The tangential velocity is proportional to the length of the rope hence when the length of the rope is doubled, the tangential velocity becomes two times greater.
We know that the tangential velocity of an object moving along a circular path depends on its radius and it's angular velocity.
In this case, we have been told that the motion of the object is uniform meaning that the angular velocity is held constant and the length of the rope which is the radius was doubled.
Since the tangential velocity is directly proportional to the length of the rope, the tangential velocity will be two times greater when the length of the rope is doubled.
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What is the relation between the specific heat capacity of a substance with change
in temperature.
Answer: The heat capacity and the specific heat are related by C=cm or c=C/m. The mass m, specific heat c, change in temperature ΔT, and heat added (or subtracted) Q are related by the equation: Q=mcΔT. Values of specific heat are dependent on the properties and phase of a given substance.
Explanation:
chang wants to build a circuit that will light up a bulb from a flashlight, and has a battery, switch, wire, and a light bulb.
The component that Chang could leave out and still be able to light up the bub is the switch.
What is a switch?The electric circuit refers to a path that is created for the flow of current. We know that current is the movement of electrons. When we connect a circuit, a proper conduit has been set up so that electrons can pass through.
In this case, we have been told that Chang wants to build a circuit that will light up a bulb from a flashlight, and has a battery, switch, wire, and a light bulb.
The component that Chang could leave out and still be able to light up the bub is the switch.
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Missing parts;
Chang wants to build a circuit that will light up the bulb from a flashlight. Which component could Chang leave out and still light up the bulb? the switch the battery the wire the light bulb
Answer:
A) the battery
Explanation:
A moving body has energy due to its motion. This energy is called
Answer:
kinetic energy is the answer
Explanation:
kinetic energy is movement
The image above shows two opposite forces acting on a rope, what can we say is true about the affect of the forces on
the rope?
Answer:
your answer is D
Explanation:
..........
Answer:
d
Explanation:
UsaTestPrep
The sound level at a distance of 3.00m from a source is 120dB. At what distance is the sound level (b) 10.0 dB ?
The sound level at a distance of 3.00m from a source is 120dB at [tex]9.48*10^{5}\;m[/tex] distance is the sound level 10.0 dB
What do you mean by sound level?The RMS (root-mean-squared) of the sound pressure measured and averaged over a given length of time is the sound level in decibels. When measured by contemporary integrating sound level meters, measurements are often A-weighted to coincide with the human reaction; see the time-average sound level definition for more information. These measurements are now commonly referred to as the LA eq. Sound pressure is defined as having a sound level when it is compared to a reference sound pressure of 20 Pa using a standard exponential time weighting and a standard frequency weighting. The ratio of the base ten logarithms to the ratio of the sound level in decibels.
(Lw) = 10·log (W/Wo) dB
Given:
Sound level, [tex]Beta = 120\;dB[/tex]
Sound level, [tex]Beta_{a} = 10\;dB[/tex]
r = 3 m
[tex]P = 4\pi r^{2}I\;\;\;\;------equation(1)[/tex]
We know that,
[tex]\beta = 10 \times log(\frac{I}{I_{o} } )[/tex]
Where, [tex]I_{o}=1 \times 10^{-12}\;W/m^{2}[/tex]
Substitute the known value in the sound level equation,
[tex]10 = 10 \times log(\frac{I_{a} }{1 \times 10^{-12} } )[/tex]
[tex]1 = log(\frac{I_{a}}{1 \times 10^{-12} } )[/tex]
[tex]10= \frac{I_{a}}{1 \times 10^{-12} }[/tex]
[tex]I_{a}= 10 \times 1 \times 10^{-12}[/tex]
[tex]I_{a}=1 \times 10^{-11}\;W/m^{2}[/tex]
[tex]P = 4\pi r_{a} ^{2}x_{123} I_{a} \;\;\;\;------equation(2)[/tex]
equation(1) and (2) are equal,
[tex]4\pi r^{2}I = 4\pi r_{a} ^{2}x_{123} I_{a}[/tex]
Simplify the above equation,
[tex]r_{a} = \sqrt{(\frac{I}{I_{a} } )}\;\;r[/tex]
Substitute the known values in the above equation,
[tex]r_{a} = \sqrt{(\frac{1 \times 10^{-12} }{1 \times 10^{-11} } )}\;\times 3[/tex]
By solving the above equation, We get,
[tex]r_{a} = 9.48 \times 10^{5}\;m[/tex]
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Marvin sells luxury cars at a dealership. He earns a 7% commission on his total weekly sales. This week, Marvin sold a $95,000 Benz and an $80,000 BMW. How much commission did he earn this week?
Answer:
5600 + 6650 = 12250
Explanation:
Technetium-99m is a radioactive isotope commonly used in medicine as a radioactive tracer. A radioactive tracer is an isotope injected into the body to help create images for diagnosis of health
problems. Technetium-99m has a half-life of 6 hours. If a patient receives a dose of technetium-99m one morning, about what percentage of the technetium-99m will be left in the patient's body 12
hours later?
A
6.25%
B
12.5%
С
25.0%
D
93.8%
Answer:
C. 25.0%
Explanation:
Radioactive decay of an atom follows the equation:
ln[A] = -kt + ln[A]₀
Where [A] could be taken as an amount of radioactive atom after time t,
k is rate constant = ln 2 / Half-Life = ln 2 / 6hours = 0.1155hours⁻¹
[A]₀ is initial amount of the isotope = 100%
Replacing:
ln[A] = -0.1155hours⁻¹ *12hours+ ln[100%]
ln[A] = 3.2192
[A] = 25.0%
Right solution is:
C. 25.0%
Q|C A bat, moving at 5.00 m/s , is chasing a flying insect. If the bat emits a 40.0 -kHz chirp and receives back an echo at 40.4 kHz , (b) Will the bat be able to catch the insect? Explain.
The bat's observation of the echo's frequency is 41.2 kHz
A bat flies speedily in this problem [tex]$$v_{\text {bat }}=5.0 \mathrm{~m} / \mathrm{s}$$[/tex] .
It makes a frequency chirp [tex]$$f_S=40 \mathrm{kHz}=4.0 \times$$10^{4} Hz.[/tex]
An adjacent wall reflects the sound. We determine the echo's frequency based on the bat's observations.
(b) Sound propagates at a speed of [tex]v=345 \mathrm{~m} / \mathrm{s}[/tex]
The sound will undergo two Doppler shifts. The first Doppler change occurs when the sound travels toward the wall, and the second Doppler shift occurs as the sound returns to the bat.
[tex]\begin{aligned}f_{O, 1} &=f_S\left(\frac{v+v_O}{v-v_S}\right) \\&=f_S\left(\frac{v+0}{v-\left(+v_{\mathrm{bat}}\right)}\right) \\f_{O, 1} &=f_S\left(\frac{v}{v-v_{\mathrm{bat}}}\right)\end{aligned}[/tex]
The moving bat, which moves in the direction of the source, serves as the observer in the second Doppler shift. The wall that isn't moving is the source. The bat's frequency observations must be
[tex]\begin{aligned}f_{\text {echo }} &=f_{O, 1}\left(\frac{v+v_O}{v-v_S}\right) \\&=f_{O, 1}\left(\frac{v+\left(+v_{\text {bat }}\right)}{v-0}\right) \\&=f_{O, 1}\left(\frac{v+v_{\text {bat }}}{v}\right) \\&=f_S\left(\frac{v}{v-v_{\mathrm{bat}}}\right)\left(\frac{v+v_{\text {bat }}}{v}\right) \\\Rightarrow f_{\text {echo }} &=f_S\left(\frac{v+v_{\mathrm{bat}}}{v-v_{\mathrm{bat}}}\right)\end{aligned}[/tex]
By substituting values in the equation, we get
[tex]\begin{aligned}f_{\text {echo }} &=f_S\left(\frac{v+v_{\text {bat }}}{v-v_{\text {bat }}}\right) \\&=\left(4.0 \times 10^4 \mathrm{~Hz}\right)\left(\frac{345+5.0}{345-5.0}\right) \\&=4.11765 \times 10^4 \mathrm{~Hz} \\f_{\text {echo }} &=41.2 \mathrm{kHz}\end{aligned}[/tex]
Hence, The bat's observation of the echo's frequency is 41.2 kHz.
Is the frequency of echo high?Ultrasound, which has frequencies above human hearing, is used in echocardiography. Pressure waves take the form of sound waves, which can go through any material.
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A reconnaissance plane flies 629 km away
from its base at 218 m/s, then flies back to its
base at 327 m/s.
What is its average speed?
Answer in units of m/s.
Answer
5. Whether you are standing, running or jumping Earth is exerting a gravitational force on you. This gravitational force is called an object's weight (W). Knowing this you can find the weight of an object if you know the mass because the acceleration will be 9.8 m/s2 due to gravities pull on the object. The equation to use then is: W = mass x acceleration. What is the weight of a 53 kg man?
Answer:
How we know, the equation is:
W = mg
Replacing according our data:
W = 53 kg × 9,8 m/s^2
Resolving:
W = 519,4 N
The weight of the object is of 519,4 Newtons.
Object A has a mass of 100 kg, and Object B has a mass of 75 kg. Both objects are resting motionless on the ground.
Which statement describes the objects’ inertias?
Object A has a greater inertia than Object B.
Object B has a greater inertia than Object A.
Both objects have the same inertias.
Both objects have zero inertia.
The statement that describes the objects’ inertias is "Object A has a greater inertia than Object B.
What is Newton's first law of motion?
Newton's first law of motion, states that if a body is at rest or moving at a constant speed in a straight line, it will remain at rest or keep moving in a straight line at constant speed unless it is acted upon by a force.
This law is also called the law of inertia because it depends on mass of the object.
The greater the mass of an object, the more reluctant it will be to move.
Thus, the statement that describes the objects’ inertias is "Object A has a greater inertia than Object B.
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A wire is formed into a circle having a diameter of 10.0cm and is placed in a uniform magnetic field of 3.00mT . The wire carries a current of 5.00 A. Find (b) the range of potential energies of the wire-field system for different orientations of the circle.
The range of potential energies of the wire-field system for different orientations of the circle are -
θ U
0° 375 π x [tex]10^{-7}[/tex]
90° 0
180° - 375 π x [tex]10^{-7}[/tex]
We have current carrying wire in a form of a circle placed in a uniform magnetic field.
We have to the range of potential energies of the wire-field system for different orientations of the circle.
What is the formula to calculate the Magnetic Potential Energy?The formula to calculate the magnetic potential energy is -
U = M.B = MB cos [tex]$\theta[/tex]
where -
M is the Dipole Moment.
B is the Magnetic Field Intensity.
According to the question, we have -
U = M.B = MB cos [tex]$\theta[/tex]
We can write M = IA (I is current and A is cross sectional Area)
U = IAB cos [tex]$\theta[/tex]
U = Iπ[tex]r^{2}[/tex]B cos [tex]$\theta[/tex]
For [tex]$\theta[/tex] = 0° →
U(Max) = MB cos(0) = MB = Iπ[tex]r^{2}[/tex]B = 5 × π × [tex]( 0.05 ) ^{2}[/tex] × 3 × [tex]10^{-3}[/tex] =
375 π x [tex]10^{-7}[/tex].
For [tex]$\theta[/tex] = 90° →
U = MB cos (90) = 0
For [tex]$\theta[/tex] = 180° →
U(Min) = MB cos(0) = - MB = - Iπ[tex]r^{2}[/tex]B = - 5 × π × [tex]( 0.05 ) ^{2}[/tex] × 3 × [tex]10^{-3}[/tex] =
- 375 π x [tex]10^{-7}[/tex].
Hence, the range of potential energies of the wire-field system for different orientations of the circle are -
θ U
0° 375 π x [tex]10^{-7}[/tex]
90° 0
180° - 375 π x [tex]10^{-7}[/tex]
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what is the electric force on a due to b in component form? express your answer in terms of the unit vectors i^ and j^ . use the 'unit vector' button to denote unit vectors in your answer.
The electric force on a due to b in component form = [tex]\bold{0\vec i+72\times10^{-9}\vec j\ N}[/tex]
Charge of A = 4 nC = [tex]4\times 10^{-9}[/tex] C
Charge of B = -8 nC = [tex]-8\times 10^{-9}[/tex] C
A is on the origin, (0,0) and B is at the point (0 cm,2cm).
Therefore, distance between charges A and B, r = [tex]\sqrt{(0-0^2)+(0-2)^2} =2[/tex]
Using Coulomb's law, the electric force is directly proportional to the product of charges and inversely proportional to the square of distance between charges.
i.e., [tex]F_{A\ on\ B}=\frac{kq_1q_2}{r^2}[/tex], where k = [tex]9\times 10^9 Nm^2C^{-2}[/tex], the Coulomb constant.
So [tex]F_{A\ on\ B}=\frac{9\times 10^9\times 4\times 10^{-9}\times 8\times 10^{-9}}{2^2} = \bold{72\times 10^{-9} N}[/tex]
Since there is no x-component for this force,
the electric force on a due to b in component form = [tex]\bold{0\vec i+72\times10^{-9}\vec j\ N}[/tex]
The question incomplete. Find the complete question here:
Object A, which has been charged to +4.0 nC is at the origin. Object B, which has been charged to -8.0 nC, is at (x, y)=(0.0 cm, 2.0 cm). What is the electric force on A due to B in component form? Express your answer in terms of the unit vectors i and j. Use the 'unit vector button to denote unit vectors in your answer.
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On a very cold day in upstate New York, the temperature is -25°C , which is equivalent to what Fahrenheit temperature? (a) -46°F (b) -77°F(c) 18°F(d) -25°F(e) -13°F
Considering the conversion between Celsius degree and Fahrenheit degree, the correct answer is option (e): -25°C is equivalent to -13 Fahrenheit temperature.
Celsius degree
The Celsius degree, represented as °C, is the unit created by Anders Celsius. This scale is also called the "Centigrade scale" and in it the temperature is divided into 100 degrees, with 0º C being the freezing point of water and 100º C the boiling point of water.
Fahrenheit degreeThe Fahrenheit degree is the unit of temperature proposed by Gabriel Fahrenheit in 1724, whose scale sets zero and one hundred in the freezing and evaporation temperatures of ammonium chloride in water. On this temperature scale, unlike the Celsius scale, the freezing point of water is 32º F while the boiling point of water is 212º F.
Conversion of Celsius degree to Fahrenheit degreeTo perform the conversion, the expression must be applied:
°F= °C× 9/5 + 32
Temperature in this caseOn a very cold day in upstate New York, the temperature is -25°C. Fahrenheit temperature is calculated as:
°F= (-25°C)× 9/5 + 32
Solving:
°F= -13
In summary, the correct answer is option (e): -25°C is equivalent to -13 Fahrenheit temperature.
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Which of the following is not a component of a normal experiment?
A. Control group
OB. Dependent variable
C. Independent variable
D. Validity group
Reset Selection
Answer:
D. Validity group
Explanation:
A validity group is not necessarily a component of a normal experiment.
A normal experiment is made up of the dependent variables, independent variables, and most times the control group.
The dependent variable is one that relies on the outcome of the effect produced from the experimental designThe independent variable is the one that causes a desired effect under the study. The control group is a group that does not receive any treatment nor attenuation of the conditions.This is when one person is guiding another
Oxygen, modeled as an ideal gas, is in a container and has a temperature of 77.0°C. What is the rms-average magnitude of the momentum of the gas molecules in the container?
The oxygen gas has root mean square velocity of 1651.67 m/s.
What is specific heat capacity ?
Scientifically, specific heat capacity is the quantity of heat (J) absorbed by a material when its temperature increases 1 K (or 1 °C) per unit mass, expressed as J/(kg K) or J/(kg °C).
Q = mCΔT
Calculation of temperature of oxygen gas is done below using formulae :
V(rms) = √3RT/M
where;
M is molar mass of oxygen gas = 32 g/mol = 0.032 kg/mol
value of gas constant R = 8.314 J/K.mol
T is temperature of the oxygen gas = 77+273 = 350 k
V(rms) = √3RT/M
V(rms) = √(3x8.314x350)/0.032
V(rms) = √87297/0.032
V(rms) = √2728031.25
V(rms) = 1651.67 m/s
Thus, The oxygen gas has root mean square velocity of 1651.67 m/s.
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Please answer the pictures below in sequential order, (there's more than 1) I'd really appreciate it. Happy holidays guys!
Answer:
happy holidays
Explanation:
Owen and Dina are at rest in frame S' , which is moving at 0.600 c with respect to frame S . They play a game of catch while Ed , at rest in frame S , watches the action (Fig. P39.75). Owen throws the ball to Dina at 0.800 c (according to Owen), and their separation (measured in S' ) is equal to 1.80 × 10¹²m .(b) According to Dina, what time interval is required for the ball to reach her? According to Ed.
The total time taken by the ball to reach Dina is 7.5 × 10³ s.
A frame of reference is a set of reference points—geometric points whose positions are known mathematically and physically—that define the origin, orientation, and scale of an abstract coordinate system.
If a body does not continuously adjust its position in relation to its environment throughout the course of time, it is said to be at rest.
In the frame S', Dina and Owen are at rest.
The speed of the ball with respect to Owen, u =0.800c
The speed of the frame S' with respect to frame S, v = 0.600c
Distance between Dina and Owen, L(p) = 1.8 × 10¹² m
Speed of light, c = 3 × 10⁸ m/s
Therefore, the ball reaches Dina in time:
t = L(p) / u
t = 1.8 × 10¹² m / 0.8c
t = 1.8 × 10¹² m /(0.8)(3 × 10⁸ m/s)
t = 7.5 × 10³ s
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What are the two forces that act on the orbit of a planet?
A) Velocity of planet and gravity between sun and planet.
B) Gravity between the aphelion and perihelion.
C) Gravity between planet and sun and the velocity of the sun.
D) Orbits of other planets and gravity between sun and planet.
HELP PLEASE!
The two forces that act on the orbit of a planet are velocity of planet and gravity between sun and planet.
What is gravity?The force that pulls items toward the center of a planet or other entity is called gravity. All of the planets are kept in orbit around the sun by gravity. Gravity applies to everything that has mass. Gravity is stronger for objects with higher mass. Along with distance, gravity weakens as well. Therefore, the gravitational pull of two things becomes stronger the closer they are to one another.
The mass of the Earth is what creates gravity. The combined gravitational force of all of its mass acts on the mass in your body.
Velocity of the planet is also related to its gravity.
Forces that acts on the orbit of a planet is force due to velocity and gravity.
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how does the thickness of wood affect its stability
Answer:
Making the lumber thick will make it stiff, which seems good. On the other hand, with thicker lumber, differences in expansion on the two faces have more leverage to make the lumber move.
If an object is not moving, the forces acting upon it are...
A.Balanced
B. Weak
C.Unbalanced
D.Hulk SMASH!
Why is copper particularly useful in electrical circuits?
a very good conductor of heat
support burning
very reactive metal
What provides The energy needed to fill the water cycle
Answer:
The water cycles energy source comes from the sun
Explanation:
The sun's solar energy helps evaporate water from several bodies of water which causes the process of transportation
Please help me on my test :) thank uu
An insulated copper wire is wrapped around an iron nail and connected to a power
source (battery). When the circuit is closed, the nail can attract and pick up paper clips,
but when the circuit is open, the nail does not attract the paper clips. Which of the
following explanations best describes this phenomenon?
A When the circuit is open, it creates a current, and a magnetic field is induced.
B When the circuit is closed, there is neither a current nor a magnetic field.
C When the circuit is closed, it creates a current, and a magnetic field is induced.
D When the circuit is open, there is a current but no magnetic field.
Answer:
d
Explanation:
because ik igvddhh56yfdsaw66 u77rfgtd gyy f music nutren
Two motorcycles start at the same point. One motorcycle travels 15 km due north and stops. The second motorcycle travels 32 km due west and stops. Which value is closest to the distance between the motorcycles when they stop?.
Two motorcycles start at the same point, one motorcycle travels 15 km due north and stops, the second motorcycle travels 32 km due west and stops, value closest to the distance between the motorcycles when they stop is 35.3 km.
What is Meant by Kilometers to Miles?In general, kilometers to miles is the conversion of distance from the kilometers to miles. kilometers and miles are used to measure length from one point to the other. In metric system, kilometer is the unit of length and it is considered as the International System of Units, whereas miles are used in the imperial and US customary units. The kilometer is abbreviated as “km”, and mile is abbreviated as “mi”. These two measures are mostly used to measure the geographical land areas.
You are aware that hypotenuse of a right triangle is shorter than the total of the legs and longer than the longest leg.
The relevant distance in this geometry is greater than the 32 km and less than 15+32 = 47 km. The only option that falls within acceptable range is 35.3 kilometers.
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Which statements describe a situation in which work is being done? Check all that apply.
Convert 93 nanometer to meters.
Answer:
9.3e-8 Meters
A net force is acting on an object. The object is moving in a
straight line under the effect of this force. If the net force
acting on the object is doubled, how will this affect the
object?
Answer:
The object's velocity would increase due to the change in force.
Explanation:
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