Calculate Kb for a 0.1 M solution of cyanide ion, given that Ka for hydrocyanic acid is 6.2 x 10â10.a) 8.4 x 10â9b) 7.87 x 10â3c) 1.34 x 10â3d) 1.8 x 105e) 7.87 x 10â6f) 1.61 x 10â5g) 7.4 x 10â8

Answers

Answer 1

Answer:

Kb = 1.6 × 10⁻⁵

Explanation:

Step 1: Given data

Acid dissociation constant of hydrocyanic acid (Ka): 6.2 × 10⁻¹⁰

Concentration of cyanide ion (Cb): 0.1 M

Step 2: Calculate the basic dissociation constant (Kb) of cyanide ion

We have the Ka of HCN. We can calculate the Kb of its conjugate base using the following expression.

Ka × Kb = Kw = 1.0 × 10⁻¹⁴

Kb = 1.0 × 10⁻¹⁴/Ka

Kb = 1.0 × 10⁻¹⁴/6.2 × 10⁻¹⁰

Kb = 1.6 × 10⁻⁵

Answer 2

The  Kb for a 0.1 M solution of cyanide ion is :

- 1.6 × 10⁻⁵

Base dissociation constant

Given:

Acid dissociation constant of hydrocyanic acid (Ka)= 6.2 × 10⁻¹⁰

Concentration of cyanide ion (Cb)= 0.1 M

Base dissociation constant (kb)=?

Ka × Kb = Kw = 1.0 × 10⁻¹⁴

Kb = 1.0 × 10⁻¹⁴/Ka

Kb = 1.0 × 10⁻¹⁴/6.2 × 10⁻¹⁰

Kb = 1.6 × 10⁻⁵

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Related Questions

Given the reaction _K(s) +_ Cl2(g) → _KCl(s) what is the amount of K, in grams, needed to completely react with 2 moles of Cl2(g)?

Answers

Answer:

156.4g K

Explanation:

I'm not sure if it is correct but I think it should be this

What do we know so far?: 2K + 1Cl2 -> 2KCl, 2 mol of Cl2

What are we looking for?: #g of K

What is the ratio of K to Cl2?: 2:1

Set up equation: 2molCl2 x [tex]\frac{2mol K}{1 mol Cl2}[/tex]

Cancel unwanted units: 2 x [tex]\frac{2mol K}{1}[/tex]

Answer we got: 2 x 2mol K = 4mol K

Converting moles to grams: 4 x 39.1 (molar mass of K) = 156.4g K

Which element would most likely have a chemical reactivity similar to bromine?

Answers

Answer:

Bromine is a very reactive element. While it is less reactive than fluorine or chlorine, it is more reactive than iodine. It reacts with many metals, sometimes very vigorously. For instance, with potassium, it reacts explosively.

Explanation:

Answer: Bromine is a high reactive element. While it is not as reactive as fluorine or chlorine, it is still more reactive than iodine. It reacts with many metals, and even sometimes very aggressively. For example, when mixed with potassium, it will explode.  

Explanation:

An object has a mass of 3.50 grams and a density of 5.61 g/mL. What is the volume of this object? *

Answers

Answer:

0.62 mL

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

[tex]volume = \frac{mass}{density} \\[/tex]

From the question we have

[tex]volume = \frac{3.50}{5.61} \\ = 0.6238859...[/tex]

We have the final answer as

0.62 mL

Hope this helps you

Which of the following are fair conductors and are always solid at room temperature?

1.Metals
2.Nonmetals
3.Metalloids
4.Ions

Answers

Answer:

Metalloids and ions

Explanation:

Mercury is not solid at room temperature. (Metals)

Many nonmetals aren't good at conducting electricity. Oxygen for example. (Nonmetals)

Metalloids are always solid at room temp and are fair conductors. (Metalloids)

Ions are same as metalloids. (Ions)

PLS GIVE BRAINLIEST

For the following reaction at equilibrium SO3(g) + NO(g) = SO2(g) + NO2(g)It is found that [SO2] = 0.70 M and [NO] = 1.20 M. Calculate the equilibrium constant for the readction knowing that the initial concentration were [SO3] = 2.55 M and [NO] = 1.90 M.

Answers

Answer:

[tex]K=0.14[/tex]

Explanation:

Hello!

In this case, for the undergoing chemical reaction, we can write the equilibrium expression via:

[tex]K=\frac{[SO_2][NO_2]}{[SO_3][NO]}[/tex]

Whereas the equilibrium concentration of both SO3 and NO are 2.55 M and 1.90 M respectively, it means that the extent of reaction [tex]x[/tex] is:

[tex]x=1.90M-1.20M=0.7M[/tex]

Because the equilibrium expression in terms of the reaction extent is:

[tex]K=\frac{x*x}{([SO_3]_0-x)([NO]_0-x)}[/tex]

It means that the concentration of SO3, NO, SO2 and NO2 at equilibrium are:

[tex][SO_3]=2.55M-0.70M=1.85M[/tex]

[tex][NO]=1.20M[/tex]

[tex][SO_2]=0.70M[/tex]

[tex][NO_2]=0.70M[/tex]

Thus, the equilibrium constant for such reaction is:

[tex]K=\frac{0.70*0.70}{1.85*1.90}\\\\K=0.14[/tex]

Best regards!

In ethane, C2H6, ethene (ethylene), C2H4, and ethine (acetylene), C2H2, there are direct carbon-carbon bonds. Which one is the shortest?

a. The carbon-carbon bond in ethane's the longest!)
b. The carbon-carbon bond in ethene is the longest
c. The carbon-carbon bond in ethyne is the longest.
d. All of the carbon-carbon bonds have the same length.

Answers

Answer:

a. The carbon-carbon bond in ethane's the longest!)

Explanation:

Ethane is a chemical compound that is organic in nature. Its chemical formula is [tex]$C_2H_6$[/tex]. It has two carbon atoms and six of hydrogen atoms that is connected to the carbon atoms.

Ethane is odorless and colorless at the standard temperature and standard pressure.

The carbon to carbon atoms in ethane is connected by a single bond.

The length of single carbon-carbon bond is greater than carbon-carbon double bond and triple bond.

Thus, carbon-carbon bond length in ethane is the longest.

A microwave operates at 7.42 mm wavelength. How much energy is produced in Joules from 359 photons?



answer numerically using scientific notation with e and significant figures.

Answers

Answer:

[tex]E=9.62\times 10^{-21}\ J[/tex]

Explanation:

Given that,

The wavelength of a microwave is 7.42 mm or 0.00742 m

No. of photons, n = 359

We need to find the energy produced by this no of photons. It can be given by the formula as follows :

[tex]E=\dfrac{nhc}{\lambda}\\\\E=\dfrac{359\times 6.63\times 10^{-34}\times 3\times 10^8}{0.00742}\\\\=9.62\times 10^{-21}\ J[/tex]

or

[tex]E=9.62e^{-21}\ J[/tex]

So, the required energy is [tex]9.62\times 10^{-21}\ J[/tex].

Answer:

⬆️That guy deserves brainliest

Explanation:

Molarity to percent by mass. Convert 1.672 mol/L MgCl2(aq) solution to percent by mass of MgCl2 in the solution. The solution density at this concentration is 1.137 g/mL. Answer to 4 significant figures with appropriate units.

Answers

Answer:

[tex]\%m/m=14\%[/tex]

Explanation:

Hello!

In this case, since the molarity of magnesium chloride (molar mass = 95.211 g/mol) is 1.672 mol/L and we know the density of the solution, we can first compute the concentration in g/L as shown below:

[tex][MgCl_2]=1.672\frac{molMgCl_2}{L}*\frac{95.211gMgCl_2}{1molMgCl_2}=159.2\frac{gMgCl_2}{L}[/tex]

Next, since the density of the solution is 1.137 g/mL, we can compute the concentration in g/g as shown below:

[tex][MgCl_2]=159.2\frac{gMgCl_2}{L}*\frac{1L}{1000mL}*\frac{1mL}{1.137g}=0.14[/tex]

Which is also the by-mass fraction and in percent it turns out:

[tex]\%m/m=0.14*100\%\\\\\%m/m=14\%[/tex]

Best regards!

PLease help me I am giving a lot of points for this please help me

Answers

Answer:

Under balanced its motion under motion its s = d/t under s - d/t is time d = distance s= speed

Explanation:

Answer:Under unbalanced it’s motion,and after motion it’s speed.Then after speed it’s s=d/t,and d=distance and t=time.Lastly,the last one is graph.

Draw conclusion: The density of water is 1.0 g/mL, or 1.0 g/cm². Look at the data in your table. How can you use the density of an object to predict whether it will sink or float?

(Data is above)

PLEASE HELP ​

Answers

Answer:

work out if it's either going to sink or float

Explanation:

this can be carried out by calculating the numbers

What is the hybridization state on the central N atom in the azide ion, N3−?

Answers

The sp hybridization of the central nitrogen is consistent with the linear structure of the azide ion. In A, the terminal nitrogens may both be sp2 hybridized; after all the drawing looks similar to the double bond in ethylene.

Calculate the Molarity when a 6.11 mL solution of 0.1 H2SO4 is diluted with 105.12 mL of water

Answers

Molarity after dilution : 0.0058 M

Further explanation

The number of moles before and after dilution is the same  

The dilution formula

 M₁V₁=M₂V₂

M₁ = Molarity of the solution before dilution  

V₁ = volume of the solution before dilution  

M₂ = Molarity of the solution after dilution  

V₂ = Molarity volume of the solution after dilution

M₁=0.1 M

V₁=6.11

V₂=105.12

[tex]\tt M_2=\dfrac{M_1.V_1}{V_2}=\dfrac{0.1\times 6.11}{105.12}=0.0058~M[/tex]

If you travel 7.5 km and walk for 1.5 h, what is your average speed?
Show your work?

Answers

Answer: 5
Explanation: you divide the distance by the time and get the speed.

A 32.65 g metal is placed in a flask. Liquid toluene is added to the flask so that the total volume of the metal and liquid toluene together is 50.00 mL. The metal and toluene together weigh 58.58 g. The density of toluene at the temperature of the experiment is 0.8640 g/mL. What is the density of the metal?

Answers

yes i did it for me and i didn’t have any answers to cowboy yet but i’m was like ok i just kidding i don’t remember the name

find examples for each polysaccharides type.​

Answers

Answer:

Glycogen: It is made up of a large chain of molecules. ...

Cellulose: The cell wall of the plants is made up of cellulose. ...

Starch: It is formed by the condensation of amylose and amylopectin. ...

Insulin: It is made up of a number of fructofuranose molecules linked together in chains.

Explanation:

What is the change in internal energy (ΔΕ) of a system when 5 kJ of work is done on the system while it releases 13 kJ of energy to the surroundings?

Answers

The change in internal energy (ΔΕ) of a system : -8 kJ

Further explanation  

The laws of thermodynamics 1 state that: energy can be changed but cannot be destroyed or created  

The equation is:  

 [tex]\tt \Delta U=Q+W[/tex]

Energy owned by the system is expressed as internal energy (U)  

This internal energy can change if it absorbs heat Q (U> 0), or releases heat (U <0). Or the internal energy can change if the system does work or accepts work (W)  

The sign rules for heat and work are set as follows:  

• The system receives heat, Q +  

• The system releases heat, Q -  

• The system does work, W -  

• the system accepts work, W +  

5 kJ of work is done on the system : W = +5 kJ

releases 13 kJ of energy to the surroundings : Q = -13 kJ

[tex]\tt \Delta E=-13+5=-8~kJ[/tex]

is the center of an atom is called the nucleus?​

Answers

Answer:

The center of the atom contains the nucleus so yes

Explanation:

During the formation of water from hydrogen atoms and one oxygen

Answers

Answer:

B

Explanation:

hydrogen only has one electron/molecule in it's only shell so it can get together and make a bond

Which one is NOT true about chemical changes? *

Answers

Answer:

The second answer

Explanation:

Phase changes is an example of physical change because it only changes the substance's appearance.

Answer: 1 and 4 are the answers

Explanation: because when you mix a sub since and it will have a chemical change

Calculate the volume in milliliters of 1.57 M potassium hydroxide that contains 10.3 g of solute.

Answers

Answer:

[tex]V = 0.117 \ L[/tex]

General Formulas and Concepts:

Chem

Reading a Periodic TableWriting compounds and polyatomic ionsMolarity = moles of solute / liters of solution

Explanation:

Step 1: Define

1.57 M KOH (potassium hydroxide)

10.3 g KOH

Step 2: Define conversions

Molar Mass of K - 39.10 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of H - 1.01 g/mol

Molar Mass of KOH - 39.10 + 16.00 + 1.01 = 56.11 g/mol

Step 3: Convert

[tex]10.3 \ g \ KOH(\frac{1 \ mol \ KOH}{56.11 \ g \ KOH} )[/tex] = 0.183568 mol KOH

Step 4: Solve for Volume

Substitute:                    [tex]1.57 \ M=\frac{0.183568 \ mol}{x \ L}[/tex]Move x:                         [tex]x1.57 \ M=0.183568 \ mol[/tex]Isolate x:                       [tex]x=\frac{0.183568 \ mol}{1.57 \ M}[/tex]Evaluate:                      [tex]x=0.116922 \ L[/tex]

Step 5: Check

We are given 3 sig figs. Follow sig fig rules.

[tex]0.116922 \ L \approx 0.117 \ L[/tex]

How many molecules are present in 4.21 moles of HBr?​

Answers

Answer:

The answer is

2.53 × 10²⁴ molecules

Explanation:

The number of molecules present can be found by using the formula

N = n × L

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

N = 4.21 × 6.02 × 10²³

We have the final answer as

2.53 × 10²⁴ molecules

Hope this helps you

What creates a weather front?

Answers

A weather front is a transition zone between two different air masses at the Earth's surface. Each air mass has unique temperature and humidity characteristics. Often there is turbulence at a front, which is the borderline where two different air masses come together. The turbulence can cause clouds and storms.

why did Aristotle disagree with Democritus

Answers

Answer: He theorized that all material bodies are made up of indivisibly small “atoms.” Aristotle famously rejected atomism in On Generation and Corruption. Aristotle refused to believe that the whole of reality is reducible to a system of atoms.

Explanation:

Aristotle disagreed with Democritus primarily on the nature of matter and the concept of atomism.

Democritus proposed the theory of atomism, suggesting that all matter is composed of indivisible and indestructible particles called atoms. He believed that atoms combine and interact to form different substances.

On the other hand, Aristotle rejected the notion of atomism and instead proposed a different theory of matter. According to Aristotle, matter is continuous and infinitely divisible. He believed that substances are composed of four primary elements - earth, air, fire, and water - which have different inherent properties and undergo transformations through the combination and separation of these elements.

Aristotle's disagreement with Democritus stemmed from their differing views on the fundamental nature of matter. While Democritus emphasized the discrete and fundamental nature of atoms, Aristotle emphasized the continuous and composite nature of matter. Their contrasting viewpoints reflected a broader philosophical divide between atomism and holism in ancient Greek philosophy.

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Calculate the percentage difference in the fundamental vibrational wavenumbers of 23Na35Cl and 23Na37Cl on the assumption that their force constants are the same. The mass of 23Na is 22.9898mu.

Answers

Answer:

1.089%

Explanation:

From;

ν =1/2πc(k/meff)^1/2

Where;

ν = wave number

meff = reduced mass or effective mass

k = force constant

c= speed of light

Let

ν =1/2πc (k/meff)^1/2  vibrational wave number for 23Na35 Cl

ν' =1/2πc(k'/m'eff)^1/2 vibrational wave number for 23Na37 Cl

The between the two is obtained from;

ν' - ν /ν  = (k'/m'eff)^1/2 - (k/meff)^1/2 / (k/meff)^1/2

Therefore;

ν' - ν /ν = [meff/m'eff]^1/2 - 1

Substituting values, we have;

ν' - ν /ν = [(22.9898 * 34.9688/22.9898 + 34.9688) * (22.9898 + 36.9651/22.9898 * 36.9651)]^1/2  -1

ν' - ν /ν = -0.01089

percentage difference in the fundamental vibrational wavenumbers of 23Na35Cl and 23Na37Cl;

ν' - ν /ν * 100

|(-0.01089)|  × 100 = 1.089%

Answer:

1.089%

Explanation:

From;

ν =1/2πc(k/meff)^1/2

Where;

ν = wave number

meff = reduced mass or effective mass

k = force constant

c= speed of light

Let

ν =1/2πc (k/meff)^1/2  vibrational wave number for 23Na35 Cl

ν' =1/2πc(k'/m'eff)^1/2 vibrational wave number for 23Na37 Cl

The between the two is obtained from;

ν' - ν /ν  = (k'/m'eff)^1/2 - (k/meff)^1/2 / (k/meff)^1/2

Therefore;

ν' - ν /ν = [meff/m'eff]^1/2 - 1

Substituting values, we have;

ν' - ν /ν = [(22.9898 * 34.9688/22.9898 + 34.9688) * (22.9898 + 36.9651/22.9898 * 36.9651)]^1/2  -1

ν' - ν /ν = -0.01089

percentage difference in the fundamental vibrational wavenumbers of 23Na35Cl and 23Na37Cl;

ν' - ν /ν * 100

|(-0.01089)|  × 100 = 1.089%

6.0 L of a gas exert a pressure of 2.5 atm. When the pressure is increased 2 points
to 10.0 atm, what is the new volume of the gas?
O 1.0L
O 1.5L
O 1.7L
O 25L

Answers

25L hope this helps.

Whats the answer 50 points and brainliest if its right

Answers

Answer:

D

Explanation:

The noble gases can be found in group/period ____

Answers

Answer:

group 18

Explanation:

The noble gases (Group 18) are located in the far right of the periodic table and were previously referred to as the "inert gases" due to the fact that their filled valence shells (octets) make them extremely nonreactive

Answer:group 18

Explanation

An organic thiol compound is 38.66% C, 9.73% H, and 51.61% S by mass. What is the empirical formula of this compound?

Answers

Answer:

Empirical formula is C₂H₆S

Explanation:

Given data:

Percentage of hydrogen = 9.73%

Percentage of carbon = 38.66%

Percentage of sulfur = 51.61%

Empirical formula = ?

Solution:

Number of gram atoms of H = 9.73 / 1.01 = 9.6

Number of gram atoms of S = 51.61 / 32 = 1.6

Number of gram atoms of C = 38.66 / 12 = 3.2

Atomic ratio:

             C                      :      H              :         S

           3.2/1.6               :     9.6/1.6       :       1.6/1.6

            2                      :        6             :        1

C : H : S = 2 : 6 : 1

Empirical formula is C₂H₆S.

A buffer is prepared by mixing 204.0 mL of 0.452 M HCl and 0.500 L of 0.400 M sodium acetate (NaC2H3O2):
Calculate the pH of the buffer.
How many grams of KOH must be added to 0.500 L of the buffer to change the pH by 0.15 units?

Answers

Answer:

pH = 4.89

0.6171g of KOH must be added

Explanation:

Sodium acetate reacts with HCl producing acetic acid as follows:

NaC2H3O2 + HCl → HC2H3O2 + NaCl

That means the moles added of HCl are moles of acetic acid produced and moles of acetate are initial moles - moles of HCl

Moles HCl = Moles acetic acid:

0.204L * (0.452mol / L) = 0.0822 moles acetic acid.

Initial moles sodium acetate:

0.500L * (0.400mol / L) = 0.200 moles

Moles sodium acetate:

0.200 moles - 0.0822 moles = 0.1172 moles sodium acetate

The pH of this buffer (Mixture of a weak acid and its conjugate base) is obtained using H-H equation:

pH = pKa + log [A-] / [HA]

Where pH is pH of the buffer,

pKa is pKa of the buffer (4.74 for acetic acid)

[A-] Moles of sodium acetate -Conjugate base-

And HA moles of acetic acid -Weak acid-

pH = 4.74 + log [0.1172 moles] [0.0822 moles]

pH = 4.89

In 0.500L the moles of the buffer are:

0.500L * (0.200moles / 0.704L) = 0.142 moles of buffer

For a pH of 0.15 units more (4.89 + 0.15 = 5.04):

5.04 = 4.74 + log [Acetate] / [Acetic acid]

0.3 = log [Acetate] / [Acetic acid]

1.9953 = [Acetate] / [Acetic acid] (1)

And as:

0.142 = [Acetate] + [Acetic acid] (2)

Replacing (2) in (1):

1.9953 = 0.142 - [Acetic acid]  / [Acetic acid]

1.9953 [Acetic acid] = 0.142 - [Acetic acid]

2.9953 [Acetic acid] = 0.142 moles

[Acetic acid] = 0.0474 moles of acetic acid must remain after the addition of KOH.

In the beginning, moles of acetic acid are:

0.0822 moles * (0.500L / 0.704L) = 0.0584 moles.

That means moles added of KOH (Equal to moles of acetic acid that react) are:

0.0584 moles - 0.0474 moles = 0.0110 moles of KOH

In grams (Molar mass KOH = 56.1g/mol):

0.0110 moles KOH * (56.1g/mol) =

0.6171g of KOH must be added

A gram sample of a KCl and KClO3 mixture was found to contain 0.00875 mol of KClO3. What is the percent by mass of KClO3 in the original mixture?

Answers

Answer:

53.5%

Explanation:

Step 1: Given data

Mass of the sample: we will suppose it is 2.00 g to show the procedureMoles of KClO₃: 0.00875 mol

Step 2: Calculate the mass corresponding to 0.00875 moles of KClO₃

The molar mass of KClO₃ is 122.55 g/mol.

0.00875 mol × 122.55 g/mol. = 1.07 g

Step 3: Calculate the percent by mass of KClO₃ in the mixture

We will use the following expression.

%m/m = mass of KClO₃/mass of the sample × 100%

%m/m = 1.07 g/2.00 g × 100%

%m/m = 53.5%

The percent by mass of KClO3 in the original mixture is 53.5%.

Calculation of the percentage:

Since

The mass of the sample should be 2.00 g

Moles of KClO₃: 0.00875 mol

The molar mass of KClO₃ is 122.55 g/mol.

Now the mass is

= 0.00875 mol × 122.55 g/mol.

= 1.07 g

Now the percentage should be

= mass of KClO₃/mass of the sample × 100%

= 1.07 g/2.00 g × 100%

= 53.5%

hence, The percent by mass of KClO3 in the original mixture is 53.5%.

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