Answer:
D. 160 nm
Explanation:
The energy released from n = 3 to n = 1 must be equal to the sum of energies released from n = 3 to n = 2 and from n = 2 to n = 1. Therefore,
Energy of Photon from 3 to 1 = Energy of Photon from 3 to 2 + Energy of Photon from 2 to 1
[tex]\frac{hc}{\lambda} = \frac{hc}{\lambda_{1}} + \frac{hc}{\lambda_{2}}\\\\\frac{1}{\lambda} = \frac{1}{\lambda_{1}} + \frac{1}{\lambda_{2}}[/tex]
where,
λ = wavelength of photon released from 3 to 1 = ?
λ₁ = wavelength of photon released from 3 to 2 = 800 nm
λ₂ = wavelength of photon released from 2 to 1 = 200 nm
Therefore,
[tex]\frac{1}{\lambda} = \frac{1}{800\ nm} + \frac{1}{200\ nm}\\\\\frac{1}{\lambda} = 0.00625 nm^{-1}\\\\\lambda = \frac{1}{0.00625 nm^{-1}}\\\\\lambda = 160 nm[/tex]
Therefore, the correct option is:
D. 160 nm
a total of 15000 ft. lb of work is used to lift a load of bricks to a height of 50 ft. the weight of the bricks is
Answer:
The weight of the brick is 300 lb.
Explanation:
Given that,
The work done in lifting a load of bricks = 15000 ft lb
It is lifted to a height of 50 ft
We need to find the weight of the brick. The work done by an object is given by :
[tex]W=F\times d[/tex]
Here, F = W (weight of the bricks)
[tex]F=\dfrac{W}{d}\\\\F=\dfrac{15000\ ft-lb}{50\ ft}\\\\F=300\ lb[/tex]
So, the weight of the brick is 300 lb.
The weight of the brick will be "300 lb".
Given:
Work done,
15000 ft.lbHeight,
50 ftAs we know the formula,
→ [tex]W = F\times d[/tex]
or,
→ [tex]F = \frac{W}{d}[/tex]
By substituting the values, we get
→ [tex]= \frac{15000}{50}[/tex]
→ [tex]= 300 \ lb[/tex]
Thus the response above is right.
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What's the quantum number for a particle in an infinite square well if the particle's energy is 64 times the ground-state energy?
Answer:
8
Explanation:
The energy levels is given as
E(n) = n² * h² / ( 8 * m * L²), where
n = 1, 2, 3, 4,... etc
At ground state energy (n = 1), therefore is E(g) = h² / (8 * m * L²).
We can then say that
E(n) = n² * Eg
Therefore, to have E = 64 Eg, we must have n² = 64. And for n² to be equal to 64, we find the square root of n
n = √64
n = 8
Essentially, the needed quantum number is 8
The angle between an incident
ray and the mirror is 40°.
1) What is the angle of reflection?
Answer:
1) 50°
Explanation:
We need to find the angle of incidence first before finding the angle of reflection.
Angle of incidence = 90° - 40°
= 50°
Since the angle of incidence is the same as the angle of reflection, the angle of reflection here would be 50°.
12 ounces of beer plus 12 ounces of wine plus 3 ounces of liquor = how
many "drinks"?
6 drinks
7 drinks
12 drinks
PLS HURRY
Answer:
12 ounces of beer plus 12 ounces of wine plus 3 ounces of liquor are equivalent to 6 drinks.
Explanation:
In the United States, a standard "drink" of beer has 12 ounces, a standard "drink" of wine has 5 ounces and standard drink of liquor has 1.5 ounces. Then, we obtain the quantity of drinks by dividing the total volume of each drink by its respective unit volume and summing each term. That is:
[tex]N = \frac{12\,oz}{12\,\frac{oz}{dr} }+\frac{12\,oz}{5\,\frac{oz}{dr} }+\frac{3\,oz}{1.5\,\frac{oz}{dr} }[/tex]
[tex]N = 1\,dr+2.4\,dr+2\,dr[/tex]
[tex]N = 5.4\,dr[/tex]
[tex]N = 6\,dr[/tex]
12 ounces of beer plus 12 ounces of wine plus 3 ounces of liquor are equivalent to 6 drinks.
Indentify the following types of reflection.
Answer:
first is regular reflection and 2nd is irregular
Point charges are located at 3, 8, and 11 cm along the x-axis(+q, -2q, +q). What is the x-component of the force on the charge located at x=8 cm given that q=1.15nc?
Answer:
Approximately [tex]1.69 \times 10^{-23}\; {\rm N}[/tex].
Explanation:
Look up the value of Coulomb's Constant: [tex]k \approx 8.988 \times 10^{-9}\; {\rm N \cdot m^{2} \cdot C^{-2}}[/tex].
Consider point charges of magnitude [tex]q_{1}[/tex] and [tex]q_{2}[/tex]. If the distance between these charges is [tex]r[/tex], the magnitude of the electrostatic force between them would be [tex](k\, q_{1}\, q_{2}) / (r^{2})[/tex].
In this question, the two [tex](+q)[/tex] charges are [tex]5\; {\rm cm}[/tex] and [tex]3\; {\rm cm}[/tex] away from the center [tex](-2\, q)[/tex] charge, respectively. Convert units to standard unit of distance (meters, [tex]{\rm m}[/tex]) and charge (coulombs, [tex]{\rm C}[/tex]):
[tex]q = 1.15 \; {\rm nC} = 1.15 \times 10^{-9}\; {\rm C}[/tex].
[tex]\begin{aligned} 5\; {\rm cm} = 5\; {\rm cm} \times \frac{1\; {\rm m}}{100\; {\rm cm}} = 0.05\; {\rm m} \end{aligned}[/tex].
[tex]\begin{aligned} 3\; {\rm cm} = 3\; {\rm cm} \times \frac{1\; {\rm m}}{100\; {\rm cm}} = 0.03\; {\rm m} \end{aligned}[/tex].
The magnitude of the electrostatic forces on the [tex](-2\, q)[/tex] charge would be:
[tex]\begin{aligned}\frac{k\, q_{1}\, q_{2}}{r^{2}} &\approx \frac{1}{(0.05\; {\rm m})^{2}} \\ &\quad \times (8.988 \times 10^{-9}\; {\rm N \cdot m^{2} \cdot C^{-2}})\\ &\quad \times ((-2) \, (1.15\times 10^{-9}\; {\rm C}))\, (1.15\times 10^{-9}\; {\rm C})) \\ &\approx 9.509\times 10^{-24}\; {\rm N}\end{aligned}[/tex].
[tex]\begin{aligned}\frac{k\, q_{1}\, q_{2}}{r^{2}} &\approx \frac{1}{(0.03\; {\rm m})^{2}} \\ &\quad \times (8.988 \times 10^{-9}\; {\rm N \cdot m^{2} \cdot C^{-2}})\\ &\quad \times ((-2) \, (1.15\times 10^{-9}\; {\rm C}))\, (1.15\times 10^{-9}\; {\rm C})) \\ &\approx 2.641\times 10^{-23}\; {\rm N}\end{aligned}[/tex].
Since the charges are of opposite sign, the [tex](-2\, q)[/tex] charge would attract both of the [tex](+q)[/tex] charges. In particular, the (approximately) [tex]9.509\times 10^{-24}\; {\rm N}[/tex] force would point to the left. The (approximately) [tex]2.641 \times 10^{-23}\; {\rm N}[/tex] force would point to the right.
As a result, the net force on the [tex](-2\, q)[/tex] charge would point to the right. The magnitude of the net force on this charge would be approximately [tex]2.641 \times 10^{-23}\; {\rm N} - 9.509\times 10^{-24}\; {\rm N} \approx 1.69 \times 10^{-23}\; {\rm N}[/tex].
AN AUTOMBILE IS TRAVELING AT 20 M/S. IT BEGINS TO ACCELERATE AT 3.8 M/S2 FOR 1.5S. HOW FAR DOES IT TRAVEL IN THOSE 1.5 SECONDS?
The distance that automobile travel in 1.5 seconds is (S)= 34.275 m.
What is distance?Distance is a scaler quantity that refers to "how much ground an object has covered" during its motion of time.
How can we calculate the amount of distance that automobile travel?To calculate the distance that automobile travel in 1.5 seconds, we are using the formula,
S= ut+(1/2)at²
Here we are given,
u= The initial velocity of the automobile = 20 m/s
t = The amount of time that the automobile travel = 1.5 Seconds.
a=The amount of acceleration of the automobile = 3.8 m/s².
We have to calculate the distance that automobile travel in 1.5 seconds = S
Now, we put the values in the above equation, we get
S= ut+(1/2)at²
Or, S= 20*1.5+(1/2)*3.8*(1.5)²
Or, S= 30+4.275
Or, S= 34.275m
Thus we can conclude that, the distance that automobile travel in 1.5 seconds is (S)= 34.275 m.
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What did kind of energy did the ruler gain when you bent it with your left hand? why?
Answer:
potential energy
Explanation:
The bent ruler possesses elastic potential energy.
• The bending of the ruler depends upon the material of which it is made up of.
• The ruler after bending will gain elastic potential energy.
• The energy stored as an outcome of applying a force to deform an elastic object is known as the elastic potential energy.
• This energy is stored unless and until the removal of force takes place and the ruler moves back to its original shape.
• When the energy is released or when the bent ruler is released from the left hand, then the potential energy stored in it gets convert to kinetic energy and the ruler will recoil or vibrate briskly.
Thus, it is the elastic potential energy gained by the ruler when one bent it with the left hand.
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A 100 g ball collides elastically with a 300 g ball that is at rest. If the 100 g ball was traveling
in the positive x-direction at 6.20 m/s before the
collision, what are the velocities of the two
balls after the collision?
Answer:
The magnitude of the velocities of the two balls after the collision is 3.1 m/s (each one).
Explanation:
We can find the velocity of the two balls after the collision by conservation of linear momentum and energy:
[tex] P_{1} = P_{2} [/tex]
[tex] m_{1}v_{1_{i}} + m_{2}v_{2_{i}} = m_{1}v_{1_{f}} + m_{2}v_{2_{f}} [/tex]
Where:
m₁: is the mass of the ball 1 = 100 g = 0.1 kg
m₂: is the mass of the ball 2 = 300 g = 0.3 kg
[tex]v_{1_{i}}[/tex]: is the initial velocity of the ball 1 = 6.20 m/s
[tex]v_{2_{i}}[/tex]: is the initial velocity of the ball 2 = 0 (it is at rest)
[tex]v_{1_{f}}[/tex]: is the final velocity of the ball 1 =?
[tex]v_{2_{f}}[/tex]: is the initial velocity of the ball 2 =?
[tex] m_{1}v_{1_{i}} = m_{1}v_{1_{f}} + m_{2}v_{2_{f}} [/tex]
[tex] v_{1_{f}} = v_{1_{i}} - \frac{m_{2}v_{2_{f}}}{m_{1}} [/tex] (1)
Now, by conservation of kinetic energy (since they collide elastically):
[tex] \frac{1}{2}m_{1}v_{1_{i}}^{2} = \frac{1}{2}m_{1}v_{1_{f}}^{2} + \frac{1}{2}m_{2}v_{2_{f}}^{2} [/tex]
[tex] m_{1}v_{1_{i}}^{2} = m_{1}v_{1_{f}}^{2} + m_{2}v_{2_{f}}^{2} [/tex] (2)
By entering equation (1) into (2) we have:
[tex] m_{1}v_{1_{i}}^{2} = m_{1}(v_{1_{i}} - \frac{m_{2}v_{2_{f}}}{m_{1}})^{2} + m_{2}v_{2_{f}}^{2} [/tex]
[tex] 0.1 kg*(6.20 m/s)^{2} = 0.1 kg*(6.2 m/s - \frac{0.3 kg*v_{2_{f}}}{0.1 kg})^{2} + 0.3 kg(v_{2_{f}})^{2} [/tex]
By solving the above equation for [tex]v_{2_{f}}[/tex]:
[tex]v_{2_{f}} = 3.1 m/s [/tex]
Now, [tex]v_{1_{f}}[/tex] can be calculated with equation (1):
[tex] v_{1_{f}} = 6.20 m/s - \frac{0.3 kg*3.1 m/s}{0.1 kg} = -3.1 m/s [/tex]
The minus sign of [tex] v_{1_{f}}[/tex] means that the ball 1 (100g) is moving in the negative x-direction after the collision.
Therefore, the magnitude of the velocities of the two balls after the collision is 3.1 m/s (each one).
I hope it helps you!
2
Look at the circult dlagram.
Direction
of current
Battery
Bulb-
What type of circuit is shown?
A. open series circult
B. closed series circuit
C. open parallel circult
D. closed parallel circult
The direction of the current from the positive to the negative battery terminals and the fact that the bulbs are connected in parallel to each other suggests that this circuit is a Closed Parallel Circuit. The correct option is D.
What is the difference between open and closed circuits?An open circuit and a closed circuit are two types of electrical circuits that describe the flow of electrical current through a circuit.
An open circuit is a circuit in which there is a break in the path of the current, meaning that the current cannot flow through the circuit. In an open circuit, the switch is in the "off" position or there is a broken wire, and so no electrical current can flow through the circuit. This means that there is no voltage or electrical energy being transferred from the source to the load.
On the other hand, a closed circuit is a circuit in which there is a complete path for the current to flow through, meaning that the current can flow through the circuit. In a closed circuit, the switch is in the "on" position, and there is a continuous path for the current to flow from the source to the load and back to the source. This means that there is voltage and electrical energy being transferred from the source to the load.
Here in this question,
The direction of the current from the positive to the negative battery and the fact that the bulbs are connected in parallel to each other suggests that this circuit is a Closed Parallel Circuit.
In a closed parallel circuit, the components are connected in parallel to each other, meaning that they are connected to the same two points in the circuit and the current has multiple paths to flow through. The voltage across each component is the same, and the total current flowing through the circuit is divided among the components according to their resistance.
In contrast, an open series circuit is a circuit in which the components are connected in series, meaning that they are connected end to end in a single path, with no other branch points for the current to follow. If one component fails, the circuit becomes open and the current stops flowing.
Therefore, based on the information provided, the circuit described in the question is a Closed Parallel Circuit.
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What is the frequency of a wave that has a period of 0.5 seconds?
A. 0.5 Hz
B. 2 Hz
C. 200 Hz
D. 20 Hz
Answer:
B. 2 Hz
Explanation:
Given parameters:
Period of the wave = 0.5Hz
Unknown:
Frequency of the wave = ?
Solution:
Frequency is the number of waves that passes through a point.
Period is the time taken for a number of waves to pass through a point.
Period is the inverse of frequency
Frequency = [tex]\frac{1}{t}[/tex]
t is the period
Frequency = [tex]\frac{1}{0.5}[/tex] = 2Hz
Answer:2
Explanation:
During a group project, two students constructed a simple machine to add to their Rube Goldberg project. They were told to create one that demonstrates the concept of force-distance tradeoff. One student created model A and the other students created model B.
image
Using the CER method, which model best demonstrates the force-distance tradeoff and why?
Answer:
Image B
Explanation:
although I'm not exactly sure, i've recently gotten this question as well. but model B demonstrates the force- distance trade off because you can see how in that image them distance is increased in the force is decreased with the object being shorter. hopefully this helps in some way
A cannonball is fired at a 45.0° angle and an initial velocity of 670 m/s. Assume no air resistance. What is the vertical component of the cannonball’s velocity? What is the horizontal component of the cannonball’s velocity?
473.8 m/s; 473.8 m/s
-525.2 m/s; 435.5 m/s
0 m/s; 670 m/s
-378 m/s; 378 m/s
Answer:
473.8 m/s; 473.8 m/sExplanation:
Given the initial velocity U = 670m/s
Horizontal velocity Ux = Ucos theta
Vertical component of the cannon velocity Uy = Usin theta
Given
U = 670m/s
theta = 45°
horizontal component of the cannonball’s velocity = 670 cos 45
horizontal component of the cannonball’s velocity = 670(0.7071)
horizontal component of the cannonball’s velocity = 473.757m/s
Vertical component of the cannonball’s velocity = 670 sin 45
Vertical component of the cannonball’s velocity = 670 (0.7071)
Vertical component of the cannonball’s velocity = 473.757m/s
Hence pair of answer is 473.8 m/s; 473.8 m/s
After concluding his research, which statements would Virchow agree with? Check all that apply.
O Living things come from nonliving things.
Cells can come from nonliving materials.
Frogs can come from mud.
O Living things can only
comeyom living things.
Cells come from pre-existing cells.
Answer:
A Living things can only come from living things.
B Cells come from pre-existing cells.
Explanation:
sorry if wrong e d g e 2022
Answer: D,E
Explanation:
I JUST TOOK IT
a train traveling at 48 m/s begins to slow down as it approaches a bend in the tracks. if it travels around the bend at a speed of 14 m/s and it takes 40 seconds to properly slow down what is the acceleration acting on the train during this time?
Answer:
The acceleration acting on the train during this
time of travel is 0.85m/s²
HOW TO CALCULATE ACCELERATION:
• The acceleration of a moving body can be calculated by using the formula below:
a = (v - u)/t
Where;
1. a = acceleration (m/s²)
2. v = final velocity (m/s) 3. u = initial velocity (m/s)
4. t = time (s)
According to this question, a = ?, v = 48m/s, u = 14m/s, t = 40s.
= (48 - 14)/40 a=
• a = 34/40
• a = 0.85m/s²
Therefore, the acceleration acting on the train during this time of travel is 0.85m/s².
Hope this helps!
Don't forget to mark me as Brainliest.
A crate of oranges on a horizontal floor has a mass of 30 kg. The coefficient of static friction is 0.62. The coefficient of kinetic friction is 0.52. The worker pulls the crate with a force of 200 N.
What is the equation to calculate the kinetic friction?
What is the kinetic friction on the crate?
Answer:
[tex]Fr_k=152.88\ N[/tex]
Explanation:
Net Force
The net force is defined as the vector sum of all the forces acting on a body at a certain moment.
We should recall some basic concepts and equations to solve the problem.
If no external forces are applied in the vertical direction, the weight of the object and the normal force have the same magnitude and point to opposite directions.
The friction force is defined as:
[tex]Fr_k=\mu_k N[/tex]
[tex]Fr_s=\mu_s N[/tex]
Where the subindices k and s are referred as to the kinetic and static friction forces respectively.
The condition for the object to move is that the applied force is greater than the friction force.
The crate of oranges has a mass of 30 Kg, thus its weight is:
W = m.g = 30 * 9.8 = 294 N
The normal force is:
N = W = 294 N
The kinetic friction is calculated as:
[tex]Fr_k=0.52* 294[/tex]
[tex]\mathbf{Fr_k=152.88\ N}[/tex]
What is the total charge of barium oxide?
what is the object's position at 6s?
Answer:
6sec and 8 postion
Explanation:
Which of these would have a high velocity? * O zamboni lamborgini O shopping cart O golf cart Search A
Golf carts have a high velocity.
Without any improvements, the conventional golf cart's peak velocity is between 12 and 14 miles per hour. The highest velocity that you can get on a golf cart without any upgrades or modifications is around 14 mph.
We can determine how quickly or slowly an item is traveling using the phrases velocity and speed. It occurs to us frequently that we must determine which of two or more moving things is traveling quicker. If both vehicles are traveling in the same direction along the same route, it is simple to determine which is quicker. It is challenging to identify who is moving quickest when their direction of motion is opposing. The idea of velocity is useful in these situations.
When gravity first exerts force on an item, its initial velocity defines how quickly the thing moves. The final velocity, on the other hand, is a vector number that gauges a moving body's speed and direction after it has attained its maximum acceleration.
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How do objects at rest and in motion respond in the presence of an external, unbalanced force?
Explanation:
Objects at rest and in motion respond to the presence of an external unbalanced force by simple changing their magnitude of motion or position.
We have this knowledge from Newtons first law of motion "a body will remain in a state of rest or continue with uniform motion unless if it is acted upon by an external force".
When an external force acts on a body at rest, it will change the position of the body or set it motion. For a body in motion, an external force can make they come to rest or change the motion of the bodyThe illustration shows a roller coaster and indicates four different positions the car might be at as it moves along the track. Identify at which point in the roller coaster's journey does it have the least potential energy and explain why. w
Answer:
I got this question on Ap3x. The answer is Car C...I got it correct
Explanation:
This is because Car C is at the lowest point with the lowest amount of potential energy. Potential energy is stored at it's highest when it has the "potential" to fall, move, or etc. Car C seems to have gone farther down from the high point of the slope, meaning that most of the potential energy transformed into kinetic energy. All in all, Car C has the least potential energy. (Please give Brainliest, or not...your choice but this is the first question that I answered)
A football is kicked at an angle of 35° with a speed of 26 m/s.
To the nearest second, how long will the ball stay in the air?
The amount of time the ball stay in the air is (t)=3.04 Seconds
What is time?The best example that would help us understand and know what time are the clock and the calendar. This clock gives us the exact hour, minutes and seconds. The calendar tells us the exact day, month and year.
How can we calculate the time?To calculate the amount of time the ball stay in the air, we are using the formula,
T=2Vsinθ/g
Here we are given,
V= The velocity of the football.=26 m/s.
θ= The angle that the football makes in the air= 35°
g= The acceleration due to gravity = 9.8 m/s².
We have to calculate, the amount of time the ball stay in the air = T
Now, we put the known values in the above equation,
T=2Vsinθ/g
Or, T= 2*26*sin (35°)/9.80
Or, T= 3.04 Seconds.
Thus, from the above calculation we can conclude that the amount of time the ball stay in the air is (t)=3.04 Seconds
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what kind of law of motion A car still moves for a short period even after the brakes
have been applied.
Answer:
inertia of motionExplanation:
.... ...
Explain how the situation shown above would be different if the skier experiences friction while traveling downhill. Include the terms kinetic energy, heat energy, mechanical energy, total energy and friction. Must answer in complete sentences.
Answer:
The force of friction acts in the direction opposite to the direction of motion. If friction would have been applied to the skier it would have resulted in a lower velocity and less kinetic energy.
Explanation:
Uranium-235 undergoes fission, forming krypton-92, barium-141, and 3
neutrons. The mass of the uranium-235 is greater than the total mass of the
products. Which statement explains this difference in mass?
A. Some of the mass was transformed into neutrons during the
process.
O B. Mass was destroyed and disappeared during the process.
C. Some of the mass was transformed into gases during the
process.
D. Mass was transformed into energy during the process.
Answer:
C
Explanation:
Some of the mass
Answer:
D. Mass was transformed into energy during the process.
The speed of sound in air is approximately 340 m/s. The speed of light in air is approximately 3 x 108 m/s. If 10 seconds elapses between seeing a lightning strike and hearing the thunder, how far away was the lightning strike?
Answer:
3400 m
Explanation:
Both lightning and thunder happen at the same time but one is faster than the other. The distance traveled by a sound can be calculated from its speed such that;
speed = distance/time, hence, distance = speed x time.
For a thunder with 340 m/s speed and 10 seconds away from lightning, the distance between the thunder and the lightning can be calculated as;
distance = 340 m/s x 10 s = 3400 m
Conveyor belts are often used to move packages around warehouses. The conveyor shown below moves packages at a steady 4.0 m/s. A 500 N employee decides to catch a ride by sitting on a 1,000 N box for a 50 m trip as shown below:
What is the work done by the employee on the box?
Answer:
0 j
Explanation:
The work done by the employee on the box at the given zero displacement is 0 J.
The given parameters;
Constant velocity of the conveyor, v = 4 m/sWeight of the employee, W = 500 NWeight of the box, W = 1,000 NDistance of the trip, h = 50 mThe work done by the employee on the box is calculated as follows;
W = Fd
where;
F is the applied force on the box by employee = weight of the employeed is the distance through which the box is movedSince the employee sits on the box without moving it, the distance moved by the box = 0
W = 500 x 0
W = 0 J
Thus, the work done by the employee on the box is 0 J.
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Which diagram shows how Rachel can see a candle flame?
Answer:
C
Explanation:
If the arrows represent light rays, then Rachel sees a candle flame when the light released by the flame is received by her eyes.
Diagram C shows how Rachel can see a candle flame.
What is an Image?This is the visual representation of a substance and the organ responsible for this is the eye.
Images are formed through the eyes receiving light sensations and and relaying it to the brain for processing. The line is the light sensation which shows it being received by the eye therefore making option C the most appropriate option.
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A cylinder is fitted with a piston, beneath which is a spring, as in the drawing. The cylinder is open to the air at the top. Friction is absent. The spring constant of the spring is 3400 N/m. The piston has a negligible mass and a radius of 0.028 m. (a) When the air beneath the piston is completely pumped out, how much does the atmospheric pressure cause the spring to compress
Answer:
x = 0.0734 m = 7.34 cm
Explanation:
First we shall calculate the area of the piston:
[tex]Area = \pi radius^2\\Area = \pi (0.028\ m)^2\\Area = 0.00246\ m^2[/tex]
Now, we will calculate the force on the piston due to atmospheric pressure:
[tex]Atmospheric\ Pressure = \frac{Force}{Area}\\\\Force = (Atmospheric\ Pressure)(Area)\\Force = (101325\ N/m^2)(0.00246\ m^2) \\Force = F = 249.56\ N[/tex]
Now, for the compression of the spring we will use Hooke's Law as follows:
[tex]F = kx\\[/tex]
where,
k = spring constant = 3400 N/m
x = compression = ?
Therefore,
x = 0.0734 m = 7.34 cm
A rock from a volcanic eruption is launched straight up into the air with no appreciable resistance Which one of the following statements about this rock while it is in the air is correct