A gas stream contains 18.0 mole% hexane and the remainder nitrogen. The stream flows to a condenser, where its temperature is reduced and some of the hexane is liquefied. The hexane mole fraction in the gas stream leaving the condenser is 0.0500. Liquid hexane condensate is recovered at a rate of 1.50 L/min. N2 C6H14(v) (5.00 mole%) N2 C6H14(v) (18.0 mole%) Liquid condensate 1.50 L C6H14 (l)/min CONDENSER (a) What is the flow rate of the gas stream leaving the condenser in mol/min

Answers

Answer 1

Answer:

the flow rate of the gas stream leaving the condenser is 71.9 moles/min

Explanation:    

Given the data in the question and the figure below;

N2 BALANCE

(100% - 18%) × ( mole rate in ) = ( 100% - 5%) × ( mole rate out)

0.82 × ( mole rate in ) = 0.95 × ( mole rate out)

mole rate in = 0.95 × ( mole rate out) / 0.82

mole rate in = 1.1585365853 × ( mole rate out)

now;

HEXANE BALANCE

0.18 × ( mole rate in ) = 0.0500 × ( mole rate out) + condensate  --- equ 1

but condensate = 1.5 L/min × ( density of hexane ) × 1/molar mass of hexane

we know that;

density of hexane is 0.6548 g/mL

and molar mass of hexane is 86.18 g/mol

so,

condensate = 1.5 L/min × ( 0.6548 g/mL × 1000 mL/L ) × ( 1/86.18 g/mol)

condensate = 11.3970758876

now lets substitute into equation 1

0.18 × ( mole rate in ) = 0.0500 × ( mole rate out) + condensate

⇒ 0.18 × ( 1.1585365853 × ( mole rate out) ) = 0.0500 × ( mole rate out) + 11.3970758876

⇒ 0.208536585354(mole rate out) = 0.0500( mole rate out) + 11.3970758876

⇒ 0.208536585354(mole rate out) - 0.0500( mole rate out) = 11.3970758876

⇒ 0.158536585354(mole rate out) = 11.3970758876

mole rate out = 11.3970758876 / 0.158536585354

mole rate out =  71.889247 ≈ 71.9 moles/min

Therefore, the flow rate of the gas stream leaving the condenser is 71.9 moles/min

A Gas Stream Contains 18.0 Mole% Hexane And The Remainder Nitrogen. The Stream Flows To A Condenser,

Related Questions


Suppose a disease wipes out most of the fox population in
the food web shown.
Mountain
lion
Deer
Hawk
Fox
Rabbit
Owl
Snake
Green
plant
Mouse
Which two populations are most likely to increase as a result?
A. Mountain lion
B. Mouse
ロロロロ
O C. Rabbit
D. Green plant

Answers

If the fox population in the given food web is significantly reduced due to a disease, two populations that are most likely to increase as a result are the populations of A. Mountain lion and C. Rabbit.

The decrease in the fox population can disrupt the balance of the food web. Since foxes are natural predators of rabbits, the reduced presence of foxes would lead to a decrease in predation pressure on rabbits. This would allow the rabbit population to increase because their natural predators are now less abundant. Also, with a decline in the fox population, there would be fewer predators to control the population of smaller animals like mice. Hence, the mouse population could also increase due to reduced predation pressure. The mountain lion population, being a predator higher up in the food chain, may indirectly benefit from the increase in rabbit and mouse populations. The increase in prey availability could potentially lead to an increase in the mountain lion population as they have more food resources available. The green plant population (D) is unlikely to directly benefit from the decrease in the fox population since they are not directly influenced by predation from foxes. Their population dynamics are primarily driven by other factors such as availability of sunlight, water, and nutrient levels. The correct answer is  A. Mountain lion and C. Rabbit

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How many grams of Kr are in 2.00 mol of Kr? (4)

Answers

Answer:

1 mole is equal to 1 moles Krypton, or 83.798 grams.

Explanation:

ANSWER: 168 grams of Kr
This is the rounded answer, but the full answer is 168.7 grams (I’m not sure if you need to use significant figures or not).

Calculate the molality of an ethylene glycol (C2H6O2) soltuion, that has a molarity of 2.07 M. The density of the solution is 1.02 g/mL. Only enter the numerical value with 3 significant figures in the answer box below. Do NOT type in the unit (m).

Answers

Answer:

2.03

Explanation:

Let's assume we have 1 L of the solution:

There would be 2.07 ethylene glycol moles.The solution would weigh (1000 mL * 1.02 g/mL) = 1020 g.

With that information we can calculate the molality:

molality = moles of solute / kg of solventmolality = 2.07 moles / (1020 ÷ 1000) = 2.03 m

Keep in mind that this is only an estimate, as we used the kg of the solution and not of the solvent.

The molality of an ethylene glycol solution is 2.03 kg.

What is molality?

The moles of solute divided by the mass of solvent in kilograms is known as the molality of a solution.

Calculation of molality:

Given that, molarity is 2.07 M

Density is 1.02 g/ml

Step 1: To convert  the litre into grams, multiply the quantity by 1000

The weight of the solution is [tex]\bold{1.02 \;g/ml\; \times 1000 = 1020 g}[/tex]

Now, molality = moles of solute is divided by mass of solvent in kilograms.

[tex]\bold{Molality = 2.07 \times \dfrac{1020}{1000} = 2.03\; kg}[/tex]

Thus, the molality of the solution is 2.03 kg

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   molality = moles of solute / kg of solvent

   molality = 2.07 moles / (1020 ÷ 1000) = 2.03 m

Keep in mind that this is only an estimate, as we used the kg of the solution and not of the solvent.

If a substance has a density of 2.545g / mL how many grams would the substance weigh if the sample has a volume of 122.1 mL?

Answers

Answer: 310.7 grams

Explanation:

Multiply the two values so the units of mL cancel and you get grams

2.545*122.1 = 310.7 grams

The graph below shows a reaction to which a catalyst has been added. How would the graph be different if it showed the same reaction without a catalyst?

A. The width of region 2 would be smaller.

B. The difference in the heights of regions 1 and 3 would be larger.

C. The height of region 2 would be larger

D. The distance between regions 1 and 3 would be smaller​

Answers

Answer:

a. the width of region 2 would be smaller

If the same reaction was shown without a catalyst, the height of region 2 would be larger, so the correct option is (C).

What is catalyst?

A catalyst is a substance that speeds up the rate of a chemical reaction without being consumed in the process. It works by providing an alternate pathway for the reaction with a lower activation energy, making it easier for the reactants to transform into products.

Catalysts can be solids, liquids, or gases, and they can be homogeneous or heterogeneous, depending on whether they are in the same phase as the reactants or in a different phase.

Catalysts are widely used in many industrial processes, such as the production of fertilizers, plastics, and fuels, to increase the efficiency and reduce the cost of the reaction. They can also be found in biological systems, where they play a crucial role in metabolic processes, such as the breakdown of food in the digestive system or the conversion of light into chemical energy in photosynthesis.

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How many atoms are in 4 moles of oxygen?

Answers

Using Avogrado's constant (6.022e23):

4(6.022e23) = 2.41e24

12) How many moles of CO can be produced from
10.0 mol of CO2

Answers

Answer:

5

Explanation:

There are 2 moles of CO in each CO2. 10 ÷ 2 = 5

There diagrams imply that’s
A TISSUEs are always rectangular
B tissues are made up of cells
C Tissues all look the same
D tissues have the same Function

Answers

B-I can’t see the diagram but tissues are a collection of cells

Answer:

b

Explanation:

bsbsbsbbebensnnsjswjjejejejejek

A sample of iron, which has a specific heat capacity of 0.449 Jg^-1℃^-1, is put into a calorimeter (see sketch at right) that contains 100.0 g of water. The iron sample starts off at container 93.3 °C and the temperature of the water starts off at 22.0 °C. When the temperature of the water stops changing it's 25.7 °C. The pressure remains constant at 1 atm.

Required:
Calculate the mass of the iron sample. Be sure your answer is rounded to 2 significant digits.

Answers

Answer:

[tex]m_{iron}=32.1g[/tex]

Explanation:

Hello!

In this case, since the interaction between hot iron and cold water allows the heat transfer from iron to water and therefore we can write up the following energetic equation:

[tex]Q_{iron}+Q_{water}=0[/tex]

Whereas the heat terms can be written in terms of mass, specific heat and temperature change:

[tex]m_{iron}C_{iron}(T_f-T_{iron}) + m_{water}C_{water}(T_f-T_{water}) = 0[/tex]

So we solve for the mass of iron as follows:

[tex]m_{iron} = \frac{m_{water}C_{water}(T_f-T_{water})}{C_{iron}(T_f-T_{iron}) }[/tex]

Now, we plug in the given data to obtain:

[tex]m_{iron} = \frac{-100g*0.449\frac{J}{g\°C} (25.7\°C-22.0\°C)}{0.449\frac{J}{g\°C} (25.7\°C-93.3\°C) }[/tex]

[tex]m_{iron}=32.1g[/tex]

Best regards!

What makes an atom a good conductor?

Answers

Very little electric force is required to cause electron flow in conductors. This is due to electrons called "free electrons", which exist in the atoms of conductors. "Free electrons" are electrons that are very weakly bonded to the atom. ... Metals such as copper, silver, and gold are good conductors.

Well, atoms are loosely bound and free to move through the material. Almost all, or just most, atoms will hold on to electrons very tightly and are insulators.

what is the difference between fluorine and oxygen?

Answers

Answer:

Continuing on across the periodic table we see that fluorine is the next element after oxygen. ... Rather than forming seven bonds fluorine only forms a single bond for basically the same reasons that oxygen only forms two bonds. Hydrogen fluoride, HF, has one bond, but four centers of electron density around the fluorine.

WORTH 18 POINTS! MY LIFE DEPENDS ON THIS ANSWER!!!
Which compound listed below is most likely to have to following properties?
-solid at room temperature
- high melting points
-solble in water
-conductive when dissolved
1.sodium chloride
2.carbon monoxide
3.nitrogen trifluoride
4.none of these compounds could have all of the properties listed

Answers

Answer:

1.sodium chloride

Explanation:

because the others dont have all the listed properties

A 8.15 g sample of hydrogen peroxide (H2O2) decomposes to form water and oxygen. The temperature and pressures conditions in the lab were 21.2oC and 761.4 torr, respectively. The oxygen gas is collected over a sample of water at 21.2oC; the vapor pressure of water at that temperature is 18.9 torr. When the water level inside and outside of the tube is equal the volume of gas is recorded as 176.23 mL. a) Write and balance the equation for the decomposition reaction

Answers

Answer: [tex]H_2O_2\rightarrow H_2+O_2[/tex]

Explanation:

Decomposition is a type of chemical reaction in which one reactant gives two or more than two products.

According to law of conservation of mass, mass can neither be created nor be destroyed. Thus the number of atoms of each element must be same on reactant and product side. Thus chemical equations are balanced.

The balanced equation for the decomposition reaction  of hydrogen peroxide is:

[tex]H_2O_2\rightarrow H_2+O_2[/tex]

Decomposition is a type of chemical reaction in which a chemical breaks into two or more molecules or atoms. One reactant breaks into two products which can be shown as:

                                         XY----->X + Y

The decomposition reaction of hydrogen peroxide can be written as:

                                           

                                              [tex]H_{2}O_{2} = H_{2} + O_{2}[/tex]

According to the mass conserving law the mass can neither be added nor deleted they can just get transferred.

For a reaction to be stable the number of atoms on both sides of the reaction should be balanced.

Therefore, the balanced chemical reaction of decomposition of hydrogen peroxide will be:

                                             [tex]H_{2}O_{2} = H_{2} + O_{2}[/tex]

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Which type of lens would you use in a microscope or telescope and why?​

Answers

Answer:

Microscopes and telescopes often use two lenses to make an image large enough to see. A compound microscope uses two lenses to achieve high magnification. Both lenses are convex, or converging. Light from the object first passes through the objective lens.

Explanation:

A compound microscope uses two lenses to achieve high magnification

how is the massive star born

Answers

Stars form from cold molecular gas and dust when gravitational force overcomes the internal pressure in molecular clouds.

An extraction procedure specifies that an aqueous solution containing dissolved organic material be extracted twice with 10 mL portions of diethyl ether. A student removes the lower layer after the first extraction and adds the second 10 mL portion of ether to the remaining upper layer. After shaking the separatory funnel, the student observes only one liquid phase with no interface. Explain.

Answers

Answer: The student observed only one liquid phase because The student removed the aqueous layer instead of the organic layer and then added organic solvent to more organic layer. Diethyl ether is less dense than water.

Explanation:

In organic chemistry, which is the chemistry of carbon atoms, liquid-liquid extraction techniques are used to separate solutes from its crude reaction mixtures. An example of liquid- liquid extraction technique used is the Separatory funnel.

The Separatory funnel extraction technique allows the separation of solutes based on their solubilities in two immiscible liquids. This appears as two phases or layers with the organic solvent on top while the aqueous solution is below the funnel. This is because the organic solvents are less dense than the aqueous solution.

From the question, the student had a dissolved organic compound in an aqueous solution and was given an organic solvent, diethyl ether for its extraction. When the first 10ml of ether was added, the dissolved organic compound mixed with it and remained in the top layer of the mixture. The student removes the lower layer after the first extraction and adds the second 10mL portion of ether to the upper layer remaining in the separatory funnel. After shaking the funnel, the student observes only one liquid phase with no interface because more organic solvent was added to the organic layer that remained after the aqueous layer was removed.

What is the volume in mL of 0.36 mol of carbon dioxide at STP?

Answers

Answer:

Zero

Explanation:

Helppp plssss pls help it’s Science I will give Brainlyist no cap I will just plssss help

Answers

Answer:

I cant see it that well but id be happy to help if u post a clearer picture!

Explanation:

How many nitrogen
atoms (N) are in 2N2

Answers

Answer: it's 4nitrogen

denotes two nitrogen atoms. 2. N 2 denotes one molecule of nitrogen gas.

Explanation:

4 nitrogen atomsssss

Fresh milk has a pH of 6.
How do you think the pH
would change as it became
sour? Explain your answer.

Answers

Yes it would because the ph has changed when the particles in the milk started to turn sour

Help pls!!!!!!!!!!!!!!!!!!!!!!!

Answers

Answer:

D a compound

Explanation:

D.
it is a compound and D is the right answer

Which equation illustrates conservation of mass?
O 1 H2 + 1 O2 + 2 H2O
O 1 H2 + 1 2 + 1 H2O
O 1 H2 + 1 Cl2 +1HCI
O 1 H2 + 1 Cl2 + 2HCI

Answers

Answer:

1H₂  +  1Cl₂  →   2HCl

Explanation:

The reaction that illustrates the law of conservation of mass is shown below:  

         1H₂  +  1Cl₂  →   2HCl

According to the law of conservation of mass "in a chemical reaction, matter is neither created nor destroy but atoms are rearranged".

Therefore, we are expected to the end a reaction with the amount of substance we start with.

   

 Element                                H                                    Cl

Reactants                               2                                      2

Products                                 2                                      2

We see that number of atoms on both sides are the same.

Calculate the number of moles 2.5 g of calcium hydroxide.

Answers

Answer:

0.044 mol CaOH

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Chemistry

Atomic Structure

Reading a Periodic TableWriting Compounds

Stoichiometry

Using Dimensional AnalysisExplanation:

Step 1: Define

2.5 g CaOH

Step 2: Identify Conversions

[PT] Molar Mass of Ca - 40.08 g/mol

[PT] Molar Mass of O - 16.00 g/mol

[PT] Molar Mass of H - 1.01 g/mol

Molar Mass of CaOH - 40.08 + 16.00 + 1.01 = 57.09 g/mol

Step 3: Convert

[DA] Set up:                                                                                                     [tex]\displaystyle 2.5 \ g \ CaOH(\frac{1 \ mol \ CaOH}{57.09 \ g \ CaOH})[/tex][DA] Multiply/Divide [Cancel out units]:                                                         [tex]\displaystyle 0.043791 \ mol \ CaOH[/tex]

Step 4: Check

Follow sig fig rules and round. We are given 2 sig figs.

0.043791 mol CaOH ≈ 0.044 mol CaOH

Compare the two shampoo

Answers

Answer:

Explanation:

I think you forgot to attach an image here!

a certain kind of pea plant has an allele for tall and an allele for short but its overall phenotype is tall.

Answers

Answer:

Tt

Explanation:

T= Dominant tall

t= non-dominant short.

Dominant always shows over non-dominant.

The work of which scientist was most essential to the use of radioactive
isotopes in medicine?
A. Antoine-Laurent Lavoisier
B. Robert Boyle
C. Marie Curie
D. John Dalton

Answers

Answer:

A

Antoine-Laurent Lavoisier

:D

The scientist was most essential to the use of radioactive isotopes in medicine is " John Lawrence's".

What is radioactive isotopes?

The radioactive isotopes of such an element were called radioisotopes. Atoms that have too much energy in their nucleus or even an unstable neutron-proton pair.

It marked the beginning of John Lawrence's lengthy career of service and the first time a radioactive isotope had already been employed in the management of a human illness. His laboratory is regarded as the origin of nuclear medicine, for which he is regarded as its father.

The scientist most essential to the use of radioactive isotopes in medicine is " John Lawrence's".

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A solid sample of Zinc Hydroxide is added to 0.350 L of 0.500 M aqueous Hydrogen Bromide. The solution that remains is still acidic. It is then titrated with 0.500 M NaOH solution, and it takes 88.5 mL of the NaOH solution to reach the equivalence point. What mass of Zinc Hydroxide was added to the Hydrogen Bromide solution?

Answers

Answer:

6.499 g

Explanation:

One part of the aqueous HBr reacted with Zinc Hydroxide following the reaction:

Zn(OH)₂ + 2HBr → ZnBr₂ + 2H₂O

And the remaining HBr reacted with NaOH:

NaOH + HBr → NaBr + H₂O

First we calculate how many HBr moles remained after reacting with Zn(OH)₂. That number equals the number of NaOH moles used in the titration:

0.500 M * 88.5 mL = 44.25 mmol NaOH = mmol HBr

Now we calculate how many moles of HBr reacted with Zn(OH)₂:

Originally there were (350 mL * 0.500 M) 175 mmol HBr175 mmol - 44.25 mmol = 130.75 mmol HBr

Then we convert those 130.75 mmoles of HBr to the Zn(OH)₂ moles they reacted with:

130.75 mmol HBr * [tex]\frac{1mmolZn(OH)_{2}}{2mmolHBr}[/tex] = 65.375 mmol Zn(OH)₂.

Finally we convert Zn(OH)₂ moles to grams:

65.375 mmol Zn(OH)₂ * 99.424 mg/mmol = 6499.8 mg Zn(OH)₂6499.8 mg Zn(OH)₂ / 1000 = 6.499 g

222 g of MTBE (CO(CH3)4) are added to gasoline, resulting in a total volume of 2 L of reformulated gas (RFG). Assume that the density of RFG is 0.70 g/mL, and the density of MTBE is 0.74 g/mL. For a-d, determine the concentration of MTBE in the RFG in the following units?
a. mg/L
b. moles/L
c. % (w/w)
d. % (v/v)
e. What is the % (w/w) oxygen in the RFG due to MTBE?

Answers

Answer:

Explanation:

From the information given:

(a)

[tex]Concentration \ in \ mg/L = \dfrac{Mass \ of \ MTBE \ in \ mg}{Total \ volume (in \ L)}[/tex]

[tex]Concentration \ in \ mg/L = \dfrac{222 \times 10^3 \ mg}{22}[/tex]

[tex]Concentration \ in \ mg/L = 111 \times 10^3 \ mg/L[/tex]

(b)

[tex]number \ of \ mole s= \dfrac{mass}{molar \ mass } \\ \\ number \ of \ mole s=\dfrac{222 \ g}{88.15 \ g/mol} \\ \\ \mathbf{= 2.518 mol}[/tex]

(c)

[tex]w/w \ percentage = \dfrac{mass \ of \ MTBE }{mass \ of \ solution (RFG)}\times 100\%[/tex]

[tex]where; \\ \\ mass \ of \ (RFG) = 2L \times 0.70 g/mL \\ \\ mass \ of \ (RFG) = 2000 ml \times 0.70 g/mL \\ \\ mass \ of \ (RFG) = 1400 g[/tex]

[tex]w/w \ percentage = \dfrac{222 \ g}{1400 \ g}\times 100\% = \mathbf{15.8\%}[/tex]

(d)

[tex]Volume of MTBE =\dfrac{mass \ of \ MTBE}{density \ of \ MTBE}[/tex]

[tex]Volume \ of \ MTBE = 300 \ mL\\[/tex]

[tex]v/v\% = \dfrac{volume \ of \ MTBE}{volume \ of \ RFG} \\ \\ v/v\% =\dfrac{300 \ mL}{2000 \ mL}\times 100\% \\ \\ \mathbf{v/v\% = 15.00\%}[/tex]

(e)

[tex]From \the \ given \ information; \\ \\ 2.5184 \ moles\ of \ MTBE contain \ 2.5184 \ mole of oxygen[/tex]

[tex]mass of oxygen MTBE = 2.5284 mol \times 16\ g/mol \\ \\ mass of oxygen MTBE = 40.3 9 \ g\\ \\ mass\ of \ RFG = 1400 g[/tex]

[tex]\% w/w = \dfrac{mass \ of \ oxygen}{mass \ of RFG }=\dfrac{40.22 \ g}{1400 \ g} \times 100\%[/tex]

[tex]\% w/w == 2.88\%[/tex]

Assume That The Density Of RFG Is 0.7 G/mL And The Density Of MTBE Is ... are added to gasoline, resulting in a total volume of 2 L of reformulated gas (RFG). ... Assume that the density of RFG is 0.7 g/mL and the density of MTBE is 0.74 g/mL. Determine the concentration of MTBE in the RFG in the following units (a-d)

David went shopping with his mom for house renovations supplies. They were looking for materials that would conduct electricity. Which material should they buy?

Copper
Glass
Plastic
Wood

Answers

Answer:

this will copper this is correct answer

Question asked: David went shopping with his mom for house renovations supplies. They were looking for materials that would conduct electricity. Which material should they buy?

Answer: Copper

Explanation: Copper would be the right answer because that's the only material that would conduct electricity.

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I hope this helps!

Which example is a long-term environmental change?
O La Niña
O EI Nino
O climate change
O small asteroid impact




C

Answers

An example would be Climate change
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