A dart is thrown horizontally at a speed of 12 m/s at the bull's-eye of a dartboard 2.7 m away. How far below the intended target does the dart hit (in m)?

Answers

Answer 1

The distance below the intended target the dart hit is 0.26 m.

Time of motion of the dart

The time taken for the  dart to fall is calculated as follows;

X = Vxt

where;

X is the horizontal displacementVx is the horizontal speedt is time of motion

t = X/Vx

t = 2.7/12

t = 0.23 seconds

Height of fall of the dart

h = vt + ¹/₂gt²

where;

v is initial vertical velocity = 0

h = ¹/₂gt²

h = ¹/₂(9.8)(0.23²)

h = 0.26 m

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Related Questions

Daniel's physician has told him that he needs to spend less time in his office chair because sitting for so long is causing him to have back pain. What ergonomic solution could help him?
(A short explanation is ok if you can)


A) wearing a wrist brace


B) a standing desk


C) moving his monitor closer to his eyes


D) using a speakerphone more often

(please help ill give brainliest as soon as i can =) )

Answers

The possible ergonomic solution that could help Daniel reduce hos back pain caused by sitting long on his chair is a standing desk.

What is ergonomic solution?

Ergonomics is defined as the science of creating a working environment that suits the capabilities and limitations of the worker while providing the best working experience.

If Daniel's physician has told him that he needs to spend less time in his office chair because sitting for so long is causing him to have back pain. The possible ergonomic solution that could help him include the following.

Daniel can use a revolving seatDaniel can also use a standing desk; this will enable him stand and reduce his back pain which happens when he sits for long.

Thus, the possible ergonomic solution that could help Daniel reduce hos back pain caused by sitting long on his chair is a standing desk.

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Answer: B. A standing desk

Explanation: I remember getting it right on my test.


What is the distance travelled by the motorbike while it is moving at
constant speed?
(a) 150m
(b) 50m
(c) 300m
(d) 750m

Any Expert Please Help me out

Answers

The distance travelled by the motorbike while it is moving at a constant speed is 150m

From the graph, we form the relationship between the speed s and the change in the time t for the journey, i.e. from t = 20sec to t = 30sec speed  s is constant = 15m/s

As the formulae states that

Speed = Distance / Time

Distance = Speed × change in time

⇒15 × ( 30 - 20 )

⇒15 × 10

⇒150m

Hence the Distance travelled by bike was 150m

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A car travels on a straight level road. Starting from rest the car is going 32 fr/s (22mi/h) at the end of 4.2s what is the cars average acceleration in ft/s^2

Answers

The acceleration of a car that travels on a straight level road starting from rest and going at 32 ft/s at the end of 4.2s is 7.62ft/s².

How to calculate acceleration?

The acceleration of a moving car can be calculated by dividing the speed by the time taken as follows:

Acceleration = Speed ÷ time

According to this question, a car travels on a straight level road starting from rest the car is going 32 ft/s (22mi/h) at the end of 4.2s. The acceleration can be calculated as follows:

Acceleration = 32ft/s ÷ 4.2s

Acceleration = 7.62ft/s²

Therefore, the acceleration of a car that travels on a straight level road starting from rest and going at 32 ft/s at the end of 4.2s is 7.62ft/s².

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2. What are the benefits of repeated trials?

Answers

Science is the study of how the world functions through the systematic process of data collection known as the scientific method.

What are repeated trials?

Repeated trials are when a measurement is performed more than once at least three times, most often five but the more the better.

The likelihood that a measurement made once will yield an accurate result is substantially smaller. However, if you measure it multiple times, you may average the results to produce a value that is considerably more accurate.

In repeated trials, the same thing is measured repeatedly to increase the accuracy of your results. This is essential since data in the actual world frequently varies and nothing is flawless. Your average will get more closely to the genuine value as you perform more trials.

Therefore, Science is the study of how the world functions through the systematic process of data collection known as the scientific method.

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Can someone solve this problem thank you!

Answers

(a) Capacitance = 4.43 * 10⁻¹¹ F

(b) Magnitude of the charge on each plate = 2.9238 * 10⁻⁸ C

(c) Stored Energy = 8.7714 * 10⁻⁶

(d) The electric field between the plates = 6.0 * 10⁴ V/m

(e) The energy density between the plates = 1.45 J/m³

(A) The ability of a conductor or group of conductors to store a separated electric charge for a given change in electrical potential is known as its capacitance. The term "capacitance" also suggests the storage of electrical energy.

Capacitance (C) = A∈ / d = [tex]\frac{55 * 10^{-4}* 8.86 * 10^{-12}}{0.011}[/tex] = 4.43 * 10⁻¹¹ F

Therefore, Capacitance = 4.43 * 10⁻¹¹ F

(B) The force per charge on any particular test charge situated within the electric field is used to calculate the electric field vector's magnitude. Either the source charge or the test charge could be directly affected by the force acting on it.

The magnitude of the charge on each plate (Q) = CV

Q = 4.43 * 10⁻¹¹ * 660 = 2.9238 * 10⁻⁸ C

Therefore, the magnitude of the charge on each plate = 2.9238 * 10⁻⁸ C

(C) The energy that a thing retains due to its position in relation to other objects, internal tensions, electric charge, or other causes is known as stored energy.

Stored Energy (U) = 0.5 CV² = 8.7714 * 10⁻⁶ J

Therefore, Stored Energy = 8.7714 * 10⁻⁶ J

(D) The region or place where the influences of the plates' charges are visible is the electric field between the plates. For instance, any charged plate will produce an electric force to either attract or repel a charged particle if it is placed close to it.

The electric field between the plates (E) = V / d = 660 / 0.011 = 6 * 10⁴ V/m

Therefore,  The electric field between the plates = 6.0 * 10⁴ V/m

(E) The quantity of energy that can be held in a specific system, substance, or area of space is known as its energy density. Energy per volume or mass can be used to measure energy density. A system or material has more energy stored in it when its energy density is higher.

The energy density between the plates (u) = U / Ad = [tex]\frac{8.7714 * 10^{-6} }{(55 * 10^{-4}) (1.1 * 10^{-3})} = \frac{0.0000063}{0.0055 * 0.0011} = \frac{0.00000878}{0.00000605} = \frac{878}{605} = 1.45 Jm^{3}[/tex]

Therefore, The energy density between the plates = 1.45 J/m³

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The earth has a radius of 6.38×10^6 meters. Assume a perfectly smooth spherical earth. Calculate the minimum horizontal velocity required for an object to orbit the earth just above the surface

Answers

The minimum horizontal velocity required for an object to orbit the earth just above the surface is 5.04 x 10¹⁰ m/s.

What is orbital speed of earth?

The orbital speed of Earth or a natural satellite is the speed at which it orbits around the center of the system.

The minimum orbital speed of the Earth is calculated as follows;

V(min) = √GMR

where;

G is universal gravitation constant = 6.67 x 10⁻¹¹Nm²/kg²M is mass of earth = 5.97 x 10²⁴ kgR is the radius of the earth = 6.38 x 10⁶ m

Substitute the given parameters and solve for the minimum orbital speed of the earth.

V(min) = √(6.67 x 10⁻¹¹ x 5.97 x 10²⁴ x 6.38 x 10⁶)

V(min) = 5.04 x 10¹⁰ m/s

Thus, the minimum horizontal velocity required for an object to orbit the earth just above the surface is 5.04 x 10¹⁰ m/s.

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Need help answering this question

Answers

Answer:

[tex] log( \beta e \alpha \sin( \cot( \sec( \binom{? \times \frac{ \\ \infty }{?} }{?} ) ) ) ) [/tex]

What is the sum of the following vectors? Write your answer, what magnitude and direction the vector will have?

Answers

The magnitude and direction of the object's displacement is 7 m and west direction respectively.

What is displacement?

The displacement of an object is the change in the position of the object. Displacement is a vector quantity because it has both magnitude and direction.

To find the sum of the vectors, we find the displacement of the vectors.

Initial position of the vector = 10 m east

final position of the vector = 3 m west

displacement of the vector = final position - initial position

displacement of the vector = 3 m - 10 m

displacement of the vector = - 7 m

magnitude of the displacement = 7 m

direction of the displacement = west

Thus, the magnitude and direction of the object's displacement is 7 m and west direction respectively.

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A 1.5 kg mass swings at the end of a 2.3 m string. A scale on the string
measures the tension in the string to be 24.5 N. What is the centripetal
force on the swinging mass? __________ Blank 1
And, what is the speed of the mass at the time the tension is measured?

Answers

The speed of the mass at the time the tension is measured is 6.12m/s

centripetal force - It is a force which makes a body follow a curved path.

It is directed inward towards center of rotation.

for example - gravitational force of sun is a centripetal force that keeps earth rotating around it.

the centripetal force on the swinging mass

Fc = mv²/r

where Fc is the centripetal force

m is the mass of body

v is the velocity

r is the radius

m = 1.5

r = 2.3 m

F = 24.5 N

To calculate the speed we put values in above equation

Fc = mv²/r

v = sqrt(Fc x r / m)

v = [tex]\sqrt[]{\frac{F *m}{r} }[/tex]

[tex]v = \sqrt[]{\frac{24.5*1.5}{2.3} }[/tex]

v = 6.12m/s

The speed of the mass at the time the tension is measured is 6.12m/s

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A ballplayer standing at home plate hits a baseball that is caught by another player at the same height above the ground from which it was hit. The ball is hit with an initial velocity of 26.8 m/s at an angle of 60.0° above the horizontal. At what distance from the home plate will the fielder be when he catches the ball?

Answers

The distance from the home plate the fielder will be when he catches the ball is 63.47 m

From the question given above, the following data were obtained:

Initial velocity (u) = 26.8 m/sAngle of projection (θ) = 60.0 °Acceleration due to gravity (g) = 9.8 m/s²Distance (i.e range) (R) =?

How to determine the range

The distance (i.e range) the fielder will be when he catches the ball can be obtained as follow:

R = u²Sine(2θ) / g

R = 26.8² × Sine (2×60) / 9.8

R = 622.014 / 9.8

R = 63.47 m

Thus, the distance the fielder will be is 63.47 m

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A piolet is required to fly directly from London,United Kingdom, to Rome,Italy,in 3.4 h. The displacements is 1.4×10³km[S 43⁰ E] . The wind velocity reported from the ground is 55km/h[S]. Determine the required velocity of the plane relative to the air.

Answers

The required velocity of the plane relative to air with a velocity of 55 km / h S is 373.42 km / h

v = d / t

d = 1400 km ( 43° E of S )

t = 3.4 hrs

[tex]V_{pg}[/tex] = d / t

[tex]V_{pg}[/tex] = 1400 / 3.4

[tex]V_{pg}[/tex] = 411.75 km / h ( SE )

[tex]V_{ag}[/tex] = 55 km / h ( S )

[tex]V_{pgx}[/tex] = sin 43° ( 411.75 )

[tex]V_{pgx}[/tex] = 280.81 km / h ( E )

[tex]V_{pgy}[/tex] = cos 43° ( 411.75 )

[tex]V_{pgy}[/tex] = 301.14 km / h ( S )

[tex]V_{x}[/tex] = [tex]V_{pgx}[/tex] - [tex]V_{agx}[/tex]

[tex]V_{x}[/tex] = 280.81 - 0

[tex]V_{x}[/tex] = 280.81 km/ h

[tex]V_{y}[/tex] = [tex]V_{pgy}[/tex] - [tex]V_{agy}[/tex]

[tex]V_{y}[/tex] = 301.14 - 55

[tex]V_{y}[/tex] = 246.14 km / h

V² = [tex]V_{x}[/tex]² + [tex]V_{y}[/tex]²

V = √ [ ( 280.81 )² + ( 246.14 )² ]

V = 373.42 km / h

tan θ = [tex]V_{y}[/tex] / [tex]V_{x}[/tex]

θ = [tex]tan^{-1}[/tex] ( 246.14 / 280.81 )

θ =  [tex]tan^{-1}[/tex] ( 0.88 )

θ = 41.35° ( S of E )

Therefore, the required velocity of the plane relative to air is 373.42 km / h at 41.35 S of E

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9. The coefficient of static
friction between a 5kg block
and horizontal surface is 0.4.
What is the maximum
horizontal force that can be
applied to the block before it
slips?

Answers

Answer:

19.6 Newtons

Explanation:

[tex]\displaystyle \textsf{The weight of the block is W= mg where m is the mass and g the acceleration due to gravity}[/tex]

[tex]\sf W = 5kg, \; and\; g = 9.80 m/s^2[/tex]

[tex]\sf W = 5 x 9.8 = 49\; Newtons[/tex]

[tex]\textsf {If the coefficient of static friction is } $\mu_s$, the force to be applied for the block to slip is given by the equation}:\\\mathsf {f_s = \mu_s \times W}\\\\\textsf {So force required, given $\mu_s$ = 0.4 is: }\\\\\\\mathsf {f_s = 0.4 \times 49 = 19.6 } \textsf{ Newtons }[/tex]

The Distance-time graph shown is for a 3000 m cross-counrty race, run by rachel and james.

Answers

From the given graph, it is shown that James is running the race with the same speed while Rachel changes his speed time-to-time. It can be inferred from the graph that James wins the race.

What is Speed?

Speed is the distance travelled by an object in a particular time. In the race, James run with a constant speed throughout the race and Rachel changes its speed after some time.

By looking at the graph, we can say that James catch up Rachel 17.5 minutes after the start of the race where they both completed 1750m distance.

Speed of James can be calculated by the formula:

Speed = Distance/Time

Speed = 3000m/30min

Speed of James = 100m/min.

Different speeds of Rachel can be calculated by the same formula:

For the first 1000m he completes the distance in 5 min. therefore, the speed will be:

Speed = 1000m/5min.

Speed = 200m/min.

For the next 1500m. he covers the distance in 25min. therefore, the speed here will be:

Speed = 1500m/25min.

Speed = 60m/min.

For the next 500m. he covers the distance in 5 min. therefore, the speed will be:

Speed = 500m/5min.

Speed= 100m/min.

As, James covers the same distance earlier than Rachel. James cover the the distance in 30 minutes while Rachel covers the same distance in 35 minutes. James will be the winner of the race.

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velocity equations solve:
15, km over second
find the m/s
and find the km/h

Answers

The 15 km/s velocity is equivalent to 15000 m/s and 54000 km/h.

Velocity is a vector quantity. It consist both a direction and a magnitude. The magnitude of velocity is called speed. Its S.I. unit is a meter/second. It also has other units like Km/h and Km/s. Its dimensional formula is [[tex]LT^{-1}[/tex]].

Given in the question

Velocity is 15 Km over a second

We can infer from the given value that the body moves 15 km per second.

1 Km = 1000 m

1 Km × 15  = 15 × 1000 m

So 15 Km = 15000 m

Hence we can say that the body travels 15000 meters in a second.

As a result, its velocity in m/s is 15000 m/s.

Now

15 kilometers can be covered in 1 second.

Distance traveled in 3600 seconds = 3600 × 15 Km

So the total distance traveled in 3600 seconds is 54000 kilometers.

Also 3600 seconds = 1 hour

In other words, The body travels 54000km in 1 hour, hence its velocity is 54000 km/h.

Therefore, the 15 km/h velocity is equal to 15000 m/s and 54000 km/h.

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A car travels due east with a speed of 50.0 km/h. Raindrops are falling at a constant speed vertically with respect to the Earth. The traces of the rain on the side windows of the car make an angle of 60.0° with the vertical. Find the velocity of the rain with respect to the following reference frames. (Enter the magnitude of the velocity.)
(a) the car
m/s
(b) the Earth
m/s

Answers

The velocity of the rain with respect to car is 43.3 km/h and the velocity of the rain with respect to earth is 50 km/h.

What is relative velocity?

Relative velocity is the velocity of one object with respect to another using a frame of reference.

Velocity of the rain with respect to the car

V(rc) = 50 km/h x sin(60)

V(rc) = 43.3 km/h

Velocity of the rain with respect to the earth

V(re) = speed of the car =  50 km/h

Thus, the velocity of the rain with respect to car as frame of reference is 43.3 km/h and the velocity of the rain with respect to earth as the frame of reference is 50 km/h.

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how does mass and velocity determine the amount of damage that occurs in a collision?

Answers

Answer:

Mass and velocity are both directly proportional to the momentum. If you increase either mass or velocity, the momentum of the object increases proportionally. If you double the mass or velocity you double the momentum.

Explanation:

An object traveling at a constant speed exhibits which of the following:

Net force of 0N.

Acceleration is 0m/s/s

Speed of 0m/s.

None of the above

Answers

When an object is traveling at a constant speed, the acceleration is 0 m/s².

What is constant speed?

If an object covers an equal amount of distance in equal interval of time, then the body is said to be moving at a constant speed.

F - ff = ma

where;

F is the applied forcem is mass of the objecta is acceleration of the object

During constant speed, acceleration = 0

Thus, when an object is traveling at a constant speed, the acceleration is 0 m/s².

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Dean is slowing down on his skateboards. He starts at a speed of 5.5 m/s and
slows to 1.0 m/s over a time of 3.0 seconds. What is Dean's acceleration?

Answers

Dean's acceleration while slowing down on his skateboards a = -1.5 m/s².

Equation :

To find the acceleration of skateboards

Using formula,

a = Δv/Δt

where,

a is acceleration

Δv is change in speed

Δt is time

By putting the given values,

a = 1.0 m/s - 5.5 m/s / 3 s

a = - 4.5 m/s / 3s

a = -1.5 m/s²

Is acceleration can be positive or negative?

When an object is moving in a positive direction, the acceleration is negative, but the rate of change of velocity is positive (velocity is decreasing). When an object moves in the reverse or opposite direction, we can define these two accelerations as well (right to left).

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Use the energy equation, your answer from #5, and Planck’s constant (6.63E-34) to find the approximate energy of this photon:


4.8E-19 Joules

3.0E-19 Joules

3.0E-17 Joules

1.21 Gigawatts

Answers

The energy for the Photon with frequency 4.6 x 10 raise to power 14 Hertz is equal to 3 × 10 raised to power minus 19.

What is a Photon?

A photon is an elementary particle that is a quantum of the electromagnetic field and the force carrier for the electromagnetic force. Photons are massless, so they always move at the speed of light in vacuum, 299792458 m/s.

What is energy equation for radiation?

Energy equation is a derivative of the energy mass equation and is used to give energy of an electromagnetic or particle have frequency.

Given:

Frequency of the photon = 4.6×10¹⁴

Value of plank constant = 6.626×10⁻³⁴

Now from energy equation we have-

Energy of photon = plank constant × frequency of the photon

E = h × v

Where,

E is Energy of photon

h is plank constant

v is frequency of the photon

On substituting values in the energy equation we get,

E = 6.626 × 4.6×10⁻²⁰

E = 3 × 10⁻¹⁹

The energy for the Photon with frequency 4.6 x 10 raise to power 14 Hertz is equal to 3 × 10 raised to power minus 19.

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what happens to the sh
ape of water when we pour the same volume of water in different containers of different shape​

Answers

Answer:

It shapes into the form of the container because water is a liquid.

Explanation:

Think of a pen name that you most likely would use if you are to become a writer. Write it down and give a brief explanation as to why you have chosen that particular pseudonym. Write your explanation on not less that three paragraph with 5 sentence each paragraph

Answers

A pen name is the name used by the writer instead of their real name when publishing. This name is called as pseudonym or a fake name. The author's real name is probably known to the publisher, but not to the public.

If I'll be the writer, I'll use Dark Shadow as my pen name.

Dark Shadow effectively acts as a living appendage that obeys his master's every command. It is sentient, capable of speech, and loyally protects its host regardless of its state. Also it is short and sweet name and can be pronounced easily.

Also thee is a drawback in seeking secrecy with the pen name. The Guardian article says, "If you try to keep your identity secret, you can't go to events or festivals; be pictured in newspapers, or be open about your possible success. And, if you become hugely successful, you'll have to come out eventually – as Madeleine Wickham, the author of the Sophie Kinsella books, did. "

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a glass block in air has a critical angle of 49degrees. what will happens to a ray of light coming through the the glass when it is incident at the angle at a angle of 50degrees

Answers

If a glass block in the air has a critical angle of 49° and an incident angle of 50°, any light rays entering to the glass will be bent away from the normal  and refraction would be happen.

The critical angle is the angle of incidence in a denser medium for which the angle of refraction in a rarer medium is 90°. which would be represented by (c). The bending of light ray through one medium to the another medium would be defined as refraction. There are two refraction laws, which are written as,The normal, refracted, and incident rays all lie on the same plane For any two media, the ratio of incident to refracting angle is a constant. This is also known as Snell's law .

[tex]\frac{sin_{i} }{sin_{r} } =n[/tex]

In above equation , n is constant, sin i and sin r are the angles of incident and refracted ray for two medium.

Therefore, from the above discussion ,as the incident angle is laser than the critical angle so that the ray of light would be refract away from the normal.

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A projectile is launched at 68.0° above the horizontal and at a speed of 55 m/s. How long will it take the projectile to reach maximum height?

Answers

Answer:

5.2s

Explanation:

We care about the vertical component of the velocity, which, in our case, is [tex]v_y=55 sin 68\° m/s \approx 51 m/s[/tex]. The projectile is affected by gravity, which means its velocity will decrease by [tex]g= 9.81 m/s[/tex] each second. Remembering that at maximum height velocity is zero, we can write [tex]0=51-9.81 t \rightarrow t= \frac{51}{9.81}\approx 5.2s[/tex]

6) A person on a bus traveling 5 m/s is walking to the back of the bus at 1 m/s. How fast does
the person on the bus appear to be moving to a person in a car going the opposite direction
traveling at 2 m/s?

Answers

Answer:

maximum velocity,then u draw your diagram then u calculate for max velocity then the answer u get use it for total shape

A car is driving on a gravel road at a speed of 12 m/s. The car maintains this speed for 10 seconds. Going around a bend the car reduces speed to 5 m/s during the next 5 seconds. Over the last 15 seconds the car increases its speed with 2 m/s every second. Determine the maximum and minimum values for both axes.

Answers

The maximum distance covered by the car from point A to B will be 120 meters, and the minimum distance covered by the car will be 25 meters.

What is Speed?

Measuring is the most important scientific concept. Many different types of quantifiable quantities can be measured using base or physical fundamental units. One such quantifiable quantity is speed, which computes the proportion of a moving object's distance travelled to its travel time.

According to the question,

Point A and B are taken on X-axis and point B,C and D are taken on y-axis.

On going from point A to B,

Time taken= 10 seconds

Speed= 12 m/s

Distance covered will be : Speed × time

=12 × 10 sec

Distance= 120 meters

On going from Point B to C,

Time taken= 5 Seconds

Speed= 5 m/s

Distance covered by car will be : Speed × Time

=5 × 5 sec

Distance= 25 meters.

Now, On going from point C to D,

Time taken= 15 seconds

Speed= 2 m/s

Distance covered = speed × time

= 2 × 15 sec

Distance= 30 meters

Hence, the maximum distance covered by car is 120 meters when it goes from point A to B and the minimum distance covered by car is 25 meters when it goes from Point B to C.

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Football player Joe is running toward the opponent's goal line with the football, and slows down as he encounters the other team. If the opponent's goal line is the reference point, which of the following best describes his motion?

Question 4 options:

Negative Velocity, Negative Acceleration


Negative Velocity, Positive Acceleration


Positive Velocity, Negative Acceleration


Positive Velocity, Positive Acceleration

Answers

Since Joe is running towards the goal line and slowing down, the option that describes this motion is negative velocity, negative acceleration.

What is negative velocity?

A negative velocity occurs when an object moves in the negative direction.

Example of negative velocity;

If a car is moving away from you (reference point) then the velocity is positive.

If a car is coming towards you (reference point) then the same vector reverses direction and hence the velocity is negative.

What is negative acceleration?

If the object is slowing down then its acceleration vector is directed in the opposite direction as its motion. Thus, the acceleration of the object will be negative.

Thus, since Joe is running towards the goal line and slowing down, the option that describes this motion is negative velocity, negative acceleration.

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vector A points in the negative x direction and has a magnitude of 25 units. The vector B points in the positive y direction. Find the magnitude of B if A+B has a magnitude of 35 units

Answers

The magnitude of vector B is determined as 24.5 units.

What is resultant vector?

A resultant vector is defined as a single vector that produces the same effect as is produced by a number of vectors collectively.

The given parameters;

magnitude of vector A = 25 unitsresultant of vector A and B = 35 unitsmagnitude of vector B = ?

The magnitude of vector B is calculated as follows;

B² = R² - A²

where;

R is the resultant vector or sum of vector A and vector B

B = √(35² - 25²)

B = 24.5 units

Thus, the magnitude of vector B is determined as 24.5 units.

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Which of the following statements is true
based upon your observations of the Earth
revolving around the Sun?
The hemisphere tilted away from the Sun
experiences winter; during this time the
pole in this hemisphere experiences 24
hours of sunshine.
The hemisphere tilted away from the Sun
experiences summer and the hemisphere
tilted towards the Sun experiences winter.
The hemisphere tilted towards the Sun
experiences summer; at this time the pole
in this hemisphere experiences 24 hours
of darkness.
The hemisphere tilted towards the Sun
experiences summer and the hemisphere
tilted away from the Sun experiences
winter.

Answers

The statement ' The hemisphere tilted towards the Sun experiences summer and the hemisphere tilted away from the Sun experiences winter.' is true.

The variation in seasons is due to the slight tilt of the earth on its axis towards the sun. This tilt is approximately equal to 29 and 1/2 degrees.

Due to this tilt of the earth, the north pole or the south pole of the northern or the southern hemisphere respectively never directly faces the sun.

But when the respective hemisphere is tilted towards the sun, it is as close to the sun as it is physically possible, and therefore that hemisphere experiences the summer season.

Whereas the other hemisphere which is tilted away from the sun is as far from it as possible and receives very little sunlight and hence experiences the winter season.

In the context of the above discussion, the statement ' The hemisphere tilted towards the Sun experiences summer and the hemisphere tilted away from the Sun experiences winter.' is true.

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Why does gravity cause acceleration?
Answer choices

A. It acts in a downward direction
B. It has a greater effect on objects with more mass.
C. It always causes objects to slow down.
D. It is a force.

Answers

it would be D because Gravity is a force that pulls objects down toward the ground and when objects fall to the ground, gravity causes them to accelerate .

You are driving through town at 12.0 m/s when suddenly a ball rolls out in front of you. You apply the brakes and begin decelerating at 3.5 m/s^2
(a) How far do you travel before stopping?
(b) When you have traveled only half the distance in part (a), is your speed 6.0 m/s, greater than 6.0 m/s, or less than 6.0 m/s?
(c) Find the speed of your car when you have traveled half the distance in part (a).

Answers

(a) The distance traveled by the driver before stopping is 20.57 m.

(b) When you have traveled only half the distance in part (a), your speed is greater than 6.0 m/s.

(c) The speed of your car when you have traveled half the distance in part (a) is 8.49 m/s.

Distance traveled by the driver before stopping

The distance traveled by the driver before stopping is calculated as follows;

v² = u² + 2as

when the car stops, the final velocity, v = 0

0 = u² + 2as

0 = 12² + 2(-3.5)s

0 = 144 - 7s

7s = 144

s = 144/7

s = 20.57 m

when you travel half of 20.57 m

v² = (12²) - 2(3.5)(0.5 x 20.57)

v² = 72.005

v = √72.005

v = 8.49 m/s

Thus, when you have traveled only half the distance in part (a), your speed is greater than 6.0 m/s.

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