A 15.9 L balloon is filled with 0.8450 mol of gas at 315.00 K. What is the pressure of the gas inside the balloon?

The mass, in grams, of 932 atoms of cesium, Cs is 2.06×10⁻¹⁹ grams

6.02×10²³ atoms = 1 mole of cesium

But

1 mole cesium = 132.91 g

Thus, we can say that:

6.02×10²³ atoms = 132.91 g of cesium

The mass of cesium that contains 932 atoms can be obtained as illustrated below:

6.02×10²³ atoms = 132.91 g of cesium

Therefore,

932 atoms = (932 atoms × 132.91 g) / 6.02×10²³ atoms

932 atoms = 2.06×10⁻¹⁹ g of cesium

Thus, the mass of cesium that contains 932 atoms is 2.06×10⁻¹⁹ grams

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The specific heat capacity of the given metal is 0.1234 J/g°C.

The specific heat capacity of a metal is the electricity required to elevate one kilogram (kg) of the cloth by one diploma Celsius (°C).

The specific heat capacity of a substance is the heating ability of a pattern of the substance divided by means of the mass of the pattern, also every so often called massic heat ability. precise warmth capability is a measure of the amount of heat power required to change the temperature of 1 kg of a material by 1 k.

q = m x C x DT

q = m x C x ( T f - T i )

q = amount of heat energy gained or lost by a substance

m = mass of the sample

C = heat capacity ( J oC⁻¹g⁻¹ or J K⁻¹ g⁻¹ )

T f = final temperature

T i = initial temperature

-q metal = q water

-(mCΔT) = mCΔT

-( mC (T f-T i ) =  mC( T f-T i )

- (240 g x C x (27°C-150°C) =  150g(4.18J/g°C ) × ( 27°C-21°C )

- ( 240g × C × -127 °C = 150 × 4.18 × 6°C

C =  150 × 4.18 × 6°C / 240g × -127 °

C = 3762 / 30480

C = 0.1234 J/g°C

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Answer:

Answer:Even though the two surfaces are sliding past each other, there can still be a frictional force between the surfaces, but this sliding friction we call a kinetic frictional force.

The volume of beaker is 326.46 mL.

The volume of a substance is the amount of space a given mass of the substance occupies.

Volume is related to mass and density of a substance by the following formula:

The volume of the beaker is calculated as follows:

Volume of beaker = volume of water

The mass of the empty beaker = 44.19 g.

Mass of the beaker + water when filled completely = 370.65 g

mass of water = 370.65  - 44.19 = 326.46 g

density of water = 1 g/mL

Volume of water = mass/density

Volume of water = 326.46 g/1 g/ml

Volume of water = 326.46 mL

Volume of beaker =  326.46 mL

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Answer:

The wax vapor starts to burn and creates the stable candle flame that you see. When you blew out the candle you should have seen white smoke rising up into the air from the wick. This is the wax vapor, which becomes visible as it condenses into small liquid droplets in the cooler air.

Explanation:

hope it helps

Answer:

This would be my answer and I hope this helps you.

observe that the flame is not touching the solid candle or the melted wax. It appears to be only touching the wick. I ask them if they think that the candle would burn as long if it were only the wick that was burning. What is the purpose of the wax? When the students place the first flame into the smoke of the second candle, they should see the second candle relight. It is not necessary to touch the wick in order for it to relight. This should lead them to conclude that it is the wax vapor that is burning.

When the students place the beaker containing the ice water above the candle, they should see condensation on the bottom of the beaker. If they hold it too close, they will not see the condensation and will see soot form. Students will usually recognize that the condensation is made of water, but they have difficulty recognizing that it comes from the combustion of the candle.

When the Erlenmeyer flask is placed over the top of the candle in the water, student should observe that the water candle goes out and the water rises. The students test the gas that was collected with phenol red solution (an acid-base indicator). They should observe that the solution changes from red to yellow. I demonstrate that this might indicate the formation of carbon dioxide by blowing through a straw into a solution of phenol red.

Explanation:

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Density of neutron is 3.9868×10¹⁷kg/m³

Here given data is radius of a neutron=1.0×10⁻¹³ we have to calculate density of neutron=?

Density=mass/volume

For calculations of density of neutron volume is not given here so volume of sphere is 4/3πr³

So ,neutron stars are composed of solid nuclear matter, primarily neutrons

Vₙ=4/3πr³

= 4/3π(1.0×10⁻¹³ × 10⁻²)³

= 4/3π((1.0×10⁻¹⁵)³

= 4.1888×10⁻⁴⁵m³ this is the volume of neutron

Neutron stars are composed of solid nuclear matter, primarily neutrons.

Assuming that a neutron star has the same density as a neutron then,

Density=mass/volume

mass of neutron=1.67×10⁻²⁷

Density=1.67×10⁻²⁷kg/4.1888×10⁻⁴⁵m³

= 3.9868×10¹⁷kg/m³ is the density of neutron

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The pair of compounds with same empirical formula will be CH3 and C2H6

Empirical formula of a specific compound is defined as the positive integer ratio of atoms that can be found in that specific compound.

Therefore, from the given option above,

The pair of compounds has the same empirical formula is

CH3 and C3H6

The empirical formula of a chemical compound is the simplest whole number ratio of atoms present in a compound.

The empirical formula of a compound can be exemplified using sulfur monoxide, which would simply be SO, as is the empirical formula of disulfur dioxide, S₂O₂.

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CH3 and C2H6 will be the compounds that have the same empirical formula one another. Option B

The positive integer ratio of atoms that can be found in a certain compound is what is meant to be understood when speaking about the empirical formula of that particular chemical.

Therefore, based on the alternative presented before,

The empirical formulas of the two compounds are identical to one another.

CH3 as well as C3H6

The empirical formula of a chemical compound is the most straightforward representation of the atomic number distribution in the molecule as a whole.

An example of an empirical formula for a molecule is the chemical symbol SO, which stands for sulfur monoxide. Another example is the empirical formula for disulfur dioxide, which is written as S2O2.

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Answer:

False

Explanation:

They need a large amount of energy because they're constantly working

Answer:

They have same volume

Explanation:

[tex]{ \tt{volume = \frac{mass}{density} }} \\ [/tex]

These objects will have the same volume (amount of space occupied) irrespective of their shapes. This occurs if only occupy fluids of the same density.

Answer: He concluded  it was dense but not massive

Explanation: Rutherford concluded that his metal foil experiment was that most of an atom was empty-spaced with a tiny, dense, positively charged nucleus at the center that contains the mass of most atoms.

Hope this Helps u3u

The words which will help him make his search for various types of plants on the Internet easier and faster is “different types of plants” and is denoted as option D.

This is defined as the process in which something is sought for carefully through the use of different types of techniques so as to make it easier.

In the case of Mark looking for information on various types of plants, the best words to type will make his search on the Internet easier and faster is “different types of plants” as it contains all the necessary keywords which is used by the search engine to bring out the result.

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The Density of copper sample is 8.9 g/cm³ to the nearest tenth.

Density is the ratio of the mass of a substance and the volume occupied by that substance.

Density measures how tightly-packed the particles in a substance are.

The more tightly-packed the particles are, the denser the substance will be.

The  formula for calculating the density of a substance is given below as:

Dense substances have smaller volumes but greater masses.

The mass of the copper sample = 39.2 g

The volume of the copper sample = 4.4 cm³

Hence, the density of the copper sample will be:

Density of copper sample = 39.2 g/4.4 cm³

Density of copper sample =8.9 g/cm³

In conclusion, density is a ratio of mass and volume.

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Answer:

time it takes the pendulum to make one full swing back and forth swing

Answer:

Answer:

d)the time it takes for the bob to swing back and forth once

Explanation:

Time period of any object is defined as the time after which it can complete its one round of repetitive motion

So here in the back and forth motion of simple pendulum we know that it will move to and fro about its mean position and the total time to make its to and from motion is known as its time period

so here correct answer would be

d) the time it takes for the bob to swing back and forth once

for simple pendulum the formula of time period is given as

T = 2\pi \sqrt{\frac{L}{g}}T=2πgL

here we know

L = length of pendulum

g = acceleration due to gravity

Answer:

Luke 1:15-17

New International Version

15 for he will be great in the sight of the Lord. He is never to take wine or other fermented drink,(A) and he will be filled with the Holy Spirit(B) even before he is born.(C) 16 He will bring back many of the people of Israel to the Lord their God. 17 And he will go on before the Lord,(D) in the spirit and power of Elijah,(E) to turn the hearts of the parents to their children(F) and the disobedient to the wisdom of the righteous—to make ready a people prepared for the Lord.”(G)

Answer:

option a

volume

Explanation:

as they differ in mass/weight ,density is not possible

The type of graph that will be to display the data collected by the store keeper is bar graph.

A bar graph can be defined as a chart or a graphical representation of data, quantities or numbers using bars or strips.

Also, a bar graph is a graph that shows complete data with rectangular bars and the heights of bars are proportional to the values that they represent.

Three bar graphs can be used to display the data collected by the store keeper.

Thus, the type of graph that will be to display the data collected by the store keeper is bar graph.

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Light can travel up to 671 million in the time of one hour.

speed of light, the rate at which light rays move through various substances. Specifically, the speed of light within a vacuum is presently calculated to be 299,792,458 meters per second.

One of nature's basic constants is the speed of light. Its importance extends well beyond its use in characterizing one aspect of electromagnetic waves. It acts as the universe's only limiting velocity, setting an upper limit on both the speed of all material atoms and the speed at which signals may travel. The speed of light (c) acts as a proportional constant in the well-known relativity equation, E = mc^2, connecting the heretofore dissimilar ideas of mass (m) and energy (E) (E).

Therefore, the speed of light is 671 miles per hour.

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Answer:

c≈0.3418 [J/(gr*K)].

Explanation:

1) formula of heat:

Q=cm(T-t), where Q- energy of heat, c - required specifie heat, m - mass, T and t - initial and final temperatures;

2) according to the formula above:

[tex]c=\frac{Q}{m(T-t)};\\ c=\frac{596}{73*(50-26)}=0.34018264840182648401826484018265[\frac{J}{g*K}].[/tex]

P.S. the differrence in °C is equal the difference in °K.

There are 3.01 × 10¹⁷ moles of AlCl₃ in 1.81 × 10⁴¹ molecules of AlCl₃.

The moles of a substance can be calculated by dividing the number of molecules in the substance by Avogadro's number as follows:

no of moles = no of molecules ÷ 6.02 × 10²³

According to this question, there are 1.81 × 10⁴¹ molecules of AlCl₃. The number of moles in this substance can be calculated as follows;

no of moles = 1.81 × 10⁴¹ ÷ 6.02 × 10²³

no of moles = 0.301 × 10¹⁸

no of moles = 3.01 × 10¹⁷ moles

Therefore, there are 3.01 × 10¹⁷ moles of AlCl₃ in 1.81 × 10⁴¹ molecules of AlCl₃.

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The mass of calcium hydroxide produced is 42.2g.

A white powder without any smell is calcium hydroxide. It is applied in commercial contexts such sewage treatment, paper manufacturing, building, and food processing. It can be used in dentistry and medicine. In root canal fillings, for instance, calcium hydroxide is frequently used. Slaked lime, often known as calcium hydroxide, is an inorganic substance having the chemical formula Ca(OH)2.

It is created when quicklime is combined or slaked with water and is a colorless crystal or white powder. It goes by a variety of names, including pickled lime, hydrated lime, caustic lime, builders' lime, and slaked lime. Calcium hydroxide, often known as E number E526, is a chemical that is employed in a variety of processes, including the production of food. A saturated solution of calcium hydroxide is known as limewater, often known as milk of lime.

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The  third quantum number of a 2p[tex]^{3}[/tex] electron in phosphorus is ml= -1.

Quantum numbers are the set of numbers describe the position of electron and energy of electron in an atom.there are four types of quantum numbers.

Electronic configuration of phosphorus is 1s[tex]^{2}[/tex] 2s[tex]^{2}[/tex] 2p[tex]^{6}[/tex] 3s[tex]^{2}[/tex] 3p[tex]^{6}[/tex]

Quantum numbers for 2p[tex]^{3}[/tex]

1) Principal quantum number (n) = 2

2) Azimuthal quantum number (l) = (n-1) = 1

3) magnetic quantum number (ml) = -l to +l = -1 , 0 , +1

form the given option , ml = -1  for n= 2 , l = 1

Thus,The third quantum number of a 2p[tex]^{3}[/tex] electron in phosphorus is m= -1

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Answer: A. m/= -1

Explanation:

Answer:

false

Explanation:

Answer:

58.) 2,727.9

Explanation:

although I am not sure but that's what my calculations say so

- - - - - - - - - - - - - - - - - - - - - - - -

For 58:

Pretend some zeros aren't there. It helps quite a bit!

For example:

3000 - 272.1 = 2730

300 - 27.21 = 273

Just don't forget to put them back, and it works great!

- - - - - - - - - - - - - - - - - - - - - - - -

~pinetreee

For an endothermic reaction, ΔH is positive (>0).

For an exothermic reaction, ΔH is negative (<0).

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Geese flying south for the winter is migration kind of adaptation the annual, large-scale movement of birds between their breeding (summer) homes and their nonbreeding (winter) grounds.

Adaptation results from evolution. Evolution causes a species to change over a long period of time. Usually, mutations or unintentional gene alterations result in adaptations. Depending on the mutation, a plant or animal may be able to live longer than other members of its species.

Adaptations might be behavioural or physical. Any structural change made to a body part qualifies as a physical adaptation. An animal will often make a response in response to some sort of external stimulation.

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