Answer:
[tex]\huge\boxed{\sf CNH_4}[/tex]
Explanation:
Empirical formula:The simplest whole number ratio of atoms in a compound is known as empirical formula.Solution:Given compound us,
C₂N₂H₈
Ratio:= 2 : 2 : 8
Divide by 2= 2 ÷ 2 : 2 ÷ 2 : 8 ÷ 2
= 1 : 1 : 4
So, we can write the formula as:
= CNH₄[tex]\rule[225]{225}{2}[/tex]
i need help with this, ive been trying to figure it out but i don’t understand. please number them 1-5 for the answers.
The solubility of the salts is affected by the temperature changes. 1. NaCl is least affected by temperature. 2. supersaturated. 3. 60 grams KBr. 4. Ethanol has both polar and non-polar groups. 5. Mixing and shaking.
A KBr solution with 90 gm solute in 100 grams of water at 50 degrees is classified as supersaturated. 60 grams of KBr are needed to make a saturated solution in 100 gm of water at 30 degrees.
Ethanol is a general solvent due to the presence of both the polar and the non-Polar groups. As a result, it is easier to dissolve both polar molecules and non-Polar molecules. The dissolving rate can be increased by mixing or shaking the solution. Also, the sugar dissolves faster in hot than cold tea.
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CHEM FINAL TOMORROW!!! I'm struggling with a few concepts, if anyone could help explain this to me & how to do it, I'd be very grateful!!!
Based on the given reaction, the acid-base pairs in this reaction are:
HCO₃⁻ (acid) and NH₃ (base)NH₄⁺ (acid) and CO₃²⁻ (base)What are the acid-base pairs in the given reaction?An acid-base pair refers to a set of two chemical species that are related through the transfer of a proton (H+ ion) during a chemical reaction.
One species acts as an acid by donating a proton, while the other acts as a base by accepting that proton.
In the given reaction:
HCO₃⁻ (aq) + NH₃ (aq) → NH₄⁺ + CO₃²⁻
An acid-base pair can be identified as follows:
HCO₃⁻ (bicarbonate ion) can act as an acid by donating a proton (H⁺), becoming CO₃⁻.
NH₃ (ammonia) can act as a base by accepting a proton (H⁺), becoming NH₄⁺ (ammonium ion).
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B2 2- orbital picture
Describe two ways in which sodium chloride is different from sodium
Answer:
Sodium (Na) is a highly reactive metal, while sodium chloride (NaCl) is a compound formed by the combination of sodium and chlorine (Cl). Sodium exists as a pure element, whereas sodium chloride is a stable, crystalline compound.
Sodium is a soft, silvery-white metal that is highly reactive and can easily react with water or air. In contrast, sodium chloride is a white crystalline solid that is highly stable and does not react readily with water or air. Sodium chloride is commonly known as table salt and is widely used as a seasoning and food preservative.
How many moles of H2O are found in a sample containing 7.1 * 10 (19) molecules
The sample containing 7.1 × 10^19 molecules of H2O corresponds to approximately 1.18 × 10^(-4) moles of H2O.
To determine the number of moles of H2O in a sample containing 7.1 × 10^19 molecules, we need to use Avogadro's number, which states that 1 mole of any substance contains 6.022 × 10^23 molecules.
Given that there are 7.1 × 10^19 molecules of H2O in the sample, we can calculate the number of moles using the following formula:
Moles = Number of molecules / Avogadro's number
Moles = 7.1 × 10^19 / 6.022 × 10^23
Moles ≈ 1.18 × 10^(-4) moles
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Question 5 of 25
What is the name of the branched alkane shown below?
Answer:
3rf or 5d cd Yu been successful of a new future
The name of the branched alkane shown below is 2- methylheptane that is in option D as alkane is a type of hydrocarbon, which is a compound consisting of hydrogen and carbon atoms only.
Alkanes are characterized by having single bonds between carbon atoms and being saturated hydrocarbons, meaning they have the maximum number of hydrogen atoms bonded to each carbon atom. Alkanes are often referred to as "paraffins" and serve as the simplest and most basic form of hydrocarbons. They are relatively unreactive and are commonly found in petroleum and natural gas. The systematic names for alkanes are derived from the prefix "n-" or "normal-," followed by the Greek numerical prefix indicating the number of carbon atoms. For example, "n-pentane" refers to the straight-chain alkane with five carbon atoms.
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Need help with this 2 part question
The limiting reagent is chlorine and the correct option is option 2.
In a chemical reaction, the limiting reagent is the reactant that determines the quantity of the products that are produced. Limiting reagents are defined as the substances which are entirely consumed in the completion of a chemical reaction and so a limiting reagent limits the formation of products and determines the amount of products obtained in the reaction.
The limiting reagent can be identified from the number of moles in the reaction, the one that is having the lesser number of moles acts as a limiting reagent in the reaction.
Given,
Moles of hydrogen = 5.3 moles
Moles of chlorine = 4.8 moles
Limiting reagent is the one that has lesser number of moles and thus chlorine is the limiting reagent in this reaction.
Thus, the ideal selection is option 2.
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convert 5 moles of water to grams of water
convert 220 J of energy to calories
The 5 moles of water is equal to 90.075 grams of water and 220 J of energy is equal to 52.636 calories.
To change moles of water to grams, it is required to find the molar mass of the substance. The molar mass of water (H2O) is equal to 18.015 grams/mol.
To change 5 moles of water to grams, by using the following calculation:
5 moles × 18.015 grams/mol = 90.075 grams of water
Thus, 5 moles of water is equal to 90.075 grams of water.
To change joules to calories, by using the conversion factor:
1 cal = 4.184 J.
To change 220 J of energy to calories, by using the following calculation:
220 J × (1 cal / 4.184 J) = 52.636 cal
Thus, 220 J of energy is equal to 52.636 calories.
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determine if the following are ionic or covalent compounds
a. P2O7
b. SnBr2
c.Fe(OH)2
d.Cl3O8
Answer:
a. P2O7 - This is a covalent compound. P and O have similar electronegativities and they form a covalent bond between them, rather than an ionic bond.
b. SnBr2 - This is a covalent compound. Sn and Br have different electronegativities, but they still form a covalent bond due to their relatively small difference in electronegativity.
c. Fe(OH)2 - This is an ionic compound. Fe has a higher electronegativity than O and H, so it tends to donate its electrons and become positively charged. This results in the formation of ionic bonds between Fe and OH.
d. Cl3O8 - This is a covalent compound. Cl and O have similar electronegativities, so they form covalent bonds rather than ionic bonds.
If you placed 413g of Bal2 in a beaker and filled it with water to a total volume of 750ml, calculate the molarity of the solution
To calculate the molarity of a solution, we need to determine the number of moles of the solute (Bal2) and then divide it by the volume of the solution in liters.
Given:
Mass of Bal2 = 413 g
Volume of solution = 750 ml = 0.75 L
1. Calculate the number of moles of Bal2:
First, we need to convert the mass of Bal2 to moles using its molar mass. The molar mass of Bal2 can be calculated by summing the atomic masses of boron (B) and iodine (I):
Molar mass of Bal2 = (atomic mass of B × 1) + (atomic mass of I × 2)
Molar mass of Bal2 = (10.81 g/mol × 1) + (126.90 g/mol × 2)
Molar mass of Bal2 = 10.81 g/mol + 253.80 g/mol
Molar mass of Bal2 = 264.61 g/mol
Now we can calculate the number of moles of Bal2:
Moles of Bal2 = Mass of Bal2 / Molar mass of Bal2
Moles of Bal2 = 413 g / 264.61 g/mol
Moles of Bal2 ≈ 1.561 mol
2. Calculate the molarity of the solution:
Molarity (M) = Moles of solute / Volume of solution (in liters)
Molarity (M) = 1.561 mol / 0.75 L
Molarity (M) ≈ 2.081 M
Therefore, the molarity of the solution is approximately 2.081 M.
The molarity of the solution is approximately 1.408 M as to calculate the molarity of a solution, one must need to know the number of moles of the solute and the volume of the solution in liters.
The molar mass of BaI₂ is:
Ba (barium) atomic mass = 137.33 g/mol
I (iodine) atomic mass = 126.90 g/mol
Molar mass of BaI₂ = (Ba atomic mass) + 2 × (I atomic mass)
= 137.33 + 2 × 126.90
= 137.33 + 253.80
= 391.13 g/mol
Given that the mass of BaI₂ is 413 g,
Number of moles = Mass / Molar mass
= 413 g / 391.13 g/mol
= 1.056 moles
Volume of solution = 750 ml = 750/1000 = 0.75 L
Finally, one can calculate the molarity of the solution using the formula:
Molarity = Number of moles / Volume of solution
= 1.056 moles / 0.75 L
= 1.408 M
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How are moles and particles related. How could you find the number of particles in 4 moles of substance
which stament is true about endothermic and exothermic reactions? 1. Energy is absorbed 2. energy is released in an endothermic reaction. 3. the products have more potential energy than the reactants in an exothermic reaction. 4. the products have more potential energy than the reactant in an endothermic reaction.
The Statement 3 (the products have more potential energy than the reactants in an exothermic reaction) is partially correct because the products do have lower potential energy than the reactants in an exothermic reaction.
The correct statement regarding endothermic and exothermic reactions is:
Energy is absorbed in an endothermic reaction.
In an endothermic reaction, energy is taken in from the surroundings, usually in the form of heat. The reactants have a lower energy level than the products, so energy must be absorbed to reach the higher energy state of the products. This energy absorption causes a decrease in the temperature of the surroundings, making the reaction feel cold.
On the other hand, in an exothermic reaction, energy is released. The reactants have a higher energy level than the products, so energy is released during the reaction, usually in the form of heat. This energy release causes an increase in the temperature of the surroundings, making the reaction feel warm or hot.
Therefore, statement 2 (energy is released in an endothermic reaction) and statement 4 (the products have more potential energy than the reactant in an endothermic reaction) are incorrect.
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While preparing 2.00 L of iced tea, Dora adds 0.750 moles of sucrose. What is the molarity of the sucrose in the iced tea mixture?
The molarity of the sucrose in the iced tea mixture prepared by dissolving 0.750 moles of sucrose in the 2.00 L of iced tea is
How do i determine the molarity of the solution?The following data were obtained from the question:
Number of mole of sucrose = 0.750 moleVolume of solution = 2 LitersMolarity of solution = ?The molarity of the solution can be obtained as illustrated below:
Molarity of solution = mole / volume
Molarity of solution = 0.750 mole / 2 liters
Molarity of solution = 0.375 M
Thus, we can conclude from the above calculation that the molarity of the solution is 2.5 M
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How many particles of Copper are produce when 3.85 grams of Copper (II) Chloride is consumed with excess aluminum according to the reaction below?
The number of particles of copper produced when 3.85 grams of Copper (II) Chloride is consumed is approximately [tex]1.728 * 10^2^2[/tex] particles.
To determine the number of particles of copper produced when 3.85 grams of Copper (II) Chloride is consumed with excess aluminum, we need to use stoichiometry and the balanced chemical equation for the reaction.
The balanced chemical equation for the reaction between Copper (II) Chloride (CuCl2) and aluminum (Al) is:
[tex]3CuCl_2 + 2Al[/tex] -> [tex]2AlCl_3 + 3Cu[/tex]
From the balanced equation, we can see that for every 3 moles of[tex]CuCl_2[/tex]consumed, 3 moles of Cu are produced.
First, we need to calculate the number of moles of [tex]CuCl_2[/tex] in 3.85 grams. To do this, we divide the mass of[tex]CuCl_2[/tex] by its molar mass. The molar mass of [tex]CuCl_2[/tex] can be calculated by summing the atomic masses of its constituent elements: Cu (63.55 g/mol) and Cl (35.45 g/mol).
Molar mass of[tex]CuCl_2[/tex] = 63.55 g/mol (Cu) + (2 * 35.45 g/mol) (Cl) = 134.45 g/mol
Number of moles of CuCl2 = 3.85 g / 134.45 g/mol ≈ 0.0287 mol
Since the stoichiometry of the reaction states that 3 moles of CuCl2 produce 3 moles of Cu, we can conclude that 0.0287 mol of CuCl2 will produce 0.0287 mol of Cu.
Finally, to calculate the number of particles (atoms or molecules) of copper produced, we multiply the number of moles of Cu by Avogadro's number, which is approximately [tex]6.022 * 10^2^3[/tex]particles/mol.
Number of particles of Cu = 0.0287 mol * [tex]6.022 * 10^2^3[/tex] particles/mol
Therefore, the number of particles of copper produced when 3.85 grams of Copper (II) Chloride is consumed is approximately [tex]1.728 * 10^2^2[/tex]particles.
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The system at equilibrium below is heated.
How does the system adjust to reestablish
equilibrium?
2SO₂(g) + O₂(g) ⇒ 2SO3(g) + 198 kJ
An atom has 17 protons and 17 electrons.The atoms charge is
An atom has 17 protons and 17 electrons. The atom's charge is neutral. The positive charge of the 17 protons in this atom is balanced by the negative charge of the 17 electrons.
The ratio of an atom's protons, which have a positive charge, to its electrons, which have a negative charge, determines the charge of the atom. The quantity of protons in an electrically neutral atom is equal to the quantity of electrons.
The positive charge of the 17 protons in this atom is balanced by the negative charge of the 17 electrons, since there are 17 protons and 17 electrons in it. Consequently, the atom is electrically neutral or has a net charge of zero.
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Discuss three types of valency
Monovalent Valency, Divalent Valency and Multivalent Valency are three types of valency.
Valency refers to the combining capacity of an atom to form chemical bonds. There are three types of valency:
Monovalent: Atoms with a valency of 1 can form only one bond. Examples include hydrogen (H) and chlorine (Cl), which can each form one bond.
Divalent: Atoms with a valency of 2 can form two bonds. Oxygen (O) and calcium (Ca) are examples of divalent atoms.
Multivalent: Atoms with multiple valencies can form different numbers of bonds. Transition metals such as iron (Fe) and copper (Cu) exhibit multivalency, allowing them to form varying numbers of bonds, depending on the specific compound and oxidation state.
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5. 75.0 g of 4.0°C water is heated until its temperature is 37°C. If the specific heat of water is 4.18 J/g°C, calculate the energy needed to cause this rise in temperature. SHOW YOUR WORK
The energy required to cause the rise in temperature of 75g of water is 10345.5J.
Specific heat is a physical property of a substance that quantifies the amount of heat energy required to raise the temperature of a unit mass of the substance by one degree Celsius (or one Kelvin).
Given information,
Mass (m) = 75g
Specific heat (c) = 4.18 J/g°C
Change in temperature (Δt) = 37°C - 4°C = 33°C
The formula that can be used to determine the energy is, Energy (Q) = m × c × Δt
Q = 75 × 4.18 × 33
Q = 10345.5J
Therefore, the energy needed to cause the rise in temperature of 75.0 g of water from 4.0°C to 37°C is 10345.5J.
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Identify reactions types and balancing equations
The following chemical equations must be balanced:
1. N2 + 3 H2 → 2 NH3
Type: Synthesis
2. 2 KClO3 → 2 KCl + 3 O2
Type: Single Replacement
3. 2 NaF + ZnCl2 → ZnF2 + 2 NaCl
Type- Decomposition
4. 2 AlBr3 + 3 Ca(OH)2 → Al2(OH)6 + 6 CaBr2
Type- Double Replacement
5. 2 H2 + O2 → 2 H2O
Type: Combustion
6. 2 AgNO3 + MgCl2 → 2 AgCl + Mg(NO3)2
Type: Synthesis
7. 2 Al + 6 HCl → 2 AlCl3 + 3 H2
Type: Decomposition
8. C3H8 + 5 O2 → 3 CO2 + 4 H2O
Type: Combustion
9. 2 FeCl3 + 6 NaOH → Fe2O3 + 6 NaCl + 3 H2O
Type: Double Replacement
10. 4 P + 5 O2 → 2 P2O5
Type: Synthesis
11. 2 Na + 2 H2O → 2 NaOH + H2
Type: Single Replacement
12. 2 Ag2O → 4 Ag + O2
Type: Decomposition
13. C6H12O6 + 6 O2 → 6 CO2 + 6 H2O
Type: Combustion
14. 2 KBr + MgCl2 → 2 KCl + MgBr2
Type: Double Replacement
15. 2 HNO3 + Ba(OH)2 → Ba(NO3)2 + 2 H2O
Type: Double Replacement
16. C5H12 + 8 O2 → 5 CO2 + 6 H2O
Type: Combustion
17. 4 Al + 3 O2 → 2 Al2O3
Type: Synthesis
18. Fe2O3 + 2 Al → 2 Fe + Al2O3
Type: Single Replacement
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Which statement best explains why different gases effuse at different rates?
Different gases effuse at different rates due to the relationship between their molecular masses, average velocities, and kinetic energy.
Lighter gases have higher average velocities and effuse more rapidly, while heavier gases have lower average velocities and effuse at slower rates. Graham's law of effusion provides a quantitative explanation for this phenomenon.
Different gases effuse at different rates due to variations in their molecular masses and average velocities. Effusion is the process by which gas molecules escape through a small opening or porous barrier into a vacuum or a region of lower pressure.
According to Graham's law of effusion, the rate of effusion of a gas is inversely proportional to the square root of its molar mass. Mathematically, it can be expressed as:
Rate A / Rate B = √(Molar mass B / Molar mass A)
This means that lighter gas molecules, with lower molar masses, effuse faster compared to heavier gas molecules. The reason behind this can be understood by considering the kinetic theory of gases.
Gas molecules are in constant random motion, colliding with each other and the walls of the container. The average velocity of gas molecules is directly related to their kinetic energy, which depends on their mass and temperature. Lighter gas molecules have higher average velocities due to their lower mass and therefore higher kinetic energy.
During effusion, gas molecules near the opening of the container collide with the walls more frequently and possess higher velocities. Lighter gas molecules have a higher chance of having a velocity that exceeds the escape velocity threshold, allowing them to effuse more easily.
On the other hand, heavier gas molecules have lower average velocities and collide less frequently with the walls. They require more energy or higher velocities to overcome intermolecular forces and effuse through the opening.
In summary, different gases effuse at different rates due to the relationship between their molecular masses, average velocities, and kinetic energy. Lighter gases have higher average velocities and effuse more rapidly, while heavier gases have lower average velocities and effuse at slower rates. Graham's law of effusion provides a quantitative explanation for this phenomenon.
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What is the percent strength of a 1:25 (weight/volume) solution?
Answer:
First, let's consider the ratio: 1:25. This means that for every 1 gram of solute, we have 25 milliliters of solvent. Therefore, if we have 100 milliliters of the solution, we can set up a proportion to find the amount of solute in grams:
1 gram solute / 25 milliliters solvent = x grams solute / 100 milliliters solution
Cross-multiplying, we get:
25 * x = 1 * 100
25x = 100
x = 100 / 25
x = 4
So, in 100 milliliters of a 1:25 (weight/volume) solution, there are 4 grams of solute.
To calculate the percent strength, we divide the mass of the solute (4 grams) by the volume of the solution (100 milliliters) and multiply by 100:
Percent strength = (mass of solute / volume of solution) * 100
Percent strength = (4 g / 100 mL) * 100
Percent strength = 4%
Therefore, the percent strength of a 1:25 (weight/volume) solution is 4%.
I need help with question 5
Determine the empirical formula for a compound that is 29.15% N, 8. 41% H, 12.50% C and 49.9% 0
[tex]\Large \textsf{$\boxed{\boxed{\rm (NH_4)_2CO_3}}$}[/tex]
Explanation:When working with percentage compositions, we can say, "let the mass of the compound be 100 grams."
[tex]\large \textsf{$\therefore$ There is 29.15 g of nitrogen, 8.41 g of hydrogen, 12.50 g of carbon, }\\ \large \textsf{\ \ \ and 49.9 g of oxygen in 100 g of compound.}[/tex]
Empirical Formula:The empirical formula of a compound is its formula in which the constituent elements are in the simplest mole ratio.
To find the number of moles of each element (denoted by symbol [tex]\textsf{$n$}[/tex]), we can divide the mass of each element (in grams, denoted by symbol [tex]\large \textsf{$m$}[/tex]), by the molar mass of each element (in g/mol, denoted by symbol [tex]\textsf{$M$}[/tex]), which can be found on an international standard IUPAC Periodic Table.
[tex]\Large \textsf{$\therefore \rm number\ of\ moles=\frac{mass\ present}{molar\ mass}$}[/tex]
[tex]\Large \textsf{$\implies \boxed{n= \frac{m}{M}}$}[/tex]
Now we can apply this to the above masses of each element:
[tex]\large \textsf{$n(\rm N) = \frac{29.15}{14.01}$}\\\\\large \textsf{$\phantom{n(\rm N)}=2.0807\ \rm mol$}\\\large \textsf{$n(\rm H) = \frac{8.41}{1.008}$}\\\\\large \textsf{$\phantom{n(\rm H)}=8.3433\ \rm mol$}\\\\\large \textsf{$n(\rm C) = \frac{12.50}{12.01}$}\\\\\large \textsf{$\phantom{n(\rm C)}=1.0408\ \rm mol$}\\\\\large \textsf{$n(\rm O) = \frac{49.9}{16.00}$}\\\\\large \textsf{$\phantom{n(\rm O)}=3.1188\ \rm mol$}\\[/tex]
[tex]\large \text{$\therefore $ the ratio of N : H : C : O}\\\\ \large \text{$\Rightarrow$2.0807 : 8.3433 : 1.0408 : 3.1188}[/tex]
Simplifying this ratio by dividing all parts by 2.0807:
[tex]\large \text{$\therefore$ 1 : 4.0098 : 0.5002 : 1.4989}\\\\\large \text{$\implies$ 1 : 4 : 0.5 : 1.5}[/tex]
Since the mole ratio is displayed in integers, multiply this result by 2:
[tex]\large \text{$\therefore$ 2 : 8 : 1 : 3 is the final mole ratio.}\\\\\\ \large \text{$\boxed{\boxed{\implies \rm N_2H_8CO_3$ or $\rm (NH_4)_2CO_3}}$}[/tex]
Note: the compound found, is a common ionic compound known as ammonium carbonate.
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what is the concentration of a nitric acid solution if 10.0 ml of the solution is neutralized by 3.6 ml of 0.2 m naoh?
Answer:
The concentration of the nitric acid (HNO3) solution is 72 M.
Explanation:
To determine the concentration of the nitric acid solution, we can use the concept of stoichiometry and the equation of the neutralization reaction between nitric acid (HNO3) and sodium hydroxide (NaOH):
HNO3 + NaOH → NaNO3 + H2O
The balanced equation shows that the molar ratio between HNO3 and NaOH is 1:1. This means that 1 mole of HNO3 reacts with 1 mole of NaOH.
Given:
Volume of HNO3 solution = 10.0 ml
Volume of NaOH solution = 3.6 ml
Molarity of NaOH solution = 0.2 M
To find the concentration of the HNO3 solution, we need to calculate the number of moles of NaOH used in the neutralization reaction:
moles of NaOH = volume of NaOH solution * molarity of NaOH solution
= 3.6 ml * 0.2 M
= 0.72 mmol (millimoles)
Since the molar ratio between HNO3 and NaOH is 1:1, the number of moles of HNO3 in the solution is also 0.72 mmol.
Now, we can calculate the concentration of the HNO3 solution using the formula:
concentration (in M) = moles of solute / volume of solution (in L)
concentration = 0.72 mmol / 0.010 L
= 72 mmol/L
= 72 M
Therefore, the concentration of the nitric acid (HNO3) solution is 72 M.
need help asap!!
u don’t gotta answer all questions btw
The molarity of the 750 ml solution of BaI₂ was calculated to be 0.787 M.
413 grams of BaI₂corresponds to 1.05 moles and 750 ml of water corresponds to 0.75 liters of water. So the molarity of the solution is calculated as
1.05* 0.75= 0.787 moles.
24) Thus the molarity of the solution is 0.787 M.
25) P₂O₇ is a covalent compound. Both phosphorous and oxygen have similar electronegativity.
SnBr₂ is ionic as the electronegativity difference between the two is less.
Fe(OH)₂ is an ionic compound.
Cl₃O₈ is a covalent compound.
26) (NH₄)₂CO₃ is highly soluble in water while Fe(OH)₂ is insoluble in water. CaOH is poorly soluble in water while PbCl₂is only sparingly soluble in water.
27) In the given reaction FeS is formed as the precipitate and it is highly insoluble in water while the KCl is dissolved in the aqueous solution.
In the second reaction, ZnCl₂ is soluble as a part of the aqueous solution while strontium sulfate forms the precipitate.
28) In salt water salt is the solute and water is the solvent.
29) Air pressure is lower in a higher atmosphere. The pressure is 0.65 atm and the temperature is -15 degrees at the altitude where the balloon has risen. As the balloon rises, the external pressure decreases and the balloon volume increases. However, the internal pressure or ballon volume remains the same.
30) With an increase in the temperature of a substance, the kinetic energy of the substance increases too.
31) With an increase in the pressure, volume decreases while with a pressure decreases volume increases.
32) If the temperature of a gas increases the pressure also increases.
33) When the plunger is pushed in, the air pressure increases. This pushes the bubbles out and reduces the size of the marshmallow. When the plunger is pushed out, the air pressure decreases, causing the marshmallow to expand.
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A gas occupies a volume of 139.3-mL at 135.5-kPa. What volume will the gas occupy at 138.7-kPa if the temperature remains the same?
The volume the gas will occupy at pressure of 138.7 KPa, given that the temperature remains the same is 136 mL
How do i determine the new volume of the gas?The new volume of the gas, given that the new pressure is 138.7 KPa can be obtained as follow:
Initial volume of gas (V₁) = 139.3 mLInitial pressure of gas (P₁) = 135.5 KPaNew pressure of gas (P₂) = 138.7 KPaNew volume of gas (V₂) =?P₁V₁ = P₂V₂
Inputting the given parameters, we have:
135.5 × 139.3 = 138.7 × V₂
18875.17 = 138.7 × V₂
Divide both side by 138.7
V₂ = 18875.17 / 138.7
V₂ = 136 mL
Thus, we can conclude that the volume of the gas will be 136 mL
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How many grams of AgCl will be produced from 5.00 g of NaCl and 103 g of AgNo3
Approximately 12.27 grams mass of AgCl will be produced from 5g of NaCl and 103g of AgNO₃.
Given information,
Mass of NaCl = 5g
Mass of AgNO₃ = 103g
The number of moles of NaCl and AgNO₃:
Molar mass of NaCl = 22.99 + 35.45 = 58.44 g/mol
Number of moles of NaCl = 5.00/ 58.44 = 0.0856 mol
Molar mass of AgNO₃ = 107.87 + 14.01 ) + 3 × 16.00 = 169.87 g/mol
Number of moles of AgNO₃ = 103 / 169.87 = 0.606 mol
The stoichiometry of the balanced chemical equation between NaCl and AgNO₃: AgNO₃ + NaCl → AgCl + NaNO₃
1 mole of AgNO₃ reacts with one mole of NaCl to produce one mole of AgCl.
For NaCl: Moles of AgCl produced from NaCl = 0.0856 mol
For AgNO₃: Moles of AgCl produced from AgNO₃ = 0.606 mol
Since NaCl produces fewer moles of AgCl, it is the limiting reactant.
Molar mass of AgCl = 107.87 + 35.45 = 143.32 g/mol
Mass of AgCl produced from NaCl = 0.0856 × 143.32 ≈ 12.27 g
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SECTION 1 Surface Water Movement (continued)
MAIN IDEA
DETAILS
Load/Stream magnesium compounds found in surface water, compare to the
Stream Explain how minerals, such as calcium carbonate and soluble
sugar in lemonade.
Answer:
Basically, they r different chemically and radically.
Explanation:
Here is how:
So,
Magnesium compounds found in surface water can vary depending on the specific water source and environmental factors. However, some common magnesium compounds that can be present in surface water include:
Magnesium Carbonate (MgCO3): This compound can form when magnesium ions (Mg2+) react with carbonate ions (CO32-) present in the water. It is often found in areas where there are limestone or dolomite formations.
Magnesium Hydroxide (Mg(OH)2): This compound can occur when magnesium ions react with hydroxide ions (OH-) in the water. It is more likely to be present in alkaline or basic water conditions.
Magnesium Sulfate (MgSO4): This compound can form when magnesium ions react with sulfate ions (SO42-) in the water. It can be found in areas where there are sulfates present, such as in some mining or industrial areas.
Now, let's compare these magnesium compounds to minerals like calcium carbonate and soluble sugar in lemonade:
Calcium Carbonate (CaCO3): Calcium carbonate is a common mineral found in many natural sources, including limestone, chalk, and shells of marine organisms. It is insoluble in water and tends to precipitate out of the solution, forming solid deposits or scale.
Soluble Sugar in Lemonade: Lemonade typically contains sucrose or other soluble sugars. These sugars are highly soluble in water, meaning they readily dissolve and form a homogeneous mixture with water.
In comparison to magnesium compounds found in surface water, calcium carbonate and soluble sugar in lemonade are chemically different. Calcium carbonate is insoluble in water and tends to separate from the solution, while soluble sugars dissolve completely.
Number 4 please please pleaseeee
If it travells at 330m/s, and it has to travel 5100m just
5100 ÷ 330
because time = distance ÷ speed
= 15.45 s
Answer:
15.4545455 seconds
Explanation:
(5100 m) / (330 (m / s))
5100/330 = 15.4545455 seconds
What is the name of LiBr and what is the charge of the cation (indicate the number and - or +)?
The name of LiBr is lithium bromate and the charge of the cation (K) is +.
What is a cation?A cation is a positively charged ion, i.e. one that would be attracted to the cathode in electrolysis. The opposite of a cation is an anion.
Cations and anions make up an ionic compound and determine the charge on the compound. For example, an ionic compound; Lithium bromate is given in this question.
Lithium bromate is made up of Lithium (Li+) as the cation and chlorine (Cl-) as the anion.
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