Answer:
300 m
Explanation:
using constant acceleration equations:
v = vi + a * t, v = final velocity = 0m/s , vi = initial velocity = 60m/s,
a = acceleration = -6m/s², t = time
solve t
t = 10s
x = vi * t + .5 * a * t²
plug
x = 300 m
What is the difference between Helium3, and Helium?
Explanation:
Helium is the type of atom, with 2 protons in the nucleus.
He-3 (which is the proper form), is an isotope of helium that has an atomic number of 3 (so 2 protons and 1 electron).
The most abundant helium isotope is He-4, just an extra fact.
How many hours are in a full day and night? I have been told 24 hrs but is that right?
Answer:
its 24 hours
Explanation:
12 hours during the night and 12 hours during the day
Yes that's right...did anyone tell you something else?
A brick of gold is 0.1 m wide, 0.1 m high, and 0.2 m long. The density of gold is 19,300 kg/m3. What pressure does the brick exert on the table if the brick is resting on its side?
Answer:
[tex]P=18,933.3Pa=18.9kPa[/tex]
Explanation:
Hello!
In this case, since we can compute the volume of the brick as shown below:
[tex]V=0.1m*0.1m*0.2m=0.002m^3[/tex]
Next, we can compute the mass of the brick given its density:
[tex]\rho =m/V\\\\m=V*\rho\\\\m=0.002m^3*19,300kg/m^3\\\\m=38.6kg[/tex]
Now, since the force exerted on the table corresponds to the weight of the brick, we use the gravity to obtain:
[tex]W=38.6kg*9.81m/s^2=378.7N[/tex]
Finally, since the surface of the brick in contact with the table corresponds to the 0.1x0.2 area (length and width), the area on which the weight force is exerted is:
[tex]A=0.1m*0.2m=0.02m^2[/tex]
Therefore, the pressure is:
[tex]P=\frac{F}{A}=\frac{W}{A}=\frac{378.7N}{0.02m^2}\\\\P=18,933.3Pa=18.9kPa[/tex]
Best regards!
Name at least two other viruses that are at all time lows due to vaccines.
A 40.0-kg football player leaps through the air to collide with and tackle a 50.0-kg player heading toward him, also in the air. If the 40.0-kg player is heading to the right at 9.0 m/s and the 50.0-kg player is heading toward the left at 2.0 m/s, what is the speed and direction of the tangled players
Answer:
The speed and direction of the tangled players is 2.89 m/s towards right.
Explanation:
Given;
mass of the player heading right, m₁ = 40 kg
initial velocity of the player heading right, u₁ = 9.0 m/s
mass of the player heading left, m₂ = 50 kg
initial velocity of the player heading left, u₂ = -2.0 m/s
let the speed of the tangled players = v
Apply the law of conservation of linear momentum;
m₁u₁ + m₂u₂ = v(m₁ + m₂)
(40 x 9) + (50 x - 2) = v(40 + 50)
360 - 100 = v(90)
260 = v(90)
v = 260 / 90
v = 2.89 m/s (towards right, since it is in position direction)
Therefore, the speed and direction of the tangled players is 2.89 m/s towards right.
A rectangular tank 6 m long and 3 m wide contains water up to a depth of 2.5 m.
Calculate the pressure and resultant hydrostatic force on the base of the tank.
Answer:
P = 24525 [Pa]
Explanation:
The pressure at the bottom of any vessel can be determined, only by knowing the depth or height of the liquid level. By means of the following equation.
[tex]P=Ro*g*h[/tex]
where:
P = pressure [Pa]
Ro = density of the water = 1000 [kg/m³]
g = gravity acceleration = 9.81 [m/s²]
h = elevation = 2.5 [m]
Now replacing:
[tex]P=1000*9.81*2.5\\P=24525 [Pa][/tex]
A railroad car of mass M moving at a speed v1 collides and couples with two coupled railroad cars, each of the same mass M and moving in the same direction at a speed v2. (a) What is the speed vf of the three coupled cars after the collision in terms of v1 and v2
Answer:
vf = v₁/3 + 2v₂/3
Explanation:
Using the law of conservation of linear momentum,
momentum before impact = momentum after impact
So, Mv₁ + 2Mv₂ = 3Mv (since the railroad cars combine) where v₁ = initial velocity of first railroad car, v₂ = initial velocity of the other two coupled railroad cars, and vf = final velocity of the three railroad cars after impact.
Mv₁ + 2Mv₂ = 3Mvf
dividing through by 3M, we have
v₁/3 + 2v₂/3 = vf
vf = v₁/3 + 2v₂/3
A generator delivers an AC voltage of the form Δv =(82 V) sin (75πt) to a capacitor. Themaximum current in the circuit is 1.00A. Find the following.
(a) rms voltage of the generator
1 V
(b) frequency of the generator
2 Hz
(c) rms current
3 A
(d) reactance
4 Ω
(e) value of the capacitance
5 F
Answer:
1. 57.99V
2. 37.5Hz
3. 0.7072A
4. 82 ohms
5. 5.18x10^-5F
Explanation:
In answer to this question, we have the Standard equation of AC emf to be
V = V0 x sin ωt
We have
V0 = 82V,
ω = 75π
1.
RMS Voltage =
V0/√2 = 82 /√2
= 82/1.414
= 57.99V
2.
ω = 2π* f
75π = 2πf
Frequency,f = 75π/2π
= 235.5/6.28
= 37.5 Hz
3.
RMS current
= Imax/√2
= 1.00/1.414
= 0.7072A
4.
Reactance
= Vrms/ Irms
= 57.99/0.7072
= 81.999
= 82.0 Ω
5.
Reactance = 1/ ω x C
Reactance = 82
ω = 75π
We put these values into the equation above and make c the subject of the formula
C = 1/82.0 x 75π
C = 1/ 82.0 x 75 x 3.14
C = 1/19311
Capacitance = 5.18x10^-5F
A weight lifter lifts a 250 Newton weight up 1.5 meters. How much work did they do?
Answer:
375 J
Explanation:
Work done is the product of force and distance moved by the object.
W=F*d
Given that ;
Force= F= 250 N
Distance= d =1.5 m
W= 250 * 1.5 =375 J
6/7 and 24/28 what is the answer proportion or no
Given that,
6/7 and 24/28
To find,
The above number are in proportion or not.
Solution,
First number is 6/7
Other number is 24/28
Multiply numerator and denominator by 4 to the first number.
[tex]\dfrac{6}{7}=\dfrac{6}{7}\times \dfrac{4}{4}\\\\=\dfrac{6\times 4}{7\times 4}\\\\=\dfrac{24}{28}[/tex]
So, 6/7 and 24/28 are in proportion.
Fraction A is proportional to fraction B because the value of fraction A is equal to fraction B.
Given the following data:
Fraction A = [tex]\frac{6}{7}[/tex]Fraction B = [tex]\frac{24}{28}[/tex]In this exercise, you're required to determine whether or not the two fractions are proportionate i.e whether fraction A is proportional to fraction B.
Two fractions are considered to be proportionate when the value of fraction A is equal to fraction B.
We would write fraction B in its simplest form by dividing both the numerator and denominator by their highest common factor (HCF).
HCF of 24 and 28 = 4.
Dividing by 4, we have:
[tex]Fraction\;B =\frac{24}{28}=\frac{6}{7}[/tex]
In conclusion, fraction A is proportional to fraction B because the value of fraction A is equal to fraction B.
Read more: https://brainly.com/question/18676621
The world’s largest wind turbine has blades that are 80 m long and makes 1 revolution every 5.7 seconds.
What is the velocity for one of the blades?
(THIS IS PHYSICS, CIRCULAR MOTION)
Answer:
88.14 m/s
Explanation:
From the question given above, the following data were obtained:
Radius (r) = length of blade = 80 m
Revolution (rev) = 1
Time (t) = 5.7 s
Velocity (v) =?
The velocity of the blade can be obtained by using the following formula:
v = (rev × 2πr) / t
NOTE: Pi (π) = 3.14
v = (1 × 2 × 3.14 × 80) / 5.7
v = 502.4 / 5.7
v = 88.14 m/s
Therefore, the velocity of the blade is 88.14 m/s
A cat swats a ball on the coffee table. The ball rolls horizontally off the edge of a table. Which statement is true?
A. The balls horizontal velocity changes at the rate of 9.8 meters/second every second.
B. As the ball falls to the ground, it moves along a parabolic path.
C. No external vertical forces acts on the ball.
D. The ball had a constant vertical velocity.
Answer:
D
Explanation:
The Sun does NOT rotate the way Earth does. Which statement best describes the difference in their rotations?
A
The Sun had different periods of rotation at different latitudes.
B
The Sun does NOT rotate.
C
The Sun rotated in different directions of rotation at different latitudes.
D
The Sun rotates in the opposite direction from Earth's rotation
What type of lever has the fulcrum between the resistance arm and the effort arm?
A) type 3 lever
B) type 2 lever
C) none of these
D) type 1 lever
E) type 4 lever
Im pretty sure I know which one just makin sure
This is for my sister
______________________ is the body's normal reaction to help the body return to a more stable temperature when a person is really cold.
pacing
walking
shivering
freezing
Answer:
shivering raises your body temperature
Spring 1 and Spring 2 are the same type of spring. Both springs were pushed or compressed into different positions and clamped into place
L
Which spring has less potential energy?
Answer:
spring 1 has less potential energy
Explanation:
since spring 2 is clampped down further it will have a greater effect but since sping 1 is barely clamped down it wont show as much energy
A 5 kg ball is dropped from a height of 200 meters on Earth.
a) What is the ball’s potential energy at its original height?
Answer:
9800 J
Explanation:
From the question given above, the following data were obtained:
Mass (m) = 5 kg
Height (h) = 200 m
Potential energy (PE) =?
Potential energy (PE) is the energy stored in an object by virtue of its location. Mathematically, it is expressed as:
PE = mgh
Where:
PE => is the potential energy.
m => is the mass of the object.
g => is the acceleration due to gravity.
h => is the height to which the object is located.
With the above formula, we can obtain the potential energy of the ball at its original height as follow:
Mass (m) = 5 kg
Height (h) = 200 m
Acceleration due to gravity (g) = 9.8 m/s²
Potential energy (PE) =?
PE = mgh
PE = 5 × 9.8 × 200
PE = 9800 J
Therefore, the potential energy of the ball at its original height is 9800 J
8 th Grade Physical Science Worksheet Part A: Read the scenario and answer the questions. David read that Fox brake pads and Best Brake pads were the best on the market. He always used NAPA pads and believed they performed the best. He decided to test all three pads and determine which was the best. David used the same car for each set of pads. He drove 25 mph and applied the brakes at the same point on the track. David then measured how many feet the car took to stop after the brakes were applied. 1. The hypothesis was: 2. The effects of the ________________(independent variable) on the __________________________________ (dependent variable). 3. List three constants:
1. What is the value of the acceleration that the car experiences? 2. What is the value of the change in velocity that the car experiences? 3. What is the value of the impulse on the car? 4. What is the value of the change in momentum that the car experiences? 5. What is the final velocity of the car at the end of 10 seconds? The car continues at this speed for a while. 6. What is the value of the change in momentum the car experiences as it continues at this velocity? 7. What is the value of the impulse on the car as it continues at this velocity? The brakes are applied to the car, causing it to come to rest in 4 s. 8. What is the value of the change in momentum that the car experiences? 9. What is the value of the impulse on the car? 10. What is the value of the force (average) that causes the car to stop? 11. What is the acceleration of the car as it stops?
Answer:
All the answers are solved and explained below.
Explanation:
Note: This questions lacks the initial and most necessary data to answer these following questions. I have found a related question. I will be considering that question to carry out the answers.
Question: A car with a mass of 1000 kg is at rest at a spotlight. when the light turns green, it is pushed by a net force of 2000 N for 10 s. (This was the information missing in this question).
Data Given:
m = 1000 kg
F = 2000N
t = 10s
Q1 Solution:
Acceleration = a = ?
F = ma
a = F/m
a = 2000/ 1000
a = 2 [tex]m/s^{2}[/tex]
Q2: Solution:
Change in velocity = Δv = ?
acceleration = change in velocity / time
a = Δv/t
Δv = axt
Δv = 2 x 10
Δv = 20 m/s
Q3: Solution:
Impulse = I = ?
Impulse = Force x time
I = 2000 x 10
I = 20000 Ns
Q4: Solution:
Change in Momentum = Δp = ?
Δp = mΔv
Δp = 1000 x 20
Δp = 20000 Kgm/s
Q5: Solution:
Final velocity of the car at the end of 10 seconds = vf = ?
Δp = m x Δv
Δp = m x (vf-vi)
Δp = 1000 x (vf - 0 )
20000 = 1000 x vf
vf = 20000/1000
vf = 20 m/s
Q6: Solution:
Change in momentum the car experiences as it continues at this velocity?
Δp = ?
Δp = mΔv
Δp = m x (0)
Δp = 0
Q7: Solution:
Impulse = Change in momentum
Impulse = Δp
Implulse = 0
Q8: Solution:
Change in momentum = Δp = mΔv
Δp = m(vf-vi)
Δp = 1000 x (0-20)
Δp = -20000 kgm/s
Q9: Solution:
Impulse = Δp
Impulse = -20000 Ns
Q10: Solution:
Impulse = ?
Impulse = F x t
F = impulse/t
F = -20000/4s
F = -5000 N
Q11: Solution:
F = ma
a = ?
a = F/m
a = -5000/1000
a = -5[tex]m/s^{2}[/tex]
Are vaccines 100% effective and safe for absolutely everyone?
IS BMI = Hight /Weight?
Yes or no ?
Answer:
Yes,BMI is a simple indicator of weight for height and can't differentiate between muscle mass and fat mass. So BMI tends to overestimate the health risk for adults with a high muscle mass, such as some athletes, and underestimate the risk for adults with a low muscle mass, as can occur with sedentary lifestyles.
Explanation:
Hope it is helpful...
what is the name of first magnet
Answer:
[tex]magnetite[/tex]
[tex]hope \: helps...[/tex]
What is the first step in the event of a fire in a building?
A) Call 911.
B) Before opening a door, check to see if it is hot.
C) Stop, drop, and roll.
D) Leave the building quickly, if possible.
Answer:
B or C
Explanation:
i don't if I'm right or not
A cannon shoots a 40 kg ball at a sailing ship and when it hits the
wall of the vessel it applies 2000N of force. How much was it
decelerated?
Answer:
ANSWER : 2000 / 40 = 50 m / s
The PE of an object is 2500 j. What is the mass of the object if it 4.0 m above the ground?
Answer:
The answer is 5.0
Explanation:
Hope that helped :D
Anyone can help?? I need it done before 9am please!!
Answer:
The answer is below
Explanation:
The equation for a linear line graph is given by:
y = mx + b, where y and x are variables, m is the slope of the graph and b is the y intercept (that is value of y when x is zero).
The slope (m) of a line passing through two points [tex](x_1,y_1)\ and\ (x_2,y_2)[/tex] is given by:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]
A) The first line passes through the point (0, 0) and (10, 60). It is represented as (time, velocity). Hence the slope is:
[tex]m=\frac{60 -0}{10-0}=6\ m/min^2[/tex]
B) The second line passes through the point (10, 60) and (15, 60). Hence the slope is:
[tex]m=\frac{60 -60}{15-10}=0\ m/min^2[/tex]
C) The third line passes through the point (15, 60) and (40, -40). Hence the slope is:
[tex]m=\frac{-40 -60}{40-15}=-4\ m/min^2[/tex]
D) The third line passes through the point (40, -40) and (55, 0). Hence the slope is:
[tex]m=\frac{0 -(-40)}{55-40}=2.67\ m/min^2[/tex]
If an object at the surface of the Earth has a weight Wt, what would be the weight of the object if it was transported to the surface of a planet that is one-sixth the mass of Earth and has a radius one third that of Earth
Answer:
We know that the gravitational acceleration in the surface of the Earth can be written as:
g = G*M/r^2
Where:
M = mass of the Earth
r = radius of the Earth.
G = gravitational constant.
The weight of an object of mass m, is written as:
W = m*g = m*(G*M/r^2)
Now, if we move our object to a place that has a mass equal to 1/6 times the mass of the Earth, and 1/3 the radius of the earth.
The gravitational acceleration on this planet is written as:
g' = G*(M/6)/(r/3)^2 = (1/6)*(G*M)/(r^2/9) = (9/6)*(G*M/r^2) = (3/2)*g
then the weight on this planet is:
W' = m*g' = m*(3/2)*g = (3/2)*(m*g)
and m*g was the weight on Earth, then:
W' = (3/2)*(m*g) = (3/2)*W
The new weight is 3/2 times the weight on Earth.
Order the layers, with the oldest at the bottom and most recent at the top.
someone plz help will give brainliest if correct
Answer:
adbce i think
Explanation:
Water enters a shower head through a pipe of radius 0.0112 m at 3.25 m/s. What is it’s volume flow rate? (Unit= m^3/s)
Answer:
[tex]1.28 \times 10 ^{-3} m^3/s[/tex]
Explanation:
Given that the radius of the pipe, r =0.0112 m
So, the area of the cross-section, [tex]a= \pi (0.0112)^2 = 3.941\times 10^{-4} m^2[/tex]
Speed of water in the pipe, v=3.25 m/s
Volume flow rate =[tex]av= 3.941\times 10^{-4} \times 3.25 = 1.28\times 10 ^{-3} m^3/s[/tex]
Hence, the volume flow rate is [tex]1.28 \times 10 ^{-3} m^3/s[/tex]
Answer:
For Acellus the answer is 0.00128
Explanation:
Trust me
The same car now travels on a straight track and goes over a hill with radius 146 m at the top. What is the maximum speed that the car can go over the hill without leaving
Answer:
v = 37.8 m/s
Explanation:
When at the top of the hill, the only force that keeps the car in the circular trajectory, is the centripetal force. This force is not a new force, is just the net force aiming to the center of the circle. In this case, is just the difference between the normal force (always perpendicular to the surface, pointing upward) and the force that gravity exerts on the car (which is known as the weight), pointing downward. So, we can write the following expression:[tex]F_{cent} = F_{g} - F_{n} (1)[/tex]
It can be showed that the centripetal force is related to the speed by the following expression: [tex]F_{cent} = m*\frac{v^{2}}{r} (2)[/tex]Replacing (2) in (1), and solving for Fn, we get: [tex]F_{n} = F_{g} - m*\frac{v^{2}}{r} (3)[/tex] Now, we need to find the value of v that makes Fn, exactly zero, because at a speed greater than this, the car will not be on track anymore.So we can write the following equation: [tex]m*\frac{v^{2}}{r} = F_{g} (4)[/tex] Replacing Fg by its value, simplifying, and solving for v, we get:[tex]v_{max} = \sqrt{g*r} =\sqrt{9.8 m/s2*146 m} = 37.8 m/s (5)[/tex]