20.57 m

v² = (12²) - 2(3.5)(0.5 x 20.57)

v² = 72.005

v = √72.005

v = 8.49 m/s

Thus, when you have traveled only half the distance in part (a), your speed is greater than 6.0 m/s.

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A car is driving on a gravel road at a speed of 12 m/s. The car maintains this speed for 10 seconds. Going around a bend the car reduces speed to 5 m/s during the next 5 seconds. Over the last 15 seconds the car increases its speed with 2 m/s every second. Determine the maximum and minimum values for both axes.

Answers

The maximum distance covered by the car from point A to B will be 120 meters, and the minimum distance covered by the car will be 25 meters.

What is Speed?

Measuring is the most important scientific concept. Many different types of quantifiable quantities can be measured using base or physical fundamental units. One such quantifiable quantity is speed, which computes the proportion of a moving object's distance travelled to its travel time.

According to the question,

Point A and B are taken on X-axis and point B,C and D are taken on y-axis.

On going from point A to B,

Time taken= 10 seconds

Speed= 12 m/s

Distance covered will be : Speed × time

=12 × 10 sec

Distance= 120 meters

On going from Point B to C,

Time taken= 5 Seconds

Speed= 5 m/s

Distance covered by car will be : Speed × Time

=5 × 5 sec

Distance= 25 meters.

Now, On going from point C to D,

Time taken= 15 seconds

Speed= 2 m/s

Distance covered = speed × time

= 2 × 15 sec

Distance= 30 meters

Hence, the maximum distance covered by car is 120 meters when it goes from point A to B and the minimum distance covered by car is 25 meters when it goes from Point B to C.

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In which of the following situations are you doing positive work on the box?
Throwing a box at someone.
Carrying a box in your arms across the room.
Carrying a box in your arms up the stairs.
Holding a box in your out-stretched arms, spinning around in a circle.
Catching a box that is thrown at you.
Pushing a box on the floor across the room.
Carrying a box in your arms down the stairs.
Holding a box in your arms.

Answers

F. The situation in which the work done is positive is, "Pushing a box on the floor across the room.".

What is positive work?

The work done on an object is said to be positive work when force applied on the object causes a displacement of the object in the same direction.

Some of the examples of positive work include the following:

pushing a table or chair across a horizontal surfacePushing a box on the floor across the room.

From the given options, the only option in which the applied force is in the same direction as the box's displacement is option F "Pushing a box on the floor across the room".

Thus, the situation in which the work done is positive is, "Pushing a box on the floor across the room.".

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Need help answering this question

Answers

Answer:

[tex] log( \beta e \alpha \sin( \cot( \sec( \binom{? \times \frac{ \\ \infty }{?} }{?} ) ) ) ) [/tex]

6) A person on a bus traveling 5 m/s is walking to the back of the bus at 1 m/s. How fast does
the person on the bus appear to be moving to a person in a car going the opposite direction
traveling at 2 m/s?

Answers

Answer:

maximum velocity,then u draw your diagram then u calculate for max velocity then the answer u get use it for total shape

Which of the following best describes the difference between experiments and correlational research methods? Which of the following best describes the difference between experiments and correlational research methods? Experiments use one type of statistical test; correlational methods use a different type of statistical test Experiments allow researchers to make claims about one thing causing the other; correlational methods don't Experiments are always the best form of research to do; correlational methods are inherently worse

Answers

(A) Experiments use one type of statistical test; correlational methods use a different type of statistical test

Correlational research:

A non-experimental research method known as correlational analysis measures two variables and evaluates the statistical relationship (also known as the correlation) between them with little to no effort to control unrelated variables. There are a variety of factors to consider when deciding whether to perform an experiment or a correlational study by researchers interested in statistical correlations between variables. First off, they either don't think the statistical relationship is causative or aren't interested in causality. Remember that the two main objectives of science are to describe and predict; the correlational research approach enables researchers to accomplish both of these objectives.

Experimental research:

Experimental research is a term used to describe a study that closely resembles a scientific research methodology. A hypothesis, a controlled variable, and variables that can be measured, computed, and compared make up this structure.The utilization of controlled conditions in experimental research is vital. The facts that the researcher gathers will either confirm or disprove the theory.

Difference between experimental and correlational methods:

You alter an independent variable and track its impact on a dependent variable in an experimental design. Other factors cannot affect the outcomes because they are under control. You measure variables in a correlational design without changing any of them.

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how does mass and velocity determine the amount of damage that occurs in a collision?

Answers

Answer:

Mass and velocity are both directly proportional to the momentum. If you increase either mass or velocity, the momentum of the object increases proportionally. If you double the mass or velocity you double the momentum.

Explanation:

The Distance-time graph shown is for a 3000 m cross-counrty race, run by rachel and james.

Answers

From the given graph, it is shown that James is running the race with the same speed while Rachel changes his speed time-to-time. It can be inferred from the graph that James wins the race.

What is Speed?

Speed is the distance travelled by an object in a particular time. In the race, James run with a constant speed throughout the race and Rachel changes its speed after some time.

By looking at the graph, we can say that James catch up Rachel 17.5 minutes after the start of the race where they both completed 1750m distance.

Speed of James can be calculated by the formula:

Speed = Distance/Time

Speed = 3000m/30min

Speed of James = 100m/min.

Different speeds of Rachel can be calculated by the same formula:

For the first 1000m he completes the distance in 5 min. therefore, the speed will be:

Speed = 1000m/5min.

Speed = 200m/min.

For the next 1500m. he covers the distance in 25min. therefore, the speed here will be:

Speed = 1500m/25min.

Speed = 60m/min.

For the next 500m. he covers the distance in 5 min. therefore, the speed will be:

Speed = 500m/5min.

Speed= 100m/min.

As, James covers the same distance earlier than Rachel. James cover the the distance in 30 minutes while Rachel covers the same distance in 35 minutes. James will be the winner of the race.

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A 1.5 kg mass swings at the end of a 2.3 m string. A scale on the string
measures the tension in the string to be 24.5 N. What is the centripetal
force on the swinging mass? __________ Blank 1
And, what is the speed of the mass at the time the tension is measured?

Answers

The speed of the mass at the time the tension is measured is 6.12m/s

centripetal force - It is a force which makes a body follow a curved path.

It is directed inward towards center of rotation.

for example - gravitational force of sun is a centripetal force that keeps earth rotating around it.

the centripetal force on the swinging mass

Fc = mv²/r

where Fc is the centripetal force

m is the mass of body

v is the velocity

r is the radius

m = 1.5

r = 2.3 m

F = 24.5 N

To calculate the speed we put values in above equation

Fc = mv²/r

v = sqrt(Fc x r / m)

v = [tex]\sqrt[]{\frac{F *m}{r} }[/tex]

[tex]v = \sqrt[]{\frac{24.5*1.5}{2.3} }[/tex]

v = 6.12m/s

The speed of the mass at the time the tension is measured is 6.12m/s

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Dean is slowing down on his skateboards. He starts at a speed of 5.5 m/s and
slows to 1.0 m/s over a time of 3.0 seconds. What is Dean's acceleration?

Answers

Dean's acceleration while slowing down on his skateboards a = -1.5 m/s².

Equation :

To find the acceleration of skateboards

Using formula,

a = Δv/Δt

where,

a is acceleration

Δv is change in speed

Δt is time

By putting the given values,

a = 1.0 m/s - 5.5 m/s / 3 s

a = - 4.5 m/s / 3s

a = -1.5 m/s²

Is acceleration can be positive or negative?

When an object is moving in a positive direction, the acceleration is negative, but the rate of change of velocity is positive (velocity is decreasing). When an object moves in the reverse or opposite direction, we can define these two accelerations as well (right to left).

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A car travels on a straight level road. Starting from rest the car is going 32 fr/s (22mi/h) at the end of 4.2s what is the cars average acceleration in ft/s^2

Answers

The acceleration of a car that travels on a straight level road starting from rest and going at 32 ft/s at the end of 4.2s is 7.62ft/s².

How to calculate acceleration?

The acceleration of a moving car can be calculated by dividing the speed by the time taken as follows:

Acceleration = Speed ÷ time

According to this question, a car travels on a straight level road starting from rest the car is going 32 ft/s (22mi/h) at the end of 4.2s. The acceleration can be calculated as follows:

Acceleration = 32ft/s ÷ 4.2s

Acceleration = 7.62ft/s²

Therefore, the acceleration of a car that travels on a straight level road starting from rest and going at 32 ft/s at the end of 4.2s is 7.62ft/s².

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A ballplayer standing at home plate hits a baseball that is caught by another player at the same height above the ground from which it was hit. The ball is hit with an initial velocity of 26.8 m/s at an angle of 60.0° above the horizontal. At what distance from the home plate will the fielder be when he catches the ball?

Answers

The distance from the home plate the fielder will be when he catches the ball is 63.47 m

From the question given above, the following data were obtained:

Initial velocity (u) = 26.8 m/sAngle of projection (θ) = 60.0 °Acceleration due to gravity (g) = 9.8 m/s²Distance (i.e range) (R) =?

How to determine the range

The distance (i.e range) the fielder will be when he catches the ball can be obtained as follow:

R = u²Sine(2θ) / g

R = 26.8² × Sine (2×60) / 9.8

R = 622.014 / 9.8

R = 63.47 m

Thus, the distance the fielder will be is 63.47 m

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Football player Joe is running toward the opponent's goal line with the football, and slows down as he encounters the other team. If the opponent's goal line is the reference point, which of the following best describes his motion?

Question 4 options:

Negative Velocity, Negative Acceleration


Negative Velocity, Positive Acceleration


Positive Velocity, Negative Acceleration


Positive Velocity, Positive Acceleration

Answers

Since Joe is running towards the goal line and slowing down, the option that describes this motion is negative velocity, negative acceleration.

What is negative velocity?

A negative velocity occurs when an object moves in the negative direction.

Example of negative velocity;

If a car is moving away from you (reference point) then the velocity is positive.

If a car is coming towards you (reference point) then the same vector reverses direction and hence the velocity is negative.

What is negative acceleration?

If the object is slowing down then its acceleration vector is directed in the opposite direction as its motion. Thus, the acceleration of the object will be negative.

Thus, since Joe is running towards the goal line and slowing down, the option that describes this motion is negative velocity, negative acceleration.

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What is the sum of the following vectors? Write your answer, what magnitude and direction the vector will have?

Answers

The magnitude and direction of the object's displacement is 7 m and west direction respectively.

What is displacement?

The displacement of an object is the change in the position of the object. Displacement is a vector quantity because it has both magnitude and direction.

To find the sum of the vectors, we find the displacement of the vectors.

Initial position of the vector = 10 m east

final position of the vector = 3 m west

displacement of the vector = final position - initial position

displacement of the vector = 3 m - 10 m

displacement of the vector = - 7 m

magnitude of the displacement = 7 m

direction of the displacement = west

Thus, the magnitude and direction of the object's displacement is 7 m and west direction respectively.

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Why does gravity cause acceleration?
Answer choices

A. It acts in a downward direction
B. It has a greater effect on objects with more mass.
C. It always causes objects to slow down.
D. It is a force.

Answers

it would be D because Gravity is a force that pulls objects down toward the ground and when objects fall to the ground, gravity causes them to accelerate .

Which of the following was NOT a part of the arrival process for Jews at the concentration camps?
A. Defense training
B. Losing all possessions
C. Hair shaving
D. Strength test for work

Answers

The answer is A if you still need it :)

A record of travel along a straight path is as follows:
1. Start from rest with constant acceleration of 2.25 m/s2 for 19.0 s.
2. Maintain a constant velocity for the next 2.50 min.
3. Apply a constant negative acceleration of −9.09 m/s2 for 4.70 s.
(a) What was the total displacement for the trip? m

(b) What were the average speeds for legs 1, 2, and 3 of the trip, as well as for the complete trip?
leg 1 m/s
leg 2 m/s
leg 3 m/s
complete trip m/s

Answers

The total displacement is 4317.34 meters and the average speeds of the legs are 27.36m, 54.72m, 27.35m.

What is average speed?

The overall distance the object covers in a given amount of time is its average speed. A scalar value represents the average speed. It has no direction and is indicated by the magnitude.

a = 2.25 m/s2 ; t1 = 19 s ; t = 2.50 min = 150 sec ; a' = -9.09 m/s2  t3 = 4.70 s

(a)The velocity at the end of the first interval will be given by

V = u + at = 0 + a t1 = 2.25 x 19 = 42.75 m/s

This velocity will remain the same throughout the second period in accordance with point (2) and serve as the initial velocity for the third interval.

We now see that, if s is the displacement, s = u t + 1/2 a t2

In our situation, the sum of the displacements in the specified three intervals will represent the total displacement.

[tex]\Delta s(total) = \Deltas1 + \Deltas2 + \Deltas3[/tex]

[tex]\Delta s(total) = [0 + 1/2 x 2.88 x (19)2) + [54.72 x 66 + 0] + ( 54.72 x 6.8 + 1/2 x (-8.05) x (6.8)2][/tex]

[tex]\Delta s(total) = 519.84 + 3611.52 + 185.98 = 4317.34 meters[/tex]

Hence,

[tex]\Delta s(total) = 4317.34 meters = 4.32 Km.[/tex]

(b)Speed for leg 1 will be

v1 = [tex]\Delta s1 / t1 = 519.84 / 19 = 27.36 m/s[/tex]

Speed for leg 2 will be

[tex]v2 = \Delta s2 / t2 = 3611.52 / 66 = 54.72 m/s[/tex]

Speed for leg 3 will be

[tex]v2 = \Delta s3 / t3 = 3611.52 / 66 = 185.98 / 6.8 = 27.35 m/s[/tex]

The average velocity of the complete trip will be given as follows:

V = [tex]\Delta s(total) / t(total)[/tex]

t(total) = t1 + t2 + t3 = 19 + 66 + 6.8 = 91.8 s

[tex]V = \Delta s(total) / t(total) = 4317.34 meters / 91.8 = 47.03 m/s[/tex]

Hence, V = 47.03 m/s

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9. The coefficient of static
friction between a 5kg block
and horizontal surface is 0.4.
What is the maximum
horizontal force that can be
applied to the block before it
slips?

Answers

Answer:

19.6 Newtons

Explanation:

[tex]\displaystyle \textsf{The weight of the block is W= mg where m is the mass and g the acceleration due to gravity}[/tex]

[tex]\sf W = 5kg, \; and\; g = 9.80 m/s^2[/tex]

[tex]\sf W = 5 x 9.8 = 49\; Newtons[/tex]

[tex]\textsf {If the coefficient of static friction is } $\mu_s$, the force to be applied for the block to slip is given by the equation}:\\\mathsf {f_s = \mu_s \times W}\\\\\textsf {So force required, given $\mu_s$ = 0.4 is: }\\\\\\\mathsf {f_s = 0.4 \times 49 = 19.6 } \textsf{ Newtons }[/tex]

Think of a pen name that you most likely would use if you are to become a writer. Write it down and give a brief explanation as to why you have chosen that particular pseudonym. Write your explanation on not less that three paragraph with 5 sentence each paragraph

Answers

A pen name is the name used by the writer instead of their real name when publishing. This name is called as pseudonym or a fake name. The author's real name is probably known to the publisher, but not to the public.

If I'll be the writer, I'll use Dark Shadow as my pen name.

Dark Shadow effectively acts as a living appendage that obeys his master's every command. It is sentient, capable of speech, and loyally protects its host regardless of its state. Also it is short and sweet name and can be pronounced easily.

Also thee is a drawback in seeking secrecy with the pen name. The Guardian article says, "If you try to keep your identity secret, you can't go to events or festivals; be pictured in newspapers, or be open about your possible success. And, if you become hugely successful, you'll have to come out eventually – as Madeleine Wickham, the author of the Sophie Kinsella books, did. "

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vector A points in the negative x direction and has a magnitude of 25 units. The vector B points in the positive y direction. Find the magnitude of B if A+B has a magnitude of 35 units

Answers

The magnitude of vector B is determined as 24.5 units.

What is resultant vector?

A resultant vector is defined as a single vector that produces the same effect as is produced by a number of vectors collectively.

The given parameters;

magnitude of vector A = 25 unitsresultant of vector A and B = 35 unitsmagnitude of vector B = ?

The magnitude of vector B is calculated as follows;

B² = R² - A²

where;

R is the resultant vector or sum of vector A and vector B

B = √(35² - 25²)

B = 24.5 units

Thus, the magnitude of vector B is determined as 24.5 units.

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velocity equations solve:
15, km over second
find the m/s
and find the km/h

Answers

The 15 km/s velocity is equivalent to 15000 m/s and 54000 km/h.

Velocity is a vector quantity. It consist both a direction and a magnitude. The magnitude of velocity is called speed. Its S.I. unit is a meter/second. It also has other units like Km/h and Km/s. Its dimensional formula is [[tex]LT^{-1}[/tex]].

Given in the question

Velocity is 15 Km over a second

We can infer from the given value that the body moves 15 km per second.

1 Km = 1000 m

1 Km × 15  = 15 × 1000 m

So 15 Km = 15000 m

Hence we can say that the body travels 15000 meters in a second.

As a result, its velocity in m/s is 15000 m/s.

Now

15 kilometers can be covered in 1 second.

Distance traveled in 3600 seconds = 3600 × 15 Km

So the total distance traveled in 3600 seconds is 54000 kilometers.

Also 3600 seconds = 1 hour

In other words, The body travels 54000km in 1 hour, hence its velocity is 54000 km/h.

Therefore, the 15 km/h velocity is equal to 15000 m/s and 54000 km/h.

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A projectile is launched at 68.0° above the horizontal and at a speed of 55 m/s. How long will it take the projectile to reach maximum height?

Answers

Answer:

5.2s

Explanation:

We care about the vertical component of the velocity, which, in our case, is [tex]v_y=55 sin 68\° m/s \approx 51 m/s[/tex]. The projectile is affected by gravity, which means its velocity will decrease by [tex]g= 9.81 m/s[/tex] each second. Remembering that at maximum height velocity is zero, we can write [tex]0=51-9.81 t \rightarrow t= \frac{51}{9.81}\approx 5.2s[/tex]

A car travels due east with a speed of 50.0 km/h. Raindrops are falling at a constant speed vertically with respect to the Earth. The traces of the rain on the side windows of the car make an angle of 60.0° with the vertical. Find the velocity of the rain with respect to the following reference frames. (Enter the magnitude of the velocity.)
(a) the car
m/s
(b) the Earth
m/s

Answers

The velocity of the rain with respect to car is 43.3 km/h and the velocity of the rain with respect to earth is 50 km/h.

What is relative velocity?

Relative velocity is the velocity of one object with respect to another using a frame of reference.

Velocity of the rain with respect to the car

V(rc) = 50 km/h x sin(60)

V(rc) = 43.3 km/h

Velocity of the rain with respect to the earth

V(re) = speed of the car =  50 km/h

Thus, the velocity of the rain with respect to car as frame of reference is 43.3 km/h and the velocity of the rain with respect to earth as the frame of reference is 50 km/h.

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What is the distance travelled by the motorbike while it is moving at
constant speed?
(a) 150m
(b) 50m
(c) 300m
(d) 750m

Any Expert Please Help me out

Answers

The distance travelled by the motorbike while it is moving at a constant speed is 150m

From the graph, we form the relationship between the speed s and the change in the time t for the journey, i.e. from t = 20sec to t = 30sec speed  s is constant = 15m/s

As the formulae states that

Speed = Distance / Time

Distance = Speed × change in time

⇒15 × ( 30 - 20 )

⇒15 × 10

⇒150m

Hence the Distance travelled by bike was 150m

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Can someone solve this problem thank you!

Answers

(a) Capacitance = 4.43 * 10⁻¹¹ F

(b) Magnitude of the charge on each plate = 2.9238 * 10⁻⁸ C

(c) Stored Energy = 8.7714 * 10⁻⁶

(d) The electric field between the plates = 6.0 * 10⁴ V/m

(e) The energy density between the plates = 1.45 J/m³

(A) The ability of a conductor or group of conductors to store a separated electric charge for a given change in electrical potential is known as its capacitance. The term "capacitance" also suggests the storage of electrical energy.

Capacitance (C) = A∈ / d = [tex]\frac{55 * 10^{-4}* 8.86 * 10^{-12}}{0.011}[/tex] = 4.43 * 10⁻¹¹ F

Therefore, Capacitance = 4.43 * 10⁻¹¹ F

(B) The force per charge on any particular test charge situated within the electric field is used to calculate the electric field vector's magnitude. Either the source charge or the test charge could be directly affected by the force acting on it.

The magnitude of the charge on each plate (Q) = CV

Q = 4.43 * 10⁻¹¹ * 660 = 2.9238 * 10⁻⁸ C

Therefore, the magnitude of the charge on each plate = 2.9238 * 10⁻⁸ C

(C) The energy that a thing retains due to its position in relation to other objects, internal tensions, electric charge, or other causes is known as stored energy.

Stored Energy (U) = 0.5 CV² = 8.7714 * 10⁻⁶ J

Therefore, Stored Energy = 8.7714 * 10⁻⁶ J

(D) The region or place where the influences of the plates' charges are visible is the electric field between the plates. For instance, any charged plate will produce an electric force to either attract or repel a charged particle if it is placed close to it.

The electric field between the plates (E) = V / d = 660 / 0.011 = 6 * 10⁴ V/m

Therefore,  The electric field between the plates = 6.0 * 10⁴ V/m

(E) The quantity of energy that can be held in a specific system, substance, or area of space is known as its energy density. Energy per volume or mass can be used to measure energy density. A system or material has more energy stored in it when its energy density is higher.

The energy density between the plates (u) = U / Ad = [tex]\frac{8.7714 * 10^{-6} }{(55 * 10^{-4}) (1.1 * 10^{-3})} = \frac{0.0000063}{0.0055 * 0.0011} = \frac{0.00000878}{0.00000605} = \frac{878}{605} = 1.45 Jm^{3}[/tex]

Therefore, The energy density between the plates = 1.45 J/m³

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Daniel's physician has told him that he needs to spend less time in his office chair because sitting for so long is causing him to have back pain. What ergonomic solution could help him?
(A short explanation is ok if you can)


A) wearing a wrist brace


B) a standing desk


C) moving his monitor closer to his eyes


D) using a speakerphone more often

(please help ill give brainliest as soon as i can =) )

Answers

The possible ergonomic solution that could help Daniel reduce hos back pain caused by sitting long on his chair is a standing desk.

What is ergonomic solution?

Ergonomics is defined as the science of creating a working environment that suits the capabilities and limitations of the worker while providing the best working experience.

If Daniel's physician has told him that he needs to spend less time in his office chair because sitting for so long is causing him to have back pain. The possible ergonomic solution that could help him include the following.

Daniel can use a revolving seatDaniel can also use a standing desk; this will enable him stand and reduce his back pain which happens when he sits for long.

Thus, the possible ergonomic solution that could help Daniel reduce hos back pain caused by sitting long on his chair is a standing desk.

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Answer: B. A standing desk

Explanation: I remember getting it right on my test.

A piolet is required to fly directly from London,United Kingdom, to Rome,Italy,in 3.4 h. The displacements is 1.4×10³km[S 43⁰ E] . The wind velocity reported from the ground is 55km/h[S]. Determine the required velocity of the plane relative to the air.

Answers

The required velocity of the plane relative to air with a velocity of 55 km / h S is 373.42 km / h

v = d / t

d = 1400 km ( 43° E of S )

t = 3.4 hrs

[tex]V_{pg}[/tex] = d / t

[tex]V_{pg}[/tex] = 1400 / 3.4

[tex]V_{pg}[/tex] = 411.75 km / h ( SE )

[tex]V_{ag}[/tex] = 55 km / h ( S )

[tex]V_{pgx}[/tex] = sin 43° ( 411.75 )

[tex]V_{pgx}[/tex] = 280.81 km / h ( E )

[tex]V_{pgy}[/tex] = cos 43° ( 411.75 )

[tex]V_{pgy}[/tex] = 301.14 km / h ( S )

[tex]V_{x}[/tex] = [tex]V_{pgx}[/tex] - [tex]V_{agx}[/tex]

[tex]V_{x}[/tex] = 280.81 - 0

[tex]V_{x}[/tex] = 280.81 km/ h

[tex]V_{y}[/tex] = [tex]V_{pgy}[/tex] - [tex]V_{agy}[/tex]

[tex]V_{y}[/tex] = 301.14 - 55

[tex]V_{y}[/tex] = 246.14 km / h

V² = [tex]V_{x}[/tex]² + [tex]V_{y}[/tex]²

V = √ [ ( 280.81 )² + ( 246.14 )² ]

V = 373.42 km / h

tan θ = [tex]V_{y}[/tex] / [tex]V_{x}[/tex]

θ = [tex]tan^{-1}[/tex] ( 246.14 / 280.81 )

θ =  [tex]tan^{-1}[/tex] ( 0.88 )

θ = 41.35° ( S of E )

Therefore, the required velocity of the plane relative to air is 373.42 km / h at 41.35 S of E

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2. What are the benefits of repeated trials?

Answers

Science is the study of how the world functions through the systematic process of data collection known as the scientific method.

What are repeated trials?

Repeated trials are when a measurement is performed more than once at least three times, most often five but the more the better.

The likelihood that a measurement made once will yield an accurate result is substantially smaller. However, if you measure it multiple times, you may average the results to produce a value that is considerably more accurate.

In repeated trials, the same thing is measured repeatedly to increase the accuracy of your results. This is essential since data in the actual world frequently varies and nothing is flawless. Your average will get more closely to the genuine value as you perform more trials.

Therefore, Science is the study of how the world functions through the systematic process of data collection known as the scientific method.

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You push a box down the hallway. The box, with a mass of 30kg, accelerates at a speed of 3m/s2. If the force of friction on the box is 20N, how much did YOU exert in order to move it?

Answers

The force you exerted in order to move the box, given the data from the question is 110 N

How to determine the net force

We'll beging by obtaining the net force on the box. This is illustrated below:

Mass (m) = 30 KgAcceleration (a) = 3 m/s²Net force (Fn) =?

Net force = mass × acceleration

Net force = 30 × 3

Net force = 90 N

How to determine the force exerted

Finally, shall obtain the force exerted to the box. This can be obtained as follow:

Net force = 90 NFrictional force = 20 NForce exerted =?

Net force = force exerted - frictional force

90 = force exerted - 20

Collect like terms

Force exerted = 90 + 20

Force exerted = 110 N

This, the force exerted on the box is 110 N

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