The equation of motion in terms of v and x is [tex]\frac{dv}{dx} = -\mu v[/tex]
What is velocity?Velocity is the directional speed of a moving item as an indication of its rate of change in position as seen from a specific frame of reference and measured by a specific time standard (e.g., 60 km/h northbound). The idea of velocity is crucial in kinematics, the part of classical mechanics that explains the motion of bodies.
A physical vector quantity called velocity requires both magnitude and direction to be defined. Speed is a coherent derived unit that expresses the scalar absolute value (magnitude) of velocity. Its quantity is expressed in SI units (metric system) of metres per second (m/s or ms1). For example, "5 meters per second" is a scalar while "5 meters per second east" is a vector.
Let [tex]v(t) = \frac{ds}{dt}[/tex] be the velocity of a time t . Now its time rate of change, [tex]\acute{v}[/tex] = [tex]\frac{dv}{dt}[/tex]
is the acceleration, Therefore,
⇒ [tex]a(t)=v^{\prime}(t)=\frac{d}{d t}\left(\frac{d s}{d t}\right)[/tex]
On the other hand, the acceleration will be given by
⇒ [tex]a = - \mu v^2[/tex]
Where [tex]\mu[/tex] is constant, thus
⇒ [tex]\frac{dv}{dt} = -\mu v^2[/tex]
Where is the motion equation expressed in terms of v and t We must now write it in terms of v and x. To accomplish this, we make use of the fact that
⇒ [tex]\frac{d v}{d t}=\frac{d v}{d x} \cdot \frac{d x}{d t}=v \frac{d v}{d x}[/tex]
We now substitute the acquired result into the supplied equation.
⇒ [tex]v \frac{d v}{d x}=\frac{d v}{d t}=-\mu v^2[/tex]
Divide the equation by v ≠ 0
⇒ [tex]\frac{dv}{dx} = -\mu v[/tex]
We have changed the provided equation of motion in terms of v and x in this manner.
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Full question
A rocket sled having an initial speed of 160 mi/h is slowed by a channel of water. Assume that, during the braking process, the acceleration a is given by
[tex]av = -\mu v^2[/tex]
where v is the velocity and \mu is a constant. (a) As in Example 4 in the text, use the relation
[tex]\frac{dv}{dt} = v\frac{dv}{dx}[/tex]
to write the equation of motion in terms of v and x.
PLS HELPPP I NEED IT
FITT principle:
Frequency-is how regular or often a person does the plan of a target health-related physical activity. It depends on how determined you want to accomplish your target. The more often you train, the faster the result.
Intensity - is how hard a person exercise during a physical activity period. It can be measured in different ways, depending on the health-related component. For example, monitoring heart rate is one way to measure the intensity during aerobic endurance activities, but does not indicate intensity during flexibility activities. The harder you work, the faster your heart beats.
Time - is the duration of the physical activity. Together with the other aspects of the FITT principle, time varies depending on the target health-related fitness component. For example, in developing flexibility, stretching may take 10-30 seconds for each activity, while the minimum time for performing an aerobic exercise is 20 minutes of continuous action.
Type - refers to the physical activity chosen to improve a specific component of health-related fitness. Different events require different training programs. For example, if a person wants to increase core muscles, he or she must do exercises that target the oblique muscles, while another person wishing to improve his or her cardiovascular endurance needs to jog, run, swim or perform some other aerobic activities.
The FIIT plan required for different type of workout is shown in the image attached.
FIIT plan is used to monitor one's workout routine. It also helps to create workout routines that helps one's fitness goal which might differ from each person. It works based on four elements i.e., Frequency, Intensity, Time and Type.
Frequency refers to how often a workout needs to be done. Intensity refers to how hard a workout must be done. Time refers to the amount of time spent on the workout. Type refers to the king of exercise which suits one's final goal.
Therefore, the FIIT plan required for different type of workout is shown in the image attached.
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A boy and a girl are biking down a hill. The boy and the girl weigh the same, and they are using bikes that weigh the same. If the boy and girl are biking at the same speed, which child has more motion energy (kinetic energy)?
Answer:
neither.
they both are going at the same speed
Explanation:
Answer:
They have the same Kinetic Energy
Explanation:
KE = 1/2 m v^2 if the velocities are the same and the masses are the same .....then the Kinetic energies are the same
A coin lies under a glass filled with water.
Explain that you cannot see the coin
Refraction is the cause of this. We perceive an object when light reflects off of it and travels to our eyes. The penny appears to vanish because light is refracted as it passes through the glass's edges and the water, never reaching our eyes.
Refraction in physics is the change in direction that results from a wave's change in speed as it passes through a medium. The electromagnetic waves that make up light are bent due to their different speeds as they pass past the boundary of one transparent medium and into another.
When partially submerged in water and viewed from an angle other than 90° to the surface, a straight stick seems bent. When travelling from air to glass, a ray of light of a single wavelength (various wavelengths appear as different colours to the human eye) is refracted, or bent, in a way that relies on the speeds of the two mediums.
A straight stick appears bent when partially submerged in water and viewed at an angle other than 90° to the surface. A light ray of a single wavelength—different wavelengths appear as different colors to the human eye—is refracted, or bent, in a way that depends on the speeds of the two media when it travels from air to glass.
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A 28.5 g sphere is added to a graduated cylinder containing 45.50 ml of water. The water level rises to the 49.10 ml mark. What is the volume of the sphere? What is its density? Based on its density, what type of metal is it?
According to this question, a 28.5 g sphere is added to a graduated cylinder containing 45.50 ml of water. The water level rises to the 49.10 ml mark.
This means that the volume of the sphere can be calculated as follows: 49.10mL - 45.50mL = 3.6mL.
The density can be calculated by dividing the mass by its volume as follows:
Density = 28.5g ÷ 3.6mL = 7.92g/mL
Based on the density of the sphere, it is incoloy.
Therefore;
The volume of the sphere that weighs 28.5g is 3.6mLThe density of the metal sphere is 7.92g/mL.Learn more about density at: https://brainly.com/question/6107689
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A Plastic fork has a mass of 5g and a volume of 5.2cm³. What is the density of the plastic fork?
Answer: 0.96153846153846 g/cm3
Explanation:
A cheetah can maintain a constant speed of 30 m/s. At this rate, how far will it travel in 3 seconds? (Express you answer in m.)
Answer:
90m
Explanation:
it travels at 30 m/s so 30*3 is 90
Photons are shone on a piece of metal and one electron is ejected for each absorbed photon. What happens when the wavelength of light is decreased?.
The ejected electrons would have greater kinetic energy if the wavelength of light is decreased when Photons are shone on a piece of metal and one electron is ejected for each absorbed photon.
What is Kinetic energy?This is referred to as the type of energy which is possessed by a body by virtue of its motion and it has an inverse relationship with the wavelength of light.
This therefore means that as the wavelength of light is decreased, the kinetic energy of the ejected electrons will increase and vice versa which is therefore the reason why it was chosen as the most appropriate choice.
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in example 2.6, we considered a simple model for a rocket launched from the surface of the earth. a better expression for a rocket's position measured from the center of the earth is given by
The expression for velocity is [tex]v(t)=\frac{\sqrt{2g}}{\sqrt[3]{x(t)}}R_{E}[/tex]
The expression for acceleration is [tex]a(t)=-\left ( \frac{gR_{E}^{2}}{[R_{E}^{\frac{3}{2}}+3\sqrt{\frac{g}{2}}R_{E}t]^\frac{4}{3}} \right )[/tex]
The expression for the rocket's position as measured from the center of the earth is
[tex]y(t)=[R_{E}^{\frac{3}{2}}+3\sqrt{\frac{g}{2}}R_{E}t]^\frac{2}{3}[/tex]
Let
[tex]x(t)=R_{E}^{\frac{3}{2}}+3\sqrt{\frac{g}{2}}R_{E}t[/tex]
We have,
[tex]y(t)=[x(t)]^\frac{2}{3}[/tex]
The velocity of the rocket as a function of time is given by
[tex]v(t)=\frac{\mathrm{d} y(t)}{\mathrm{d} t}=\frac{2}{3}[x(t)]^{-\frac{1}{3}}\frac{\mathrm{d} x(t)}{\mathrm{d} t}[/tex]
[tex]v(t)=\frac{\mathrm{d} y(t)}{\mathrm{d} t}=\frac{2}{3}\frac{1}{\sqrt[3]{x(t)}}\frac{\mathrm{d} x(t)}{\mathrm{d} t}[/tex]
Since
[tex]x(t)=R_{E}^{\frac{3}{2}}+3\sqrt{\frac{g}{2}}R_{E}t[/tex]
We have,
[tex]\frac{\mathrm{d} x(t)}{\mathrm{d} t}=3\sqrt{\frac{g}{2}}R_{E}[/tex]
[tex]v(t)=\frac{2}{3}\frac{1}{\sqrt[3]{x(t)}}\frac{\mathrm{d} x(t)}{\mathrm{d} t}[/tex]
[tex]v(t)=\frac{2}{3}\frac{1}{\sqrt[3]{x(t)}} X 3 \sqrt{\frac{g}{2}}R_{E}=\frac{\sqrt{2g}}{\sqrt[3]{x(t)}}R_{E}[/tex]
[tex]v(t)=\frac{\sqrt{2g}}{\left ( R_{E}^{\frac{3}{2}}+3\sqrt{\frac{g}{2}}R_{E}t \right )^\frac{1}{3}}R_{E}[/tex]
[tex]v(t)=\frac{\sqrt{2g}}{\sqrt[3]{x(t)}}R_{E}[/tex] .......(i)
The acceleration as a function of time is given by
[tex]a(t)=\frac{\mathrm{d} v(t)}{\mathrm{d} t}[/tex]
[tex]a(t)=\frac{\mathrm{d}}{\mathrm{d} t}\left (\frac{\sqrt{2g}}{\sqrt[3]{x(t)}}R_{E}\right )[/tex]
[tex]a(t)=\frac{\mathrm{d}}{\mathrm{d} t}\left ({\sqrt{2g}}R_{E}[x(t)]^{-\frac{1}{3}}\right )[/tex]
[tex]a(t)=\sqrt{2g}R_{E}\frac{\mathrm{d}}{\mathrm{d} t}[(x(t)]^{-\frac{1}{3}}[/tex]
[tex]a(t)=-\frac{1}{3}\sqrt{2g}R_{E} [(x(t)]^{-\frac{4}{3}}\frac{\mathrm{d} x(t)}{\mathrm{d} t}[/tex]
[tex]a(t)=-\frac{1}{3}\sqrt{2g}R_{E} [(x(t)]^{-\frac{4}{3}}3\sqrt{\frac{g}{2}}R_{E}[/tex]
[tex]a(t)=-gR_{E}^2 [(x(t)]^{-\frac{4}{3}}[/tex]
[tex]a(t)=-\left ( \frac{gR_{E}^{2}}{[x(t)]^\frac{4}{3}} \right )[/tex]
[tex]a(t)=-\left ( \frac{gR_{E}^{2}}{[R_{E}^{\frac{3}{2}}+3\sqrt{\frac{g}{2}}R_{E}t]^\frac{4}{3}} \right )[/tex] .......(ii)
Therefore, the expression for velocity is [tex]v(t)=\frac{\sqrt{2g}}{\sqrt[3]{x(t)}}R_{E}[/tex]
& the expression for acceleration is [tex]a(t)=-\left ( \frac{gR_{E}^{2}}{[R_{E}^{\frac{3}{2}}+3\sqrt{\frac{g}{2}}R_{E}t]^\frac{4}{3}} \right )[/tex]
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In Example 2.6, we considered a simple model for a rocket launched from the surface of the Earth. A better expression for a rocket's position measured from the center of the Earth is given by [tex]y(t)=[R_{E}^{\frac{3}{2}}+3\sqrt{\frac{g}{2}}R_{E}t]^\frac{2}{3}[/tex]
where RE is the radius of the Earth (6.38 ✕ 106 m) and g is the constant acceleration of an object in free fall near the Earth's surface (9.81 m/s2).
(a) Derive expressions for v(t) and a(t).
(Use the following as necessary: g, RE, and t. Do not substitute numerical values; use variables only.)
define a system you interact with every day. is the system open, closed, or isolated? how do matter and energy flow into, out of, or within the system?
In daily life the common example of isolated system, closed system and open system is themosteel bottle , human body and ecosystem respectively.
Water in a thermos, or thermosteel bottle is an example of isolated system where no transfer of energy neither transfer of matter takes place between the system and surroundings. Although no system is perfectly isolated, after some instant there a hear loss takes place by some means.
There are three types of system in thermodynamics,
Open system – system which allows transfer of heat and matter between system and surroundings. For example- Ecosystem.Closed system – system which allows transfer of heat but no transfer of matter between system and surroundings. For example- human body. Isolated system – no transfer of energy neither transfer of matter takes place between the system and surroundings For example – thermosteel bottle.Thermodynamics is the branch of science is which we study about the heat, temperature, work and their relation to energy.
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the 25-m crane boom ao lies in the yz plane. determine the maximum permissible tension in cable ab if the absolute value of moments about the coordinate axes of the force exerted on a by cable ab must be |mx|≤ 61.6 kn·m, |my|≤ 13.6 kn·m, |mz|≤ 9.6 kn·m.
The maximum permissible tension in cable AB is 3.11 kN
Given that,
I [tex]M_{x}[/tex] I ≤ 61.6 kN.m
I [tex]M_{y}[/tex] I ≤ 13.6 kN.m
I [tex]M_{z}[/tex] I ≤ 9.6 kN.m
OC = √ [tex]OA^{2}[/tex] - [tex]AC^{2}[/tex]
OC = √ [tex]25^{2}[/tex] - [tex]15^{2}[/tex]
OC = 20 m
[tex]r_{A}[/tex] = 15j + 20k
AB = √ [tex]2.5^{2}[/tex] + [tex]15^{2}[/tex] = 15.2069 m
P = P AB / AB = ( P ) 2.5i - 15j / 15.2069
P = 0.164399P i - 0.98639P j
[tex]M_{o}[/tex] = [tex]r_{A}[/tex] * P = [tex]\left[\begin{array}{ccc}i&j&k\\0&15&20\\0.163499P&-0.98639P&0\end{array}\right][/tex]
[tex]M_{o}[/tex] = ( 19.7828P ) i + ( 3.2700P ) j - ( 2.4525P )k
I [tex]M_{x}[/tex] I ≤ 61.6
19.7828P ≤ 61.6
P ≤ 3.11 kN
I [tex]M_{y}[/tex] I ≤ 13.6
3.2700P ≤ 13.6
P ≤ 4.16 kN
I [tex]M_{z}[/tex] I ≤ 9.6
2.4525P ≤ 9.6
P ≤ 3.91 kN
Tension is the act of stretching. It is a force transmitted through a object when pulled by forces across opposite sides.
Therefore, the maximum permissible tension in cable AB is 3.11 kN
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Find the electrical energy expended by an electric lamp labelled 100 W in 8 seconds.
Tropical rainforests are being cleared at a rate of 8 million hectares per year. How many football fields per hour are being deforested? One hectare is equal to 2.47 acres, and there are 1.32 acres in a football field. (Round to the nearest acre per hour.)
The number of football fields per hour that are being deforested is 1710 football fields.
How to convert hectares to acres?According to this question, tropical rainforests are being cleared at a rate of 8 million hectares per year.
This means that 8 million hectares are being cleared every 8760 hours, since there are 365 days in a year and 24 hours in a day.
1 hectare = 2.471 acres
8 million hectares = 19.77 million acres
If 19.77 million acres is cleared every 8760 hours
Per hour, 19770000 ÷ 8760 = 2256.8 acres is cleared.
Since there are 1.32 acres in a football field, this means that approximately 1710 football fields are being deforested per hour.
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A bicyclist starts from rest and accelerates along a straight path to a speed of 12. 15 m/s in a time of 4. 5 seconds. What is the bicyclist’s acceleration to the nearest tenth of a m/s2?.
Answer:The cyclist's acceleration to the nearest tenth is: C. 2.7 .
Given the following data:
Initial velocity = 0 m/s (since the cyclist starts from rest).
Final velocity = 12.5 m/s.
Time = 4.5 seconds.
To find the cyclist's acceleration to the nearest tenth:
Acceleration is calculated by subtracting the initial velocity from the final velocity and dividing by the time.
Mathematically, acceleration is given by the formula;
Where:
A is the acceleration.
V is the final velocity.
U is the initial velocity.
t is the time measured in seconds.
Substituting the given parameters into the formula, we have;
Acceleration, A = 2.7
Therefore, the cyclist's acceleration to the nearest tenth is 2.7 .
Explanation:
an electron is to be accelerated from a velocity of 2.50×106 m/sm/s to a velocity of 9.00×106 m/sm/s . through what potential difference must the electron pass to accomplish this?
Through -212 V potential difference must the electron pass to accomplish this
What is Potential difference?The difference in electric potential between two points, which is defined as the effort required per unit of charge to move a test charge between the two places, is known as voltage, electric potential difference, electric pressure, or electric tension.
The initial kinetic energy of the electron is,
[tex]{K_i} = \frac{1}{2}mv_i^2[/tex]
Here, m is the mass of the electron and
is the initial velocity of the electron.
[tex]\begin{array}{c}\\{K_i} = \frac{1}{2}\left( {9.11 \times {{10}^{ - 31}}\;{\rm{kg}}} \right){\left( {2.5 \times {{10}^6}\;{\rm{m/s}}} \right)^2}\\\\ = 2.88 \times {10^{ - 18}}\;{\rm{kg}}\\\end{array}[/tex]
The final kinetic energy of the electron is,
[tex]\begin{array}{c}\\{K_f} = \frac{1}{2}\left( {9.11 \times {{10}^{ - 31}}\;{\rm{kg}}} \right){\left( {9 \times {{10}^6}\;{\rm{m/s}}} \right)^2}\\\\ = 3.68 \times {10^{ - 17}}\;{\rm{kg}}\\\end{array}[/tex]
[tex]\begin{array}{c}\\{V_1} - {V_2} = \frac{{3.68 \times {{10}^{ - 17}}\;{\rm{J}} - 2.88 \times {{10}^{ - 18}}\;{\rm{J}}}}{{ - 1.6 \times {{10}^{ - 19}}\;{\rm{C}}}}\\\\ = - 212\;{\rm{V}}\\\end{array}[/tex]
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a 100 w incandescent light bulb converts approximately 2.5% of the electrical energy supplied to it into visible light. assume that the average wavelength of the emitted light is λ
The question is incomplete the right solution for this question is:
E photon = 2.39 eV, b = 6.32 * 1048 fotones/s, c = 9.87 * 1048 fotones/s.
To compute the answer, we must take into account the Plack postulate, which states that each photon's energy is given by
Ephoton is equal to h*f, where f is the frequency of light and h is the Planck universal constant.
We also know that the relationship between wavelength and frequency for waves has the following form:
velocity equals wavelength times frequency (f) Assuming that velocity in our case is the same as the speed of light, we can derive
Ephoton= h*f= h*c/ and hc= 1240 eV/nm are related terms.
Consequently, Ephoton=1240/540 nm=2.39 eV
Since power is defined as energy/time, we may calculate the power emitted by considering a number per second (n) and multiplying it by its energy.
Power in this instance: n*h*f
On the other hand, we must take into account that the light is emitted isotropically in order to compute the number of photons per second at a distance of 5 m from a light bulb using an area of 2 cm2.
the percentage of the 2 cm2 at 5 meters is 425 of the total area radiated.
0.02*0.02/25=1,6*10^-5
To perform the calculations for photons at 810 nm, we must alter the photon energy to 1.53 eV.
As 810 nm photons have lower energy, 100 W light bulbs emit more of these photons than they do.
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When is simple observation more appropriate than experimenting in a controlled laboratory?
Simple observation more appropriate than experimenting in a controlled laboratory when the results can be gotten solely by using our sense organs.
What is Experiment?This is referred to as a part of a scientific method and it is performed by scientists to test a hypothesis so as to know whether it will be accepted or refuted.
This is usually performed by different people from all over the world so as to ascertain its authenticity before it becomes a theory or law. This doesn't involve only sense organs alone as different techniques are required to arrive at a conclusion in this process.
Observation on the other hand requires the use of sense organs such as the eyes, nose etc to determine the results and may not need the use of experiments which is therefore the reason why it was chosen as the correct choice.
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a future space explorer has been kidnapped and is held prisoner on a planet in our solar system. with nothing else to do, our prisoner amuses herself by dropping her watch from eye level (170 cm) to the floor. she observes that the watch takes 0.95 s to fall. ignore air resistance.
The acceleration due to gravity of Jupiter is found to be 24.5m/s².
What is free fall?Any motion of a body in which gravity is the sole force acting on it is referred to as free fall in Newtonian physics. A body in free fall has no force acting on it according to general relativity, where gravity is reduced to a space-time curvature.
When gravity and the resulting acceleration are the only forces acting on an object, this is referred to as freefall in physics. A body falling freely due to the earth's gravity is what the phrase "freefall" refers to. Gravitational acceleration will result from this motion.
F = (G x m1 x m2)/r2
F = (6.67 x 10-11) (1.9 x 1027) (185) / ( 7.18 x 107)2
= 4547.8 N
Since the probe is on Jupiter's surface and the force we just discovered is the force of gravity on the surface between the two, this would also be the probe's weight.
Since F = mg:
4547.8 = 185g
24.58 m/s² = g
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use the above information to answer the questions, Run 1 Distance between the intervals position (m) AB= 1,3 BC=1,3 CD 1,3 DE = 1,3 EF = 1,3 Perioel (P)=1/25×5 =0,2sec Run2 Distance between the intervals position (m) AB= 1,5 BC = 1,8 CD = 2 DE 2,2 EF=2,4 Draw a graph of position versus time for 2.1 Run 1 2.2 Run 2
Using the charter system conversation in the right angled value triangle we apply distance formula and get the G-plot value of 9.876 u.
How is position determined in velocity - time?The movement in a graph is determined through the two perpendicular axis in which the first coordinate represents the distance to be traveled in the x axis and the second coordinate shows the distance to be traveled in the y axis .
What is distance formula ?If you want to determine the distance between any two point in a graph the distance formula is used in such case the distance formula is applied like Pythagoras theorem.
Given:
A (1,3)
Period = 0.2 seconds
B (1,5)
Period = 0.5 seconds
Before applying distance formula we need to simplify the given value into charter system.
Where,
A become a substituted value for the argument of square on the basic structure.
Since A symmetrical is that of right angled triangle we can use the basic charter values.
Therefore A now become A(π,2)
Similarly B become B(e,nπ)
Using distance formula to find the graph plot we get:
AB = 5.6π - e×3.14
AB = 9.876
where AB is the distance between A and B.
Therefore using the charter system conversation in the right angled value triangle we apply distance formula and get the G- plot value of 9.876 u.
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The social cognitive perspective of personality focuses on social factors such as your parents guardians and teachers and cognition what does cognition mean
The social cognitive perspective of personality focuses on social factors such as your parents guardians and teachers and cognition means how we as individuals process and store information.
What is Cognition?This is referred to as the process in which information is stored and processed through the use of our senses, experience etc and is common to all individuals.
The social cognitive perspective of personality on the other hand focuses on social factors such as parents and also in which cognition is among and it is influenced by genetic and environmental factors which therefore makes it the most appropriate choice.
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When jumping, a flea accelerates at an astounding 1500 m/s2 , but over only the very short distance of 0.44 mm . if a flea jumps straight up, and if air resistance is neglected (a rather poor approximation in this situation), how high does the flea go?
When the flea jumps straight up, and if air resistance is neglected, the height of the flea will be 0.089m.
What is air resistance?Air resistance acts as a force on objects moving through the atmosphere. This force acts in the opposite direction when a body is travelling through the air. Air resistance causes the moving body to experience frictional force. A body's speed decreases as it goes due to air resistance.
It should be noted that the equation of kinematics will be illustrated thus:
V = ✓(2 × 1500 × 0.44mm)
Therefore, h = V² / 2g
= (✓(2 × 1500 × 0.44mm)² / (2 × 9.8)
= 0.089m
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We have that the flea goes as high as
h=0.0889m
How high does the flea go?From the Question, we are told that
Acceleration =1500ms^2
Distance d=0.47mm
Generally, the equation for height is mathematically given as
h=\frac{u^2}{2 g}
Where
u^2=2 * 1500 * 0.44 * 10^{-3}
u=1.32ms
Therefore
h=\frac{1.32^2}{2 * 9.8}
h=0.0889m
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HELP ASAPP PLEASE!!! I know that I got one correct but i’m not sure what the other one is.
Answer:
Replace distance with "direction"
Explanation:
a boat can travel at a speed of 8 km/h in still water on a lake. in the flowing water of a stream, it can move at 8 km/h relative to the water in the stream. if the stream speed is 3 km/h, how fast can the boat move past a tree on the shore when it is traveling.
Relative velocity of the river with respect to shore, V = 20 km/h.
Relative velocity of the river with respect to shore ,V = 10 km/h
Velocity of the shore = 0 km/h
Relative velocity of the river with respect to shore:
[tex]V = V_{r} - V_{s}[/tex]
Velocity of the river [tex]V_{r}[/tex] = 10 km/h
Relative velocity of the boat with respect to river ,V'= 10 km/h
[tex]V^{'} = V_b} -V_{r}[/tex]
Velocity of the boat [tex]V_b}[/tex] = 20 km/h
Relative velocity of the boat with respect to shore, V":
[tex]V_{"} = V_{b} - V_{s}[/tex]
Relative velocity of the boat with respect to shore is 20 km/h.
What is Relative velocity?It is the pace at which one object's relative location changes in relation to another object over time.
Think about two trains that are traveling in the same direction and at the same pace. Even though the tracks, buildings, and trees on each side of the railway indicate that both trains are moving, to the observer of one train, the other train appears to be stationary. The other train seems to be moving at a constant speed.
The speed at which one thing moves in relation to another is known as the relative velocity of the two objects.
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daniel harris has always enjoyed eating tuna fish. unfortunately, a study of the mercury content of canned tuna in 2010 found that chunk white tuna contains 0.6 ppm hg0.6 ppm hg and chunk light tuna contains 0.14 ppm.20.14 ppm.2 the u.s. environmental protection agency (epa) recommends no more than 0.1 μg hg/kg0.1 μg hg/kg body weight per day. a person weighs 69 kg69 kg . how often may the person eat a can containing 6 ounces6 ounces (16 oz
One 6 oz can of chunk light tuna is to be consumed every four days.
How to find the number of days interval?The mercury content in 2010:
White tuna chunks weigh 0.6 ppm in total.
A piece of light tuna has a mass of 0.14 ppm.
The body weighed 63 kg, and the tuna weighed 6 oz.
The maximum quantity of mercury that the body should ingest each day is advised to be no more than 0.1 micrograms.
Solution:
Let's first convert the tuna's mass to grams.
As 1 oz equals 28.3495 g
The tuna weighs 6 oz, or 28.3495 g.= 170.097 g
The maximum daily mercury (Hg) intake for a 63 kg body weight is equal to 63 0.1.
6.3 micrograms per day
But the mass of the mercury (Hg) = concentration (Hg) mass of the tuna
= 0.6 × 10⁻⁶ × 170.097 g
= 1.0206 × 10⁻⁴ g
= 102.06 μg (micrograms)
The interval needed to consume one 6 oz can of chunk white tuna = 102.06/6.3
= 16.2 days
≅ 16 days
An average of 16 days must pass between consuming one 6 oz can of chunk white tuna.
the mass of the mercury (Hg) is equal to the product of the concentration (Hg) and
the mass of the tuna (0.14 106 170.097 g = 2.4814 105 g = 23.814 g).
= 23.814/6.3
= 3.78
As a result, it takes 3.78 days plus 4 days to consume one 6 oz can of chunk white tuna.
Approximately every four days, a single 6 oz can of chunk light tuna is consumed and the total 6-ounce tuna can be consumed in 16 days.
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5. What is Deviation?
6. a) Why don't walkers usually have a problem with deviation?
b) When might deviation be a problem for a walker trying to use a compass?
7. Why can deviation be a problem in ships?
8. Describe two ways of correcting for deviation in a ship.
A gait deviation is a a physiotherapy term. It refers to change in the gait cycle that affects the trunk, hip, knee, or ankle joint. Increased age and/or certain disorders might cause gait abnormalities. These diseases can be either musculoskeletal or neurological in origin.
Why don't walkers usually have a problem with deviation?Walkers don't usually have problem with gait deviation because, walking in itself helps to correct problems with gait deviation. Walking correctly exercises the muscles and skeletons associated with gait hence preventing deviation.
When might deviation be a problem for a walker trying to use a compass?Deviation might be a problem for a walker trying to use a compass if the walker is having or experiencing a Spastic Hemiparetic Gait.
It is distinguished by unilateral leg extension and circumduction, in which the paretic limb moves laterally (circumducts) during the swing phase. This is sometimes referred to as circumductory gait.
The compass can hardly be maintained pointed in the appropriate direction with this configuration.
Why would deviation be a problem when travelling in a ships?Sea travel is known to produce gait changes or deviation.
The reason for this is not far-fetched. Ships don't travel on smooth terrain.
The open sea is characterized by complex, oscillating motion of ships in three translational dimensions (surge, sway, and heave) and three rotational dimensions (roll, pitch, and yaw).
The ship is the base of support or ground surface for passengers and crew: body control must be changed to accommodate for the ship's 6 degrees of freedom oscillatory motion.
Changes in stride that define those who have fully acclimated to living at sea are one of the most well-known characteristics of this compensation.
Anecdotal evidence focuses on a "rolling gait" that is prominent enough to be seen by casual onlookers.
What are two ways of correcting for deviation in a ship?The two ways of correcting deviation are:
In other circumstances, physical therapy may be necessary to enhance balance, strength, and flexibility. You should also undergo fall prevention training.Maintaining good foot alignment may need the use of in-shoe splints or leg braces. In circumstances of uneven leg length, a shoe raise may be useful.Learn more about physiotherapy :
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From his observations of the phases of venus, galileo concluded that the ptolemaic model of planetary motion was wrong because it predicted.
Galileo’s telescopic discoveries of the moons of Jupiter are often mentioned. But they did not amount to proof that the Ptolemaic system was incorrect.
It's hard to tell you how big a shakeup this caused in astronomy at the time. Thanks to Galileo, we now knew that planets weren't perfect, ethereal lights in the sky. That things could orbit them, same as (most astronomers thought) things did around Earth, making Earth less special, and providing evidence that maybe that heliocentric theory wasn't that out there.
Basically, before Galileo, astronomers were looking at an unchanging, heavenly firmament, separate from Earth by its very heavenly nature.
After, they were studying planets - actual worlds like ours - and moons and the physical (as opposed to heavenly) reality of their place in the universe.
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Imagine the following objects in deep space, separated by a kilometre. which pair of objects experiences the largest gravity force? a proton and an electron an apple and a brick two apples an apple and a proton
The pair of objects that experiences the largest gravity force is an apple and a brick
An object will be weightless in outer space, away from the gravitational field of Earth (or another massive planet), yet it will still have mass and consequently resistance to a given force.
When one body has a higher mass than another, it is said to be more massive. The electron, with a mass of about 9.11 10-31 kg, is one of the Universe's least massive things. Hence, the combination of a proton and electron would experience the least gravity force. The combination of an apple and a brick has the most mass hence would experience the largest gravity force. Two apples or an apple and a proton are less massive compared to an apple and a brick thus incorrect.
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If the same change in velocity occurs in less time does the magnitude of the corresponding average acceleration increase, decrease, or stay the same
The magnitude of the related average acceleration will increase if the same change in velocity occurs in less time.
The rate at which a body's distance changes in relation to time is referred to as its velocity. The SI unit is meter per second ( m/s).
Acceleration is the rate at which speed and direction of velocity vary over time. When something moves faster or slower, it is considered to be accelerating. Motion on a circle accelerates even while the speed is constant because the direction is always changing.
Acceleration can be defined as the time rate of change in velocity
a = Δv / t
Now as t is in the denominator.
The smaller value of time will result in greater acceleration values with constant velocity change.
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A train travelling at 22m/s accelerates uniformly at 0.85 m/s^2 for 25s. Calculate the distance travelled by the train at this time.
The distance travelled by the train travelling at 22 m/s, which accelerates uniformly at 0.85 m/s² for 25s is 815.62.
What is Second equation of motion?
The second equation of motion is used to calculate the distance traversed by the body moving with uniform velocity. Mathematically -
S = ut + 1/2 at²
Given in the question is a train travelling at 22 m/s accelerates uniformly at 0.85 m/s² for 25s. From this, we can write -
Initial velocity [u] = 22 m/s
acceleration [a] = 0.85 m/s²
time taken [t] = 25 s
In order to find the distance travelled by the train, we will use the second equation off motion -
S = ut + 1/2 at²
S = 22 x 25 + 1/2 x 0.85 x 25 x 25
S = 815.62 meters
Therefore, the distance travelled by the train travelling at 22 m/s, which accelerates uniformly at 0.85 m/s² for 25s is 815.62.
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Prompt: Explain how your physical, emotional, and mental state affects your performance in your exercise. Use specific examples from your experience
Being physically, emotionally, and mentally healthy can keep you healthy and help you avoid significant health issues during exercises.
How to illustrate the information?Exercise boosts mental health by lowering anxiety, depression, and depressive symptoms, as well as by raising self-esteem and increasing cognitive abilities. Additionally, it has been discovered that exercise helps with symptoms including poor self-esteem and social withdrawal.
Exercise on a regular basis can significantly improve symptoms of sadness, anxiety, and ADHD. Additionally, it lowers stress, enhances memory, promotes sound sleep, and uplifts your mood in general. It should be noted that it's important to be in the right state of mind during exercise to prevent injuries.
Therefore, being physically, emotionally, and mentally healthy can keep you healthy and help you avoid significant health issues during exercises.
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J. J. Thomson used a cathode-ray tube to calculate the charge-to-mass ratio of the electron. Which of these suggested the presence of a negative particle?.
J. J. Thomson used a cathode-ray tube to calculate the charge-to-mass ratio of the electron. The deflection of cathode rays towards the positively charged surface proved that they are negatively charged particles.
In 1897, J.J Thomson performed a cathode ray tube experiment to determine the charge-to-mass ratio of electrons.
Due to high flow of voltage, a beam of particles was allowed to flow from the negatively charged end to the positively charged end of the tube.
An end of the tube was painted with phosphorous and when electrons struck that end, a green spark was observed which confirmed the presence of negatively charged particles i.e. electrons.
To put it simply, cathode rays came from the cathode tube and deflected towards a positively charged plate showing that they are negatively charged particles.
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