ANSWER ASAP
1. Based on the patterns you observe in the figure, what do you think the number inside each box represents? What do you think the circles and dots represent?

Answer:

I think it will carbon hope it helps

Answer:

16.8 L

Explanation:

From the question given above, the following data were obtained:

Number of mole of He = 0.750 mole

Volume of He =?

Recall:

1 mole of any gas occupy 22.4 L at STP. This also implies that 1 mole of He occupies 22.4 L at STP.

Finally, we shall determine the volume occupied by 0.750 mole of He. This can be obtained as follow:

1 mole of He occupied 22.4 L at STP.

Therefore, 0.750 mole of He will occupy = 0.750 × 22.4 = 16.8 L at STP.

Thus, 0.750 mole of He is equivalent to 16.8 L

Answer:

jayfeather friend me

Explanation:

Table 1. Summary of the Straight-Chain Alkanes

Name Formula Number of Structural Isomers

Octadecane C18H38

Nonadecane C19H40

Eicosane C20H42 366,319 (!)

29 more rows

The formula of the alkanes the molecule contains 28 hydrogen atoms is [tex]C_1_3H_2_8[/tex], i.e., tridecane.

Alkanes are organic compounds made up entirely of single-bonded carbon and hydrogen atoms with no other functional groups.

Alkanes have the general formula CnH2n+2 and are classified into three types: linear straight-chain alkanes, branched alkanes, and cycloalkanes.

Alkanes are important raw materials in the chemical industry and the main component of gasoline and lubricants.

Natural gas is primarily composed of methane and ethane and is used for heating, cooking, and power generation (gas turbines).

Natural gas and petroleum are separated from the alkanes. Natural gas is primarily composed of methane, with trace amounts of other low molecular weight alkanes.

All other alkanes are derived from petroleum, which is a complex mixture of many compounds.

Here, the formula for 28 hydrogen atom containing alkane is

[tex]C_1_3H_2_8[/tex]

Thus, this given formula is of tridecane.

For more details regarding alkanes, visit:

https://brainly.com/question/4260635

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Answer:

80grams

Explanation:

RAM of O=16

molar mass of O2= 16×2=32g/mol

mass= mole × molar mass

= 2.5×32= 80g

Answer:A) After the values are added, we determine how many significant figures are involved by looking at the decimal places of the original values. 52.13 had only 2 digits past the decimal point so the answer can only contain 2 significant numbers after the decimal point which would be 53.88 g

Explanation:

Answer:

Physical science, in turn, can be divided into chemistry and physics. Chemistry is the study of matter and energy at the scale of atoms and molecules. ... Physics is the study of matter and energy at all scales—from the tiniest particles of matter to the entire universe but i dont really know if there is new information to discover

Explanation:

hope it help and if it doesnt sorry ;)

Answer:

the molar mass of propane (c3H8) is

12*3+1*8

=36+8=44

Answer:

A substance is a pure single form of matter. It cannot be separated into other kinds of matter by any physical process.

Answer:

2.69 * 10^-6 Mol/L

Explanation:

The equation of the reaction is;

Cl2CHCO2CH3 -------------------> Cl2CHCO2H + CH3OH

To convert from ppm concentration to Mol/L, we have

M = ppm/MM * 1000

Where;

M = mol/l

MM= Molar mass

M = 1/142.97 g/mol * 1000 =

M= 6.99 * 10^-6 Mol/L

For first order reaction;

ln[A] = ln[A]o -kt

Given that

[A]o = 6.99 * 10^-6 Mol/L

[A]=??

k= 2.7 x 10-4/sec

t= 30 mins * 60 = 1800 s

ln[A] = ln[6.99 * 10^-6] -   (2.7 x 10-4 * 1800)

ln[A] = -11.87 - 0.486

ln[A] = -12.356

[A] = e^(-12.356)

[A] = 4.3 * 10^-6 Mol/L

Concentration of methanol present after 30 mins= 6.99 * 10^-6 - 4.3 * 10^-6 = 2.69 * 10^-6 Mol/L

The question is incomplete, the complete question is;

Suppose 1.87g of nickel(II) bromide is dissolved in 200.mL of a 52.0mM aqueous solution of potassium carbonate. Calculate the final molarity of nickel(II) cation in the solution. You can assume the volume of the solution doesn't change when the nickel(II) bromide is dissolved in it. Be sure your answer has the correct number of significant digits. The answer is needed in M.

Answer:

0.0428 M

Explanation:

The equation of the reaction is;

NiBr2 + K2CO3 → NiCO3 + 2KBr

Number of moles of NiBr2 = mass/molar mass = 1.87 g/218.53 g/mol =

8.557 *  10^-3 moles

Now, we know that the Ni^2+ comes from the NiBr2. Also, the concentration of Ni^2+ in NiBr2 = concentration of Ni^2+ in NiCO3

So,

Concentration of Ni^2+ = 8.557 *  10^-3 moles/0.2 L = 0.0428 M

Answer:

The roman numeral in copper(I) oxide indicates that the oxidation number of copper in the compound is 1.

Explanation:

Roman numeral is used to indicate the oxidation number of an element in a compound.

The roman numeral in copper(I) oxide indicates that the oxidation number of copper in the compound is 1.

This can be seen from the following illustration:

copper(I) oxide => Cu₂O

Oxidation number of O = –2

Oxidation number of Cu₂O = 0

Oxidation number of Cu =?

Cu₂O = 0

2Cu + O = 0

2Cu – 2 = 0

Collect like terms

2Cu = 0 + 2

2Cu = 2

Divide both side by 2

Cu = 2/2

Cu = 1

Thus, we can see that the oxidation number of Cu in Cu₂O is 1. Hence the name of Cu₂O is copper(I) oxide indicating that the oxidation number of of copper (Cu) in the compound is 1.

For copper(II) oxide, we shall determine the oxidation number of Cu. This can be obtained as follow:

copper(II) oxide, CuO => CuO

Oxidation number of O = –2

Oxidation number of CuO = 0

Oxidation number of Cu =?

CuO = 0

Cu + O = 0

Cu – 2 = 0

Collect like terms

Cu = 0 + 2

Cu = 2

Thus, the oxidation number of Cu in CuO is 2. Hence the name of CuO is copper(II) oxide indicating that the oxidation number of of copper (Cu) in the compound is 2.

From the above illustrations,

We can see that the roman numeral in both copper(I) oxide, Cu₂O and copper(II) oxide, CuO are different because the oxidation number of Cu in both cases are different.

Answer: A: Has little to no reaction; might turn slightly red in color. B: The liquid grows darker in color to a more reddish tone.

Explanation: I didn’t have the necessary materials to complete the experiment so the teacher told me and I put it in my own words.

Answer:

See explanation and image attached

Explanation:

The  Gilman reagent is a lithium and copper (diorganocopper) reagent with a general formula R2CuLi.  R is an alkyl or aryl group.

They are useful in the synthesis of alkanes because they react with organic halides to replace the halide group with an R group.

In this particular instance, we intend to synthesize propylcyclohexane. The structure of the  lithium diorganocopper (Gilman) reagent required is shown in the image attached to this answer.

Explanation:

Moreover, increasing use of fossil fuels also causes serious environmental problems. Hence, there is a pressing need to use renewable energy sources like solar energy, wind, tide, biomass and energy from waste material. (i) it reduces the dependence on fossil fuels for energy. (ii) they donot produces pollution.

Answer:

2812.6 g of H₂SO₄

Explanation:

From the question given above, the following data were obtained:

Mole of H₂SO₄ = 28.7 moles

Mass of H₂SO₄ =?

Next, we shall determine the molar mass of H₂SO₄. This can be obtained as follow:

Molar mass of H₂SO₄ = (1×2) + 32 + (16×4)

= 2 + 32 + 64

= 98 g/mol

Finally, we shall determine the mass of H₂SO₄. This can be obtained as follow:

Mole of H₂SO₄ = 28.7 moles

Molar mass of H₂SO₄ =

Mass of H₂SO₄ =?

Mole = mass / Molar mass

28.7 = Mass of H₂SO₄ / 98

Cross multiply

Mass of H₂SO₄ = 28.7 × 98

Mass of H₂SO₄ = 2812.6 g

Thus, 28.7 mole of H₂SO₄ is equivalent to 2812.6 g of H₂SO₄

Answer:

yes

Explanation:

due to gravity &hggggggggg%ggghhbvvvghh

Answer:

1 a

2 b

3 a

4. c

Explanation:

Answer: the answer is C

Explanation:

Answer:C

Explanation:I got it correct

Answer:

A wheel and axle is a simple lifting machine that consists if rope that unwind a wheel onto a cylindrical drum/ shaft to provide mechanical advantage.

wheel and axle is a simple machine having two co-axial cylinder of different radii fitted to a common axies.

Answer:

i wish i know

Explanation:

i wish i know

Answer:

150.17 g/mol

Explanation:

Answer:

The final balanced equation is

Ni2+ + 2NaOH --> Ni (OH)2 + 2Na+

Explanation:

It is given that sodium hydroxide is added to collect the solid nickel(II) hydroxide product

The empirical equation for this statement is

Ni2+ + NaOH --> Ni (OH)2 + Na+

We will first balance the hydroxide molecule. On the right side there are two OH molecules.

Thus, on the left side we will take 2 sodium hydroxide

Ni2+ + 2NaOH --> Ni (OH)2 + Na+

Now we will balance the sodium ion which are 2 in numbers on the left side and 1 on the right side

Ni2+ + 2NaOH --> Ni (OH)2 + 2Na+

So, the final balanced equation is

Ni2+ + 2NaOH --> Ni (OH)2 + 2Na+

Answer:

44.84 ml

Explanation:

14.86

+

15.0

+

14.980

_______

44.84

Answer:

Lithium oxide, Li₂O.

Explanation:

Hello!

In this case, according to the given amounts, it is possible to write down the chemical reaction as shown below:

[tex]M_2O+H_2 \rightarrow 2M+H_2O[/tex]

Which means that the metallic oxide has the following formula: M₂O. Next, we can set up the following proportional factors according to the chemical reaction:

[tex]5.00gM_2O*\frac{1molM_2O}{(2x+16)gM_2O}*\frac{2molM}{1molM_2O}*\frac{xgM}{1molM} = 2.32gM[/tex]

Thus, we perform the operations in order to obtain:

[tex]\frac{10x}{2x+16}=2.32[/tex]

So we solve for x as shown below:

[tex]10x = 2.32(2x+16)\\\\10x = 4.64x+37.12\\\\x = \frac{37.12}{10-4.64}\\\\x= 6.93 g/mol[/tex]

Whose molar mass corresponds to lithium, and therefore, the metallic oxide is lithium oxide, Li₂O.

Best regards!

Answer:

0.011mole

Explanation:

Given parameters:

Mass of potassium in the banana = 0.42g

Unknown:

Number of moles of potassium in the banana = ?

Solution:

To solve this problem, we use the expression below:

     Number of moles  = [tex]\frac{mass}{molar mass}[/tex]  

Molar mass of K  = 39g/mol

   Number of moles  = [tex]\frac{0.42}{39}[/tex]   = 0.011mole