A house on the market was valued at $397,000. After several years, the value decreased by 8%. By how much did the
house's value decrease in dollars? What is the current value of the house?

Answers

Answer 1
House value=278000$

Decrease of 9%=0.09

1. Value decrease: 278000$x0.09%=25020$

The house decreased by 25020$.

2. Current value of the house:
278000$-25020$=252980$

The current value of the house is 252980$.
Answer 2

Answers:

The house's value decreased by   $31,760  

The current value is    $365,240  

===========================================================

Work Shown:

8% of 397,000 = 0.08*397000 = 31,760 is the amount of lost value in the home. In other words, the value has dropped by this much.

The current value is 397,000-31,760 = 365,240

---------------

If you didn't care about how much value was lost, and only cared about the current value, then you can take this slight shortcut

100% - 8% = 92%

92% of 397,000 = 0.92*397000 = 365,240

If the house lost 8% of its value, then it keeps the remaining 92% to be currently valued at $365,240

This shortcut is useful if you wanted to chain together many percentage increases or decreases together.


Related Questions

help pleaseeeeeeeeeeeeeeeeee

Answers

D- The forces are balanced.
20N pushing against another 20N pushing cancels each other out, subsequently balancing the forces.

chapter 8
5.Find the circumference of each circle. Use your calculator's value of [pi]. Round your answer to the nearest tenth.

Answers

Answer:

50.2655

Step-by-step explanation:

Which number is an irrational number?
O
-233723
9
O -√√3
O 2.56
O 16

Answers

√3 is an irrational number as it is non terminating and non repeating number.

Irrational number - In mathematics, the irrational numbers are all the real numbers that are not rational numbers. That is, irrational numbers cannot be expressed as the ratio of two integers.

They are non terminating and non repeating in nature.

For example 22 / 7 , √ 5 , √ 7 and many more.

Here, √3 is an irrational number as it is non terminating and non repeating number.

Therefore, √3 is an irrational number as it is non terminating and non repeating number.

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Write the formula for the sequence: 10,6.5,3,−0.5,−4...
A. an= 3.5n − 10
B. an= 3.5n- 4
C. an= 10 - 3.5n
D. an= 13.5 - 3.5n

Answers

The formula of the sequence is aₙ = 13.5 - 3.5n

How to find the formula for a sequence?

The sequence is as follows:

10, 6.5, 3, −0.5, −4...

Studying the sequence, it's an arithmetic sequence.

Therefore, using arithmetic formula,

aₙ = a + (n - 1)d

where

a = first termd = common differencen = number of terms

Therefore,

common difference = d = 6.5 - 10 = -3.5

a = first term = 10

Therefore, the formula of the sequence is as follows:

aₙ = 10 + (n - 1)-3.5

aₙ = 10 - 3.5n + 3.5

aₙ = 13.5 - 3.5n

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What is the product?

Answers

Answer:

24x^4+32x^3+32x^2+16x+10

Step-by-step explanation:

Using distributive property,

1. multiple 4x^2 times (6x^2+8x+5)

2. multiple 2 times (6x^2+8x+5)

3. add them together

24x^4+32x^3+20x^2

+ 12x^2+16x+10

______________________

24x^4+32x^3+32x^2+16x+10

12 push-ups in 2 days = push-ups per day

Answers

Answer:

6 push ups per day

Step-by-step explanation:

→  [tex]12 \div 2 = 6~push~ups[/tex]

Answer: 6 push-ups per day

Step-by-step explanation:

12 push-ups/2 days = 12/2 = 6 push-ups each day for 2 days to have 12 push-ups total.

Lorene plans to make several open-topped boxes in which to carry plants. She makes the boxes from rectangular sheets of cardboard from which she cuts out 5-in squares from each corner. The length of the original piece of cardboard is 10 in more than the width. If the volume of the box is 1875 in3, determine the dimensions of the original piece of cardboard.

Answers

The dimensions of the original shapes are 15 and 25 inches respectively

How to determine the dimensions

The formula for volume of a rectangle is expressed as;

Volume = length × width × height

From the information given, we have;

Length = yWidth = y + 10Height = 5Volume = 1875

Substitute the values

1875 = 5 × y × y + 10

Divide both sides 5

1875 / 5 = y(y + 10)

expand the bracket

375 = y² + 10y

y² +10y - 375 = 0

y² + 25y - 15y - 375 = 0

y(y + 25) - 15( y + 25) = 0

y= 15 or y = -25

If y = 15 Inches

Width = 15 + 10 = 25 Inches

Thus, the dimensions of the original shapes are 15 and 25 inches respectively

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Erin wants to create a flower garden in the shape of a triangle. If the triangle has a base of 12 feet and a height of 10 feet, what's the area of the garden?

Answers

Answer:

[tex]60cm {}^{2} [/tex]

Step-by-step explanation:

Area for triangle is equal to half base time perpendicular height.

[tex] \frac{1}{2} (10 \times 12)[/tex]

[tex] \frac{1}{2} (120)[/tex]

[tex]60cm ^{2} [/tex]

note that it's 10cm X 12 cm that's how you get cm²

Question 12 *
12. Marcus is building a scale model of a skyscraper using the ratio 2:225. If the width of
the skyscraper is 405 ft, what is the width of the model?
A. 25 ft
B. 3.6 ft
C. 9.0 ft
D. 11.3 ft

Answers

Answer:

the answer is 3.6 ft

Step-by-step explanation:

I didn't know how to do it so I looked it up

The concrete foundation of a house requires 15 truckloads of concrete. The concrete was
poured at a depth of 0.5 meters and covered an area of 540 square meters.
a. How many cubic meters of concrete were used?
b. If each truckload was the same size, how many cubic meters did each truck carry?

Answers

Answer:

See below

Step-by-step explanation:

Area * thickness = volume

540 m^2  * .5 m = 270 m^3

15 trucks  ===>     270 m^3 / 15 trucks = 18 m^3 per truck

Given
m

Q
P
S
=
8
8

m∠QPS=88

m, angle, Q, P, S, equals, 88, degrees
m

R
P
S
=
5
x
+
3
4

m∠RPS=5x+34

m, angle, R, P, S, equals, 5, x, plus, 34, degrees
m

Q
P
R
=
8
x
+
1
5

m∠QPR=8x+15

m, angle, Q, P, R, equals, 8, x, plus, 15, degrees
Find
m

R
P
S
m∠RPSm, angle, R, P, S:

Answers

The required angle measure for the condition of the proportion of angles m∠RPS is 212.35°.

Given that,
m∠QPS = 88
m∠RPS = 5x+34
m∠QPR=8x+15
The measure of the angle m∠RPS is to be determined.

What is the angle?

The angle can be defined as the one line inclined over another line. the measure of an angle is measured in two units of degrees and in radiants.

Here,
m∠QPR = m∠QPS + m∠RPS
8x + 15 = 88 +  5x + 34
8x  - 5x = 88 + 34 - 15
3x = 107
x = 107 / 3
x = 35.67
Now,
m∠RPS = 5x+34 = 5 * 35.67 + 34 = 212.35°

Thus, the required angle measure for the condition of the proportion of angles m∠RPS is 212.35°.

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An urn contains seven white balls and three green balls. A sample of three balls is selected at random. What is the probability that the sample contains two white balls and one green ball?

Answers

the probability that the sample contains two white balls and one green ball is 21/40.

In probability and statistics, an urn problem is an idealized mental exercise in which some objects of real interest (such as atoms, people, cars, etc.) are represented as colored balls in an urn or other container. One pretends to remove one or more balls from the urn; the goal is to determine the probability of drawing one color or another, or some other properties.

Total number of balls: 7 White and 3 Green = 10 balls

Cases for three balls are drawn at random:

Selection of 3 balls from 10 balls = [tex]^1^0C_3[/tex]

Case A: 1 White and 2 Green = [tex]\frac{^7C_1 * ^3C_2}{^1^0C_3} = \frac{7*3}{120} = \frac{21}{120} \\[/tex]

Case B: 2 White and 1 Green = [tex]\frac{^7C_2 * ^3C_1}{^1^0C_3} = \frac{21*3}{120} = \frac{63}{120}[/tex]

Case C: 3 White and 0 Green = [tex]\frac{^7C_3 * ^3C_0}{^1^0C_3} = \frac{28*1}{120} = \frac{28}{120}[/tex]

Case D : 0 White and 3 Green = [tex]\frac{^7C_0 * ^3C_3}{^1^0C_3} = \frac{1*1}{120} = \frac{1}{120}[/tex]

The probability that the sample contains two white balls and one green ball = Case B

So, the probability that the sample contains two white balls and one green ball = 63/120 = 21/40

Therefore, the probability that the sample contains two white balls and one green ball is 21/40.

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the probability that the sample contains two white balls and one green ball is 21/40.

In probability and statistics, an urn problem is an idealized mental exercise in which some objects of real interest (such as atoms, people, cars, etc.) are represented as colored balls in an urn or other container. One pretends to remove one or more balls from the urn; the goal is to determine the probability of drawing one color or another, or some other properties.

Total number of balls: 7 White and 3 Green = 10 balls

Cases for three balls are drawn at random:

Selection of 3 balls from 10 balls = [tex]^1^0C_3[/tex]

Case A: 1 White and 2 Green = [tex]\frac{^7C_1*^3C_2}{^1^0C_3} =\frac{7*3}{120}= \frac{21}{120}[/tex]

Case B: 2 White and 1 Green = [tex]\frac{^7C_2*^3C_1}{^1^0C_3} =\frac{21*3}{120}= \frac{63}{120}[/tex]

Case C: 3 White and 0 Green = [tex]\frac{^7C_3*^3C_0}{^1^0C_3} =\frac{35*1}{120}= \frac{35}{120}[/tex]

Case D : 0 White and 3 Green = [tex]\frac{^7C_0*^3C_3}{^1^0C_3} =\frac{1*1}{120}= \frac{1}{120}[/tex]

The probability that the sample contains two white balls and one green ball = Case B

So, the probability that the sample contains two white balls and one green ball = 63/120 = 21/40

Therefore, the probability that the sample contains two white balls and one green ball is 21/40.

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3,3,5,6 need to make 3

Answers

Answer: (3+3*5):6

Step-by-step explanation:

[tex](3+3*5):6=\\(3+15):6=\\18:6=\\3[/tex]

Answer:

12

Step-by-step explanation:

1. \: 3 + 15 - 6 \\ 2. \: 18 - 6 \\ 3. \: 12

What is 4.5E-11 written in scientific notation

Answers

Answer: 4.5 x 10^-11

Step-by-step explanation:

4.5E-11 = 4.5 x 10^-11      ==> 4.5e-11 is basically 10^-11 multiplied by 4.5

For a certain company, the cost for producing x items is 60x+300 and the revenue for selling x items is 100x−0.5x2
Part c: Is it possible for the company to make a profit of $15,000 ?

Answers

It is not possible for a company to make a profit of $15,000 with the revenue function as 100 x − 0.5 x² and the cost function as 60 x + 300.

We know that:

Profit = Revenue - Cost

Here, we have:

Revenue function = 100 x − 0.5 x²

Cost function = 60 x + 300

Profit = $ 15,000

Substituting the values, we get that:

100 x − 0.5 x² - 60 x - 300 = 15,000

40 x - 0.5 x² - 300 = 15,000

80 x - x² - 300 = 15,000

x² - 80 x + 300 + 15,000 = 0

x² - 80 x + 15,300 = 0

No, it is not possible for a company to make a profit of $15,000 as the above equation has no real solution.

Therefore, it is not possible for a company to make a profit of $15,000 with the revenue function as 100 x − 0.5 x² and the cost function as 60 x + 300.

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What is the product in 61.18 -82?

Answers

It should be noted that the product of 61.18 and 82 will be 5016.76.

How to calculate the product?

It should be noted that a product of a given set of numbers simply means the multiplication of the numbers that are given.

In this case, we want to get the product of 61.18 and 82. This will be:

= 61.18 × 82

= 5016.76

In conclusion, the product of 61.18 and 82 will be 5016.76.

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What is the product of 61.18 and 82?

.A person can travel from NYC to Buffalo by going north 205 miles to Albany and then west 425 miles to Buffalo. A new highway is built to connect NYC to Buffalo.Find how many miles it would take to get from NYC to Buffalo if you traveled the new highway. (*Round to the nearest tenth.)

Answers

Answer: 471.9 miles

Step-by-step explanation:

This is a right triangle so a^2+b^2=c^2

205^2=42025

425^2=180625

=222650

sqrt222650 =471.9

There are 13 different types of cookies at the bakery. The baker made 24 of each type of cookie. How many cookies did the baker make in total?​

Answers

Answer:

312 in total.

Step-by-step explanation:

if 1 type of cookie is 24 cookies. so 13 types of cookies are 312 cookies.l. because 13×24=312

38 - (-74) perform the indicated operation

Answers

The result of the arithmetic expression as given in the task content is; 112.

What is the result of.thee indicated operation as in the task content?

It follows from the task content that the given expression is; 38 - (-74).

Hence, in a bid to solve the parentheses, the two negative signs are multiplied to yield a positive sign.

Ultimately, we have the result of the indicated operation as; 38 + 74 = 112.

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Which function has a range of {y|y ≤ 5}?

f(x) = (x – 4)2 + 5
f(x) = –(x – 4)2 + 5
f(x) = (x – 5)2 + 4
f(x) = –(x – 5)2 + 4

Answers

The Function that has a range of {y|y ≤ 5} is  mathematically given as

f(x) = –(x – 4)2 + 5

This is further explained below.

Which function has a range of {y|y ≤ 5}?

Generally, the equation for the function is  mathematically given as

f(x)=-(x-4)^2+5

Where

f(x)=-(x-4)^2+5 is a quadratic function. Its graph looks like a parabola. One of the vertices in the graph is (4,5) and opens in a downward direction.

Proving that f(x)=-(x-4)^2+5≤  5 for all x

[tex]x^2 \geq 0 \Rightarrow(x-4)^2 \geq 0 \\\\-(x-4)^2 \leq 0 \\\\-(x-4)^2+5 \leq 5 \text {. }[/tex]

In conclusion, The Function that has a range of {y|y ≤ 5} is  mathematically given as

f(x) = –(x – 4)2 + 5

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a copy machine makes 24 copies per minute how many copies does it make in 4 minutes and 45 seconds

Answers

Answer:76 copies

Step-by-step explanation:

hope this helps

I'm having trouble with this problem, if anyone could help I would really appreciate it. Thank you :)

Answers

The probability of the event of a wafer to be conforming and from lot A are as follows;

(a) P(A) ≈ 0.15541

(b) P(C) ≈ 0.84

(c) P(AC) ≈ 0.159

(d) P(A|C) ≈ 0.86

(e) P(C|A) ≈ 0.185

(f) E1 and E2 are independent events

How can the probability of an event be determined?

Probability is given by the ratio of the number of required outcomes divided by the number of possible outcomes.

(a) The number of wafers from lot A = 79 + 13 = 92

79+13+157+43+260+40 = 592

Which gives;

The probability that the wafer is from lot A is therefore;

P(A) = 92/592 ≈ 0.15541

(b) The conforming wafers = 79+157+260 = 496

Which gives;

P(C) = 496/592 ≈ 0.84

(c) The conforming wafers in lot A are 79

Therefore;

The probability that the wafer is from lot A and conforming is therefore;

P(AC) = 79/496 ≈ 0.159

(d) The probability that the wafer is conforming, given that it is from lot A is therefore;

P(A|C) = 79/92 ≈ 0.86

(e) The number of conforming wafers = 496

The probability that the wafer is from lot A given that it is conforming is therefore;

P(C|A) = 92/496 ≈ 0.185

(f) Independent events are events such that the occurrence of one does not impact the probability of the other.

Given that the occurrence of E1 changes the probability of event E2 if the wafer is not replaced, the events are not independent events.

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A charity-event manager counted 54 ticket receipts the day after an event. The price for an adult ticket was $21, and the
price for a student ticket was $5. The register confirms that $974 was taken in.

Answers

According to the linear equation, The number of adults tickets are 44  and number of Student tickets are 10.

According to the statement

We have to find that the Linear equation and solve it.

So, For this purpose, we know that the

The definition of a linear equation is an algebraic equation in which each term has an exponent of one and the graphing of the equation results in a straight line.

From the given information:

A charity-event manager counted 54 ticket receipts the day after an event. The price for an adult ticket was $21, and the price for a student ticket was $5. The register confirms that $974.

Then

Let number of adult tickets = x

Let number of student tickets = y

And charity-event manager counted 54 ticket receipts

=> x + y = 54 -(1)

The price for an adult ticket was $21

price for a student ticket was $5

Total Amount = 21x + 5y

The register confirms that $974 was taken in.

=> 21x + 5y = 974 -(2)

The system of equations represents matters :

x + y = 54

21x + 5y = 974

Eq2 - 5 * Eq1

=> 21x - 5x = 974 - 270

=> 16x = 704

=> x = 44

And

44 + y = 54

=> y = 10

The number of tickets are 44 Adults & 10 Student tickets.

So, According to the linear equation, The number of adults tickets are 44  and number of Student tickets are 10.

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HELP THANK YOU VERY MUCH

For which value of x is line N parallel to line M?

Answers

Answer:

x=70°

x=109°

Step-by-step explanation:

x+30+80=180

x=180-30-80=70

16.

x=64+45=109°

U(–10,–1) after a rotation 270° clockwise around the origin.

Answers

The value of the given point after rotating the graph from the 270° clockwise around the origin is U(1,10).

According to the statement

We have to find that the value of the given points after rotation.

So, For this purpose, we know that the

The definition of a graph is a diagram showing the relationships between two or more things or equation.

From the given information:

The point U(–10,–1) after a rotation 270° clockwise around the origin.

Then

we have to rotate the graph about the clockwise

And when we rotate the graph clockwise the value of the x and y are interchanged and their signs also changed.

Thus, The value on the graph become 1,10.

So, The value of the given point after rotating the graph from the 270° clockwise around the origin is U(1,10).

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-156 - (-4)

Find the difference

Answers

Answer:

-152

Step-by-step explanation:

-156 - (-4)

-156+4

= -152

you could also just go into a normal chrome browser at the top and type in -156-(-4) it will give you -152.

The ratio x:y is 3:7
Find the following in terms of x:
a) The HCF of (9y+x) and (3y+4x)
b) The LCM of (9y+x) and (3y+4x)

Answers

(a) The HCF of ( 9y + x ) and ( 3y + 4x ) is 11x

b) The LCM of ( 9y + x ) and ( 3y + 4x ) is 22x.

The ratio of x and y is given as:

x : y = 3 : 7

Then,

(x / y) = ( 3 / 7)

7x = 3y

(a) HCF of ( 9y + x) and ( 3y + 4x)

Now,

9y + x = 3(3y) + x

9y + x = 3(7x) + x

9y + x = 22x

And;

3y + 4x = 7x + 4x

3y + 4x = 11x

Now, the HCF of 22 and 11 is 11 because 22 = 2 × 11 and 11 = 11 × 1.

Therefore,

HCF of ( 9y + x ) and ( 3y + 4x ) is 11x.

(b) The LCM of (9y+x) and (3y+4x)

We know,

9y + x = 22x and 3y + 4x = 11x

So, LCM of ( 9y + x ) and ( 3y + 4x ) is 22x.

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for each final matrix, state the solution.

1 0 0 | 3
0 1 0 | -1
0 0 1 | 8

1 0 -6 | 11
0 1 4 | 7
0 0 0 | -2

1 0 2 | 9
0 1 -8 | 5
0 0 0 | 0

Answers

Answer:

Step-by-step explanation:

3TRWRRW

Determine which diagram could be used to prove △ABC ~ △EDC using similarity transformations.

Triangle A B C is rotated about point C and then dilated to form triangle C E D.

Triangle A B C is reflected across point C and then is rotated to form triangle C E D.

Triangles A B C and C E D do not have congruent angle measures.

Answers

The diagram could be used to prove △ABC ~ △EDC using similarity transformations is (a) Triangle ABC is rotated about point C and then dilated to form triangle CED.

How to determine which diagram could be used to prove △ABC ~ △EDC using similarity transformations?

From the question, we have the following highlights

The triangles are similar trianglesThe triangles are △ABC and △EDC

Similar triangles do not have to be congruent triangles

This means that if two triangles are similar, then one triangle  has been dilated to form the other triangle

This also means that

The corresponding angles of the triangles are equal while the corresponding sides of the triangles are not equal

The transformation that supports the above highlights is (a) Triangle ABC is rotated about point C and then dilated to form triangle CED.

Hence, the diagram could be used to prove △ABC ~ △EDC using similarity transformations is (a) Triangle ABC is rotated about point C and then dilated to form triangle CED.

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Answer: A. or the first one.

Step-by-step explanation: TRUST ME!  Answer correct on Edge.

My first attempt was wrong but my second attempt was correct.

HELP ME EXTRA POINTS PLSPLSPLS

Answers

Answer:a = 5b = [tex]\bf{5\frac{1}{7}}[/tex]Step-by-step explanation.

[tex]\bf \longrightarrow{f(x) = \frac{1}{x - 7} \: \: \: \: , \: \: \: g(x) = \frac{1}{x - 5} }[/tex]

[tex]\bf \longrightarrow{f \circ g = \frac{1}{ \frac{1}{x - 5} - 7} }[/tex]

So we know [tex]\frac{a}{b}[/tex] , b ≠ 0

[tex] \bf \longrightarrow{so \: \: x - 5 \neq0 \: \: , \: \: \frac{1}{x - 5} \neq7} \\ \\ \bf \longrightarrow{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: x \neq0 \: \: , \: \: \frac{1}{x - 5} \neq0 }\\ \\\bf \longrightarrow{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: x = 5 \frac{1}{7} } \\ \\ \bf \longrightarrow{and \: a < b }\\ \bf \longrightarrow{so \: a = 5 \: , \: b = 5\frac{1}{7} }[/tex]

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