After 3.0 s, If the first player makes up his mind to chase his opponent. If he accelerates uniformly at 3.5 m/s^2 then it would take 3.13 seconds to catch his opponent.
What are the three equations of motion?There are three equations of motion given by Newton,
v = u + at
S = ut + 1/2×a×t²
v² - u² = 2×a×s
As given in the problem, a hockey player is standing on his skates on the Rideau Canal when an opposing player, moving with a uniform speed of 2.8 m/s, skates by with the puck. After 3.0 s, the first player makes up his mind to chase his opponent. If he accelerates uniformly at 3.5 m/s^2,
Let us assume the time taken to catch up would be t seconds.
The distance traveled by the hockey player = 2.8×3 + 2.8×t
By using the second equation of the motion,
s = ut+0.5at² = 2.8×3 + 2.8×t
1.75t² - 2.8t -8.4 = 0
t = 3.13 seconds
The distance traveled by the hockey player to catch up = 2.8×(3+3.13)
=17.164 meters
Thus, it would take 3.13 seconds to catch his opponent.
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how can you set up and solve 200x44?
Answer: 8800
Explanation:
There are two ways to solve this question.
1. Use the algorithm method which is:
First, multiply the 4 in the ones place to the zero in the one's place. Second, multiply the 4 in the ones place by the 0 in the tens place. Third, multiply the 4 in the ones place by the 2 in the hundreds place. you should get 800. next put a zero underneath the 800 in the ones place.
Next, multiply the 4 in the tens place to the 0 in the ones place of the 200. Then, multiply the same 4 to the zero in the tens place. After that, multiply the 4 of the tens place to the 2 in the hundreds place. You should write all these digits underneath your 800. Finally, add everything up and you should get your final answer of 8,800.
200
x44
-------------
800
8,000
------------
8,000
2. Another way to solve this problem is by breaking it up:
First, multiply 44 and 100 which is 4400. Then, multiply 44 and 100 again which is 4400. Add both numbers together which equals 8,800. We broke up 200 into 100's to make it easier to solve.
the amount of energy radiated by the earth peaks in the portion of the electromagnetic spectrum. visible light infrared ultraviolet gamma ray
The amount of energy radiated by the earth peaks in the Infrared portion of the electromagnetic spectrum.
The amount of energy radiated by the sun, when reaching the Earth's surface, 49.4 % is infrared radiation, 42.3 % is visible light and 8.3 % is ultraviolet radiation.
Energy is radiated back into the atmosphere after receiving from the sun ( in the form of light ). Since the Earth is much cooler when compared to the Sun, the energy radiated is much weaker. So it is radiated in the form of Infrared radiation ( long wavelength )
Therefore, the amount of energy radiated by the earth peaks in the Infrared portion of the electromagnetic spectrum.
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on the famous 18th hole at pebble beach, lionel forrest stands next to his ball on the fairway, 165 meters from the hole. his caddie hands him a golf club that will hit the ball at a 65° angle. the gravitational acceleration is 9.8 m/s2, and a stiff tailwind exactly cancels the effects of air resistance. how hard should lionel hit the ball to land it as close to the hole as possible?
The horizontal distance is R=165m
What is horizontal distance?
The angle of launch is θ=65∘
Let the hit velocity be u.
Using the formula of the range of a projectile,
R=u2 sin2θ/g
(165m)=u2sin(2×65∘)/9.8 m/s2
u2=2111 (m/s)2
⟹u≈46m/s
The projectile's horizontal range is the distance it travels while in flight. Since there is no acceleration in the horizontal direction, the greatest distance traveled in the horizontal direction is what is meant by this definition.
Therefore,
on the famous 18th hole at pebble beach, lionel forrest stands next to his ball on the fairway, 165 meters from the hole. his caddie hands him a golf club that will hit the ball at a 65° angle. the gravitational acceleration is 9.8 m/s2, and a stiff tailwind exactly cancels the effects of air resistance. how hard should lionel hit the ball to land it as close to the hole as possible?
The horizontal distance is R=165m
The angle of launch is θ=65∘
Let the hit velocity be u.
Using the formula of the range of a projectile,
R=u2 sin2θ/g
(165m)=u2sin(2×65∘)/9.8 m/s2
u2=2111 (m/s)2
⟹u≈46m/s
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Answer:
lionel should hit the ball at 46m/s
A plot of the maxwell distribution of speeds for the same sample of gas at different temperatures shows that.
At low temperatures, most molecules have speeds close to their average speed.
What is a molecule?A molecule is the smallest unit of a substance that keeps its content and properties. It is made up of two or more atoms that are joined together by chemical bonds. Chemistry is built on molecules. The element symbol and a subscript indicating the number of atoms are used to identify molecules.For instance, the symbols for the oxygen atom and molecule are O and O2, respectively.The smallest identifiable unit into which a pure substance may be divided while retaining its composition and chemical properties is a molecule, which is a collection of two or more atoms.A plot of the maxwell distribution of speeds for the same sample of gas at different temperatures shows that: At low temperatures, most molecules have speeds close to their average speed.
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What can we do with atoms?
A. bond different atoms together
B. cut them into tiny pieces
C. take out all of the protons
The only possible thing we can do is combine different atoms to form molecules and compounds
so the Correct choice is A
Mark is doing a pass to his teammate Dan. Mark is square to Dan; his thumbs are against
his chest and his elbows bent and out. Mark steps toward Dan and releases the ball
towards Dan without fully extending his arms. What type of pass is Mark doing and does
he do the pass correctly?
O Overhead pass: No, he did not bring the ball to his forehead
O Push pass: Yes, he did the pass correctly
O Chest pass: No, he should have fully extended his arms when passing to Dan
O Bounce pass: Yes, he did the pass correctly
Bounce pass: Yes, he did the pass correctly
What is Bounce passing?The bounce pass is thrown in the same motion, but it is directed at the ground instead of the air. The throw should be made so that the ball lands at the receiver's waist. Some advise trying to toss it 3/4 of the way to the receiver, and it would be a decent starting point. However, each player must experiment to determine the right distance to throw it so that it bounces to the receiver. The distance will be simpler to determine if the pass has a decent and consistent backspin.To learn more about bounce passing refer to:
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A 0.66 kg block is suspended from the middle of a 1.56 m long string. The ends of the string are attached to the ceiling at points separated by 1 m, and the block can slip along the long string. The acceleration of gravity is 9.81 m/s 2 . What is the tension in the string? Answer in units of N.
The tension in the string suspending the weight of the block is determined as 6.47 N.
What is force of tension?Tension is defined as the force transmitted through a rope, string or wire when pulled by forces acting from opposite sides.
The tension in the rope used in towing the car up hill is calculated as follows;
T = ma
where;
m is mass of the carg is the acceleration due to gravitySubstitute the given parameters and solve for the tension in the string suspending the weight of the block.
T = 0.66 kg x 9.8 m/s²
T = 6.47 N
Thus, the tension in the string suspending the weight of the block is determined as 6.47 N.
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you are given a vector in the xy plane that has a magnitude of 80.0 units and a y component of -57.0 units. part a what are the two possibilities for its x component?
The two possibilities for its x component are +56.13 units and -56.13 units.
We are given the resultant magnitude and the y component of a vector.
The x- component of the vector along with the y component and the resultant make a right-angled triangle.
The x - component can be calculated by applying the Pythagoras Theorem
Here the square of the resultant is equal to the square of the y-component and x- component.
(80)^2 = (57)^2 + (x)^2
6400 = 3249 + (x)^2
3151 = (x)^2
X=+- 56.13 units
Hence, the two possibilities for its x component are +56.13 units and -56.13 units.
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A pony is released in its new pasture. Upon entering, the pony walks 40m North, then turns and walks 20m East, before turning again and walking another 40m South. What is the ponies total displacement?
The total displacement of the ponies in the new pasture is 20m in the East direction.
The change in position of an object is measured by two physical quantities namely Distance and Displacement.
Distance is the total path traveled by the object. It is a scaler quantity. It can never be zero for a moving object. Also, its value can never be negative.
Displacement is the length of the shortest path connecting the initial and final position of the object. It is a vector quantity. Its value can be negative or zero for a moving object.
Given in the question, the pony moves 40m in the North direction and 40m in the South direction. These Directions are opposite to each other and cancel out each other. So the net displacement is only due to the movement of 20m in the East direction.
So Total Displacement = (40m North) - (40m South) + (20m East)
Total Displacement = 20m East
Hence, the total displacement of the ponies in the new pasture is 20m in the East direction.
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What do we call what is transported through a sound wave?
Answer:
n the first part of Lesson 1, it was mentioned that sound is a mechanical wave that is created by a vibrating object. The vibrations of the object set particles in the surrounding medium in vibrational motion, thus transporting energy through the medium
5. in cars, one battery terminal is connected to the metal body. how does this allow a single wire to supply current to electrical devices rather than two wires?
The battery’s negative terminal is attached to the chassis or metal body in automobiles. A single wire is used to connect the positive terminal to multiple electrical appliances.
The chassis is next connected to the negative terminal of the gadgets, completing the circuit for the current flow.
What happens if a battery’s terminals are connected?There will be a low resistance path for the current to travel when a wire is connected directly between a battery’s two terminals.
The battery will swiftly deplete, and the wire will become slightly heated (the amount of heat depends on the wire’s diameter; the smaller the diameter, the more heat).
Why is it necessary to connect a battery’s terminals?A battery can generate power when it is included in a circuit. The positive terminal (cathode) and the negative terminal are the two ends of a battery (anode).
A circuit is created by connecting the two terminals with wire. A current of electricity is created as electrons move across the wire.
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What is the work required to move a charge q from the other vertex to the center of the line joining the fixed charges?
The work required to move a charge q from the other vertex to the center of the line joining the fixed charges is zero.
The charge on two vertices of the equilateral triangle are Q and -Q which is fixed. On the other vertex is a point charge q. The work done to move the point charge q from the vertex to the midpoint of other two charges Q and -Q is the change in potential energy of the charge q.
We know that,
U = q V
V = k q / r
where,
U = Electric potential energy of a charge
V = Electric potential at a point due to a point charge
k = Coulomb's constant
r = Distance
Change in potential energy of charge q, ΔU = q ΔV
ΔU = q ( [tex]V_{f}[/tex] - [tex]V_{i}[/tex] )
Electric Potential at the midpoint of charges Q and -Q,
[tex]V_{f}[/tex] = k Q / ( a / 2 ) + k ( - Q ) / ( a / 2 ) = 0
Electric Potential at the vertex of charges q,
[tex]V_{i}[/tex] = k q / a + k ( - q ) / a = 0
ΔU = 0
The given question is incomplete. The complete question is:
Two particle with charges Q and -Q are fixed at the vertices of an equilateral triangle with sides of length a, the work required to move a particle with a charge q from the other vertex to the center of the line joining the fixed charges is?
Therefore, the work required to move a charge q from the other vertex to the center of the line joining the fixed charges is zero.
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A rock is dropped from a cliff and takes 6 seconds to hit the ground. At what time is the acceleration of the rock the greatest?
Can someone help plss:
A student gathered two boxes of the same size made of different materials: glass and clear plastic. She placed them on a windowsill in the sun for an hour, and then measured the temperature of the air in each box.
Which statement best describes the purpose of the experiment?
A. To relate the type of box material to the temperature of air within the box
B. To relate the size of the box to the temperature of air within the box
C. To relate the amount of time a box is exposed to sunlight to the temperature of air within the box
D. To relate the type of box material to the mass of the box
The statement best describes the purpose of the experiment is A ) To relate the type of box material to the temperature of air within the box
Here, two boxes of same size is exposed to sunlight for the same amount of time. The only different factor is the material of the box. So, only factors relating to the material of box might change. The temperature of air inside the box will change due to the material of box.
The glass allows up to 90 % of visible light and 72 % of UV light to pass through whereas plastic does not allow UV light to pass through. So there will be a temperature difference between the air in two boxes made of glass and clear plastic.
Therefore, the purpose of this experiment is to relate the type of box material to the temperature of air within the box ( A )
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what is velocity vs time. i need help with my test on edge
Answer:
See below
Explanation:
It is a graph on the x -y coordinate system with (generally ) the y-axis is labelled 'velocity' and the x - axis is 'time' <==== with this, you can look at the time and find the velocity at that time on the graph
Can some one Explain to me how the orbits of the planets around the sun work?
Kepler 2nd and 3rd law are tricky can someone explain?
Since the powerful gravitational pull of the Sun, all of the the solar system's planets revolve around it. The Sun basically attracts the solar system's planets, encompassing Earth, as well as allows them to be in orbit.
What is Kepler's law?Kepler's laws of planetary motion was initially published at 1609 and 1619 by Johannes Kepler which implies the description of the main orbits of planets around the Sun.
They explain the following scenarios:
Planets move in elliptical orbits all around the Sun.A planet grab the similar quantity of space in the similar time not relating of the place it is in its orbit.A planet's orbital period is usually proportional to the size of its orbit.Thus, this way, the orbits of the planets around the sun work.
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A car is traveling along the road. List three forces that act on it
Answer:
Normal force
Friction force
Gravity force
Explanation:
1.Friction force F is the sum of all the horizontal tire forces.
2.Normal force R is the sum of all normal tire forces applied by ground on the vehicle in the r direction
3gravity g =mgk
Answer:
1. Time
2.Energy
3.speed
Explanation:
1.time : as the driver moves every seconds the driver move is counted and know as time he can drive for an hr
2. Energy : the strength the driver put In to make the car move is energy
3. Speed : speed is the acceleration the driver uses
a spherical balloon has a surface charge density of omega on its outer surface and ahs radius a what is the electric field outside of the balloohn at all points in space
The electric field outside the balloon at all points in space is ω/ε where ω = Q/4πa^2.
To find the electric field(E) due to a symmetrical surface, Gauss’ Law is used, which is
E x (ds) = q/ε
Here ds = surface area of the surface
And Q = charge enclosed by the surface
As the balloon is spherical with radius a, its area will be 4πa^2
Putting the values in the above equation
E x 4πa^2 = Q/(ε)
E = Q/4πa^2(ε)
The surface charge density(ω) = Q/4πa^2
Hence
E = ω/ε
Thus, The electric field outside the balloon at all points in space is ω/ε where ω = Q/4πa^2.
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Write down the value of
an object moving in 1-dimension along a horizontal surface denoted as the x-axis. the object is initially moving in the positive x-axis direction and the rate of energy decrease of the object is proportional to the square of its speed.
The acceleration of the moving object can be defined by [tex]a_x = mv^{2} _0 * \lambda/(\lambda v_0t + m)^{2}[/tex].
What is acceleration?In physics, acceleration is the rate at which the velocity of an object changes over time. They are vector quantities and accelerations. The direction of the net force acting on an item determines the direction of its acceleration.
Acceleration is the rate at which the speed and direction of a moving object change over time. A point or object is going ahead directly when it accelerates or decelerates.
the question is incomplete
An object moving in 1-dimension along horizonta surface denoted as the x-axis. The object is initially moving in the positive X-axis direction and the rate of energy decrease of the object is proportional to the square of its speed dE ~Avz In this equation A is a constant with units of kglm_ The speed of the object at b 0 s is Vo: What is the speed of the object as function of t > 62 HINT: since the object is moving along horizontal surface its energy is simply its kinetic energy: Substitute the equation for kinetic energy into the above differential equation for energy to determine the acceleration of the object:
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A 557 hz tone is sounded at the same time as a 517 hz tone. what is the beat frequency? hz
When a 557 hz tone is sounded at the same time as a 517 hz tone, the beat frequency would be 40hz.
What does beat frequency mean?The difference in frequency between two waves is known as the beat frequency. It is as a result of both positive and negative interference. While we perceive the regular frequency of the waves as the pitch of the sound, we perceive the beat frequency as the rate at which the loudness of the sound varies.
What is the formula for beat frequency?The difference in frequency between the two superimposed waves is the formula for beat frequency.
What is vibration’s beat?Beat is the pulsing that two waves with slightly differing frequencies combine to create in physics.
CalculationBeat frequency = | f1 - f2 | or no. of cycles/time
= |557-517|
= 40Hz
Thus, the beat frequency is 40Hz
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A cyclist and a bike have a combined mass of 99kg. show that the combined weight is 990n
Explanation:
9.80665 N/kg is the force applied by Earth's gravity on a 1 kg of mass (that is then the weight of 1kg mass). the acceleration due to this gravity is usually correspondingly defined as 9.81m/s².
now we have 99 kg.
that means we have to multiply 9.81 by 99
99×9.81 = 971.19 N
if we just roughly round the weight of 1 kg from 9.81 to 10 N, we get then the proposed 99×10 = 990 N result.
but as you can see, this is not very precise.
9. Rank the four displacements for the time intervals CD, DE, EF, and FG in
decreasing order. Explain your answer.
In decreasing order, the ranking is as follows:
CD, DE, EF, and FGWhat is displacement?
Displacement can simply be defined as the difference in the position of the two objects and is independent of the path taken when traveling between the two objects.
Displacement is a vector quantity that has both a direction and magnitude.
The displacement of a hiker with a constant acceleration is equal to the average velocity during a time interval multiplied by the time interval.
The reason is because the time intervals are equal, the displacements are in the same order as decreasing average velocities. So therefore, the average velocity decreases in the order CD, DE, EF, and FG.
In conclusion, displacement depends on two positions which is the initial position and the final position.
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An earthquake in California produces seismic waves that are detected in Phoenix
990 km from the epicenter. If the wave travels at 6.3 km/sec, how long
did it take for the wave to reach Phoenix?
approximately
In seconds? |
In minutes?
Answer:
t = 157.1428 s
t = 2.619 min
Explanation:
d = v/t
t = dv
t = (990km)(6.3km/s)
t = 157.1428 s
t = 2.619 min
Hope that helps
The books has a mass of 3.5kg. the coefficient of friction between the book and the wall is 0.85.how much force must be applied to keep the book from slliding
The force that must be applied to keep the book from sliding is 41.17 N.
When a body is pressed against a wall, the four forces act on it, as shown in the image Applied force, Frictional Force, Weight and Normal Force.
To keep the book from sliding, the forces should balance each other in the horizontal and vertical directions. Thus, Applied Force and Normal Force should be equal. And Frictional force and Weight should be equal.
Hence, Applied Force = Normal Force(N)
Frictional Force = Weight (mg)
μN = mg
As applied force = N
μ x applied force = mg
0.85 x Applied Force = 3.5 x 10
Applied Force = 41.17 N
Hence, the force that must be applied to keep the book from sliding is 41.17 N.
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___ is NOT a homogeneous mixture vinegar glue a salad gelatin
(A) Salad, is not a homogeneous mixture.
If the chemical makeup of a combination remains constant throughout, it is considered to be homogenous. Homogeneous mixtures and pure substances are sometimes confused with one another since they are both uniforms. The uniformity of the substance's makeup matters. The amount of salt in the water can vary from sample to sample.
All solutions would be regarded as homogenous since the dissolved ingredient is distributed uniformly across the entire solution. Since none of the components of the combination have interacted with one another, the identities of the individual materials have not changed.
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a train travels 220km in 1.5 hours. what’s the average velocity?
Answer:caca
Explanation:
because
850 mg into kg
a, 0.85 kg
b, 0.085
c, 0.000 85 kg
d, 850, 000 kg
e, 850,000,000
help
Karen is asked to look at two spots of light and judge which one gets brighter over time. Both spots start out at 100 units of brightness. She notices that the right spot is brighter when it is 110 units. If she is presented with two new spots of light both starting at 300 units, how much brighter will one have to get before she will be able to reliably detect the difference?.
As spots start out at 100 units of brightness. One of the light spots will have to get 330 units brighter than the other for her to be able to tell the difference.
In the case of the first bulb, she noticed the difference when the right was 0.10 % brighter than the other one.
100 * 0.10 = 10
100 + 10 = 110
If we apply the same sense in the second case, one of the spots will have to be 0.10% brighter than the other.
300 * 0.10=30
300+30 = 330
In order to tell the difference, the other spot should be at 330 units of brightness.
The unit of brightness is Lumen. It is use to calculate the total amount of brightness emitted from a source over a unit of time.
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Calculate the longest wavelength (nm) that can provide an energy of at least 415 kj/mol.
The longest wavelength (nm) that can provide an energy of at least 415 kj/mol for a signal that is carried down in the consecutive cycles is 6.263 x [tex]10^{38}[/tex] /sec.
What is wavelength?A waveform is a kind of signal that is carried throughout in space or down a wire that has a wavelength, which is the separation between two identical places in the consecutive cycles.
This length can be mostly defined in wireless systems in metres (m), centimetres (cm), or millimetres (mm).
The wavelength, can also be applied to troughs, is the separation between two wave crests.
This frequency can be measured in cycles per second (Hz), which is the also defined as the quantity of vibrations that cross a specific area in a second (Hertz).
What is Plank's Constant?The fundamental universal constant that is known as Planck's constant, or also symbolized as H, is the one that establishes the quantum nature of energy and links the energy of a photon to its frequency.
Energy = plank's constant x frequency
⇒ frequency = energy/ plank's constant
= 4.15 x [tex]10^{5}[/tex]/6.626 x [tex]10^{-34}[/tex]
= 6.263 x [tex]10^{38}[/tex] /sec
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