8. (01.05 MC)
Which of the following equations represents the greatest value of x? (5 points)
Equation 1 Equation 2 Equation 3 Equation 4
x2 = 35 x3 = 64 = 125 x2 = 38
x3 =
Equation 1
Equation 2
Equation 3
Equation 4

Answer:

Step-by-step explanation:

No matter what the value of y is, x = 2. That's exactly what the answer is.

The line is vertical and the equation is x = 2.

Answer: y = 11

Step-by-step explanation:

first, i collected the like terms.

7y + 9 = 4y + 42

then, i moved the terms.

7y - 4y + 42 - 9

then, i collected the like terms and calculated it.

3y - 33

finally, i divided both sides.

y = 11

Answer:

y = 11

Step-by-step explanation:

-5y + 12y + 9 = 4y + 42

Add like terms on the left side, -5y + 12y.

7y + 9 = 4y + 42

Subtract 4y from both sides.

3y + 9 = 42

Subtract 9 from both sides.

3y = 33

Divide both sides by 3.

y = 11

Answer:

mali aaudina so sorry and again please don't asked me

Answer:

The slope of line q is -7/6

Step-by-step explanation:

To find the slope of a perpendicular line, you need to find the opposite reciprocal. So, flip the fraction (7/6) and then take the opposite, (-7/6).

Hope this helps!

Answer:

By an online search, i found that the table is:

x = 0°       30°         60°    90°    120°      150°       180°

y= 10     4+3*√3        7       4       1        4 -3*√3      -2

Where x is in degrees.

And we want to find the value of y, when x = 45°.

And our equation is:

y = a*cos(x) + b

Notice that we have two variables in our equation, a and b, then we need to choose two of the points in the table to write equations.

I will choose te points

x = 0°, y = 10

and

x = 90°, y = 4

Now we can replace these values in the equatio to get:

10 = a*cos(0°) + b

4 = a*cos(90°) + b

We know that:

cos(0°) = 1

cos(90°) = 0

(because of those relationships is that i choosen these points)

Replacing that in the equations, we get:

10 = a*1 + b = a + b

4 = a*0 + b = b

From the second equation, we get:

b = 4

Now we can replace this in the first equation to get:

10 = a + b = a + 4

10 - 4 = a = 6

Then our equation is:

y = 6*cos(x) + 4.

Now we want to find the value of y when x = 45, to do it, we just replace the value of x in that equation:

y = 6*cos(45°) + 4 = 6*(√2/2) + 4 = 8.24

Answer:

2x^2 - 4

Step-by-step explanation:

- A "constant" in an equation is a number that stands alone, with no attached variable or exponents.

- A "coefficient" is a number placed before a variable that is multiplying with the variable. For example, 2 would be the coefficient of 2xy, because it is the number you are multiplying "xy" by.

Answer:

8x+10y cannot be simlified because they do not have a common variable

so until you find the value for x and y u cannot simplify

Answer:8 x+ 10 y can not be simplified .

Step-by-step explanation:

Explanation:This is because the term are not the same.8x has the term x while 10 y has the term y.

Answer:

1,420,236

Step-by-step explanation:

According to the problem, computation of the given data are as follows,

Total number of applicants = 35,505,900

Applicants admitted = 4% of total number of applicants

So, Number of successful applicants = Applicant admitted percent × Total number of applicant

By putting the value, we get

Number of successful applicants = 35,505,900 × 4%

= 1,420,236

Answer:

4

Step-by-step explanation:

The computation is shown below:

Given that

There are total number of students i.e. 48

The ratio at present is 4:1

Now the computer needed to make the ratio be 3:1

So let us assume the number of students be 4x

And, the number of computers be x

So the 4x = 48

x = 12

So the computer be 12

Now the new ratio is 3:1

Students be 3x

And, computers be x

So

3x = 48

x = 16

Now the more computer needed is

= 16 - 12

= 4

hence, this is the answer but the same is not provided in the given options

Mrs. Mitra needs to buy 4 more computers to make the ratio 3: 1

The present total number of students = 48

Ratio of the number of students to the number of computers = 4: 1

(Number of students) / (Number of computers) = 4/1

48 /  (Number of computers) =  4/1

Number of computers = 48/4

Number of computers = 12

If the ratio of the number of students to the number of computers = 3:1

48 / (Number of computers) = 3/1

3(Number of computers) = 48

Number of computers = 48/3

Number of computers = 16

Additional number of computers = 16 - 12

Additional number of computers = 4

Mrs. Mitra needs to buy 4 more computers to make the ratio 3: 1

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Answer:

183.6 miles

Step-by-step explanation:

Kindly check the picture attached for the solution diagram

Using the cosine formula (Diagram has two sides and an included angle)

x² = y² + z² - 2zy * cosX

x² = 150² + 60² - 2(150*60) * cos115

x² = 22500 + 3600 - 18000 * −0.422618

x² = 22500 + 3600 + 7607.1287

x² = 33707.128 miles

x = √33707.128

x = 183.59501

x = 183.6 miles

Answer:

D

Step-by-step explanation:

183.60

Answer:

21 cats

Step-by-step explanation:

98/14=7   7x3=21

Answer:

21 cats

Step-by-step explanation:

98/14=7

7 times 3=21

Answer:

[tex] \frac{ {(x + 1)}^{2} }{ {(x - 2)}^{3} } [/tex]

Answer:

X angle

Step-by-step explanation:

The number of paper newsletters the school needed is given by the equation A = 149.5

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

Given data ,

Let the number of paper newsletters the school needed be A

Now , the equation will be

The percentage of parents who prefers newsletters electronically = 77 %

So , percentage of parents who prefers paper newsletters = 100 % - 77 %

The percentage of parents who prefers paper newsletters = 23 %

The total number of parents = 650

So , the number of paper newsletters the school A = percentage of parents who prefers paper newsletters x total number of parents

Substituting the values in the equation , we get

The number of paper newsletters the school A = ( 23/100 ) x 650

The number of paper newsletters the school A = 149.5

Therefore , the value of A is 149.5

Hence , the equation is A = 149.5

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Answer: 75 + 25(3)

Step-by-step explanation:

From the question, we are informed that Trey has 75 in his saving account and that each month he deposits 25 into the account.

The expression that shows the amount of money that Trey deposits in 3 months would be:

= 75 + 25m

where, m = number of months

= 75 + 25(3)

= 75 + 75

= 150

Answer:

8.) u=12.37

16.) p=75

17.) m=52

18.) n=112

Step-by-step explanation:

u-2.07=10.3

u=12.37

5=p/15

p=75

m/26=2

m=52

n/16=7

n=112

Answer:

3.

Step-by-step explanation:

- / - = +

-39 / -13

= 3

Answer:

84-24%=63.84

Step-by-step explanation:

Answer: 2827 cm squared is the answer

Answer:

8x

Step-by-step explanation:

Answer:

I think it is 8x

Step-by-step explanation:

Hope this helped have an amazing day/month/year!

Answer:

$0.50/pounds

Step-by-step explanation:

5 pounds= 2.49

1 pound = $2.29 ÷ 5 = $0.50 (nearest hundredth)

Answer:

13 students per row

13 rows total

(169\13=13)

Answer:  B. [tex]\dfrac{23520}{32928}[/tex]

Step-by-step explanation:

Let A = Event that species of fish comes from the Pacific Ocean .

B =  Event that species of fish comes from world's three largest oceans.

To find : P(A |B)

Formula : [tex]P(A|B)=\dfrac{P(A\cap B)}{P(B)}[/tex]

Here,

[tex]P(B)=\dfrac{32928}{33600}\ \ \ [Probability =\dfrac{favourable\ outcomes}{Total outcomes}][/tex]

[tex]P(A\cap B)=\dfrac{23520}{33600}[/tex]

[tex]P(A|B)=\dfrac{\dfrac{23520}{33600}}{\dfrac{32928}{33600}}=\dfrac{23520}{32928}[/tex]

Correct option : B. [tex]\dfrac{23520}{32928}[/tex]

Answer:

B.

Step-by-step explanation:

geometry b final exam

Answer:

  [tex]\sqrt{\frac{2x^{5} }{18} }[/tex]   = [tex]\frac{\sqrt{x^{5} } }{3}[/tex]

Step-by-step explanation:

Given expression

            [tex]\sqrt{\frac{2x^{5} }{18} }[/tex]

we know that the algebra formula

[tex]\sqrt{\frac{a}{b} } = \frac{\sqrt{a} }{\sqrt{b} }[/tex]

[tex]\sqrt{\frac{2x^{5} }{18} } = \frac{\sqrt{2} \sqrt{x^{5} } }{\sqrt{18} } = \frac{\sqrt{2} \sqrt{x^{5} } }{\sqrt{9} \sqrt{2} }[/tex]

          = [tex]\frac{\sqrt{x^{5} } }{3}[/tex]

Answer A

Step-by-step explanation:

The solution is, <a and <d; <b and <c, these two sets of angles are corresponding angles. of the triangles. So, correct answer is A. <a and <d; <b and <c.

Here, we have,

When two triangles are said to be similar, the ratio of the corresponding sides of both triangles is always the same, also, their corresponding angles are congruent. That is, they are equal.

The 2 set of angles that are corresponding angles of the two similar triangles given in the question above are:

<a and <d; <b and <c.

Both set of angles are congruent to each other. In other words, they are equal.

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