A toy car accelerates uniformly from rest at a constant rate. The car travels 1.0 meters in 1.0 seconds. The acceleration of the car is ________ meters per second squared.

Answer:

he two people agree with your answer

  v_B = v_{oB} - a t

              v_A = cte

Explanation:

To analyze if they are both in Kurdish, let's see the movement of the two cars

at t = 1s

the velocity of carriage B is greater than the speed of carriage a

             v_B> v_A

at t = 2 s

the speed of the two cars is nipple

              v_B = v_A

For this to be true, the speed of car B must be decreasing

              v_B = v_{oB} - a t

              v_A = cte

therefore the two people agree with your answer

Answer:

yes

Explanation:

becausw yesnssjsdkwww

Answer:

i think its ancestor

Explanation:

sry if im wrong

Answer:

scientists compare organisms DNA to support the theory that all species share a common Ancestor.

Answer:

Explanation:

The enclosure will behave as black body . For black body , the formula for radiant energy is given by Stefan's law as follows

E = σ A T⁴ where σ = 5.67 x 10⁻⁸ W m⁻² T⁻⁴

Area A = .01 m²

E = 48 W

48 = .01 x 5.67 x 10⁻⁸ T⁴

T⁴ =  846.56 x 10⁸

T= 539 K

Following are the calculation to the temperature of the interior enclosure wall:

Given:

[tex]\to A_s=50\ m^2\\\\\to A_0=0.01\ m^2\\\\\to q_{rad}=48\ w\\\\\to \sigma = 5.67 \times 10^{-8}\ \frac{W}{m^{-2} T^{-4}} \\\\[/tex]

To find:

[tex]T_s=?[/tex]

Solution:

Using the value to calculate the surface is black radiates power:

[tex]\to q_{rad}=A_0 E_0 T_s\\\\\to q_{rad}=A_0 \sigma T_{s}^4\\\\\to 48=0.01 \times 5.67 \times 10^{-8} \times T_{s}^4\\\\[/tex]

[tex]\to T_{s}^4 =\frac{48}{0.01 \times 5.67 \times 10^{-8}} \\\\[/tex]

        [tex]=\frac{48\times 100}{ 5.67 \times 10^{-8}} \\\\=\frac{48\times 100\times 10^{8} }{ 5.67 } \\\\=\frac{48\times 10^{10} }{ 5.67 } \\\\=8.46\times 10^{10} \\\\[/tex]

[tex]\to \bold{T_s=\pm 539.31 \ K}[/tex]

Therefore the final answer is "[tex]\bold{\pm 539.31 \ K}[/tex]".

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Answer:

Electric and gravitational forces have many similar features because they follow idenitical mathematical formulas. In particular, Charge in electricity plays the equivalent role of mass in gravity, while electric field, plays a role corresponding to free-fall acceleration. Because of this kinematics describing projectiles in gravity would carry over to electricity, but the main difference is that in electricity we have positive and negative charges, while in gravity mass is always positive, which means gravity is always attractive, but electricity could be attractive and repulsive.

Explanation:

The formulas of Electric and gravitational fields are as follow

Electric Field

F(electric)=kq1q2/r^2

Gravitationlal Fieeld

F(grav)=GMm/r^2

As you see both follow the inverse square law in the formula

Both of these act between two bodies without having any contact. The gravitational field acts on the mass of an object Whereas the electric field acts on the charge.

The gravitational field can only attractive while the electric field can be attractive or repulsive.

Normally electric field is stronger than the gravitational field.

In particular, Charge in electricity plays the equivalent role of mass in gravity, while electric field,

Newton's law of gravity states that each particle having mass in the universe attracts each other particle with a force known as the gravitational force.

Gravitational force is proportional to the product of the masses of the two bodies and inversely proportional to the square of their distance.

Electric and gravitational forces have many similar features because they follow identical mathematical formulas.

In particular, Charge in electricity plays the equivalent role of mass in gravity, while electric field,

Plays a role corresponding to free-fall acceleration. Because of these kinematics describing projectiles in gravity would carry over to electricity,

but the main difference is that in electricity we have positive and negative charges, while in gravity mass is always positive,

which means gravity is always attractive, but electricity could be attractive and repulsive.

Hence, in particular, Charge in electricity plays the equivalent role of mass in gravity, while electric field,

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Answer:

Δr = 0.425 m

Explanation:

This is a sound interference exercise, the expression for destructive interference is

          Δr = (2n + 1) λ / 2

in this case the movement is in the same direction as the sound, therefore the movement is one-dimensional

let's use the relationship between the speed of sound and its frequency and wavelength

          v = λ f

          λ = v / f

the first minium occurs for n = 0

           Δr = λ / 2

            Δr = v / 2f

            Δr = [tex]\frac{340}{2 \ 400}[/tex]

             Δr = 0.425 m

this is the distance from the current position that we assume in the center of the room

Answer:

a) V = 0.24 m/s

b) v = 1.53 m/s

Explanation:

In this case, we are asked to find two values that are pretty similar and use the same units, however, there are differences between them.

The average velocity is often referred to a vector quantity, therefore, if time is a scalar magnitude, we need to find the vector quantity of distance. In this case, is the displacement, which is also referred as a vector.

So, to calculate the average velocity we need to determine first the displacement of the person. As the person heads east and then west, his total displacement (D) is:

D = 55 - 40 = 15 m

Now the total time would be the time taken to go to the windmill and then, to a bench:

t = 25 + 37 = 62 s

Finally, the average speed is:

V = D/t

V = 15 / 62

The average speed is a scalar magnitude, so we use the covered distance by the person (d) and the total time:

d = 40 + 55 = 95 m

Then, the speed:

v = 95/62

Hope this helps

Answer:

Scalar

Explanation:

A scalar quantity is a physical quantity that has magnitude but no directional attribute.

An example of a scalar is speed and distance.

A vector is a physical quantity that has both magnitude and direction.

An example is displacement and velocity.

Scalar has only the magnitude value specified and nothing else.

Answer:

While working as a staff physicist at hughes Research Laboratories McNair learned that the National Aeronautics and Space Administration (NASA) was looking for scientist to join the shuttle program;)

Correct temperature is 80°F

Answer:

T_f = 38.83°F

Explanation:

We are given;

Volume; V = 8 ft³

Initial Pressure; P_i = 100 lbf/in² = 100 × 12² lbf/ft²

Initial temperature; T_i = 80°F = 539.67 °R

Time for outlet flow; t_o = 90 s

Mass flow rate at outlet; m'_o = 0.03 lb/s

Final pressure; P_f = 30 lbf/in² = 30 × 12² lbf/ft²

Now, from ideal gas equation,

Pv = RT

Where v is initial specific volume

R is ideal gas constant = 53.33 ft.lbf/°R

Thus;

v = RT/P

v_i = 53.33 × 539.67/(100 × 12²)

v_i = 2 ft³/lb

Formula for initial mass is;

m_i = V/v_i

m_i = 8/2

m_i = 4 lb

Now change in mass is given as;

Δm = m'_o × t_o

Δm = 0.03 × 90

Δm = 2.7 lb

Now,

m_f = m_i - Δm

Thus; m_f = 4 - 2.7

m_f = 1.3 lb

Similarly in above;

v_f = V/m_f

v_f = 8/1.3

v_f = 6.154 ft³/lb

Again;

Pv = RT

Thus;

T_f = P_f•v_f/R

T_f = (30 × 12² × 6.154)/53.33

T_f = 498.5°R

Converting to °F gives;

T_f = 38.83°F

The final temperature, in °F, of the air remaining in the tank is 38.83°F

It is given that volume V = 8 ft³

Initial Pressure Pi = 100 lbf/in² = 100 × 12² lbf/ft²

Initial temperature Ti = 80°F = 539.67 °R

Time for outlet flow; to = 90 s

Mass flow rate at outlet; m'o = 0.03 lb/s

Final pressure; Pf = 30 lbf/in² = 30 × 12² lbf/ft²

Now, from ideal gas equation,

Pv = RT

where v is initial volume, R is ideal gas constant = 53.33 ft.lbf/°R

[tex]v = RT/P\\ \\ v_i = 53.33 *539.67/(100*12^2)\\ \\ v_i = 2 ft^3/lb [/tex]

The initial mass is;

[tex]m_i = V/v_i\\ \\ m_i = 8/2\\ \\ m_i = 4 lb [/tex]

Now change in mass is given as;

Δm = [tex]m'_o*t_o[/tex]

Δm = 0.03 × 90

Δm = 2.7 lb

[tex]m_f[/tex] = [tex]m_i[/tex] - Δm

[tex]m_f[/tex] = 4 - 2.7

[tex]m_f[/tex] = 1.3 lb

now,

[tex]v_f = V/m_f\\ \\ v_f = 8/1.3\\ \\ v_f = 6.154 f^3/lb [/tex]

From the gas equation

Pv = RT

Final state:

[tex]T_f = P_fv_f/R\\\\ T_f = (30*12^2*6.154)/53.33\\\\ T_f = 498.5^oR [/tex]

Converting to °F:

[tex]T_f[/tex] = 38.83°F is the final temperature.

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Answer:

convection currents

Explanation:

Answer:

E_total = 26.97 N/C

Electric field points towards the positive charge

Explanation:

We are given;

Charge 1; q1 = 6 nC = 6 × 10^(-9) C

Charge 2; q2 = 3 nC = 3 × 10^(-9) C

Distance between both charges; R_o = 2 m

Since we want to find electric field midway, the distance midway is r = 2/2 = 1 m

Using coulumbs law;

E = kq/r²

Where k is a constant with a value of 8.99 × 10^(9) N.m/C²

Thus;

E1 = kq1/r²

E1 = (8.99 × 10^(9) × 6 × 10^(-9))/1²

E1 = 53.94 N/C

Similarly;

E2 = kq2/r²

E2 = (8.99 × 10^(9) × 3 × 10^(-9))/1²

E2 = 26.97 N/C

Since both electric fields are positive, it means that they are both moving towards the midpoint of the distance between both charges.

This implies they will have opposite directions.

Thus, total electric field at the midway point is;

E_total = E1 - E2

E_total = 53.94 - 26.97

E_total = 26.97 N/C

Answer:

a horizontal force of 120N to Push the block into the floor is called net force

Answer:

6 kg

Explanation:

F=ma

F is Force(newtons)

m is mass(kg)

a is acceleration(m/s^2)

Plug in the numbers

3000 = m(500)

divide both sides by 500 to cancel out the 500.

3000/500=6

6 = m

6kg is the mass

Answer:

  λ = 440 nm

Explanation:

The phenomenon of constructive interference is described by the expressions

          d sin θ= m λ                    (1)

where d is the separation of the slits d = 0.0250 mm = 2.50 10⁻⁵ m, lam is the wavelength of the incident radiation and m is an integer indicating the order of interference

let's use trigonometry to find the angle

          tan θ = y / L

where L is the distance to the screen L = 1.25 m

in general interference experiments angles are very small

         tan θ = [tex]\frac{sin \ \theta }{cos \ \theta}[/tex]

         ten θ = sin θ

substituting

         sin θ = y / L

we substitute 1

          d y / L = m λ

          λ = [tex]\frac{ d \ y }{m \ L}[/tex]

in the exercise indicate

        m = 3

         y = 6.6 cm = 6.6 10-2 m

we calculate

          λ = 2.50 10⁻⁵ 6.6 10⁻² /( 3   1.25)

          λ = 4.4 10⁻⁷ m

let's reduce to nm

          λ = 4.4 10⁻⁷ m (10⁹ nm / 1 m)

          λ = 440 nm

Answer:

The political actions that led to successful conservation in both stories were what they call an FC company that makes the forest industry true. They make it out of a factory and it can make it very successful and accomplished.

Explanation:

Answer:

the average kinetic energy of the 10 molecules is 10 J.

Explanation:

Given;

energy on one molecule in motion, E = 100 J

number of molecules, n = 10

(A) The average kinetic energy of the 10 molecules

since the remaining 9 molecules are at rest, their kinetic energy = 0

[tex]E_{Avg} = \frac{E_1 + E_9}{10} \\\\E_{Avg} = \frac{100J+ 0}{10} \\\\E_{Avg} = \frac{100J}{10} \\\\E_{Avg} = 10J[/tex]

Therefore, the average kinetic energy of the 10 molecules is 10 J.

Answer:

#1 ( Balanced ) ( Rest)

#2 ( Unbalanced)  ( Accelerating)

Explanation:

Answer:

Lifting your binder out of your backpack into your top row locker.

Pushing a shopping cart down the aisle at Publix

Explanation:

These are the only two in which an object is moving because of an applied force

Answer:

the speed of the mass when it is halfway to the equilibrium position is 1.26 m/s

Explanation:

Given that;

mass of the object m = 1.20 kg

period of oscillation = 0.750 s

Amplitude ( A/x) = 15.0 cm = 0.15 m

now;

a) Determine the oscillation frequency;

oscillation frequency f = 1/T

we substitute

f = 1 / 0.750 s

f = 1.33 Hz

Therefore, the oscillation frequency is 1.33 Hz

b) Determine the spring constant;

we solve for spring constant from the following expression;

T = 2π√(m/k)

k = 4π²m / T²

so we substitute

k = (4π² × 1.20) / (0.750)²

k = 47.3741 / 0.5625

k =  84.22 N/m

Therefore, the spring constant is 84.22 N/m

c) determine the speed of the mass when it is halfway to the equilibrium position

So, at equilibrium, the energy is equal to K.E

such that;

1/2mv² = 1/2kx²

mv² = kx²

v² = kx² / m

v = √( kx²/m)

we substitute

v = √( 84.22×(0.15 m)²/ 1.2 )

v = √( 1.89495 / 1.2 )

v = √ 1.579125

v = 1.26 m/s  

Therefore, the speed of the mass when it is halfway to the equilibrium position is 1.26 m/s

Answer:

Vf = 21 m/s

Explanation:

Data:

Use formula:

Replace:

Multiply the acceleration with time:

Solve the sum:

The velocity of the car at the end of the 3 second interval is 21 meters per second.

Answer:

4363.3231 feets²

Explanation:

Given that :

Distance, r = 50 ft

θ = 200°

The arc length of area covered :

Arc length = θ/360° * πr²

Arc length = (200/360) * 50 ft ^2 * π

Arc length = 0.5555555 * 2500 * π

Arc length = 4363.3231 feets²

Answer:

Explanation:

Distance travelled by Henrietta in 5.5 s = 4.15 x 5.5 = 22.825 m .

Time taken by lunch of bagels to fall vertically by 55.2 m . Let it be t .

s = ut + 1/2 g t²

55.2 = 0 + .5 x 9.8 x t²

t² = 11.26

t = 3.356 s

By the time the lunch of bagels touches the hand of Henrietta , she would have travelled further by distance

s = 3.356 x 4.15 = 13.9 m

She is now at distance of 22.825 + 13.9 = 36.725 m from window .

So lunch of bagels must travel a horizontal distance of 36.725 m in 3.356 s which the time of fall of bagel .

Speed of bagel = distance / time

= 36.725 / 3.356

= 10.94 m /s

b )

Henrietta is 36.725 m from window at the time when she catches the bangel.

Answer:

the work done by friction on the car is 524,582 J.

Explanation:

Given;

mass of the roller coaster, m = 800 kg

distance moved by the coaster, d = 225 ft = 68.58 m

final velocity of the coaster, v = 80 mi/h = 35.76 m/s

The time taken for the coaster to drop down the hill is calculated as;

[tex]t = \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2\ \times \ 68.58}{9.8} } \\\\t = 3.74 \ s[/tex]

The work done by friction on the car is calculated as;

[tex]W =F\ \times \ d = \frac{mv}{t} \times \ d\\\\W = \frac{800 \ \times \ 35.76 }{3.74} \times \ 68.58\\\\W = 524,582 \ J[/tex]

Therefore, the work done by friction on the car is 524,582 J.

Answer:

12 kg

Explanation:

q = 52,800 J

c = 880 J/(kg * K) Pretty sure you missed the kg here

ΔT = 5 °C = 5 K (reminder that this only applies to ΔT and not T)

q = mcΔT ⇒ m = q/(cΔT) = 52,800 J / (880 J/(kg * K) * 5 K) = 12 kg

The mass of a block concrete that gains 52,800 joules of energy when its temperature is increased by 5 degrees Celsius specific heat of concrete 880 J/K degrees Celsius is 12kg

The formula for calculating the quantity of heat energy absorbed by the block is expressed as:

Q = mcΔt

Q is the quantity of heat = 52,800 Joules

m is the mass of the concrete

c is the  specific heat of concrete = 880 J/K

Δt is the change in temperature = 5 degrees

substitute the given values into the formula:

[tex]52800=m(880)(5)\\52800 = 4400m\\m=\frac{52800}{4400}\\m= 12kg[/tex]

Hence the mass of a block of concrete that gains 52,800 joules of energy when its temperature is increased by 5 degrees Celsius specific heat of concrete 880 J/K degrees Celsius is 12kg

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