A train travelling at 22m/s accelerates uniformly at 0.85 m/s^2 for 25s. Calculate the distance travelled by the train at this time.

Answer:in this situation we have during the two tiny spheres of masks, 5.8 mg carry Charges of equal magnitude 30 77 Nano column but opposite in sign They are tied to the same ceiling hook by light in spring of 2.53 m. It is known that when they original uniform electric village applied that is directed to the left. The angle between the springs is 58°. Then we have to find the value of E. So given that the mass M is 5.8 mg, that is 5.8 into 10 to the power -3 g. And This is five and we have the charge that is Q. Is 77 and a column. So this is 77 into 10 to the power -9 columns. The length of the string is 0.53 m. And the angle between the spring.

Answer:  The difference is in how the carrier wave is modulated, or altered

Explanation:

With AM radio, the amplitude, or overall strength, of the signal is varied to incorporate the sound information. With FM, the frequency (the number of times each second that the current changes direction) of the carrier signal is varied

couldnt read that so gave my input hope it helps or is closly related to one of the answers

Answer: C. FM radio waves carry more energy than AM radio waves. This is supported by the fact that FM radio waves have a shorter wavelength compared to AM radio waves.

Explanation:

The time spent in air by the ball is 2.04 seconds.

The maximum height reached by the ball is 20.41 m.

The time of motion of the ball is calculated as follows;

v = u - gt

where;

0 = u - gt

gt = u

t = u/g

given;

t = (20) / 9.8

t = 2.04 s

The maximum height reached by the ball is calculated as follows;

v² = u² - 2gh

0 = u² - 2gh

2gh = u²

h = u²/2g

h = (20²) / (2 x 9.8)

h = 20.41 m

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Answer:

Charging a phone is the exact opposite of discharging a battery's energy. By supplying current (the manipulated variable), a charger transfers lithium ions from the positive electrode to the negative electrode, thus restoring energy

Explanation:

The magnitude of the resulting forces applied to the nails if they are located at A and B is 64.44 N, at B and C is 120.83 N and at A and C is 56.86 N.

We know that,

C = F d

where,

C = Couple

F = Magnitude of resulting forces

d = Distance between two points

Given that,

C = 29 N m

[tex]d_{AB}[/tex] = 450 mm = 0.45 m

[tex]d_{BC}[/tex] = 240 mm = 0.24 m

F = C / d

The magnitude of the resulting forces applied to the nails if they are located at A and B is

F = 29 / [tex]d_{AB}[/tex] = 29 / 0.45

F = 64.44 N

The magnitude of the resulting forces applied to the nails if they are located at B and C is

F = 29 / [tex]d_{BC}[/tex]  = 29 / 0.24

F = 120.83 N

The magnitude of the resulting forces applied to the nails if they are located at A and C is

F = 29 / [tex]d_{AC}[/tex]  

[tex]d_{BC}[/tex]  = √ ( [tex]d_{AB}[/tex] )² + ( [tex]d_{BC}[/tex] )²

[tex]d_{BC}[/tex]  = √ ( 0.45² + 0.24² )

[tex]d_{BC}[/tex]  = 0.51 m

F = 29 / 0.51

F = 56.86 N

A Couple is two parallel forces of equal magnitude acting in opposite direction.

Therefore, the magnitude of the resulting forces applied to the nails if they are located at

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Answer:

120 m

Explanation:

4 m/s  * 30 s  = 120 m

Answer:

the answer to this question is false because a airplane wouldve survive in space

The maximum height reached by the bullet is 12,500 m.

The velocity of the of the bullet at 10s is 600 m/s.

The velocity of the of the bullet at 20s is 700 m/s.

The velocity of the of the bullet at 60s is 1,700 m/s.

The time required for the object to move to maximum height is 50.5 seconds.

The height reacted by the bullet at time, t = 20 seconds is 12,000 m.

The height risen by the bullet when the first velocity is 40 m/s is 80 m.

The maximum height reached by the bullet is calculated as follows;

v² = u² - 2gh

v² = 2gh

h = v² /2g

h = (500²)/(2 x 10)

h = 12,500 m

v = u + at

when t = 10 s

v = 500 m/s  +  10(10)

v = 600 m/s

when the time, t = 20 seconds

v = 500 + 20(10)

v = 700 m/s

when the time, t = 60 s

v = 500 + 20(60)

v = 1,700 m/s

t = √(2h/g)

t = √(2 x 12,500 / 9.8)

t = 50.5 seconds

h = ut + ¹/₂gt²

h = (500 x 20)  +  ¹/₂(10)(20²)

h = 12,000 m

h = v² /2g

h = (40²)/(2 x 10)

h = 80 m

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By calculating, a) frequency = 100 Hz b)wavelength = 4 cm  C )Speed = 400 cm/s d) Amplitude =  2 cm e)period = 0.01 s f)wave number  = 0.5π  g)angular velocity = 200π. ​

Given in question

Y = 2 sin π (0.5x - 200t)

Y = 2 sin (0.5πx - 200πt)

Comparing it with the standard form of a wave equation:

Y = Asin (kx - ωt) where

A= amplitude

K = wave number = 2π/λ where λ = wavelength

ω = Angular velocity = 2πf where f = frequency

We get

a) 2πf = 200π

    f = 100 Hz

b) 2π/λ =0.5π

   λ = 2π/0.5π

   λ = 4 cm

c) Speed v = ω/k

v = 200π/0.5π

v = 400 cm/s

d) A= amplitude = 2 cm

e)  period = 1/f = 0.01 s

f) K = wave number = 0.5π

g) ω = Angular velocity = 200π

Therefore, by comparing  a) frequency = 100 Hz b)wavelength = 4 cm  C )Speed = 400 cm/s d) Amplitude =  2 cm e)period = 0.01 s f)wave number  = 0.5π  g)angular velocity = 200π. ​

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The circuit directory shows the load/area in a vocabulary that would be clear for "nonelectrical" people to decipher and determine the circuit number for luminaires, receptacles, appliances, or tools.

True stress is the spread load divided by the actual cross-sectional scope of material. Engineering strain is the applied load separated by the original cross-sectional area of material. Also known as nominal stress.

As expected by the units, stress is assigned by dividing the force by the location of its generation, and since this area (“A”) is either sectional or axial, the basic stress formula is “σ = F/A”.

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Copper sulfate is a salt that is made up of the copper ion and the sulfate ion further, the sulfate ion is the combination of the sulfur and the oxygen atom.

The chemical compound is a combination of two or more  either similar or dissimilar chemical elements

As given in the problem we have to compare copper sulfate with the elements that form copper sulfate,

The salt copper sulfate is composed of the copper ion and the sulfate ion. In addition, the sulfate ion is a mixture of sulfur and oxygen atoms.

The chemical formula for the copper sulfate is CuSO₄ which is made up of a Copper (Cu) atom, Sulphur (S)  atom, and Oxygen (O) atom.

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According to the research, the correct option is weak interaction. A type of fundamental force is weak interaction.

They are those that cannot be explained based on other more basic ones, where the particles interact by virtue of some characteristic that they possess and according to physics, four fundamental forces are recognized at the quantum level:

In this sense, weak interaction is manifested in the transmission of particles where neutrinos and antineutrinos are emitted, without electrical charge and whose mass is very small or even zero, as in the case of the photon.

Therefore, we can conclude that according to the research, the correct option is weak interaction. A type of fundamental force is weak interaction.

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The eccentricity of Venus is = 0.0068. That is option C.

The orbital eccentricity is defined as the measurement that is used to show how an orbit deviates from the shape of a circle.

The Venus is one of the planets of the universe that is the second closest to the sun.

The Venus is one of the planets that has a small orbital eccentricity being 0.006772 which is approximately 0.0068. This means that it is closest to being circular in shape.

The planets with the largest orbital eccentricity is the planet Mercury with orbital eccentricity of 0.2056.

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By using uniform motion, the high up the slope will it strike is 730.62 m.

We need to know about uniform motion to solve this problem. The uniform motion is an object's motion under acceleration. It should follow the rule

vt = vo + a . t

vt² = vo² + 2a . s

s = vo . t + 1/2 . a . t²

where vt is final velocity, vo is initial velocity, a is acceleration, t is time and s is displacement.

From the question above, we know that

θ = 70⁰

vi = 200 m/s

x = 300 m

Find the initial velocity in x and y axis

vx = vi cosθ = 68.40 m/s

vy = vi sinθ = 187.94 m/s

Find the time taken to reach 300 m

vx = x / t

68.4 = 300 / t

t = 4.39 second

Find the time taken to reach maximum height

vt = vo + a . t

0 = vy - g . t

vy = gt

187.94 = 9.8 . t

t = 19.18 second

The motion of projectile is raising to maximum height, hence

s = vo . t + 1/2 . a . t²

h = vy . t - 1/2 . g . t²

h = 187.94 . 4.39 - 1/2 . 9.8 . 4.39²

h = 730.62 m

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Answer:

146.4 s

Explanation:

Distance / rate = time

205 m / 1.4 m/s =  146.4 s

The true statement about the equation of respiration is:

The mass of the reactants is the same as the mass of the products; option C.

Respiration is the process by which living organisms break down large molecules such as glucose into smaller molecules such a carbon dioxide and water to release energy in the form of ATP.

Respiration are of two types in living organisms:

The equation of aerobic respiration is given below:

In the given equation above, glucose reacts i the presence of oxygen is broken down into carbon dioxide and water and energy is released.

According to the law of conservation of mass, the mass of reactants is equal to the mass of the products.

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Note that the complete question is given below:

Respiration describes the process that living cells use to release energy by combining sugar and oxygen. The primary chemical changes that happen during respiration are shown in the equation below.

C₆H₁₂O₆ + 6 O₂ → 6 CO₂ + 6 H₂O + energy

Which statement correctly compares the reactants and products of the equation?

Which statement correctly compares the reactants and products of the equation?

A.

The mass of the reactants is less than the mass of the products.

B.

The mass of the reactants is greater than the mass of the products.

C.

The mass of the reactants is the same as the mass of the products.

D.

The number of reactant molecules is greater than the number of products.

The magnitude of the force in newtons needed to supply 100 newton-meters of torque to the bolt is   359N.

The amount that encapsulates the force's power is known as its magnitude. Consider the following scenario: the force is 10 N in the east. The direction is indicated by "towards east," while the force is indicated by "10." Magnitude may be thought of as simply the "value" or "amount" of any physical quantity.

The force applied that applies torque is:

Fz = 100 N-m / .3m = 333.33 N

Find the angle:

theta = tan^-1 ( 5/2) = 68.19 degrees

Total force:

F= 333.33 / sin(68.19) = 359N

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Bob and Carol are both observing the moon at exactly the same time. However, bob is in Miami and carol is in Los Angeles. Bob observes the moon in the first quarter phase. Carl will also observe the moon in the first quarter phase.

The moon cycle consists of four primary and secondary phases.

The four primary phases are New Moon, First Quarter Phase , Full Moon, and the Last Quarter.

During the new moon and full moon periods, there are definite chances of solar and lunar eclipses.

The secondary phases of the moon are waxing crescent, waxing gibbous, waning gibbous, and waning crescent.

In the southern hemisphere and northern hemisphere, people observe the same phases of the moon.

As Miami and Los Angeles are in the southern hemisphere i.e. south of the equator, therefore, people living in that hemisphere will observe the moon in the same phases.  Thus Bob and Carol will also observe the moon in the first quarter phase from different cities.

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A pebble off a cliff to hit the ground below t = 0.128 sec.

Given,

distance = 18m

velocity = 2.3m /s

time = ?

To find the time in given data,

Use formula,

velocity = distance / time

Putting the value in formula,

We get,

2.3 m/s = 18 m / t

t = 2.3 m/s / 18 m

t = 0.128 sec

The vector quantity velocity (v), denoted by the equation v = s/t, measures displacement (or change in position, s), over change in time (t). Speed (or rate, r) is a scalar quantity, denoted by the equation r = d/t, that measures the distance traveled (d) over the change in time (t).

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Answer:

[tex]\boldsymbol {\boxed{v = 12 \ \dfrac{\text{ km}}{\text{hr}} }}[/tex]

Explanation:

Data:

t = 2 hr

S = 12 km

Find:

[tex]v \ - \ ?[/tex]

-----------------------------------

Solution:

[tex]\boldsymbol {\boxed{v = \dfrac{S}{t} }}[/tex]

Calculations:

[tex]\boldsymbol v =[/tex] 12 km / 2 hr = 6 km/hr.

Answer: [tex]v =[/tex] 6 km/hr.

The distance travelled by the airplane before takeoff is 1721 m.

2. The acceleration of the race car is 11.2 m/s², and Distance travelled by the car is 79.9 m.

3. The acceleration of the bullet is 1.62 * 10⁵ m/s².

The distance travelled by the airplane before takeoff is determined using the formula:

s = ut + ¹/₂at²

u = 0; a = 3.20 m/s², t = 32.8 s

s = 0 * 32.0 +  ¹/₂ * 3.2 * 32.8²

s = 1721 m

2. The acceleration of the race car is calculated as follows:

a = (v - u)/t

v = 46.1 m/s, u = 18.5 m/s, t = 2.47 s

a = (46.1 - 18.5)/2.47

a = 11.2 m/s²

Distance travelled, s = 18.5 * 2.47 + ¹/₂ * 11.2 * 2.47²

s = 79.9 m

3. The acceleration of the bullet is calculated as follows:

a = (v² - u²)/2s

where v = 0 m/s, u = 521 m/s, s = 0.840 m

a = (0² - 521²)/2 * 0.840

a = 161572.0238

a = 1.62 * 10⁵ m/s²

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For a 0.7500 cm diameter plastic sphere, used in a static electricity demonstration, the potential near its surface is 144V.

V= kq/r = 9 x [tex]10^{9}[/tex] [tex]\frac{6*10^{-11}}{0.00375}[/tex]

=144 V

The magnitude of the potential point per unit charge is the electric potential at a specific point. However, the following definition is far more accurate: The amount of work required to move a unit positive charge from infinity to a certain place is known as the electric potential at that location.

Potential is characterized as a thing’s potential to materialize. The greatest grades to which a specific student is capable are an illustration of potential.

The external effort required to move a charge in an electric field from one position to another is known as an electric potential difference, or voltage.

The difference in potential energy experienced by an object is known as its electric potential.

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Answer:

It is not possible to change direction twice, given constant acceleration. To convince yourself, imagine any general v−t graph - it would be straight line in case of constant acceleration. Change in direction corresponds to v going from positive to negative or vice versa.Explanation:

Answer:It is not possible to change direction twice, given constant acceleration. 

Explanation:To convince yourself, imagine any general v−t graph - it would be straight line in case of constant acceleration. Change in direction corresponds to v going from positive to negative or vice versa.

If it takes 4.6 seconds for an object to fall a certain distance from rest on earth, then it would take 10.29 seconds to fall the same distance on planet X.

There are three equations of motion given by  Newton,

v = u + at

S = ut + 1/2×a×t²

v² - u² = 2×a×s

Keep in mind that these calculations only apply to uniform acceleration.

As given in the problem, The acceleration due to gravity on planet X is one-fifth that on the surface of the earth. If it takes 4.6 s for an object to fall a certain distance from rest on earth, then we have to find how long would it take to fall the same distance on planet X,

By using the second equation of motion given by newton,

Let us suppose the acceleration due to gravity on the earth is 10 m / s²

S = ut + 1/2at²

  = 0 + 0.5×10×4.6²

  = 105.8 meters

The acceleration due to gravity on planet X = 2 meters / second

S = ut + 1/2at²

105.8 = 0 + 0.5×2×t²

t² = 105.8

t = 10.29 seconds

Thus, it would take 10.29 seconds to fall the same distance on planet X

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Change in the starting time of the robots for the race will allow the slower robot to win the race.

Robots are any autonomously run machines that eliminate the need for human labour, even if they may not look like humans or carry out tasks in a way that is humanlike. Robotics, then, is the branch of engineering that deals with the creation, maintenance, and use of robots.

Although the idea of synthetic people predates written history, the term "robot" is derived from the Czech word "robota," which means "forced labour" or "serf," and was used in Karel apek's play R.U.R. (1920).

Runaround, a work of science fiction by Isaac Asimov, introduced the word robotics (1942). It established a new level of plausibility regarding the possible difficulty of creating sentient robots and the potential technological and societal issues that might arise, along with Asimov's other robot stories.

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The car travels a distance of 820m in the first 34s after the light changes to green.

Acceleration, a = 2ms⁻²

Initial velocity, u = 0 ms⁻¹ (Since the car start from rest)

Final velocity, v = 20 ms⁻¹

From first equation of motion,

v - u = at

20 - 0 = 2 × t

20 = 2t

t = 10s

From second equation of motion,

S = ut + ¹/₂ at²

Distance travelled during 10s:

S₁ = 0 × 10 + ¹/₂ × (10)²

S₁ = 100m

Distance travelled for the remaining 36s:

S₂ = v × t

S₂ = 20 × 36

S₂ = 720m

Total distance travelled:

S = S₁ + S₂

S = 100 + 720

S = 820m

Therefore, the car travels a distance of 820m in the first 34s after the light changes to green.

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By using uniform motion, the high up the slope will it strike is 730.62 m.

We need to know about uniform motion to solve this problem. The uniform motion is an object's motion under acceleration. It should follow the rule

vt = vo + a . t

vt² = vo² + 2a . s

s = vo . t + 1/2 . a . t²

where vt is final velocity, vo is initial velocity, a is acceleration, t is time and s is displacement.

From the question above, we know that

θ = 70⁰

vi = 200 m/s

x = 300 m

Find the initial velocity in x and y axis

vx = vi cosθ = 68.40 m/s

vy = vi sinθ = 187.94 m/s

Find the time taken to reach 300 m

vx = x / t

68.4 = 300 / t

t = 4.39 second

Find the time taken to reach maximum height

vt = vo + a . t

0 = vy - g . t

vy = gt

187.94 = 9.8 . t

t = 19.18 second

The motion of projectile is raising to maximum height, hence

s = vo . t + 1/2 . a . t²

h = vy . t - 1/2 . g . t²

h = 187.94 . 4.39 - 1/2 . 9.8 . 4.39²

h = 730.62 m

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