a copper wire that is 1 mm thick and 30 cm long is connected to a 1 v battery. (the resistivity of copper is 1.69 x 10-8 ω⋅m.)

Answers

Answer 1

A copper wire that is 1 mm thick and 30 cm long is connected to a 1 v battery. (the resistivity of copper is 1.69 x 10-8 ω⋅m). The power is 154.82 W.

As we know the formula of Power:

P = V²/R ......(i)

Where,

P = power dissipated, V = voltage R = resistance

Now,

R = Lρ/A .....(ii)

Where,

L = length of the wire, A = cross-sectional area,  ρ = resistivity of the wire.

From eq (i) and eq(ii),

P = V²/(Lρ/A)

P = AV²/Lρ........ (iiI)

Here,

A = πd²/4, Where d = 1 mm

A = (3.14×0.001²/4) = 7.85×10⁻⁷ m²

Putting the value of A and the given values from the question in equation (iii).

P = (7.85×10⁻⁷×1²)/(0.3×1.69 x 10⁻⁸)

P = 154.82 W

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Related Questions

A flywheel has a radius of 20. 0cm.What is the speed of a point on the edge of
the flywheel if it experiences a centripetal acceleration of 900.0cm/s 2 ?

Answers

Given that,

The radius of a flywheel, r = 20 cm = 0.2 m

The centripetal acceleration experienced on the edge of the flywheel = 900 cm/s² = 9 m/s²

To find,

The speed of a point on the edge.

Solution,

The formula for the centripetal acceleration is given by :

[tex]a=\dfrac{v^2}{r}\\\\v=\sqrt{ar} \\\\v=\sqrt{9\times 0.2} \\\\=1.34\ m/s[/tex]

Hence, the required speed is 1.34 m/s

The speed of a point on the edge of  the flywheel is 134.16cm/s

The formula for calculating the centripetal acceleration of the flywheel is expressed as:

[tex]a=\frac{v^2}{r}[/tex]

where;

v is the speed of the flywheel

r is the radius of the wheel

Given the following parameters

r = 20.0cm

a = 900cm/s²

Substituting the given parameters into the formula above;

[tex]900=\frac{v^2}{20}\\v^2=900\times 20\\v^2=18,000\\v=\sqrt{18,000}\\v= 134.16cm/s[/tex]

Hence the speed of a point on the edge of  the flywheel is 134.16cm/s

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why does a star go through a cycle?

Answers

Answer:

the sun

Explanation:

that is how the solar system works

The information gathered in an investigation is called _________.

Answers

Answer:

Evidence

Explanation:

Two cats jump off a roof that is 23m off the ground. Cat A jumps directly up with a velocity of 7m/s, and cat B jumps directly down with a velocity of 7m/s. How far up does cat A go? How fast does cat A go just before it hits the ground? How fast does cat B go just before it hits the ground? How much longer is cat A in the air than cat B?

Answers

(1) The height reached by cat A is 2.5 m.

(2) The speed of cat A before it hits the ground is 36.4 m/s.

(3) The speed of cat B before it hits the ground is 22.39 m/s.

(4) The time spent in air by cat A than cat B is 1.43 seconds.

Time of motion of cat A

The time of motion of cat A is calculated as follows;

h = vt - ¹/₂gt

-23 = 7t - 4.9t²

4.9t² - 7t - 23 = 0

solve the quadratic equation using formula method;

a = 4.9, b = -7, c = - 23

t = 3.0 seconds

Time of motion of cat B

The time of motion of cat B is calculated as follows;

h = vt - ¹/₂gt

23 = 7t + 4.9t²

4.9t² + 7t - 23 = 0

solve the quadratic equation using formula method;

a = 4.9, b = 7, c = -23

t = 1.57 seconds

Height reached by cat A

h = u²/2g

h = (7²)/(2 x 9.8)

h = 2.5 m

Speed of cat A before it hits the ground

v = u + gt

v = 7  + 3(9.8)

v = 36.4 m/s

Speed of cat B before it hits the ground

v = u + gt

v = 7  + 1.57(9.8)

v = 22.39 m/s

Time spent in air by cat A than cat B

Time difference = 3 s - 1.57 s = 1.43 seconds

Thus, the height reached by cat A is 2.5 m.

The speed of cat A before it hits the ground is 36.4 m/s.

The speed of cat B before it hits the ground is 22.39 m/s.

The time spent in air by cat A than cat B is 1.43 seconds.

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When water turns to ice:
1. The distances between the molecules increase, 2. Heat is released into the environment, 3. The temperature of the ice does not change during the transformation, 4. All statements are correct.

Answers

Answer:

1

Explanation:

How do we determine the conditions that existed in the very early universe? A We can only guess at the conditions, since we have no way to calculate or observe what they were. B The conditions in the very early universe must have been much like those found in stars today, so we learn about them by studying stars. C From the current expansion rate we can work backward to estimate temperature and densities at various times in the early universe. D By looking all the way to the cosmological horizon, we can see the actual conditions that prevailed all the way back to the first instant of the Big Bang.

Answers

Answer:

D By looking all the way to the cosmological horizon, we can see the actual conditions that prevailed all the way back to the first instant of the Big Bang.

Explanation:

Astrophysicists are able to determine the conditions that existed in the early universe, by using instruments such as telescopes to observe and study cosmic horizons. More ideas about the early universe can be found from the thermal light present in cosmic backgrounds.

Scientists study these details that provide an insight into the conditions that existed so many years ago. They have been able to determine that the Big Bang involved so many collisions from these observations.

What two kinds of energy are part of thermal energy?

Answers

Answer:

Many forms of energy exist, but they all fall into two basic categories:

Potential energy.Kinetic energy.

Explanation:

Thermal energy is due to the movement, and the kinetic energy associated with this movement, of molecules that make up an object or substance.

Hoped I helped U!! ❤️

Answer:

1.) mechanical energy and 2.) potential energy

Explanation:

Sound is made up of vibrations thermal energy consists of moving molecules in air or in an object, and mechanical energy is the combination of kinetic and potential energy of a moving object.

I hope this helps!!!!

please help me on this!

A rock has been sent on a journey down through the layers of the Earth until it reaches the inner core. Explain what happens to the atoms in the rock as it moves through each layer.

Answers

Answer:

erosion

Explanation:

grows into the eirth each year. the atmosphere and how the worldchanges every year

A uniform electric field exists in a region of space containing no charges. What can you conclude about the net electric flux through a gaussian surface placed in this region of space?

Answers

The net electric flux in such gaussian surface is zero.

In a uniform electric field existing in a region of space and contains no charge, it is impossible for there to be an electric flux in such space. This is because flux generated in an electric field is a product of the charge and the permittivity of the free space.

In other words, every field line sent into a given closed surface continues through the interior and is typically directed outward somewhere on the surface if there is no provided net charge there. The net or total electric flux is zero because the negative flux barely equals the positive flux in magnitude.

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Gases, just like liquids are made of particles which can be further classified as atoms or molecules,
True
False

Answers

Answer:

True

Explanation:

Solids, Liquids, and Gases are all make up of atoms and molecules.

Coach carver has created a new team game for his students to play it involves sprinting tagging and throwing a ball

Answers

Coach Carver has created a new team game for his students to play. It involves sprinting, tagging, and throwing a ball. Each team consists of 10 to 20 students. Which place is the safest to play the game

Answer:

Football Field

Explanation:

In sporting or gaming activities that involve sprinting, tagging, and throwing a ball. The safest place to play the game is "FOOTBALL FIELD"

This is because the football field is originally designed and created for footballing activities which are deemed spacious and free of danger. There is also evidence in the Olympic sporting activities.

Therefore, in this case, even though there is no option in the question, the correct answer is the Football field.

picture is attached with question ​

Answers

59.00 m is the calculated distance.

Distance is the sum of an object's movements, regardless of direction. Distance can be defined as the amount of space an object has covered, regardless of its starting or ending position. The International System of Units defines a meter as the distance unit. It's interesting to note that many other derived units or quantities, such as volume, area, acceleration, and speed, may be constructed using this as the basic unit and a few formulae.

V = V₀ + at = 4.30 + 3.00*5.00 = 19.30 m/s

d = V₀t + (1/2) at²

= 4.30*5.00 + (1/5.00) ² = 59.00 m

or

d = (1/2) (V₀+V) t

= (1/2) (4.30+19.30) (5.00)

= 59.00 m

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draw the schematic of a circuit where there are now two capacitors in parallel with each other, and in series with the battery, switch, and resistor.

Answers

This is the schematic of a circuit where there are two capacitors in parallel with each other, and in series with the battery, switch, and resistor.

What is resistor?

A resistor is a two-terminal electrical component that produces electrical resistance in circuits. In electrical circuits, resistors can limit current flow, regulate signal levels, divide voltages, bias active components, and terminate transmission lines, among other functions. High-power resistors can be used as test loads for motor controllers, power distribution systems, and generators because they can produce many watts of heat instead of electrical energy. Only sporadically can variations in operating voltage, period of operation, or temperature affect the resistance of fixed resistors. Variable resistors can be used as humidity sensors, chemical activity sensors, force sensors, heat sensors, light sensors, volume controls, lamp dimmers, and light sensors. Resistors are frequently used in both electrical networks and technological gadgets.

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A player hits a ball with a bat. The action is the force of the bat against the ball.
What is the reaction to this force?

Answers

Answer:

Force of the ball against the bat

Explanation:

Newton's third law of motion states that for every action, there is an equal and opposite reaction. When a player hits a ball with a bat, the force the player exerted on the ball through the bat gave the ball a push force in the forward direction. This is an action force. Now that an action has been initiated, there must be a reaction according to Newton's third law of motion. The magnitude of the force on the ball equals the magnitude of the force on the bat. The direction of the force on the ball is opposite to the direction of the force on the ball. The ball will give the bat an equal and opposite force trying to push the bat backward by resisting the impact of the bat. This is the reaction. The ball will only move if the applied force is able to overcome the resisting force by the bat.

Where;

is the action force of the bat against the ball.

is the equal and opposite reaction force of the ball towards the ball.

2. A person lifts 200kg seven times over the course of 11.8s. If they displaced the weight 2.2m up each time, how much power did the person deliver?​

Answers

Answer:

The person delivered a power of 2,558 Watt

Explanation:

Work and Power

Mechanical work is the amount of energy transferred by a force. It's a scalar quantity, with SI units of joules.

Being  the force vector and  the displacement vector, the work is calculated as:

[tex]W=\vec F\cdot \vec s[/tex]

If both the force and displacement are parallel, then we can use the equivalent scalar formula:

W=F.s

Power is the amount of energy transferred per unit of time. In the SI, the unit of power is the watt, equivalent to one joule per second.

The power can be calculated as:

[tex]\displaystyle P=\frac {W}{t}[/tex]

Where W is the work and t is the time.

If the person lifts a mass of m=200 Kg, then exerts a force equal to its weight:

F = m.g = 200*9.8 = 1,960

F = 1,960 N

The work done when lifting the weight 7 times by a distance of s=2.2 m is:

W = 7*1,960*2.2=30,184

W = 30,184 J

Finally, the power delivered in t=11.8 seconds is:

[tex]\displaystyle P=\frac {30,184}{11.8}[/tex]

P = 2,558 Watt

The person delivered a power of 2,558 Watt

Calculate the centripetal force of a ball on a string in circular motion if the mass is 7 kg
traveling at 3 m/s and the radius of the string is 4 meters.
0 11 N
0 14 N
0 16 N
0 25 N

Answers

Answer:

F = 16 N

Explanation:

Given that,

Mass of the ball, m = 7 kg

Speed of the ball in circular motion, v = 3 m/s

The radius of the string, r = 4 m

We need to find the centripetal force of a ball on a string in circular motion. The formula for the centripetal force is given by :

[tex]F=\dfrac{mv^2}{r}[/tex]

Putting all the values in the above formula

[tex]F=\dfrac{7\times (3)^2}{4}\\\\=15.75\ N[/tex]

or

F = 16 N

Hence, the correct option is (c).

Of there was no matter to vibrate, How will this affect a sound?

1. This sound would be louder.
2. The sound would have higher pitch.
3. There would be no sound.
4. The sound would have a lower pitch

Answers

Answer:

3. There would be no sound.

Explanation:

Sound is produced by vibrations that travel through a medium, most commonly through air.

If there is no matter to vibrate (such as in the vacuum of space) then there's no way for a sound wave to be produced.

Thus the answer is option 3. There would be no sound.

A representation of a chemical reaction that uses symbols to show the relationship between the reactants and the products is called a __________. a. symbolic statement b. chemical equation c. mole ratio d. chemical proportion

Answers

Answer:

B. chemical equation.

Explanation:

This explained to be a short method of representing different symbols and structures that are seen to make up a chemical reaction. It is known to have been formulated by a French chemist Jean Beguin. In a course of writing a chemical reaction, its reaction is seen to show a starting compound which is been written on the left hand side of the said equation while the product is written by the right hand side and are separated in different directions by an arrow. When this is done, charges on this equation that is balanced is also written on each side of the equation.

obtain derivatives of x/sinx​

Answers

Answer:

[tex]\displaystyle \frac{x}{\sin x} = \sum^{\infty}_{n = 0} \frac{(2n + 1)!}{(-1)^nx^{2n}}[/tex]

General Formulas and Concepts:

Calculus

Differentiation

DerivativesDerivative Notation

Sequences

Series

Taylor Polynomials

MacLaurin Polynomial:                                                                                 [tex]\displaystyle P_n(x) = \frac{f(0)}{0!} + \frac{f'(0)}{1!}x + \frac{f''(0)}{2!}x^2 + \frac{f'''(0)}{3!}x^3 + \cdots + \frac{f^n(0)}{n!}x^n + \cdots[/tex]

Power Series

Power Series of Elementary FunctionsMacLaurin SeriesTaylor Series

Explanation:

*Note:

You could derive the Taylor Series for sin(x) using Taylor polynomials by differentiation by usually you have it memorized.

We want to obtain an infinite amount of derivatives of the given:

[tex]\displaystyle \frac{x}{\sin x}[/tex]

We know that a power series is defined as an infinite derivatives of a function. We know that the power series for sin(x) is:

[tex]\displaystyle \sin x = \sum^{\infty}_{n = 0} \frac{(-1)^nx^{2n + 1}}{(2n + 1)!}[/tex]

Divide x by the power series to obtain our derivatives:

[tex]\displaystyle \frac{x}{\sin x} = \sum^{\infty}_{n = 0} \frac{x}{\frac{(-1)^nx^{2n + 1}}{(2n + 1)!}}[/tex]

Simplify this down:

[tex]\displaystyle \frac{x}{\sin x} = \sum^{\infty}_{n = 0} \frac{(2n + 1)!}{(-1)^nx^{2n}}[/tex]

And we have our final answer.

Topic: AP Calculus BC (Calculus I + II)

Unit: Power Series

Think back on what we have learned about gravity, mass, and weight. We are
going to take 5 minutes to write a 5-6 sentence reflection on what you learned
during this time. Make sure to use as many vocabulary words as you can.
Your answer

Answers

Answer: mass is both a property of a physical body and a measure of its resistance to acceleration when a net force is applied. An object's mass also determines the strength of its gravitational attraction to other bodies. weight is the weight of an object is the force acting on the object due to gravity. and gravity is a natural phenomenon by which all things with mass or energy—including planets, stars, galaxies, and even light—are brought toward one another.

Explanation: and that is mass weight and gravity

A duck flies 60 m in 6 seconds what is the ducks speed? Show your work plz

Answers

Answer:

Wouldn’t his or hers speed be 10m?

Explanation:

because 60 divided by 6 = 10

so 10m per second?

We know from experience that the harder we throw a ball (apply more force), the faster it will be
moving (greater initial velocity resulting from acceleration). If you throw a 1 kg softball as hard
as you can, and it is traveling at 20 m/s when it leaves your hand, how fast do you think a 5 kg
shot put would travel with the same throw?

Answers

The velocity the 5 Kg shot put would have, given the data from the question is 4 m/s

What is momentum?

Momentum is defined as the product of mass and velocity. It is expressed as

Momentum = mass × velocity

How to determine the momentum of the 1 Kg ball

We'll begin by calculating the momentum of the 1 Kg ball. This can be obatined as follow:

Mass = 1 KgVelocity = 20 m/sMomentum = ?

Momentum = mass × velocity

Momentum = 1 × 20

Momentum = 20 Kg.m/s

How to determine the velocity of the 5 Kg shot putMass = 5 KgMomentum = 20 Kg.m/sVelocity of 5 Kg = ?

Momentum = mass × velocity

20 = 5 × velocity

Divide both sides by 5

Velocity = 20 / 5

Velocity of 5 Kg = 4 m/s

Thus, the 5 Kg shot put will have a velocity of 4 m/s

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URGENT‼
An amateur marksman aims directly at a bulls-eye (on the same level) 75.0 m away. If the bullet leaves the gun at a speed of 180 m/s, by how much will it miss the target?

Answers

Hello!

He will miss it by ≈ 0.852 m

Begin by finding the amount of time necessary to hit the target. Use the formula t = d / s:

t = 75 / 180 = 0.4167 sec

Use the equation d = vi + 1/2at² to solve for the amount the bullet will miss the target. (vi is 0 in this instance). We are solving for the vertical component, so use a  = 9.81 m/s (gravity).

d = 0 + 1/2(9.81)(0.4167²)

d ≈ 0.852 m

Using 6. 0×1024 kg for the mass of the earth, what is the acceleration of the earth toward her as she accelerates toward the earth with an acceleration of 9. 8 m/s2 ? assume that the net force on the earth is the force of gravity she exerts on it.

Answers

   The value of the acceleration of the earth toward it when it accelerates toward the earth with 9.8m/s² is a = 7.35×10-²³m/s².

What are forces?

   Forces are the definition of Newton's second law, which is stated under the relation:

∑ Force = mass × acceleration.

  In other words, force is the origin of motion since it generates acceleration in a system.

   In this case we must complete the statement:

"A student with mass 45 kg jumps off a high diving board. Using 6. 0×1024 kg for the mass of the earth, what is the acceleration of the earth toward her as she accelerates toward the earth with an acceleration of 9. 8 m/s2 ? assume that the net force on the earth is the force of gravity she exerts on it."

  We determine the Force of the student:

F = ma

F = 45kg * 9.8m/s².

F = 441N

  Now we go to the acceleration of the earth:

a = F/m

a = 441N / 6×10²⁴ Kg

a = 7.35×10-²³m/s².

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A dog runs after a ball that is 45 meters away. It takes him 9 seconds to reach the ball. How fast is the dog running?

Answers

Answer:

The answer in 5m/s

Explanation:

You use the formula s=d devided by t, so in other words, you devide 45 meters by 9seconds and the answer is 5m/s

fluid flow: a pump uses a piston of 15 cm diameter that moves at 2.0 cm/s as it pushes a fluid through a pipe. what is the speed of the fluid when it enters a portion of the pipe that is 3.0 mm in diameter? treat the fluid as ideal and incompressible.

Answers

As per the question, a pump uses a piston of 15 cm diameter that moves at 2.0 cm/s as it pushes fluid through a pipe. The speed of the fluid when it enters a portion of the pipe that is 3.0 mm in diameter is 5000cm/sec.

The volumetric flow rate refers back to the three-dimensional area occupied by using fluid flowing thru a move section according to time. it's far the ratio of the change within the volume of a flowing fluid to the alternate in time.

According to the question, the volumetric flow rate in the pump and the pipe is the same.

Q = AV

Q = Volumetric flow rate

A = Cross-sectional area

V = Velocity

Q ( pump ) = ( π * 15^2 ) / 4 * 2 = 353.43 cm^3/sec

Q ( pipe ) =  ( π * ( 3/10 )^2 ) / 4 * V = 0.071V

Q ( pump ) = Q ( pipe )

Therefore  0.071V = 353.43

Velocity (V) = 5000 cm/sec

Therefore the speed of the fluid when it enters the pipe is 5000 cm/sec.

Velocity is the directional pace of an object in movement as a demonstration of its rate of change in function as determined from a specific body of reference and as measured by way of a selected standard of time.

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The insulating material placed between the conducting plates of a capacitor is a(n) ?

Answers

Answer:

the answer is dielectric

hope helps you

Explanation:

Answer:

dielectric

Explanation:

edge

Part A
If you are not wearing a seat belt in a car that rounds a curve, and you slide across your seat and slam against a car door, what kind of force is responsible for your slide
centripetal, centrifugal, or no force?
O It is centrifugal force as viewed by someone outside the car.
There is no force as viewed by someone outside the car. To them you move in a straight line
O Centripetal force
It is centripetal force, but only as viewed by someone inside the car.

Answers

Answer:

I think it is the last option

Explanation:

Explain how a musical instrument such as a piano may be tuned by using the phenomenon of beats.

Answers

Hence , musical instrument such as a piano may be tuned by using the phenomenon of beats.

Suppose 2 sound waves of various frequencies reach your ear. the 2 waves can interfere with one another leading to constructive and damaging interference. This may lead to the sound being instead soft and loud, that we have a tendency to decision beats. The beat frequency is that the distinction between the frequency of the 2 sound waves.

A musician typically uses the development of beat frequency to tune their piano. They pluck one string of the piano and faucet a implement at the same time. If the 2 sound sources turn out completely different beats, their frequencies will not be identical, and that they are aforementioned to be out of tune. The musician can modify the string's tension and repeatedly repeat the above mentioned method till the beats cannot be distinguished, that means the frequencies are identical. they're aforementioned to be in tune.

This methodology can work a lot of expeditiously for associate degree instrument entirely out of tune as a result of it'll be easier to differentiate the beats of the instruments and also the implement.

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If the total charge inside a closed surface is known but. the distribution of the charge is unspecified, can you use Gauss's law to find the electric field? Explain.

Answers

No, Gauss’s law of charge distribution in electric field only applies to specified charge distribution. Hence, it cannot be used to find the electric field if the total charge inside a closed surface is known but. the distribution of the charge is unspecified

The electric flux is defined as the electric field multiplied by the area of the surface in a plane perpendicular to the field. Another interpretation of Gauss' rule holds that the net flow of an electric field across a particular surface divided by the contained charge should equal a constant. Gauss' law is only applicable to continuous charge distribution. In such instance, we may calculate the total electric field across the surface. However, we cannot use Gauss' law to calculate the electric field of charge with an uncertain distribution.

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