By ideal gas approximation, the mass of the helium in the tire is 0.465 grams.
We need to know about the ideal gas theory to solve this problem. The ideal gas is assumed that there is no interaction between particles in a gas. It can be determined by the equation
P . V = n . R . T
where P is pressure, V is volume, n is the number of moles of gas which represents mass, R is the ideal gas constant (0.0821 L.atm/mol.K) and T is temperature.
From the question above, we know that
V = 365 mL = 0.365 L
P = 7.8 atm
T = 25⁰ C = 298 K
Mr = 4
By using the equation of ideal gas, we get the mass
P . V = n . R . T
7.8 . 0.365 = gr / Mr . 0.0821 . 298
7.8 . 0.365 = gr / 4 . 0.0821 . 298
gr = 0.465 grams
Find more on mass at: https://brainly.com/question/25290815
#SPJ4
For each question, select the right answer from the choices below:
a Object A weighs 30 N on Earth. Object B weighs 30 N on the Moon (which
has a gravitational field strength 1/6 the size of Earth's). Which object has the greater mass?
i. A
ii. B
iii. neither of them
iv. depends on air resistance
Option (ii) B is the correct option. The object on the moon has greater mass.
To resolve this, utilize the formulas Force = Mass * Acceleration.
The equation can be used to find the mass given the force in Newtons, using 9.8 m/s² for the acceleration of gravity of the earth and 1.6 m/s² for the moon.
Calculating the mass on earth:
30 N = 9.8 m/s² * mass
This results in a mass of 3.0 kg for the object on Earth.
Calculating the mass of the moon:
30 N = 1.6 m/s²2 * mass
Thus, the moon's object has a mass of 19. kg.
This can be explained by the fact that the earth has a stronger gravitational pull than the moon, producing more force per kilogram of mass. As a result, the moon's mass must be bigger to produce the same amount of force at a lower acceleration from gravity (1.6 m/s² vs. 9.8 m/s²).
To know more about Mass, refer to this link :
https://brainly.com/question/13386792
#SPJ9
REVIEW
1 A train travelled along a
straight track from a particular
stop back to its depot.
This 5.0 km journey took
12 minutes. Calculate the
train's average speed. (Give
your answer in km/h.)
According to given data, the average speed of train is 25 km/h.
Equation :Given data,
distance = 5 km
time = 12 minutes
average speed = ?
changing time from minute to hour
So,
hour = 12 / 60
hour = 0.2
Then to calculate speed use the formula,
s = d / t
s = 5km / 0.2hr
s = 25 km/h
What is speed?Velocity is the rate and direction of an object's movement, whereas speed is the time rate at which an object is moving along a path. In other words, velocity is a vector value, whereas speed is a scalar value. It has a dimension of time-distance. As a result, the basic unit of time and the basic unit of distance are combined to form the SI unit of speed. Thus, the metre per second (m/s) is the SI unit of speed.
To know more about scalar value :
https://brainly.com/question/12660208
#SPJ9
Flying from LA to New York is a 3,944,000 meter trip. What order of magnitude is this measurement?
The order of magnitude of the distance between Los Angeles (LA) to New York (NY) is determined as 6.
What is the order of magnitude of a measurement?
An order of magnitude of a measurement is an approximation of the logarithm of a value relative to some contextually understood reference value, usually 10, interpreted as the base of the logarithm and the representative of values of magnitude one.
Also, the order of magnitude can be defined as the power of 10 a number is raised to when it's in scientific notation.
The given measurement;
m = 3,944,000 m
The measurement in scientific notation;
3,944,000 m = 3.944 x 10⁶ m
Thus, the order of magnitude of the distance between Los Angeles (LA) to New York (NY) is determined as 6.
Learn more about order of magnitude here: https://brainly.com/question/24468862
#SPJ1
are their final velocities necessarily equal? explain. yes, the final velocity is the instantaneous velocity at the moment a sprinter crosses the fini
The answer is statement 2 which states that only the average velocity must be same but not necessarily the instantaneous velocity.
The given situation is that two sprinters start the race on a straight track, in which they cross the finish line at the same time. So, they covered the same amount of distance at the same amount of time. This means that both their average velocity is equal, since it is independent of instantaneous velocity.One sprinter might start the race faster and finish at a slower speed whereas the other sprinter might start the race slower and finish the race at a faster speed. In this situation the final velocities are not equal.Instantaneous velocity is the velocity of an object at a specific time whereas average velocity is the average velocity of an object throughout the time.
The given question is incomplete. The complete question is:
Two sprinters start a race along a straight track at the same time and cross the finish line at the same time.
Are their final velocities necessarily equal? Explain.
1 ) Yes, the final velocity is the instantaneous velocity at the moment a sprinter crosses the finish line, which will be the same between two sprinters. The instantaneous velocities for the entire race must be the same.
2) No, the final velocity is just the instantaneous velocity at the moment a sprinter crosses the finish line, which can vary between two sprinters. Only the average velocity for the entire race must be the same.
Therefore, the correct answer is statement 2.
To know more about average velocity
https://brainly.com/question/862972
#SPJ4
at a distance from the slits which is large compared to their separation, what is the phase difference (in radians) in the light from the two slits at an angle of 25.8 ∘∘ from the centerline
∅=2021rad is the phase difference (in radians) in the light from the two slits.
using the formula below
Φ =( [tex]2\pi d/[/tex]β )sinα
∅=2021rad
What is phase difference?The time difference between the same points within the two sounds' wave cycles (the peaks or positive-going zero crossings, for example), expressed as a fraction of one wave cycle, determines the phase difference between two sound waves of the same frequency travelling past a fixed spot.
Phase shift occurs when the sine and cosine function graphs are moved to the left or right of where they usually are, or we can say that the function is moved horizontally how far from its normal position. Functions are typically moved from their normal place.
To learn more about phase difference from the given link:
brainly.com/question/2396792
#SPJ4
If we apply a potential difference of 4. 50 v between the ends of a wire that is 2. 50 m in length and 0. 654 mm in radius, the resulting current through the wire is 17. 6. What is the resistivity of the wire material?.
According to the resistance, the resistivity of wire material is 1.37 x 10¯⁷ Ωm.
We need to know about the resistance of conductive material to solve this problem. Resistance can be defined as the ratio of the voltage applied to current flow It can be written as
R = V / I
where R is resistance, V is voltage and I is current.
The resistance of the material depends on its resistivity and follows this equation
R = ρ . L / A
where ρ is resistivity, L is the length of the material and A is the surface.
From the question above, we know that
V = 4.5 V
L = 2.5 m
r = 0.654 mm = 6.54 x 10¯⁴ m
I = 17.6 A
Find the surface area
A = π . r²
A = π . ( 6.54 x 10¯⁴ )²
A = 1.34 x 10¯⁶ m²
Find the resistivity of the wire
R = V / I
ρ . 2.5 / (1.34 x 10¯⁶)= 4.5 / 17.6
ρ = 1.37 x 10¯⁷ Ωm
Find more on resistance at: https://brainly.com/question/17563681
#SPJ4
a simple formula for the distance traveled (x in meters) by an air car traveling a track uses the initial starting point (x0 in meters), the initial velocity (v0 in units meters per second), and the acceleration (a in units meters per second squared), and the time traveled (t in seconds).
The simple formula for the distance travelled ( in m ) by the air car is s = [tex]V_{0}[/tex] t + 1 / 2 at² which is an equation of motion.
According to equations of motion,
s = ut + 1 /2 at²
where,
s = Distance travelled
u = Initial velocity
t = Time travelled
a = Acceleration
Given that,
u = [tex]V_{0}[/tex]
s = [tex]V_{0}[/tex] t + 1 / 2 at²
Equations of motion are used to describe position of an object as a function of time. It is done using acceleration, velocity, distance and time.
Therefore, the simple formula for the distance travelled is s = [tex]V_{0}[/tex] t + 1 / 2 at²
To know more about Equations of motion
https://brainly.com/question/15080570
#SPJ4
help! an asteroid is heading towards us at 15 km/s . scientists decide the best solution is to attach a rocket to the asteroid and fire it to change the trajectory of the asteroid. if the rocket is fired for 8 min, the scientists calculate that the new speed for the asteroid will be 21 km/s and its new trajectory will be at an angle of 33 ∘ to its original path.
The acceleration of the asteroid which is moving at a speed of 15km/s is [tex]a = (0.0058i + 0.023j)km/s^{2}[/tex].
What is trajectory ?A mass-moving object's route through space as a function of time is known as its trajectory or flight path. A full trajectory is defined by location and momentum at the same time in classical mechanics since a trajectory is determined by Hamiltonian mechanics using canonical coordinates.
[tex]v_{i} = 15km/s\\v_{f} = 21km/s(cos33i + sin33j)\\v_{f} = 21km/s(0.83i + 0.54j)\\t = 8 min = 480 s\\a = v_{f} - v_{i}/t\\a = 17.83i + 11.34j - 15i/480\\a = (0.0058i + 0.023j)km/s^{2}[/tex]
to learn more about trajectory go to -
https://brainly.com/question/88554
#SPJ4
a string or rope will break apart if it is placed under too much tensile stress. thicker ropes can withstand more tension without breaking because the thicker the rope, the greater the cross-sectional area and the smaller the stress. one type of steel has density 7710 kg/m3 and will break if the tensile stress exceeds 7.0×108n/m2. you want to make a guitar string from a mass of 4.2 g of this type of steel. in use, the guitar string must be able to withstand a tension of 900 n without breaking. your job is the following.
The maximum length the string can have is 13.02 meter.
(a) Determine the maximum length the string can have
Answer:
As we know that density(p)= mass(m)/volume(V)
Solve for volume(V)= mass/density
If the given mass value is in gram then we have to divide it by 1000 to get the value in kilogram so our mass in kg will be 3.7/1000= 0.0037 kg
And if density is in kg/m^3
Then volume will be V= 0.0037/7730 =>
4.79^10-7m^3
Now we know that stress = Force/Area
For Area = force/stress => 900/7*10^8=> 2795.95m^2
For length= volume/Area => 4.79^10-7/2795.95
Length= 13.02 m
To learn more about similar question from the given link:
brainly.com/question/14103537
#SPJ4
A bicyclist starts from rest and accelerates along a straight path to a speed of 12. 15 m/s in a time of 4. 5 seconds. What is the bicyclist’s acceleration to the nearest tenth of a m/s2?.
Answer:The cyclist's acceleration to the nearest tenth is: C. 2.7 .
Given the following data:
Initial velocity = 0 m/s (since the cyclist starts from rest).
Final velocity = 12.5 m/s.
Time = 4.5 seconds.
To find the cyclist's acceleration to the nearest tenth:
Acceleration is calculated by subtracting the initial velocity from the final velocity and dividing by the time.
Mathematically, acceleration is given by the formula;
Where:
A is the acceleration.
V is the final velocity.
U is the initial velocity.
t is the time measured in seconds.
Substituting the given parameters into the formula, we have;
Acceleration, A = 2.7
Therefore, the cyclist's acceleration to the nearest tenth is 2.7 .
Explanation:
Can a car that has been traveling at different speeds in a straight line east have accelerated west?.
Yes. If a car is traveling eastward and slowing down, its acceleration is opposite to the direction of travel: its acceleration is westward.
A car that has been traveling at different speeds is already accelerating.
Now suppose it is traveling at different speeds means some force is applied to that car.
It is traveling in a straight line in the east and traveling at a different speed, which means the speed keeps on changing so sometimes it can be possible that acceleration can also be in the opposite direction to that in which it is traveling, so here it can be in the west as it is an easterly course of travel direction so no north or south direction movement.
For more information on speed click on the link below:
https://brainly.com/question/13943409
#SPJ4
A boy and a girl are biking down a hill. The boy and the girl weigh the same, and they are using bikes that weigh the same. If the boy and girl are biking at the same speed, which child has more motion energy (kinetic energy)?
Answer:
neither.
they both are going at the same speed
Explanation:
Answer:
They have the same Kinetic Energy
Explanation:
KE = 1/2 m v^2 if the velocities are the same and the masses are the same .....then the Kinetic energies are the same
a boat can travel at a speed of 8 km/h in still water on a lake. in the flowing water of a stream, it can move at 8 km/h relative to the water in the stream. if the stream speed is 3 km/h, how fast can the boat move past a tree on the shore when it is traveling.
Relative velocity of the river with respect to shore, V = 20 km/h.
Relative velocity of the river with respect to shore ,V = 10 km/h
Velocity of the shore = 0 km/h
Relative velocity of the river with respect to shore:
[tex]V = V_{r} - V_{s}[/tex]
Velocity of the river [tex]V_{r}[/tex] = 10 km/h
Relative velocity of the boat with respect to river ,V'= 10 km/h
[tex]V^{'} = V_b} -V_{r}[/tex]
Velocity of the boat [tex]V_b}[/tex] = 20 km/h
Relative velocity of the boat with respect to shore, V":
[tex]V_{"} = V_{b} - V_{s}[/tex]
Relative velocity of the boat with respect to shore is 20 km/h.
What is Relative velocity?It is the pace at which one object's relative location changes in relation to another object over time.
Think about two trains that are traveling in the same direction and at the same pace. Even though the tracks, buildings, and trees on each side of the railway indicate that both trains are moving, to the observer of one train, the other train appears to be stationary. The other train seems to be moving at a constant speed.
The speed at which one thing moves in relation to another is known as the relative velocity of the two objects.
To learn more about Relative velocity from the given link:
brainly.com/question/19260269
#SPJ4
Is there any formula to calculate the height a ball will reach depending on the bounce number and it’s initial height? Alternatively, can any formula calculate the amount of times a ball will bounce without going into infinity?
Answer:
yeas
Explanation:
beac×high ×sides and after you fins tims you need to add beac+high and add the sides together and add what did you got from beac,high and sides and thin you will add every thing together
three 3.0 -μc point charges are at the three corners of a square of side 0.50 m. the last corner is occupied by a −3.0 -μc charge. find the magnitude of the electric field at the center of the square.
The magnitude of the electric field at the center of the square is 4.32 * [tex]10^{5}[/tex] N / C
We know that,
The magnitude of the electric field by the one positive charge and other negative charge at the centre is
E = k ( [tex]q_{2}[/tex] - [tex]q_{4}[/tex] ) / [tex]r^{2}[/tex]
The distance of each charge from the centre of the square is
r = d / √ 2
where,
k = Coulomb's constant
[tex]q_{1}[/tex], [tex]q_{2}[/tex], [tex]q_{3}[/tex], [tex]q_{4}[/tex] = Point charges
d = Side of square
Given that,
[tex]q_{1}[/tex] = [tex]q_{2}[/tex] = [tex]q_{3}[/tex] = 3 μ C = 3 * [tex]10^{-6}[/tex] C
[tex]q_{4}[/tex] = - 3 μ C = - 3 * [tex]10^{-6}[/tex] C
d = 0.5 m
k = 9 * [tex]10^{9}[/tex] N m² / C²
E = k ( [tex]q_{2}[/tex] - [tex]q_{4}[/tex] ) / [tex]r^{2}[/tex]
E = 2 k / d² ( [tex]q_{2}[/tex] - [tex]q_{4}[/tex] )
E = 2 ( 9 * [tex]10^{9}[/tex] ) ( 3 * [tex]10^{-6}[/tex] - ( - 3 * [tex]10^{-6}[/tex] )) / 0.5²
E = 4.32 * [tex]10^{5}[/tex] N / C
Electric field is the field surrounding an electrically charged particle. If any other charged particle enters the field, it exerts force on the particle.
Therefore, the magnitude of the electric field at the center of the square is 4.32 * [tex]10^{5}[/tex] N / C
To know more about Electric field
https://brainly.com/question/15800304
#SPJ4
Astronomers observe a typical star using a telescope and a spectrometer. they will see?
Astronomers observe a typical star using a telescope and a spectrometer, they will see an absorption spectrum and is therefore denoted as option B.
What is an Absorption spectrum?This is referred to as the percentage of incident radiation which have been absorbed by the material over a range of different frequencies.
Astronomers are referred to as scientists who are involved in the study planets and space with the use of instruments such as telescope and a spectrometer and they are most likely to see an absorption spectrum due to the different frequencies of light which are present in space.
Read more about Absorption spectrum here https://brainly.com/question/10252035
#SPJ1
The options are:
an emission spectruman absorption spectruma continuous spectrummore than one of the above.How does the kinetic energy of the car traveling 32 m/s compare to the energy released by burning a gallon of gasoline. That is, what is the ratio of the two?
The ratio of burning a gallon of gasoline to kinetic energy of the car is 1.27*102 :1
Burning a gallon of gasoline yields Egas = 1.3×108 J of energy.
A car's mass may vary in the range of 990 to 2000 kg.
Kinetic energy of a car is given as 1/2mv2
K.E = ½ m(32)2
K.E = ½*2000(32)2
K.E =1000 * 1024
K.E = 1.024 * 106 J
Comparing the Energy of gas to the kinetic energy of the car travelling at 32 m/s we have
Gas: Car = 1.3×108 J: 1.024 * 106 J
= (1.3 ×〖10〗^8)/(1.024×〖10〗^6 )
= 1.27*102 :1
Hence, the ratio of the energy of a burning gallon of gasoline to that of a car (assume weight is 2000 kg) moving at 32 m/s is 1.27*102 :1.
To learn more about energy. Click, https://brainly.com/question/16182853
#SPJ4
a uniform electric field exists in the region between two oppositely charged plane parallel plates. a proton is released from rest at the surface of the positively charged plate and strikes the surface of the opposite plate, 1.60 cmcm distant from the first, in a time interval of 3.80×10−6 ss .
The magnitude of the electric field is
[tex]1.29 \: \times 10 ^{ - 24} \: N/C.[/tex]
The time interval is t.
[tex]t = 3.8 \times 10 ^{ - 6} \: s[/tex]
The distance of the second proton from the first proton is d.
[tex]d = 1.60 \: 10^{ - 2} \: m[/tex]
[tex]∆x = \frac{1}{2} at ^{2} [/tex]
The magnitude of the electric field is,
[tex]E = \frac{ F}{e}[/tex]
[tex]E = \frac{ma}{e} [/tex]
[tex] = \frac{2 \: ∆x \: m}{e \: t ^{2} } [/tex]
[tex] = 2 \times \frac{(1.6 \times 10 ^{ - 2} )(1.9 \times 10 ^{ - 3}) }{(1.6 \times 10 ^{ - 19})(3.8 \times 10 ^{ - 6} ) ^{2} } [/tex]
[tex] = 1.29 \: \times 10 ^{ - 24} \: N/C[/tex]
Therefore, the magnitude of the electric field is
[tex]1.29 \: \times 10 ^{ - 24} \: N/C.[/tex]
To know more about the electric field, refer to the below link:
https://brainly.com/question/26690770
#SPJ4
Every time you inhale, oxygen makes its way to millions of tiny, sponge like sacs called ______that line the walls of your lungs.
Popliteal
Arterial
Alveoli
Capillaries
Every time you inhale, oxygen makes its way to millions of tiny, sponge like sacs called alveoli that line the walls of your lungs.
Lungs :Your lungs contain tiny, balloon-shaped air sacs called alveoli. Moving oxygen and carbon dioxide (CO2) molecules into and out of your bloodstream is what the alveoli are there for. Alveoli are a crucial component of your respiratory system, which includes the body parts that aid in breathing.
What lines walls of alveoli?An alveolus is made up of an extracellular matrix encircled by capillaries, a layer of simple squamous epithelium (extremely thin, flattened cells), and an epithelial layer. The alveolar membrane, also known as the respiratory membrane, which permits the exchange of gases, includes the epithelial lining.
To know more about epithelial layer :
https://brainly.com/question/14838165
#SPJ9
Use the position-time graph below to answer the following questions.
What is the displacement of the object?
What is the distance travelled by the object?
Sketch the velocity-time graph that corresponds to this data.
Answer:49
Explanation:47484=4848489
problem 11.043 - uniformly accelerated motion of two particles - dependent multi-part problem - assign all parts skip to question note: this is a multi-part question. once an answer is submitted, you will be unable to return to this part. two automobiles a and b are approaching each other in adjacent highway lanes. at t
The vehicles pass each other after 20.7 seconds
We know that,
s = ut + 1 / 2 a[tex]t^{2}[/tex]
s = Displacement
u = Initial velocity
t = Time taken
a = Acceleration
Given that,
s = 3200 ft = 0.606 mi
[tex]u_{a}[/tex] = 68 mi / [tex]hr^{2}[/tex]
[tex]t_{a}[/tex] = 40 s = 40 / 3600 hr
[tex]u_{b}[/tex] = 37 mi / [tex]hr^{2}[/tex]
[tex]t_{b}[/tex] = 42 s = 42 / 3600 hr
s = [tex]u_{a}[/tex][tex]t_{a}[/tex] + 1 / 2 [tex]a_{a}[/tex][tex]t_{a} ^{2}[/tex]
0.606 = 68 ( 40 / 3600 ) + [tex]a_{a}[/tex] 0.5 ( 40 / 3600 [tex])^{2}[/tex]
[tex]a_{a}[/tex] = - 2422 mi / [tex]hr^{2}[/tex]
s = [tex]u_{b}[/tex][tex]t_{b}[/tex] + 1 / 2 [tex]a_{b}[/tex][tex]t_{b} ^{2}[/tex]
0.606 = 37 ( 42 / 3600 ) + [tex]a_{b}[/tex] 0.5 ( 42 / 3600 [tex])^{2}[/tex]
[tex]a_{b}[/tex] = 2561.63 mi / [tex]hr^{2}[/tex]
[tex]s_{a}[/tex] + [tex]s_{b}[/tex] = 0.606
68 t + 0.5 ( - 2422 ) [tex]t^{2}[/tex] + 37 t + 0.5 ( 2561.63 ) [tex]t^{2}[/tex] = 0.606
105 t + 1280.67 [tex]t^{2}[/tex] - 1211.4 [tex]t^{2}[/tex] - 0.606 = 0
t = 5.75 * [tex]10^{-3}[/tex] hr = 20.7 sec
The equations of motion are basically used to describe the motion of an object using position, velocity, acceleration and time.
Therefore, the vehicles pass each other after 20.7 seconds
The given question is incomplete. The compete question is :
Two automobiles A and B are approaching each other in adjacent highway lanes. At t- 0, A and B are 3200 ft apart, their speeds are VA 68 mi/h and VB 37 mi/h, and they are at points P and Q, respectively. A passes point Q 40 s after B was there and B passes point P42s after A was there. 3200 ft Problem 11.043.b - Uniformly accelerated motion of two particles Determine when the vehicles pass each other
To know more about equations of motion
https://brainly.com/question/15080570
#SPJ4
Photons of wavelength 0.024 a are incident on free electrons. (a) find the wavelength of a photon which is scattered 3
When Photons of wavelength 0.024 a are incident on free electrons, the wavelength of a photon which is scattered 30° is 0.0576 x [tex]10^{-11}[/tex] and for the one scattering at 120° is 0.38 x [tex]10^{-11}[/tex] A.
How can the Compton effect be used to determine the energy of scattered photons?The incident photon’s energy is equal to the scattered photon’s energy minus the total of the recoil electron’s kinetic energy and binding energy.
Compton scattering causes the loss of an electron and ionization of the absorbing atom, just like photoelectric absorption does.
What is the scattered photon’s wavelength?After the scattering event and before, the photon’s wavelength varies by ∆λ = (h/mc) (1-cosφ). Here, c is the speed of light, m is the rest mass of the electron, and is the angle at which the photon is scattered. H is the Planck constant.
Given photon wavelength λ = 0.024A
φ = 30°
From the Compton effect we know that
∆λ = λ1 - λ = h/mc (1-cosφ)
λ1 = [tex]\frac{6.62*10^{-34}}{9.1}[/tex] x [tex]10^{-3}[/tex] x 3 x [tex]10^{8}[/tex] (1- cos30°) + 0.024A
= 0.0576 x [tex]10^{-11}[/tex] A
And then calculating the same for
φ = 120°
we get,
λ1 = 0.38 x [tex]10^{-11}[/tex]A
To know more about scattered wavelength visit:
https://brainly.com/question/13200635
#SPJ1
Complete Question
Photons of wavelength 0.024A are incident on free electrons.
(a) Find the wavelength of a photon which is scattered 30° from the incident direction and the kinetic energy imparted to the recoil electron
(b) Do the same if the scattering angle is 120°.
A fellow student reports his measurements of time for a speed calculation in minutes. How could he express that calculation using SI
base units?
convert minutes to meters and redo his calculations
convert minutes to hours and redo his calculation
convert minutes to seconds and redo his calculation
Okeep his calculation as it is
Convert minutes to seconds and redo his calculation.
How do we measure time?The quick response. Atomic clocks are the most precise timekeeping devices we have for measuring the length of time between two events. Atoms in the clocks jump from one energy level to another as a result of the precise frequency at which these clocks emit electromagnetic radiation, such as microwaves.
Time is an illusion, says theoretical physicist Carlo Rovelli, because our simple perception of its flow doesn't match up with physical reality. In fact, much more, including Isaac Newton's depiction of a constantly ticking clock, is illusory, according to Rovelli's claim in The Order of Time.
How do you calculate hours and minutes?In an hour, there are 60 minutes. Divide the amount of minutes by 60 to convert it to hours. For instance, 120/60=2 means that 2 hours are equal to 120 minutes.
To know more about microwaves :
https://brainly.com/question/1593533
#SPJ9
A shuttle bus slows to a stop with an average acceleration of -1.8 m/s^2. How long does it take the bus to slow down from 9.0 m/s to 0.0 m/s?
Time taken to slow down the speed will be 5 seconds.
Average acceleration of the bus, a = 1.8 m/s²
Initial velocity of the bus, u = 9.0 m/s
Final velocity of the bus, v = 0 m/s
According to the First Equation of the motion which relates the acceleration, velocity and time we can say that
v = u + at
v - u = at
0 - 9 = (-1.8) * t
9 = 1.8 * t
t = [tex]\frac{9}{1.8}[/tex]
t = 5 s
Therefore 5 seconds will be required by the bus to slow down its speed from 9.0 m/s to 0.0 m/s
To know more about Time,
https://brainly.com/question/13463741
#SPJ1
which phrase best describes a chaparral
There are many different types of landforms in the chaparral biome, including rocky hills, level plains, and mountain slopes. Option C
What was the Chaparral Biome's temperature?The Chaparral biome often has very hot days and frigid to freezing nights. The summertime temperature range might be between 15 and 30 degrees.
Winter days are cooler, with temperatures ranging from 4° to 20°. The Chaparral biome has an average temperature of 18 degrees. The average yearly temperature is between -1° and 38° C (30° to 100° F).
Chaparral, or Mediterranean Forests and Shrubs, is a temperate biome distinguished by its hot, dry summers and mild, wet winters. Nearly the majority of the rainfall falls during the winter and spring rainy seasons.
Learn more about Chaparral here:
brainly.com/question/9894593
#SPJ1
CQ
Which phrase best describes a chaparral?
O A. Is home to herds of giraffea, zebras, and wildebeests
O B. Receives less than 25 cm of precipitation per year
O C. Has low-growing, tough shrubs and rocky, dry soils
O D. Contains mostly needle-leaved evergreen trees
Answer:
here you go :)
ALL CREDIT TO THE OTHER PERSON!!
Explanation:
A train travelling at 22m/s accelerates uniformly at 0.85 m/s^2 for 25s. Calculate the distance travelled by the train at this time.
The distance travelled by the train travelling at 22 m/s, which accelerates uniformly at 0.85 m/s² for 25s is 815.62.
What is Second equation of motion?
The second equation of motion is used to calculate the distance traversed by the body moving with uniform velocity. Mathematically -
S = ut + 1/2 at²
Given in the question is a train travelling at 22 m/s accelerates uniformly at 0.85 m/s² for 25s. From this, we can write -
Initial velocity [u] = 22 m/s
acceleration [a] = 0.85 m/s²
time taken [t] = 25 s
In order to find the distance travelled by the train, we will use the second equation off motion -
S = ut + 1/2 at²
S = 22 x 25 + 1/2 x 0.85 x 25 x 25
S = 815.62 meters
Therefore, the distance travelled by the train travelling at 22 m/s, which accelerates uniformly at 0.85 m/s² for 25s is 815.62.
To solve more questions on Kinematics, visit the link below-
https://brainly.com/question/16876581
#SPJ1
The net force on a moving object suddenly becomes zero and remains zero. The object will.
The net force on a moving object suddenly becomes zero and remains zero then the object will be in rest according to Newton's first law of motion.
The force on an object is equal to its mass times of its acceleration i.e.
F =ma
where , m is the mass , F is the force and a is the acceleration of the object. Its unit is Newton (N).
Newton's first law can be stated as , when an object at rest remains at rest, or if in motion, remains in motion at a constant velocity unless acted on by a net external force. A reaction force is a force that acts in the opposite direction to an action force.
Velocity of an object can be said as, the rate of change of displacement with respect to time of an object . Its unit is m/s and it is a vector quantity.
V = Δx/Δt
In here , V is velocity , Δx is change in displacement and Δt is change in time of an object.
In hence ,when the net force becomes zero F=0 the velocity of the object will be zero , then the object will remain at rest.
To know more about force
https://brainly.com/question/1528116
#SPJ1
Suppose a plane accelerates from rest for 30 s, achieving a takeoff speed of 80 m/s after traveling a distance of 1200 m down the runway. A smaller plane with the same acceleration has a takeoff speed of 40 m/s . Starting from rest, after what distance will this smaller plane reach its takeoff speed?
Answer:600 m is required for smaller plane to reach its takeoff speed. ... So 300 m is required for smaller plane to reach its takeoff speed.
Explanation:
Answer:
300 m
Explanation:
Find acceleration of first plane
v = a t
80 = a (30) shows a = 2.67 m/s^2
For the smaller plane
v = at
40 = 2.67 t shows t = 14.98 seconds
d = 1/2 a t^2
= 1/2 2.67 (14.98^2) = 299.6 = ~ 300 meters
PLS HELPPP I NEED IT
FITT principle:
Frequency-is how regular or often a person does the plan of a target health-related physical activity. It depends on how determined you want to accomplish your target. The more often you train, the faster the result.
Intensity - is how hard a person exercise during a physical activity period. It can be measured in different ways, depending on the health-related component. For example, monitoring heart rate is one way to measure the intensity during aerobic endurance activities, but does not indicate intensity during flexibility activities. The harder you work, the faster your heart beats.
Time - is the duration of the physical activity. Together with the other aspects of the FITT principle, time varies depending on the target health-related fitness component. For example, in developing flexibility, stretching may take 10-30 seconds for each activity, while the minimum time for performing an aerobic exercise is 20 minutes of continuous action.
Type - refers to the physical activity chosen to improve a specific component of health-related fitness. Different events require different training programs. For example, if a person wants to increase core muscles, he or she must do exercises that target the oblique muscles, while another person wishing to improve his or her cardiovascular endurance needs to jog, run, swim or perform some other aerobic activities.
The FIIT plan required for different type of workout is shown in the image attached.
FIIT plan is used to monitor one's workout routine. It also helps to create workout routines that helps one's fitness goal which might differ from each person. It works based on four elements i.e., Frequency, Intensity, Time and Type.
Frequency refers to how often a workout needs to be done. Intensity refers to how hard a workout must be done. Time refers to the amount of time spent on the workout. Type refers to the king of exercise which suits one's final goal.
Therefore, the FIIT plan required for different type of workout is shown in the image attached.
To know more about fitness
https://brainly.com/question/8860814
#SPJ1
After Thanksgiving, Kevin and Gamal use the turkey's wishbone
to
make a wish. If Kevin pulls on it with a force 0.17 N a larger than
the force Gamal pulls
with in the opposite direction, and the
wishbone has a mass of 13
g, what is the wishbone's initial
acceleration?
According to the given statement the wishbone's initial acceleration is 13.08 m/s².
How does acceleration work?Velocity's rate of change with time, both in terms of speed and direction. A point or item going straight ahead is accelerated when it increases or decelerates. Even if the speed remains constant, motion on a circular accelerates so because direction is always shifting.
Briefing:In this task, we calculate the acceleration for a given force and the mass on which the force was applied.
F[tex]_n_e_t[/tex] = 0.17 N
m = 13g
m = 1.3 × 10⁻² kg
a =?
F = m × a
a = F/m
a=0.17 N/1.3× 10⁻² kg
a=13.08 m/s²
To know more about Acceleration visit:
https://brainly.com/question/21652405
#SPJ9