Answer:
4.04 seconds
Explanation:
Context before solving:In order to solve this problem, we must keep in mind that the initial 2.00 seconds at which the fuel is exhausted does not signal when the rocket reaches its maximum height.
From this moment on, the rocket has a downward acceleration of 9.8 m/s² but it still has an upwards velocity, which we will calculate. This upwards velocity keeps the rocket moving up for a certain period of time, which we will also calculate.
For this problem, let's set the upwards direction to be positive and the downwards direction to be negative.
To find the time that the rocket takes to reach its maximum height, we are going to use the initial 2.00 seconds and find the additional seconds it takes to reach a final vertical velocity of 0 m/s. This represents the time at which the rocket stops moving and heads in the downwards direction, which takes place after the rocket has reached its maximum height.
Solving for initial velocity:The time in the air of an object in projectile motion can be found using this equation, derived from one of the constant acceleration kinematic equations.
Time in the air (projectile motion):
[tex]$t=\frac{2v_isin\theta}{g}[/tex] where g = gravitation acceleration = 9.8 m/s²Solve for [tex]v_i[/tex] by plugging in 2.00 seconds for t, 30 degrees for theta, and 20.0 m/s² for acceleration, since this is not a constant acceleration problem.
[tex]$2.00=\frac{2v_isin(30)}{20.0}[/tex]Multiply sin(30) and 2 together.
[tex]$2=\frac{v_i}{20}[/tex]Multiply 20 to both sides of the equation.
[tex]$40=v_i[/tex] [tex]v_i=40[/tex]Finding the vertical component:Now we know that the initial velocity of the rocket is 40 m/s. We need to solve for the vertical component of the rocket's velocity in order to solve for the additional time it took after the 2.00 seconds to reach its maximum height.
Vertical component:
[tex](v_i)_y=v_i \times sin\theta[/tex] [tex](v_i)_y=(40) \times sin(30)[/tex][tex](v_i)_y=20[/tex]The vertical component of the velocity vector is 20 m/s.
Finding additional seconds after 2.00 s:Now, in order to solve for the additional seconds that the rocket took to reach its maximum height, let's use one of the kinematic constant acceleration equations that uses the variables [tex]v_f[/tex], [tex]v_i[/tex], [tex]a[/tex], and [tex]t[/tex].
[tex]v_f=v_i + at[/tex]Since we are trying to solve for time, we need to use this equation in terms of the vertical direction, aka the y-direction. Time is the same in either case.
[tex](v_f)_y=(v_i)_y+a_yt[/tex]The final vertical velocity of this rocket is 0 m/s at the top, or its maximum height. We found that the vertical component, aka the rocket's initial vertical velocity, is 20 m/s. The acceleration is given to us: -9.8 m/s² (since it's falling downwards, the acceleration must be negative because we already established this in the beginning).
We are trying to solve for time t. Substitute the known values into the equation.
[tex]0=(20)+(-9.8)t[/tex]Subtract 20 from both sides of the equation.
[tex]-20=-9.8t[/tex]Divide both sides of the equation by -9.8.
[tex]2.040816327=t[/tex] [tex]t=2.04\ \text{seconds}[/tex] Finding total time to reach max height:Now we can take this time and add it to the initial 2.00 seconds of the rocket. This time we just solved for is the time after these initial seconds that the rocket kept going upwards, since its initial vertical velocity was not 0 m/s yet.
[tex]2.00+2.04=4.04 \ \text{seconds}[/tex]The time that the rocket takes to reach its maximum height is 4.04 seconds.
Answer:
4.04 second is your answer hope it help you........
A ball rolling on the ground has what form of energy?
A. KE
B. Chemical
C. PE
D. None
Answer:
a kinetic energy
Explanation:
because it is moving
PLS HELP THIS IS DUE IN TWO HOURS
Answer:
C
Explanation:
What is the function of hammer and anvil in human ear
Answer:
Vibrations of the eardrum are in turn translated into oscillations of tiny bones (ossicles) found within the middle ear. The Hammer, Anvil, and Stirrup magnify the oscillations and relay this information to the chamber of the inner ear.
Answer:
The Hammer, Anvil, and Stirrup magnify the oscillations and relay this information to the chamber of the inner ear.
The amount of oxygen in the reactants is 4 atoms. In the products, the oxygen is distributed to water (H2O) and O2 gas. Which coefficients would be placed in front of water and oxygen?
2 in front of water and 2 in front of oxygen
1 in front of water and 2 in front of oxygen
1 in front of water and 1 in front of oxygen
2 in front of water and 1 in front of oxygen
Answer:
Answer:
2 in front of water and 1 in front of oxygen
Explanation:
This question is describing balancing a chemical reaction. A balanced chemical reaction has the same number of atoms of each elements on both the reactant and product side. According to the question, the reactants contains 4 atoms of oxygen. The reactants give rise to water (H20) and O2 in the products side.
This reaction is most likely the decomposition of hydrogen peroxide (H2O2) as follows:
H2O2 (l) ----> H2O (l) + O2(g)
Based on the description, H2O2 will be 2H2O2 as it is said to contain four atoms of oxygen. This means that, in order to have a balanced equation, we must place coefficient 2 in front of water and coefficient 1 in front of oxygen. That is;
2H2O2 (l) ----> 2H2O (l) + O2(g)
Explanation:
Answer:
2 in front of water and 1 in front of oxygen
Explanation:
i took the test and got 100 so it has to be right ;)
NEED ASAP!! 23 POINTS!! Look at the pic above and tell me the velocity, distance and time. Thanks!
Answer:
Vp = 66.67 [mi/h]
Explanation:
To solve this type of problem we must remember that speed is defined as the relationship of space between time.
speed = distance/time
7)
v = speed = 100 [km/h]
distance = 750 [km]
time = distance/speed
time = 750/100
t = 7.5 [h]
8)
v1 = 200/3 = 66.67[mi/h]
v2 = 100/1.5 = 66.67 [mi/h]
Vp = average speed = (v1+v2/2)
Vp = (66.67 + 66.67)/2
Vp = 66.67 [mi/h]
answer is 9 Billion due to the decrease in Cactus
How does the law of conservation of mass apply to this reaction: C2H4 + O2 → 2H2O + 2CO2?
Answer:
The equation needs to be balanced. There are fewer oxygen atoms in the equation than hydrogen or carbon. ... There is an equal number of each element on both sides of the equation.
Explanation:
11. The professor who first
implemented a scientific approach in
order to investigate a problem, and
who is often referred to as ‘the father
of scientific methodology’, is:
a. Galileo
b. Democritus
c. Newton
d. Einstein
12. Which of the following adjustments
to a pendulum would affect the
period of oscillation?
a. Increasing the mass
b. Decreasing the length
c. Increasing the length
d. Increasing the angle of
displacement
13. The width of a desk was measured
using a meter ruler, which of the
following is the most appropriate
reading expressing the result?
a. 0.724 m
b. 0.7248 m
c. 0.72 m
d. 72 cm
Answer:Newton
Explanation:
What is the Net Force acting
on the box below?
At a local swimming pool, the diving board is elevated h = 9.5 m above the pool's surface and overhangs the pool edge by L = 2 m. A diver runs horizontally along the diving board with a speed of v0 = 2.7 m/s and then falls into the pool. Neglect air resistance. Use a coordinate system with the horizontal x-axis pointing in the direction of the diver’s initial motion, and the vertical y-axis pointing up. Let the y-axis be directed vertically down. Express the time t_w it takes the diver to move off the end of the diving board to the pool surface in terms of v_0, h, L, and g. Calculate the time, t_w in seconds, it takes the diver to move off the end of the diving board to the pool surface. Determine the horizontal distance, d_w in meters, from the edge of the pool to where the diver enters the water.
Answer:
1) The time it takes the diver to move off the end of the diving board to the pool surface, [tex]t_w[/tex], is approximately 1.392 seconds
2) The horizontal distance from the edge of the pool to where the diver enters the water, [tex]d_w[/tex], is approximately 5.76 meters
Explanation:
1) The given parameters are;
The height of the diving board above the pool's surface, h = 9.5 m
The length by which the diving board over hangs the pool L = 2 m
The speed with which the diver runs horizontally along the diving board, v₀ = 2.7 m/s
Taking [tex]t_w[/tex] = The time it takes the diver to move off the end of the diving board to the pool surface
Therefore, we have from the equation of free fall;
h = 1/2 × g × [tex]t_w[/tex]²
Where;
g = The acceleration due to gravity = 9.81 m/s²
Substituting the values, gives;
9.5 = 1/2 × 9.81 × [tex]t_w[/tex]²
[tex]t_w[/tex] = √(9.5/(1/2 × 9.81)) ≈ 1.392 s
The time it takes the diver to move off the end of the diving board to the pool surface = [tex]t_w[/tex] ≈ 1.392 s
2) The horizontal distance, [tex]d_w[/tex], in meters from the edge of the pool to where the diver enters the water is given as follows;
[tex]d_w[/tex] = L + v₀ × [tex]t_w[/tex] = 2 + 2.7× 1.392 ≈ 5.76 m
∴ The horizontal distance from the edge of the pool to where the diver enters the water ≈ 5.76 meters.
the traits of friends
Answer:
someone you trust the most
Explanation:
At which point does the image appear?
W
X
Y
Z
Miguel's parents drove him to a track meet that was 305 km away from the school. It took them 3 hours, which included a 30 minute break for breakfast. What was their average speed?
A.101.7 km/h
B.915 km/
C.122 km/h
D.275 km/h
What is the difference between m/s and m.s.
Answer
m/s rate of change of dispalcement per sec. ie velocity
m/s^2 is (m/s)/s ie rate of change of velocity per sec. ie accelerationplanation:
Answer:
Hi there. I hope your having an amazing day. Here is the answer to you question. Give me brainlest please!
Explanation:
m/s rate of change of displacement per sec. ie velocity
m/s^2 is (m/s)/s ie rate of change of velocity per sec. ie acceleration plantation
can u plz help
Define: Medium
Answer:
Medium: something in a middle position, maybe in between sizes big or small, or in a situation it's not negative or positive it's just neutral. (I'm sorry if that wasn't helpful)
Explanation:
El cloro (Z igual a 17) es un elemento utilizado generalmente en la desinfección de piscinas en la naturaleza hay 2 isótopos del cloro: el Cl-35, con una abundancia del 75% y el Cl-37 con una abudancia del 25%. Determina : a)los protones y los neutrones que hay en el nucleo de cada uno de estos isotopos b) la masa atomica media del cloro expresada en u c) el numero de atomos de cloro que hay en 15g de cloro
Answer:
a) El número de neutrones de Cl-35 es 18 y del Cl-37 es 20.
b) La masa atómica media del cloro es 35.5 uma.
c) En 15 g de cloro hay 2.55x10²³ átomos.
Explanation:
a) Para calcular los protones y neutrones de los isótopos Cl-35 y Cl-37 debemos usar la siguiente fórmula:
[tex] A = Z + N [/tex]
En donde:
Z: es el número de protones = 17
N: es el número de neutrones
A: es la masa atómica
Los isótopos de un elemento dado tienen el mismo número de protones (número atómico) y en ellos sólo varia la la masa atómica (y por ende el número de neutrones); por lo que el Cl-35 y Cl-37 tienen igual Z (17).
Para el Cl-35 tenemos:
[tex] N = A - Z = 35 - 17 = 18 [/tex]
Y para el Cl-37 tenemos:
[tex]N = 37 - 17 = 20[/tex]
Por lo tanto, el número de neutrones de Cl-35 es 18 y del Cl-37 es 20.
b) La masa atómica media del cloro está dada por:
[tex]M_{Cl} = A_{Cl-35}*\%_{Cl-35} + A_{Cl-37}*\%_{Cl-37} = 35 u*\frac{75}{100} + 37 u*\frac{25}{100} = 35.5 u[/tex]
Entonces, la masa atómica media del cloro es 35.5 uma.
c) Para encontrar el número de átomos de Cl que hay en 15 g debemos usar el número de Avogadro (6.022x10²³ átomos/mol):
[tex] N = \frac{1 mol}{35.5 g}*15 g*\frac{6.022 \cdot 10^{23} atomos}{1 mol} = 2.55 \cdot 10^{23} atomos [/tex]
Finalmente, en 15 g de cloro hay 2.55x10²³ átomos.
Espero que te sea de utilidad!
I have a really long assignment I don't understand! please help
I can try and help whats it about?
Hi there can you guys please help me write 2 paragraphs (4-6 sentences) about in article ("How Many Sets & Reps Should I Do? (Building the Correct Workout Plan)" (Links to an external site.)
Answer:
well, to create the correct workout plan I think the first day you should do as many reps as you can for each muscle you are targeting. you should also have a day you rest so your body's muscles can build. Monday, Wednesday, Friday are your workout days. Tuesday, Thursday, and Saturday are your rest days. And Sunday can be anything whether it's going to the gym, yoga, or another rest day. But back to the reps, the days you do reps, each day you should be trying to get one more rep/set than the last. If a person is new to working out then they should have a goal of ten rep/sets or something like that, so they don't overwork themselves or tear a muscle. I don't really have any other ideas for a workout plan besides just trying to be consistent and not overworking yourself, but I hope this helps. <3
Explanation:
You'll have to add on your own ideas to make it longer and add a bit more detail of course but I think you'll do well.
Connor is the paper
football champion of
all of Black Middle
School. If he thumps a
paper football with an
initial velocity of 3.0
meters per second at
an angle of 30
degrees, how far will
the football travel?
Explanation:
First we have to descompose velocity, and get Velocity of X and Y side:
Vx = V * cos 30°
Vx = 3 m/s * 0,866...
Vx = 2,598 m/s
Vy = V * sen 30°
Vy = 3 m/s * 0,5
Vy = 1,5 m/s
Lets calculate time of fly:
Firat, lets calulate up time:
uT = (Fv - Iv) / g
uT = (0 m/s - 1,5 m/s) / -9,8 m/s^2
uT = -1,5 m/s / -9,8 m/s^2
uT = 0,15 s
Like up time is equal to down time, time of fly will be:
T =uT + dT
T = 0,15 s + 0,15 s
T = 0,3 s
Now for calculate how far will reach, lets aplicate the formula:
d = Vx * T
d = 2,598 m/s * 0,3 s
d = 0,779 meters
Will reach 0,779 meters
Gud luck
The planes LA534 and LA639 are coming in for a landing on the same runway which means they are each lowering their altitude. Note that LA534 is traveling at twice the speed of LA 639. What must they do to keep from crashing into each other on the runway
Answer:
plane LA534 will have to decrease it speed by twice that of plane LA639.
Explanation:
Since both planes want to land there must be a decrease in speed.
We are told that plane LA534 velocity is twice that of plane LA639.
Now for the two planes to land without a crash. the opposite or reverse will be the case in terms of deceleration, that is
Plane LA639 will have to decrease its speed by twice the decrease in speed of plane LA534
What would happen to the number of home runs a player could hit if the air was removed from above the field? Use your understanding of Newton's laws to explain.
Answer:
number of home runs a player would hit would drastically increase
Explanation:
In a hypothetical scenario, if this were to happen the number of home runs a player would hit would drastically increase. When a player hits the ball force is applied to the ball which sends it flying, then the ball meets an opposing force of air resistance and a downward force of gravity which ultimately causes the ball to fall to the ground. This is explained in Newton's first law which states that "objects in motion remain in uniform motion and in a straight line unless they are met by an opposing unbalanced force." Without the force of air resistance, the ball will only be met with a downward force of gravity which would allow it to travel at a much greater distance before hitting the ground, thus resulting in a drastic increase of home runs.
Answer:
number of home runs a player would hit would drastically increase
Explanation:
How long will it take a plane to fly 1256km
if it travels 500km/hr?
Answer:
The answer is 2.51 sExplanation:
The time taken can be found by using the formula
[tex]t = \frac{d}{v} \\ [/tex]
d is the distance
v is the velocity
From the question we have
[tex]t = \frac{1256}{500} \\ = 2.512[/tex]
We have the final answer as
2.51 sHope this helps you
pls help me with this question pls
Explanation:
pls help me with this question pls
A catapult with a spring constant of 10,000 N/m is used to launch a target from the deck of a ship. The spring is compressed a distance of 0.5 m
before the 1.56-kg target launched. What is the target's velocity as it leaves the spring?
Please help.
(A) 10m/s
(B) 20m/s
(C) 40m/s
(D) 30m/s
Answer:
(C) 40m/s
Explanation:
Given;
spring constant of the catapult, k = 10,000 N/m
compression of the spring, x = 0.5 m
mass of the launched object, m = 1.56 kg
Apply the principle of conservation of energy;
Elastic potential energy of the catapult = kinetic energy of the target launched.
¹/₂kx² = ¹/₂mv²
where;
v is the target's velocity as it leaves the catapult
kx² = mv²
v² = kx² / m
v² = (10000 x 0.5²) / (1.56)
v² = 1602.56
v = √1602.56
v = 40.03 m/s
v ≅ 40 m/s
Therefore, the target's velocity as it leaves the spring is 40 m/s
HELP!! WILL MARK BRAINLIEST!!!!!
Complete the following sentences. Energy is required to _______ bonds in a molecule and released when bonds are _______.
Answer:
Create
Broken
Explanation:
Bond formation or creation requires the use of energy. Energy is used during bond formation between chemical species. The energy is required for the reaction to occur.
When bonds are broken, energy is releasedBond breaking process is a procedure that releases energy. This energy makes them able to react.diffrence uniform and non uniform
Un automóvil se mueve hacia el norte siguiendo una trayectoria rectilínea con una velocidad constante, recorre 195 Km cada 1.3 h. ¿Calcula la velocidad con que se mueve?
Answer:
La velocidad con la que se mueve el automóvil es 150 [tex]\frac{km}{h}[/tex]
Explanation:
La velocidad es una magnitud que expresa la relación entre el espacio recorrido por un objeto, el tiempo empleado para ello y su dirección.
Es decir, la velocidad se define como la relación que se establece entre la distancia recorrida y el tiempo transcurrido en el movimiento de un móvil.
Se puede calcular la magnitud de la velocidad utilizando la siguiente expresión:
[tex]velocidad=\frac{distancia}{tiempo}[/tex]
En este caso:
distancia= 195 kmtiempo= 1.3 hReemplazando:
[tex]velocidad=\frac{195 km}{1.3 h}[/tex]
Resolviendo:
velocidad=150 [tex]\frac{km}{h}[/tex]
La velocidad con la que se mueve el automóvil es 150 [tex]\frac{km}{h}[/tex]
Which of the following describes the acceleration of an object with constant velocity?
a) Negative acceleration
b) Positive acceleration
c) Not enough acceleration to tell
d) No acceleration
Do you always need
more than one reactant
or more than one
product to have a
chemical reaction?
Answer:
no
Explanation:
A block of mass 3 kg is pushed 1 m along a frictionless horizontal table by a constant 16 N force directed 34◦ below the horizontal. Determine the work done by the applied force. Answer in units of J.
please help i'm a struggling physics student. Thanks so much!
Answer:
W = 13.26 [J]
Explanation:
Work in physics is defined as the product of force by the distance traveled by the object.
It is important to clarify that the force should be parallel to the direction of movement. In this way, we have to decompose the force into the X component of the movement.
Fx = 16*cos(34) = 13.26 [N]
W = F*d
where:
F = force = 13.26 [N]
d = distance = 1 [m]
W = 13.26*1
W = 13.26 [J]
Answer:
the guy above me is correct
Explanation:
Please help I will give brainliest
Answer:
ask questions that the findings bring up
Explanation:
hope this helps :)
Answer:
ask questions that the findings bring up