Given that,
Mass of a girl, m = 50 kg
Mass of the boat, m' = 300 kg
Speed of girl, v = 3 m/s
To find,
The velocity with which the boat begin to move backwards.
Solution,
Let the velocity be v'. Using the conservation of momentum to find it. It is given by :
[tex]mv=m'v'\\\\v'=\dfrac{mv}{m'}\\\\v'=\dfrac{50\times 3}{300}\\\\v'=0.5\ m/s[/tex]
So, the velocity moves backward with a speed of 0.5 m/s.
A stretched string is 1.95 m long and has a mass of 19.1 g. When the string oscillates at 440 Hz, which is the frequency of the standard A pitch, transverse waves with a wavelength of 16.7 cm travel along the string. Calculate the tension T in the string.
T= ________ N
Answer:
The tension in the string is 52.89 N.
Explanation:
Given;
mass of the string, m = 19.1 g = 0.0191 kg
length of the string, L = 1.95 m
⇒mass per unit length, μ = 0.0191 / 1.95 = 0.009795 kg/m
Also Given;
frequency of the string, F = 440 Hz
wavelength of the sound wave, λ = 16.7 cm = 0.167 m
⇒the speed of the wave, v = Fλ = 440 x 0.167 = 73.48 m/s
The tension T in the string is calculated as;
[tex]v = \sqrt{\frac{T}{\mu} } \\\\v^2 = \frac{T}{\mu}\\\\T = v^2 \mu\\\\T = (73.48)^2 (0.009795)\\\\T = 52.89 \ N[/tex]
Therefore, the tension in the string is 52.89 N.
As fuel is burned in an electrical generator, the chemical energy of the fuel is converted into thermal energy that is used to boil water. after the steam from the boiling water moves through the pipe, what sequence of energy transformation best describes what happens?
Answer choices:
A:mechanical ----> electrical ---> light
B: light ----> electrical----> mechanical
C: Electrical---> Mechanical----> light
D: Mechanical----> light ----> electrical
Answer: A
Explanation:
m
An ostrich accelerates from rest until reaching a speed of 6.0 A graph of the ostrich's velocity over time
is shown below.
S
Velocity
()
6+
3+
Time (s)
3 6 9 12 15 18
What is the ostrich's average acceleration from 9.0 to 18 seconds?
O
Answer:
0 m/s2
Explanation:
khan
when a horse pulls a cart, the horse move forward due to?
Answer:
The horse moves due to kinetic energy and is walking balanced because of the gravitational energy
Explanation:
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An object undergoing simple harmonic motion completes one cycle of motion in 1.7 seconds. Determine the angular frequency (rad/s) of the motion.
Answer:
3.69 rad/s
Explanation:
From the question given above, the following data were obtained:
Period (T) = 1.7 s
Angular frequency (ω) =?
Thus, we can obtain the angular frequency (ω) by applying the following formula:
ω = 2π/T
Period (T) = 1.7 s
Pi (π) = 3.14
Angular frequency (ω) =?
ω = 2π/T
ω = 2 × 3.14 / 1.7
ω = 6.28 / 1.7
ω = 3.69 rad/s
Thus, the angular frequency of the motion is 3.69 rad/s
A car breaks down 3.5 meters away from the side of the road. 2.060 Newtons of
force is used to push the car off the road. How much work has been done on the
car?
Answer:
7.21 JExplanation:
The work done by an object can be found by using the formula
workdone = force × distance
From the question we have
workdone = 2.060 × 3.5
We have the final answer as
7.21 JHope this helps you
A 12 V battery applies a potential difference to three resistors in series. If the potential at point P is 0.0 V, the potential at point B is:
This question is incomplete, the complete question is on the image uploaded along this answer.
Answer:
the potential at point B is 5 V, Option d) is the correct answer
Explanation:
Given that;
from the image;
R = 3 + 4 + 5 = 12 Ω
so I = 12/12 = 1 A
Q = 0 + 12 = 12 V
now
VA - VQ = - I × 3 = -3 V
VA = VQ - 3 = 12 - 3 = 9 V
VB - VA = - I × 4Ω = - 4 V
⇒VB = VA - 4 = 9 V - 4 V = 5 V
Therefore the potential at point B is 5 V
Option d) is the correct answer
At 3.00 m from a source that is emitting sound uniformly in all directions, the sound level (b) is 60.0 dB.
How many meters from the source would the sound level be one-fourth the sound level at 3.00 m?
Given that,
At 3.00 m from a source that is emitting sound uniformly in all directions, the sound level is 60.0 dB.
To find,
The distance from the source would the sound level be one-fourth the sound level at 3.00 m.
Solution,
The intensity from a source is inversely proportional to the distance.
Let I₁ = 60 dB, r₁ = 3 m, I₂ = 60/4 = 15 dB, r₂ =?
Using relation :
[tex]\dfrac{I_1}{I_2}=\dfrac{r_2^2}{r_1^2}\\\\r_2^2=\dfrac{I_1r_1^2}{I_2}\\\\r_2^2=\dfrac{60\times (3)^2}{15}\\\\r_2=6\ m[/tex]
So, at a distance of 6 m the sound level will be one fourth of the sound level at 3 m.
A bolt of lightning hits a tree 170m from your house. How long before you hear it?
the weakest type of friction that occurs between solid surfaces is _____ friction
Answer:
Static, sliding, and rolling friction occur between solid surfaces. Static friction is strongest, followed by sliding friction, and then rolling friction, which is weakest. Fluid friction occurs in fluids, which are liquids or gases.
Explanation:
In which of the following situations is the normal force greater than the weight of the object?
Your answer:
a truck towing a car so that only the back tires are running along the road
pushing down on a lawnmower in front of you to mow the lawn
a box resting on a ramp
a picture frame hung up by two wires
Pretty sure answer is B
due to the fact your exerting extra force down on the lawn mower to move it
An electron has a mass of 9.109 x 10^-31 kg. What is its weight in Newtons on Earth
Answer:
[tex]W=8.93\cdot 10^{-30}\ N[/tex][tex]\mathbf{W=8.93\cdot 10^{-30}\ N}[/tex]
Explanation:
Mass and Weight
The mass of an object is a measure of the object's amount of matter it contains. It's expressed in Kilograms or similar units.
The weight of an object is a measure of the force exerted on the object by gravity. It's often expressed in Newtons or similar units.
The formula to calculate the weight of an object with known mass m is:
W = m.g
Where g is the acceleration of gravity in the place it's located. We are given the mass of an electron:
[tex]m=9.109\cdot 10^{-31}\ Kg[/tex]
On Earth, the acceleration of gravity is:
[tex]g=9.8\ m/s^2[/tex]
Thus, the weight is:
[tex]W =9.109\cdot 10^{-31}\ Kg*9.8\ m/s^2[/tex]
[tex]\mathbf{W=8.93\cdot 10^{-30}\ N}[/tex]
A particle is moving with (SHM) of period 8.0s and amplitude5.0m
Find
The speed of the particle when it is 3.0m from the centre of it's motion,
The maximum speed,
The maximum acceleration
Answer:
[tex]velocity(x)=15\,\frac{\pi}{4}\,cos(\frac{\pi}{4}x)[/tex]
Max speed = [tex]\frac{15\, \pi}{4} \,\, \frac{m}{s}[/tex]
Max acceleration = [tex]\frac{15\,\pi^2}{16} \,\,\frac{m}{s^2}[/tex]
Explanation:
Given the description of period and amplitude, the SHM could be described by:
[tex]f(x)=5\,sin(\frac{\pi}{4}x)[/tex]
and its angular velocity can be calculated doing the derivative:
[tex]f(x)=5\, \,sin(\frac{\pi}{4}x)\\f'(x)=5\,\frac{\pi}{4}\,cos(\frac{\pi}{4}x)[/tex]
And therefore, the tangential velocity is calculated by multiplying this expression times the radius of the movement (3 m):
[tex]velocity(x)=15\,\frac{\pi}{4}\,cos(\frac{\pi}{4}x)[/tex] and is given in m/s.
Then the maximum speed is obtained when the cosine function becomes "1", and that gives:
Max speed = [tex]\frac{15\, \pi}{4} \,\, \frac{m}{s}[/tex]
The acceleration is found from the derivative of the velocity expression, and therefore given by:
[tex]acceleraton(x)=-15\,\frac{\pi^2}{16}\,sin(\frac{\pi}{4}x)[/tex]
and the maximum of the function will be obtained when the sine expression becomes "-1", which will render:
Max acceleration = [tex]\frac{15\,\pi^2}{16} \,\,\frac{m}{s^2}[/tex]
PLEASE HELP ME!!!1
Differentiate between the distance and displacement for an object that started at point A and traveled as shown to point B.
Distance: _____ units and Displace: _____ units to the left.
"Distance" here is the total distance traveled along the red path (see attached) from point A to point B. Just count how many how sides of each square in the grid are touched by the path. Then distance = 24 units.
"Displacement" is the net distance covered by moving from point A to point B, or the length of the green path. So displacement = 2 units to the right. Of course, your question seems to ask for the displacement in terms of units to the left, in which you could say -2 units to the left.
Does Light Transmission in oxygen ?
You select a rental package that includes a car with an average consumption of 6.00 litersliters of fuel per 100 kmkm. Considering that in Europe the average fuel cost is 1.063 euros/litereuros/liter, how much (in US dollars) will you spend in fuel on your trip
Answer:
Cost = $ 7.72
Explanation:
Considering the trip of 100 km, the cost spent on the fuel during the trip can be calculated by the following formula:
[tex]Cost = Average Fuel Consumption\ x\ Unit Fuel Cost\ x\ Distance[/tex]
where,
Average Fuel Consumption = 6 liter/100 km
Unit Fuel Cost = (1.063 euros/liter)($ 1.21/1 euro) = $ 1.29/liter
Distance = 100 km
Therefore,
[tex]Cost = (6\ liter/100\ km)(\$\ 1.29/liter)(100\ km)\\[/tex]
Cost = $ 7.72
It takes light 4 hours and 10 minutes to travel from the sun to the Planet Neptune. How far is Neptune from the sun?
a. 1.2 × 10^8 km
b. 4.5 × 10^9 km
c. 12 × 10^8 km
d. 45 × 10^9 km
Answer:b) 4.5×10^9km
Explanation:use s= vt/1000 here, v= speed of light which is 3×10^8m/s
t= time in second
You push a permanent magnet with its north pole away from you toward a loop of conducting wire in front of you. Just before the north pole enters the loop, the current in the loop is: zero clockwise counterclockwise
Answer:
Counter clockwise
Explanation:
A force F=9 N acting on a tooth is not in the direction of the tooth axis and runs at a distance L=1 mm from the axis. Find the torque on the tooth about point C
Answer:
τ = 0.009 Nm
Explanation:
The torque applied on the tooth can be given by the following formula:
[tex]\tau = Fd[/tex]
where,
τ = Torque on the tooth= ?
F = Force acting on tooth = 9 N
d = distance between force and tooth axis = 1 mm = 0.001 m
Therefore, using these values in the equation, we get:
[tex]\tau = (9\ N)(0.001\ m)[/tex]
τ = 0.009 Nm
Which of the following will have the least effect on the motion of a ball? A the mass of the ball B the direction of the force C the strength of the force D the weather conditions
Answer:
letter B..
Explanation:
because pinililit you direction pina force nyang itulak
The ball encounters resistance as it travels through the air. Drag is the term for the air's resistance to the ball. Drag slows down the baseball because it is applied against the direction of the ball's flight. Thus, option B is correct.
What the least effect on the motion of a ball?When two objects rub against one another, a force known as friction is applied. Friction force often works to prevent an object from moving. For instance, friction between a ball and carpet when rolling a ball across it causes the ball to move more slowly.
A baseball in flight is impacted by three forces. The three forces are lift, drag, and weight. Actually, the aerodynamic force exerted on the ball is made up of two parts: lift and drag. Lift acts perpendicular to the motion, and drag acts in the direction opposite to the motion.
Therefore, the direction of the force the least effect on the motion of a ball.
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When a moving object reduces its speed, what happens to the object's acceleration in relation to its velocity?
Answer:
When speed reduces, acceleration decreases
Explanation:
From first equation of motion;
[tex]{ \tt{v = u + at}}[/tex]
When time is constant:
[tex]{ \tt{v = 0 + kt}} \\ { \tt{v = kt}} \\{ \tt{v \: \alpha \: \: a}}[/tex]
When speed is decreasing, velocity and acceleration are in opposite directions.
en the current in one coil changes at a rate of 3.2 A/s, an emf of 5.7 is induced in a second, nearby coil. What is the magnitude of the mutual inductance of the two coils
Given that,
The rate of change of current = 3.2 A/s
Emf induced in the coil = 5.7 V
To find,
The magnitude of the mutual inductance of the two coils.
Solution,
The mutual inductance between the coils is given by the formula as follows :
[tex]\epsilon=M\dfrac{dI}{dt}\\\\M=\dfrac{\epsilon}{\dfrac{dI}{dt}}\\\\M=\dfrac{5.7}{3.2}\\\\=1.78\ H[/tex]
So, the mutual inductance of the two coils is 1.78 H.
The same car slows from 36 m/s to 15 m/s over 3 seconds. What is its average acceleration over this time interval?
The average acceleration of the car over 3 seconds is -7 m/s².
What is Acceleration?
Acceleration is defined as the rate of change of velocity with respect to time. Mathematically -
a = Δv/Δt
Given is a car that car slows from 36 m/s to 15 m/s over 3 seconds.
We can calculate acceleration as follows -
a = Δv/Δt
a = (15 - 36)/(3)
a = -21/3
a = - 7m/s²
Therefore, the average acceleration of the car over 3 seconds is -7 m/s².
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You witness the birth of a littler of puppies.Where were the atoms that make up these puppies come from? How did these atoms form?
The atoms come from the parents of the puppies and were formed by biosynthesis in the bodies of the parent dogs.
What are biological molecules?The term biological molecules are those molecules that are important for life. These are the molecules that are involved in the processes of life that take place in an organism.
Now, from the time of conceptions, the biomolecules in the new organism begins to form. Recall that the DNA is the molecule that is used to store the genetic information of an organism. Now et us recall that the DNA is passed on from the parents to the offspring.
Now, we know that the atoms that compose these puppies come from the parent organisms. The molecules in which the atoms are formed are formed during the natural processes that were taking place in the bodies of the parents of puppies. This occurs by the process of reproduction.
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A futuristic train rushes past you at an incredible, relativistic speed such that it appears to only be 80% as long as you know it to be. At what speed is that train traveling from the point of view of your reference frame
Answer:
v = 0.6c = 1.8 x 10⁸ m/s
Explanation:
From Einstein's theory of relativity, we know that the length of an object contracts while traveling at a speed relative to speed of light. The contraction is according to following equation:
[tex]L = L_{0}\sqrt{1 - \frac{v^2}{c^2}}[/tex]
where,
L = Relative Length
L₀ = Rest Length
According to given:
L = 0.8 L₀
c = speed of light = 3 x 10⁸ m/s
v = relative speed of train = ?
Therefore,
[tex]0.8L_{0} = L_{0}\sqrt{1 - \frac{v^2}{c^2} } \\\\0.8 = \sqrt{1 - \frac{v^2}{c^2} }[/tex]
squaring on both sides:
[tex]0.64 = 1-\frac{v^2}{c^2}\\\\\frac{v^2}{c^2} = 1-0.64 \\v^2= 0.36c^2\\[/tex]
taking square root on both sides:
v = 0.6c = 1.8 x 10⁸ m/s
What is an induction?
Answer:
An induction is the process a new recruit goes through to be introduced to the company and their new role. ... Beyond the initial days, the induction programme continues for many months, so that the new employee can fully integrate into life in the company and settle into their role to become a valuable member of staff.
Explanation:
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1 Which statement
about mas
A Mass and weight are both fo
3 Neither mass nor weight is a
C Only mass is a force.
Only weight is a force.
D Only weigh is a force
Only weigh is a force. force is mass multiplied by acceleration. weight is the mass plus the gravitational force acting on it.
The difference between mass and weight is that mass is a measure of inertia and weight is a measure of force. We use both of these terms interchangeably but this is not quite correct.
Mass can be defined as how much a material an object is made up of. so considering the smallest particles we can say that the number of protons, neutrons, and electrons in an object is a simply the measure of its mass. Mass, can be referred as both a property of an object and a measure of an object's resistance to acceleration. kilograms and grams is the unit of mass.
The weight of an object can be referred as the force acting on it because or due to gravity. That is, the gravitational interactions between bodies and masses, and when they interacts with the Earth, that force will be considered as the weight. its Unit is Newtons.
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Determine the net work a hiker must do on a 3.35-kg backpack to carry it up a
hill of height h = 12.49 m, as shown
Answer:
410.4J
Explanation:
Step one:
given
mass= 3.35kg
weight= 3.35*9.81= 32.86N
h=12.49m
Required
The net work done
Step two:
the work done is given as
WD= force* distance
WD= 32.86*12.49
WD= 410.4J
Two interfering sound waves have frequencies of 223 Hz and 214 Hz. Determine the beat period (in s) of the composite wave. (Hint: first determine the beat frequency.)
Answer:
The beat period of the composite wave is 0.11 s.
Explanation:
Given;
frequency of the first sound wave, F₁ = 223 Hz
frequency of the second sound wave, F₂ = 214 Hz
The beat frequency is given as;
Fb = F₁ - F₂
Fb = 223 Hz - 214 Hz
Fb = 9 Hz
The beat period is given as;
[tex]T_b = \frac{1}{F_b} \\\\T_b = \frac{1}{9} \\\\T_b = 0.11 \ s[/tex]
Therefore, the beat period of the composite wave is 0.11 s.
b) Write the name of the devices
which are shown in the given
figures and write their uses
Answer:
transparent Prism
Explanation:
The device shown is a prism. It is used to study the refraction of light according with its wavelength as it transverses from a medium (air for example) to another (either glass, fluorite, plastic), and vice versa.
For that reason is also used to separate white light into its spectral wavelength components.