A runner is jogging in a straight line at a steady vr= 7 km/hr. When the runner is L= 7.6 km from the finish line, a bird begins flying straight from the runner to the finish line at vb= 28 km/hr (4 times as fast as the runner). When the bird reaches the finish line, it turns around and flies directly back to the runner.

What cumulative distance does the bird travel? Even though the bird is a dodo, assume that it occupies only one point in space (a “zero” length bird), travels in a straight line and that it can turn without loss of speed.
Answer in units of km.

After this first encounter, the bird then turns around and flies from the runner back to the finish line, turns around again, and flies back to the runner. The bird repeats the back and forth trips until the runner reaches the finish line. How far does the bird travel from the beginning (including the distance traveled to the first encounter)?
Answer in units of km.

Answer:

6m/s

Explanation:

A=d÷t

A=60÷10

6

Answer:

The gravitational potential energy of the ball is 39,200 J

Explanation:

Gravitational Potential Energy

It is the energy stored in an object because of its vertical position or height in a gravitational field.

It can be calculated with the equation:

U=m.g.h

Where m is the mass of the object, h is the height with respect to a fixed reference, and g is the acceleration of gravity or [tex]9.8 m/s^2[/tex].

The wrecking ball is hung at a height of h=20 m and has a mass of m=200 Kg. Substituting in the formula:

U=200*9.8*20

U = 39,200 J

The gravitational potential energy of the ball is 39,200 J

Answer:

Smoke alarms detect fires by sensing small particles in the air using a couple of different kinds of technologies. Once they detect those particles above a certain threshold, they signal the alarm to sound so that you and your family can get to safety and call 911. Smoke alarms save lives.

Answer:

the app your on now is great and can ask anything

Answer:

"The sun releases energy at a mass–energy conversion rate of 4.26 million metric tons per second, which produces the equivalent of 384.6 septillion watts (3.846×1026 W)."

Explanation:

This might help you, also this is searched.

Answer:

C

Explanation:

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Answer:

You should write the vectors in their proper sequence: i , j, k

If the vectors are perpendicular their dot product must be zero:

1) A dot B   is obviously zero since A and B have no common terms in i , j , k

2) looks like A = 2 i - 4 j + 3 k and B = i + 2 j + 2 k

A dot B = (2 * 1) + (-4 * 2) + (3 * 2) = 0

Note that the dot product produces a scalar with no direction (vector components)

Only i dot i, j dot j, and k dot k    have components   i dot j = zero, etc.

The obvious differences between the beam observations and cylinder observations are that the maximum value of the cylinder observations is higher and the observations for cylinders are more variable or spread out.

In the above case, the material strength observations in Mega Pascals for cylinder and beams are given.

The values for cylinders are as follows

6.1, 5.8, 7.8, 7.1, 7.2, 9.2, 6.6, 8.3, 7.0, 8.3, 7.8, 8.1, 7.4, 8.5, 8.9, 9.8, 9.7 14.1, 12.6 11.2, 8.1, 7.4, 8.5, 8.9, 9.8, 9.7, 14.1, 12.6, 11.2

And the values for beams are

5.9, 7.2, 7.3, 6.3, 8.1, 6.8, 7.0, 7.6, 6.8, 6.5, 7.0, 6.3, 7.9, 9.0, 8.2 , 8.7, 7.8, 9.7, 7.4, 7.7, 9.7,7.8, 7.7, 11.6 11.3 11.8 10.7,8.2, 8.7, 7.8, 9.7, 7.4, 7.7, 9.7, 7.8, 7.7, 11.6, 11.3, 11.8, 10.7

From the above-given values, we can calculate the mean/average value of the observations.

The average value for cylinders comes out to be 8.57.

The average value for beams comes out to be 8.14.

Among the given values, the maximum value is 14.1 for cylinder observations.

The values of beam observations range from 5.9 to 11.8 while the values for cylinder observations range from 5.8 to 14.1. Therefore, the observations for the cylinder are more variable or spread out.

Thus, the maximum value of the cylinder observations is higher and the observations for cylinders are more variable or spread out.

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This question is incomplete. The data used for solving the question is given in the adjoining image.

Because most particles fired at metal foil passed straight through, Rutherford concluded that only a small area of an atom is positively charged called the nucleus.

Rutherford's atomic model states that the atom is a small-sized particle that is composed of other fundamental objects i.e. electrons, protons, and neutrons.

In the core of an atom, there is an extremely dense, tiny-sized object called the nucleus which is positively charged.

Moreover, the nucleus is the central point containing all the mass of an atom around which negatively charged particles revolve in circular paths called electrons.

To put it simply, this model suggests that when electrons interacted with atoms in gold metal foil, only a few changed their path after colliding with the massive dense nucleus.

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Answer: Newton's third law of motion states that for every action, there is an equal and opposite reaction. When a player hits a ball with a bat, the force the player exerted on the ball through the bat gave the ball a push force in the forward direction.

Explanation:

(a) If we consider the waves to travel in a straight line (x = 0), according to their wave speed,

(b) The waves are ranked according to the tension in the strings along which they travel, with the greatest first,

The linear density of the string and the tension in the string both affect the wave's speed. The linear density is the mass divided by the string's length. In general, the square root of the ratio of the medium's elastic to inertial properties determines a wave's speed.

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The displacement at a constant acceleration of 3.0[tex]m/s^{2}[/tex] is 526.5m.

Distance, which is a scalar quantity, describes "how much ground an object has covered" while moving. The term "how far out of place an object is" relates to displacement, a vector number that describes the total change in position of the object.

For constant acceleration, displacement is:

[tex]d = (\frac{1}{2} ) (\frac{v_{f}^{2} - v_{i} ^{2} }{a} )[/tex]

[tex]d = \frac{60^{2}-21^{2} }{2*3}[/tex]

[tex]d = \frac{3600-441}{6}[/tex]

[tex]d = \frac{3159}{6}[/tex]

d = 526.5m

Therefore, the displacement at a constant acceleration of 3.0[tex]m/s^{2}[/tex] is 526.5m.

The complete question is: An airplane accelerates with a constant rate of 3.0m/s^2 starting at a velocity of 21m/s. If the final velocity is 60m/s what is the displacement during this period?

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The correct answer is 2.51 m/s.

The principle of conservation of momentum states that an isolated system's total momentum will remain unchanged in the absence of an external force. In other words, momentum cannot be created or destroyed but can only be changed by the action of forces as they are described by Newton's laws of motion.

Momentum is the product of an item's mass and its speed, and it is also equivalent to the entire amount of force needed to bring an object to rest.

From the conservation of momentum,

[tex]m_1 u_1 + m_2 u_2 = ( m_1 + m_2 ) v[/tex]

Substitute the values, to get the required speed,

[ ( 0.45 ) ( 0 )] + [ ( 0.67 )([tex]u_2[/tex])] = ( 0.45 + 0.67 ) ( 1.5 )

[tex]u_2[/tex] = 2.51 m/s

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Answer:

Three Laws

Newton's Three Laws of Motion. Sir Isaac Newton: The Universal Law of Gravitation. Sir Isaac Newton and the Unification of Physics & Astronomy.

Explanation:

Answer:

Average: 22.142857142857  

Average =  

Sum

Count

=  

155

7

=  22.142857142857

Sum 155

Count 7

Median 23

Geometric Mean 16.412764443111

Largest 38

Smallest 2

Range 36

Answer:

15.4

Explanation:

Answer:

[tex]4800\; {\rm kg}[/tex].

Explanation:

When an object of mass [tex]m[/tex] travels at a velocity of [tex]v[/tex], the momentum [tex]p[/tex] of that object would be [tex]p = m\, v[/tex].

Momentum is conserved immediately after the collision. Hence, the momentum that the [tex]3600\; {\rm kg}[/tex] vehicle lost in the collision would be equal to the momentum that the other vehicle has gained.

Momentum that the [tex]3600\; {\rm kg}[/tex] vehicle lost:

[tex]\begin{aligned}(\text{momentum change}) &= (\text{new momentum}) - (\text{original momentum}) \\ &= m\, v(\text{new}) - m\, v(\text{old}) \\ &= m\, (v(\text{new}) - v(\text{old})) \\ &= 3600\; {\rm kg} \, (9.0\; {\rm m\cdot s^{-1}} - 21.0\; {\rm m\cdot s^{-1}}) \\ &= (-43200)\; {\rm kg \cdot m \cdot s^{-1}}\end{aligned}[/tex].

The vehicle that was originally at rest would have gained that [tex]43200\; {\rm kg \cdot m\cdot s^{-1}}[/tex] of momentum. The momentum of that vehicle was [tex]0\; {\rm kg \cdot m \cdot s^{-1}}[/tex] before the collision since that vehicle was initially not moving. After gaining the [tex]43200\; {\rm kg \cdot m\cdot s^{-1}}\![/tex] of momentum, the new momentum of that vehicle would be [tex]p = 43200\; {\rm kg \cdot m\cdot s^{-1}}\!\![/tex].

Rearrange the equation [tex]p = m\, v[/tex] to obtain an expression for mass: [tex]m = (p / v)[/tex]. It is given that the velocity of this vehicle is [tex]v = 9.0\; {\rm m\cdot s^{-1}}[/tex] after the collision. Substitute both momentum [tex]p[/tex] and velocity [tex]v[/tex] into the equation [tex]m = (p / v)\![/tex] to find mass [tex]m\![/tex]:

[tex]\begin{aligned} p &= \frac{m}{v} \\ &= \frac{43200\; {\rm kg \cdot m \cdot s^{-1}}}{9.0\; {\rm m\cdot s^{-1}}} \\ &= 4800\; {\rm kg} \end{aligned}[/tex].

In other words, the mass of the vehicle that was originally not moving would be [tex]4800\; {\rm kg}[/tex].

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Answer:

The answer is 200 joules.

Answer:

Its answer is 200joule.

Explanation:

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Answer:

I think the correct answer from the choices listed above is option A. The correct arrangement of the substances according to the most to the least ordered particle arrangement should be wood, water and neon gas. Wood should be the first since it is solid which has the most ordered structure as compared to the liquid and a gas. The neon gas is the last since as a gas it has the least ordered structure.

Answer:

A) wood, water, neon gas

Explanation:

wood, water, neon gas.

The particles of solids have an arrangement that is highly ordered and regular. Liquids have an arrangement that is less ordered, and the particle arrangement in gases is the least ordered and regular of the three states of matter.

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Answer:

[tex] \sf t = \dfrac{V_f - V_i}{a} [/tex]

Explanation:

[tex] \rm V_f = V_i + at \\ \rm V_f - V_i = at \\ \rm at = V_f - V_i \\ \rm t = \dfrac{V_f - V_i}{a} [/tex]

Answer:

D.) South American becomes dire than normal

Explanation:

La Niña effect can be regarded as an effect that has impacts on the global climate, this effect bring about disruption in normal weather patterns, as a result of this intense storms as well as drought is experienced. The effect could be intense by worsening of above temperature. It bring an increases the probability of having a rainfall below normal. As a result of this

South American becomes dire than normal.

Answer:

The five basic types of chemical reactions are combination, decomposition, single-replacement, double-replacement, and combustion

Explanation:

The five basic types of chemical reactions are combination, decomposition, single-replacement, double-replacement, and combustion. Analyzing the reactants and products of a given reaction will allow you to place it into one of these categories

Justin's average speed for the triathlon is 15.23km/h

Average speed is the total distance covered in total time taken.

(given) 28 minutes to finish the 1500 meter swim

1.75 hours for the 40 kilometer biking portion

70 minutes for the 10 kilometer run

total distance covered = 1500m + 40 km+ 10 km

                                   = 51500m = 51.500km

                                            (1km = 1000m)

total time taken = 28mint + 1.75hr + 70 mint

                           = 203mint

                time in hours = 203/60 hr

                                            (1hour = 60 mint)

average speed = total distance covered / time taken

   = 51.5 x  203/60                    

    = 15.23km/h

Justin's average speed for the triathlon is 15.23km/h

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By utilising a galaxy model that accurately explains all of the data that has been collected thus far.

In other words, while every star is a star, not every star is a Sun. Since the Sun is bigger than most stars, it is also more brighter. In our galaxy alone, there are billions of Suns, and as was already established, many of the stars we can see are Suns. However, a lot of what you see while gazing up into space is not a star.

The sizes of stars range from neutron stars, which can be about 12 miles (20 kilometres) across, to supergiants, which have a diameter that is 1,000 times larger than the sun. The brightness of a star is influenced by its size. Particularly, brightness and radius are related.

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Answer:

4ac (quadruples)

Explanation:

The general formula for centripetal acceleration is given as follows:

[tex]a_{c} = \frac{v^2}{r}\\\\[/tex]   -------------- equation (1)

where,

ac = centripetal acceleration

v = tangential speed

r = radius of circular path

Now, if we double tangential speed, v' = 2v, then the acceleration will become:

[tex]a_{c}' = \frac{(2v)^2}{r}\\\\a_{c}' = \frac{4v^2}{r}[/tex]

using equation (1):

[tex]a_{c}' = 4a_{c}[/tex]

therefore, the correct answer is:

4ac (quadruples)

Answer:

is there any options

Explanation:

Answer:

3.68 m/s².

Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 9.4 ms¯¹

Maximum height (h) reached = 12 m

Final velocity (v) = 0 (at maximum height)

Acceleration of free fall (g) =?

v² = u² – 2gh (since the rock is going against gravity)

0 = 9.4² – 2 × g × 12

0 = 88.36 – 24g

Collect like terms

0 – 88.36 = –24g

–88.36 = –24g

Divide both side by –24

g = –88.36 / –24

g = 3.68 m/s²

Thus, the acceleration of free fall near the surface of Mar is 3.68 m/s².

The  acceleration of free fall near the surface of Mars is [tex]3.68 \;\rm m/s^{2}[/tex].

Given data:

The magnitude of initial velocity of rock is, u = 9.4 m/s.

The height raised up by rock is, h = 12 m.

Here, we need to find the acceleration of free fall, which is nothing but the gravitational acceleration. So we will use the Third kinematic equation of motion, which is given as,

[tex]v^{2}=u^{2}+2gh[/tex]

Solving as,

[tex]0^{2}=9.4^{2}+(2 \times -g \times 12)\\\\g = 3.68 \;\rm m/s^{2}[/tex]

Thus, we can conclude that the  acceleration of free fall near the surface of Mars is [tex]3.68 \;\rm m/s^{2}[/tex].

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