A student wants to determine the coefficient of static friction μ between a block of wood and an adjustable inclined plane. Of the following, the minimum additional equipment the student needs to determine a value for μ is

Explanation:

Total energy (kinetic + potential)

1/2×mv^ + mgh

1/2×5×8×8+ 5×9.8×10

1/2×320 + 5×98

320/2 + 480

320/2 + 980/2 (multipling to make the denominator equal)

1300/2 = 650 joules

Hope it helps, if you don't understand try doing it yourself with the formula.

:)

Answer:

I'm pretty sure its c

Hope you get a good grade-

Answer:

Explanation:

Impulse is the change of momentum of an object when the object is acted upon by a force for an interval of time.

the expression is Ft=mv

where F= force

 m= mass

t= time

v= velocity

Step one:

given data

mass m= 110g= 0.11kg

velocity v= 6.5m/s

time t= 0.19seconds

Step two:

we also know that the force on impulse is given as

Ft=mv

F=0.11*6.5/0.19

F=0.715/0.19

F=3.76N

The magnitude of the average force on the wall if the duration of the collision is 0.19 is 14N

Answer:

C. a liter of salt water.

Explanation:

Defination of Solution =>

a liquid mixture in which the minor component (the solute) is uniformly distributed within the major component (the solvent).

Answer:

The energy lost to the environment is 0.461 J

Explanation:

Given;

mass of the magnet, m = 0.2 kg

height of fall, h = 35 cm = 0.35 m

initial speed of the magnet, u = 0

final speed of the magnet, v = 1.5 m/s

Initial energy of the magnet is given by;

E₁ = P.E₁ + K.E₁

E₁ = mgh₁ + ¹/₂mu²

E₁ = (0.2 x 9.8 x 0.35) + ¹/₂(0.2)(0)²

E₁ = 0.686 J

Final energy of the magnet as it emerges from the tube is given by;

E₂ = mgh₂ +  ¹/₂mv²

E₂ = (0.2 x 9.8 x 0) + ¹/₂(0.2)(1.5)²

E₂ = 0 + 0.225 J

The energy lost to the environment is given by;

E = E₂ - E₁

E = 0.225 J - 0.686 J

E = -0.461 J (negative sign indicates lost energy to the environment)

Therefore, the energy lost to the environment is 0.461 J

Answer:

It isn't moving

Explanation:

Answer:

ok tbh i didnt cry when neji died but now when i think about it i just cry thinking about how himawari could have met her uncle

Explanation:

Answer:

Explanation:

The pressure transmitted in the hydraulic system can be found by using the formula

[tex]p = \frac{f}{a} \\ [/tex]

f is the force

a is the area

From the question we have

[tex]p = \frac{35}{5} \\ [/tex]

We have the final answer as

Hope this helps you

Answer:

A. -5.5 N

Explanation:

I can confirm that the answer is A.

Answer:

Radio waves

Explanation:

Radio wavs are electromagnetic waves.

Hope this helped!

Answer:

Explanation:

Step one:

given data

acceleration a=4m/s^2

final velocity v=35m/s

time t=5 seconds

Step two:

Required

initial velocity u=?

Applying the first equation of motion

v=u+at

substituting we have

35=u+4*5

35=u+20

u=35-20

u=15 m/s

The initial velocity is 15m/s

Answer:

hi mate,

interesting question, first of all the pressure is determined by using the following formula:

Pg = p * G * h  

where p is the density of the liquid, G is the gravity and h is the height difference, in you case you have:

p = 1015 kg/m3

G = 9.8m/s2

h = 0.085 m  

insert these values into the equation above:

Pg = 1015 kg/m3 * 9.8m/s2 * 0.085 m = 849.81 kg·m-1·s-2 or 849.81 pascal

hope it helps, :-)

please mark me as brainliest

Answer: Natural science can be divided into two main branches

Explanation:

life science and physical science. Life science is alternatively known as biology, and physical science is subdivided into branches: physics, chemistry, astronomy and Earth science.

Answer:

Umm sorry just came for the points.

Answer:

The energy stored is [tex]E_s = 0.0064 \ J[/tex]

Explanation:

From the question we are told that  

   The capacitance  is  [tex]C = 8 \ \mu F = 8*10^{-6} \ F[/tex]

    The resistance is  R = 3.00-Ω

    The emf is  [tex]E_t = 70.0 V[/tex]

      The power  is  P = 300 W

Generally the total  emf is mathematically represented as

   [tex]E_t = E_c + E_r[/tex]

Here  [tex]E_c[/tex] is the emf across that capacitor which is mathematically represented as

      [tex]E_c = \frac{q}{C}[/tex]

and [tex]E_r[/tex] is the emf across the resistor which is mathematically represented as

       [tex]E_r = \sqrt{P R}[/tex]

So  

       [tex]E_t = \sqrt{PR} + \frac{q}{C}[/tex]

=>    [tex]q = C[E_t - \sqrt{PR} ][/tex]

Generally the energy stored in a capacitor is mathematically represented as

          [tex]E_s = \frac{q^2}{2C}[/tex]

=>      [tex]E_s = \frac{[C [ E_t - \sqrt{PR} ]]^2}{2C}[/tex]

=>      [tex]E_s = \frac{[8.0*10^{-6} [ 70 - \sqrt{300 * 3}}{2 *(8.0*10^{-6})}[/tex]

=>      [tex]E_s = 0.0064 \ J[/tex]

The energy that has been stored in the capacitor will be 0.0064 J. The stored energy is utilized in the different electrical works.

A capacitor is a device that can store electrical energy. It is a two-conductor configuration separated by an insulating medium that carries charges of equal size and opposite sign.

An electric insulator or vacuum, such as glass, paper, air, or a semi-conductor termed a dielectric, can be used as the non-conductive zone.

The given data in the problem is;

C is the capacitance = 8.00-μF = 8.00 ×10 ⁻⁶

R is the resistance =  3.00-Ω

E is  the emf  = 70.0 V

P is the power  = 300 W

The total emf is the sum of the emf due to the capacitor and emf due to the resistor;

[tex]\rm E_t = E_C + E_R[/tex]

The emf generated by the capacitor is;

[tex]\rm E_C = \frac{q}{C}[/tex]

[tex]\RM E_R = \sqrt{PR}[/tex]

[tex]\rm E_t = \frac{q}{C} + \sqrt{PR} \\\\ \rm q= C [ E_t-\sqrt{PR} ]\\\\[/tex]

Generally, the energy stored in the capacitor is;

[tex]\rm E_S= \frac{q^2}{2C} \\\\ \rm E_S= \frac{\rm C [ E_t-\sqrt{PR} ]\\\\^2}{2C} \\\\ \rm E_S= \frac{\rm 8.0 \times 10^{-6}[ 70-\sqrt{300\times 3} ]\\\\^2}{2 \times (8.0 \times 10^{-6}} \\\\ \rm E_S= 0.0064 \ J[/tex]

Hence the energy that has been stored in the capacitor will be 0.0064 J.

To learn more about the capacitor refer to the link;

https://brainly.com/question/14048432

This question is incomplete, the complete question is;

A 8.45μC particle with a mass of 6.15 x 10⁻⁵ kg moves perpendicular to a 0.493-T magnetic field in a circular path of radius 34.1 m.

How much time will it take for the particle to complete one orbit?

a. 92.7 s

b. 0.0927 s

c. 9.27 s

d. 927 s

Answer:

it will take 92.7 seconds for the particle to complete one orbit.

Option a) 92.7 s is the correct option

Explanation:

Given that;

mass m =  6.15 x 10⁻⁵ kg

q = 8.45μC = 8.45 × 10⁻⁶ C

B = 0.493

we know that

Time period T = 2πr / V

where r = mv/qB

so T = 2πm/qB

we substitute

T = (2 × 3.14 × 6.15 x 10⁻⁵) / ( 8.45 × 10⁻⁶ × 0.493)

T = 0.0003862 / 0.000004165

T = 92.7 sec

Therefore it will take 92.7 seconds for the particle to complete one orbit.

Option a) 92.7 s is the correct option

Answer:

D. [tex]\vec F_{B} = -20\,\hat{i}-15\,\hat{j}\,\,\,[N][/tex]

Explanation:

The statement is not correctly written, the correct form is now described:

A particle with charge [tex]q = -1\,C[/tex] is moving in the positive z-direction at 5 meters per second. The magnetic field at its position is [tex]\vec B = 3\,\hat{i}-4\,\hat{j}\,\,\,[T][/tex]. What is the magnetic force on the particle?

From classic theory on Magnetism, we remember that the magnetic force  exerted on a particle ([tex]\vec F_{B}[/tex]), measured in newtons, is determined by the following vectorial formula:

[tex]\vec F_{B} = q\cdot \vec v \,\times \,\vec B[/tex] (1)

Where:

[tex]q[/tex] - Electric charge, measured in coulombs.

[tex]\vec v[/tex] - Velocity of the particle, measured in meters per second.

[tex]\vec B[/tex] - Magnetic field, measured in teslas.

If we know that [tex]q = -1\,C[/tex], [tex]\vec v = 5\,\hat{k}\,\,\,\left[\frac{m}{s} \right][/tex] and [tex]\vec B = 3\,\hat{i}-4\,\hat{j}\,\,\,[T][/tex], then the magnetic force on the particle is:

[tex]\vec F_{B} = \left|\begin{array}{ccc}\hat{i}&\hat{j}&\hat{k}\\0\,\frac{C\cdot m}{s}&0\,\frac{C\cdot m}{s} &(-1\,C)\cdot (5\,\frac{m}{s} ) \\3\,T&-4\,T&0\,T\end{array}\right|[/tex]

[tex]\vec F_{B} = -(-4\,T)\cdot (-1\,C)\cdot \left(5\,\frac{m}{s} \right)\,\hat{i}+(-1\,C)\cdot\left(5\,\frac{m}{s} \right)\cdot (3\,T)\,\hat{j}[/tex]

[tex]\vec F_{B} = -20\,\hat{i}-15\,\hat{j}\,\,\,[N][/tex]

Which corresponds to option D.

Answer:

17. NADH has a molar extinction coefficient of 6200 M2 cm at 340 nm. Calculate the molar concentration of NADH required to obtain an absorbance of 0.1 at 340 nm in a 1-cm path length cuvette. 18. A sample with a path length of 1 cm absorbs 99.0% of the incident light at a wavelength of 274 nm, measured with respect to an appropriate solvent blank. Tyrosine is known to be the only chromophore present in the sample that has significant absorption at 274 nm. Calculate the molar concentration of tyrosine in the sample.

Explanation:

Explanation:

yooooooooo

Answer:

Energy, in physics, the capacity for doing work. It may exist in potential, kinetic, thermal, electrical, chemical, nuclear, or other various forms. There are, moreover, heat and work—i.e., energy in the process of transfer from one body to another.

Explanation:

Hope this helps!

Answer:

If the starting height of a sloped racetrack is increased, then the speed at which a toy car travels along the track will increase because the toy car will have a greater acceleration.

Explanation:

I hope this helped

Hypothesis: If the starting height of a sloped racetrack is increased, then the speed at which a toy car travels along the track will increase because the toy car gains more potential energy at the higher starting point.

When a toy car moves along a sloped racetrack, it converts its potential energy (due to its height above the ground) into kinetic energy (energy of motion). The higher the starting height of the racetrack, the more potential energy the toy car possesses initially.

As the toy car moves down the sloped track, it will accelerate due to the force of gravity. The potential energy is converted into kinetic energy, and the car's speed increases. According to the law of conservation of energy, the total mechanical energy (sum of potential and kinetic energy) remains constant as long as no external forces, such as friction, act on the car.

Therefore, if the starting height of the racetrack is increased, the toy car will have more potential energy to start with. As it moves down the track, it will convert this increased potential energy into kinetic energy, resulting in a higher speed compared to when it starts from a lower height.

To know more about speed here

https://brainly.com/question/17661499

#SPJ2

Answer:

500 g

Explanation:

m = Mass of water

c = Specific heat of water = [tex]1\ \text{cal/g}^{\circ}\text{C}[/tex]

[tex]\Delta T[/tex] = Temperature difference = [tex]100-20=80^{\circ}\text{C}[/tex]

Q = Heat added = 40000 cal

Heat is given by

[tex]Q=mc\Delta T\\\Rightarrow m=\dfrac{Q}{c\Delta T}\\\Rightarrow m=\dfrac{40000}{1\times 80}\\\Rightarrow m=500\ \text{g}[/tex]

The mass of water is 500 g.

Answer:

A) r = 0.03 m

B) r = 0.0533 m

C) B_max = 0.00003 T

Explanation:

Formula for magnetic field inside the capacitor when it is parallel to the length element is;

B_in = (μ_o•I•r/(2πR²)

Formula for maximum magnetic field is;

B_max = (μ_o•I/(2πR)

Formula for magnetic field outside the capacitor is; B_out = (μ_o•I/(2πr)

A) Magnetic field inside the capacitor is gotten from our first equation above;

B_in = (μ_o•I•r/R²)

Since we want to find the radius at which the magnitude of the induced magnetic field equal to 75% or 0.75 of its maximum value.

Thus;

B_in = 0.75B_max

(μ_o•I•r/(2πR²) = 0.75((μ_o•I/(2πR))

μ_o•I and 2πR will cancel out to give;

r/R = 0.75

r = 0.75R

We are given R = 40 mm = 0.04 m

r = 0.75 × 0.04

r = 0.03 m

B) magnetic field outside the capacitor is; B_out = (μ_o•I/(2πr)

Thus for the magnitude of the induced magnetic field equal to 75% or 0.75 of its maximum value:

B_out = 0.75B_max

(μ_o•I/(2πr) = 0.75((μ_o•I/(2πR))

μ_o•I and 2π will cancel out to give;

1/r = 0.75/R

r = R/0.75

r = 0.04/0.75

r = 0.0533 m

C) B_max = μ_o•I/(2πR)

μ_o is a constant known as vacuum of permeability with a value of 4π × 10^(-7) T.m/A

Thus;

B_max = (4π × 10^(-7) × 6)/(2π × 0.04)

B_max = 0.00003 T

The question is incomplete,I will complete the question and provide the answer.

Due to the nature of the question,I will sketch an answer/solution to the question and submit it as an attachment.

So you will be having two attachments,

1) The question

2) The solution

From the options given in the first attachment with is the question,the correct answer is option C.

1 AND 2 ARE GOING UP.

Proper explanation using sketch and arrows is given in the second attachment which shows the solution to the question.

Answer:

its a

Explanation:

Answer:no sure sorry

Explanation:

Answer:

The person is on the Moon having a weight of 500 N. The acceleration of gravity on the Moon is approximately 1.6 m/s2. What is your his, which includes his space suit?

f= Force (of gravity)=500N

g=acceleration of gravity=1.6m/s^2

m=mass=312kg

m=f/a= 500N/1.6 m/s^2 = 500 (kg-m/1.6m/s^2) = 500/1.6kg = 312kg

his mass is 312kg

Answer:

D

Explanation: