.
المرور
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6. find the focal length of alens of power
-2.0D. what type of lens is this?

Answers

Answer 1

Answer:

[tex]-\frac{1}{2}[/tex]

Diverging lens

Explanation:

Given parameters:

Power of lens  = -2.0D

Unknown:

Focal length  = ?

Solution:

The power of lens is the reciprocal of the focal length;

   P  = [tex]\frac{1}{f}[/tex]

where  f is the focal length

 f  = [tex]\frac{1}{P}[/tex]   = [tex]-\frac{1}{2}[/tex]

The lens is a diverging lens


Related Questions

what would be the velocity
when a dog of 10kg and it's kinetic energy is 20J​

Answers

Answer:

2 m/s

Explanation:

20 divided by 10 is 2 meters per second

how is an object's motion related to speed, velocity, and acceleration?

Answers

Answer:

Speed describes only how fast an object is moving, whereas velocity gives both the speed and direction of the object’s motion being a vector quantity. The standard unit to measure velocity is meter per second (m/s or ms-1). For example, “10 meters per second” is scalar and “10 meters per second West” is vector. Acceleration

Under what conditions can an object have forces acting on it, but its motion does not change ?

Answers

Answer: An object at rest has zero velocity - and (in the absence of an unbalanced force) will remain with a zero velocity. Such an object will not change its state of motion.

Explanation: I hoped that helped!!

Due to the friction between a tire and the road surface, the temperature of the air inside a tire increases as one drives. If the tire pressure is 37 psi when the car is in the driveway at 25° C, What is the pressure of the tire when the temperature increases to 50° C?

Answers

Answer:

40.10 atm .

Explanation:

Here volume of tire is assumed to be nearly constant .

Modified gas law ,

P₁ / T₁ = P₂ / T₂

37 / ( 273 + 25 ) = P₂ / ( 273 + 50)

37 / 298 = P₂ / 323

P₂ = 37 x 323 / 298

= 40.10 atm .

Two teams are competing in a tug-of-war contest. Team A is pulling at 4000N and Team B is pulling at 4900N is the opposite direction.

Answers

Answer:

There is 8900N of force on the rope and team B wins

Explanation:

A 200 N net force acts on a 50 kg box. What is the acceleration of the box?

Answers

Answer:

a= 4m/s^2

Explanation:

Fnet =200N

m=50kg

a=?

Fnet = ma

200=50a then divide both sides by 50 to get acceleration

Taking into account the Newton's second law, the acceleration of the box is 4 [tex]\frac{m}{s^{2} }[/tex].

In first place, you have to know that Newton's second law, called the fundamental law or fundamental principle of dynamics, states that a body accelerates if a force is applied to it.

Then, the amount of force necessary is proportional to the acceleration that the body acquires, and the constant of proportionality  is the mass of the body.

Mathematically, Newton's second law is:

F= m×a

where:

F = Force [N] m = Mass [kg] a = Acceleration [m/s²]

In this case, you know:

F= 200 N m= 50 kg a= ?

Replacing in the Newton's second law:

200 N= 50 kg×a

Solving:

a=200 N÷ 50 kg

a= 4 [tex]\frac{m}{s^{2} }[/tex]

In summary, the acceleration of the box is 4 [tex]\frac{m}{s^{2} }[/tex].

Learn more about the Newton's second law:

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a baby carriage is sitting on the top of a hill that is 21 m high. the carriage with a baby 75kg. the carriage has what energy? calculate it

Answers

Answer:

It has potential energy

PE = 15450.75 J

Explanation:

we know its potential energy because the carriage is not moving, although it can

PE = mgh

in this case, m is 75, h is 21, and g is always 9.81

plug these in: PE = (75) (21) (9.81)

your answer: PE = 15450.75 J

A 2,100kg car drives toward a 55kg cart that has a velocity of 0.50m/s west. The two objects collide giving the car a final velocity of 6.31m/s east and the shopping cart a velocity of 13.5m/s east what the initial velocity of the car?

A. 6.68m/s east
B. 7.19m/s west
C. 6.68m/s west
D. 7.19m/s east

Answers

Answer: A. 6.68m/s east

Explanation: just did it on ap3x

Which of the following equations is balanced?

a. 2Al2O3 -----> 3Al + 3O2
b. 3Al2O3 -----> 3Al + 2O2
c. 2Al2O3 -----> 4Al + 3O2
d. 2Al2O3 -----> Al + 3O2

Answers

Answer: c

Explanation:

The way to check which one is the correct one is to simply multiply and see if there are the same number of atoms in both sides for each element.

a. 2×2 atoms of Al ≠ 3×1 atoms of Al

2×3 atoms of O = 3×2 atoms of O

BOTH MUST BE EQUAL FOR IT TO BE ADJUSTED!!!!!

b. 3×2 atoms of Al ≠ 3×1 atoms of Al

3×3 atoms of O ≠ 2×2 atoms of O

c. 2×2 atoms of Al = 4×1 atoms of Al

2×3 atoms of O = 3×2 atoms of O

BOTH ARE EQUAL, CORRECT ANSWER!!!

d. 2×2 atoms of Al ≠ 1×1 atoms of Al

2×3 atoms of O = 3×2 atoms of O

Someone help me plz. I have no idea. ​

Answers

Answer:

fault im pretty sure

Explanation:

Answer:

fault............

...........

You are traveling down the highway when you notice a cop 200 meters ahead of you. For the next 5 seconds, you step on the bake to avoid a speeding ticket. The brake causes an acceleration on your car of -2.0 m/s^2.
What is the time it takes?
What is the displacement of your car?
What is the acceleration of your car?
Write the equation you will use to solve the problem.
What was your initial velocity?

Answers

Answer:200 5 -20 = v=323

Explanation:

Density Questions
How many blocks of ice-cream each 10cm x 10 cm x 4cm can be stored in the compartenent of a deep-freeze measuring 40 cm x 40cm x 20cm?

Answers

Explanation:

let's take the volume of each first:

ice cream: 10×10×4=400cm^3

freezer: 40×40×20=32,000cm^3

now we just divide: 32000/400=80

The distance recorded for riding a motorcycle on its rear wheel without stopping is more than 320 km! Suppose the rider in this impressive position is traveling with an initial velocity of 8.0 m/s before accelerating. Then the rider travels 40.0 m at a constant acceleration of 2.00 m/s2. What is the rider's velocity after the acceleration?

Answers

Answer:

14.97m/s

Explanation:

Given

Initial velocity of the car u = 8m/s

Distance travelled by the rider S = 40m

Acceleration a = 2m/s²

Required

rider's velocity after the acceleration v

Using the equation of motion

v² = u²+2as

v² = 8²+2(2)(40)

v² = 64+160

v² = 224

v = √224

v = 14.97m/s

Hence the rider's velocity after the acceleration is 14.97m/s

Bird man is flying horizontally at a speed of 30m/a and a height of 69 m. Bird man releases a turd directly above the start of the field. How far from the start of the field should the robot hood the bucket to catch the turd?

Answers

Answer:

The distance is [tex]d = 112.5 \ m[/tex]      

Explanation:

From the question we are told that

   The horizontal speed is  [tex]v_x = 30 \ m/s[/tex]

    The height is [tex]s = 69 \ m[/tex]

     

Generally from kinematic equation we have that

    [tex]s = ut + \frac{1}{2} gt^2[/tex]

Here u  is the initial velocity of the turd in the vertical direction and the value is 0 m/s

So

    [tex]69 = 0 * t + \frac{1}{2} * 9.8 t^2[/tex]

=>   [tex]t = \sqrt{\frac{2 * 69}{4.9} }[/tex]

=>   [tex]t = 3.75 \ s[/tex]

Generally the distance which the robot have to  hood the bucket in order to catch the turd  is mathematically represented as

     [tex]d = v_x * t[/tex]

=>  [tex]d = 30 * 3.75[/tex]

=>  [tex]d = 112.5 \ m[/tex]      

What would be the y-component of a velocity vector that had a
magnitude of 37m/s in a direction 30° from the x-axis?

Answers

Answer:

18.5 m/s

Explanation:

Just did it on EdPuzzle

The y-component of a velocity vector that had a magnitude of 37 m / s in a direction 30° from the x - axis would be 18.5 m / s .

What is a vector quantity?

The quantities that contain the magnitude of the quantities along with the direction are known as the vector quantities.

Examples of vector quantities are displacement, velocity acceleration, force, etc.

As given in the problem we have to find out the y-component of a velocity vector that had a magnitude of 37 m / s in a direction 30° from the x - axis.

The y-component of a velocity vector = 37 × sin 30

                                                                   = 18.5 m / s

Thus , y-component of a velocity vector that had a magnitude of 37 m / s in a direction 30° from the x - axis would be 18.5 m / s.

To learn more about the vector quantity here , refer to the link given below ;

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Three vectors , , and , each have a magnitude of 52.0 m and lie in an xy plane. Their directions relative to the positive direction of the x axis are 29.0 ˚, 191 ˚, and 311 ˚, respectively. What are (a) the magnitude and (b) the angle of the vector (relative to the +x direction in the range of (-180°, 180°)), and (c) the magnitude and (d) the angle of in the range of (-180°, 180°)? What are (e) the magnitude and (f) the angle (in the range of (-180°, 180°)) of a fourth vector such that ?

Answers

Answer:

a)   A´= A  

b)   θ₁´ = 29º,  θ₂´ = - 169º ,  θ₃´ = -49º

Explanation:

In this exercise you are asked to give the magnitudes and angles of the vectors from another system of

reference

a) The magnitudes

The magnitude of a vector, the size of which is a scalar, this does not depend on the reference system, since it is obtained by subtracting the coordinates of the end point minus the coordinate of the origin of the vector

          A = [tex]x_{f}[/tex]- x₀

if the vectors are measured in another reference frame

         x_{f}´ = xx_{f}- U

         x₀´ = x₀ -U

where U is the distance between the two reference frames

         A´ = x_{f}´ - x₀´

we substitute

         A´ = (x_{f} - U) - (x₀-U) = x_{f} - x₀

         A´ = A

 it does not change

b) Angles

The given angles are measured from the positive part of the x axis in a counterclockwise direction, it is asked to give these angles from the x axis

     θ₁ = 29º

     does not change

     θ₁´ = 29º

    θ₂ = 191º

   we measure clockwise

     θ₂´ = θ₂ - 360

     θ₂´ = 191 - 360

     θ₂´ = - 169º

     θ₃ =311º

    we measure clockwise

     θ₃´ = 311 -360

     θ₃´ = -49º

GOOD MFRNING
PAGE NO.:
DATE:
cap a b
body have larger mess be holter than another of smaller
maws if they are same temperature why,
at the​

Answers

Answer:

umm im confused

Explanation:

Answer:

larger mass more the molecule more heat absorbed

and vice versa .Thats the reason ok?

Un delfín nada en el mar, a una profundidad tal que experimenta es de 2,22 x 10⁵ PA. Si la densidad del agua del mar es de 1030kg/m³, ¿A qué profundidad nada el delfín?

Answers

Answer:

El delfín nada a una profundidad de 22 m

Explanation:

El principio fundamental de la hidrostática establece que la presión en un punto del interior de un fluido (presión hidrostática) es directamente proporcional a su densidad, a la profundidad que se encuentre dicho punto y a la gravedad del sitio en el que se encuentre el fluido.

Esto se expresa como:

P=ρ⋅g⋅h

donde:

P es la presión en un punto del fluido. ρ es la densidad del fluido .g es la gravedad del lugar donde se encuentre el fluido. h es la profundidad.

En este caso:

P= 2.22*10⁵ Paρ= 1,030 [tex]\frac{kg}{m^{3} }[/tex]g= 9.8 [tex]\frac{m}{s^{2} }[/tex]h= ?

Reemplazando:

2.22*10⁵ Pa= 1,030 [tex]\frac{kg}{m^{3} }[/tex] * 9.8 [tex]\frac{m}{s^{2} }[/tex] * h

Resolviendo:

[tex]h=\frac{2.22*10^{5} Pa}{1,030\frac{kg}{m^{3} }*9.8 \frac{m}{s^{2} }}[/tex]

h= 21.993 m ≅ 22 m

El delfín nada a una profundidad de 22 m

When the car was stopped by the tree, its change in velocity during the collision was -6 meters/second. This change in velocity occurred in 2 seconds. What was the acceleration of the car?

Answers

6 meters per second

You will need to add six two times to find the acceleration

Inside a car that was at 273 K, a bottle with a pressure at 100,000 pascals warms up to 350 K. If the volume of the bottle remains constant, what is the pressure, in pascals, inside the hot water bottle!

Answers

Answer:

128.205.1

Explanation:

Which statement describes the pattern in the density of gases in the

atmosphere?

A. They are least dense in the atmosphere near sea level

B. They are less dense near the top of the atmosphere

C. They are densest near the middle of the

atmosphere

D. They are every dense thoughout the attesohere

Answers

B

Because less particle are found near the top of the atmosphere

Gases are less dense near the top of the atmosphere.

What is atmosphere?

All life on Earth is shielded by the atmosphere, a layer of gases that regulates temperatures within a narrow range and deflects harmful solar rays.

The layer of gases that covers Earth is known as the atmosphere. The gravitational pull of the Earth keeps it close to the planet's surface. The three primary gases that make up the atmosphere are argon, oxygen, and nitrogen.

Density of atmosphere is high at sea level and gradually decreases with height. And at top of the atmosphere, gas is less dense.

Learn more about atmosphere here:

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In a container there are 2 liters of liquid, of which 75% is alcohol and the remaining 25% is water.
Determine how many cm3 of alcohol must be added to bring the alcohol percentage to 80%.

Answers

Answer:

There must be added 500 cm3 of alcohol to bring the concentration to 80%.

Explanation:

Concentration

The concentration of a solution is a measure of the amount of solute that has been dissolved in a given amount of solution.

In the container, there are 2 liters (2000 cubic centimeters) of a solution, 75% of which is alcohol (solute) and 25% of water (solvent).

The original amount of alcohol is:

H = 2000*75% = 1500 cc

The original amount of water is:

W = 2000*25% = 500 cc

When we add x cc of pure alcohol, there are 1500+x cc of alcohol out of 2000+x cc of solution.

The new concentration is calculated as:

[tex]\displaystyle \frac{1500+x}{2000+x}[/tex]

And it's known this concentration is 80% (0.8), thus:

[tex]\displaystyle \frac{1500+x}{2000+x}=0.8[/tex]

Multiplying by 2000+x:

[tex]1500+x = 0.8(2000+x)[/tex]

Operating:

[tex]1500+x = 1600+0.8x[/tex]

Rearranging:

[tex]x-0.8x=1600-1500[/tex]

[tex]0.2x=100[/tex]

[tex]x=100/0.2[/tex]

x= 500

There must be added 500 cm3 of alcohol to bring the concentration to 80%

A baseball is thrown horizontally with an initial speed of 10 m/s from the edge of a cliff. A stop watch measures the stone's time in the air until it hits the ground to be 4.3 s. How far does the baseball travel horizontally?

Answers

Complete Question

A baseball is thrown horizontally with an initial speed of 10 m/s from the edge of a cliff. A stop watch measures the ball's time in the air until it hits the ground to be 4.3 s. How far does the baseball travel horizontally?

Answer:

The distance covered horizontally is  [tex]d = 43 \ m[/tex]

Explanation:

From the question we are told that

     The initial horizontal velocity is  [tex]u = 10 \ m/s[/tex]

     The time taken by the ball in the air is  [tex]t = 4.3 \ s[/tex]

Generally the distance traveled by the ball is  

       [tex]d = u * t[/tex]

=>     [tex]d = 10 * 4.3[/tex]

=>     [tex]d = 43 \ m[/tex]

A car drives 0.696 km North, and then turns and drives 4.326 km East. Calculate the magnitude of the car's resultant displacement. Include equation, substitution with units, and answer with units.

Answers

Answer:

4.3186km

Explanation:

If a car drives 0.696 km North, and then turns and drives 4.326 km East, the magnitude of the car's resultant displacement will be gotten using the Pythagoras theorem as shown;

d² = x²+y²

Given;

x = 4.326km

y = 0.696km

Substitute into the formula and get d;

d² = (4.326)²+(0.696)²

d² = 18.714276+0.484416

d² =19.198692

d = √19.198692

d = 4.3816km

Hence the magnitude of the car's resultant displacement is 4.3186km

What happens to the strength of an electromagnet when the number of coils
in the solenoid is increased?
O A. It depends on what metal makes up the solenoid.
B. It increases.
C. It remains the same.
D. It decreases.

Answers

Answer:

It decreases

Explanation:

<3

When the number of coils in the solenoid is increased, the strength of the electromagnet also increases. So, the correct option is B.

What is meant by a solenoid ?

A solenoid is defined as a type of electromagnet formed by winding a wire into a helical coil on a rod made of solid iron or steel.

Here,

The number of coils in the solenoid is increased. This increase in the number of coils, would affect the strength of the electromagnet.

The equation for the strength of the magnetic field of a solenoid can be written as,

B = μ₀NI/L

where,

B is the magnetic field strength

μ₀ is the permeability of free space

N is the number of turns of the coil

I is the current flowing through the solenoid

L is the length of the solenoid

From the equation, we can say that the magnetic field strength of a solenoid is directly proportional to the number of turns or the number of coils formed.

B [tex]\alpha[/tex] N

Therefore,

As, the number of coils in a solenoid increases, the magnetic field strength of the solenoid also increases.

Hence,

When the number of coils in the solenoid is increased, the strength of the electromagnet also increases.

To learn more about solenoid, click:

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An object with a mass of 43 kg measured on Earth is taken to the Moon. What is the mass of the object on the Moon's surface if the acceleration due to gravity on the Moon is one-sixth of that on Earth? O a. 16 kg O b. 43 kg O c. 7.9 kg O d. 26 kg​

Answers

Answer:

b 43 kg

Explanation:

mass doesn't differ from place to place.

but the weight may

What is the speed in kilometers per hour of a 27.78m/s baseball pitch?

Answers

Answer:

I actually don't know

Explanation:

ok chillll

Silver has a mass of 10.5 grams and a volume of 19.3 cm3. What is its density?

Answers

Answer:

The answer is 0.54 g/cm³

Explanation:

The density of a substance can be found by using the formula

[tex]density = \frac{mass}{volume} \\ [/tex]

From the question we have

[tex]density = \frac{10.5}{19.3} \\ = 0.54404145...[/tex]

We have the final answer as

0.54 g/cm³

Hope this helps you

A box is pushed horizontally with constant speed across a rough horizontal surface.
Which of the following must be true?

Answers

Answer:

what is the answers? so i can't answer.

Explanation:

The statement that is true as regards movement of the box when pushed horizontally with constant velocity is given by;

Option D; The friction is equal to the applied force

The missing options are;

a) The friction is less than the applied force

b) There is no friction acting on the box

c) The friction is greater than the applied force

d) The friction is equal to the applied force

We are told that the box is pushed with constant speed. We know that at constant speed, acceleration is equal to zero.

If acceleration is zero, the 2 forces acting on the box will be the applied force and the frictional force from the rough horizontal surface.

Now, if the frictional force was less than the applied force, it means the velocity of the box will gradually be increasing but we are told the velocity is constant.

Also, if the frictional force is more than the applied force, it means the object will not move because the force of resistance is more than the applied force.

Finally, if the frictional force is equal to the applied force, then the box will move with a constant motion.

Thus, in conclusion the friction is equal to the applied force.

Read more at; https://brainly.com/question/25152945

En un año se otorgará uno de tres premios (a la investigación, la enseñanza y el servicio) a algunos de los estudiantes, de un grupo de 25, de posgrado del departamento de estadística. Si cada estudiante puede recibir un premio como máximo, ¿cuántas selecciones posibles habría?

Answers

Answer:

Habría 13,800 selecciones posibles.

Explanation:

Permutar es colocar elementos en distintas posiciones.

Se llama permutación de m elementos a cada una de las diferentes ordenaciones  que se pueden hacer con esos elementos. En otras palabras, se llama permutaciones de  m elementos en n posiciones a las distintas formas en que se pueden ordenar los m elementos ocupando únicamente las n  posiciones.

En el caso de la permutación no se repiten los elementos, ya que de repetirse o ser iguales entre si, al intercambiarlos no se genera una nueva permutación.

El número de permutaciones de n elementos elegidos k a la vez es calculado como:

[tex]P=\frac{n!}{(n-k)!}[/tex]

Como los premios son distinguibles, la permutación es usada en este caso, donde n=25 y k=3

Entonces:

[tex]P=\frac{25!}{(25-3)!}[/tex]

Resolviendo:

[tex]P=\frac{25!}{(22)!}[/tex]

Recordando que el factorial es una operación matemática que indica que se deben multiplicar todos los números enteros y positivos que hay entre el número al cual deseas calcular el factorial y el número 1, entonces se obtiene:

P= 13,800

Habría 13,800 selecciones posibles.

La selección de los alumnos se puede realizar de 2300 formas.

Teniendo en cuenta eso, tenemos 25 estudiantes graduados para ser seleccionados para tres tipos diferentes de premios, como pabellones de investigación, docencia y servicio.

Ahora;

25C3 = 25! / 3! (25 - 3)!

25C3 = 25! / 3! 22!

25C3 = 2300

La selección de los alumnos se puede realizar de 2300 formas.

Más información: https://brainly.com/question/13387529

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