A 7.40-kg object initially has 347 J of gravitational potential energy. Then an elevator lifts the object a distance of 20.6 m above its previous position. How much work did the elevator perform on the object?

Answer:

B

Explanation:

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Answer:

The basket ball

Explanation:

The heavier an object is the more kinetic energy it will have even if it is thrown at the same speed; therefore, since the basketball is the heaviest, it is the logical answer.

While a marble is heavy for its size, it would not have the same kinetic energy as the basket ball.

Beach balls weigh the least out of the options given so this cannot be the answer.

Golf balls, while they are dense, they do not weigh nearly as much as a basketball would!

Hope this helps <3

Answer:

The answer is B the basketball

Explanation:

Answer:

Explanation:

The area of the base of the statue can be found by using the formula

[tex]a = \frac{f}{p} \\ [/tex]

f is the force

p is the pressure

From the question we have

[tex]a = \frac{1000}{20000} = \frac{1}{20} \\ [/tex]

We have the final answer as

Hope this helps you

Answer:

radiation heat.

Explanation:

That is any heat that passes through the air, like the sun.

Answer:

radiation

Explanation: I’m sure

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Answer:

It would be transformer

Explanation:

hope this helped

Answer:

transformer

Explanation:

got it right

Answer:

The answer is 315 km

Answer:

^ correct

Explanation:

Option A on edge 2020

Answer: False

Explanation:

Answer: A current of 1 A is flowing in a circuit if a charge of 1 coulomb passes any point in the circuit every second.

1 Amp = 1 Coulomb per second

We can write this formula as:

Current (I) = Charge (Q) / Time (t)

Charge (Q) = Current (I) x Time (t)

Explanation:

Answer:

As she raises the height of the ramp, the speed of the toy car decreases.

Explanation:

Speed is the ratio of the distance traveled by an object to the time taken.

i.e speed = [tex]\frac{distance}{time}[/tex]

From the given question, it would be observed that:

i. when the height of the ramp was 10 cm, the car traveled 5 meters.

ii. when the height of the ramp was increased to 13 cm, the car traveled 6 meters.

Therefore, an increase in the height of the ramp causes a decrease in the speed of the toy car so that the distance traveled per unit time increases. Showing that there is an inverse relationship between the height of the ramp and the speed of the toy car.

Answer:

16.2 m/s

Explanation:

2ad=Vf^2-Vi^2

2 (1.5) (40) = Vf^2 -(12)^2

Vf= 16.2 m/s

Answer:

Environment

Explanation:

Your Environment, More Than Genetics, Determines Your Immune Health. When it comes to immunity, the environment you grow up in, or how you were 'nurtured' , is more important than nature, a new study suggests. Particularly as you get older.

Answer:

Gravitational force is noncontact force

Explanation:

Contact force occurs due to the contact between two different objects. Non-contact force occurs due to either attraction or repulsion between two objects such that there is no contact between these objects. There is no field linked with the contact force. ... Gravitational force is an example of a non-contact force.

Answer:

4.04 seconds

Explanation:

In order to solve this problem, we must keep in mind that the initial 2.00 seconds at which the fuel is exhausted does not signal when the rocket reaches its maximum height.

From this moment on, the rocket has a downward acceleration of 9.8 m/s² but it still has an upwards velocity, which we will calculate. This upwards velocity keeps the rocket moving up for a certain period of time, which we will also calculate.

For this problem, let's set the upwards direction to be positive and the downwards direction to be negative.

To find the time that the rocket takes to reach its maximum height, we are going to use the initial 2.00 seconds and find the additional seconds it takes to reach a final vertical velocity of 0 m/s. This represents the time at which the rocket stops moving and heads in the downwards direction, which takes place after the rocket has reached its maximum height.

The time in the air of an object in projectile motion can be found using this equation, derived from one of the constant acceleration kinematic equations.

Time in the air (projectile motion):

Solve for [tex]v_i[/tex] by plugging in 2.00 seconds for t, 30 degrees for theta, and 20.0 m/s² for acceleration, since this is not a constant acceleration problem.

Multiply sin(30) and 2 together.

Multiply 20 to both sides of the equation.

Now we know that the initial velocity of the rocket is 40 m/s. We need to solve for the vertical component of the rocket's velocity in order to solve for the additional time it took after the 2.00 seconds to reach its maximum height.

Vertical component:

The vertical component of the velocity vector is 20 m/s.

Now, in order to solve for the additional seconds that the rocket took to reach its maximum height, let's use one of the kinematic constant acceleration equations that uses the variables [tex]v_f[/tex], [tex]v_i[/tex], [tex]a[/tex], and [tex]t[/tex].

Since we are trying to solve for time, we need to use this equation in terms of the vertical direction, aka the y-direction. Time is the same in either case.

The final vertical velocity of this rocket is 0 m/s at the top, or its maximum height. We found that the vertical component, aka the rocket's initial vertical velocity, is 20 m/s. The acceleration is given to us: -9.8 m/s² (since it's falling downwards, the acceleration must be negative because we already established this in the beginning).

We are trying to solve for time t. Substitute the known values into the equation.

Subtract 20 from both sides of the equation.

Divide both sides of the equation by -9.8.

Now we can take this time and add it to the initial 2.00 seconds of the rocket. This time we just solved for is the time after these initial seconds that the rocket kept going upwards, since its initial vertical velocity was not 0 m/s yet.

The time that the rocket takes to reach its maximum height is 4.04 seconds.

Answer:

4.04 second is your answer hope it help you........

Explanation:

The original acceleration is:

∑F = ma

10 N = (5 kg) a

a = 2 m/s²

If the mass is tripled, the new acceleration is:

∑F = ma

10 N = (15 kg) a

a = 0.67 m/s²

The acceleration is reduced by a factor of 3.

Answer:

1.35 miles per second

Explanation:

1 step it depende the way and hight he is

2 step the mass of the brick it depends

3 if it was triplet the acceleration it would be 1.50

Answer:

it is an upside-down image but the brain realizes it and corrects it in its orientation so we see it in right direction.

Answer:

The lens of the eye is a convex lens. The image that it forms on the retina is upside down.

Explanation:

The eye makes an image, but it is upside down, the brain corrects the image and turns it right side up

Answer:

B i think

Explanation:

B because it travels in the same wavelentgh.............

[tex]gjkrejktg[/tex]

Type A is constructive interference and Type B wave gives destructive interference. The constructive interference would be louder.

Interference can be described as a natural phenomenon that occurs at every place and at every moment. Interference can be defined as the phenomenon in which two waves superpose to produce the resultant wave of the lower, higher, or same amplitude. Light waves are produced randomly by most of the sources.

The interference of light from the soap bubble which reflects colors when illuminated by a light source. The starting point of the wave produced may be a maximum or a minimum,  and there is no way to predict which phase the wave will start.

Interference can either be constructive interference or destructive interference. Constructive interference occurs when the crest of one wave falls on the crest of another wave and the amplitude is maximum.

In destructive interference, when the crest of one wave falls on the trough of another wave and the amplitude is minimum. The phase and displacement of these waves are not the same.

Learn more about interference, here:

https://brainly.com/question/22320785

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Answer:

1010 m

Explanation:

The following data were obtained from the question:

Height (h) of cliff = 500 m

Horizontal velocity (u) = 100 m/s

Horizontal distance (s) =?

Next we shall determine the time taken for the cannon ball to hit the ground. This can be obtained as follow:

Height (h) of cliff = 500 m

Acceleration due to gravity (g) = 9.8 m/s²

Time (t) =?

h = ½gt²

500 = ½ × 9.8 × t²

500 = 4.9 × t²

Divide both side by 4.9

t² = 500/4.9

Take the square root of both side

t = √(500/4.9)

t = 10.1 s

Finally, we shall determine the horizontal distance travelled by the cannon ball.

This can be obtained by using the following formula (s = ut) as illustrated below:

Horizontal velocity (u) = 100 m/s

Time (t) = 10.1 s

Horizontal distance (s) =?

s = ut

s = 100 × 10.1

s = 1010 m

Thus, the cannon ball was launched 1010 m away from the cliff.

Answer:

The percentage uncertainty in his calculated value of density is [tex]\pm 0.713\,\%[/tex].

Explanation:

We can estimate the absolute uncertainty by the definition of total differential. That is:

[tex]\Delta \rho \approx \frac{\partial \rho}{\partial m}\cdot \Delta m + \frac{\partial \rho}{\partial d}\cdot \Delta d + \frac{\partial \rho}{\partial l}\cdot \Delta l[/tex] (1)

Where:

[tex]\frac{\partial \rho}{\partial m}[/tex] - Partial derivative of the density with respect to mass, measured in [tex]\frac{1}{mm^{3}}[/tex].

[tex]\frac{\partial \rho}{\partial d}[/tex] - Partial derivative of the density with respect to diameter, measured in grams per cubic milimeter.

[tex]\frac{\partial \rho}{\partial l}[/tex] - Partial derivative of the density with respect to length, measured in grams per cubic milimeter.

[tex]\Delta m[/tex] - Mass uncertainty, measured in grams.

[tex]\Delta d[/tex] - Diameter uncertainty, measured in milimeters.

[tex]\Delta l[/tex] - Length uncertainty, measured in milimeters.

[tex]\Delta \rho[/tex] - Density uncertainty, measured in grams per cubic milimeters.

Partial derivatives are, respectively:

[tex]\frac{\partial \rho}{\partial m} = \frac{4}{\pi\cdot d^{2}\cdot l}[/tex] (2)

[tex]\frac{\partial \rho}{\partial d} = -\frac{8\cdot m}{\pi\cdot d^{3}\cdot l}[/tex] (3)

[tex]\frac{\partial \rho}{\partial l} = - \frac{4\cdot m}{\pi\cdot d^{2}\cdot l^{2}}[/tex] (4)

And we expand (1) as follows:

[tex]\Delta \rho \approx \frac{4\cdot \Delta m}{\pi\cdot d^{2}\cdot l} - \frac{8\cdot m\cdot \Delta d}{\pi\cdot d^{3}\cdot l}-\frac{4\cdot m\cdot \Delta l}{\pi\cdot d^{2}\cdot l^{2}}[/tex]

[tex]\Delta \rho \approx \left(\frac{4}{\pi\cdot d^{2}\cdot l}\right)\cdot \left(\Delta m -\frac{m\cdot \Delta d}{d}-\frac{m \cdot \Delta l}{l} \right)[/tex] (5)

If we know that [tex]d = 2\,mm[/tex], [tex]l = 25\,mm[/tex], [tex]m = 6.2\,g[/tex], [tex]\Delta m = \pm 0.1\,g[/tex], [tex]\Delta d = \pm 0.01\,mm[/tex] and [tex]\Delta l = \pm 0.1\,mm[/tex], then the absolute uncertainty is:

[tex]\Delta \rho \approx \pm\left[\frac{4}{\pi\cdot (2\,mm)^{2}\cdot (25\,mm)} \right]\cdot \left[(0.1\,g)-\frac{(6.2\,g)\cdot (0.01\,mm)}{2\,mm} -\frac{(6.2\,g)\cdot (0.1\,mm)}{25\,mm} \right][/tex]

[tex]\Delta \rho \approx \pm 5.628\times 10^{-4}\,\frac{g}{mm^{3}}[/tex]

And the expected density is:

[tex]\rho = \frac{4\cdot m}{\pi\cdot d^{2}\cdot l}[/tex] (6)

[tex]\rho = \frac{4\cdot (6.2\,g)}{\pi\cdot (2\,mm)^{2}\cdot (25\,mm)}[/tex]

[tex]\rho \approx 78.941\times 10^{-3}\,\frac{g}{mm^{3}}[/tex]

The percentage uncertainty in his calculated value of density is:

[tex]\%e = \frac{\Delta \rho}{\rho}\times 100\,\%[/tex] (7)

If we know that [tex]\Delta \rho \approx \pm 5.628\times 10^{-4}\,\frac{g}{mm^{3}}[/tex] and [tex]\rho \approx 78.941\times 10^{-3}\,\frac{g}{mm^{3}}[/tex], then the percentage uncertainty is:

[tex]\%e = \frac{\pm 5.628\times 10^{-4}\,\frac{g}{mm^{3}} }{78.941\times 10^{-3}\,\frac{g}{mm^{3}} }\times 100\,\%[/tex]

[tex]\%e = \pm 0.713\,\%[/tex]

The percentage uncertainty in his calculated value of density is [tex]\pm 0.713\,\%[/tex].

Answer:

[tex]-\frac{1}{2}[/tex]

Diverging lens

Explanation:

Given parameters:

Power of lens  = -2.0D

Unknown:

Focal length  = ?

Solution:

The power of lens is the reciprocal of the focal length;

   P  = [tex]\frac{1}{f}[/tex]

where  f is the focal length

 f  = [tex]\frac{1}{P}[/tex]   = [tex]-\frac{1}{2}[/tex]

The lens is a diverging lens

Answer:

This question is incomplete

Explanation:

This question is incomplete because of the absence of the picture of the print in question. However, when the quality of the print obtained from a crime scene is high/good, then this is a good/positive step in identification of a suspect. However, if the quality is bad, other options might need to be explored in addendum to the print obtained in identifying a suspect.

If the quality of the print is good enough to make a pattern, then another factor comes into play. If the pattern is a rare pattern or is not common, then it becomes easier to identify the suspect because there would be fewer people having that fingerprint and fewer people to deal with. Of the three major patterns of fingerprints (whorl, loop and arch), arch fingerprints are the least common.

Answer:

0.61°

Explanation:

Since the box move at constant velocity, it means there is no acceleration then we can say it has a balanced force system.

Pulling force= resistance force

From the formula for pulling force,

F(x)= Fcos(θ)

= 425×cos(35.2)

=347N

The force exerted downward at an angle of 35.2° below the horizontal= Fsin(θ)= 425sin(35.2)

=425×0.567=245N

Resistance force= (325N+ 245N) (α)= 570N(α)

We can now equates the pulling force to resistance force

570 (α)= 347N

(α)= 347/570

= 0.61

Answer:

pressing a shirt with an iron

Explanation:

Heat transfer by conduction is when heat is transferred by two objects in contact with each other.

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Answer:

7m/s²

Explanation:

Given parameters:

Velocity at the top = 1m/s

Velocity at the bottom  = 36m/s

Time  = 5s

Unknown:

Average acceleration = ?

Solution;

Acceleration is the rate of change of velocity with time. It is expressed as;

  A = [tex]\frac{v -u}{t}[/tex]

v is the velocity at the top

u is the velocity at the bottom

t is the time taken

 Now, insert the parameters and solve;

  A = [tex]\frac{36 - 1}{5}[/tex]   = 7m/s²

Given values:

Top velocity,

Bottom velocity,

Time,

The acceleration is:

→ [tex]A = \frac{v -u}{t}[/tex]

By putting the values,

       [tex]= \frac{36-1}{5}[/tex]

       [tex]= \frac{35}{5}[/tex]

       [tex]= 7 \ m/s^2[/tex]

Thus the answer above i.e., "option d" is correct.

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Answer:

The answer is 500

Explanation:

Answer:

The electron is a negatively charged particle found in the atoms of all the elements. The electrons are located outside the nucleus in an atom. An electron is usually represented by the symbol (e –). The mass of an electron is about the mass of a hydrogen atom.

Explanation: