Answer:
the flow rate of the gas stream leaving the condenser is 71.9 moles/min
Explanation:
Given the data in the question and the figure below;
N2 BALANCE
(100% - 18%) × ( mole rate in ) = ( 100% - 5%) × ( mole rate out)
0.82 × ( mole rate in ) = 0.95 × ( mole rate out)
mole rate in = 0.95 × ( mole rate out) / 0.82
mole rate in = 1.1585365853 × ( mole rate out)
now;
HEXANE BALANCE
0.18 × ( mole rate in ) = 0.0500 × ( mole rate out) + condensate --- equ 1
but condensate = 1.5 L/min × ( density of hexane ) × 1/molar mass of hexane
we know that;
density of hexane is 0.6548 g/mL
and molar mass of hexane is 86.18 g/mol
so,
condensate = 1.5 L/min × ( 0.6548 g/mL × 1000 mL/L ) × ( 1/86.18 g/mol)
condensate = 11.3970758876
now lets substitute into equation 1
0.18 × ( mole rate in ) = 0.0500 × ( mole rate out) + condensate
⇒ 0.18 × ( 1.1585365853 × ( mole rate out) ) = 0.0500 × ( mole rate out) + 11.3970758876
⇒ 0.208536585354(mole rate out) = 0.0500( mole rate out) + 11.3970758876
⇒ 0.208536585354(mole rate out) - 0.0500( mole rate out) = 11.3970758876
⇒ 0.158536585354(mole rate out) = 11.3970758876
mole rate out = 11.3970758876 / 0.158536585354
mole rate out = 71.889247 ≈ 71.9 moles/min
Therefore, the flow rate of the gas stream leaving the condenser is 71.9 moles/min
Suppose a disease wipes out most of the fox population in
the food web shown.
Mountain
lion
Deer
Hawk
Fox
Rabbit
Owl
Snake
Green
plant
Mouse
Which two populations are most likely to increase as a result?
A. Mountain lion
B. Mouse
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O C. Rabbit
D. Green plant
If the fox population in the given food web is significantly reduced due to a disease, two populations that are most likely to increase as a result are the populations of A. Mountain lion and C. Rabbit.
The decrease in the fox population can disrupt the balance of the food web. Since foxes are natural predators of rabbits, the reduced presence of foxes would lead to a decrease in predation pressure on rabbits. This would allow the rabbit population to increase because their natural predators are now less abundant. Also, with a decline in the fox population, there would be fewer predators to control the population of smaller animals like mice. Hence, the mouse population could also increase due to reduced predation pressure. The mountain lion population, being a predator higher up in the food chain, may indirectly benefit from the increase in rabbit and mouse populations. The increase in prey availability could potentially lead to an increase in the mountain lion population as they have more food resources available. The green plant population (D) is unlikely to directly benefit from the decrease in the fox population since they are not directly influenced by predation from foxes. Their population dynamics are primarily driven by other factors such as availability of sunlight, water, and nutrient levels. The correct answer is A. Mountain lion and C. Rabbit
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How many grams of Kr are in 2.00 mol of Kr? (4)
Answer:
1 mole is equal to 1 moles Krypton, or 83.798 grams.
Explanation:
Calculate the molality of an ethylene glycol (C2H6O2) soltuion, that has a molarity of 2.07 M. The density of the solution is 1.02 g/mL. Only enter the numerical value with 3 significant figures in the answer box below. Do NOT type in the unit (m).
Answer:
2.03
Explanation:
Let's assume we have 1 L of the solution:
There would be 2.07 ethylene glycol moles.The solution would weigh (1000 mL * 1.02 g/mL) = 1020 g.With that information we can calculate the molality:
molality = moles of solute / kg of solventmolality = 2.07 moles / (1020 ÷ 1000) = 2.03 mKeep in mind that this is only an estimate, as we used the kg of the solution and not of the solvent.
The molality of an ethylene glycol solution is 2.03 kg.
What is molality?The moles of solute divided by the mass of solvent in kilograms is known as the molality of a solution.
Calculation of molality:
Given that, molarity is 2.07 M
Density is 1.02 g/ml
Step 1: To convert the litre into grams, multiply the quantity by 1000
The weight of the solution is [tex]\bold{1.02 \;g/ml\; \times 1000 = 1020 g}[/tex]
Now, molality = moles of solute is divided by mass of solvent in kilograms.
[tex]\bold{Molality = 2.07 \times \dfrac{1020}{1000} = 2.03\; kg}[/tex]
Thus, the molality of the solution is 2.03 kg
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molality = moles of solute / kg of solvent
molality = 2.07 moles / (1020 ÷ 1000) = 2.03 m
Keep in mind that this is only an estimate, as we used the kg of the solution and not of the solvent.
If a substance has a density of 2.545g / mL how many grams would the substance weigh if the sample has a volume of 122.1 mL?
Answer: 310.7 grams
Explanation:
Multiply the two values so the units of mL cancel and you get grams
2.545*122.1 = 310.7 grams
The graph below shows a reaction to which a catalyst has been added. How would the graph be different if it showed the same reaction without a catalyst?
A. The width of region 2 would be smaller.
B. The difference in the heights of regions 1 and 3 would be larger.
C. The height of region 2 would be larger
D. The distance between regions 1 and 3 would be smaller
Answer:
a. the width of region 2 would be smaller
If the same reaction was shown without a catalyst, the height of region 2 would be larger, so the correct option is (C).
What is catalyst?A catalyst is a substance that speeds up the rate of a chemical reaction without being consumed in the process. It works by providing an alternate pathway for the reaction with a lower activation energy, making it easier for the reactants to transform into products.
Catalysts can be solids, liquids, or gases, and they can be homogeneous or heterogeneous, depending on whether they are in the same phase as the reactants or in a different phase.
Catalysts are widely used in many industrial processes, such as the production of fertilizers, plastics, and fuels, to increase the efficiency and reduce the cost of the reaction. They can also be found in biological systems, where they play a crucial role in metabolic processes, such as the breakdown of food in the digestive system or the conversion of light into chemical energy in photosynthesis.
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How many atoms are in 4 moles of oxygen?
Using Avogrado's constant (6.022e23):
4(6.022e23) = 2.41e24
12) How many moles of CO can be produced from
10.0 mol of CO2
Answer:
5
Explanation:
There are 2 moles of CO in each CO2. 10 ÷ 2 = 5
There diagrams imply that’s
A TISSUEs are always rectangular
B tissues are made up of cells
C Tissues all look the same
D tissues have the same Function
Answer:
b
Explanation:
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A sample of iron, which has a specific heat capacity of 0.449 Jg^-1℃^-1, is put into a calorimeter (see sketch at right) that contains 100.0 g of water. The iron sample starts off at container 93.3 °C and the temperature of the water starts off at 22.0 °C. When the temperature of the water stops changing it's 25.7 °C. The pressure remains constant at 1 atm.
Required:
Calculate the mass of the iron sample. Be sure your answer is rounded to 2 significant digits.
Answer:
[tex]m_{iron}=32.1g[/tex]
Explanation:
Hello!
In this case, since the interaction between hot iron and cold water allows the heat transfer from iron to water and therefore we can write up the following energetic equation:
[tex]Q_{iron}+Q_{water}=0[/tex]
Whereas the heat terms can be written in terms of mass, specific heat and temperature change:
[tex]m_{iron}C_{iron}(T_f-T_{iron}) + m_{water}C_{water}(T_f-T_{water}) = 0[/tex]
So we solve for the mass of iron as follows:
[tex]m_{iron} = \frac{m_{water}C_{water}(T_f-T_{water})}{C_{iron}(T_f-T_{iron}) }[/tex]
Now, we plug in the given data to obtain:
[tex]m_{iron} = \frac{-100g*0.449\frac{J}{g\°C} (25.7\°C-22.0\°C)}{0.449\frac{J}{g\°C} (25.7\°C-93.3\°C) }[/tex]
[tex]m_{iron}=32.1g[/tex]
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What makes an atom a good conductor?
what is the difference between fluorine and oxygen?
Answer:
Continuing on across the periodic table we see that fluorine is the next element after oxygen. ... Rather than forming seven bonds fluorine only forms a single bond for basically the same reasons that oxygen only forms two bonds. Hydrogen fluoride, HF, has one bond, but four centers of electron density around the fluorine.
WORTH 18 POINTS! MY LIFE DEPENDS ON THIS ANSWER!!!
Which compound listed below is most likely to have to following properties?
-solid at room temperature
- high melting points
-solble in water
-conductive when dissolved
1.sodium chloride
2.carbon monoxide
3.nitrogen trifluoride
4.none of these compounds could have all of the properties listed
Answer:
1.sodium chloride
Explanation:
because the others dont have all the listed properties
A 8.15 g sample of hydrogen peroxide (H2O2) decomposes to form water and oxygen. The temperature and pressures conditions in the lab were 21.2oC and 761.4 torr, respectively. The oxygen gas is collected over a sample of water at 21.2oC; the vapor pressure of water at that temperature is 18.9 torr. When the water level inside and outside of the tube is equal the volume of gas is recorded as 176.23 mL. a) Write and balance the equation for the decomposition reaction
Answer: [tex]H_2O_2\rightarrow H_2+O_2[/tex]
Explanation:
Decomposition is a type of chemical reaction in which one reactant gives two or more than two products.
According to law of conservation of mass, mass can neither be created nor be destroyed. Thus the number of atoms of each element must be same on reactant and product side. Thus chemical equations are balanced.
The balanced equation for the decomposition reaction of hydrogen peroxide is:
[tex]H_2O_2\rightarrow H_2+O_2[/tex]
Decomposition is a type of chemical reaction in which a chemical breaks into two or more molecules or atoms. One reactant breaks into two products which can be shown as:
XY----->X + Y
The decomposition reaction of hydrogen peroxide can be written as:
[tex]H_{2}O_{2} = H_{2} + O_{2}[/tex]
According to the mass conserving law the mass can neither be added nor deleted they can just get transferred. For a reaction to be stable the number of atoms on both sides of the reaction should be balanced.Therefore, the balanced chemical reaction of decomposition of hydrogen peroxide will be:
[tex]H_{2}O_{2} = H_{2} + O_{2}[/tex]
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Which type of lens would you use in a microscope or telescope and why?
Answer:
Microscopes and telescopes often use two lenses to make an image large enough to see. A compound microscope uses two lenses to achieve high magnification. Both lenses are convex, or converging. Light from the object first passes through the objective lens.
Explanation:
A compound microscope uses two lenses to achieve high magnification
how is the massive star born
An extraction procedure specifies that an aqueous solution containing dissolved organic material be extracted twice with 10 mL portions of diethyl ether. A student removes the lower layer after the first extraction and adds the second 10 mL portion of ether to the remaining upper layer. After shaking the separatory funnel, the student observes only one liquid phase with no interface. Explain.
Answer: The student observed only one liquid phase because The student removed the aqueous layer instead of the organic layer and then added organic solvent to more organic layer. Diethyl ether is less dense than water.
Explanation:
In organic chemistry, which is the chemistry of carbon atoms, liquid-liquid extraction techniques are used to separate solutes from its crude reaction mixtures. An example of liquid- liquid extraction technique used is the Separatory funnel.
The Separatory funnel extraction technique allows the separation of solutes based on their solubilities in two immiscible liquids. This appears as two phases or layers with the organic solvent on top while the aqueous solution is below the funnel. This is because the organic solvents are less dense than the aqueous solution.
From the question, the student had a dissolved organic compound in an aqueous solution and was given an organic solvent, diethyl ether for its extraction. When the first 10ml of ether was added, the dissolved organic compound mixed with it and remained in the top layer of the mixture. The student removes the lower layer after the first extraction and adds the second 10mL portion of ether to the upper layer remaining in the separatory funnel. After shaking the funnel, the student observes only one liquid phase with no interface because more organic solvent was added to the organic layer that remained after the aqueous layer was removed.
What is the volume in mL of 0.36 mol of carbon dioxide at STP?
Answer:
Zero
Explanation:
Helppp plssss pls help it’s Science I will give Brainlyist no cap I will just plssss help
Answer:
I cant see it that well but id be happy to help if u post a clearer picture!
Explanation:
How many nitrogen
atoms (N) are in 2N2
Answer: it's 4nitrogen
denotes two nitrogen atoms. 2. N 2 denotes one molecule of nitrogen gas.
Explanation:
Fresh milk has a pH of 6.
How do you think the pH
would change as it became
sour? Explain your answer.
Help pls!!!!!!!!!!!!!!!!!!!!!!!
Answer:
D a compound
Explanation:
Which equation illustrates conservation of mass?
O 1 H2 + 1 O2 + 2 H2O
O 1 H2 + 1 2 + 1 H2O
O 1 H2 + 1 Cl2 +1HCI
O 1 H2 + 1 Cl2 + 2HCI
Answer:
1H₂ + 1Cl₂ → 2HCl
Explanation:
The reaction that illustrates the law of conservation of mass is shown below:
1H₂ + 1Cl₂ → 2HCl
According to the law of conservation of mass "in a chemical reaction, matter is neither created nor destroy but atoms are rearranged".
Therefore, we are expected to the end a reaction with the amount of substance we start with.
Element H Cl
Reactants 2 2
Products 2 2
We see that number of atoms on both sides are the same.
Calculate the number of moles 2.5 g of calcium hydroxide.
0.044 mol CaOH
General Formulas and Concepts:Math
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightChemistry
Atomic Structure
Reading a Periodic TableWriting CompoundsStoichiometry
Using Dimensional AnalysisExplanation:Step 1: Define
2.5 g CaOH
Step 2: Identify Conversions
[PT] Molar Mass of Ca - 40.08 g/mol
[PT] Molar Mass of O - 16.00 g/mol
[PT] Molar Mass of H - 1.01 g/mol
Molar Mass of CaOH - 40.08 + 16.00 + 1.01 = 57.09 g/mol
Step 3: Convert
[DA] Set up: [tex]\displaystyle 2.5 \ g \ CaOH(\frac{1 \ mol \ CaOH}{57.09 \ g \ CaOH})[/tex][DA] Multiply/Divide [Cancel out units]: [tex]\displaystyle 0.043791 \ mol \ CaOH[/tex]Step 4: Check
Follow sig fig rules and round. We are given 2 sig figs.
0.043791 mol CaOH ≈ 0.044 mol CaOH
Compare the two shampoo
Answer:
Explanation:
I think you forgot to attach an image here!
a certain kind of pea plant has an allele for tall and an allele for short but its overall phenotype is tall.
Answer:
Tt
Explanation:
T= Dominant tall
t= non-dominant short.
Dominant always shows over non-dominant.
The work of which scientist was most essential to the use of radioactive
isotopes in medicine?
A. Antoine-Laurent Lavoisier
B. Robert Boyle
C. Marie Curie
D. John Dalton
Answer:
A
Antoine-Laurent Lavoisier
:D
The scientist was most essential to the use of radioactive isotopes in medicine is " John Lawrence's".
What is radioactive isotopes?The radioactive isotopes of such an element were called radioisotopes. Atoms that have too much energy in their nucleus or even an unstable neutron-proton pair.
It marked the beginning of John Lawrence's lengthy career of service and the first time a radioactive isotope had already been employed in the management of a human illness. His laboratory is regarded as the origin of nuclear medicine, for which he is regarded as its father.
The scientist most essential to the use of radioactive isotopes in medicine is " John Lawrence's".
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A solid sample of Zinc Hydroxide is added to 0.350 L of 0.500 M aqueous Hydrogen Bromide. The solution that remains is still acidic. It is then titrated with 0.500 M NaOH solution, and it takes 88.5 mL of the NaOH solution to reach the equivalence point. What mass of Zinc Hydroxide was added to the Hydrogen Bromide solution?
Answer:
6.499 g
Explanation:
One part of the aqueous HBr reacted with Zinc Hydroxide following the reaction:
Zn(OH)₂ + 2HBr → ZnBr₂ + 2H₂OAnd the remaining HBr reacted with NaOH:
NaOH + HBr → NaBr + H₂OFirst we calculate how many HBr moles remained after reacting with Zn(OH)₂. That number equals the number of NaOH moles used in the titration:
0.500 M * 88.5 mL = 44.25 mmol NaOH = mmol HBrNow we calculate how many moles of HBr reacted with Zn(OH)₂:
Originally there were (350 mL * 0.500 M) 175 mmol HBr175 mmol - 44.25 mmol = 130.75 mmol HBrThen we convert those 130.75 mmoles of HBr to the Zn(OH)₂ moles they reacted with:
130.75 mmol HBr * [tex]\frac{1mmolZn(OH)_{2}}{2mmolHBr}[/tex] = 65.375 mmol Zn(OH)₂.Finally we convert Zn(OH)₂ moles to grams:
65.375 mmol Zn(OH)₂ * 99.424 mg/mmol = 6499.8 mg Zn(OH)₂6499.8 mg Zn(OH)₂ / 1000 = 6.499 g222 g of MTBE (CO(CH3)4) are added to gasoline, resulting in a total volume of 2 L of reformulated gas (RFG). Assume that the density of RFG is 0.70 g/mL, and the density of MTBE is 0.74 g/mL. For a-d, determine the concentration of MTBE in the RFG in the following units?
a. mg/L
b. moles/L
c. % (w/w)
d. % (v/v)
e. What is the % (w/w) oxygen in the RFG due to MTBE?
Answer:
Explanation:
From the information given:
(a)
[tex]Concentration \ in \ mg/L = \dfrac{Mass \ of \ MTBE \ in \ mg}{Total \ volume (in \ L)}[/tex]
[tex]Concentration \ in \ mg/L = \dfrac{222 \times 10^3 \ mg}{22}[/tex]
[tex]Concentration \ in \ mg/L = 111 \times 10^3 \ mg/L[/tex]
(b)
[tex]number \ of \ mole s= \dfrac{mass}{molar \ mass } \\ \\ number \ of \ mole s=\dfrac{222 \ g}{88.15 \ g/mol} \\ \\ \mathbf{= 2.518 mol}[/tex]
(c)
[tex]w/w \ percentage = \dfrac{mass \ of \ MTBE }{mass \ of \ solution (RFG)}\times 100\%[/tex]
[tex]where; \\ \\ mass \ of \ (RFG) = 2L \times 0.70 g/mL \\ \\ mass \ of \ (RFG) = 2000 ml \times 0.70 g/mL \\ \\ mass \ of \ (RFG) = 1400 g[/tex]
∴
[tex]w/w \ percentage = \dfrac{222 \ g}{1400 \ g}\times 100\% = \mathbf{15.8\%}[/tex]
(d)
[tex]Volume of MTBE =\dfrac{mass \ of \ MTBE}{density \ of \ MTBE}[/tex]
[tex]Volume \ of \ MTBE = 300 \ mL\\[/tex]
∴
[tex]v/v\% = \dfrac{volume \ of \ MTBE}{volume \ of \ RFG} \\ \\ v/v\% =\dfrac{300 \ mL}{2000 \ mL}\times 100\% \\ \\ \mathbf{v/v\% = 15.00\%}[/tex]
(e)
[tex]From \the \ given \ information; \\ \\ 2.5184 \ moles\ of \ MTBE contain \ 2.5184 \ mole of oxygen[/tex]
∴
[tex]mass of oxygen MTBE = 2.5284 mol \times 16\ g/mol \\ \\ mass of oxygen MTBE = 40.3 9 \ g\\ \\ mass\ of \ RFG = 1400 g[/tex]
∴
[tex]\% w/w = \dfrac{mass \ of \ oxygen}{mass \ of RFG }=\dfrac{40.22 \ g}{1400 \ g} \times 100\%[/tex]
[tex]\% w/w == 2.88\%[/tex]
Assume That The Density Of RFG Is 0.7 G/mL And The Density Of MTBE Is ... are added to gasoline, resulting in a total volume of 2 L of reformulated gas (RFG). ... Assume that the density of RFG is 0.7 g/mL and the density of MTBE is 0.74 g/mL. Determine the concentration of MTBE in the RFG in the following units (a-d)
David went shopping with his mom for house renovations supplies. They were looking for materials that would conduct electricity. Which material should they buy?
Copper
Glass
Plastic
Wood
Answer:
this will copper this is correct answer
Question asked: David went shopping with his mom for house renovations supplies. They were looking for materials that would conduct electricity. Which material should they buy?
Answer: Copper
Explanation: Copper would be the right answer because that's the only material that would conduct electricity.
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Which example is a long-term environmental change?
O La Niña
O EI Nino
O climate change
O small asteroid impact
C