5,000 joules of thermal energy were applied to 1-kg aluminum bar. What was the temperature increase?

Answers

Answer 1

Answer:

ΔT = 4.9°C

Explanation:

The thermal energy of the bar can be given as follows:

Thermal Energy = mCΔT

where,

m = mass of bar = 1 kg

C = specific heat capacity of aluminum = 1020 J/kg.°C

ΔT = Change in Temperature = ?

Therefore,

5000 J = (1 kg)(1020 J/kg.°C)ΔT

ΔT = (5000 J)/(1020 J/°C)

ΔT = 4.9°C


Related Questions

A train is traveling at a speed of 80\,\dfrac{\text{km}}{\text{h}}80 h km ​ 80, start fraction, start text, k, m, end text, divided by, start text, h, end text, end fraction when the conductor applies the brakes. The train slows with a constant acceleration of magnitude 0.5\,\dfrac{\text{m}}{\text{s}^2}0.5 s 2 m ​ 0, point, 5, start fraction, start text, m, end text, divided by, start text, s, end text, squared, end fraction. We want to find the distance the train travels from the time the conductor applies the brakes until the train comes to a complete stop. Which kinematic formula would be most useful to solve for the target unknown? Choose 1 answer:

Answers

Answer:

The distance the train travels before coming to a (complete) stop = 40/81 km which is approximately 493.83 meters

Explanation:

The initial speed of the train u = 80 km/h = 22 2/9 m/s = 22.[tex]\bar 2[/tex] m/s

The magnitude of the constant acceleration with which the train slows, a = 0.5 m/s²

Therefore, we have the following suitable kinematic equation of motion;

v² = u² - 2 × a × s

Where;

v = The final velocity = 0 (The train comes to a stop)

s = The distance the train travels before coming to a stop

Substituting the  values gives;

0² = 22.[tex]\bar 2[/tex]² - 2 × 0.5 × s

2 × 0.5 × s = 22.[tex]\bar 2[/tex]²

s = 22.[tex]\bar 2[/tex]²/1 = 493 67/81 m = 40/81 km

The distance the train travels before coming to a (complete) stop = 40/81 km ≈ 493.83 m.

Answer:

v^2=v0^2+2aΔx

Explanation:

cuz khan academy says so

How does the observed pitch of the buzzer change as it moves
observer?
pitch of the buzzer increased (higher tone) as it moves towards the observer
The pitch of the buzzer decreased (lower tone) as it moves towards the observer
The pitch of the buzzer stayed the same no matter where it was in relationship
to the observer

Answers

The answer is

Pitch of the buzzer increased (higher tone) as it moves towards the observer

The correct option that explains the change in the observed pitch of the buzzer as it moves  towards the observer is;

A; pitch of the buzzer increased (higher tone) as it moves towards the observer

This is based on the concept of doppler effect which is defined as the change in frequency/pitch of a sound that is heard by an observer due to the fact that the sound source and the observer have different velocities with respect to the medium  through the sound travels.

Now, according to doppler effect, when the source of the sound moves towards the observer, the frequency will increase due to the fact that the time between successive sound waves is shortened. Thus, this means that the pitch will be higher.

However, when the sound source moves away from the observer, the frequency would decrease due to the fact that the time between successive sound waves or the crest is now longer. Thus, the pitch will decrease.

In conclusion, the pitch of the buzzer will increase as it moves towards the observer.

Read more at; https://brainly.com/question/3826119

Imagine you are running PE class. You run the first 1000 meters in 3 minutes and then get tired and run the last 600 meters in 5 minutes. What was your *average* speed?

Answers

Answer:

Va = 3.77 [m/s]

Explanation:

We know that speed is defined as the relationship between the distance traveled in a given time.

v = L/t

where:

v = speed [m/s]

L = distance = 1000 [m]

t = time = 3 [min] = 180 [s]

Therefore the first speed is:

v = 1000/180

v = 5.55 [m/s]

Now the second velocity:

t = 5 [min] = 300 [s]

v = 600/300

v = 2 [m/s]

The average speed is calculated by the sum of both speeds divided by two.

Va = (5.55 + 2) /2

Va = 3.77 [m/s]

A box weighing 12,000 N is parked on a 36° slope. What will be the component of the weight parallel to the plane that balances friction *


Fg sin 36 degrees
Fg cos 36 degrees
Fg tan 36 degrees
Fg x N

Answers

Given :

A box weighing 12,000 N is parked on a 36° slope.

To Find :

What will be the component of the weight parallel to the plane that balances friction.

Solution :

The component of that will be parallel to the plane to balance friction is :

[tex]F \ cos ( 90 - 36)^o\\\\F\ ( sin\ 36^o)[/tex]

Therefore, component of force to balance friction is F sin 36° .

Hence, this is the required solution.

i would appreciate it if u would answer

Answers

Answer:

A) Kinetic energy and gravitational energy

Explanation:

The blimp has kinetic energy, because it is moving. When it circles the event, it gains and uses kinetic energy. It also has potential energy because it has the potential to go a lot faster, and because it has so much stored energy and pressure.

Hope this helps!

The number of waves that pass a given point in a second is___.

1- amplitude
2- wavelength
3- frequency
4- wave speed

Answers

Answer:

Frequency

Explanation:

The frequency ( ) of a wave is the number of waves passing a point in a certain time.

A farmer is pushing a 75 kg plow across a field with 700 N at an angle of 35 degrees above the ground. If the kinetic frictional force between the plow and the field is 250 N. What is the Normal Force from the ground onto the plow? And what is the acceleration of the plow?

Answers

Given :

A farmer is pushing a 75 kg plow across a field with 700 N at an angle of 35 degrees above the ground.

The kinetic frictional force between the plow and the field is 250 N.

To Find :

The Normal Force from the ground onto the plow.

The acceleration of the plow.

Solution :

Normal force = mg + F sin Ф

= 75×10 + 700 × sin 35°

= 1151.50 N

Now,

ma = 700 cos Ф - 250

75×a = 323.4

a = 4.31 m/s²

Hence, this is the required solution.

What is the net force on this box?

Answers

Answer:

I believe 0

Explanation:

this is due to the fact that the box will not move anywhere the forces are canceling themselves out.  


Find the range of a projectile launched at an angle of 30° with an initial velocity of 20m/s.​

Answers

Answer:

The range is 35.35 m

Explanation:

Projectile Motion

It's the type of motion that experiences an object projected near the Earth's surface and moves along a curved path exclusively under the action of gravity.

Being vo the initial speed of the object, θ the initial launch angle, and [tex]g=9.8m/s^2[/tex] the acceleration of gravity, then the maximum horizontal distance traveled by the object (also called Range) is:

[tex]\displaystyle d={\frac {v_o^{2}\sin(2\theta )}{g}}[/tex]

The projectile was launched at an angle of θ=30° with an initial speed vo=20 m/s. Calculating the range:

[tex]\displaystyle d={\frac {20^{2}\sin(2\cdot 30^\circ )}{9.8}}[/tex]

[tex]\displaystyle d={\frac {400\sin(60^\circ )}{9.8}}[/tex]

[tex]d=35.35\ m[/tex]

The range is 35.35 m

Which of the following is the best example of positive peer pressure?

Answers

Answer:

1.Your friend says "no thanks" to the dinner your dad cooked and prefers to just hang out with friends instead.

2. Your teammates keep making fun of you for spending so much time studying for Friday's math test.

3. Your coworkers spend every weekend watching movies at Tim's house and invite you to join them.

4. Your friends all sign up for a free class at the gym and suggest you sign up for it, too.

kinetic energetic plus potential energy is called

Answers

Object mechanical energy

if you walk at an avaerage speed of 5 km/h for 30 min how far will you walk

Answers

Answer:

2.5 km/30min

Explanation:

Divide 5 by 2 because 30  min is half of 1 hour. when you do that you get 2.5

There is a ball at rest on a flat floor. What kind of equilibrium is it in? *

Stable Equilibrium
Unstable Equilibrium
Neutral Equlibirum
Not in Equilibrium

Answers

answer : neutral equilibrium

John walks four kilometers east, two kilometers north as shown in the diagram below. What is John’s displacement

4 km

11 km

2 km north

7 km east

Answers

not 100% positive, but i believe 7 km east?
I think its 7 km east

Help on this pls. !!!!!

Answers

Answer:

C

Explanation:


W1 has a weight of 220 N acting 0.6m away from the pivot.
How far does W2 whose weight is 180 N need to sit for the see
saw to be in equilibrium.
&
?
W-220 N
W2 - 180N
a) 0.3 m
Ob) 0.73 m
C) 0.5m
O d) 0.83 m

Answers

Answer:

0.73m

Explanation:

Given parameters:

W1  = 220N

D1  = 0.6m

W2 = 180N

Unknown

D2 = ?

Solution:

The torque on each side must be balanced;

 Torque  = force x distance

     T₁   = T₂  

  W1  x D1  = W2 x D2

Insert the parameters and solve for D2;

   220 x 0.6  = 180 x D2

     132  = 180D2

     D2 = [tex]\frac{132}{180}[/tex]   = 0.73m

Which type of carbohydrate is the body unable to digest, but is still important for lowering cholesterol, balances glucose levels, and helps prevent overeating.

Answers

Answer:

Cellulose

Explanation:

Cellulose is the carbohydrate which is unable to be digested by body. Adding fiber's (cellulose)  to one's diet reduces blood cholesterol level because soluble fiber  dissolves in water to form a gel, which moves slowly through the intestines binding up fat, dietary cholesterol, bile salts, and sugar to be excreted. Once excreted, these are no longer available to build more cholesterol. Also cellulose remains undigested but is effectively making one gain more calories, so it helps prevents over eating.

A bugatti chiron travels 116 m/s for 10 seconds.how far did it travel

Answers

Answer:

V=  1,160 m

Explanation:

formula:

            V=  V*  T

remplazamos:

V= 116m /s * 10s

V=  1,160 m

Answer:

V=  1,160 m

Explanation:

A race car accelerates uniformly from 18.5 m/s to 46.1 m/s in 2.47 seconds.
Determine the acceleration of the car and the distance traveled.

Answers

Answer:

79.8 is the answere

I hope this HELP :)

Explanation:

Here, initial velocity is u=18.5m/s and final velocity is v=46.1m/s

Time taken t=2.47s

If a be the acceleration of the car.

Using v=u+at,

46.1=18.5+a(2.47)

⟹ a=11.17m/s

2

If d be the distance traveled by car.

Using formula v

2

−u

2

=2ad,

(46.1)

2

−(18.5)

2

=2(11.17)d

⟹ d=79.8m

Which statement is correct about two objects that have gravitational force?
They have mass.
They move slowly.
They are round in shape.
They have high temperature.



Answers

Answer:

1 and 2

Explanation:

The formula itself has nothing to do with shape or temperature. The formula does have mass and the speed depends on the how great the mass/radius is.

They have mass
They move slowly
A and B

A motor with a resistance of 320 is connected to a voltage source. Four amps of current flows
in the circuit. What is the voltage of the source?
I

Answers

Answer:

V = 1280 [V]

Explanation:

To solve this problem we must use ohm's law which tells us that the voltage is equal to the product of the resistance by the current.

Therefore we have:

V = I*R

where:

V =  voltage [V] (Units of volts)

I = current = 4 [amp]

R = resistance = 320 [ohms]

V = 4*320

V = 1280 [V]

Lucia kicks a ball on a level playing field with an initial velocity of 11.3 m/s at an angle of 35° above the horizontal. Find: Time of flight? Horizontal distance traveled? Maximum height?

Answers

Explanation:

Given that,

Initial velocity, u = 11.3 m/s

Angle above the horizontal, [tex]\theta=35^{\circ}[/tex]

Time of flight :

[tex]t=\dfrac{2u\sin\theta}{g}\\\\t=\dfrac{2\times 11.3\times \sin(35)}{9.8}\\\\t=1.32\ s[/tex]

Horizontal distance traveled  is given by :

x = ut

x = 11.3 m/s × 1.32 s

x = 14.916 m

Maximum height is given by :

[tex]H=\dfrac{u^2\sin^2\theta}{2g}\\\\H=\dfrac{(11.3)^2\times \sin^2(35)}{2\times 9.8}\\\\H=2.14\ m[/tex]

Hence, time of flight is 1.32 s, horizontal distance is 14.916 m and maximum height is 2.14 m.

what are the 5 destructive tests used in fiber analysis

Answers

Most common are destructive tests, such as stress, fatigue and micro sectioning tests. There are also methods that allow non-destructive testing (NDT), so the material can be still be used after testing. Common methods are ultrasonic, X-ray, HF Eddy Current, Radio Wave testing or thermography.

please help lol
im also on my sisters acc btw

Answers

Answer:

D. Smooth muscle

Explanation:

Smooth muscle is a type of muscle tissue which is used by various systems to apply pressure to vessels and organs. Smooth muscle is composed of sheets or strands of smooth muscle cells. These cells have fibers of actin and myosin which run through the cell and are supported by a framework of other proteins.

Can I get brainliest please since I have enough explanation

A permanent magnet picks up an iron nail, magnetizing the nail. How is this system different from an electromagnet?

Answers

Answer:the nail is magnetized by a permanent magnet instead of by a solenoid with an electric current running through it

Explanation:

The permanent magnet magnetizing the nail will differently function like electromagnet, by utilizing the electric current through the iron. Hence, option (B) is correct.

The given problem is based on the concept and fundamentals of magnetization. The term magnetizations means that the density of magnetic dipole moments induced in a magnetic material, when it is placed near a permanent magnet.

In the given problem, the magnetization of iron nail takes place by passing the current through the nail.The electric current utilize the electric charge which responds the electric field. When the current carrying nail is placed beside the permanent magnet, the dipole set up and it will create a polarity for which the nail will now itself behave as a magnet.

Thus, we can conclude that the permanent magnet magnetizing the nail will differently function like electromagnet, by utilizing the electric current through the iron. Hence, option (B) is correct.

Learn more about the magnetization here:

https://brainly.com/question/2841288

100 PTS!!! PLEASE HELP!
I need this 6 questions done!

Answers

i’m really sorry but we can’t read the problem...

Answer:

don t know

Explanation:

A periodic wave is a wave that follows a repeating pattern as it propagates through space. That is, the oscillating pattern repeats at regular intervals of time. This repeating motion is also known as periodic motion

Answers

Answer:

Simple harmonic motion

Explanation:

What is simple harmonic motion?

"Simple harmonic motion is a type of motion directed along a straight line, whose acceleration is fixed towards a point  and is proportional to its distance from that point"

An object is said to be in simple harmonic motion if the following occurs:

• It moves in a uniform path.

• A variable force acts on it.

• The magnitude of the force is proportional to the displacement of the mass.

• The force is always opposite in direction to the displacement direction.

• The motion is repetitive and a round trip, back and

  forth, is always made in equal time periods

characteristics of radiation from the sun's energy would be

A. heat from a distance source, elcetromagnatic waves and energy that travels through space.
B. Direct contact of the energy source of sufaces
C. Movement of heat through fluids
WHICH ONE IS THE ANSWER HELPPP

Answers

Answer:

Answer is A

Explanation:

Which of the following best describes a hypothesis?
O A. A question that scientists study
B. A possible answer to a scientific question
C. An explanation supported by many observations
O D. A list of scientific data

Answers

I am 99% sure it is B :)

Answer:

B. A possible answer to a scientific question

Explanation:

It's usually a possible or testable explanation made on the basis of limited evidence as a starting point for further investigation.

What is the potential energy of a rock that weighs 10.0 kg and is sitting on top of a hill 300 meters high?

Answers

PE = mgh, g= 9.8 m/s^2
10 kg * 9.8 m/s^2 * 300 m
= 29400 J

The potential energy of a rock that weighs 10.0 kg and is sitting on top of a hill 300 meters high is 29400J

POTENTIAL ENERGY:

Potential energy refers to the energy due to the position of an object. It can be calculated by using the following formula:

P.E = m.g.h

Where;

m = mass of the rock

g = gravitational force of Earth (9.8m/s²)

h = height (m)

According to this question, a rock weighs 10.0 kg and is sitting on top of a hill 300 meters high. The potential energy can be calculated as follows:

P.E = 10 × 9.8 × 300

P.E = 29400J

Therefore, the potential energy of a rock that weighs 10.0 kg and is sitting on top of a hill 300 meters high is 29400J.

Learn more: https://brainly.com/question/15613166?referrer=searchResults

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