Answer:
16m/s
Explanation:
Given the following data;
Force, F = 16N
Mass, m = 5kg
Time, t = 5 seconds.
First of all, we would find the acceleration of the object.
Force is given by the multiplication of mass and acceleration.
Mathematically, Force is given by the formula;
[tex] F = ma[/tex]
Where;
F represents force.m represents the mass of an object.a represents acceleration.Making acceleration (a) the subject, we have;
[tex]Acceleration, a = \frac{F}{m}[/tex]
Substituting into the equation;
[tex]Acceleration, a = \frac{16}{5}[/tex]
Acceleration, a = 3.2 m/s²
Now, to find velocity;
We would use the first equation of motion given by the formula;
[tex] V = U + at[/tex]
Where;
V is the final velocity. U is the initial velocity. a is the acceleration. t is the time measured in seconds.We know that acceleration due to gravity is 9.8m/s² and initial velocity (U) is 0 since the object is at rest.
Substituting into the equation, we have;
[tex] V = 0 + 3.2*5[/tex]
[tex] V = 0 + 16[/tex]
Velocity, V = 16m/s.
What happens when light from the sun passes through any type of matter
Answer:
its it filled with energy
Answer:
The light slows down.
Explanation:
How does the movement of thermal energy differ from that of other forms of energy?
heat and thermal energy can be differentiated as is that thermal energy is not actually transferred. It is not moving, but remains part of the system's internal energy. Heat, on the other hand, is a passing energy. H. Energy transferred from a hotter system.
In summary, thermal energy is the energy hipster. As such, it cannot be converted into other types of energy. Only the difference in thermal energy can be converted/used to do work. Such processes are never 100% efficient. Every energy form that cannot be recovered.
Thermal energy transfer occurs in three ways: convection, conduction and radiation. When heat energy is transferred between adjacent molecules that are in contact with each other, it is called conduction
Thermal energy and temperature are closely related. However, temperature is the average kinetic energy of matter particles and thermal energy is the total kinetic energy of matter particles.
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calculate the load placed 10m from the fulcrum that can be balanced by an effort of 5 N applied at a distance of 4 m from the fulcrum in a lever .
Answer:
L/E =de/dl so dl is 10m de=4m E=5N
Explanation:
L=(de x E)/dl = 2N
so when load is < effort it is speed multiplayer
1. Why is physics sometimes called the fundamental science?
Because it explains the basics of all sciences
Because it examines the rules that govern the universe
Because it does not require experiments or the scientific method
Because it was developed before any other branch of science
Because it is the easiest branch of science to understand
Explanation:
Because it is the easiest branch of science to understand
How much work is done by an applied mass to lift 55 kg block and 4.5 meter high?
Given=
Unknown=
Formula=
Solution=
Answer=
Answer:
Given = 55kg, 4.5 m
Unknown = Work done
Formula = (mg) × d
Solution = 2425.5 J
Answer = 2425.5 J
Explanation:
Formula we use,
→ W = (mg) × d
Then the value of work done is,
→ (55 × 9.8) × 4.5
→ 539 × 4.5
→ 2425.5 J
Hence, the work done is 2425.5 J.
what is the job title) makes the decision regarding the quality of produce and if it will be sold fresh or processed?
. Emily pushes a 38.8 kg grocery cart of groceries by exerting a 76.0 N force on the handle inclined at 40.0 degrees below the horizontal. What are:
a. The horizontal and vertical components of Emily’s force
b. The acceleration of the cart?
Answer:
a) [tex]F_{x} = 58.2 N[/tex]
[tex] F_{y} = 48.9 N [/tex]
b) a = 1.5 m/s²
Explanation:
a) The horizontal and vertical components of Emily's force can be found knowing the angle and the exerted force.
Since the handle is inclined at 40.0° below the horizontal we have:
[tex] F_{x} = |F|*cos(\theta) = 76.0 N*cos(40) = 58.2 N [/tex]
[tex] F_{y} = |F|*sin(\theta) = 76.0 N*sin(40) = 48.9 N [/tex]
b) The acceleration of the car can be calculated as follows:
[tex] F_{x} = ma [/tex]
We used the horizontal component of the force because the cart is moving in that direction.
[tex] a = \frac{F_{x}}{m} = \frac{58.2 N}{38.8 kg} = 1.5 m/s^{2} [/tex]
Hence, the acceleration of the car is 1.5 m/s².
I hope it helps you!
Which measurement is used to determine if an object has balanced forces
Answer:
a spring scale
Explanation:
i think it is correct
a 1.0 kg ball falls from rest a distance of 15m. what was its change in potential energy
Answer:
112.5 J
Explanation:
I calculated it by K/G BY M/S TO POTENTIAL ENERGY.
Given values are:
Mass, m = 1.0 kgDistance, h = 15 mg = 9.8 m/s²The change in Potential energy is:
→ [tex]\Delta PE = mgh[/tex]
By substituting the values, we get
[tex]= 1.0\times 9.8\times 15[/tex]
[tex]= 147 \ J[/tex]
Thus the above response is correct.
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5. Correct the statement : Human being
can hear sounds of frequencies upto
60000Hz.
Answer:
Humans can detect sounds in a frequency range from about 20 Hz.
A ball is thrown horizontally at a height of 1.5 meters at a velocity of 70 m/s. Assume no air resistance. How long until the ball reaches the ground?
0.25 s
0.38 s
0.55 s
0.67 s
Answer:
[tex]t = 0.55[/tex]
Explanation:
Given
[tex]Height, s = 1.5m[/tex]
[tex]Velocity, v = 70m/s[/tex]
Required
Determine the time to hit the ground
Using free fall formula:
[tex]S = \frac{1}{2}gt^2[/tex]
Take g as 9.8 and substitute value for S
[tex]1.5 = \frac{1}{2} * 9.8 * t^2[/tex]
[tex]1.5 = 4.9 * t^2[/tex]
Make t^2 the subject
[tex]t^2 = \frac{1.5}{4.9}[/tex]
[tex]t^2 = 0.30612244898[/tex]
Solve for t
[tex]t = \sqrt{0.30612244898[/tex]
[tex]t = 0.55[/tex] -- approximated
What do you mean by Galvanometer Constant?
Answer:
It is a value that reading in the galvanometer must be multiplied with to get the ordinary unit
Explanation:
What is a galvanometer?
A galvanometer is an electromechanical instrument used for detecting and indicating an electric current.
A Number by which a certain function of the reading of a galvanometer must be multiplied to obtain the current value in ordinary units is a galvanometer constant
A diffraction pattern is formed on a screen 150 cm away from a 0.500-mm-wide slit. Monochromatic 546.1-nm light is used. Calculate the fractional intensity I/Imax at a point on the screen 4.10 mm from the center of the principal maximum.
Solution :
The expression for the intensity of light is given by :
[tex]$I=I_{max}\left(\frac{\sin \frac{\pi a \sin \theta}{\lambda}}{\frac{\pi a \sin \theta}{\lambda} }\right)^2$[/tex]
For a small angle, θ
sin θ = tan θ
[tex]$=\frac{y}{L}$[/tex]
Therefore the above equation becomes,
[tex]$I=I_{max}\left(\frac{\sin \frac{\pi a y}{\lambda L}}{\frac{\pi a y}{\lambda L} }\right)^2 $[/tex]
The given data is
λ = 546.1 nm
L = distance between the slit and the screen = 140 cm
= 1.40 m
a = width of the slit
= [tex]$0.50 \times 10^{-3} \ m$[/tex]
Therefore,
[tex]$I=I_{max}\left(\frac{\sin \frac{\pi \times 0.50 \times 10^{-3} \times 4.10 \times 10^{-3}}{546.1 \times 10^{-9} \times 1.20}}{\frac{\pi \times 0.50 \times 10^{-3} \times 4.10 \times 10^{-3}}{546.1 \times 10^{-9} \times 1.20} }\right)^2 $[/tex]
[tex]$=\left(\frac{0.170}{9.82}\right)^2$[/tex]
[tex]$= 2.89 \times 10^{-4} \ I_{max}$[/tex]
Therefore the fractional intensity is [tex]$\frac{I}{I_{max}}= 2.89 \times 10^{-4} $[/tex]
A swimmer speeds up from 1.1 m/s to 3.2 m/s during the last 13.0 seconds of the race. What is the acceleration of the swimmer?
Answer:
a = 0.16 [m/s²]
Explanation:
To solve this problem we must use the following equation of kinematics.
[tex]v_{f}=v_{o}+a*t\\[/tex]
where:
Vf = final velocity = 3.2 [m/s]
Vo = initial velocity = 1.1 [m/s]
t = time = 13 [s]
a = acceleration [m/s²]
Now replacing:
[tex]3.2=1.1+a*13\\2.1=13*a\\a=0.16[m/s^{2} ][/tex]
A rock is thrown straight up with an initial speed of 22 m/s. How long will it be in the air before it returns to the thrower?
Answer:
The time spent in air by the rock before it returns to the thrower is 4.5 s
Explanation:
Given;
initial velocity of the rock, u = 22 m/s
Neglecting air resistance, the time it takes the rock to go up equals the time it takes it to return to the thrower. This is also called time of flight.
The time to go up is calculated as;
v = u - gt
where;
v is the final velocity at the maximum height
0 = u - gt
gt = u
t = u / g
t = 22 / 9.8
t = 2.245 s
thus time to go up = 2.245 s
and time to return to the thrower = 2.245s
The total time spent in air by the rock before it returns to the thrower
= 2.245 s + 2.245s
= 4.5 s
Need Help Please and Thank You). Question 1: Explain how longitudinal waves and transverse waves are similar to each other and different from each other. Question 2) Compare and contrast reflection and refraction. Question 3) What does it mean that energy is neither created nor destroyed? ( Please No Plagiarism and Be 100% positive with your answer. Will Mark Brainliest. If you write anything down that doesn't contain to my question you will be reported. Need two answers.
1) The longitudinal waves move in parallel direction to the source of vibration. The transverse waves move in perpendicular direction to the source of vibration . They are similar in the sense that energy is transferred in the form of waves.
2) Reflection occurs when waves bounce from a surface back toward the source. Refraction is when waves are deflected when the waves go through a substance.
3) The Law of Conservation of Energy
states that energy can neither be created
nor destroyed, it can only be transferred or
changed from one form to another.
A rocket burns fuel at a rate of 199 kg/s and exhausts the gas at a relative speed of 9 km/s. Find the thrust of the rocket. Answer in units of MN.
Answer:
1.791 MN
Explanation:
Thrust of the rocket can be found using the relation
T = v.dm/dt, where
T = thrust off the rocket
v = speed of the rocket, 9 km/s = 9000 m/s
dm/dt = rate at which fuel burns, 199 kg/s
Substituting the values into the formula, we have
T = 9000 * 199
T = 1791000 N
T = 1.791*10^6 N
Since 1 MN = 10^6, thus
T = 1.791 MN
The thrust of the rocket in units of MN is 1.71 Meganewton.
Given the following data:
Rate = 199 kg/sRelative speed = 9 km/s.Conversion:
Relative speed = 9 km/s to m/s = 9000 m/s
To determine the thrust of the rocket in units of MN:
Mathematically, the thrust of an object is given by this formula:
[tex]Thrust = V\frac{dm}{dt}[/tex]
Substituting the given parameters into the formula, we have;
[tex]Thrust = 9000 \times 199[/tex]
Thrust = 1,791,000 Newton
In units of MN:
1 MN = [tex]1 \times 10^6\;N[/tex]
Thrust = 1.71 MN
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Determine whether the inertia of an object changes as the object's
velocity changes.
Answer:
The inertia of an object does not change as the objects velocity changes because the inertia will remain the same as long as the mass is the same.
:
A particular engine has a power output of 5 kW and an efficiency of 30%. If the engine expels 6464 J of thermal energy in each cycle, find the heat absorbed in each cycle. Answer in units of J.
Answer:
The heat absorbed in each cycle is 9,234.286 J
Explanation:
Given;
power output, P = 5 kW = 5,000 W
efficiency of the engine, e = 30 % = 0.3
thermal heat expelled, [tex]Q_c[/tex] = 6464 J
let the heat absorbed = [tex]Q_h[/tex]
The efficiency of the engine is given as;
[tex]e = \frac{W}{Q_h} = \frac{Q_h-Q_c}{Q_h} = \frac{Q_h}{Q_h} - \frac{Q_c}{Q_h} = 1-\frac{Q_c}{Q_h}\\\\e = 1-\frac{Q_c}{Q_h}\\\\0.3 = 1-\frac{Q_c}{Q_h}\\\\\frac{Q_c}{Q_h} = 1-0.3\\\\\frac{Q_c}{Q_h} = 0.7\\\\Q_h = \frac{Q_c}{0.7} \\\\Q_h = \frac{6464}{0.7} = 9,234.286 \ J.[/tex]
Therefore, the heat absorbed in each cycle is 9,234.286 J.
Uses Hooke's Law to solve this problem. If a force of N stretches a spring m beyond its natural length, how much work does it take to stretch the spring m beyond its natural length?
Answer:
Work done = 1/2 × Ne
Explanation:
Given that if a force of N stretches a spring m beyond its natural length, how much work does it take to stretch the spring m beyond its natural length
Using Hook's law
Force = N
Let the extension = e
Work done in stretching spring m beyond its natural length will be
Workdone = 1/2 × Ne
Or
From Hook law,
N = Ke
Work done = 1/2 × Ke^2
The physical quantity which have both magnitude and direction is a vector?why?
Answer:
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A 0.500 kg object tied to a string is swung around a person's
head in a horizontal circle. The length of the string is 1.00 m
and the maximum force the string can withstand without
breaking is 25.0 N. What is the maximum speed the object may
be swung without breaking the string?
Answer:
25 N
If you’re doing ck-12
The object may be swung with maximum velocity of 7.07 m/s without breaking the string.
What is centripetal force?The centripetal force definition states that: The force applied to an item in curved motion that is pointed toward the axis of rotation or the centre of curvature is known as a centripetal force.
Newtons are used to measure centripetal force.
Given that:
mass of the object = 0.500 kg.
The length of the string = 1.00 m.
If the maximum speed of the object be v,
maximum centripetal force be = 0.5v²/1.0 N = v²/2 N.
As the maximum force the string can withstand without breaking is 25.0 N,
25.0 = v²/2
⇒ v = 5√2 m/s = 7.07 m/s.
Hence, the object may be swung with maximum velocity of 7.07 m/s without breaking the string.
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A trailer truck traveling east at 38 m/s sounds a 1300 Hz horn. what is the wavelength stationary listener west?
Answer:
0.0292mExplanation:
The velocity of sound wave is expressed using the formula;
[tex]v = f \lambda[/tex] where
f is the frequency
[tex]\lambda\\[/tex] is the wavelength
Given
f = 1300Hz
v = 38m/s
Required
wavelength [tex]\lambda\\[/tex]
From the formula;
[tex]\lambda\\[/tex] = v/f
[tex]\lambda\\[/tex] = 38/1300
[tex]\lambda\\[/tex] = 0.0292m
Hence the required value of the wavelength is 0.0292m
The wavelength of a stationary listener is 0.029 m.
The given parameters;
speed of the truck's sound, v = 38 m/sfrequency of the truck's sound, f = 1300 HzThe wavelength of a stationary listener is calculated as follows;
[tex]v = f\lambda[/tex]
where;
λ is the wavelength of the sound wave
The value of the wavelength is determined as;
[tex]\lambda = \frac{v}{f} \\\\\lambda = \frac{38}{1300} \\\\\lambda = 0.029 \ m[/tex]
Thus, the wavelength of a stationary listener is 0.029 m.
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Which describes one feature of the image formed by a convex mirror?????
Answer:
The image formed by a convex mirror will always have its smaller than the size of the object no matter what the position of the object.
Explanation:
The image formed by a convex mirror will always have its smaller than the size of the object no matter what the position of the object.
Also notice that convex mirror always makes virtual images.
Another feature of the convex mirror is that an upright image is always formed by the convex mirror.
An important mirror formula to remember which is applicable for both convex and mirrors
1/f= 1/u + 1/vHere:
'u' is an object which gets placed in front of a spherical mirror of focal
length 'f' and image 'u' is formed by the mirror.
Answer:
right side up
Explanation:
You are driving your car down a straight road at a constant speed of 23 m/s
(about 50 mi/h). What is your acceleration?
Answer:
0 m/s^2
Explanation:
If you're driving at constant speed in the same direction, your acceleration is always 0 m/s^2. acceleration is a vector, so any change in speed or direction would result in acceleration.
As the angle between two concurrent forces is
decreased from 55° to 15°, the magnitude of
the resultant force
Answer:
resultant increases by factor of 1.12
Explanation:
EDITED :
Assume force = 1 for simplicity and one vector is on the x axis
at 55 degrees
horizontal components = 1 + cos 55 = 1.574
vertical component = sin 55 = .8192
resultant = 1.77
at 15 degrees
horizontal components = 1 + cos 15 = 1.966
vertical component = sin 15 = .2588
resultant = 1.98
resultant increases by 1.98 / 1.77 = 1.12 original
A baseball accelerates at 15m/s2, changing its velocity from 0m/s to 50 m/s down the way. How long did it take the baseball to accelerate?
Answer:
3.33s
Explanation:
Given parameters:
Acceleration = 15m/s²
Initial velocity = 0m/s
Final velocity = 50m/s
Unknown:
Time taken for the acceleration = ?
Solution:
To solve this problem, we must understand that acceleration is the rate of change of velocity with time.
Mathematically;
a = [tex]\frac{v - u}{t}[/tex]
a is the acceleration
v is the final velocity
u is the initial velocity
t is the time taken
So;
15 = [tex]\frac{50 - 0}{t}[/tex]
15t = 50
t = 3.33s
what are the different intensity of an earthquake
Ranking Earthquake Intensity
Magnitude Average number per year Modified Mercalli Intensity
2.0 – 2.9 >1 million I
3.0 – 3.9 about 100,000 II – III
4.0 – 4.9 about 10,000 IV – V
5.0 – 5.9 about 1,000 VI – VII
Explanation:
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Im need some help with this please
Answer:
c) Aeroplane
Explanation:
The aeroplane has the greatest mass than the other three objects, so it experiences the greatest gravitational force. Hence, the option (c) is the answer.
A train travels 6 meters in the first second of travel, 6 meters again during the second second of travel, and 6 meters again during the third second. Its acceleration is
velocity of the train is same so acceleration of the train is zero.
Acceleration of an object is known as change in velocity of the object. For a given interval of time.
Distance travelled by the train in first second is, d₁ = 6m
Distance travelled by the train in the 2nd second is, d₂ = 6m
Distance traveled by the train in 3rd second, d₃ = 6m
Formula for the velocity of the train.
v= d/t
where v is velocity
d is distance travelled
t is time taken
For first second velocity is
v₁ = d₁/t₁
v1 = 6/1s = 6m/s
for 2nd second velocity is
v₂= d₂/t₂
v₂ = 6/1 = 6m/s
for 3rd second velocity is
v₃ = d₃/t₃
v₃ = 6/1 = 6m/s
here we saw that the speed of train remains constant for each interval of time. So change of velocity is zero.
velocity of the train is same so acceleration of the train is zero.
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