The acceleration of an airplane that had an initial velocity of 10km/min and a final velocity of 18km/min covered over 90min is 0.09km/min².
How to calculate acceleration?The acceleration of a moving substance can be calculated by dividing the change in velocity by the time taken as follows:
a = (v - u)/t
Where;
a = accelerationv = final velocity (km/min)u = initial velocity (km/min)t = time (minutes)According to this question, an airplane was flying from Cincinnati to Denver. The velocity of an airplane was measured shortly after take off at 10km/min. The velocity was measured again mid-flight to be 18km/min.
a = (18km/min - 10km/min)/90min
a = 8km/min ÷ 90min
a = 0.09km/min²
Therefore, acceleration of an airplane that had an initial velocity of 10km/min and a final velocity of 18km/min covered over 90min is 0.09km/min².
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a chain lying on the ground is 10 m long and its mass is 90 kg. how much work (in j) is required to raise one end of the chain to a height of 6 m? (use 9.8 m/s2 for g.)
Amount of work done required to raise one end of the chain is 158.6 J
Work is said to be done when a force act on a body and it displaced from its position.
It's unit is joule.
W = F × S
where
W = work done
F = force applied
S = displacement
Force acting on the chain with respect to the distance is given by
F = mgx / 10
m is mass
m = 90 kg
g is gravity (9.8 m/s2 for g.)
90× 9.8× x / 10
F = 88.2x Newton
To calculate the amount of work done.
[tex]W = \int\limits^f_i{F(x)} \, dx[/tex]
[tex]W = \int\limits^6_0 {F(x)} \, dx[/tex]
[tex]W = 88.2\int\limits^6_0 {x} \, dx[/tex]
[tex]W = 88.2 | \frac{x^2}{2}|^{6} _{0}[/tex]
W = 88.3( 6² - 0²)/2
W = 88.2 (36- 0) /2
W = 88.2 × 18
W = 158.6 J
Amount of work done required to raise one end of the chain is 158.6 J
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QUESTION 2: Switch on your light source. Make sure it is shining onto a wall Hold your largest cardboard square between the light source and the wall. . • 2a. What do you observe? . Now do the same with the second cardboard square. 2b. What do you observe? ▸ Now do the same with the third cardboard square. 2c. What do you observe? 2d. What differences do you observe between the shadows of the three sh QUESTION 33 Switch on your light source. Make sure it is shining onto a wali. Hold your largest plastic shopping bag square between the light sourc
When a light source falls on an object if it is a opaque object it will form shadow.
And the light falls on the largest cardboard there will be a big shadow formed in the wall. Now when we take a second cardboard the shadow will form in accordance with that cardboard that if the cardboard is more it will form small shadow
And when we do with the same third cardboard or small cardboard the shadow will be according to the size of the cupboard now when we keep a plastic shopping bag in between the light source and the wall if the plastic bag is transparent the light will pass through the plastic bag and if the plastic bag is opaque the light will not pass through the bag and a shadow will be not be formed
Here we can conclude that if a light is passing through a pack object the light cannot pass through the object and it will format shadow but when the light is passing through a transparent object that light will pass through the object and there will be no shadow formed
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A parallel-plate capacitor has a capacitance of 10 mf and is charged with a 20-v power supply. The power supply is then removed and a dielectric material of dielectric constant 4. 0 is used to fill the space between the plates. What is the voltage now across the capacitor?.
The capacitor's energy becomes 0.5 J when the dielectrics have been inserted between its plates.
How does capacitance work?The quantity of energy held in the form of an electric charge in an electric device is referred to as capacitance.
Data provided
C = 10 mF = 0.01 F is the parallel-plate capacitor's capacitance.
V' = 20 V is the power supply's potential.
The material has a dielectric constant of 4.0.
First, let's determine the charge that the capacitor has stored:
[tex]C^{\prime}=\epsilon \times C[/tex]
Solving as,
[tex]\begin{aligned}&C^{\prime}=4.0 \times 0.01 \\&C^{\prime}=0.04 \mathrm{~F}\end{aligned}[/tex]
Now, the expression for the energy stored in the capacitor is,
[tex]U^{\prime}=\frac{q^2}{2 C^{\prime}}[/tex]
Hence
[tex]\begin{aligned}U^{\prime} &=\frac{0.2^2}{2 \times 0.04} \\U^{\prime} &=0.5 \mathrm{~J}\end{aligned}[/tex]
Thus, we may say that the capacitor's energy reserves are 0. 5J
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________ is a measure of your ability to work with and adapt to people from other backgrounds.
Answer:
Cultural intelligence
Explanation:
Niagra falls is 170 feet tall. How much gravitational potential energy is lost when a pound of water falls from
the top of the falls to the bottom of the falls? Answer in BTU.
The amount of gravitational potential energy lost when a pound of water falls from the top of the falls to the bottom is 233.55 Joules.
What is Gravitational Potential Energy?
The gravitational potential energy of a body is due to virtue of its position. A body of mass 'm' at height 'h' is given by -
P.E. = mgh
Given in the is Niagara falls which 170 feet tall. A pound of water falls from the top of the falls to the bottom of the fall. From this we can write -
Height of Niagra falls = 170 feet tall = 51.81 m
Mass of water = 1 pound = 0.46kg
Assume that the potential energy of the pound of water at 170 feet tall is (P[1]) and that at the bottom is (P[2]).
Now, at the top of falls, the potential energy of 1 pound of water = P[1] =
m x g x h = 0.46 x 9.8 x 51.81 = 233.55 J
At the bottom of the falls -
P[2] = 0
The amount of gravitational potential energy lost = P[1] - P[2] =
233.55 - 0 = 233.55 joules.
Therefore, the amount of gravitational potential energy lost when a pound of water falls from the top of the falls to the bottom is 233.55 Joules.
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By deflecting cathode rays with a magnetic field thomson was able to measure what property of electrons?.
The negatively charged electric plate is avoided in favor of the positively charged electric plate by the cathode ray. Thomson was able to estimate the mass-to-charge ratio of the particles by measuring the degree to which the ray was refracted by a magnetic field.
What property of the electron did Thomson measure?J.J. Thomson measured the electron's mass in terms of its physical characteristics.Similar experiments were conducted with cathode rays and magnets by William Crookes, who came to the conclusion that cathode rays were made up of negatively charged molecules based on his observations of the rays' deflection by magnetic fields.J.J. Thomson used a Crookes, or cathode ray, tube to conduct experiments that discovered the electron in 1897. He provided evidence that cathode rays have a negative charge.The negatively charged electric plate is avoided in favor of the positively charged electric plate by the cathode ray. Thomson was able to estimate the mass-to-charge ratio of the particles by measuring the degree to which the ray was refracted by a magnetic field.
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What is the voltage of a source which provides 12.0 J to each Coulomb of charge
present?
The voltage of the source is 12 Volts or 12 Joules per Coulomb.
The difference in electric potential between two points is known as voltage or electric potential difference.
In a static electric field, this difference is defined as the amount of work per unit of charge required to move a test charge between the two points.
Work per unit charge is expressed in SI units as joules per coulomb, with 1 volt equaling 1 joule of work per 1 coulomb of charge.
The voltage or potential difference between two points in a system can be measured using a voltmeter.
Given in the question
Energy provided = 12 J
Charge = 1 Coulomb
We know Voltage = (Energy or Work done)/(Charge)
Put in the value, we get
Voltage = 12/1 Volt or J/C
Voltage = 12 Volt
Hence, the voltage of the source is 12 Volts or 12 Joules per Coulomb.
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the football team at enormous state university (esu) uses vector displacements to record its plays, with the origin taken to be the position of the ball before the play starts. in a certain pass play, the receiver starts at 1.0i^−5.0j^, where the units are yards, i^ is to the right, and j^ is downfield. subsequent displacements of the receiver are 7.0i^ (he is in motion before the snap), 8.0j^ (breaks downfield), −7.0i^ 3.0j^ (zigs), and 11.0i^ 12.0j^ (zags). meanwhile, the quarterback has dropped straight back to a position −7.0j^.
The quarterback will throw the ball 44.4 yards in a particular direction with the angle of 54.16 °
We shall use the ideas connected to the vector sum to develop this issue. To achieve this, we will add the person's displacement vectors to determine the total distance he has gone from the initial point (0 position) to the destination position.
[tex]\overrightarrow R[/tex] = [tex](+1.0 \^{i} - 5\^{j}) + (7\^{i}) + (+12\^{j}) + (6.0\^{i} + 4.0\^{j}) + (+ 12.0\^{i} + 18.0\^{j})[/tex]
[tex]\overrightarrow R[/tex] = [tex]26\^{i} + 29\^{j}[/tex]
subtracting the quarterback's position [tex]\overrightarrow Q[/tex]
[tex]\overrightarrow Q[/tex] = [tex]-7.0\^{j}[/tex]
We can now get the relative location of the two individuals by subtracting the vectors; hence, the position between the individual and the quarterback is
[tex]\overrightarrow R[/tex] - [tex]\overrightarrow Q[/tex] = [tex]26\^{i} + 29\^{j}[/tex] - ([tex]-7.0\^{j}[/tex])
= [tex]26\^{i} + 36\^{j}[/tex]
The magnitude of the relative distance would be calculated using vector characteristics
[tex]|\overrightarrow R - \overrightarrow Q|[/tex] = [tex]\sqrt{26^2 + 36^2}[/tex]
[tex]|\overrightarrow R - \overrightarrow Q|[/tex] = 44.40 yards
The vector's direction would be determined by the tangent of the two vectors, which is
[tex]\theta = tan ^{-1} (\frac{36}{26} )[/tex] = 54.16°
As a result, with regard to 54.16 °, the quarterback will throw the ball 44.4 yards in one direction.
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Full question
At Enormous State University (ESU), the football team records its plays using vector displacements, with the origin taken to be the position of the ball before the play starts. In a certain pass play, the receiver starts at +1.0 i^ - 5.0 j^, where the units are yards, i^ is to the right, and j^ is downfield. Subsequent displacements of the receiver are +7.0 i^ (in motion before the snap), +12 j^ (breaks downfield), ?6.0i^+4.0j^ (zigs), and +12.0i^+18.0j^ (zags). Meanwhile, the quarterback has dropped straight back to a position ?7.0j^.
Part A
How far must the quarterback throw the ball? (Like the coach, you will be well advised to diagram the situation before solving it numerically.)
Part B
In which direction must the quarterback throw the ball?
Which timeline best shows the history development of cell theory
Answer:
you did not show a timeline luckly i did the the quiz it is the second timeline
Explanation:
Answer:
b
Explanation:
I did the test
a train startes from rest and accelerate uniformly until it attains a velocity of 8m/s in 10 seconds. calculate the acceleration of the train
The rate at which an object's velocity with respect to time changes is referred to as acceleration in mechanics. They are vector quantities, accelerations. The direction of the net force applied on the item determines the object's acceleration.
A train starts from rest and accelerate uniformly until it attains a velocity of 8m/s in 10 seconds. calculate the acceleration of the train.
a = 8/10
a = 0.8m/s2
The equation a = v/t denotes acceleration (a), which is the change in velocity (v) over the change in time (t). This enables you to calculate the change in velocity in meters per second squared (m/s2). Since acceleration is a vector quantity, both its magnitude and its direction are included.
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You have been given sheets of four different materials, sand paper,polished wood, rubber and plastic. Design an activity to compare the amount of friction when a wooden block is pulled across sand paper, polished paper, wood and rubber
Force, Friction (static and kinetic), (balanced and unbalanced).
Materials - Tape, spring scales, measuring tape, string, wooden blocks, wooden blocks with sandpaper on the bottom, and different surfaces.
Procedure - 1. To test and gather information on surface friction, each group will look at four distinct surfaces (a concrete floor, a lab desk, a lab floor, and a carpet).
2. Each item should have a string firmly tied around it (a plain block of wood and the wood with sandpaper). Connect the string's looped end to the spring scale.
3. The 50 cm measuring line should be fastened to your surface. Your beginning point will be in the front, and your finishing point will be at the back.
4. Pull the unadorned wood block across the designated surface at a SLOW, STEADY SPEED for 50 cm. Note the amount of force (in N) necessary to pull the object.
5. Pull the wood block with the sandpaper on it across the designated surface at a SLOW, STEADY SPEED for 50 cm. Note the amount of force (in N) necessary to pull the object.
6. Step 5 must be repeated twice more. Put your findings in a table and on the class data spreadsheet.
REPEAT STEPS 1-6 FOR EACH SURFACE!
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!!Help pleaseee!!
Two cars start at the same point and drive in a straight line for 5 km. At the end of the drive their distances are the same but their displacements are different. Explain how this could happen. Illustrate with a diagram.
The two displacements are different because their direction can be different from each other even if their magnitude is equal.
Displacement is a vector quantity. Its magnitude is equal to the distance traveled by the body only if the body always travels in straight lines. Two displacements may be different even if their magnitude is the same but the direction in which they took place is different
So as we know, 'displacement' always consists of a magnitude and a direction. Given in the question, the two cars that start at the same point have displacements with the same magnitude that is equal to 5 km. But it could be possible that their displacements are different if they drive in different directions, which seems to be the case.
-- 12 m/s² towards the right and 12 m/s² towards the left are different accelerations
-- 30 Kph South-East and 30 Kph South-West are the same speed but different velocities as their directions are different.
-- 10 km North and 10 km South are the same distance but different displacements due to the same reasons.
Therefore the two displacements are different because their direction can be different from each other even if their magnitude is equal.
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CAN SOMEONE PLEASE HELP ME WITH THIS GRADE 11 PHYSICS ASSIGNMENTTTTTT
The value of the normal force on the object of mass 50 kg such that it experiences a friction force of 5 Newton is equal to 490 Newton.
What is friction force?Friction force is a force that opposes the force. It acts in the direction opposite to the intention of the motion of the object ,it is a non conservative force in nature.
What is Normal force?Normal force is a type of force that's perpendicular to the surface of the object when it is placed in contact with another surface the SI unit of normal force is the same as force in general that is Newton.
Given:
Surface area of the sphere = 6 u
Mass of the sphere = 50 kg
First we use the mass value of the sphere, we will calculate the value of the weight of a sphere so that we know force against which against which the normal force will be acting.
Weight of the sphere = 50 × 9.8
Weight of the sphere = 490 Newton
Now since the normal force is being used to balance of the weight of the sphere we can say that the value of the normal force will be equal to 490 Newton.
Therefore, The value of the normal force on the object of mass that it experiences a friction force of 5 Newton is equal to 490 Newton.
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Karen is asked to look at two spots of light and judge which one gets brighter over time. Both spots start out at 100 units of brightness. She notices that the right spot is brighter when it is 110 units. If she is presented with two new spots of light both starting at 300 units, how much brighter will one have to get before she will be able to reliably detect the difference?.
One of the light spots will have to get 330 units brighter than the other for her to be able to tell the difference.
In the case of the first bulb, she noticed the difference when the right was 0.10 % brighter than the other one.
100 * 0.10 = 10
100 + 10 = 110
If we apply the same sense in the second case, one of the spots will have to be 0.10% brighter than the other.
300 * 0.10=30
300+30 = 330
In order to tell the difference, the other spot should be at 330 units of brightness.
The unit of brightness is Lumen. It is use to calculate the total amount of brightness emitted from a source over a unit of time.
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a baseball is thrown straight into the air with an initial velocity of 85 mph. How far will the ball travel if it takes 5.4 seconds to land?
A) 316.0 m
B) 179.3 m
C) 432.5 m
D) 62.71 m
D. The distance traveled by the baseball during the given time is 62.32 m.
Distance traveled by the baseball
The distance traveled by the baseball is calculated as follows;
s = vt - ¹/₂gt²
where;
s is the distance traveled by the baseballv is the initial velocity of the baseballg is acceleration due to gravityt is the time of motion of the baseballThe given parameters;
v, initial velocity of the baseball = 85 mph = 38 m/s
g is acceleration due to gravity = 9.8 m/s²
t is the time of motion, = 5.4 seconds
Substitute the given parameters and solve for the distance travelled by the baseball as shown below.
s = (38 m/s)(5.4 s) - ¹/₂(9.8 m/s²)(5.4 s)²
s = 205.2 - 142.88
s = 62.32 m
Thus, the distance traveled by the baseball during the given time is 62.32 m.
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You are driving down the road at a constant speed. Another car going a bit faster catches up with you and passes you. Choose the correct position graph for both vehicles on the same set of axes, and notes the point on the graph where the other vehicle passes you.
Answer: Option 4 (last graph)
Explanation:
1. Since you're driving at a constant speed, the line for your car will be linear. This rules out the first option.
2. This is a position time graph (x-t) graph. This means that to be moving forwards, there should be a positive slope. Option 3 can be eliminated as your car has a slope of 0. A slope of 0 on a position time graph shows an object at rest, not an object in motion.
3. The 2nd option can be ruled out as it represents that you are going faster than the other car. The steeper the slope = the faster the speed.
4. This ultimately leaves you with the last option as your final answer!
A rock is dropped from a cliff and takes 6 seconds to hit the ground. At what time is the speed of the rock the highest??
Answer:
Time to reach ground = t = 6 sec
Explanation:
Acceleration due to gravity = g = 9.8 m/s²
Initial Velocity of the Rock = Vi = 0 m/s (Because, the rock will be at rest, initially)
When a rock is dropped and takes 6 seconds to touch the ground, its maximum speed will be [tex]6^{th}[/tex] second.
The force of gravity causes a rock to accelerate when it is dropped from a cliff. On Earth, the acceleration caused by gravity is roughly 9.8 meters per second squared (m/s2). This indicates that the rock's speed increases by 9.8 m/s per second as it falls.
According to the question, it takes the rock 6 seconds to hit the ground. It takes the rock exactly this long to fall from the cliff to the ground.
One must comprehend that the rock's speed rises steadily as it falls in order to determine the moment at which it is moving at its fastest. The rock's initial velocity (Vi) is 0 m/s because it begins at rest. The acceleration brought on by gravity causes it to move faster as it drops.
The rock will reach its highest speed just before it touches the ground because its velocity is constantly rising. As a result, the rock is moving at its fastest at the moment of impact (t = 6 sec).
Thus, the maximum speed will be at T= 6 seconds.
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A truck driver has a shipment of apples to deliver to a destination 500 miles away. The trip usually takes him 9.0 hours. Today he finds himself daydreaming and realizes 110 miles into his trip that that he is running 20 minutes later than his usual pace at this point.
At what speed must he drive for the remainder of the trip to complete the trip in the usual amount of time?
The speed at which the driver must drive for the remaining time to complete the trip in the usual time is 61.25 miles per hour.
What are the total distance the driver needs to cover and the approximate time?The total distance the driver should cover is 500 miles and this should be completed in 9 hours.
What is the regular speed?
Based on the information provided, the regular speed is:
500 miles/ 9 hours = 55.55 miles per hourHowever, we know today he has covered 110 miles and he is 20 minutes late. This means, there are 390 miles to cover and the remaining time is 6.7 hours.
500 miles= 9 hours or 540 minutes110 miles = x118.8 minutes + 20 extra minutes = 138.8 minutes = 2.3 hours9 hours - 2.3 hours = 6.7 hoursBased on this, let's calculate the new speed:
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True or False: A "reference point" is needed to determine the position of an object.
if false please tell me the correct word(s) to replace reference point.
Answer:
it should be true
Explanation:
:) hope it's right
How far did car A travel in the time interval t = 0 to t = 6?
Answer: Problem 03.043 - Velocity-time graph The figure shows a plot of vx(for a car traveling in a straight line. Vx (m/s) 20 | 15 20 7(s) What is aav.x between t = 9.00 s and t = 110 s? 7 m/s2 What is Vav,x for the time interval from t= 9.00 s to r= 110 s? What is Vav.x for the interval t = 0 to t= 15.0 s? m/s What is the increase in the car's speed between 10.0 s and 15.0 s? m/s How far does the car travel from time t = 100 s to t = 170 s?
The answer is 03.043 but i dont know maybe my brain is incorrect but I got 03.043. :| hope it helped if its correct.
Explanation: Well, I havent done math in a while bc im not in school anymore so i forgot all that stuff :|
steam is accelerated in a steady-flow nozzle from a low velocity to a velocity of 210 m/s at a rate of 3.2 kg/s. if the temperature and pressure of the steam at the nozzle exit are 200 ºc and 600 kpa, what is the exit area of the nozzle?
The exit area of the nozzle is 0.000861 m² which is calculated using ideal gas equation.
What is an ideal gas?
Velocity = 280 m/s
Rate = 2.5 kg/s
Pressure = 2 MPa
Temperature = 400°C
Using equation of Ideal gas
PV= RT
V= RT/P
V= 0.0965 [tex]m^{3}[/tex]/ kg
Using equation of continuity
(dm/dt) = [tex]A_{1}[/tex]v/V
[tex]A_{1}[/tex]= 0.000861 [tex]m^{2}[/tex].
A theoretical gas known as an ideal gas is made up of several randomly moving point particles with no interparticle interactions. Because it abides by the ideal gas law, a condensed equation of state, and is amenable to statistical mechanics analysis, the ideal gas concept is helpful.
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Two kg of refrigerant 134a undergoes a polytropic process in a piston–cylinder assembly from an initial state of saturated vapor at 2 bar to a final state of 12 bar, 80°c. Determine the work for the process, in kj.
The work done by polytropic process is -69.88 kJ.
The work for the polytropic process is determined using
P . v^n = constant.
where P is pressure, V is specific volume
As we know that
W = m∫Pdv
W = m(P2v2 - P1v1) / (1 - n)
In order to evaluate this expression, we need to determine the specific volumes and the polytropic exponent, n.
State 1: v1 = vg1 = 0.0993 m3/kg
State 2: at 12 bar, 80oC; v2 = 0.02051 m3/kg
Hence by using polytropic exponent
P1 / P2 = (v2 / v1)^n
n = ln(2/12) / ln(0.02051/0.0993)
n = 1.136
Find the work done
W = m(P2v2 - P1v1) / (1 - n)
W = 2kg(12bar . 0.02051m³/kg - 2 . 0.0993) / (1 - 1.136) x (10⁵ N/m²/1 bar) x (1 kJ / 10³ Nm)
W = -69.88 kJ
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An ocean liner is cruising at 10 meters/second and is about to approach a stationary ferryboat. A parcel is released from the ocean liner from a height of 5.5 meters above the ferryboat’s deck. Calculate the distance at which the ferryman should position the boat from the point horizontally below the point of release so that the parcel lands inside the boat.
Answer:
If a stream channel is 5 meters wide and 3 meters deep, and the velocity of the water moving through the channel is 10 meters/second, what is the stream's discharge (include units)? ... and deposition (point bars) occurs on the inside
Explanation:
The road is 6 kilometers long. How
long is the road in meters?
Answer:
6000 meters
Explanation:
Because 6kilometers is 6000 maters
If Tim walks to the mailbox 600 m south and then to his
neighbor's house 300 m north and the entire trip takes him 5
minutes, then what is his average velocity?
a 2 m/s
b 3 m/s
C 60 m/s
d 1 m/s
What’s the answer ???
The average velocity of Tim is 1 m/s.
What is average velocity?Average velocity is the ratio of total displacement to total time.
The S.I unit of velocity is m/s.
To calculate the average velocity, we use the formula below.
Formula:
v = (D-d)/t.........equation 1Where:
v = Average velocityFrom the question
Given:
D = 600 md = 300 m t = 5 munites = 300 sSubstitute these values into equation 1
v = (600-300)/300v = 300/300v = 1 m/sHence, the average velocity of Tim is 1 m/s.
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Use differentials to estimate the amount of metal in a closed cylindrical can that is 10 cm high and 4 cm in diameter if the metal in the top and bottom is 0. 1 cm thick and the metal in the sides is 0. 05 cm thick.
The amount of metal in a closed cylindrical can that is 10 cm high and 4 cm in diameter if the metal on the top and the bottom is 0.1 cm thick and the metal on the sides is 0.05 cm thick is 8.8 cm.
The formula for calculating the volume of a cylinder is given below.
V = πr^2 h
Get the differential of the volume as shown:
dV = V/ h dh + V / r dr
V/ h = πr^2
V/ h = 2 πr h
Now, the differential becomes
dV = πr^2dh + 2πrh dr
Given the following parameters i.e. diameter and height
dh = 0.1 + 0.1 = 0.2 cm
dr = 0.05 cm
h = 10 cm
d = 4 cm
r = 2cm
Substituting the values in the above equation, we get
dV = 3.14(2)^2(0.2) + 2(3.14)(2)(10)(0.05)
dV = 2.512 + 6.28
dV = 8.792 cm
dV = 8.8 cm
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A car acccelerates at 4m/s/s. Assuming the car starts from rest, how much time does it need to accelerate to a speed of 40 m/s?
A car is travelling with a acceleration of 4 m/s². Assuming the car starts from rest, The time need to accelerate to the speed of 40 m/s is (t)=10 s.
What is time?Time is a scalar quantity. its shows the period when the process happened. It can be measured in hour, minute, seconds etc.
How can we calculate the time?To calculate the time need to accelerate to the wanted speed we are using the formula, v=u+at
Here we are given,
u= the initial velocity of the car = 0m/s [Note: the car starts from rest]
a= the acceleration of the car = 4 m/s².
v= the final velocity of the car = 40 m/s.
we have to calculate the time need to accelerate to the wanted speed =t
Now, we put the values in the above equation,
v=u+at
Or, t= v/a [Note: u=0]
Or, t= 40/4
Or, t=10 m/s.
From the above calculation, we can say that the time need to accelerate to the wanted speed is (t)=10 s
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Helium-4 and Lithium -6 fuse to form a new product.
The graph below shows Claire's speed during a parachute jump. At certain points the force of Claire's weight balanced the force of air resistance. Add up the numbers of these points (e.g. 1 and 3 and 5 would be 9).
What's the answer?
The points at which Claire's weight balanced the force of air resistance are 2, 3 and 5. The sum of these points is 10.
What is force?We know that force is a vector quantity. This implies that force has both magnitude and direction. The direction of the force determines the sign that the force would carry. In this case there are two forces that acts on Claire as she jumps out of the parachute. These two forces are the Claire's weight balanced and the force of air resistance.
The two forces tend to act in the opposing directions. The points at which the two forces are balanced, the speed time graph shows a plateau to indicate that the speed is not changing with time.
The points at which Claire's weight balanced the force of air resistance are 2, 3 and 5. The sum of these points is 10.
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During which of the following intervals is no unbalanced force acting on the car?
The friction force that is exerted on the car's rotating wheels causes an imbalanced force to be applied to the vehicle, which then accelerates. The center of the circle the car is turning is the target of both the unbalanced force and the acceleration. Your body, however, continues to move and is in motion.
An object's motion may vary if an imbalanced force is applied to it. The small car will alter speed, direction, or even halt if a heavier, faster toy car moves into its path or along its side. The small toy car is being subjected to a stronger force, which is why its motion has changed.
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