To determine the resistance of a resistor in a circuit using Ohm's law, we need to know the voltage across the resistor and the current flowing through it. Ohm's law states that the resistance (R) of a component is equal to the voltage (V) across it divided by the current (I) flowing through it:
R = V / I
Ohm's law is a fundamental principle in electrical engineering and physics that describes the relationship between voltage, current, and resistance in an electrical circuit. It states that the current flowing through a conductor between two points is directly proportional to the voltage across the two points, while inversely proportional to the resistance of the conductor. Mathematically, Ohm's law is expressed as:
V = I * R
Where:
V represents the voltage across the conductor (measured in volts, V)
I represents the current flowing through the conductor (measured in amperes, A)
R represents the resistance of the conductor (measured in ohms, Ω)
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a skydiver has bailed out of his airplane at a height of 3000 m. the mass of the skydiver and his parachute is 80 kg. what is the drag (force of air resistance) on the system (man plus parachute) when he reaches terminal speed?
The drag (force of air resistance) on the system (man plus parachute) when the skydiver reaches terminal speed is equal to the gravitational force acting on him, which is 80 kg × 9.8 m/s² = 784 N.
To calculate the drag force at terminal speed, we must first understand that at terminal speed, the net force acting on the system is zero. This is because the gravitational force (weight) acting downward on the skydiver is balanced by the upward air resistance (drag force).
The weight of the skydiver can be calculated by multiplying his mass (80 kg) by the acceleration due to gravity (9.8 m/s²), resulting in a gravitational force of 784 N. Since the net force is zero, the drag force must also be 784 N, meaning the force of air resistance on the system at terminal speed is 784 N.
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Let the orbital radius of a planet be R and let the orbital period of the planet be T. What quantity is constant for all planets orbiting the sun, assuming circular orbits? What is this relation (law) called ? You will have to write complete calculations. a. T2/R b. T2 R3 c. T3/R2 d. T/R e. T/R2
The quantity that is constant for all planets orbiting the Sun, assuming circular orbits, is the ratio of the orbital period squared (T^2) to the orbital radius cubed (R^3). This relation is known as Kepler's Third Law or the Law of Harmonies.
Kepler's Third Law states that the square of the orbital period of a planet is directly proportional to the cube of its average distance from the Sun. Mathematically, it can be expressed as:
T^2/R^3 = constant
To derive this relation, let's start with the basic equation for centripetal force:
F = (m*v^2) / R
where m is the mass of the planet, v is its orbital velocity, and R is the orbital radius.
The centripetal force is also given by the gravitational force between the planet and the Sun:
F = (G * M * m) / R^2
where G is the gravitational constant and M is the mass of the Sun.
Setting these two expressions for F equal to each other and rearranging, we have:
(m*v^2) / R = (G * M * m) / R^2
Canceling the mass of the planet (m) from both sides, we get:
v^2 / R = (G * M) / R^2
Rearranging the equation further, we have:
v^2 = (G * M) / R
We know that the orbital velocity of a planet is given by:
v = 2πR / T
Substituting this expression into the equation, we have:
(2πR / T)^2 = (G * M) / R
Simplifying, we get:
4π^2 * R^2 / T^2 = (G * M) / R
Multiplying both sides by T^2 and dividing by 4π^2, we obtain:
R^3 / T^2 = (G * M) / (4π^2)
Since (G * M) / (4π^2) is a constant, we can rewrite the equation as:
R^3 / T^2 = constant
Therefore, the correct answer is (b) T^2 R^3.
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in this example, if the emf of the 4 v battery is increased to 19 v and the rest of the circuit remains the same, what is the potential difference vab ?
The potential difference Vab in the given circuit, with a 19V battery and the rest unchanged, will also be 19V.
In this circuit, if the EMF of the 4V battery is increased to 19V while the rest of the circuit remains the same, the potential difference Vab will be equal to the EMF of the battery. This is because, in a simple series circuit, the potential difference across the terminals of a battery is equal to its EMF.
As the battery EMF is increased to 19V, the potential difference Vab will also be 19V. The voltage is divided across the resistors in the circuit, but the sum of the voltage drops across the resistors will equal the total potential difference, which is the EMF of the battery, in this case, 19V.
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Unreasonable Results What is wrong with the claim that a cyclical heat engine does 4.00 kJ of work on an input of 24.0 kJ of heat transfer while 16.0 kJ of heat transfers to the environment?
That a cyclical heat engine does 4.00 kJ of work on an input of 24.0 kJ of heat transfer while 16.0 kJ of heat transfers to the environment is that it violates the first law of thermodynamics, which states that energy cannot be created or destroyed, only transferred.
His discrepancy means that the claim is not reasonable and violates the first law of thermodynamics.
In the case of the claim that a cyclical heat engine does 4.00 kJ of work on an input of 24.0 kJ of heat transfer while 16.0 kJ of heat transfers to the environment, the numbers don't add up. If the engine is doing 4.00 kJ of work, and losing 16.0 kJ of heat to the environment, then it must be receiving 20.0 kJ of heat energy, not 24.0 kJ. T
The claim states that a cyclical heat engine does 4.00 kJ of work with an input of 24.0 kJ of heat transfer, while 16.0 kJ of heat transfers to the environment. According to the first law of thermodynamics, energy cannot be created or destroyed, only converted from one form to another. In the case of a heat engine, this law can be expressed as results do not match, which means that the claim is unreasonable and violates the first law of thermodynamics. There must be an error in the values provided for the heat engine.
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