The rate constant increases by a factor of 1.3 when the temperature increases from 200k to 400k for a reaction with an activation energy of 845 j/mol.
Calculationln k2/k1 = 845/8.314 (1/200 - 1/400)
ln k2/k1 = 0.254
k2/k1 = 1.3
How are k1 and k2 the rate constants determined?The Arrhenius equation, which has the form lnk=RE(T1T1), relates the activation energy (Ea) and rate constants (k1 and k2) of a chemical process at two distinct temperatures (T1 and T2).
Where T1 and T2 are the temperatures of rates k1 and k2 (respectively) in K, k1 and k2 are rate constants, Ea is the activation energy in J/mol, and R is the gas constant which has a value of 8.314 J/K mol.
The activation energies employed were 20.1 kJ/mol and 59.8 kJ/mol.
K1 and K2 are what temperature?The rate constants K1 and K2 are 1016 e-2000/T and 1015 e-1000/T, respectively, for two distinct reactions.
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onur drops a basketball from a height of 10\,\text{m}10m10, start text, m, end text on mars, where the acceleration due to gravity has a magnitude of 3.7\,\dfrac{\text{m}}{\text{s}^2}3.7 s 2 m 3, point, 7, start fraction, start text, m, end text, divided by, start text, s, end text, squared, end fraction. we want to know how many seconds the basketball is in the air before it hits the ground. which kinematic formula would be most useful to solve for the target unknown?
The time the ball spend on the air before reaching the ground is 2.325 seconds.
The kinematic formula would be most useful to solve for the target unknown is
H = ut + ½gt²
Basket ball is drop from height
H=10m
It is dropped on planet mass
And the acceleration due to gravity on Mars is given as
g= 3.7m/s²
Time taken for the ball to reach the ground
Initial velocity of the body is zero
u=0m/s
Using equation of motion: free fall
H = ut + ½gt²
10 = 0•t + ½ × 3.7 ×t²
10 = 0 + 1.85t²
10 = 1.85t²
Then, t² =10/1.85
t² = 5.405
t = √ 5.405
t = 2.325seconds
So the time the ball spend on the air before reaching the ground is 2.325 seconds.
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Onur drops a basketball from a height of 10 m on Mars, where the acceleration due to gravity has a magnitude of 3.7 m/s². We want to know how many seconds the basketball is in the air before it hits the ground.
Which kinematic formula would be most useful to solve for the target unknown?
Answer: Δy = v0t - ½ at²
A car travels 40 miles north in the first 40 minutes of a trip. The same car travels 30 miles west in the next 30 minutes of the trip. What can be said about the motion of the car?.
Answer: The car is travelling at a constant speed. Because it travells 30 miles in 30 minutes. While it travells 40 miles in 40 minutes.
Explanation:
An electron moving in a straight line has an initial speed of 2.320 x 10^7 m/s. It undergoes an acceleration of 2.20 x 10^10 m/s^2 [Bwd].
a. How long will it take to reach a speed of 3.42 x 10^5 m/s [Bwd]?
b. How far will it have travelled in this time?
KKdkekskAnswer:
Explanation:
There is a car traveling 36 Km/h to the west. The concert is 12Km away. How 1 point
long would it take them to get there?
Is this a SPEED or VELOCITY problem?
The Time to get there is 3 hours
The Speed(s) of a car traveling is = 36 km/h west
Distance(d) to the concert is = 12km
Time to get there = t hours
The formulae used are
Speed(s) = Distance(d) / Time(t)
⇒Time(t) = Distance(d) / Speed(s)
⇒ t = 36 / 12
⇒ 3 hours
Hence, the time for the car to get to the concert with a speed of 36km/hr was 3 hours. This is a VELOCITY problem because it involves direction too along with the speed of the car.
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the smallest unit of charge is −1.6×10−19 c,−1.6×10−19 c, which is the charge in coulombs of a single electron. robert millikan was able to measure the charge on small droplets of oil by suspending them between a pair of electrically charged plates.
Since an electron cannot be fractionalized, any number that is a multiple of 1.6 is true. Therefore, the appropriate options are -3.2x10-19C, -4.8x10^-19C and -8.0x10-19C.
Why -1.2x10^-19C is not possible?Matter's electric charge is what gives it a force when it's in an electromagnetic field, which is its physical property.
Protons and electrons, which act as charge carriers, frequently carry both positive and negative electric charges. Charges moving around in a system produce energy.
-1.2x10^-19C in choices is incorrect even if it is a multiple of 1.6 since it has a fraction of one electron because its charge is less than that of a single electron.
Consequently, the values of 1.2x10-19, 5.6x10-19, and -9.4x10-19 are wrong because they contain fractions of electrons that are impossible to exist.
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A satellite is in uniform circular motion around the Moon. What happens to the direction of the acceleration vector during one full orbit?
(1 point)
O The acceleration vector oscillates back and forth.
O The acceleration vector always points inward.
O The acceleration vector always points outward.
O The acceleration vector always points in the direction of motion.
An car is brought to rest in a distance of 484 m using a constant acceleration of -8.0 m/s2. What was the velocity of the car when the acceleration first began?
The initial velocity of the car was 88m/s
The pace at which an object's direction changes as it is traveling, as observed from a particular viewpoint and as quantified by a certain unit of time, is known as its velocity.
Any object exposed to forces will accelerate. The object's velocity is altered as a result of this acceleration. The speed of the entity prior to the change imposed on by acceleration is therefore known as the initial velocity.
Given:
Final velocity, v = 0m/s
Acceleration, a = -8 [tex]m/s^2[/tex]
Distance covered, d = 484m
To find:
Initial velocity, u = ?
Formula:
[tex]v^2 - u^2 = 2ad[/tex]
Calculations:
Initial velocity, u = [tex]\sqrt{v - 2ad}[/tex]
u = [tex]\sqrt{0 - 2 (8) (484)}[/tex]
u = 88m/s
Result:
The initial velocity of the car was found to be 88m/s.
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A car travels 40 miles north in the first 40 minutes of a trip. The same car travels 30 miles west in the next 30 minutes of the trip. What can be said about the motion of the car?.
It can be said that the car which travels first at 40 miles in 40 minutes and then 30 miles in 30 minutes is traveling at a constant speed.
The formula and procedure we will use to solve this exercise is:
v = x /t
Where:
x = distancet = timev = velocityInformation about the problem:
t₁ = 40 minx₁= 40 milest₂ = 30 minx₂= 30 milesv₁ = ?v₂ = ?Applying the velocity formula for the first data information of the travel, we get:
v₁ = x₁ /t₁
v₁ = 40 miles /40 min
v₁ = 1 mile/min
Applying the velocity formula for the second data information of the travel, we get:
v₂ = x₂ /t₂
v₂ = 30 miles /30 min
v₂ = 1 mile/min
As we notice v₁ = v₂ that means that the car is traveling with a constant speed during the trip
What is velocity?It is a physical quantity that indicates the displacement of a mobile per unit of time, it is expressed in units of distance per time, for example (miles/h, km/h).
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Give me 5 examples of High heat vaporization
Answer:
ironing clothes, process of sweating, line drying clothes, melting a glass of ice, drying of wet towels
Explanation:
Answer:
Water is vaporized when it is boiled on the stove to cook some pasta, and much of it forms into a thick steam. Water evaporates – Water evaporates from a puddle or a pool during a hot summer’s day.
Explanation:
hope this helps♡
A weather balloon has a volume of 100L when it is released from above sea level, where the pressure is 101kPa. What will the balloon's volume when it reaches an altitude where the pressure is 43kPa?
Can someone please help me with this and quick??
The volume of the balloon is 234.88L.
What is volume?Volume can be defined as the capacity of a solid shape.
To calculate the volume of the balloon, we use the formula below.
Formula:
PV = P'V'.......... Equation 1Where:
P = Initial pressure of the balloonP' = Final pressure of the balloonV' = Initial volume of the balloonV = Final volume of the balloon
Make V' the subject of the equation
V' = PV/P'................. Equation 2From the question,
Given:
P = 101 kPaV = 100 LP' = 43kPaSubstitute these values into equation 2
V' = 101×100/43V' = 234.88 LHence, The volume of the balloon is 234.88L.
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As a freely falling object picks up downward speed, what happens to the power supplied by the gravitational force?.
As a freely falling object picks up downward speed, then the power supplied by gravitational force will increase.
We know that Power = work done /time
Power = W ×t and work = Force × displacement.
W= F(d) = F× speed/time (distance = speed /time)
So, if we increase the speed then work done will also increase, eventually it increases the power.
The longer an object is in free fall, the faster it falls toward the ground due to gravity. means it depend on the mass of object.
A falling object accelerates as it falls downward rapidly. The quantity of air resistance rises in proportion to the speed. The pull of gravity eventually is balanced by the force of air resistance as it grows. The item will cease accelerating since there is no net force at this point in time 0 newton.
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A signal contains the following frequencies, 100 hz, 247 hz, and 750 hz. what is the nyquist frequency of the signal?
The nyquist frequency of the signal containing the following frequencies 100hz, 247hz and 750hz is taken to be calculated as 1500 hz.
CalculationThe provided frequencies are as follows:
100hz, 247hz, 750hz
Then the accurate Nyquist frequency can be taken out as
fs = 2 fmax
= 2 (750)
= 1500 Hz
Describe the Nyquist theorem in a few words.The sampling theorem is another name for the Nyquist theorem. The rule is that a pure sine wave measurement, or sample rate, must be at least twice as frequent as the original to be accurately reproduced.
What is the formula for Nyquist’s theorem?Nyquist explains that we can send data at a rate of up to C=2Blog2M bits per second in a channel with no noise. B is seen as the bandwidth (in Hz) and M is the number of signal levels.
The Nyquist frequency formula is what?The Nyquist frequency can be defined as fn = 1/2t. When spectra for digital data are displayed, the highest frequency displayed is the Nyquist frequency.
For an IRIS type of broadband seismic stations, Δt = 0.05 s, so the Nyquist frequency is 10 Hz.
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Bob and carol are both observing the moon at exactly the same time. However, bob is in miami and carol is in los angeles. Bob observes the moon in the first quarter phase. In what phase will carol observe the moon to be?.
Bob and Carol are both observing the moon at exactly the same time. However, bob is in Miami and carol is in Los Angeles. Bob observes the moon in the first quarter phase. Carl will also observe the moon in the first quarter phase.
The moon cycle consists of four primary and secondary phases.
The four primary phases are New Moon, First Quarter, Full Moon, and the Last Quarter.
However, people living in different hemispheres see the contemporary phase of the moon from different angles.
The secondary phases of the moon are waxing crescent, waxing gibbous, waning gibbous, and waning crescent.
If a person travels from the southern hemisphere to the northern hemisphere, he will see that the moon is in the same phase as it was at home.
Thus Bob and Carol, living in different cities, will also observe the moon in the same phase i.e. the first quarter phase.
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problem 11.003 - mass on a spring - dependent multi-part problem - assign all parts skip to question note: this is a multi-part question. once an answer is submitted, you will be unable to return to this part. the vertical motion of mass a is defined by the relation x
The position, velocity, and acceleration of A
when t= 0.5 s are = 98.748 mm/s², respectively.
Steps of the equation:
This is a multi-part question: Once an answer is submitted, you will be unable to return to this part:
The vertical motion of mass A is defined by the relation x = cos (iot O.1sin (1Of, where x and tare expressed in mm and seconds, respectively:
Consider t = 0.5 s. Problem 11.003.
a Velocity and acceleration of a mass on a spring Determine the position, velocity; and acceleration of A (You must provide an answer before moving to the next part)
The position, velocity, and acceleration of A
when t= 0.5 s are
= -0.379 mm,
= -1.867| mm/s, and
= 98.748 mm/s², respectively
What exactly is a dependency in Spring?Dependency Injection is a key feature of the Spring framework that allows the Spring container to "inject" objects into other objects or "dependencies." Simply put, this allows for loose coupling of components and shifts responsibility for component management to the container.Spring IOC's primary functionality is dependency injection (Inversion of Control). The Spring-Core module is in charge of injecting dependencies via Constructor or Setter methods.To learn more about dependency in Spring refer to
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Why it is not appropriate to use a rubber protection on high voltage cables that exceeds a transmission voltage of 120000V
It is not appropriate to use a rubber protection on high voltage cables that exceeds a transmission voltage of 120000V, because the high voltage transmitted in these lines can cause heating effect on the lines which can melt the rubber used to the coat the lines.
What is high voltage transmission?
High voltage transmission lines deliver electricity over long distances
This high voltage transmission lines transmit power at very high voltage.
The high voltage rating of these transmission lines often cause heating effect on the lines or wires.
The heating effect of the transmission lines can melt rubbers, hence it is not advised or required to use a rubber to cover these high transmission lines.
Thus, it is not appropriate to use a rubber protection on high voltage cables that exceeds a transmission voltage of 120000V, because the high voltage transmitted in these lines can cause heating effect on the lines which can melt the rubber used to the coat the lines.
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1.
Which of the following numbers has two
significant digits?
A. 0.01
B. 0.010
C. 10
D. 10.00
Answer:The answer is B.
Explanation: the 1 and the 0 are the significant digits in 0.010
a 5.00 kg stone is rubbed across the horizontal ceiling of a cave passageway (fig. 6-48). if the coefficient of kinetic friction is 0.65 and the force applied to the stone is angled at u ???? 70.0°, what must the magnitude of the force be for the stone to move at constant velocity?
We take the +x direction to be horizontal to the right and the +y direction to be up.
Newton’s second lawThe equations for the x, y components of the force as per Newton’s second law are:
Fx=Fcosθ−f=ma
Fy=Fsinθ−FN−mg=0
Now, f=μkFN and the second equation from above gives
FN=Fsinθ−mg,
which yields f=μk(Fsinθ−mg).
This expression is replaced for f in the first equation to obtain
Fcosθ−μk(Fsinθ−mg)=ma.
For a = 0 ,
the force is F= cosθ− μksinθ− μkmg
With μk=0.65, m = 5.0kg,
and θ = 70∘, we obtain F = 118 N.
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If the green house effect did not exist at all,what would Erath would be like?
The heat generated by the Earth would keep passing radially outward from the Earth's surface into space if the natural greenhouse effect did not exist, and the Earth would have an average temperature of about -20°C.
What is greenhouse effect?The greenhouse effect describes how "greenhouse gases" trap heat near the Earth's surface.
These heat-trapping gases act like a blanket wrapped around Earth, keeping it warmer than it would be without them.
Earth would turn into an icy wasteland if greenhouse gases were not present.
Greenhouse gases maintain our planet habitable by retaining some of the Earth's heat energy, preventing it from escaping into space. The greenhouse effect is the sequestration of heat.
Thus, the greenhouse effect can decrease the temperature of the Earth below average.
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PLS HELP!! WILL MARK BRAINLIEST
In 3-5 sentences, summarize the balanced forces that are present when a soccer ball is resting on the ground, and the unbalanced forces that are present when a soccer ball is kicked and moves through the air or rolls on the ground.
When the ball is kicked, there is now an unbalanced force that acts on the ball thereby impacting an acceleration.
What are unbalanced forces?We know that according to Newton's laws, an object would remain in its state of rest or a state of uniform motion unless it is acted upon by an external force. This is also known as the law of inertia.
As the ball is kept on the ground, there are two forces that act on the ball;
1) The weight of the ball that act downwards
2) The reaction force on the ball that acts upwards
The two forces are balanced hence the ball remains on the ground.
When the ball is kicked, there is now an unbalanced force that acts on the ball thereby impacting an acceleration.
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Answer:
When the ball is kicked, there is now an unbalanced force that acts on the ball thereby impacting an acceleration.
Explanation:
What are unbalanced forces?
We know that according to Newton's laws, an object would remain in its state of rest or a state of uniform motion unless it is acted upon by an external force. This is also known as the law of inertia.
As the ball is kept on the ground, there are two forces that act on the ball;
1) The weight of the ball that act downwards
2) The reaction force on the ball that acts upwards
The two forces are balanced hence the ball remains on the ground.
When the ball is kicked, there is now an unbalanced force that acts on the ball thereby impacting an acceleration.
What solution has a pH is closest to neutral?
Hand soap
Chicken soup
Milk
Saliva
Answer:
Saliva
Explanation:
meaning of quantity survey
Explanation:
quantity surveying is the action or profession of a person who estimates the cost of the materials and labour necessary for a construction job.
Convert 500 cubic feet into gallons. Round your answer to the nearest whole number.
A man walks 20 km in 4 hours. Find his speed.
O 5 km/hr
O2 km/hr
O 10 km/hr
O1 km/hr
Answer: 5 km/hr
Explanation: 20Km / 4 hours is 5km a mile
An object is projected horizontally at 8.0m/s from he top of a 122.5m cliff. How far from the base of the cliff will the object strike the ground?
The object strikes 40.0 meters far from the base of the cliff on the ground.
Let us assume that the object strikes the ground after a time equal to 't' seconds. And horizontal distance covered by it in 't' seconds is x meters. The vertical distance traveled by it in 't' second would be equal to the height of the cliff.
Now for finding time 't' secondsVertical distance traveled = s = 122.5m
Initial vertical speed = u = 0 m/s
Acceleration due to gravity = g = 9.8 m/s²
By using the second equation of motion:
s = ut + 1/2gt²
Put in the value
122.5 = (0)t + 1/2(9.8)t²
122.5 = 0 + 4.9t²
t² = 122.5/4.9
t² = 25
t =√25
t = 5 seconds
For finding the distance x metersHorizontal speed = v = 8.0 m/s
Time taken = t = 5 s
Acceleration = 0 m/s
Using the formula, distance = speed × time
x = v × t
x = 8.0 × 5
x = 40.0 m
Therefore the object strikes 40.0 meters far from the base of the cliff on the ground.
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Two gases are contained in gas bulbs connected by a valve. Gas a is present in a 1 liter bulb at a pressure of 818 torr. Gas b exerts a pressure of 328 torr in a 1 liter bulb. The valve is opened and the two gases come to equilibrium. What is the partial pressure of gas a expressed after equilibrium?.
The partial pressure of gas expressed after equilibrium is 409 torr.
Which gas is used for bulbs?Incandescent light bulbs are usually filled with argon, which is a common gas. It prolongs bulb life by keeping the tungsten filaments from decaying too quickly. Lighting also makes use of other gases like helium, neon, nitrogen, and krypton.Incandescent lights are what gas lamps are. They generate heat by burning fuel like propane, white gas, or kerosene, and the heat drives light production from the mantles. The mantles, which are made of a ceramic mesh, contain the lantern's flame.The first kind of gas employed, argon, is a gas that is typically found in incandescent light bulbs. Nitrogen may occasionally be added to argon gas. Halogen or xenon gas can be found in some light bulbs. Some light bulbs also include krypton gas.What is the partial pressure of gas expressed after equilibrium:
1. Write out the units given.
V1= 1 L
Ptot= 818 torr
PPB= 328 torr
V2= 1L
2. Remember= PaVa= PtotVtot
3. Add together volumes for total volumes.
1 L + 1 L= 2 liters
4. Plug in values and solve for PP of gas A.
PPA= Ptot x VA/Vtot
818 torr x 1/2 L= 409 torr
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a circular cylindrical post with a circumference of 4 feet has a string wrapped around it, spiraling from the bottom of the post to the top of the post. the string evenly loops around the post exactly four full times, starting at the bottom edge and finishing at the top edge. the height of the post is 12 feet. what is the length, in feet, of the string?
The length of the string wrapped around a circular cylindrical post is 20ft.
We have a circular cylinder and a string wrapped around it.
If we unwrap one complete revolution of string around the post. We have a rectangle. Having a width of 4ft (that is the circumference of the post.)
height of the post is 12 feet
Then height of the rectangle is. 12/4 = 3ft
The string evenly loops around the post exactly four full times, starting at the bottom edge and finishing at the top edge.
So the length of this is the hypotenuse of right triangle sides 3 and 4
then length determined using Pythagoras theorem
L² = 3²+4² = 25
L =√25 =5ft
Here we have three more similar triangles in more 3 revolution.
1 revolution×5+ 3revolution×5
4×5 =20ft
The length of the string wrapped around a circular cylindrical post is 20ft.
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problem 11.009 - slowing car - dependent multi-part problem - assign all parts skip to question note: this is a multi-part question. once an answer is submitted, you will be unable to return to this part. the brakes of a car are applied, causing it to slow down at a rate of 13 ft/s2. the car stops at 300 ft.
The velocity of the car before the brakes were applied is 88.32 ft / s
We know that,
a = ( v - u ) / t
s = ut + 1 / 2 a[tex]t^{2}[/tex]
where,
a = Acceleration
v = Final velocity
u = Initial velocity
t = Time taken
s = Displacement
Given that,
v = 0
s = 300 ft
a = - 13 ft / [tex]s^{2}[/tex]
a = ( v - u ) / t
- 13 = ( 0 - u ) / t
t = u / 13
s = ut + 1 / 2 a[tex]t^{2}[/tex]
300 = u ( u / 13 ) + 1 / 2 ( - 13 ) ( u / 13 [tex])^{2}[/tex]
300 = [tex]u^{2}[/tex] / 13 - [tex]u^{2}[/tex] / 26
[tex]u^{2}[/tex] = 7800
u = 88.32 ft / s
Velocity is the rate of change of distance with respect to time. It is denoted by V. Its units are mostly m/s, ft/s etc.
Therefore, the velocity of the car before the brakes were applied is 88.32 ft / s
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A cannonball is shot from level ground with a velocity of 240.0 m/s at an angle of 32 degrees. How long does the ball take to hit the ground?
The time of flight is obtained as 25.9 seconds
What is the time of flight?The time of flight is the time taken to move the object that have been projected along the parabolic path. In this case, we have a cannonball that have been fired from level ground with a velocity of 240.0 m/s at an angle of 32 degrees.
We know that from the question
T = 2usinθ/g
T = time of flight
u = initial velocity
θ = angle of projection
g = acceleration
T = 2 * 240.0 m/s * sin 32 degrees/9.8 m/s^2
T = 25.9 seconds
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The change in internal energy for a given system is –325 j. The system loses 155 j of energy as heat at the same time that it expands from an initial volume of 15. 0 l at 1. 00 atm of pressure. What is the final volume of the system in liters?.
According to internal energy, the final volume is 19.75 liters.
We need to know about internal energy to solve this problem. For a closed system, with matter transfer excluded, the changes in internal energy are due to heat transfer and due to thermodynamic work done by the system on its surroundings. It can be determined as
ΔU = Q - W
where ΔU is the change in internal energy, Q is heat and W is work done.
From the question above, we know that
ΔU = -325 J
Q = 155 J
Vo = 15 L = 0.015 m³
P = 1 atm = 1.01 x 10⁵ Pa
By substituting the given parameter, we can calculate the work done
ΔU = Q - W
-325 = 155 - W
W = 480 joule
Find the final volume
W = P . (Vi - Vo)
480 = 1.01 x 10⁵ (Vi - 0.015)
Vi = 0.01975 m³
Vi = 19.75 liters
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if the straight-line distance from her home to the university is 8.9 km in a direction 25° south of east, what was the magnitude of her average velocity in kilometers per hour?
The magnitude of her average velocity in kilometers is 29 km/h.
The average velocity of an object is defined as the average distance covered by an object in a given time interval. It can be presented in the unit as a meter per second or kilometer per second. It is represented by the symbol 'v'.
The straight line distance from her home is d.
d. = 8.9 km
The direction of her home = 50° south of east
The magnitude of her average velocity is,
[tex]Average \: velocity = \frac{ Distance \: trailed \: by \: the \: object}{ Time \: taken \: to{ cover \: the \: distance}}[/tex]
[tex] = \frac{8.9}{18} \times \frac{18}{1} [/tex]
= 29 km/h
Therefore, the magnitude of her average velocity in kilometers is 29 kilometers per hour.
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