A 0.7500 cm diameter plastic sphere, used in a static electricity demonstra-tion, has a uniformly distributed 60.0 pc charge on its surface. what is the potentialnear its surface?

D. The slope of the line is equal to zero and the object will be in motion.

Velocity of a body is said to be constant, if it covers equal distances in equal intervals of time, and also does not change the direction it is moving in

To have a constant velocity, an object must have a constant speed in a constant direction.

slope = change in velocity / change in time

if the velocity is constant, then change in velocity = 0

slope = 0/change in time = 0

In constant velocity, the object will be in motion, but the velocity of the object will not change.

Thus, the slope of the line is equal to zero and the object will be in motion.

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Hello! Lets begin!

1. Which answer best describes displacement?

2. Kelley is playing pool and hits the cue into the nine ball, which is directly in the center of the pool table. The nine ball travels a total of 7 meters before stopping, 1 meter to the left of the initial starting point of the nine ball. Which sentence reflects the correct statement regarding distance and displacement when considering the motion of the nine ball?

3. What is velocity?

4. Imagine a time-position graph where the velocity of an object is constant. What will be observed on the graph concerning the slope of the line segment as well as the velocity of the object?

5. Select the option that best summarizes the reason for the use of position-time graphs when studying physical science.

_______________________________________________________

Good luck my peeps! ;D

The power supplied by the gravitational force will increase because (Power=work/time).

A falling object gains momentum as it descends.

An increase in air resistance is caused by a speed increase.

At some point, the force of air resistance grows strong enough to counteract the pull of gravity.

Since there is no net force at this point, the object will stop accelerating.

Although the direction and magnitude of velocity fluctuate, the acceleration caused by gravity remains constant and downward.

The ball has zero velocity at the highest point in its trajectory, and it picks up speed as it descends back toward the earth.

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The density of the neutron star is  ρ = [tex]7.733[/tex]×[tex]10^{14}[/tex] [tex]g/cm^{3}[/tex].

The volume of the neutron star is

V=([tex]4\pi /3[/tex])×[tex]R^{3}[/tex]

V= [tex]25.72^{17} cm^{3}[/tex]

Now the density of the neutron star is

ρ = M/V

ρ =  [tex]7.733[/tex]×[tex]10^{14}[/tex]g/[tex]cm^{3}[/tex]

The collapsing core of a large supergiant star with a total mass of between 10 and 25 solar masses—possibly even more if the star was very metal-rich—is what we refer to as a neutron star. Neutron stars are the tiniest and densest class of stellar objects currently known, with the exception of black holes and other hypothetical phenomena.

Although the galaxy may contain hundreds of millions of ancient neutron stars, only about 1,000 pulsars are known to exist. Although the enormous pressures found at neutron star cores may be similar to those at the moment of the big bang, conditions like this cannot be replicated on Earth.

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11 m

Explanation:

d = 1/2 a t^2

  = 1/2 (9.81)(1.5)^2 =11 m

[tex] \large \bf \implies{s = 200 \: m}[/tex]

A. The force of gravity causes the coin to change its velocity.

Force of gravity always act toward the center of the earth , so when an object is thrown up, the force of gravity will act in opposite direction of motion, that's toward the center of earth.

This will cause the object moving upwards to slow down due to the force of gravity acting on the opposite direction of the object's upward motion.

When a coin is tossed in the air, it travels upward, gradually slows down, momentarily reaches zero speed, then moves back downward with increasing speed due to effect of force of gravity.

Thus, the statement that best explains the change in the coin's motion is "The force of gravity causes the coin to change its velocity".

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Dilution is needed to bring the unknown’s absorbance within the range of the standard curve.

If the dilution procedure is documented, it is possible to calculate the full-strength concentration after determining the diluted unknown quantity. Beer’s Law only applies to diluted solutions; hence it is preferable to dilute the unknown than to create new standards.

Spectrophotometers gauge transmittance (T) and absorbance (A) (T). Photons per second are used to quantify the light’s intensity. A blank sample, which does not absorb light when light passes through it, is represented as (I).

The principle of the spectrometer. The spectrophotometer is a device that calculates how much light a substance absorbs.

The spectrophotometer measures the light intensity of a sample by passing a light beam through it.

A spectrophotometer is a device that counts the number of photons (light’s energy) absorbed after they have passed through a sample solution.

The spectrophotometer can also be used to determine the concentrations (amounts) of known chemical substances.

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The reaction force is string pulling on the Nellie when a tether ball in a horizontal circular path over her head .

A reaction force is a force that acts in the opposite direction to an action force. i.e. Newton's third law of motion describes action and reaction forces and the law states that for every action force, there is an equal and opposite reaction force.

There are Newton's three law of motion which can be describe as ,

The first law is can be stated as, an object will not change its motion unless a external force acts on it.

The second law is describe as, the force on an object is equal to its mass times its acceleration. i.e.

F = ma

In above equation F is force , m is mass and a is acceleration on an object.

The third law can be explained as, when two objects interact, they apply forces to each other of equal magnitude and opposite direction.

Therefore , from the above discussion can be said as Nellie whirls a tether ball in a horizontal circulars path over her head. if the action force is nellie pulling on the string, the reaction force is string pulling on the Nellie.

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The speed of the elevator, given that it travels a distance of 210 m in 35 s is 6 m/s

The formula for calculating the speed of an object is given as follow:

Speed = distance / time

Considering the question given above, we can obtain the speed of the elevator as follow:

Speed = distance / time

Speed = 210 / 35

Speed = 6 m/s

From the calculation made above, we can see that the speed of the elevator is 6 m/s

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Answer:

You grab (grasp or seize suddenly and roughly.) the pizza with your toes

Explanation:

Answer:

First, you have to wash your toes to get all the germs off.

Next, make sure you have a good grip on the pizza.

Then, make sure you are in a comfortable position.

Next, wrap your leg around your neck so the pizza can reach.

Finally, you can enjoy your pizza.

Hope this helped!

Answer:Transverse waves cause the medium to move perpendicular to the direction of the wave.

Explanation:

In a transverse wave, particles of the medium vibrate up and down perpendicular to the direction of the wave. In a longitudinal wave, particles of the medium vibrate back and forth parallel to the direction of the wave.

The voltage across the resistor is 0.2V.

Heat energy is given as H = [tex]I^{2}[/tex]Rt.

Voltage across the resistor is

V= 0.2v

12 = [tex]0.02^{2}[/tex]×R×60

R= 500 ohms.

voltage across the resistor is

V=IR

V=   0.02^{2} ×500

V= 0.2V

A resistor is an electrical component with two terminals that implements electrical resistance as a circuit element. Resistors are employed in electronic circuits for a variety of purposes, including lowering current flow, adjusting signal levels, dividing voltages, biasing active devices, and terminating transmission lines.

An electrical component known as a resistor controls or restricts the passage of electrical current in an electronic circuit. Additionally, resistors can be used to supply a specified voltage to an active device like a transistor.

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Explanation:

Throughout this question, we will be taking the position at which the package is dropped as the origin.

We know that the package lands 100 m from the initial position. We have to investigate the position in the horizontal direction.

To do that, let's first calculate the time of flight of the package.

Here is what we know about the vertical motion taking the downward direction as the positive direction:

the vertical displacement is

s

=

100

m

.

the acceleration is

a

=

g

=

9.81

m

/

s

2

.

the initial velocity of the package is

u

=

0

m

/

s

.

By using an equation that connects the details that we have with the time of flight

t

, we get the time of flight as follows:

s

=

u

t

+

1

2

a

t

2

s

=

0

+

0.5

a

t

2

Make

t

the subject

0.5

a

t

2

=

s

t

2

=

s

0.5

a

t

=

√

s

0.5

a

=

√

100

m

0.5

(

9.81

m

/

s

2

)

≈

4.52

s

The horizontal displacement

x

equals the product of the horizontal velocity

v

x

=

40.0

m

/

s

and the time of flight

t

=

4.52

s

, i.e.

x

=

v

x

t

=

40.0

m

/

s

(

4.52

s

)

≈

181

m

The package will strike the ground at

(

181

m

;

−

100

m

)

.

Part b)

The horizontal component of the velocity is constant throughout the flight and is

v

x

=

40.0

m

/

s

.

For the downward motion, here is what we know:

the vertical displacement is

s

=

100

m

.

the acceleration is

a

=

g

=

9.81

m

/

s

2

.

the initial velocity of the package is

u

=

0

m

/

s

.

By applying an equation that combines the details that we have with the final instantaneous velocity

v

=

v

y

, we get the final instantaneous velocity as follows:

v

2

=

u

2

+

2

a

s

v

=

√

u

2

+

2

a

s

v

y

=

√

(

0

m

/

s

)

2

+

2

(

9.8

m

/

s

2

)

(

100

m

)

≈

44.3

m

/

s

The velocity vector at the instant the package just hits the ground is (40.0 m/s ; 44.3 m/s).

Part c)

At the instant that the plane hits the ground, the plane's position is (181 m ; 0 m): i.e. the plane is directly on top of the package and 100 meters above the ground. This is because horizontally, the plane and the package move with the same velocity.

Part d)

The vertical component of the velocity of the package increases at a steady rate. In fact, the rate or gradient is the acceleration

g

=

9.8

m

/

s

2

.

Answer: the forces must be unbalanced, with the force from the left greater than the force from the right.

Explanation:

Gravity is the sole force acting on the body during free fall motion.

The student should launch the sphere at 2v0 because it will land in the 3 point zone at a distance of around 1.41D.

The variables mentioned are;

the sphere's travel distance when thrown from a height, H = D

The speed at which the ball travels to D = v0

The launcher's current available height is H/2.

The available speeds are v0 and 2v0.

Using the formula H = ut + (1/2)gt2, where u is the beginning velocity of the ball's vertical motion, the following is obtained:

H = (1/2)·g·t²

The time it takes for the ball to fall from H is given by t = ((2H/g)).

The length, D = v0 (2H/g),

we obtain when the height is H/2;

t = √(2·H/(2·g)) = √(H/g)

D1 = v0 (H/g) is the distance traveled.

D = (2) v0 (H/g) = ((2)) D1 follows.

D₁ = D/(√2) ≈ 0.71·D

D₁ ≈ 0.71·D

We have at pace 2v0;

D2 = 2v0 (H/g) = 2 v2 v0 (H/g) = 2 v0 (2H/g) = 2D1 1.41D

D₂ ≈ 1.41·D

The 2 point zone is equal to D/2 x D = 0.5 D x D. (This is where position D1 0.71D is placed)

The 3 Point Zone is located at position D2 1.41D and is defined as D x 3D/2 = D x 1.5D.

The student should launch the sphere at the speed, 2v0, such that the ball will land at D2 1.41D, which is in the 3 Point Zone, given that the ball lands at D2, where it is in the 3 Point Zone.

A group of students prepare for a robotic competition and build a robot that can launch large spheres of mass M in the horizontal direction with variable speed and from a variable vertical position and a fixed horizontal position x=0.

The robot is calibrated by adjusting the speed at which the sphere is launched and the height of the robot’s sphere launcher. Depending on where the spheres land on the ground, students earn points based on the accuracy of the robot. The robot is calibrated so that when the spheres are launched from a vertical position y=H and speed v0, they consistently land on the ground on a target that is at a position x=D. Positive directions for vector quantities are indicated in the figure.

When the students arrive at the competition, it is determined that the height of the sphere launcher can no longer be adjusted due to a mechanical malfunction. Therefore, the spheres must be launched at a vertical position of y=H2. However, the spheres may be launched at speed v0 or 2v0.

Question: In a clear response that may also contain diagrams and/or equations, describe which speed, v0 or 2v0, the students should launch the sphere at so that they earn the maximum number of points in the competition.

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Answer:

H= Mass × specific heat capacity ×change in temperature

= 2×380×(10-0)

=2×380×10

=7600 Joules

After 3.0 s, If the first player makes up his mind to chase his opponent. If he accelerates uniformly at 3.5 m/s^2 then it would take 3.13 seconds to catch his opponent.

There are three equations of motion given by  Newton,

v = u + at

S = ut + 1/2×a×t²

v² - u² = 2×a×s

As given in the problem, a hockey player is standing on his skates on the Rideau Canal when an opposing player, moving with a uniform speed of 2.8 m/s, skates by with the puck. After 3.0 s, the first player makes up his mind to chase his opponent. If he accelerates uniformly at 3.5 m/s^2,

Let us assume the time taken to catch up would be t seconds.

The distance traveled by the hockey player = 2.8×3 + 2.8×t

By using the second equation of the motion,

s = ut+0.5at²   = 2.8×3 + 2.8×t

1.75t² - 2.8t -8.4 = 0

t = 3.13 seconds

The distance traveled by the hockey player to catch up = 2.8×(3+3.13)

                                                                                             =17.164 meters

Thus, it would take 3.13 seconds to catch his opponent.

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If we want to burn a paper by focusing sunlight then we have to use a converging lens that can converge all sunlight at a point called the focus.

Thus Convex lens is used to burn the paper.

The transmissive optical device known as a lens employs refraction to focus or disperse a light beam. While a compound lens is made up of numerous simple lenses (elements), they are typically oriented along a common axis, as opposed to a simple lens, which is made up of a single transparent piece. Materials like glass or plastic are used to create lenses, which are then polished, ground, or molded into the desired shape. Unlike a prism, which refracts light without concentrating, a lens can focus light to create an image. Lenses are also used to describe instruments that focus or scatter waves of radiation other than visible light, such as explosives, microwaves, and electron lenses.

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The variations get passed on from one generation of tree snails to the next from both parents to offspring and through the environment (Option C is correct).

The expression of genetic variation refers to differences in the nucleotide sequences between individuals of the same special which are passed across generations from parents to offspring and are selected by natural selection.

In conclusion, the variations get passed on from one generation of tree snails to the next from both parents to offspring and through the environment (Option C is correct).

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School population.

The biggest school in the world is in lucknow, india. it has more than 40,000 students and 2500 teachers! would it be easier to make new friends in a school with 40,000 kids than a school with fewer than 100 kids? School population.

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The distance d between the golfer and point b where the ball first lands is 4933.17 ft

Initial velocity = 250.0ft/s

Launch angle ([tex]\theta[/tex]        )= 25°

slope angle([tex]\phi[/tex]) = 5°

Let d is the distance on the slope after which projectile lands

∴ horizontal distance covered by projectile

x = dcos[tex]\theta[/tex]

Vertical distance covered by projectile

y = dsin[tex]\theta[/tex]

now Considering horizontal motion

Initial horizontal velocity [tex]v_{x} = v cos25[/tex]

then position after time t

d cos5 = 250cos25×t

d = 227.44t          ---------1.

when we consider vertical motion then

Initial vertical velocity [tex]v_{y} = v sin25[/tex]

[tex]v_{y} = v sin\theta t-\frac{1}{2}gt^{2}[/tex]

-d sin5 = 250 sin25.t - gt²/2

-d = 1212.25t - 56.221 t²

1212.25t - 56.221 t² + d = 0         ----2

put value of d in equation 2

1212.25t - 56.221t² + 227.44t =0

t(1212.25+227.44 - 56.221 t) =0

t(1234.69 - 56.221 t) = 0

t = 21.96 ,t≠0

substitute the value of t in equation 1

d = 227.44t    

d = 227.44×21.96

d = 4933.17 ft

The distance d between the golfer and point b where the ball first lands is  4933.17 ft

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If A brick is dropped (zero initial speed) from the roof of a building. The brick strikes the ground in 1.90s then the building is 17.69 meters tall.

Velocity is the directional speed of a moving item as an indication of its rate of change in position as seen from a specific frame of reference and measured by a specific time standard (e.g., 60 km/h northbound). The idea of velocity is crucial in kinematics, the part of classical mechanics that explains the motion of bodies.

A physical vector quantity called velocity requires both magnitude and direction to be defined. Speed is a coherent derived unit that expresses the scalar absolute value (magnitude) of velocity. Its quantity is expressed in SI units (metric system) of metres per second (m/s or ms1). For example, "5 meters per second" is a scalar while "5 meters per second east" is a vector.

We have given that

u = 0 m/s                          (initial velocity)

t = 1.90 s                           (time)

a = g = 9.80 m/s²             (acceleration = falling = gravity)

We will use the second equation of motion to determine the height(S) of the building in meters:

⇒ S =  [tex]ut + \frac{1}{2} at^2[/tex]

⇒ S = (0)(1.90) + [tex]\frac{1}{2}[/tex](9.80)(1.90)²

⇒ S = 4.9 × 3.61

       = 17.69 meters

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Full question

A brick is dropped (zero initial speed) from the roof of a building. The brick strikes the ground in 1.90 s. You may ignore air resistance, so the brick is in free fall. (a) How tall, in meters, is the building?

Answer:

Positive: Proton, Negative: Electron, Neutral: Neutron

Explanation:

Answer:

1.) B

2.) Polar Regions or high altitudes.

Explanation:

The ratio of (ε true/ε engr) = (1.2556/2.51) = 0.5002

So, the engineering strain is around 0.5002 bit wrong from the value of the true strain. This calculated value of difference is known as the extensional deformation.

For finding out the Engineering strain,

Engineering strain is a unit used to describe how much a material deforms when subjected to a specific force. It is equal to the amount of deformation divided by the material's initial length in the direction of the applied force.

⇒ε(engineering) = ΔL/L₀

⇒Lₓ= final length = 3.51 L₀

⇒L₀ = original length = L₀

⇒ΔL = Lₓ- L₀

        = 3.51 L₀ - L₀

        = 2.51 L₀

⇒ε(engineering) = ΔL/L₀

                            = (2.51L₀)/L₀  

                            = 2.51

For finding out the True Strain,

Deformation is measured by True Strain. It can be calculated by integrating the strain across short time intervals and adding them up. Hence,

⇒ε(true) = In (Lₓ/L₀)

⇒Lₓ = 3.51L₀

⇒L₀ = L₀

⇒ε(true) = In (Lₓ/L₀)

              = In (3.51L₀/L₀)

              = In 3.51

              = 1.2556

So, dividing both the values, we get

(ε true/ε engr) = (1.2556/2.51) = 0.5002

The complete question is as follows:

The elastic cords used for bungee jumping are designed to endure large strains. Consider a bungee cord that stretches to a maximum length 3.51 times the original length. There are different ways to report this extensional deformation. Calculate how wrong' the engineering strain is compared to the true strain by evaluating the ratio: ε true/ε engr

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Answer:

2800 N

Explanation:

Acceleration = change in velocity / change in time

                     =    14 m/s  /  7 s = 2 m/s^2

F = ma

 = 1400 (2) = 2800 N