a recipe calls for 30.0mL of baking soda. calculate the of the baking soda given its denstiy of 2.20g/mL

Answers

Answer 1

The mass of baking soda required that will have a volume of 30 mL is  66 g.

What mass of baking soda will have a volume of 30.0 mL given that the density of baking soda is 2.20 g/mL?

The mass of a substance can be determined if the volume and the density of the substance are known.

The mass of a substance is related to the density and the volume of the substance by the following equation:

mass = density * volume

Considering the data provided about the baking soda:

volume of baking soda required = 30.0 mL

density of baking soda = 2.20 g/mL

Hence, mass of baking soda will be;

mass of baking soda = 2.20 g/mL * 30.0 mL

mass of baking soda = 66 g

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Related Questions

When placed inside of a magnetic field, the magnetic field that electrons generate aligns in the opposite direction of the applied magnetic field. This has what effect on the nucleus the electrons are around?.

Answers

The effect is that the electrons shield the nucleus from the magnetic field.

What is a magnetic field?

A magnetic field is a vector field that explains the magnetic influence on moving electric charges, electric currents, and magnetic materials.

A force perpendicular to the charge's own velocity and the magnetic field acts on it when it moves through a magnetic field.

Moving electric charges generate magnetic fields.

Everything is constructed of atoms, and each atom has an orbiting nucleus that is composed of protons and neutrons.

Compass, motors, refrigerator magnets, railroad tracks, and modern roller coasters are all examples of objects that use magnetic force.

Charges that travel across its areas feel a force. All moving charges produce a magnetic field.

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Which graphs show the correct relationship between kinetic energy and mass? A. Graph representing a relationship between mass on the x-axis and kinetic energy on the y-axis. the line starts at the origin and increases upwards B. Graph representing the relationship between mass on the x-axis and kinetic energy on the y-axis. the curve starts at the origin and keeps on increasing C. Graph representing a linear relationship between mass on the x-axis and kinetic energy on the y-axis D. Graph representing a relationship between mass on the x-axis and kinetic energy on the y-axis. the line starts at the origin and increases as it goes with a small bend

Answers

The graph representing a linear relationship between mass [m] on the x-axis and kinetic energy (E[k]) on the y-axis is the correct graph.

What is Mechanical Energy ?

Mechanical energy is the energy of either an object in motion or the energy that is stored in objects by their position. Mechanical energy is the sum of Kinetic and Potential Energy. Mathematically -

E [M] = E [K] + E [P]

Given is a set of statements that represents the relationship between mass and Kinetic energy of the body.

The Kinetic energy of the body is the energy of the body by virtue of its motion. Consider a body of mass 'm' moving with velocity 'v' in a straight line. The Kinetic energy of the body will be -

E [K] = 1/2 mv²

If we assume that the velocity remains constant, than the value of 1/2 v² will become constant (say A). Then, the equation can be written as -

E [K] = A × m    ... Eq. 1

The general equation of a straight line representing a linear equation whose y - intercept is 0 is -

y = mx     ... Eq. 2

Comparing Eq. 1 and Eq. 2, we get -

y = E [K]   {Kinetic energy}

m = A    {slope of line}

x = m    {mass}

For A = 1

E [K] = m

E [K] [tex]\alpha[/tex] m

The graph will be linear in relationship with Kinetic energy along y - axis and mass along the x - axis. The graph is attached with the answer.

Therefore, the graph representing a linear relationship between mass [m] on the x-axis and kinetic energy (E[k]) on the y-axis is the correct graph.

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the asthenosphere is an important layer because it . 5) a) responds to forces by flowing as it is relatively strong b) responds to forces by staying rigid as it is relatively strong c) responds to forces by flowing as it is relatively weak d) responds to forces by staying rigid as it is relatively weak

Answers

The asthenosphere is an important layer because it responds to forces by flowing as it is relatively weak.

This is because the asthenosphere is solid, but mobile, meanwhile the lithosphere is solid and relatively rigid.

What is asthenosphere?

The Earth's upper mantle contains an area known as the asthenosphere, which is ductile and mechanically fragile. Between 80 and 200 km (50 and 120 mi) below the surface, it is located beneath the lithosphere, and it can reach a depth of 700 km (430 mi). It is difficult to determine the asthenosphere's lower border, though.

Despite the asthenosphere being almost completely solid, its mechanical weakness is caused by a tiny quantity of rock melting (less than 0.1% of the rock). This is the primary source of magma on Earth because as it wells higher, more extensive decompression melting of the asthenosphere occurs.

It is where some magmas that erupted above subduction zones or in areas of continental rifting, as well as mid-ocean ridge basalt (MORB), originated.

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In the mass spectrum of pentane, the presence of a peak with m/z = 15 is most likely to the detection of:_________-

Answers

In the mass spectrum of pentane, the presence of a peak with m/z = 15 is most likely due to the detection of A) methyl radical cation that has been lost from the spectrum.

Mass Spectrum

The m/z ratios of any ions contained in a sample displayed against their intensities that forms a mass spectrum.

The height of the peaks in any kind of mass spectrum denotes the relative abundance of the various components in the sample, and each peak in a mass spectrum displays a component that a distinct m/z is in the sample.

How do mass spectra function?

Only when a molecule has been transformed into a gas-phase ion can a mass spectrometer calculate the mass of the molecule.

In order to do this, it gives molecules an electrical charge and transforms the flow of electrically charged ions that results into a proportional electrical current that a data system can subsequently read.

Give an example of the mass spectral range.

Whenever any molecules are ionized in an ionization box, many different kinds of ions have been created.

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Complete Question

In the mass spectrum of pentane, the presence of a peak with m/z = 15 is most likely to the detection of: _________-

A) Methyl Radical

B) Ethyl Radical

C) Propyl Radical

D) Butyl Radical

find the magnitude and direction of this vector

Answers

Answer:

(174^2 + 88.4^2)^1/2 = 195 m       magnitude of resultant vector

(tan θ = 88.4 / 174 = .508 or 26.9 deg)

What should you do every time you exercise?
A.
Warm up
B.
Drink plenty of water
C.
Stretch
D.
All of the above

Answers

Answer:

D. All of the above

Explanation:

Because it's the most logical answer.

D /All of the above

Advantages and disadvantages of reflecting telescope

Answers

Answer:

advantages is you can look at the stars disadvantage is don't look at the sun you will go blind

I tried to solve this, not sure what I did wrong, nor what the question is actually asking for

Answers

In cartesian coordinates, we can write the position vectors as-

a) → r = 12.4 m , θ = 170°    ↔     - 12.21 i + 2.15 j

b) → r = 4 cm , θ = 50°   ↔    2.57 i + 3.06 j

c) → r = 20 inches , θ = 210°   ↔    - 17.32 i - 10 j

What are polar coordinates?

It is two-dimensional coordinate system which uses a straight line distance (from a reference point) and the angle made by it (with respect to reference direction) to represent a point in the X-Y plane.

Given are the position vectors in polar coordinates of three points in X-Y coordinate system.

The transformation from polar coordinates (r, θ) into cartesian coordinates (x, y) is done using the following formulae -

x = r cosθ

y = r sinθ

a) → r = 12.4 m , θ = 170°

x = 12.4 x cos (170°) = 12.4 x -0.98480775301 = -12 .21

y = 12.4 x sin (170°) = 12.4 x 0.17364817766 = 2.15

In cartesian form → ( -12.21 i + 2.15 j )

b) → r = 4 cm , θ = 50°

x = 4 x cos (50°) = 4 x 0.64278760968 = 2.57

y = 4 x sin (170°) = 4 x 0.76604444311 = 3.06

In cartesian form → ( 2.57 i + 3.06 j )

c)r = 20 inches , θ = 210°

x = 20 x cos (210°) = 20 x -0.86602540378 = -17.32

y = 20 x sin (210°) = 20 x -0.5= -10

In cartesian form → ( -17.32 i - 10 j )

Therefore, in cartesian coordinates, we can write the position vectors as -

a) → r = 12.4 m , θ = 170°    ↔     - 12.21 i + 2.15 j

b) → r = 4 cm , θ = 50°   ↔    2.57 i + 3.06 j

c) → r = 20 inches , θ = 210°   ↔    - 17.32 i - 10 j

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The buildup of thermal energy in a collapsing gas cloud leads to thermal pressure that can halt the gravitational collapse. What must happen for the gravitational collapse to continue?.

Answers

Answer:The buildup of thermal energy in a collapsing gas cloud leads to thermal pressure that can halt the gravitational collapse. What must happen for the gravitational collapse to continue? The cloud must radiate away some of its thermal energy.

Explanation:

By what factor does the rate constant increase when the temperature increases from 200. k to 400. k for a reaction with an activation energy of 845 j/mol?

Answers

The rate constant increases by a factor of 1.3 when the temperature increases from 200k to 400k for a reaction with an activation energy of 845 j/mol.

Calculation

ln k2/k1 = 845/8.314 (1/200 - 1/400)

ln k2/k1 = 0.254

k2/k1 = 1.3

How are k1 and k2 the rate constants determined?

The Arrhenius equation, which has the form lnk=RE(T1T1), relates the activation energy (Ea) and rate constants (k1 and k2) of a chemical process at two distinct temperatures (T1 and T2).

Where T1 and T2 are the temperatures of rates k1 and k2 (respectively) in K, k1 and k2 are rate constants, Ea is the activation energy in J/mol, and R is the gas constant which has a value of 8.314 J/K mol.

The activation energies employed were 20.1 kJ/mol and 59.8 kJ/mol.

K1 and K2 are what temperature?

The rate constants K1 and K2 are 1016 e-2000/T and 1015 e-1000/T, respectively, for two distinct reactions.

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The continuous circular motion of the wind (air mass) between the equatorial low pressure belt and the subtropical high pressure belts is known as __________

Answers

The continuous circular motion of the wind (air mass) between the equatorial low pressure belt and the subtropical high pressure belts is known as Trade winds

These winds helps ships to travel west. It also steers hurricanes. These winds are air currents that are closer to the Earth's surface. These winds start as warm air from equator and as it travels to polar regions it gets cooler. Trade winds can be found 30 degrees North and South of the equator.

The subtropical high pressure belts extends from 35 degrees North and South of the equator. It is also called as Horse latitude. The equatorial low pressure belt is the area where the trade winds from Horse latitudes of both hemispheres converges.

Therefore, the continuous circular motion of the wind (air mass) between the equatorial low pressure belt and the subtropical high pressure belts is known as Trade winds

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a uniform electric field of magnitude 4.6 ✕ 104 n/c passes through the plane of a square sheet with sides 3.0 m long. calculate the flux (in n · m2/c) through the sheet if the plane of the sheet is at an angle of 60° to the field. find the flux for both directions of the unit normal to the sheet. unit normal with component parallel to electric field n · m2/c unit normal with component antiparallel to electric field n · m2/c

Answers

41.4 x 104 Nm2/C is the electric flux through the sheet.

How to find the electric flux?

The electric flux through a planar area A is calculated as the product of the electric field, the area of the plane, and the cosine of the angle between the electric field and a vector that is perpendicular to the area.

Φ = E A cos θ -----1  

By the question;

E = 4.6 x 10⁴ N/C

A = Area of the square = l²          [l = length of the square]

=> A = (3m)² = 9m²

θ = 0°    [since the electric field is perpendicular to the square sheet, then the area vector is parallel to the field]

Substitute the values in equation 1

Φ = 4.6 x 10⁴ x 9 x cos 0°

Φ = 4.6 x 10⁴ x 9 x 1

Φ = 41.4 x 10⁴ Nm²/C

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3. Terrell drops an egg off of the top of Street Academy. How fast will the egg be going
after 2 seconds if it hasn't hit the ground yet?

Answers

The egg is traveling at least at a speed due to gravity of 20 m/s.

The force of gravity causes items to fall toward the ground. The force of gravity accelerates items as they descend to the ground. Velocity is a measure of the speed and direction of motion, and acceleration is a change in velocity. The longer an object is in free fall, the faster it descends toward the ground due to gravity.

In actuality, an object's velocity rises by 9.8 m/s2, so it reaches 9.8 m/s by the time it begins to fall. By the time it has been falling for 2 seconds (9.8 m/s plus 9.8 m/s), it is moving at 19.6 m/s, and so on.

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What did you include in your response? check all that apply. the law of conservation of momentum is satisfied. the momentum before the collision is 1.5 kg • . the momentum after the collision is 1.5 kg • . the momentum is the same after the collision as it was before the collision.

Answers

After a collision, there is no change in the momentum from the initial situation. This statement  satisfies the law of conservation of momentum. Hence, Option D is correct.

What is the law of conservation of Momentum?

Momentum is the sum of an object's mass and velocity, and it is a property of all moving objects. This can be expressed mathematically as p=MV, where p stands for momentum. The momentum of an object can fluctuate because its velocity can. When describing the momentum of a system of objects, the Law of Conservation of Momentum is helpful. The Law of Conservation of Momentum, in its most basic form, states that the total momentum of an isolated system stays constant.

Hence, the momentum will be the same after the collision as it was before the collision.

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on which date will the sun’s altitude be highest for an observer at 23 degrees north latitude? on which date will the sun’s altitude be highest for an observer at 23 degrees north latitude? march 21 june 21 september 21 december 21

Answers

On June 21 the sun’s altitude will be highest for an observer at 23 degrees north latitude.

What is special on June 21?

In the Northern Hemisphere, June 21 is both the longest day and the shortest night of the year. Here summer solstice occurs.

It is during this time that the Northern Hemisphere is closest to the Sun, and the Sun shines directly overhead on the Tropic of Cancer (23.5° North). North and south of the equator, the Tropics of Cancer and Capricorn, respectively, are located at latitudes of 23.5°.

At 5:14 a.m. Eastern time, the summer solstice occurs in 2022. As far north as the sun ever shines in the sky, it is exactly overhead the Tropic of Cancer at this particular moment.

The June solstice depends on the moment the Sun crosses its northernmost point from the celestial equator, not on any particular day or time on the calendar.

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For this assignment, consider the fact that our country spends millions of dollars each year to explore space and to learn about the structure and composition of the universe. Why do you think learning about space is a priority for our country and why are we willing to spend so much money on it? Create a discussion post about your thoughts on space exploration, including why or why not you think space exploration should be a national priority and what you think scientists hope to learn by continuing to explore the makeup of the universe.

Answers

I think that our nation's leaders prioritize space education because they see the potential benefits for us in the future.

The phrase "space exploration" is used to describe any activities connected to the study of space. Space exploration has generally been one of the subjects that mankind have been interested in. However, fresh discoveries have been made in recent years as a result of technological advancements.The majority of people on Earth are interested in space exploration because we think we fully understand the Earth's space and we want to go beyond what is possible. But the question is: Should space exploration be a top priority for the country?Space exploration shouldn't, in my opinion, be a top priority for our government since the millions of money spent on it may be better spent on enhancing the lives of many people here on Earth and abroad.I don't mean to imply that space exploration is a topic that doesn't merit consideration and investigation. However, I do think that it shouldn't be a top priority. Instead of looking for life on other planets and potentially habitable spaces when we already have our place in the universe, we should consider that our reality is on Earth and use those resources to protect it from the environmental damage we have caused it.

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What is the distance traveled by the red ball between 12s and 24

Answers

The distance the red ball travelled between 12 s and 24 s is 2116.8 m

What is free fall?

Free fall is motion under gravity.

What is the distance traveled by the red ball between 12s and 24

If we assume the red ball is falling freely, it has an initial velocity of zero.

Using the equation of motion s = ut - 1/2gt², we find the distance it travels or height it drops after the given time. where

u = initial velocity = 0 m/s, t = time and g = accleration due to gravity = 9.8 m/s²

So, s = ut - 1/2gt²

s = 0 × t - 1/2gt²

s = -1/2gt²

Distance the red ball fall in 12 s.

Since the distance the red ball falls is s = -1/2gt² with t = 12 s, we have

s = -1/2gt²

= -1/2 × 9.8 m/s² × (12 s)²

= -1/2 × 9.8 m/s² × 144 s²

= -4.9 m/s² × 144 s²

= -705.6 m

Distance the red ball fall in 24 s.

Since the distance the red ball falls is s = -1/2gt² with t = 24 s, we have

s' = -1/2gt²

= -1/2 × 9.8 m/s² × (24 s)²

= -1/2 × 9.8 m/s² × 576 s²

= -4.9 m/s² × 576 s²

= -2822.4 m

So, the distance the red ball travelled between 12 s and 24 s is d = s' - s

= -2822.4 m - (-705.6 m)

= -2822.4 m + 705.6 m

= -2116.8 m

So, the distance the red ball travelled between 12 s and 24 s is 2116.8 m

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a cylindrical container 1.0 m tall contains mercury to a certain depth, d. the rest of the cylinder is filled with water. if the pressure at the bottom of the cylinder is two atmospheres, what is the depth d?

Answers

The  pressure at the bottom of the cylinder is two atmospheres at the depth d will be 202650 Pa.

What is pressure?

The force delivered perpendicularly to an object's surface per unit area across which that force is dispersed is known as pressure. In comparison to the surrounding pressure, gauge pressure is the pressure. Pressure is expressed using a variety of units.

Calculate the size of that surface. Check to see that both numbers are expressed in the proper units, such as newtons/meters squared or pounds/inches squared. By the area, divide the force. The units of measurement for your pressure are pascals (Pa) or pounds per square inch (psi).

[tex]P = {P_{{\rm{atm}}}} + {\rho _1}gd + {\rho _2}g{h_2}[/tex]

[tex]{h_2} = \left( {1 - d} \right)\\P = 2\;{\rm{atm}}\\\begin{array}{c}\\P = \left( {2\;{\rm{atm}}} \right)\left( {\frac{{101325\;{\rm{Pa}}}}{{1\;{\rm{atm}}}}} \right)\\\\ = 202650\;{\rm{Pa}}\\\end{array}[/tex]

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different rose bushes are grown in a greenhouse for two months the number of flowers on each bushes is counted at the end of the experiment what is the independent dependent and control variable​

Answers

The independent variable is the type of rose, and the dependent variable is the quantity of flowers.

What is independent variable?

In mathematical modelling, statistical modelling, and experimental sciences, there are dependent and independent variables. Dependent variables get their name because, during an experiment, their values are investigated under the presumption or requirement that they are dependent on the values of other variables due to some law or rule.

Consider what is being recorded first in order to identify the variables; in this situation, it would be the variety and quantity of roses cultivated.

Asking yourself which one depends on which other will help you distinguish between which is reliant and which is independent.

Is it more likely that the number of flowers determines the type of rose?

Or does the type of rose affect how many blossoms are present?

Saying that a rose's kind depends on how many blossoms it has is illogical.

However, it does make sense to state that the type of rose affects how many blossoms are there.

As a result, the independent variable is the type of rose, and the dependent variable is the quantity of flowers.

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I already found Rx = -0.2 and Ry = -3. The magnitude is the square root of 0.2^2 + 3^2 = 3.01 I only need help understanding why when I plus in to solve for the direction why it won’t accept 86.2 when tan^-1(-3/0.2) doesn’t work. Please help explain to me the real answer or how I’m wrong. Thank you in advance

Answers

The values you found are incorrect.

The sum/resultant vector is

[tex]\hat R = \hat A + \hat B \\\\ \hat R = (5.00\,\mathrm m)\,\hat\imath + (6.00\,\mathrm m)\,(-\cos(30.0^\circ)\,\hat\imath - \sin(30.0^\circ)\,\hat\jmath) \\\\ \hat R = (2.00\,\mathrm m) \,\hat\imath - (3\sqrt3\,\mathrm m)\,\hat\jmath \\\\ \hat R \approx \boxed{(2.00\,\mathrm m)\,\hat\imath - (5.20\,\mathrm m)\,\hat\jmath}[/tex]

The magnitude of the resultant is

[tex]\|\hat R\| = \sqrt{(2.00\,\mathrm m)^2 + (-5.20\,\mathrm m)^2} \approx \boxed{5.57\,\mathrm m}[/tex]

The direction or angle the resultant makes with the positive horizontal axis is [tex]\theta[/tex] such that

[tex]\tan(\theta) \approx \dfrac{-5.20\,\mathrm m}{2.00\,\mathrm m} \approx -2.60[/tex]

Note the signs of the [tex]\hat\imath[/tex] and [tex]\hat\jmath[/tex] components of [tex]\hat R[/tex]. They tell us that [tex]\hat R[/tex] points into the fourth quadrant, and this means we can take the inverse tangent of both sides without any extra steps*. We then get

[tex]\theta \approx \tan^{-1}(-2.60) \approx \boxed{-67.0^\circ}[/tex]

* There would have been an extra step if [tex]\hat R[/tex] were pointing into either the second (negative [tex]\hat\imath[/tex], positive [tex]\hat\jmath[/tex]) or third quadrant (both negative [tex]\hat\imath[/tex] and [tex]\hat\jmath[/tex]). The inverse tangent function has a range of -90° to 90°, which means upon taking the inverse tangent of both sides of

[tex]\tan(\theta) = \dfrac{R_y}{R_x} \implies \theta = \tan^{-1}\left(\dfrac{R_y}{R_x}\right)[/tex]

we would only recover some angle [tex]\theta[/tex] between -90° and 90°. Yet our resultant must have some angle between -180° and -90°, or between +90° and +180° to belong to quadrant II or III. To get around this, we add an appropriately chosen multiple of 180° to the right side after taking the inverse tangent.

Suppose the magnitude of an electric field that exerts a 4. 80 x 10-17 n force on an electron is 300 n/c. What magnitude of the force does this field exert on a proton?.

Answers

The magnitude of the force exerted by the electric field on the proton will be 4.80 × 10—¹⁷ N.

The force exerted by the electric field on the electron =

4.80 × 10—¹⁷ N.

The direction of the electric field that is exerting force on the electron = West

The magnitude of the electric field is,

[tex] = \frac{4.80 \times 10 ^{ - 17} }{1.6 \times 10 - 19} [/tex]

= 300 N/C

The magnitude of the electric field is 300 N/C.

The magnitude of the force exerted by the electric field on the proton will be,

The magnitude of the force exerted by the electric field on the electron = The magnitude of the force exerted by the electric field on the electron.

[tex] = 4.80 \times 10 ^{ - 17} [/tex]

Therefore, the magnitude of the force exerted by the electric field on the proton will be 4.80 × 10—¹⁷ N.

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upiter has a mass of approximately . jupiter’s moon ganymede has a mass of approximately and it orbits jupiter at a distance of approximately . calculate the approximate magnitude of the attractive gravitational force between ganymede and jupiter.

Answers

The approximate magnitude of the attractive gravitational force between ganymede and jupiter  is 16.35 x 10^21 N .

According to Newton’s Law of Gravitation, the gravitational force between two bodies is directly proportional to the masses of the two objects and is inversely proportional to the square of the distance between them.

The above statement can be represented by the following equation:

F = Gx (m1)x (m2)/r^2

Here G = Universal Gravitational Constant = 6.67 x 10^-11 N m^2/kg^2

m1 and m2 are the masses of two bodies

r is the distance between the bodies

Putting m1= Mass of Jupiter= 1.89 x 10^27 kg

m2 =Mass of Ganymede 1.48 x 10^23 kg

r = Distance between Jupiter and Ganymede = 1.07 x 10^9 meters

F = 6.67 x 10^-11 x 1.89 x 10^27 x 1.48 x 10^23/(1.07 x 10^9)^2

On solving the above equation F comes out to be 16.35 x 10^21 N.

Thus, the approximate magnitude of the gravitational force between Ganymede and Jupiter is 16.35 x 10^21 N.

What is gravitational force?

Because it consistently attempts to pull masses together rather than pushing them apart, the gravitational force is known as attractive. In actuality, every thing in the cosmos, including you, is pulling on every other object.

Gravitation is the force in physics that draws two masses together. Unbelievably, every single particle of matter in the cosmos attracts every other particle through gravity. The phrases gravitation and gravity are sometimes used synonymously to refer to the attraction that exists between anything with mass or energy.

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a soccer ball is kicked at an angle of 64° to the horizontal with an initial speed of 15 m/s. assume for the moment that we can neglect air resistance. (a) for how much time is the ball in the air?

Answers

Time taken by the soccer ball in the air when we neglect the air resistance is 2.75s

projectile motion - It is the motion of an object which projected into the air  and moving under the gravity.

a soccer ball is kicked at an angle of 64° to the horizontal

initial speed = 15 m/s

Initial velocity in vertical direction is given as

[tex]V_{v} = V_{0}sin \theta[/tex]

[tex]V_{v} = 15sin(64)[/tex]

[tex]V_{v}[/tex] = 15× 0.8987

    = 13.48m/s

time taken to reach the maximum height is given by

T =[tex]V_{v}[/tex] /g

where

[tex]V_{v}[/tex]  is the velocity

g is the gravity

Ball comes downward with the same speed

then that time period is given by.

2[tex]V_{v}[/tex] /g

= 2× 13.48 /9.8

T = 2.75s

Time taken by the soccer ball in the air when we neglect the air resistance is 2.75s

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An object attached to one end of a spring makes 20 vibrations in 10 seconds. its angular frequency is? 0.79 rad/s 1.57 rad/s 2.0 rad/s 6.3 rad/s 12.6 rad/s

Answers

An object attached to one end of a spring makes 20 vibrations in 10 seconds, its angular frequency is 12.6 rad/s.

The quantity of complete waveforms produced per second is a wave’s frequency (f). This is equivalent to the quantity of cycles per second or oscillations per second.

In this instance, a spring-attached object causes 20 vibrations in 10 seconds. 20 vibrations in 10 seconds, in other words. S creates two vibrations in a second.

As a result, the object’s frequency is 2 Hertz.

The anglular frequency

Angular frequency, abbreviated “[tex]\omega[/tex]” is a scalar measure of rotation rate in physics. It describes the rate of change of the argument of the sine function, the rate of change of the phase of a sinusoidal waveform, or the angular displacement per unit of time.

Calculation

у = 20/10

= 2 vibrations in 1 second

Then w = 2[tex]\pi[/tex]v = 4 x 3.14

=12.56 rad /s

Thus, the angular frequency is 12.56 rad /s

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Soccer player 1 has a mass of 47 kg and moves to the right with a speed of 1.1 m/s. Soccer player 2 has a mass of 38 kg. If the total momentum of the two players is 2.2 kg m/s to the right, what are the speed and the direction of motion of player 2?

Answers

The speed and the direction of motion of player 2 is 2.2 = M1xV1 + M2xV2

2.2 = 47x1.1 + 38×V2

2.2 = 51.7 + 38xV2

-49.5 = 38×V2

V2 = -1.3 m/sec.

It means that the second object is moving opposite to first object.

What is momentum?

Momentum is product of mass and velocity. It is a vector quantity and it's S.I unit kgxmeter/sec.

In above question

Player one has

M1 = 47 kg

V1 = 1.1 m/sec

Player two has

M2 = 38 kg

V2 = not given

Total momentum = 2.2 kgxm/sec

Total momentum = momentum of first body + momentum of second body

2.2 = M1xV1 + M2xV2

2.2 = 47x1.1 + 38×V2

2.2 = 51.7 + 38xV2

-49.5 = 38×V2

V2 = -1.3 m/sec.

It means that the second object is moving opposite to first object.

Therefore, The speed and the direction of motion of player 2 is 2.2 = M1xV1 + M2xV2

2.2 = 47x1.1 + 38×V2

2.2 = 51.7 + 38xV2

-49.5 = 38×V2

V2 = -1.3 m/sec.

It means that the second object is moving opposite to first object.

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How much elastic potential energy does a spring store when it is compressed by 0.2 m if it has a spring constant of 5 N/m?​

Answers

0.1 J of elastic potential energy will be stored by the spring when it gets compressed by 0.2 m if it has the spring constant of 5 N/m.

Elastic potential energy can be defined as the potential energy stored by the spring when it is stretched or compressed.

Amount of energy stored in the elastic material or spring is directly proportional to the amount of compression or elongation.It is represented by U.Mathematically, U = [tex]\frac{1}{2} k x^{2}[/tex] ; k is the spring constant and x is the compression or expansion suffered by the spring

According to the question.

Compression in the spring, x = 0.2 m

Spring constant, k = 5 n/m

Elastic potential Energy, U = [tex]\frac{1}{2} (0.2)^{2} (5)[/tex]

U = 0.1 J

0.1 J of elastic potential energy will be stored by the spring.

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What is a good way to turn an interview into a human interest story? A. By identifying a key quotation B. By making up some information C. By presenting two people as one D. By presenting the whole interview

Answers

Identifying a key quotation is a good way to turn an interview into a human interest story. Option A

This is further explained below.

What is a key quotation?

Generally, Locating quotes that provide light on the underlying ideas of the text.

In conclusion, Being a good listener is the single most significant factor in determining one's level of success. "Accept both who you are and the heavenly purpose that you were created for.

Determine the obstacles that you face in your life and work on cultivating the self-discipline, fortitude, and strength necessary to overcome them in a way that is long-lasting so that you may continue to make progress.

Identifying a key quotation is a good way to turn an interview into a human interest story.

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To extend the range of an ammeter, a(n) _____ can be added. these are connected in _____ to the meter movement coil.

Answers

Answer:

A "resistor" can be connected in "parallel" to the meter

Suppose that an ammeter reads from 1-10 amps.

Now add a resistor in parallel to the ammeter where the resistor has the same value as the resistance of the ammeter - Now the ammeter will read 1-20 amps because only 1/2 the current passes thru the ammeter.

a sled is initially moving on a straight track at 3.5 m/s. what is its velocity two seconds later, if the sled's recorded acceleration is 2.0 (m/s)/s?

Answers

A sled is initially moving on a straight track at 3.5 m/s. The final velocity of the sled will be 3.75m/s. When the acceleration is 2.0 m/s².

What is acceleration?

The rate at which an object's velocity with respect to time changes is referred to as acceleration in mechanics. They are vector quantities, accelerations. The direction of the net force applied on an item determines the direction of its acceleration.

Given parameters:

Initial velocity  = 3.5m/s

Final velocity  = ?

Time taken  = 2s

acceleration = 2m/s²

[tex]a = v_f - v_i/t[/tex]

2 = x - 3.5/2

x = 3.75 m/s

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an ink-jet printer steers charged ink drops vertically. each drop of ink has a mass of 10-11 kg, and a charge due to 751896 extra electrons. it goes through two electrodes that gives a vertical acceleration of 104 m/s2. the deflecting electric field is mv/m.

Answers

The deflecting electric field is 0.83mv/m

Acc. to the newtons 2nd law - there is an acceleration when a force acts on an object.

F = ma     (equation 1)

where

F is force

m is mass of object

a is acceleration

Electric field intensity- it is defined as force experienced by a unit positive charge placed at that point.

it is denoted by E = F/q

where

F is force

q is the charge

F = Eq     (equation2)

from 1 and 2 equation we get

ma = Eq

E = ma /q

Charge on the drop of ink.is q.

(e is the charge on an electron.)

so,

q = 751896×e

q = 751896×1.6 ×⁻¹⁹

q = 12.03 ×10⁻¹⁴

m = 10⁻¹¹kg

a = 10⁴ m/s²

using above values

E = ma /q

E = 10⁻¹¹×10⁴/12.03 ×10⁻¹⁴

E = 0.83mv/m

The deflecting electric field is 0.83mv/m

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