A boy on a swing set has a speed of 4.5 m/s and a centripetal acceleration of 8.1 m/s2 at the bottom of his swing. How long are the ropes of the swing?

Pls help!!!!

Answers

Answer 1

Answer:

R = 1.8 m

Explanation:

This is a simple harmonic movement exercise, at the bottom of the swing the acceleration is vertical upwards and the speed is tangential to the trajectory, that is horizontal; the expression for the centralized acceleration is

              [tex]a_{c}[/tex] = v² / R

              R = v² /a_{c}

where the radius is equal to the length of the swing

let's calculate

            R = 8.1 / 4.5

            R = 1.8 m


Related Questions

which topic are you most likely to find in a physics textbook?

Answers

I think D would be the best answer provided.

PLEASE HELP FAST what is the frequency of a wave that has a period of 50 seconds
A.0.2 Hz
B.2 Hz
C.0.02 Hz
D.20 Hz

Answers

Answer:

0.02 HZ

Explanation:

There is no way to explain it.

Answer:

C.0.02 Hz

Explanation:

What is the change in momentum of a ball if a force of 5.0 N acts on it for a brief time of 4 ms?

Answers

Answer:

0.02 Ns

Explanation:

From the question given above, the following data were obtained:

Force (F) = 5 N

Time (t) = 4 ms

Change in momentum =?

Next, we shall convert 4 ms to s. This can be obtained as follow:

1 ms = 1×10¯³ s

Therefore,

4 ms = 4 ms × 1×10¯³ s / 1 ms

4 ms = 4×10¯³ s

Thus, 4 ms is equivalent to 4×10¯³ s

Change in momentum = Impulse

Impulse (I) = Force (F) × time (t)

Change in momentum = Force (F) × time (t)

Force (F) = 5 N

Time (t) = 4×10¯³ s

Change in momentum =?

Change in momentum = 5 × 4×10¯³

Change in momentum = 0.02 Ns

Therefore, the change in the momentum of the ball is 0.02 Ns.

A baseball pitcher delivers a pitch by exerting an average force of 15 N for a time interval of 0.42 s. How much impulse does he impart to the ball ?

Answers

Answer:

6.3Ns

Explanation:

Impulse can be calculated by using the formula as follows:

I = F × ∆t

Where;

I = impulse (Ns)

F = Force exerted (N)

∆t = change in time (s)

According to the information provided in the question, I = ?, F = 15N, ∆t (time interval) = 0.42s

I = 15 × 0.42

I = 6.3Ns

How fast must a train accelerates from rest to cover 518 m in the first 7.48 s?

Answers

Heya!

For this problem, use the formula:

s = Vo * t + (at^2) / 2

Since the initial velocity is zero, the formula simplifies like this:

s = (at^2) / 2

Clear a:

2s = at^2

(2s) / t^2 = a

a = (2s) / t^2

Data:

s = Distance = 518 m

t = Time = 7,48 s

a = Aceleration = ¿?

Replace according formula:

a = (2*518 m) / (7,48 s)^2

Resolving:

a = 1036 m / 55,95 s^2

a = 23,34 m/s^2

The aceleration must be 23,34 meters per second squared

According to the workshop, habits, attitudes, feelings and thoughts
contribute to 60% of your college success.
contribute to 30% of your college success.
contribute to 70% of your college success.
contribute to 100% of your college success.

Answers

Answer:

60%

Explanation:

HELP PLEASE
Balloons and static electricity
Answer the following questions:

Answers

Can’t see the pictures !

The shape of Sugarloaf mountain, in Rio de Janeiro, Brazil, is such that, if you
were to kick a soccer ball hard enough, it could land near the base of the mountain
without hitting the mountain's side. Suppose the ball is kicked horizontally with an
initial speed of 9:37 m/s. If the ball travels a horizontal distance of 85.0 m, how tall
is the mountain?

Answers

Answer:

The mountain is 403 m tall

Explanation:

Horizontal Launch

When an object is thrown horizontally with a speed v from a height h, it describes a curved path ruled by gravity until it hits the ground.

The range or maximum horizontal distance traveled by the object can be calculated as follows:

[tex]\displaystyle d=v\cdot\sqrt{\frac {2h}{g}}[/tex]

It's given that if a ball is kicked from the top of the Sugarloaf Mountain, it will land near its base without hitting the side. The initial speed is v=9.37 m/s and it reaches a horizontal distance of d=85 m. Solving the equation for h:

[tex]\displaystyle h=\frac{d^2g}{2v^2}[/tex]

Substituting:

[tex]\displaystyle h=\frac{85^2*9.8}{2*9.37^2}[/tex]

[tex]\displaystyle h=403 \ m[/tex]

The mountain is 403 m tall

Determine the absolute pressure on the bottom of a swimming pool 30.0 mm by 8.5 mm whose uniform depth is 2.0 mm .

Answers

Answer:

To calculate the absolute pressure we used the depth as 2 m instead of 2 mm because the given dimensions for the swimming pool do not make sense (they are too small).  

The absolute pressure on the bottom of a swimming pool is 1.21x10⁵ Pa.

Explanation:

The absolute pressure is given by:

[tex]P_{A} = P_{g} + P_{atm}[/tex]

Where:

[tex]P_{g}[/tex]: is the gauge pressure

[tex]P_{atm}[/tex]: is the atmospheric pressure = 1 atm = 101325 Pa

The gauge pressure can be found as follows:

[tex]P_{g} = \rho gh[/tex]

Where:

ρ: is the density of water = 1000 kg/m³

g: is the gravity = 9.81 m/s²

h: is the height or the depth

Since the given dimensions in the statement for the swimming pool do not make sense (they should be in meters instead of millimeters), we will use h = 2 m.

[tex]P_{g} = \rho gh = 1000 kg/m^{3}*9.81 m/s^{2}*2.0 m = 19620 Pa[/tex]

Hence, the absolute pressure is:

[tex]P_{A} = P_{g} + P_{atm} = 19620 Pa + 101325 Pa = 120945 Pa = 1.21 \cdot 10^{5} Pa[/tex]        

Therefore, the absolute pressure on the bottom of a swimming pool is 1.21x10⁵ Pa.

I hope it helps you!                                                  

1. Which one of the following physical quantities is formed after dividing
mass by volume?​

Answers

Answer:

xxxxx

Explanation:

Density is the mass of an object divided by its volume. Density often has units of grams per cubic centimeter (g/cm3). Remember, grams is a mass and cubic centimeters is a Volume (the same volume as 1 milliliter).

g Amateur radio operators in the United States can transmit on several bands. One of those bands consists of radio waves with a wavelength near . Calculate the frequency of these radio waves.

Answers

Answer:

7.5 × 10¹⁵ Hz

Explanation:

CHECK THE COMPLETE QUESTION BELOW;

Amateur radio operators in the United States can transmit on several bands. One of those bands consists of radio waves with a wavelength near 40nm.

Calculate the frequency of these radio waves.

The frequency of these radio waves can be calculated using the expression below

ν = c/λ

Where

v = Frequency of the radio waves

c= Speed of light= 3.00 × 10⁸ m/s

λ= Wavelength= 40 nm

= 40 × 10⁻⁹ m

ν = 3× 10⁸/40 × 10⁻⁹

= 7.5 × 10¹⁵ Hz

Hence, the frequency of these radio waves is 7.5 × 10¹⁵ Hz

A batter hits a fastball with a mass of 0.145 kg that was traveling at 40.0 m/s; the force exerted by the bat on the ball is 29 N. What is the time of contact with the ball in order to reverse its motion at its original speed?

Answers

The force applies an acceleration in the reverse direction of

29 N = (0.145 kg) a   →   a = 200 m/s²

and in order to hit the ball back with speed 40.0 m/s, this acceleration is applied over time t such that

200 m/s² = (40.0 m/s - (-40.0 m/s)) / t   →   t = (80.0 m/s) / (200 m/s²) = 0.4 s

A brick of gold is 0.1 m wide, 0.1 m high, and 0.2 m long. The density of gold is 19,300 kg/m3. What pressure does the brick exert on the table if the brick is resting on its side?

Answers

Answer:

The pressure exerted by the brick on the table is 18,933.3 N/m².

Explanation:

Given;

height of the brick, h = 0.1 m

density of the brick, ρ = 19,300 kg/m³

acceleration due to gravity, g = 9.81 m/s²

The pressure exerted by the brick on the table is calculated as;

P = ρgh

P = (19,300)(9.81)(0.1)

P = 18,933.3 N/m²

Therefore, the pressure exerted by the brick on the table is 18,933.3 N/m².

a car and its passengers have a mass of 1200kg it is travelling at 12m/s.
Calculate the increase in kinetic energy when the car increases its speed to 18 m/s.

Show clearly how you work out your answer and give the unit.

Answers

Answer:

The increase of kinetic energy is 108,000 J

Explanation:

Kinetic Energy

Is the energy an object has due to its state of motion. It's proportional to the square of the speed and the mass.

The equation for the kinetic energy is:

[tex]\displaystyle K=\frac{1}{2}mv^2[/tex]

Where:

m = mass of the object

v = speed at which the object moves

The kinetic energy is expressed in Joules (J)

A car has a total mass of m=1,200 kg and travels at v1=12 m/s. Then it increases its speed at v2=18 m/s.

It's required to compute the increase of kinetic energy. We'll calculate both energies K1 and K2 and then subtract them.

[tex]\displaystyle K_1=\frac{1}{2}1,200*12^2=86,400\ J[/tex]

[tex]\displaystyle K_2=\frac{1}{2}1,200*18^2=194,400\ J[/tex]

The increase of kinetic energy is:

[tex]\Delta K=K_2-K_1 =194,400\ J-86,400\ J[/tex]

[tex]\Delta K=108,000\ J[/tex]

The increase of kinetic energy is 108,000 J

what is formulae method​

Answers

Answer:

Explanation:

The formula method is used to calculate termination payments on a prematurely ended swap, where the terminating party compensates the losses borne by the non-terminating party due to the early termination.

How will the motion of the arrow change after it leaves the bow?

Answers

The string moves to the right, as it restores its original position with the median plane of the bow. As a result, the string "pulls" on the arrow with a force F2. 2. The tip of the arrow T moves slightly to the left.

pls thank me and brainliest me

Suppose someone caused a book to fall from the shelf to the ground. Compared to the total sum of kinetic and potential energy the book has while on the shelf, about how much would it have when it is halfway from the shelf to the ground? no energy, half as much,twice as much, or the same amount? Pretty easy question.​

Answers

Answer:

book resting on a shelf has no potential energy relative to the shelf since it has a height of zero meters relative to the shelf. However, if the book is elevated to some height above the shelf, then it has potential energy proportional to the height at which it resides above the shelf.

An object can have both kinetic and potential energy at the same time. For example, an object which is falling, but has not yet reached the ground has kinetic energy because it is moving downwards, and potential energy because it is able to move downwards even further than it already has. The sum of an object's potential and kinetic energies is called the object's mechanical energy.

As an object falls its potential energy decreases, while its kinetic energy increases. The decrease in potential energy is exactly equal to the increase in kinetic energy.

Another important concept is work.

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