The maximum height above the point of contact with the bat that the ball would reach would be 88.72 meters
What is a projectile motion?It is the movement of any item or body when it is launched from the the earth's surface and follows any curving course while being affected by the gravitational pull of the planet.
The maximum height of the projectile motion is given by,
Maximum height = v² sin²θ / 2 g
=45² sin² 68/ 2 *9.81
=88.72 meters
Thus, the maximum height the ball would reach would be 88.72 meters
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A car traveling 83.0 km/h on a straight road is 1900 m behind a truck traveling at 61.0 km/h . How much time will it take the car to catch up with the truck?
A car traveling 83.0 km/h on a straight road is 1900 m behind a truck traveling at 61.0 km/h. The required voltage is 10 Volts.
What is Electric Current ?Electric current is defined as the rate at which charge passes a fixed unit cross sectional area.
What is Voltage ?Voltage is defined as the physical quantity required to move charge from one end to other.
What is Resistance ?Resistance is defined as the the factor which opposed the electric current.
It states that voltage is directly proportional to electric current
V=IR
Given:
current (I) = 0.1 A
resistance (R) = 100 Ω
Now from definition of voltage we have:
V = I × R
V = 100 × 0.1
V = 10 volts
Thus from the above conclusion we can say that therefore the required voltage is 10 volts.
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When will you say a body is in Uniform acceleration and Non Uniform acceleration?
Answer:
(i) A body has a uniform acceleration if its velocity changes by equal amounts in equal intervals of time. The motion of a freely falling body is an example of uniform acceleraion.
(ii) A body has a non-uniform acceleration if its velocity changes by unequal intervals of time. The motion of a car on a crowded city road is an example of non-uniform acceleration.
A car travels at a speed of 55 km/h for 2.4 h. How far has the car traveled during this journey?
World should shift its energy dependence from nonrenewable sources to renewable sources. Write your opinion
Answer:
•Renewable energy, often referred to as clean energy, comes from natural sources or processes that are constantly replenished. For example, sunlight or wind keep shining and blowing, even if their availability depends on time and weather.
• Renewable sources of energy are better than nonrenewable sources because they refill themselves over a short period of time.
Two football players hit each other head on in a football game. One football
player had an acceleration of 4 m/s² and a mass of 150 kg. The second football
player had an acceleration of 2 m/s² and a mass of 200 kg. Calculate the force
each player had when they hit. What will be the net force of both players and who
knocked who back.
Answer:
200N in Player 1's direction
Player 2 is knocked back
Explanation:
Let's start by working out the force exerted by each player by using the equation F=ma, Force = Mass x Acceleration.
Player 1 has an acceleration of 4m/s2 and a mass of 150kg, therefore their force will be: [tex]F = (150)(4)[/tex], [tex]F=600N[/tex]
Player 2 has an acceleration of 2m/s2 and a mass of 200kg, therefore their force will be: [tex]F = (200)(2)[/tex], [tex]F=400N[/tex]
They are both coming from different directions so we can find the net force by subtracting one from the other: [tex]600-400=200N[/tex]
Player 1 has the higher force so the net force will be 200N in the direction Player 1 is travelling in and Player 2 will be the one knocked back.
Hope this helped!
What are the reasons Flat Earther's use to prove their claim?
Answer:
The ground we walk on is flat, not round. Gravity doesn't exist. Objects don't fall down, the flat earth(disk) goes up with a force called dark energy. There is a 45 ft tall ice wall to prevent people from falling off the Earth.
Explanation:
A ball dropped from a window strikes the ground at 4.00 s later. How high is the window above the ground?
Answer:
15
Explanation:
After 30s, a runner is sprinting at 3 m/s. But 10 s later, the runner is sprinting at 3.8 m/s. What is the runners acceleration during this time? Need to show step by step work please. Content is from physical science, 8th grade.
Need to show step by step - I need to check please
The acceleration of the runner 10 sec later will be 0.08 meters per second square (m/s²).
What is Average acceleration?Average acceleration is defined as the average rate of change of velocity with time. Mathematically -
a = Δv/Δt
Given is a runner sprinting at 3 m/s and after 10 s the same runner is sprinting at 3.8 m/s. Therefore, we can write -
Initial velocity [u] = 3 m/s
Final velocity [v] = 3.8 m/s
time taken [Δt] = 10 s
The average acceleration of the sprinter can be calculated as follows -
a = Δv/Δt
Δv = v - u
Δv = 3.8 - 3 = 0.8 m/s
Δt = 10 s
Therefore -
a = 0.8/10 = 0.08 m/s².
Therefore, the acceleration of the runner 10 sec later will be 0.08 meters per second square (m/s²).
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One group of nursing home patients drinks orange juice before watching an
informative film. A similar group drinks water before watching the same film.
After the film, both groups are tested for their memory of the film's contents.
Here, the independent variable is:
The Independent variable here in this sentence is the type of drink each group was subjected to intake.
Independent variable in a experiment is the one which stands independent and acts as a control which influences the experiment's outcome. Independent variables are employed in a experiment to test whether the dependent variable changes accordingly.
Here, in this experiment the dependent variable, i.e., the theory to be tested is the memory of the patients. The independent variable here is the type of juice given to the patients, which acts as a control of the experiment's outcome. Any variable which alters the final result of the experiment and which can be controlled through out the experiment is termed as Independent variable.
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1. A 10kg ball moving at a speed of 6 m/s strikes another 5kg ball at rest with a contact time of 0.5 seconds. The 10kg comes to a complete stop. (a) What average force was exerted on the 10kg ball? (b) What average force was exerted on the 5kg ball? (c) What is the final momentum of the 5kg ball? (d) What is the initial momentum of the 10kg ball?
a)average force was exerted on the 10kg ball= -120 N
b)average force was exerted on the 5kg ball= 60N
c)What is the final momentum of the 5kg ball= 2.5 kg m/s
d) the initial momentum of the 10kg ball=60 kg m/s
The average force can be calculated by formula F=m(vf–vi)/ Δt so, 10 (0-6)/0.5 = -120 N the minus is representing opposite direction
the average force on the 5 kg ball = 5(6-0)/0.5= 60 N
The final momentum of 5 kg ball is 5 X 0.5 =2.5 kg m/s and initial momentum of 10 kg ball = 10 X 6 = 60 Kg m/s.
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The pressure at the top of Mount Everest is 0.31×105N/m2, and the temperature is −30∘C. The pressure at sea level is 1.0×105N/m2, and the temperature is 20∘C.
Determine how much more frequently you need to breathe on top of Mount Everest to inhale the same amount of oxygen as you do at sea level.
________ times more frequently.
It takes 2.7 times approximately to breath frequently on top of Mount Everest as you do at sea level.
What is Pressure ?Pressure is force per unit area. Pressure in fluid is the product of fluid density, acceleration due to gravity and the height. Pressure is measured in N/m²
Given that the pressure at the top of Mount Everest is 0.31×105N/m2, and the temperature is −30∘C.
From Ideal gas law, PV = nRT
Where
P = 31000 N/m²
T = - 30 + 273 = 243 K
n/V = ?
R = 8.314 1/K/Mol
n/V = P / RT
n/V = 31000 / (8.314 × 243)
n/V = 31000 / 2020.302
n/V = 15.34
When the pressure at sea level is 1.0×105N/m2, and the temperature is 20∘C, then
T = 20 + 273 = 293 K
n/V = 100000 / (8.314 × 293)
n/V = 100000 / 2436.002
n/V = 41.05
To determine how much more frequently you need to breathe on top of Mount Everest to inhale the same amount of oxygen as you do at sea level, you divide the two values. That is,
41.05 / 15.34 = 2.67
Therefore, it takes 2.7 times approximately to breath frequently on top of Mount Everest as you do at sea level.
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Two ropes are attached to a heavy object. The ropes are given to two strong physics students (is there any other kind?) with instructions for each to pull with 1000 N of force. Determine the resultant force if the two students pull: a) in the same direction east.
story problem questions for newtons 3rd law
A proton is moving in a circular orbit of radius 14 cm in a uniform magnetic field of
magnitude 0.35 T directed perpendicular to the velocity of the proton. Find the orbital speed
of the proton.
The orbital speed of the proton is 4.7 x 10⁶ m/s.
What is the orbital speed of the proton?The orbital speed of the proton is calculated by applying the following equations as shown below.
Centripetal force of the proton = magnetic force of the proton
Fc = qVB
mv²/r = qvB
mv² = qvBr
v² = qvBr/m
v = qBr/m
where;
v is the speed of the protonB is the magnetic field strengthr is the radius of the circular pathm is mass of the protonThe orbital speed of the proton is calculated as follows;
v = (1.6 x 10⁻¹⁹ x 0.35 x 0.14) / (1.67 x 10⁻²⁷)
v = 4.7 x 10⁶ m/s
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Which of the following best describes a position versus time graph foran accelerating object?
Answer: I don't really see the answer choices.
Explanation:
What is the condition for block b to move downwards
A) mb/ma > sin theta - mew cos theta
B) mb/ma > cos theta + mew sin theta
C) mb/ma > sin theta + mew cos theta
D) mb/ma > cos theta - mew sin theta
And what would the condition for the block to move upwards
A) mb/ma < sin theta - mew cos theta
B) mb/ma < cos theta + mew sin theta
C) mb/ma < sin theta + mew cos theta
D) mb/ma < cos theta - mew sin theta
Answer:
Solution in Photo
Explanation:
To solve this question, draw the Free Body Diagram (FBD) for the whole system such that
theta < 90, it will be more clearer that way.
Expert help me
When firing a rifle, the bullet is shot at a high speed as the rifle recoils in the opposite directo How do you compare the force which they impart on each other? • How do you then explain the big difference in the velocities of two? Would you care to fire a rifle whose bullet is ten times as massive as the rifle? Why or why not?
Answer:
See below
Explanation:
The forces are equal but opposite directions
the velocities of the two differ because of the different masses of the two objects....the bullet is light compared to the rifle/shooter.
I would not want to fire a heavy projectile...the 'kick' or 'recoil' of the rifle would be quite large.....and painful!
Question is down here
⬇️
The property that the wire must have to be used in the game is high conductivity.
What is a wire?A wire is a material that is used to carry electric current from one point to another. Thus, we know that when we connect wire to a source, there is a movement of electrons. We can thus see that the wire is able to conduct electricity.
Having said that, the game as shown in the image attached has to do with the formation of a circuit and the flow of electricity in that circuit that is formed.
We can see that the property that the wire must have to be used in the game is high conductivity.
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I went driving the other day and I covered 100 miles in the first 2 hours. Then I had a picnic for an hourThen continue driving to my friends house and traveled 50 miles in 2 hoursWhat was my average speed?
Determine the upward applied force, in lbf, required to accelerate a 4.5-lb model rocket vertically upward, with an acceleration of 3 g’s. The only other significant force acting on the rocket is gravity, and 1 g 5 32.2 ft/s2.
The upward applied force will be 579.249 lbf.
Mass of the rocket, m = 4.5 lb
Acceleration, a = 3g
as we know g = 32.2 ft/s²
therefore acceleration, a = 3 * 32.174 = 96.522 ft/s²
According to the Newton's second law of motion, which states that the magnitude of the force acting on an object is equal to the product of the object's mass and the acceleration with which it is moving.
Mathematically, it is F = [tex]\frac{mass}{acceleration}[/tex] ;
Upward force (F₀) for the rocket will be the sum of Force applied by the weight (Fₓ) and the force by the acceleration(Fₐ).
i.e. gₙ *F₀ = Fₓ + Fₐ
Fₓ = mg
Fₐ = ma
F₀ = ma + mg
F₀ = m (a + g)
F₀ = 4.5 (96.522 + 32.2)
F₀ = 4.5 * 128.722
F₀ = 579.249 lbf.
The upward applied force, required to accelerate a 4.5-lb model rocket vertically upward will be 579.249 lbf.
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HELPPP
Is the density of an object always the same as its mass?
Yes
No
How would you calculate the density of an object?
mass/area
mass/volume
After completing the liquids portion of the lab, which liquid was the least dense?
oil
water
syrup
In a density column experiment (like the one explained in the lesson), the density of the liquids depends on the order in which they are added to the column.
True
False
Would a golf ball or a ping pong ball (of the same volume) have more density?
golf ball
ping pong ball
The correct responses are;
1) No the density of an object is not always the same as its mass
2) The density of an object is calculated from mass/volume
3) After completing the liquids portion of the lab, oil has the lest density
4) It is a false statement that the density of the liquids depends on the order in which they are added to the column.
5) The golf ball has a greater density than the ping pong ball
What is density?The term density refers to the mass per unit volume of an object. This implies that if measure the mass of the object and divide this value by the volume of the object then we obtain the density of the object. The density is an empirical property hence it does not change.
Let us now answer the questions individually;
1) No the density of an object is not always the same as its mass
2) The density of an object is calculated from mass/volume
3) After completing the liquids portion of the lab, oil has the lest density
4) It is a false statement that the density of the liquids depends on the order in which they are added to the column.
5) The golf ball has a greater density than the ping pong ball
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Temperature is a vector quantity because it can go down as well as up. True or false?
Answer:
Explanation:
temperature is a scalar quantity
You drop a 20 Ton object and a
10 Ton object at the same time.
How does the acceleration
compare through the fall
assuming minimal air resistance.
Explanation:
it dosent depend on the weights of the items. I'll reach the ground at same time taking as no air friction or restrictions.
i.e
v = u + gt
whte v is final velocity of the object
u is initial velocity of the object
g is acceleration due to gravity and
t is time. thanks
please if found helpful rate brainliest
Assuming there is little air resistance, the acceleration felt by both objects when one drops a 20-ton object and a 10-ton object at the same time will be the same.
Even though both objects accelerate at the same rate, the forces acting on them will be different because of their different masses. Newton's second law of motion states that an object's force is inversely proportional to its mass (F = ma). The 20-ton object will therefore encounter twice as much force as the 10-ton object, but their rates of acceleration will remain constant.
In conclusion, both the 20-ton and 10-ton objects will accelerate to about 9.8 meters per second squared when dropped simultaneously with little air resistance.
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A speedboat moves west at 108 km/h for 22.0 min. It then moves at 60.0° south of west at 90.0 km/h for 10.0 min.
What is the average speed for the trip?
What is the magnitude of average velocity for the trip?
What is the direction of average velocity for the trip? Enter the angle in degrees where negative indicates north of west and positive indicates south of west.
Answer:
108 km/hr = 1.8 km/min
90 km/hr = 1.5 km/min
V1 = (-39.6, 0)
V2 = (-10.6, -10.6) (10.6^2 + 10.6^2)^1/2 = 15 1.5 km/min * 10 min
V = (-50.2, -10.6) final displacement vector
Total time = 22 + 10 = 32 min
S = (50.2^2 + 10.6^2)^1/2 = 51.3 km
Average speed = (1.8 * 22 + 1.5 * 10) / 32 = 1.71 km / min
Displacement = 51.3 km
Average velocity = 51.3 / 32 = 1.60 km/min
Direction = 10.6 / 50.2 = .211 or 11.9 deg S of W
Not sure if it’s right can someone make sure
Explanation:
stones a and b will hit the ground at the same time because they are of identical weight I think your right
If f(x) = 2x - 8 and g(x) = x4, what is (g°f)(5)?
080
Clear all
Enter the correct answer.
I
+00
DONE
6 of 15
Exit
The correct answer is 16.
The conventional way to express function is F(x).
You may alternatively describe it as a machine that has input, output, and some other ways they are connected.
You must first evaluate the first function in order to get the value of a composite function like this one. We placed the value for x in parentheses first in that equation because f is on the right side.
f (x) = 2x - 8
f (5) = 2 × 5 - 8
f (5) = 10 - 8
f (5) = 2
Once the first portion of a composite function has an answer, we insert that response into the second part. We insert our response (2) into g because it is on the left side.
g(x) = x^4
g(2) = 2^4
g(2) = 16
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Explain why sound connot travel in a vaccum
Sound cannot travel through a vacuum because there are no particles to carry the vibrations.
Explanation:
When travelling through air, the speed of sound is about 330 metres per second (m/s).
A boat travels west at a speed of 20 m/s across a river that is flowing south at 9 m/s. What is the
resultant velocity of the boat?
Answer:
22m/s
Explanation:
This is a vector addition problem. First identify the two vectors: 20m/s in the -x direction and 9m/s in the -y direction. Since neither vector shares an axis component you can use the formula [tex]\sqrt{20^2+9^2\\[/tex] =21.93 (This is the Pythagorean Theorem where your non-hypotenuse sides are your velocity vectors). Round to 2 significant figures and you'll get 22m/s.
A rescue helicopter lifts a 50kg rock climber. If he accelerates at 5m/s what is the tension of the rope
The tension of the rope is 750 N.
According to Newton's second law of motion, the mass of a rock climber, m = 50 kg, while lifting a thing upwards with an acceleration, the upward force must be larger than the weight of the object in order to have a net force in upward direction to induce acceleration in upward direction.
accelerating a rock climber upward with a rope,
a= 5 m/s
determining the rope's tension (T)
The following two forces are at work on the rock climber as it is raised:
Rope tension acting upward. The rock climber's weight acting downward. Using Newton's second rule of motion, we may now:
Mass times climber's acceleration equals net upward force.
T−m×g=m×aT
=m×(g+a)T
=50× (10+5) T
=750 N
The complete question is -A rescue helicopter lifts a 50 kg rock climber by a rope from a cliff face. The rock climber is accelerated vertically a 5m/s−² What is the tension in the rope?
a) 350N
b) 500N
c) 750N
d) 1500 N
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a half meter ruler is pivoted at its midpoint and balances whaen a weight of 20N is placed at the 10 cm mark and a weight W is placed at the 45 cm mark on the ruleer. Calculate the weight W
Answer:
W = 15 N
Explanation:
The moments from the center mus be equal for balance to occur
center is at 25 cm ( for a 1/2 meter stick)
moment one : 15 cm * 20 N
moment two : 20 cm * W these must be equal
15 * 20 = 20 * W W = 15 N