50 Points
PLEASE SOLVE THIS :)

Answer:

0.5b + 4 = 2(b + 2)

0.5b + 4 = 2b + 4

0.5b - 2b = 4 - 4

-1.5b = 0

b = 0/-1.5

b = 0

Answer:

Step-by-step explanation:

Answer:

a farmer has 9 1/ 2 ha of land . He needs 11/4 ha for each crops

the no of different crop he can plant is ..

Step-by-step explanation:

Charles is correct as the solution of the mathematical operation (6 + 6) × 6 is also 72 as 12 × 6 = 72.

So, 12 × 6 = 72

Now, let's do what Charles say as follows:
Break 12 as 6 + 6.

Therefore, Charles is correct as the solution of mathematical operation (6 + 6) × 6 is also 72 as 12 × 6 = 72.

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Answer:

I believe its cubic polynomial because it has 3 degrees

Step-by-step explanation:

Answer:

quartic

Step-by-step explanation:

The degree of a polynomial is the highest exponent in the expression. Polynomials are classified by their degree

This polynomial has its highest exponent 4

Therefore the degree of this polynomial is 4

A polynomial with degree 4 is known as a quartic polynomial

Frequency Histogram for the data using a class width of 10 and using 95 as the lower limit of the first class.

A histogram is a bar graph type of data representation in this representation the width of the class size is represented by the rectangle shapes reaching a particular height which describes the the number of frequency distribution.

The girls scouted got their weight recorded. The weights of the girls recorded are 97 120 137 124 117 108 134 126 123 106 130 110 100 120 140.

All the weights are measured in pounds.

The histogram is represented in the x axis and the y axis. The weight of the girls is represented on the y axis. The number of girls is represented on the x axis.

Each girl's weight is represented by a different color to understand the graph easily.

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Macro bought 175 pens

The number of pens Macro bought can be calculated as follows

let x represent the number of pens bought

let y represent the number of pencils bought

x + y = 300.........equation 1

0.25x + 0.15y= 62.50.........equation 2

From equation 1

x + y= 300

x= 300-y

Substitute 300-y for x in equation 2

0.25(300-y) + 0.15y= 62.50

75 - 0.25y + 0.15y= 62.50

75 - 0.1y= 62.50

-0.1y= 62.50-75

0.1y= 12.5

y= 12.5/0.1

y= 125

Substitute 125 for y in equation 1

x + y= 300

x + 125= 300

x= 300-125

x= 175

Hence Marco bought 175 pens

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Another name for a zero sum pair is additive inverse.

A number's cumulative is its inverse number. When a number is multiplied by its cumulative , the sum of both figures equals zero. The straightforward approach is to convert a positive number to a negative number and vice versa. We formerly know that 7(- 7) Equals 0. Accordingly,-7 is the cumulative of 7, and 7 is the cumulative  of-7.

Inverse cumulative Property

When the sum of two real figures is zero, each is said to be the cumulative  of the other.

Inverse Complement of Real figures

A whole number, a natural number, an integer, a bit, a numeric, or any real number can be specified.

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Answer:

[tex]\sf A. \quad -3.5 < -\dfrac{10}{3}[/tex]

Step-by-step explanation:

Convert -3.5 into a fraction:

[tex]\implies \sf -3.5=-\dfrac{35}{10}=-\dfrac{\diagup\!\!\!\!5 \times 7}{\diagup\!\!\!\!5 \times 2}=-\dfrac{7}{2}[/tex]

Rewrite both fractions so that they have the same denominator:

[tex]\implies \sf -\dfrac{7}{2}=-\dfrac{7 \times 3}{2 \times 3}=-\dfrac{21}{6}[/tex]

[tex]\implies \sf -\dfrac{10}{3}=-\dfrac{10 \times 2}{3 \times 2}=-\dfrac{20}{6}[/tex]

[tex]\textsf{As }\: -\dfrac{21}{6} < -\dfrac{20}{6} \textsf{ then}:[/tex]

[tex]\sf \implies -3.5 < -\dfrac{10}{3}[/tex]

Answer:

8a^5 - 28a^4 + 2a^3 +29a^2 + 6a - 9

Step-by-step explanation:

(4a3-5a-3) × (2a2-7a+3)

= 4a^3 × 2a^2 + 4a^3(-7a) + 4a^3 × 3 - 5a × 2a^2 - 5a(-7a) - 5a × 3 - 3 × 2a^2 - 3(-7a) - 3 × 3

= 8a^5 - 28a^4 + 2a^3 +29a^2 + 6a - 9

Answer:

1/2

Step-by-step explanation:

If there are 13 men, then the ratio of men to the total is 13:26. If you simplify that, it would just be 1:2, so for every 2 students in the class, 1 of those students is a man. This would just be half.

In linear equation, The value of the r is a P-q-s.

According to the statement

We have to find that the value of the r .

So, For this purpose, we know that the

The definition of a linear equation is an algebraic equation in which each term has an exponent of one and the graphing of the equation results in a straight line.

From the given information:

The equation is a :

P=q+r+s

This a type of the linear equation then

P=q+r+s

Now, rearrange the terms

P-q-s = r

Then the value of the r is

r = P-q-s .

So, In linear equation, The value of the r is a P-q-s.

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Answer:

Step-by-step explanation: just mutiply 7x3 you get 21

If [tex]x[/tex] is positive, then [tex]\tan^{-1}(x)[/tex] is between 0 and π/2, which means [tex]\cos(\tan^{-1}(x))[/tex] is between 1 and 0.

Let [tex]\theta = \tan^{-1}(x)[/tex]. Then [tex]\tan(\theta) = x[/tex], and it follows from the Pythagorean identity that

[tex]\sin^2(\theta) + \cos^2(\theta) = 1 \implies \tan^2(\theta) + 1 = \sec^2(\theta) \\\\ ~~~~ \implies \sec(\theta) = \sqrt{1 + \tan^2(\theta)} \\\\ ~~~~ \implies \cos(\theta) = \dfrac1{\sqrt{1+\tan^2(\theta)}} \\\\ ~~~~ \implies \cos(\tan^{-1}(x)) = \boxed{\dfrac1{\sqrt{1+x^2}}}[/tex]

We took the positive square root when solving for [tex]\sec(\theta)[/tex] because we know [tex]\cos(\theta)[/tex] is non-negative, between 0 and 1.

a > 4 for which the solutions of the inequality are all real numbers.

It is an expression mathematical that represents a non-equal relationship between a number or another algebraic expression. Therefore, it is common the use following symbols: ≤ (less than or equal to), ≥ (greater than or equal to), < (less than), and > (greater than).

The solutions for inequalities can be given by: a graph in a number line or numbers.

For solving this exercise, it is necessary to find a  for the given inequality.

a(x+3) < 5x+15-x

a(x+3) < 4x +15

ax+3a < 4x+15

Subtract 3a from both sides

ax+3a -3a< 4x+15-3a

ax < 4x+15-3a

ax-4x < 15-3a

x(a-4) < 15-3a

[tex]x < \frac{15-3a}{a-4}[/tex]

Like there is a variable a in the denominator, a-4 >0, then a>4.

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The required solution of the given expression is -9.

A straight line with numbers placed at equal intervals or segments along its length. Number line is a straight line with a "zero" point in the middle, with positive and negative numbers listed on either side of zero and going on indefinitely.

Given:

The given expression is

-2-(+7)

According to given question we have

Number line is a line with 0 in the middle, and then increasing positive numbers to the right of the 0 and decreasing negative numbers to the left of the 0. The line is infinite in length and it's not possible to show the whole line, but we will illustrate where on the line 9 and -9 are located.

-2-(+7)

=-2-7

=-9

Therefore, the required solution of the given expression is -9.

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Answer: DG and EF are parallel. DE=13

Step-by-step explanation:

DG and EF are parallel. They are both right angled triangles.
EF/DG=DE/CD

5/1.25=DE/3.25

4=DE/3.25

4*3.25=DE

13=DE

Approximately 733395 babies were born in the UK in 2018.

Given,

In the UK in 2018 a baby was born every 43 seconds.

We have to find the total number of babies in the UK in 2018.

A baby in every 43 seconds.

There is 3600 seconds in an hour.

There is 24 hours in a day.

In 2018 there were 365 days.

So, the total number of babies born in 2018 in the UK:

= (Seconds in an hour × hours in a day × total days in 2018) ÷ 43

= (3600 × 24 × 365) ÷ 43

= 31536000 ÷ 43

= 733395.3488

≈ 733395

That is, in the UK in 2018 approximately 733395 babies were born.

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Answer:

Step-by-step explanation:

Answer:29

Step-by-step explanation:14 multiplied by 29=406

Answer:

14 x 29 = 406

Step-by-step explanation:

so I believe it's 29

Answer:

38

Step-by-step explanation:

[tex]3x {}^{2} y - x[/tex]

[tex] 3 \times ( - 2) { \\ }^{2} \times 3 - ( - 2)[/tex]

[tex]3 \times 4 \times 3+ 2[/tex]

[tex]36 + 2[/tex]

[tex]38[/tex]

Answer:

0.67

Step-by-step explanation:

Original price = $8.10

New price = $13.50

Increase in price = 13.50−8.10=$5.40

Ratio of the increase in price to the original price = 5.40 8.10=0.67

Answer:

32

Step-by-step explanation:

1-295/2

Answer:

x>22/3 or x<-32/3

Step-by-step explanation:

Step 1 - add 6 to both side

Step 2 - divide both sides by two

Step 3 - Solve Absolute Value

We know either x+ 5/3 >9 or x+5/3<-9

Subtract 5/3 from both sides

Answer:

[tex]\mathrm{a + 4 = |+All~real~numbers|}[/tex] (+∞)

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The probability that the next spin will land on blue or green or purple as a fraction in simplest form is 44/71.

Given that, a spinner is divided into five coloured sections that are not of equal size: red, blue, green, yellow, and purple.

Probability can be defined as the ratio of the number of favourable outcomes to the total number of outcomes of an event. For an experiment having 'n' number of outcomes, the number of favourable outcomes can be denoted by x. The formula to calculate the probability of an event is as follows.

Probability(Event) = Favorable Outcomes/Total Outcomes = x/n

The spinner results are as follows:

Colour        Frequency

Red                  19

Blue                 20

Green               14

Yellow               8

Purple               10

Total number of outcomes = 19+20+14+8+10=71

The probability of getting blue =20/71

The probability of getting green =14/71

The probability of getting purple =10/71

So, the probability of getting blue or green or purple = 20/71 + 14/71 + 10/71

=44/71

Therefore, the probability that the next spin will land on blue or green or purple as a fraction in simplest form is 44/71.

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Answer:

a diamond ♦ it as acute angles

We have the identity

[tex](a + b)^2 = a^2 + 2ab + b^2 = a^2 + ab + b (a + b) \\\\ ~~~~ \implies a + b = \sqrt{a^2 + ab + b (a + b)} \\\\ ~~~~ \implies a + b = \sqrt{a^2 + ab + b \sqrt{a^2 + ab + b \sqrt{a^2 + ab + b \sqrt{\cdots}}}}[/tex]

assuming [tex]a+b\ge0[/tex].

For the numerator, let [tex]b=1[/tex], so [tex]a\ge-1[/tex], which means

[tex]a^2 + a = x \implies a = \dfrac{-1 + \sqrt{1 + 4x}}2[/tex]

and so

[tex]\sqrt{x + \sqrt{x + \sqrt{x + \sqrt{\cdots}}}} = \dfrac{-1 + \sqrt{1 + 4x}}2 + 1 = \dfrac{1 + \sqrt{1 + 4x}}2[/tex]

For the denominator, let [tex]b=-1[/tex] so that [tex]a\ge1[/tex]. Now

[tex]a^2 - a = x \implies a = \dfrac{1 + \sqrt{1 + 4x}}2[/tex]

so that

[tex]\sqrt{x - \sqrt{x - \sqrt{x - \sqrt{\cdots}}}} = \dfrac{1 + \sqrt{1 + 4x}}2 - 1 = \dfrac{-1 + \sqrt{1 + 4x}}2[/tex]

So, in the integral we can simplify and evaluate it to

[tex]\displaystyle \int_0^{2021} \frac{\sqrt{x + \sqrt{x + \sqrt{x + \sqrt{\cdots}}}}}{1 + \sqrt{x - \sqrt{x - \sqrt{x - \sqrt{\cdots}}}}} \, dx \\\\ ~~~~~~~~ = \int_0^{2021} \frac{\frac{1 + \sqrt{1 + 4x}}2}{1 - \frac{1 - \sqrt{1+4x}}2} \, dx \\\\ ~~~~~~~~ = \int_0^{2021} \frac{1 + \sqrt{1 + 4x}}{1 + \sqrt{1 + 4x}} \, dx \\\\ ~~~~~~~~ = \int_0^{2021} dx = \boxed{2021}[/tex]

In this problem you have two unknowns: the weight of a bag of apples and the weight of a bag of oranges.

You have one given equation, which allows you to reduce the number of unknowns by one. This means that you will not be able to tell both the weight of the apples and the oranges, but find a line with possible solutions instead.

e.g. apples weigh 6+2x, oranges 7-3x where x is any real number.

You may narrow the problem down by assuming the weights to be non-negative, but to solve for x you need another piece of information that allows you to eliminate the last unknown.

The algebraic expression of the mathematical statement three more than a number, multiplied by five more than the number is (3 + x) * (5 + x)

The mathematical statement is given as

Three more than a number, multiplied by five more than the number.

Let the number be represented with x.

So, we have the following illustration

Three more than a number, multiplied by five more than the number ⇒ Three more than x, multiplied by five more than x

More than means +

So, we have the following illustration

Three more than a number, multiplied by five more than the number ⇒ 3 + x, multiplied by 5 + x

Multiplied by means *

So, we have the following illustration

Three more than a number, multiplied by five more than the number ⇒ (3 + x) * (5 + x)

Hence, the algebraic expression of the mathematical statement three more than a number, multiplied by five more than the number is (3 + x) * (5 + x)

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Work Shown:

x = number of people in week 3

280/x = 4/3

280*3 = 4*x

x = 280*3/4

x = 210