4350 g = how many kilograms

1 apple contains a number of times calories = 95

In contrast to functions defined for other values, an arithmetic function is any mathematical function defined for integers (..., 3, 2, 1, 0, 1, 2, 3,...) and relies on the qualities of the integer itself as a number (real numbers, complex numbers, or even other functions)

Based on the given conditions, formulate: 20+6 * x = 590

Rearrange unknown terms to the left side of the equation: 6x = 590 - 20

Calculate the sum or difference:6x = 570

Divide both sides of the equation by the coefficient of variable: x = 570/6

Cross out the common factor: x = 95

get the result: x = 95

1 apple contains a number of times calories = 95.

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Answer:

1.33

Step-by-step explanation:

14÷10 1/2= 1.33

Answer: use a picture math thing

Step-by-step explanation:0.0038 x 105=0.399 so move the decimal point over 1 then it should look like 0.038 x 10.5=0.399 then repeat.

The solutions are;

1. U = {a, d, e, i, l, n, o, p, y}

2. E ∪ I = {a, d, e, i, l, n, o, p, y}

3. E ∩ I = { }

4. J' = {a, d, e, l}

5. I ∪ J = {p, i, n, a, o, y}

6.( J ∩ I ) ∪ E = {d, o, l, e, p, i, n, y}

7. E' = {a, i, n, p, y}

8. I' ∪ J = {d, e, l, o, p, i, n, y}

9. (E ∩ I) ∩ (I ∪ J) = { }

10. (J ∪ I)' = {d, e, l}

What is Union of the set?

Union of two or more set is the set containing all the elements of the given set.

Here, U is the universal set, which is the set of all elements of the three given sets.

And, Three sets are;

⇒ E = {d, o, I, e},     I = {p, i, n, a, y},     J = {p, i, n, o, y}

Now, We find the universal set as;

1. U = {{a, d, e, i, l, n, o, p, y}

2. And, E ∪ I =  {d, o, I, e} ∪ {p, i, n, a, y}

                = {a, d, e, i, l, n, o, p, y}

Hence, E ∪ I = {a, d, e, i, l, n, o, p, y}

3.  E ∩ I =  {d, o, I, e} ∩ {p, i, n, a, y}

Since, It cannot contain any common elements.

So, Intersection of E and I is null set.

Hence, E ∩ I = { }

4. Since, J' = U - J

J' = {a, d, e, i, l, n, o, p, y} - {p, i, n, o, y}

J' = {a, d, e, l}

Hence, J' = {a, d, e, l}

5. I ∪ J = {p, i, n, a, y} ∪ {p, i, n, o, y}

           = {p, i, n, a, o, y}

Hence,  I ∪ J = {p, i, n, a, o, y}

6. ( J ∩ I ) ∪ E = ({p, i, n, o, y} ∩ {p, i, n, a, y}) ∪ {d, o, I, e}

                     = {p, i, n, y} ∪ {d, o, I, e}

                     = {d, o, l, e, p, i, n, y}

Hence, ( J ∩ I ) ∪ E = {d, o, l, e, p, i, n, y}

7.  E' = U - E

       = {a, d, e, i, l, n, o, p, y} - {d, o, I, e}

       = {a, i, n, p, y}

Hence, E' = {a, i, n, p, y}

8.  I' ∪ J = (U - I) ∪ J

            = ( {a, d, e, i, l, n, o, p, y} - {p, i, n, a, y}) ∪ {p, i, n, o, y}

            = {d, e, l, o} ∪ {p, i, n, o, y}

            =  {d, e, l, o, p, i, n, y}

Hence, I' ∪ J = {d, e, l, o, p, i, n, y}

9. (E ∩ I) ∩ (I ∪ J) = ( {d, o, I, e} ∩ {p, i, n, a, y}) ∩ ({p, i, n, a, y} ∪ {p, i, n, o, y})

                          = { } ∩ {p, i, n, a, o, y}

                          = { }

Hence,  (E ∩ I) ∩ (I ∪ J) = { }

10. (J ∪ I)' = U - (J ∪ I)

              = {a, d, e, i, l, n, o, p, y} - ({p, i, n, a, y} ∪ {p, i, n, o, y})

              = {a, d, e, i, l, n, o, p, y} - {p, i, n, a, o, y}

              =  {d, e, l}

Hence,  (J ∪ I)' = {d, e, l}

So, The solutions are;

1. U = {a, d, e, i, l, n, o, p, y}

2. E ∪ I = {a, d, e, i, l, n, o, p, y}

3. E ∩ I = { }

4. J' = {a, d, e, l}

5. I ∪ J = {p, i, n, a, o, y}

6.( J ∩ I ) ∪ E = {d, o, l, e, p, i, n, y}

7. E' = {a, i, n, p, y}

8. I' ∪ J = {d, e, l, o, p, i, n, y}

9. (E ∩ I) ∩ (I ∪ J) = { }

10. (J ∪ I)' = {d, e, l}

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If the expression is log₄ 5x+log₄3x, then the expression in single logarithm form looks like [tex]log_{4} 15x^{2}[/tex].

Given that the expression is log₄ 5x+log₄3x.

We have to express the expression in single logarithm.

Product property of logarithm says that the logarithm of a product is equal to a sum of logarithms. Because logs are exponents which we have to multiply like bases, we can add the exponents.

The expression is log₄ 5x+log₄3x.

log₄ 5x+log₄3x=[tex]log_{4} 15x^{2}[/tex]     (We are not required to change the base)

Hence if the expression is log₄ 5x+log₄3x, then the expression in single logarithm form looks like [tex]log_{4} 15x^{2}[/tex].

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The gymnasts average score is 9.07

The scores are given as

8.9, 9.2, 9.15, 9.03

The gymnasts average score is calculated using'

Average = Sum/Count

So, we have

Average = (8.9 + 9.2 + 9.15 + 9.03)/4

Evaluate

Average = 9.07

Hence, the gymnasts average score is 9.07

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Answer:

Personally, I think it depends on the amount of the product you’re buying. If the product is expensive, you should go the store with a percentage-off discount. If the product is not expensive, you should go to the store with coupon savings.

Step-by-step explanation:

For example, if you’re buying a $5 toy with a $1 coupon and 10% off, you should chose the coupon. Because if you chose the discount, it doesn’t change a lot of things. However, if you’re buying a million dollar airplane(just kidding), then you should definitely chose the discount. Because a million dollar minus 1 changes nothing. But a 10% discount can decrease the cost by 1 hundred thousand! Isn’t that surprising? Hope you understand it.

The error is due to different bases of logarithmic value on both sides.

In, mathematics a logarithmic equation is inverse of exponential equation. That means, we can easily convert the logarithmic equation into exponential equation and vice versa. The basic form of the logarithm function can be written as [tex]log_{a}x[/tex] .

where, a is the base of function or equation

           x = expression

Mathematically, if [tex]a^x = N[/tex] is an exponential function then, this can be converted to logarithmic function as  [tex]log_aN = x[/tex].

There are many formulas that are given to us for solving several simple and complex problems based on logarithmic functions and logarithmic equations.

Some important formulas of logarithms :

In the question,

the error is due to different bases on both the sides.

correct solution is:

[tex]log_2x = 2log_39\\log _2x=log_39^ 2\\log_2x=log_33^4\\log_2x=4log_33\\log_2x=4\\x=16[/tex]

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The complete question is :

Describe and correct the error made in solving the equation.

[tex]log_2x = 2log_39\\log _2x=log_39^ 2\\x=9^2\\x=81[/tex]

Based on the information given, the value of line RT is 36

A line segment can be defined as the part of a straight line bounded by two distinct end point

It also contains every point on the line between its endpoints.

From the information given, we have line PT is a line with segments PR and RT and R is the point between P and T

This can be represented as;

PR + RT = PT

Where;

Substitute into the equation;

3x + 2x + 24 = 54

collect like terms

5x = 54 - 24

5x = 30

Make 'x' the subject of formula

x = 30/ 5

x = 6

But;

RT = 2x + 24

RT = 2(6) + 24

RT = 36

Thus, the value of line RT is 36

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The domain of the expression is all real numbers except where the expression is undefined. In this case, there is no real number that makes the expression undefined.

Interval Notation:

                             ( -∞ , ∞ )

Set-Builder Notation:

                                  { x | x ∈ R }

The range is the set of all valid  y  values. Use the graph to find the range.

Interval Notation:

                               ( -∞ , ∞ )

Set-Builder Notation:

                                 { y | y ∈ R }

Determine the domain and range.

Domain:  ( −∞ , ∞ ), { x | x ∈ R }

Range:  ( −∞ , ∞ ), { y | y ∈ R }

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Answer:

x = -1, y = 1

Step-by-step explanation:

Solve the following system:

{y = 3 x + 4 | (equation 1)

y = x + 2 | (equation 2)

Express the system in standard form:

{-(3 x) + y = 4 | (equation 1)

-x + y = 2 | (equation 2)

Subtract 1/3 × (equation 1) from equation 2:

{-(3 x) + y = 4 | (equation 1)

0 x + (2 y)/3 = 2/3 | (equation 2)

Multiply equation 2 by 3/2:

{-(3 x) + y = 4 | (equation 1)

0 x + y = 1 | (equation 2)

Subtract equation 2 from equation 1:

{-(3 x) + 0 y = 3 | (equation 1)

0 x + y = 1 | (equation 2)

Divide equation 1 by -3:

{x + 0 y = -1 | (equation 1)

0 x + y = 1 | (equation 2)

Collect results:

Answer: {x = -1, y = 1

Answer:

Step-by-step explanation:

If 8 panes cost 1880

then 1 pane cost 1880 divided by 8

1 pane = $ 235

3 pane = $235 x 3

            = $ 705

$1715 + $705 = $ 2420

Answer: The answer is <

Step-by-step explanation:

Really can explain sorry

The scatter plot is shown in attached images and the line of best fit for the data set is y=1.9821x+2.1937.

The given data set is (0,2),(1,4),(2,6.5),(3,8.5),(4,10),(5,12),(6,14).

Plot the points on a coordinate plane.

Calculate the means of the x -values and the y -values.

[tex]\begin{aligned}\bar{X}&=\frac{0+1+2+3+4+5+6}{7}\\ &=\frac{21}{7} \text{ or } 3\\ \bar{Y}&=\frac{2+4+6.5+8.5+10+12+14}{7}\\ &=\frac{57}{7}\text{ or }8.14\end[/tex]

Now, we will calculate the [tex]\sum_{i=1}^{n}(x_{i}-\bar{X})(y_{i}-\bar{Y})[/tex] and [tex]\sum_{i=1}^{n}(x_{i}-\bar{X})^{2}[/tex], we get

[tex]\sum_{i=1}^{n}(x_{i}-\bar{X})^{2}=28[/tex]

and [tex]\sum_{i=1}^{n}(x_{i}-\bar{X})(y_{i}-\bar{Y})=55.5[/tex]

Calculate the slope.

[tex]\begin{aligned}m&=\frac{\sum_{i=1}^{n}(x_{i}-\bar{X})(y_{i}-\bar{Y})}{\sum_{i=1}^{n}(x_{i}-\bar{X})}\\ &=\frac{55.5}{28}\\ &=1.9821\end[/tex]

Calculate the y -intercept.

Use the formula to compute the y -intercept.

[tex]\begin{aligned}b&=\bar{Y}-m\bar{X}\\ &=8.14-(1.9821\times3)\\ &=8.14-5.9463\\ &=2.1937\end[/tex]

Use the slope and y -intercept to form the equation of the line of best fit.

The slope of the line is 1.9821 and the y -intercept is 2.1937 .

Therefore, the equation is y=1.9821x+2.1937 .

Draw the line on the scatter plot.

Hence, the scatter plot is shown in attached image and the line of best fit for given data set (0,2),(1,4),(2,6.5),(3,8.5),(4,10),(5,12),(6,14) is y=1.9821x+2.1937.

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The values for f(x)-2 g(x) = -2x² + 8x - 1

Given :  f(x)=2 x+5

            g(x)=x²-3 x+2

Solution:

            2g(x)=2x²-6x+4

            f(x)-2 g(x) = 2 x+5 - (2x²-6x+4)

            f(x)-2 g(x) = 2 x+5 - 2x² + 6x - 4

            f(x)-2 g(x) = -2x² + 8x - 1

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Question:

Answer:

This is pretty simple, just multiply 9.0 by $13.95, which will give you the answer of $125.55.

* I am not responsible if you get this question wrong, for you are the one who asked the question. *

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If this helped, your welcome! Please know that I might be wrong, and if I am, I am truly sorry for that. But If you would, please make me brainliest.

I hope you have a great rest of your day! If there is an issue with this question, be happy to comment. <3

-niaxfandoms

Harry needs to pay $ 125.55 in total for the 9.0 pizzas he ordered at $ 13.95 each.

To calculate how much Harry needs to pay, multiply the number of pizzas (9.0) by the cost of each pizza ($ 13.95).

Total cost = Number of pizzas × Cost per pizza

Total cost = 9.0 × $ 13.95

To find the product, we can treat 9.0 as a whole number and then multiply:

Total cost = 9 × $ 13.95

Now, calculate the product:

Total cost = $ 125.55

Harry needs to pay $ 125.55 in total for the 9.0 pizzas he ordered at $ 13.95 each.

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Answer:

Simplify

x

=

35.99

dollar

11.33

dollar

.

x

=

3.1765225

Step-by-step explanation:

The expression is completely simplified to give 13√7

Surds are defined as square root values that cannot be further decreases to integers or whole numbers.

Another name for surds are irrational numbers.

Given the surd forms;

5√28 + √63

Now, let's find the factors of the value 28 with perfect squares.

√28 = √4 × 7

The factors of 63 with perfect squares

√63 = √9 × 7

Now, let's substitute the values

5√4 × 7 + √9 × 7

Find the perfect squares

5 × 2√7 + 3√7

Multiply through

10√7 + 3√7

Since the values have common roots, add the coefficient and keep the root the same.

We have;

13√7

Thus, the expression is completely simplified to give 13√7

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Answer:

m∠COD = 83°(I assumed it was somewhere right in-between 80-89 degrees, so I picked 83 as the most logical in between those integers.)

∠COD is an acute angle since it's less than 90°.

I hope this helps you, let me know if you have concerns related to this question and I will help with that.

The geometric mean between -32 and i is given by:

[tex]\sqrt{-32i}[/tex]

The geometric mean between n values is given by the nth root of the multiplication of these values.

For this problem, we have that:

Due to the two values, we take the square root, hence, the geometric mean between -32 and i is given by:

[tex]\sqrt{-32i}[/tex]

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Answer:

58

Step-by-step explanation:

2-2x-3y5

2-2(2)-3(-4)5

-2+60

58

The value of x from the given linear equation x/3-3=x/9+3 is 27.

What is linear equation?

A linear equation is an algebraic equation of the form y=mx+b, where m is the slope and b is the y-intercept, and only a constant and a first-order (linear) term are included.

Given equation

x/3-3=x/9+3

=> x/3-x/9=3+3

=>(3x-x)/9=6

=>2x/9=6

=> x=9*6/2

x=27.

Therefore, the value of x from the given linear equation is 27.

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Answer:

3/4 of the members.

Step-by-step explanation:

4/12 simplifies to 3/4

Answer:1133.5 mm²

Step-by-step explanation:

area= πr² where r is the radius

3.14x19²= 1133.5 mm²

Area of the floor of the bandstand in regular octagon is  1931.2 ft²

dimensions of a square bandstand with the same area as the octagon is 43.94 ft

square bandstand has largest perimeter.

floor has the shape of a regular octagon

Area of a regular octagon = 2a²(1+[tex]\sqrt{2}[/tex])

a = length of the side of the octagon

here a = 20 ft

Area = 2a²(1+[tex]\sqrt{2}[/tex]) = 2(20)(20)(1+[tex]\sqrt{2}[/tex])

                           = 800(1+1.414)

                           = 800(2.414)

                           = 1931.2 ft²

square bandstand with the same area as the octagon

Area of square = b²

b = length of the side of the square

1931.2 = b²

b = 43.94 ft

Perimeter of regular octagon = 8a

                                                = 8(20)

                                                = 160ft

Perimeter of Square = 4b

                                  = 4(43.94)

                                  = 175.78ft

area of the floor of the bandstand in regular octagon is  1931.2 ft²

dimensions of a square bandstand with the same area as the octagon is 43.94 ft

square bandstand has largest perimeter.

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[tex](\stackrel{x_1}{-3}~,~\stackrel{y_1}{-3})\hspace{10em} \stackrel{slope}{m} ~=~ 3 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-3)}=\stackrel{m}{ 3}(x-\stackrel{x_1}{(-3)}) \implies y +3= 3 (x +3) \\\\\\ y+3=3x+9\implies {\LARGE \begin{array}{llll} y=3x+6 \end{array}}[/tex]