The boy jumps horizontally off the raft with a velocity of 3.50 m/s. The raft moves in the opposite direction with a velocity of -7.70 m/s.
What is the difference between Mass and Raft?The Department of Housing and Community Development funds the RAFT Program, which prevents homelessness (DHCD). RAFT offers low-income families who are homeless or in danger of homelessness short-term financial support. This force is 67° north of east and has a magnitude of 15 N. Find the x and y components of the raft's acceleration, ignoring any water resistance. The buoyant force on the raft is equal to the weight of the water displaced according to Archimedes' principle.
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an antelope moving with constant acceleration covers the distance 80.0 m between two points in time 8.00 s. its speed as it passes the second point is 16.0 m/s.
Antelope's acceleration as it passes the second point is 1.65 m/s².
Speed: The ratio of distance to time can be used to quantify speed. M/s is the S.I. unit of speed.
Newton's equation of motion yields the following: S = (v+u)t/2.
u is the starting speed, v is the final speed, and S is the distance.
Given: v = 16.0 m/s, t = 7.10 s, S = 72 m.
making u the subject of the equation,
7.1(16+u) = 72×2
113.6+7.1u = 144
7.1u = 144-113.6
7.1u = 30.4
u = 30.4/7.1
u = 4.28 m/s
Thus the speed at the first point = 4.28 m/s .
The rate at which velocity changes is known as acceleration. M/s2 is the SI unit of acceleration.
a = (v-u)/t............................ Equation 2: acceleration is given by a.
v = 16.0 m/s, u = 4.28 m/s, and t = 7.10 s are given.
Replace in equation 2
a = (16-4.28)/7.1
a = 11.72/7.10
a = 1.65 m/s²
Thus the acceleration = 1.65 m/s².
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before going in for an annual physical, a 70.0-kg person whose body temperature is 37.0∘c consumes an entire 0.355-liter can of a soft drink (which is mostly water) at 12.0∘c.
The equilibrium temperature is required and to find whether the temperature change can be measured by a thermometer is required. The temperature is 310 K.
What is temperature ?A physical measure that describes how hot a substance or radiation is is called temperature.
There are three different types of temperature scales: those, like the SI scale, that are defined in terms of the average translational kinetic energy per freely moving microscopic particle, like an atom, molecule, or electron, in a body; those that only rely on strictly macroscopic properties and thermodynamic principles, like Kelvin's original definition; and those that are defined by practical empirical properties of particulates rather than by theoretical principles.
With a thermometer, temperature is measured. It is calibrated in a number of temperature scales that historically defined themselves using different reference points and thermometric substances. The Celsius scale, originally known as "centigrade," is the most popular scale.
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newton’s law of cooling says that the temperature of a body changes at a rate proportional to the difference between its temperature and that of the surrounding medium (the ambient temperature) where t
The temperature from t=0 to 10min with a step size of 2 min is as follows:
t (in min) 0 2 4 6 8 10
T ( in °C ) 70 68.1 66.27 64.514 62.82 61.2
We know that,
The solution of first order differential equation is
dT / dt = - k ( T - [tex]T_{a}[/tex] )
where,
T = Initial temperature
[tex]T_{a}[/tex] = Ambient temperature
Given that,
k = 0.019 / min
[tex]T_{a}[/tex] = 20 °C
Using Euler method
[tex]T_{i} ^{'}[/tex] = - 0.019 ( [tex]T_{i}[/tex] - 20 )
[tex]T_{i+1}[/tex] = [tex]T_{i}[/tex] + ( [tex]T_{i+1}[/tex] * h )
With t = 0 to 10, h = 2, the iterative solution is as follows
At i=1, [tex]t_{i}[/tex] = 0, [tex]T_{i}[/tex] = 70
[tex]T_{i} ^{'}[/tex] = - 0.019 ( 70 - 20 ) = - 0.95
[tex]T_{i+1}[/tex] = 70 - ( 0.95 * 2 ) = 68.1
At i=2, [tex]t_{i}[/tex] = 2, [tex]T_{i}[/tex] = 68.1
[tex]T_{i} ^{'}[/tex] = - 0.019 ( 68.1 - 20 ) = - 0.914
[tex]T_{i+1}[/tex] = 68.1 - ( 0.914 * 2 ) = 66.27
At i=3, [tex]t_{i}[/tex] = 4, [tex]T_{i}[/tex] = 66.27
[tex]T_{i} ^{'}[/tex] = - 0.019 ( 66.27 - 20 ) = - 0.88
[tex]T_{i+1}[/tex] = 66.27 - ( 0.88 * 2 ) = 64.514
At i=4, [tex]t_{i}[/tex] = 6, [tex]T_{i}[/tex] = 64.514
[tex]T_{i} ^{'}[/tex] = - 0.019 ( 64.514 - 20 ) = - 0.846
[tex]T_{i+1}[/tex] = 64.514 - ( 0.846 * 2 ) = 62.82
At i=5, [tex]t_{i}[/tex] = 8, [tex]T_{i}[/tex] = 62.82
[tex]T_{i} ^{'}[/tex] = - 0.019 ( 62.82 - 20 ) = - 0.8136
[tex]T_{i+1}[/tex] = 62.82 - ( 0.8136 * 2 ) = 61.2
At i=6, [tex]t_{i}[/tex] = 10, [tex]T_{i}[/tex] = 61.2
Euler's method is used for solving ordinary differential equation with a given initial value. It is a first order numerical procedure.
The given question is incomplete. The complete question is:
Newton's law of cooling says that the temperature of a body changes at a rate proportional to the difference between its temperature and that of the surrounding medium (the ambient temperature), dT/dt = -k(T-Ta) where T = the temperature of the body (°C), t = time (min), k = the proportionality constant (per minute), and Ta = the ambient temperature (°C). Suppose that a cup of coffee originally has a temperature of 70 °C. Use Euler's method to compute the temperature from t = 0 to 10 min using a step size of 2 min if Ta = 20 °C and k = 0.019/min.
Therefore, the temperature from t =0 to 10 min with a step size of 2 min is as follows:
t (in min) 0 2 4 6 8 10
T ( in °C ) 70 68.1 66.27 64.514 62.82 61.2
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Ammonia is a weak bas. Potassium hydroxide is a strong base. Which statement is correct?
A solution of potassium hydroxide will always have greater productivity than a solution of ammonia
A solution of potassium hydroxide will always have a lesser concentration of salute in a solution of ammonia
A solution of potassium hydroxide will always have a higher pH of a solution of ammonia
A solution of potassium hydroxide will always have more OH negative ions in a solution of ammonia
Ammonia is a weak base and Potassium hydroxide is a strong base, then then the solution of potassium hydroxide will always have a higher pH than a solution of ammonia, therefore the correct answer is option C.
What is a Chemical compound?A chemical compound is a combination of two or more either similar or dissimilar chemical elements.
As given in the problem, ammonia is a weak base. Potassium hydroxide is a strong base then we have to find out which statement is correct from the given list of statements,
Since ammonia is a weak base and potassium hydroxide is a strong base, their solutions will always have a higher pH than ammonia solutions. Option C is the right response.
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you are driving a car at 30\text{ m/s}30 m/s when a bad driver traveling at a constant speed of 20\text{ m/s}20 m/s swerves into your lane 2020 meters ahead. as soon as you see the car in front of you, you begin to brake. what is the smallest deceleration needed, in \text{m/s}^2,m/s 2 , to avoid rear-ending the car? you may assume your acceleration is constant
the smallest deceleration needed, in m/s^2, to avoid rear-ending the car
will we of a = -12.5m/s^2.
What is deceleration?A reduction in velocity, or momentum, is referred to as a deceleration. The slowing of a rise is referred to as a deceleration. For instance, the wind has a certain amount of momentum. We may say that the wind is decelerating when its momentum slows down, i.e., when it blows less forcefully.
To avoid rear-ending the car
Reduce final velocity of the car to less or equals to the speed of bad driver's car before car travels 20 m
Because if final velocity of car is less than or equal to the speed of bad driver's car then car can't able to cross bad driver's car.
Final velocity of the car (Vf) = 20 m/s
Using equation of motion
[tex]v^{2} _{f} = v^{2} _{i} + 2as\\ a = v^{2} _{f} - v^{2} _{i} / 2s\\= 20 ^{2} - 30 ^{2}/ 2 *20\\= -12.5m/s^{2}[/tex]
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A girl delivering newspapers covers her route by traveling 3.00 blocks west, 4.00 blocks north, and then 6.00 blocks east. what is her resultant displacement magnitude and direction?
A girl delivering newspapers covers her route by traveling so resultant displacement is 5 blocks.
CalculationHer net x (east-west) displacement is –3.00+0+6.00= +3.00 blocks, while her net y (north-south) displacement is 0+4.00+0=+4.00 blocks.
The magnitude of the resultant displacement is
R= [tex]\sqrt{x^{2} +y^{2} } =\sqrt{3^{2} + 4^{2} }[/tex] = 5 blocks
and the angle made by the resultant
= [tex]\theta[/tex] = [tex]tan^{-2} =[/tex] 4/3
= 53.1°
The resultant displacement is 5 blocks at 53.1°
How does displacement work?The term “displacement” refers to a shift in an object’s position. It is a vector quantity with a magnitude and direction. The symbol for it is an arrow pointing from the initial location to the ending place.
For instance, if an object shifts from location A to position B, its position changes.
An object’s displacement is equal to its velocity times its acceleration times its time squared plus one-half (t2).
What are distance and displacement?A scalar quantity known as distance measures “how much ground an object has traversed” while moving.
The term “how far out of place an object is” is referred to as displacement, a vector quantity.
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two parallel conducting plates are separated by 10.0 cm, and one of them is taken to be at zero volts. (a) what is the electric field strength (in kv/m) between them, if the potential 5.50 cm from the zero volt plate (and 4.50 cm from the other) is 470 v?
Based on the problem, the distance between two parallel conducting plate is x=10cm=0.10mx=10cm=0.10m
The electric fielda)
The potential difference is V= 593VV= 593V
The distance between is d=7.05cm= 0.705md= 7.05cm= 0.705m
Recall the expression for the electric field.
E= VdE= Vd
Substitute the given values in above equation.
E= 5930.705= 841.13V/ mE =5930.705 = 841.13V/Vmm
Thus, the electric field strength is 841.13V/m.841.13V/Vmm.
b)
Recall the term for the voltage between the plate.
ΔV= E× x ΔV= E×x
Substitute the given values in above equation.
ΔV=841.13V/m×0.10m=84.11VΔV=841.13V/Vmm×0.10m=84.11V
Thus, the voltage within the plate is 84.11V.
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two parallel conducting plates, each of cross sectional area 460 cm2, are 4.0 cm apart and uncharged. if 4.9 ✕ 1012 electrons are transferred from one plate to the other, what are the following? (a) the charge density on each plate (enter the magnitude in c/m2.) c/m2 (b) the electric field between the plates (enter the magnitude in n/c.) n/c
Surface Charge density on each plate sigma =+- Q/a = +4.9×10²⁴/4.6×10⁻²C/m² and Electric field is found to be 0.12×10³⁸N/C.
Given, here the cross sectional area of the conducting plate (A)
A = 460 cm² = 460 x 10-4 m² = 4.6 x10-²m² and distance between plate, d = 4.0 cm = 4x10² m²
Charge on the plate, Q = ne ,where n= 1×10¹²
Q = ± 10¹² x4.9x 10¹²c = ± 4.9x 10²⁴ c
Now, we have to find charge density on each plate sigma =+- Q/a = +4.9×10²⁴/4.6×10⁻² C/m²
σ= 1.09× 10²⁶ C/m²
Now we have to find electric field between the plates.
E= σ /E°= 1.09× 10²⁶/ 8.85×10⁻¹²
E= 0.12×1038N/C
Charge density is a measure of the amount of electric charge present in a space per unit volume in one, two, or three dimensions. The quantity of electric charge per surface area or volume, respectively, is known as the linear surface or volume charge density.
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Which is true of photosynthesis and cellular respiration
Im confused on your questions, however they both need each other to work :D
Answer:
Photosynthesis and cellular respiration are processes by which plants and animals use to create energy from food.
Photosynthesis is exclusive to plants only though. It starts with sunlight which goes through the Electron Transport Chains (ETC's) and then through a cycle known as the Calvin-Benson cycle to create glucose.
Cellular respiration (cell resp) takes the glucose made in photosynthesis (or in the case of humans, from our food) and takes it through the Krebs cycle (sometimes referred to as the Citric Acid cycle) to create Adenosine Triphosphate (ATP) which is used to give us energy.
Hope that helps.
Kriti does a work of 450 joule using the power of 1500 watt. how much time is taken to do the work?
Answer:
450
Explanation:
I think answer is 450.
For all of their diversity, many less developed countries are linked by a range of common problems. what are these problems? which do you think are the most important? why?
The major problem in a least developed country according to me is probably the low per capita income.
The problems that a less developed country faces are:
Crippling debt ( Due to low per capita income )High populationPoor infrastructureHigher usage of primary sectorA lot of these countries have poor infrastructure for other sectors than primary sector ( Eg. Agriculture, fishing etc. ). This results in exploitation of natural resources with less per capita income ( Amount of money earned per person in a region ). This leads to crippling debts, not just as a person, but as a whole nation.
Therefore, the major problem in a least developed country is probably the low per capita income.
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James defines a circle as "the set of all the points equidistant from a given point." His statement is not precise enough because he should specify that
(b) the set of points is in a plane
A circle has points in a plane, a center, a radius, and a diameter. Depending on the situation, at least one of the following words must be included in the definition of a circle:
Points in a planeRadiusCenterDiameterBased on James' definition of a circle, he needed to specify that the points are in a plane (option b).
The phrase "the set of all the points," as he defines it, has a variety of meanings. among them are:
the set of points on a line.
a plane's set of points.
the region's collection of points
James should have made it clear that the collection of points is in a plane.
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The complete question is mentioned below:
James defines a circle as "the set of all the points equidistant from a given point." His statement is not precise enough
because he should specify that
(a) a circle includes its diameter
(b) the set of points is in a plane
(c) a circle includes its radius
(d) the set of points are collinear
A block of mass 5.00 kg rests on a horizontal surface where the coefficient of kinetic friction between the two is 0.200. a string attached to the block is pulled in direction 25 degrees with horizontal, resulting in a 2.50-m/s2 acceleration by the block. find the tension in the string. (g = 9.80 m/s2)
The tension in the string is 19.8 N.
What is mass?Mass is a physical body's total amount of matter. It also serves as a gauge for the body's inertia or resistance to acceleration (change in velocity) in the presence of a net force. The strength of an object's gravitational pull to other bodies is also influenced by its mass.The kilogram is the SI unit of mass (kg). In science and technology, a body's weight in a given reference frame is the force that causes it to accelerate at a rate equal to the local acceleration of free fall in that frame.For instance, a kilogram mass weighs around 2.2 pounds at the surface of the planet. However, the same kilogram mass would weigh just about 0.8 pounds on Mars and about 5.5 pounds on Jupiter.An object's mass is a crucial indicator of how much stuff it contains. Weight is a measurement of an object's gravitational pull. It is influenced by the object's location in addition to its mass. As a result, weight is a measurement of force.Find the tension in the string:
The net force on the block will be:
T - Fr = Fnet = ma
Where T is the tension and Fr is the frictional force
T - ukR = ma
Where R is the upwards normal force equal to the block's weight. R = mg
therefore,
T - uk mg = ma
T - 0.2(5 x 9.8) = 5(2)
=> T = (0.2 x 5 x 9.8) + 5(2) = 19.8 N
This is the tension in the string.
For the free body diagram, draw a block and show a rope connected horizontally to it. The tension in the string will be along the rope outwards from the block. Now, the frictional force will be between the ground and the block and it will be in the opposite direction to the direction of tension of the rope. The force due to gravity will act vertically downwards while the normal force R will act vertically upwards.
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Calculate the weight force of the Mars vehicle when it is on Earth and when it is on Mars.
The mass of the Mars vehicle is 2500 kg.
Weight of vehicle on Earth, where g = 10 N kg-¹.
Weight of the vehicle on Earth is 6736.72 kg.
What is the weight of an object?
The weight of an object is the force exerted on it owing to gravity in science and engineering. Weight is defined as a vector quantity in certain standard textbooks, as the gravitational force exerted on the item. Others describe weight as a scalar quantity, the magnitude of gravity.
Weight on Mars = (Weight on earth/10) x 3.711
Given, weight on mars = 2500 kg
Therefore, weight on Earth = 6736.72 kg.
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A starship's engines produce 10,000 N of force. It is traveling at 10 m/s through space. If the starship drops the engine
force output to 3000 N of force, what is the ship's acceleration going to be?
If the starship drops the engine force output to 3000 N of force he ship's acceleration going to be at acceleration, a = 4.28 m/s².
Equation :In the given equation we can see the different force working on engine so,
To find the acceleration first we need the mass of engine
Using formula,
F = m x v
10,000 - 3000 N = m x 10 m/s
7000N = m x 10 m/s
m = 700 kg
Now as we have mass of the engine,
By the formula,
a = F / m
F = 3000 N
m = 700 kg
So, putting values we have :
a = 3000 / 700
a = 4.28 m/s²
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THE FIRST PERSON TO GIVE ANSWERS GETS BRAINLIEST
PLEASE HELP URGENT
Answer:
number 3
Explanation:
the effort is almost equal to the load
A car moving with an initial speed of 16 meters per second is brought to rest uniformly in 4. 0 seconds. How far does the car travel during this 4. 0-second interval?.
The car in a time of 4 seconds will travel a distance of: 32 m
The formulas for uniformly varied rectilinear motion (UVRM) and procedures we will use to solve this exercise are:
a = (vf - vi) /tx = (vf²-vi²)/ (2a)Where:
x = distancevf = final velocityvi = initial velocitya = accelerationt= timeInformation about the problem:
vi = 16 m/svf= 0 m/st = 4 sa = ?x= ?Applying the acceleration formula we have:
a = (vf - vi) /t
a = (0 m/s - 16 m/s) /4 s
a = (-16 m/s) /4 s
a = -4 m/s²
Acceleration is negative because the car is decelerating
Applying the distance formula, we get:
x = (vf²-vi²)/ (2a)
x = [(0 m/s)²- (16 m/s)²]/ (2 * -4 m/s²)
x = (0 m²/s²- 256 m²/s²)/ -8 m/s²
x = -256 m²/s²/ -8 m/s²
x = 32 m
What is acceleration?It is a physical quantity that indicates the variation of velocity as a function of time, it is expressed in units of distance per time squared e.g.: m/sec2 ; km/h2
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Which object has the least thermal energy?
OA. 5 kg of oxygen gas at 30°C
OB. 5 kg of liquid oxygen at -225°C
OC. 2 kg of oxygen gas at 20°C
OD. 2 kg of liquid oxygen at -225°C
OD. 2kg of liquid oxygen at -225 *C has the least thermal energy.
The thermal energy for a phase of matter is given by the formula
Q = mCΔT where
m = mass
C = Specific heat constant
T = Temperature
For Oxygen, the Specific heat constant = 0.92 J/gK
Let's calculate the thermal energy for each case, assuming that the initial temperature is 0 Kelvin
OA.
m= 5000 g
ΔT = 303 K
So Q =5000×0.92×303 = 1393800 J = 1393.8 KJ
OB.
m= 5000 g
ΔT = 48 K
So Q =5000×0.92×48 = 220800 J = 220.8 KJ
OC.
m= 2000 g
ΔT = 293 K
So Q =2000×0.92×293 = 539120 J = 539.12 KJ
OD.
m= 2000 g
ΔT = 48 K
So Q =2000×0.92×48 = 88320 J = 88.32 KJ
Therefore, OD 2kg of liquid oxygen at -225 *C has the least thermal energy which is 88.32 KJ.
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Answer:
2 kg of liquid oxygen at -225°C
Explanation:
B has the same temperature, yet it's more mass. So, to use this as an example--B has the most thermal energy. If the mass decreased, then the thermal energy would decrease. More mass=more thermal energy. Hence, why the mass decreasing to 2 kg would equal the least amount of thermal energy.
a ball is initially rolling up a incline with velocity 0.2 m/s. during the motion is it decelerates uniformly at 0.05 m/s² a) at what time does the ball come to a stop? a ball is initially rolling up a incline with velocity 0.2 m/s. during the motion is it decelerates uniformly at 0.05 m/s² a) at what time does the ball come to a stop?
The ball will stop after 6 s.
The initial velocity of the ball is u.
u = 0.2 m/s
Acceleration of the ball is a.
a = 0.05 m/s²
The time interval is t.
t = 6 seconds.
The displacement of the ball at time t is s.
The displacement of the ball at time t is,
[tex]s= ut + \frac{1}{2} at ^{2} [/tex]
[tex]s= 0.2 \times 6+ \frac{1}{2} \times ( - 0.05) \times (6)^{2} [/tex]
[tex]s= 0.3 \: m[/tex]
Therefore, the displacement of the ball at time t is 0.3 meters.
The time at which the ball will stop is,
Distance = Speed × Time
0.3 = 0.05 × Time
Time = 6 seconds.
Therefore, the ball will stop after 6 s.
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A typical laboratory centrifuge rotates at 4300 rpm. test tubes have to be placed into a centrifuge very carefully because of the very large accelerations. what is the acceleration at the end of a test tube that is 10 cm from the axis of rotation? for comparison, what is the magnitude of the acceleration a test tube would experience if dropped from a height of 1.0 m and stopped in a 1.0-ms-long encounter with a hard floor?
The first acceleration is 20276.6 m/s² and the second one is 4427.2 m/s².
First of all, you need to calculate the angular velocity of the centrifuge as it is needed in the formula for centripetal acceleration that is given by [tex]a = r\omega^2[/tex].The frequency is given in rotations per minute and the calculation would look like the following,[tex]\begin{aligned}\\\\\omega &= 2\pi.f\\\\&= 2\pi.\big(\frac{4300\,\text{rpm}}{60\,s})\\\\&= 450.29\, rad/s\end{aligned}[/tex]
Then simply the acceleration that the test tube experiences is calculated as follows,[tex]\begin{aligned}\\\\a &= r\omega^2 \\\\&= 0.1\, m\,\times\,(450.29\,rad/s)^2\\\\&= 20276.1\, m/s^2 \end{aligned}[/tex]
For the second part, you need to calculate the speed the test tube would acquire just before hitting the surface as a result of free fall under gravity. And that is simple as [tex]v = \sqrt{2gh}[/tex].Once it is calculated you need to divide the speed difference by the time it took until the tube came to a rest.[tex]\begin{aligned}\\\\v &= \sqrt{2.\times 9.8\,m/s^2\,\times 1.0\,m }\\\\&= 4.427\,m/s\\\\a &=\frac{\Delta v}{\Delta t}\\\\&= \frac{0-4.427\,m/s}{0.001\,s}\\\\&= -4427\, m/s^2\cdots(\text{- indicates a deceleration})\end{aligned}[/tex]
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he offense can gain the 10 yards by running, or passing the ball, or by a ________________ assessed against the opposition
Answer:
penalty
Explanation:
Penalties can gain your team yards if assessed against the opposition...their are multiple penalties which are assessed 10 yards
protein electrophoresis uses electric field to separate charged blood protein in a gel. this helps diagnoses various diseases, e.g. cancer. a protein typically has 23 excess electrons. the needed force to separate a protein is 10-14 n. the required electric field in the equipment is n/c.
The required electric field in the equipment is 35.77 * [tex]10^{17}[/tex] N/C.
We know that,
E = F / q
where,
E = Electric field
F = Electric force
q = Charge of electron
Given that,
F = 10e - 14 N = 13.18 N
No. of electrons = 23
q = 23 * 1.602 * [tex]10^{-19}[/tex] = 36.846 * [tex]10^{-19}[/tex] C
E = 13.18 / 36.846 * [tex]10^{-19}[/tex] = 35.77 * [tex]10^{17}[/tex] N / C
Protein electrophoresis is a test used to measure specific proteins in blood. The separation of proteins is based on their electric charge.
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a 1.0m1.0m by 2.0m2.0m by 3.0m3.0m rectangular block has a uniform density of 600kg/m3600kg/m3and is completely submerged and held stationary in a deep pool of water. the water exerts an upward buoyant force on the block of 6×104n6×104n . the block is released and, after rising a short distance toward the surface, experiences a drag force of 2×104n2×104n. the magnitude of the acceleration of the block at this instant is most nearly
The magnitude of the acceleration of the block at this instant is 1.11m/s².
Given here the dimension of the block 1×2×3m, so the volume = l×b×h =6m3 and density = 600kg/m³
Mass of the block can be calculated as, m= volume × density = 600×6=3600kg.
Now, we calculate magnitude of force which is given by,
∑Force = F buoyant – ∑F drag- ∑F gravity
Force = 6×104 -2×104 – 3600× 9.8 =3600 ×a
On calculating this, we get
a= 1.11m/s².
Thus, the magnitude of acceleration is found to be 1.11m/s².
Buoyant force, is an upward force applied by a fluid against the weight of an object that is partially or completely submerged. The weight of the fluid on top causes pressure in a fluid column to rise with depth. If the buoyant force acting on an object is greater than the gravitational force then object will float, if gravitational force is greater than buoyant force then object will sink or drown.
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Calculate the number of atoms of zinc, zn, if you begin with 8.35 moles of zinc.
Taking into account the definition of Avogadro's Number, 5.029×10²⁴ atoms of zinc are in 8.35 moles.
Definition of Avogadro's NumberAvogadro's Number or Avogadro's Constant is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023×10²³ particles per mole. Avogadro's number applies to any substance.
Number of atoms of zincThen you can apply the following rule of three: If 1 mole of zinc contains 6.023×10²³ atoms, 8.35 moles of zinc contains how many atoms?
amount of atoms of zinc= (6.023×10²³ atoms× 8.35 moles)÷ 1 mole
amount of atoms of zinc= 5.029×10²⁴ atoms
Finally, 5.029×10²⁴ atoms of zinc are in 8.35 moles.
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Which substance is insoluble and Which substance is insoluble and floats in water?
A wood chips
B an ice cube
C a sugar cube
D a handful of salt
The substante that is insoluble and floats is the wood chip and the one that is insoluble is a sugar cube.
What is solubility?Solubility is a property that a substance has to dissolve in another that is called a solvent, this can also depend on the conditions of the temperature to which the solution can be exposed and also the pressure. The solubility will depend on the properties of each of the components, it is not always the same in all types of solutions.
When no more of the solute can dissolve in a solution, the solution is said to be saturated.
Therefore, we can confirm that the substante that is insoluble and floats is the wood chip and the one that is insoluble is a sugar cube.
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A_____is a short-circuited winding, which consists of a single turn of copper wire and acts on only a portion of the stator windings.
A shaded pole is a short-circuited winding, which consists of a single turn of copper wire and acts on only a portion of the stator windings.
Most single-phase motors just require the two start leads to be switched in order to turn the rotor in the opposite direction.
Is a copper wire winding that has been short-circuited and has only one turn acceptable?An AC motor that starts using a shaded stator pole. A partial short-circuited winding that affects only some of the stator windings, made up of a single turn of copper wire.
What does the stator do?The motor is momentarily changed into a two-phase motor during the starting time to get around this problem and make it self-start. A single-phase motor’s stator is equipped with an additional winding, referred to as the starting winding, for this function (or auxiliary).
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At dusk, a man in a park is using binoculars big enough that they are being supported on a tripod. Based on this knowledge, what can be
Inferred about these binoculars?
OA. They have a small field of view.
OB. They use lithium Ion batteries.
OC. They have a lower than normal magnifying power.
OD. They were purchased using a research grant.
They have a lower-than-normal magnifying power. is the correct answer.
Whatever your objective, a binocular tripod enables you to focus and stay there regardless of the wind or other environmental circumstances. You can see various regions simultaneously by using a tripod to hold several lenses in focus at once. Work your way down from the top of your head to get the appropriate tripod height. About four to five inches separate your eyes from the top of your head. The tripod head is roughly 4 to 4.5 inches high, and the telescopic eyepiece is about 4 inches above the bottom of the mount plate.
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Two vectors have length v1 = 3. 5 km and v2 = 4. 0 km. What are the maximum and minimum magnitudes of their vector sum? discuss how you decided on those magnitudes
Answer:
77ruririfusjd u 6r7r u y9r8
Question 1 (4 points)
A ball was kicked 50 m/s and is rolling to a stop. It is slowing
down at a rate of -3 m/s². How long was the ball in motion?
(YOU MUST FILL IN ALL THE BLANKS)
Givens:
Initial velocity=
Final Velocity=
Acceleration=
m/s
m
m/s²
Answer: (Use one decimal place) Time=
S
The ball was in motion for 16.7 seconds before coming to rest.
Let us assume that the ball was in motion for a time equal to 't' seconds before coming to rest.
Given in the question
Initial velocity = u = 50 m/s
Final Velocity = v = 0 m/s ( As the ball stops moving after some time, its final velocity hence becomes zero. )
Acceleration = a = -3 m/s²
To find
Time = t seconds
Using the first equation of motion,
v = u + at
Put in the value in the equation, we get
0 = 50 + (-3)(t)
3t = 50
t = 50/3
t = 16.66 seconds
t = 16.7 seconds ( rounding off to one decimal place )
Therefore, the ball was in motion for 16.7 seconds before coming to rest.
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calculate the frequency of each wavelength of electromagnetic radiation: 632.8 nm (wavelength of red light from helium–neon laser) 503 nm (wavelength of maximum solar radiation) 0.052 nm (wavelength contained in medical x-rays)
the frequency of each wavelength of electromagnetic radiation is
A)frequency of wavelength 632.8nm(red light from helium–neon laser)
is 4.738×10¹⁴ s⁻¹
B)frequency of wavelength 503 nm (maximum solar radiation)
is5.960×10¹⁴ s⁻¹
C)frequency of wavelength 0.052nm (medical x-rays)
is5.765×10¹⁸s⁻¹
A)
632.8 nm (wavelength of red light from helium–neon laser)
1 nm = 10⁻⁹ m
632.8 nm = 632.8×10⁻⁹ m = 6.328×10⁻⁷ m
The speed of light is c = 2.998×10⁸ m/s
λ = 6.328×10⁻⁷ m
the frequency can be calculated as
ƒ = c / λ
ƒ = (2.998×10⁸m/s) / (6.328×10⁻⁷ m)
ƒ = 4.738×10¹⁴ s⁻¹
frequency of wavelength 632.8nm is 4.738×10¹⁴ s⁻¹
B)
503 nm (wavelength of maximum solar radiation)
1 nm = 10⁻⁹ m
503 nm = 503×10⁻⁹m = 5.03×10⁻⁷ m
c = 2.998×10⁸ m/s
λ = 5.03×10⁻⁷ m
the frequency can be calculated as;
ƒ = c / λ
ƒ = (2.998×10⁸ m/s) / (5.03×10⁻⁷m)
ƒ = 5.960×10¹⁴ s⁻¹
frequency of wavelength 503 nm is5.960×10¹⁴ s⁻¹
C)
0.052 nm (wavelength contained in medical x-rays)
1 nm = 10⁻⁹ m
0.0520 nm = 0.0520×10⁻⁹ m = 5.20×10⁻¹¹m
Where the speed of light is
c = 2.998×10⁸ m/s
λ = 5.20×10⁻¹¹ m
the frequency can be calculated as
ƒ = c / λ
ƒ = (2.998×10⁸ m/s) / (5.20×10⁻¹¹ m)
ƒ = 5.765×10¹⁸s⁻¹
frequency of wavelength 0.052nm is5.765×10¹⁸s⁻¹
A)frequency of wavelength 632.8nm(red light from helium–neon laser)
is 4.738×10¹⁴ s⁻¹
B)frequency of wavelength 503 nm (maximum solar radiation)
is5.960×10¹⁴ s⁻¹
C)frequency of wavelength 0.052nm (medical x-rays)
is5.765×10¹⁸s⁻¹
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