A dog runs after a ball that is 45 meters away. It takes him 9 seconds to reach the ball. How fast is the dog running?

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Answer:

Gravitational potential energy and Elastic potential energy

Explanation:

The two types of potential energy the springs described in the question have are Gravitational potential energy and Elastic potential energy.

Firstly, it must be noted that potential energy is the energy stored/present in a stationary (non-moving) object (or object at rest).

Gravitational potential energy is the potential energy as a result of the vertical position of an object due to force of gravity acting to pull it down. The gravitational potential energy is as a result of the springs been attached to the ceiling which causes the force of gravity to want to pull it down. This gravitational force is further increased when the swing is attached causing the weight of swing to act in the direction of the force of gravity.

Elastic potential energy is the potential energy stored in an elastic object or energy stored in an object that can be stretched or compressed. This is the energy that would always be found in a spring, so when the springs have been attached to the ceiling and the swing has been fastened to them, there elastic potential energy would reduce as a result of the kinetic energy that must have been used to stretch the springs.

For this we have the hidrostatic equation:

[tex]\boxed{P = \rho gh}[/tex]

Being:

P = Pressure

ρ = Density of liquid (water) = 1000 kg/m

g = Gravity = 9,81 m/s²

h = Height = 4 m

Replacing acording formula:

[tex]\boxed{P = 1000 \ kg/m ^{3} * 9,81 \ m/s^{2} * 4 \ m}[/tex]

Resolving:

[tex]\boxed{P = 39240 \ Pa}[/tex]

Result:

The pression at the bottom is 39240 Pa.

Answer:

a) 800 J

Explanation:

Work is said to be done when a force induces movement over a distance in an object. The amount of work done (W) is calculated by multiplying the force by the distance traveled.

That is;

W = F × d

Where;

W = work done (J or N/m)

F = force (N)

d = distance (m)

In the information given in this question, F = 40N, d = 20m

Hence,

Work done = 40N × 20m

Work done = 800N/m or 800 J

Answer: True

Explanation:

Answer:

I'll give you all the answers, I know them all, I just did this. I need $1 via cas ap tho since it's hard

Apparent magnitude refers to the properties which best measures a star's brightness and is denoted as option D.

This is a term commonly used in astronomical system which talks about the brightness of a star based on its composition such as hydrogen and helium.

it is also determined by how far or bright it is from the planet such as earth when they are viewed by individuals which is regarded as the property in which astronomers use to define its brightness.

This is therefore the reason why apparent magnitude was chosen as the correct choice.

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Answer:

A: Absolute magnitude

Explanation:

I Just did it and the correct answer is ABSOLUTE MAGNITUDE

Answer:

The displacement of the object is -8 m

Explanation:

Displacement

The displacement of a moving object can be calculated as the area under (or above) the graph of velocity vs time.

If the area is below the y-axis, then the displacement is negative. Otherwise is positive.

It's important to differentiate displacement from distance. Displacement takes into consideration the direction of the movement. Distance does not and it's always positive.

From the graph provided, we can see the velocity from t=12 s from t=16 s is negative, and the displacement will also be negative.

The displacement is calculated as the area of the triangle with base b=16-12= 4 seconds and height = -4 m/s, thus:

[tex]\displaystyle D = \frac{4*(-4)}{2}=-\frac{16}{2}=-8\ m[/tex]

The displacement of the object is -8 m

The end of the detergent molecule which attaches to fat (grease) repels water molecules. It is known as hydrophobic, meaning "water fearing." By attempting to move away from the water molecules, the hydrophobic ends of the detergent molecules push up to the surface. This weakens the hydrogen bonds holding the water molecules together at the surface. The result is a break in the surface tension of the water.

Answer:

In a soap-and-water solution the hydrophobic (greasy) ends of the soap molecule do not want to be in the liquid at all. Those that find their way to the surface squeeze their way between the surface water molecules, pushing their hydrophobic ends out of the water. This separates the water molecules from each other.

Explanation:

The velocity of Jay after five minutes is 1 Km/min. The greatest speed occurred at 45 mins.

The velocity time graph is a representation of the movement of a body a body from one point to another. It is the plot of the velocity on the vertical axis against the time on the horizontal axis. Ideally this graph would be divided into three portions;

We can be able to read off from the graph, the instantaneous velocity of the object at any time. This could be done by tracing the time against the velocity axis and extrapolating according from the graph as shown.

Recall that the acceleration of the body is obtained as the slope of the velocity time graph at any point and the acceleration could be uniform or non uniform as judged from the velocity time graph.

Having said all these, it is clear that the velocity of Jay after five minutes is 1 Km/min.

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Answer:

5000 J

Explanation:

W=F*D

W=500N*10m

w=5000 J

When a man applies a force of 500 N to push a truck 10 m down the street. Then the work of 5000 J has been done.

Work done is the amount energy gained (loosed) in bringing the body from initial position to final position. It is denoted by W and its SI unit is joule(J). i.e. Work(W) is force(F) times displacement(s). W=F× s When a body is displaced with 1 newton of force by 1 m, then we can say that work has been done on the body by 1 joule.

Writing for it's dimension, W=F× s

Force has dimension [L¹ M¹ T²]

Displacement has dimension [L¹]

multiplying both the dimensions Force and Displacement we get, dimension of Work [L² M¹ T²].

Given,

F = 500 N

s = 10 m

Work = Fs = 500×10 = 5000 J

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The best radioisotope that can be used for radioisotope imaging and for radionuclide therapy is It emits beta particles and gamma rays.

It is a treatment in which ionizing radiation (X-ray, for example) is used to destroy a tumor or prevent its cells from increasing. These radiations are not seen and during the application the patient does not feel anything. Radiation therapy can be used in combination with chemotherapy or other treatments.

in this case, the best radioisotope that can be used for imaging is radionuclide because It emits beta particles and gamma rays.

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Answer:

It emits beta particles and gamma rays.

Explanation:

To find limits of the amplitude of motion of real vibrating system that is driven at one of its resonant frequencies, Here the damping of vibrations  turns the energy of vibration into internal energy.

(a) The height reached by cat A is 2.5 m.

(b) The speed of cat A before it hits the ground is 36.4 m/s.

(c) The speed of cat B before it hits the ground is 22.39 m/s.

(d) The time spent in air by cat A than cat B is 1.43 seconds.

The time of motion of cat A is calculated as follows;

h = vt - ¹/₂gt

-23 = 7t - 4.9t²

4.9t² - 7t - 23 = 0

solve the quadratic equation using formula method;

a = 4.9, b = -7, c = - 23

t = 3.0 seconds

The time of motion of cat B is calculated as follows;

h = vt - ¹/₂gt

23 = 7t + 4.9t²

4.9t² + 7t - 23 = 0

solve the quadratic equation using formula method;

a = 4.9, b = 7, c = -23

t = 1.57 seconds

h = u²/2g

h = (7²)/(2 x 9.8)

h = 2.5 m

v = u + gt

v = 7  + 3(9.8)

v = 36.4 m/s

v = u + gt

v = 7  + 1.57(9.8)

v = 22.39 m/s

Time difference = 3 s - 1.57 s = 1.43 seconds

Thus, the height reached by cat A is 2.5 m.

The speed of cat A before it hits the ground is 36.4 m/s.

The speed of cat B before it hits the ground is 22.39 m/s.

The time spent in air by cat A than cat B is 1.43 seconds.

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Answer:

A. higher, lower

Explanation:

Hope this helps!     :3

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Answer:

323.4N

Explanation:

Given parameters:

Mass of the box = 33kg

Unknown:

Normal force on the body  = ?

Solution:

The normal force of a body is the vertical force the body exerts on another body.

It is expressed as;

        Normal force  = mass x acceleration due to gravity

Acceleration due to gravity  = 9.8m/s²

Normal force  = 33 x 9.8  = 323.4N

Answer:

1) The Speed of the plane is approximately 39.596 m/s

2) Please find attached the required velocity and acceleration graphs

Explanation:

1) The height at which the plane was flying, h = 500 m

The location the bottle lands from the initial dropping point = 400 m

The time it takes the bottle to land is given by the equation for free fall as follows;

h = 1/2·g·t²

Where;

g = The acceleration due to gravity = 9.8 m/s²

t = √(h/(1/2·g) = √(500/(1/2×9.8) ≈ 10.102

The Speed of the plane = The horizontal velocity of the bottle = 400/10.102 ≈ 39.596

The Speed of the plane ≈ 39.596 m/s

2) Please find attached the velocity graph for the vertical and horizontal velocities of the bottle and the acceleration graph for the vertical motion of the bottle, created with Microsoft Excel

Answer:

the answer would be D because not only is it going up but it's going up as an angle

Answer:

Electrical energy

Explanation:

electrical energy Essentials. A battery is a device that stores chemical energy and converts it to electrical energy. The chemical reactions in a battery involve the flow of electrons from one material (electrode) to another, through an external circuit. The flow of electrons provides an electric current that can be used to do work.

Answer:

I would say D. Believable. Sorry if its wrong.

Explanation:

The study of the physical properties of light, such as its wavelength and amplitude, and the human perception of color is called psychophysics. It comprises two major areas: discrimination and absolute.

The study of wavelength and amplitude, interaction between physical stimuli and their consequential effects such as perceptions and sensations is called psychophysics.

This concept is applied in psychophysics tasks where extensive research and studies are performed on sensory and other visual information.

To put it in simple words, psychophysics is vital for measuring the perception of a subject through stimulus detection experiments.

Stimuli detection is done either through the method of limits, adjustment technique, or constant stimuli method.

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Answer:

11m/s

Explanation:

Given parameters:

Mass of the lead shot = 8kg

Energy of the shot  = 484J

Unknown:

Velocity of the shot  = ?

Solution:

To solve this problem, we apply the kinetic energy formula;

        K.E  = [tex]\frac{1}{2}[/tex] m v²  

m is the mass

v is the unknown

 Now, insert the parameters and solve;

        484  = [tex]\frac{1}{2}[/tex] x 8 x v²

        484  = 4v²

           v² = 121

            v  = 11m/s

Answer:

5.9 x 10⁻⁷m

Explanation:

Given parameters:

Frequency = 5.085 x 10¹⁴Hz

Speed of light  = 3.0 x 10⁸m/s

Unknown:

Wavelength of the orange light  = ?

Solution:

The wavelength can be derived using the expression below;

            wavelength  = [tex]\frac{v}{f}[/tex]

v is the speed of light

f is the frequency

            wavelength  = [tex]\frac{3 x 10^{8} }{5.085 x 10^{14} }[/tex]   = 5.9 x 10⁻⁷m

Answer:

12500W

Explanation:

Given parameters:

Work done  = 250000J

Time taken  = 20s

Unknown:

Power of the crane = ?

Solution:

Power is the defined as the rate at which work is being done;

  Mathematically;

        Power = [tex]\frac{work done}{time }[/tex]

 insert the parameters and solve;

      Power  = [tex]\frac{250000}{20}[/tex]   = 12500W

Hello!

C. KE ≈ 9120.105 J

D. m = 151.45 kg

Question C:

Calculate kinetic energy using the formula:

[tex]KE = \frac{1}{2}mv^{2}[/tex]

Substitute in the given mass. We have to convert kilometers to meters in order to solve.

[tex]\frac{42km}{1hr} * \frac{1hr}{3600sec} *\frac{1000m}{1km} = 11.67 m/s[/tex]

Use the equation above:

KE = 1/2(1563)(11.67)

KE ≈ 9120.105 J

Question D:

Plug in the given Kinetic Energy and velocity to solve. Convert kilometers/hour to meters/second:

[tex]\frac{7km}{1hr} * \frac{1hr}{3600sec} *\frac{1000m}{1km} = 1.94 m/s[/tex]

[tex]KE = \frac{1}{2}mv^{2}[/tex]

285 = 1/2(m)(1.94²)

570 = (1.94²)m

151.45kg = m

Answer:

D. Time t = 1 [s]

Explanation:

To solve this problem we must use the following equation of kinematics.

[tex]v_{f}=v_{o}-g*t[/tex]

where:

Vf = final velocity = 0 (when the ball reaches the maximum height its elevation won't be increased since the velocity is zero)

vi = initial velocity = 10 [m/s]

g = gravity acceleration = 10 [m/s²]

t = time [s]

Now replacing:

[tex]0 = 10-10*t\\10 = 10*t\\t = 1 [s][/tex]