The dimension of the amplitude, A is L.
What is amplitude of a wave?The amplitude of a wave is the maximum displacement of the wave.
The amplitude of a wave is measured in the units of meters.
The given displacement of the light wave;
x = A sin(2πft)
where;
x is the displacement of the waveA is the amplitude of the wavef is frequency of the wavet is time of the wave's motionDimension of of amplitude, ASince amplitude of a wave measures the wave's displacement, then amplitude will have the same dimension as displacement.
A = meters = L
Thus, the dimension of the amplitude, A is L.
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European sports car dealer claims that his product will accelerate at a constant rate from rest to a speed of 100 km/h in 8 seconds. What is the speed after the first 5 seconds of acceleration?
Answer:
[tex]62.5[\frac{km}{h}][/tex]
Explanation:
if the required speed is 's', then it is possible to make up the next equation:
[tex]\frac{100}{8} =\frac{s}{5};[/tex]
finally,
s=100*5/8=62.5 [km/h].
Which characteristic is used to measure of light radiated by sh star
The characteristic that is used to measure light radiated by a star is luminosity. The correct option is C.
What is luminosity?The radiant power emitted by a light-emitting object with respect to time is measured as luminosity, which is an absolute measure of radiated electromagnetic power.
The total amount of electromagnetic energy radiated per unit of time by a star, cosmos, or other celestial object is referred to as luminosity in astronomy.
The amount of light emitted by a star is measured using luminosity. It is the total amount of emery or light emitted by a star per unit of time. Or it is the total energy produced by a star in one second from its surface.
Thus, the correct option is C.
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Your question seems incomplete, the missing options are:
Size
color
luminosity
temperature
Snow how the units of from the ROU Fundamental for (A) (Area) (B) (speed) is derived whits,
Area and Speed are derived Units Because they are derived from the Fundamental Units
By proceeding using the dimensional analysis,
We can see,
Area = Length of object x Breadth of object
As we know, both the length and the breadth of the object are measured as Meter(M),
Area = M x M
Now, for Speed,
Speed = distance/time
unit of distance is Meter(M) and unit of time is Second(S), both of these are fundamental quantities.
Speed = Meter/second
Speed = M/S
As we can see, the unit of area is a composition of a fundamental unit and speed is also a composition of fundamental unit and any unit which is composition of one or more fundamental unit is called derived Unit.
Hence it is proved that Area and Speed are Derived Units.
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A light-year (ly) is the distance light travels in one year (at speed of 2.998 × 10^8 m/s ). An astronomical unit (AU) is the average distance from the Sun to Earth, 1.50 × 10^8 km. 1 year = 3.156 × 10^7 s.
A. How many meters are there in 1.50 ly ?
B. How many AU are there in 1.50 ly light-year?
There are few points given to us in this question.
The speed of lightTime (in seconds) in a yearDistance between Earth and SunSpeed of light in m/sA) There are 1.41× 10^16 m in 1.5 light years
B) There are 9.4 × 10^4 AU in 1.5 light years
What is a light year?
Many might confuse it with time because of the presence of term “year” this term is actually used for space objects to measure distance. Light Year is the distance travelled by light in one Earth year.
It’s a term named by German scientist Friedrich Bessel who first used it in 1838.
One light year is about 6 trillion miles or 9.46 trillion kilometers.
To solve part A, we will first multiply V(light) with time (in seconds) in a year and multiply the product with 1.5 light year per light year.
Now let us understand what is Astronomical Unit AU?
AU is also used to measure distance but within our solar system. It is usually the average distance between Sun and Earth. It is about 93 million miles or 150 million kilometers.
To solve part B, we first convert the light year to AU and we do this by using the final value from part A and then convert it in significant figure to obtain a proper value for the answer.
The calculations are shown in the figures below.
Hence,
A) There are 1.41× 10^16 m in 1.5 light years
B) There are 9.4 × 10^4 AU in 1.5 light years
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In a nuclear power plant, a 1.0 kg of water at 58.6 °C is converted into 1.0 kg of steam at 131.8 °C. The total heat (in kcal) supplied by the plant is: Use cwater = 1.00 kcal/(kg.°C), csteam = 0.48 kcal/(kg.°C), and Lv = 540.0 kcal/kg
The total heat supplied by the plant to convert the water to steam is 596.7 kcal.
What is heat capacity?Heat capacity is the quantity of heat required to raise the temperature of entire mass of a substance.
Q = Heat supplied to the water to the boiling point + Heat supplied to vaporize the water.
Q = mc₁Δθ + mc₂Δθ + mLv
where;
m is the mass of the waterc₁ is specific heat capacity of waterc₂ is specific heat capacity of steamΔθ is change in temperatureLv is latent heat of vaporizationSubstitute the given parameters and solve for the heat supplied in the process.
Q = (1)(1)(100 - 58.6) + (1)(0.48)(131.8 - 100) + 540(1)
Q = 41.4 + 15.264 + 540
Q = 596.7 kcal
Thus, the total heat supplied by the plant to convert the water to steam is 596.7 kcal.
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A runner can maintain a constant acceleration of 1.1m/s^2 for 8.5 seconds. What distance could the runner cover in that time of starting from rest
The distance covered by the runner after starting from rest is 39.74 m/s².
The real route length of a moving particle or object is referred to as distance. The shortest distance between a body's initial and final positions is referred to as displacement. Speed is the amount of distance a particle travels in one unit of time.
The constant acceleration of a runner is 1.1 m/s².
The runner maintains the constant acceleration for 8.5 seconds.
So,
a = 1.1 m/s²
t = 8.4 seconds
Since the runner starts from the rest.
Therefore, the initial velocity u = 0 m/s
Using the equation of motion,
s = ut + (1/2) × a × t²
s = 0 × 8.5 + ( 1/2 ) × 1.1 × 8.5 × 8.5
s = ( 1/2 ) × 79.475
s = 39.737 m/s²
s = 39.74 m/s²
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What balancing level are we at if we are standing at normal posture?
Medium
High
Low
Normal
The balancing level that we are when standing at a normal posture is the Normal balancing level. That is option D.
What is posture?Posture is defined as the bearing of one's body while at rest or while moving.
Normal posture can be defined as the normal position of the body while standing which involves standing straight and tall with shoulders back and the hands by the sides with the head kept in line with the body level.
The balancing level of posture is that level where the body is being positioned in such a manner as to reduce the amount of work done by the muscles.
Therefore, the balancing level that we are when standing at a normal posture is the Normal balancing level.
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What’s more dense, a 200g bar of Aluminum or a 2g cube of Aluminum?
Answer:
2g cube of Aluminum
Explanation:
A soccer ball is kicked horizontally off a cliff with an initial speed of 8 m/s and lands 16 m from the base of the cliff.
The height of the cliff from the ground is 19.6 meters.
What is Projectile motion?Projectile motion is the motion of an object thrown or projected into the air, subject to only the acceleration due to gravity.
Given is the initial speed of soccer ball kicked horizontally off a cliff which is 8 m/s. It cover a horizontal distance of 16 m. From this, we can write -
Horizontal initial velocity = u [h] = 8m/s
Horizontal distance covered = S [h] = 16m
For horizontal direction, of motion, we can write -
u [h] = 8m/s
S [h] = 16m
From second equation of motion applied for the horizontal direction -
S[h] = u[h] x t + 1/2 a[h] x t²
Since horizontal acceleration a[h] is zero, we can write -
t = S[h]/u[h]
t = 16/8
t = 2 seconds
Since the ball is kicked horizontally, the initial vertical velocity u[v] will be 0 m/s.
The acceleration in the vertical direction a[v] is directed vertically downwards and is equal to 9.8 m/s².
From second equation of motion applied for the vertical direction -
S[v] = u[v] x t + 1/2 x a[v] t²
S[v] = 1/2 x a[v] t² {u[v] = 0}
S[v] = 1/2 x 9.8 x 4
S(v) = 9.8 x 2
S[v] = 19.6 m
Therefore, the height of the cliff from the ground is 19.6 meters.
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[ The given question is not complete, the complete question is -
A soccer ball is kicked horizontally off a cliff with an initial speed of 8 m/s and lands 16 m from the base of the cliff: What is the time of flight of the soccer ball? What is the height of the cliff? ]
During the COVID pandemic many people acted to help those in need despite the risk to themselves. This action best illustrates
The Blue Origin rocket ship starts vertically upward from the launch pad a constant
acceleration of 6.3 m/sec2. How high does the rocket ship raise above the launch
pad after 94 seconds of flight?
Assume that the rocket ship moves vertically up all the time. Enter your answer in
meters (m).
The rocket ship rises to a height of 27.83 km above the launch pad after 94 seconds of flight.
We know that,
s = u t + 1 / 2 a t²
where,
s = Displacement
u = Initial velocity
a = Acceleration
t = Time
Given that,
u = 0
a = 6.3 m / s²
t = 94 s
s = 0 + 1 / 2 ( 6.3 * 94² )
s = 27833.4 m
s = 27.83 km
Displacement the distance between the initial point and final point. It is denoted using s.
Therefore, the rocket ship rises to a height of 27.83 km above the launch pad after 94 seconds of flight.
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Metric Conversions:
1) 5KL = ?L
2) 3L = ?KL
3) 4g = ?Kg
4) 81Kg = ?g
5) 52dg = ?g
6) 3dm = ?m
7) 14mm = ?m
The metric conversion of the given quantities is determined as
5 KL = 5,000 L3L = 0.003 KL4g = 0.004 kg81 kg = 81,000 g52 dg = 5.2 g3 dm = 0.3 m14 mm = 0.014 mWhat is metric conversion?Metric Conversion refers to the conversion of the given units to desired units for any quantity to be measured.
The metric conversion of the following quantities is calculated as follows;
5 KL = 5 x 1000 L = 5,000 L
3L = 3 x 1/1000 L = 0.003 KL
4g = 4 x 1/1000 g = 0.004 kg
81 kg = 81 x 1000 g = 81,000 g
52 dg = 52 x 1/10 g = 5.2 g
3 dm = 3 x /10 m = 0.3 m
14 mm = 14 x 1/1000 m = 0.014 m
Thus, the metric conversion of the given quantities is determined as
5 KL = 5,000 L3L = 0.003 KL4g = 0.004 kg81 kg = 81,000 g52 dg = 5.2 g3 dm = 0.3 m14 mm = 0.014 mLearn more about metric conversion here: https://brainly.com/question/26259781
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What ia the speed of A car travels 100meters in 50 seconds what's it's speed
A right triangle has a leg that measures 17 measures 24 ft. What would the missing length be
The lenght of the missing side is 29.41 ft.
To calculate the missing length of the triangle, we use pythagoras theorem.
What is pythagoras theorem?
Pythagoras theorem states that in a right angle triangle, the square the hypotenus is equal to the sum of the square of the two other sides.
These can be expressed mathematically as
a² = b²+c²...............Equation 1From the question,
b = 17 ftc = 24 ftSubstitute these values into equation 1
a² = 17²+24²a² = 289+576a² = 865a = √865a = 29.41 ft.Hence, the lenght of the missing side is 29.41 ft.
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which of the statements is not correct
Answer:
The electrostatic interactive force between electrical charges is exactly the same as the gravitational interaction between them
Explanation:
The magnitude of charge is independent of the weight and displacement of the charge but only sign of the charge is the dependent factor.
[tex]{}[/tex]
What will be the acceleration of an object at rest with 70kg if the force exerted is 1400N?
Force = (mass) x (acceleration)
so
Acceleration = Force / mass
Acceleration = (1400 N) / (70 kg)
Acceleration = 20 m/s²
A construction worker on the 24th floor of a building project accidentally drops a wrench and yells “Look out below” Could a person of ground level hear his warning in time to get out of the way? The speed of sound is about 1100 feet per second
Answer:
Assuming the height at which the wrench was dropped is 336 feet,
the person will hear the sound in 0.3 sec and the wrench will hit the ground only after 4.58 seconds so there is enough time to get out of the way
Explanation:
Without knowing the exact height at which the 24th floor is located, it would be difficult to determine whether the wrench will hit the ground before the sound hits the ground
Realistically, we can assume each floor of the building is 14' high
So the height at which the 24th floor is located is 24 x 14 = 336 feet
To travel 336 feet at 1100 feet per second, sound will take 336/1100 seconds which is 0.30 second
Let's compute the time taken for the wrench to hit the ground
The acceleration due to gravity is usually taken to be 16 feet/second²
The displacement which is the distance traveled by an object with an initial velocity of u in time t is given by the equation:
s = ut + (1/2)t²
Here the initial velocity is 0
So the equation is
s = 1/2 x 32 x t² = 16t²
To cover 336 feet we substitute 336 for s and get
336 = 16t²
t² = 336/16
t = ±√(336/16) ≈ 4.58 seconds (we only take the positive root)
So the person will hear the sound in 0.3 sec and the wrench will hit the ground only after 4.58 seconds so there is enough time to get out of the way
In general, we can state that if the height from which the wrench was dropped is h then time t taken for wrench too hit the ground is
t = √(h/16) seconds
If this is greater than the time taken for sound to travel the same distance then the person can get out of the way
A 100.0 kg person will need to climb a 10.0 m stairway how many times to "work off" each excess 20 Cal (kcal) consumed?
The person must climb the stairs about eight times.
What is the energy required?We know that energy is the ability to do work. Work and energy are two quantities that are dimensionally similar to each other. In this case, we are trying to obtain the number of times that A 100.0 kg person will need to climb a 10.0 m stairway how many times to "work off" each excess 20 Cal (kcal) consumed.
Now;
Work done by the person = mgh = 100.0 kg * 10 m/s^2 * 10 m = 10000 J
To convert from joules to kcal, we know that;
1 kcal = 4184 J
x = 10000 J
x = 1 kcal * 10000 J/4184 J
x = 2.39 kcal
In order to burn off the excess calories, the person must climb the stairs;
20 kcal/2.39 kcal = 8
The person must climb the stairs about eight times.
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pls helppp
A model rocket has a mass of 0.2 kg, with a motor that can provide a force of 100 N. A second model rocket is being built with the
same motor, but it is being designed to accelerate half as much as the first rocket. What kind of change can be made in the design to
achieve this objective? (1 point)
O The mass of the second rocket should be 0.1 kg.
The mass of the second rocket should be 0.01 kg.
The mass of the second rocket should be 0.4 kg.
O The mass of the second rocket should be 0.2 kg.
The mass of the second rocket should be 0.4 kg in order for the acceleration to be half of the first rocket's acceleration.
We know that,
F = m a
where,
F = Force
m = Mass
a = Acceleration
Given that,
[tex]F_{1}[/tex] = 100 N
[tex]m_{1}[/tex] = 0.2 kg
[tex]F_{1}[/tex] = [tex]F_{2}[/tex] = 100 N
[tex]a_{2}[/tex] = [tex]a_{1}[/tex] / 2
[tex]F_{1}[/tex] = [tex]m_{1}[/tex] * [tex]a_{1}[/tex]
[tex]a_{1}[/tex] = 100 / 0.2
[tex]a_{1}[/tex] = 500 m / s²
[tex]a_{2}[/tex] = 500 / 2
[tex]a_{2}[/tex] = 250 m / s²
[tex]m_{2}[/tex] = 100 / 250
[tex]m_{2}[/tex] = 0.4 kg
According to Newton's second law of motion, acceleration of an object is the result of force acting on the object.
Therefore, The mass of the second rocket should be 0.4 kg
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Question 12 (1 point)
Football player Joe is running toward the opponent's goal line with the football, and slows down as he encounters the other team. If the opponent's goal line is the reference point, which of the following best describes his motion?
Question 12 options:
Negative Velocity, Positive Acceleration
Negative Velocity, Negative Acceleration
Positive Velocity, Positive Acceleration
Positive Velocity, Negative Acceleration
Answer:
d
Explanation:
I remember it was right
An airplane touches down at a speed of 55.0 m/s on a runway that is 600.0 m long. The plane can decelerate at a uniform rate of 2.50 m/s². Will the plane be able to stop before the end of the runway?
The final velocity of the plane at the end of the railway is:
V2f=v2i+2a(x)
v2f=(55m/s)2−(2)(2.5m/s2)(600m)
vf=5m/s.
Since the final velocity is not equal to zero, the plane would not be able to stop at the end of the runway.
Technically, there may be the most effective manner for the aircraft to stay putting motionless inside the air if weight and raise cancel every other out perfectly, and at the equal time thrust and drag cancel every different out too. but this is exceptionally uncommon. To live within the air and sustain its flight, a plane wishes to be moving forward.
In addition to wing spoilers, airplanes use disc brakes. aircraft disc brakes are just like the braking system in automobiles. They consist of a pair of calipers that, while engaged, squeeze pads towards the rotors of an aircraft's landing gear. Disc brakes are designed to stay static at all times. maximum planes use a long runway earlier than takeoff to gain enough velocity for the aircraft to raise up into the air. most airplanes can take off handiest if they are moving rapidly sufficient.
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A person swims at a constant speed of 1 meter per second. What type of function can be used to model the distance the swimmer travels?
Hint: sketch a graph of what this would like and see which parent function it looks like
If a person swims at a constant speed of 1 meter per second, than the linear function will be used to model the distance travelled by the swimmer.
The parent function is "the principal's of ice"
A linear function is a function that forms a straight line on a graph. It is generally a polynomial function whose degree is at most 1 or 0. Although linear functions are also represented in terms of calculus and linear algebra.
Here Y-axis represents Distance and X-axis represents Time.
Also speed is the rate of change of distance with respect to time i.e. distance is changing linearly with time
Mathematically it is [tex]Speed = \frac{distance}{time}[/tex].
Change in Distance = Change in time and hence speed is constant.
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The gravitational potential energy of an object
depends on ....
[mark all correct answers]
a. mass of the object
b. velocity of the object
c. gravitational field
d. height of the object
e. stretch of the object
f. stiffness of the object
The gravitational potential energy of an object depends on mass of the object, gravitational field and height of the object.
What is gravitational potential energy?
The gravitational potential energy of an object is the energy possessed by the object due to the object's position above the ground level.
P.E = mgh
where;
m is mass of the objectg is acceleration due to gravityh is the height of the objectThe factors affecting gravitational potential energy of an object include;
mass of the objectheight of the objectacceleration due to gravity or gravitational fieldThus, the gravitational potential energy of an object depends on mass of the object, gravitational field and height of the object.
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An objects
A) weight
B) density
C) mass
D) Any of these.
determines the extent of resistance to a change of motion.
OA
OB
OC
OD
Answer:
B
Explanation:
A rectangular pool is 3 feet wide. It is 4 times as long as it is wide. Label the diagram with the dimensions of the pool. Then find the perimeter of the pool.
The perimeter of the pool is measured as 30 feet.
What is the perimeter?We know that a rectangle is a four sided polygon recall that a polygon is any figure that has n sides. The number of sides in a polygon could move from three to infinity. The polygons come in different shapes and are solids with definite values of surface areas and volumes.
The rectangle is four sided which each of the angles of the rectangle adding up to give 360 degrees. It must be noted that the opposite sides of the rectangle are equal to each other.
We have the following information;
Length of the pool = 4(3 feet) = 12 feet
Width of the pool = 3 feet
Since perimeter = 2 ( length + width)
Perimeter = 2( 12 + 3)
Perimeter = 30 feet
Hence, the perimeter of the pool is measured as 30 feet.
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An auto's velocity increases uniformly from 6.0 m/s to 20 m/s while covering 70 m in a straight line. Find the acceleration and the time taken.
An auto's velocity increases uniformly from 6.0 m/s to 20 m/s while covering 70 m in a straight line, its acceleration is 2.6 [tex]m/s^2\\[/tex] and the time taken is 5.4 s.
AccelerationThe probable rate at which an object’s velocity changes with respect to time is referred to as its acceleration in mechanics. They are vector quantities and accelerations.
The direction of the net force acting on an object determines the direction of its acceleration.
Measurement scaleThe meter per second ([tex]m/s^2\\[/tex]) unit of acceleration is used to measure speed. The square meter is a measure of area ([tex]m^2[/tex])
The auto's velocity increases uniformly from 6m/s to 20m/s while it is covering the total of 70m.
Since it increases uniformly, thus we can use equation of motion
[tex]V^2 - U^2 =2as[/tex]
U = 6m/s
V = 20m/s
s = 70 m
Thus,
[tex](20)^2 - (6)^2 = 2*a*70[/tex]
a = 2.6 [tex]m/s^2\\[/tex]
Then for the time, we have
a = [tex]\frac{(V-U)}{t}[/tex]
2.6 = [tex]\frac{20 - 6}{t}[/tex]
t = 5.4 s
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A ball is dropped from the top of a tall building of height = 91 m. What was the magnitude of the velocity of the ball at impact?
The magnitude of gravity use 10
m/s²
Answer to the nearest hundredth of a meter/sec
Draw a position time graph that represents the problem
Draw a velocity time graph that represents the problem.
The magnitude of velocity of the ball dropped from a 91 m tall building at the point of impact is 42.8 m / s
s = ut + 1 / 2 at²
a = v / t
s = Distance
u =Initial velocity
a = Acceleration
t = Time
s = 91 m
a = 10 m / s²
s = ut + 1 / 2 at²
91 = 0 + ( 1 / 2 * 10 * t² )
t = √ ( 18.2 )
t = 4.27 s
v = 10 * 4.27
v = 42.7 m / s
The position-time graph and the velocity-time graph that represents the problem is drawn in the image attached.
Therefore, the magnitude of velocity of the ball is 42.7 m / s
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An archer stands at rest on a frictionless frozen lake; his total mass including his bow and quiver of arrows is 60.00 kg. He then fires a 0.030kg arrow at 50.0 m/s at an angle of 30.0° above the horizontal. If it takes 650N of force to break the ice and the arrow leaves the bow in 10ms, what force does the archer exert on the ice?
The speed of the archer is 0.15m/s
The weight of the arrow compared to the man is
60/0.03 = 2000.
Thus, the man is 2000x heavier than the arrow.
Momentum is defined as P = m v or mass times velocity.
This must always be conserved. Since they stand at rest, the total momentum is zero.
The momentum of the arrow once shot is
50 x 0.03,
and thus the momentum of the archer is given by
60 x speed = 50 x 0.03
This rearranges into speed = (50 x 0.03) / 60
=0.15m/s
The speed of the archer is
=(speed of the arrow x mass of the arrow) / mass of the archer
=(50 × 0.030)/60
=0.15m/s
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A skateboarder travels on a horizontal surface with an initial velocity of 3.6 m/s toward the south and a constant acceleration of 2.6 m/s2 toward the east. Let the x direction be eastward and the y direction be northward, and let the skateboarder be at the origin at t=0 .
What is her x position at t=0.80s ?
What is her y position at t=0.80s ?
What is her x velocity component at t=0.80s ?
What is her y velocity component at t=0.80s ?
a. Her x position at t = 0.80 s is 0.0832 m
b. Her y position at t = 0.80 s is -28.8 m
c. Her x velocity component at t = 0.80s is 2.08 m/s
d. her y velocity component at t = 0.80s is -3.6 m/s
Since the skateboarder travels on a horizontal surface with an initial velocity of 3.6 m/s toward the south and a constant acceleration of 2.6 m/s² toward the east.
Her velocity v = (0i - 3.6j) m/s and her acceleration a = (2.6i + 0j) m/s²a. What is her x position at t = 0.80s ?Now since she starts from the origin, to find her x position after 0.80 s, using the equation of motion for the x - components of motion,
x = ut + 1/2at² where
u = x - component of velocity = 0 m/s, a = x - component of acceleration = 2.6 m/s² and t = time = 0.8 sSo, substituting the values of the variables into the equation, we have
x = ut + 1/2at²
x = 0 m/s × 0.8 s + 1/2 × 2.6 m/s² × (0.8 s)²
x = 0 m + 1.3 m/s² × 0.64 s²
x = 0 m + 0.832 m
x = 0.832 m
So, her x position at t = 0.80 s is 0.0832 m
b. What is her y position at t = 0.80s ?Using the equation of motion for her y - components of motion, her y position is y = ut + 1/2at² where
u = y - component of velocity = -3.6 m/s, a = y - component of acceleration = 0 m/s² and t = time = 0.8 sSo, substituting the values of the variables into the equation, we have
y = ut + 1/2at²
y = -3.6 m/s × 0.8 s + 1/2 × 0 m/s² × (0.8 s)²
y = -3.6 m × 0.8 s + 0
y = -28.8 m
So, her y position at t = 0.80 s is -28.8 m
c. What is her x velocity component at t = 0.80s ?Using the equation of motion for her x - component of motion, her x velocity compoent after t = 0.8 s is
v = u + at where
u = initial x - component of velocity = 0 m/s, a = x - component of acceleration = 2.6 m/s² and t = time = 0.8 sSo, we have
v = u + at
v = 0 m/s + 2.6 m/s² × 0.8 s
v = 0 m/s + 2.08 m/s
v = 2.08 m/s
So, her x velocity component at t = 0.80s is 2.08 m/s
d. What is her y velocity component at t = 0.80s ?Using the equation of motion for her y - component of motion, her xyvelocity compoent after t = 0.8 s is
v = u + at where
u = initial y - component of velocity = -3.6 m/s, a = y - component of acceleration = 0 m/s² and t = time = 0.8 sSo, we have
v = u + at
v = -3.6 m/s + 0 m/s² × 0.8 s
v = -3.6 m/s + 0 m/s
v = -3.6 m/s
So, her y velocity component at t = 0.80s is -3.6 m/s
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a ball is thrown vertically upward with a speed of 19 m/s from a height of 7 m. how high does the ball rise from original position?
The ball rise 18.42 m from its original position.
What is Height?Height is the vertical distance between two points.
To calculate the height of the ball, from the original position, we use the formula below.
Formula:
v² = u²+2gh.......... Equation 1Make h the subject of the equation
h = (v²-u²)/2g...........Equation 2Where:
v = Final speedu = Initial speedg = Acceleration due to gravityh = Height of the ball from the original positionFrom the question,
v = 0 m/su = 19 m/sg = -9.8 m/s²Substitute these values into equation 2
h = (0-19²)/(2)×(-9.8)h = -361/-19.6h = 18.42 mHence, the ball rise 18.42 m from its original position.
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