Calculate the maximum mass of a metal, with equivalent mass of 20 g, that should be used in an equivalent mass determination with a 100-mL eudometer tube for collection. For the purposes of calculation, assume 80 mL of hydrogen gas produced at standard conditions. (Round to 2 sig figs)

Answer:

695.8kJ/mol = Enthalpy of combustion

Final temperature = 407.4°C

Explanation:

Taken the reaction:

2CH₃NO₂ + 3/2 O₂ → 2CO₂ + 3H₂O + N₂

The enthalpy of the reaction is the heat released when 1 mole of nitromethane are in combustion.

We need to find the moles presents in 121L of nitromethane using its density and molar mass (61.04g/mol). As these moles releases 1.6x10⁶kJ, we need to find heat released per mole of nitromethane

Mass nitromethane:

121L = 121000cm³ * (1.16g/cm³) = 140360g

Moles:

140360g * (1mol / 61.04g) = 2299.5 moles of nitromethane

Heat released per mole of nitromethane:

1.6x10⁶kJ / 2299.5 mol = 695.8kJ/mol = Enthalpy of combustion

The symbol - is because the heat is released, a + symbol is when the heat is absorbed.

Using:

Q = m×C×ΔT

Where Q is heat (1.6x10⁶kJ = 1.6x10⁹J)

m is mass of water:

1kL = 1000L = 1x10⁶mL = 1x10⁶g

C is specific heat of water: 4.184J/g°C

And ΔT is change in temperature.

Solving for ΔT:

1.6x10⁹J = 1x10⁶g * 4.184J/g°C * ΔT

ΔT = 382.4°C

As initial temperature was 25°C, final temperature is:

382.4°C + 25°C =

407.4°C

Answer:

Explanation:

no of moles=given mass/molar mass

no of moles=150 g/207.19

no of moles=0.72

We will use dimensional analysis to answer this question.

[tex]150 g * \frac{1 g}{207.19 mol} = 0.724 mol[/tex]

The answer is 0.724 mol.

Answer:

1.5 moles of Fe produced.

Explanation:

Given data:

Moles of FeO react = 1.50 mol

Moles of iron produced = ?

Solution:

Chemical equation:

FeO + CO       →       Fe + CO₂

Now we will compare the moles of ironoxide with iron.

                           FeO          :           Fe

                              1             :             1

                             1.5           :           1.5

Thus from 1.5 moles of FeO 1.5 moles of Fe are produced.                                    

1.5 moles of Fe can be obtained when 1.50 mol of FeO reacts with an excess

of CO

Moles of FeO reacted  = 1.50 mol

Moles of iron produced = ? mol

The chemical equation is given as

FeO + CO       →       Fe + CO₂

Comparisons of FeO and Fe show they are in the ratio 1 : 1

                          FeO          :           Fe

                            1.5           :           1.5

which translates to the number of moles being equal

Therefore, 1.5 moles of FeO 1.5 moles of Fe are produced.    

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Answer:

I believe its 1,2, and 5

Explanation:

C D E

temperature of medium

type of wave

type of medium

Answer:

[tex]E=1.98\times 10^{-31}\ J[/tex]

Explanation:

Given that,

The frequency of a wave, f = 300 Hz

We need to find the energy of a wave. The formula for the energy of a wave is given by :

E = hf,

Where h is Planck's constant

[tex]E=6.63\times 10^{-34}\times 300\\\\=1.98\times 10^{-31}\ J[/tex]

So, the energy of the wave is [tex]1.98\times 10^{-31}\ J[/tex].

Answer:

You didn't provide any statements. If it is an option, art is a form of expression. Something created from imagination that expresses the thoughts and emotions of the artist.

The statement that best answers the question: What is art is that—Art is a form of visual language. Therefore, the correct option is A.

Art is a diverse range of human activities and products that are created with the intention of expressing the imagination, emotions, or ideas, or to make a statement, in a visually appealing way.

Art can take many forms, including visual arts (such as painting, sculpture, and photography), performing arts (such as music, dance, and theater), and literary arts (such as poetry and prose).

It is typically seen as a form of communication and can be used to convey ideas, emotions, or political, social or cultural messages. It can also be used to simply evoke a response or emotion in the viewer, or to create a sense of beauty or aesthetic enjoyment. Therefore, the correct option is A.

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#SPJ6

The question is incomplete, but most probably the complete question is,

Which of these statements best answers the question: What is art?

A. Art is a form of visual language.

B. Art is a form of written language.

C. Art is a form of spoken language.

D. Art is a form of dance language.

Answer:

2HBr + O2 = H20 +Br2

Explanation:

Answer:

4hbr(aq) + O2(g) = 2H2O + 2Br2

Explanation:

Answer:

From the numerical steps highlighted under explanation, the average atomic mass of bromine is 79.91 u

Explanation:

The steps to be taken will involve;

1) Find the number of isotopes of bromine.

2) Identify the atomic mass and relative abundance of each of the isotopes.

3) Multiply the atomic mass of each of the isotopes by their corresponding values relative abundance value.

4) Add the value in step 3 above to get the average atomic mass of bromine.

Now;

Bromine has 2 isotopes namely;

Isotope 1: Atomic mass = 78.92amu and a relative abundance of 50.69%.

Isotope 2: Atomic mass = 80.92amu and a relative abundance of 49.31%.

Using step 3 above, we have;

(78.92 × 50.69%)

And (80.92 × 49.31%)

Using step 4 above, we have;

(78.92 × 50.69%) + (80.92 × 49.31%) ≈ 79.91 u

The atomic mass of bromine has been calculated as 79.9062 amu.

The relative atomic mass of the element has been given as the mass of each isotope with respect to their abundance.

The atomic mass has been given as:

[tex]amu=\sum mass\;\times\;\% Abundance[/tex]

The available isotopes of Bromine have been:

Isotope 1 = 78.92 amu, and 0.5069 % abundance

Isotope 2= 80.92 amu, and 0.4931 % abundance

Submitting the values for the atomic mass unit of bromine ([tex]amu_{\text{Br}}[/tex]):

[tex]amu_{\text {Br}}= (78.92\;\times\;0.5069)\;+\;(80.92\;\times\;0.4931)\\amu_{\text{Br}}=40.0045\;+\;39.9016\\amu_{\text{Br}}=79.9062[/tex]

The atomic mass of bromine has been calculated as 79.9062 amu.

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Answer:900j

Explanation:

Answer:

[tex]23.093\ \text{torr}[/tex]

Explanation:

[tex]M_g[/tex] = Molar mass of glucose = 180.2 g/mol

[tex]M_w[/tex] = Molar mass of water = 18 g/mol

[tex]m_g[/tex] = Mass of glucose = 76.6 g

[tex]m_w[/tex] = Mass of water = [tex]250\times 1\ \text{g/mL}=250\text{g}[/tex]

[tex]P_0[/tex] = Vapor pressure of pure water at 25°C = 23.8 torr

The mole fraction of glucose is

[tex]x_g=\dfrac{\dfrac{m_g}{M_g}}{\dfrac{m_g}{M_g}+\dfrac{m_w}{M_w}}=\dfrac{\dfrac{76.6}{180.2}}{\dfrac{76.6}{180.2}+\dfrac{250}{18}}\\\Rightarrow x_g=0.0297[/tex]

Mole fraction of the solute would be

[tex]\dfrac{P_0-P}{P_0}=x_g\\\Rightarrow 0.0297=\dfrac{23.8-P}{23.8}\\\Rightarrow P=23.8-0.0297\times23.8\\\Rightarrow P=23.093\ \text{torr}[/tex]

The vapor pressure of the solution is [tex]23.093\ \text{torr}[/tex].

Answer:

The correct answer would be C.) a line graph

Explanation:

I just did the assignment on edge 2020 and got it right

Answer:

the mole fraction of water in a solution is 0.17

Explanation:

The computation of the mole fraction of water in a solution is shown below:

Given that

Ethanol be 8.0 mol

And, the water be 1.6 mol

Based on the above information, the mole fraction of water in a solution is

= Water ÷ (Water + ethanol)

= 1.6 mol ÷ (1.6 mol + 8.0 mol)

= 1.6 mol ÷ 9.6 mol

= 0.17

Hence, the mole fraction of water in a solution is 0.17

Answer:

it is C

Explanation:

because Potassium iodide (KI) is an ionic compound which is made of the following ions: K+I−

Answer:

maalat ang salt

Explanation:

Answer:

A. C3H3O

Explanation:

We have the following data:

m = mass of organic compound = 1.038g

Then mass of CO2 is 2.48g

Also mass of H2O is 0.510g

To calculate percentage of carbon = 12 x mass of CO2 x 100/44 x mass of organic compound

This gives us 65.1 percent

Formula to calculate percentage of H=

2 x mass of water x 100/18 x mass of organic compound.

= 2 x 0.510 x 100/18x 10038

This gives 5.4%

Percentage of Oxygen =100-(percentageof carbon +percentageof H)

= 100-(65.1+5.4)

= 100-70.5

= 29.5

We have to calculate emperical formula:

For C = 65.1

65.1/12

= 5.4

= 5.4/1.8

=3

For H=5.4

5.4/1

= 5.4

= 5.4/1.8

=3

For O = 29.5

= 29.5/16

= 1.8

= 1.8/1.8

=1

So the emperical formula of organic compound is given as

C3H3O1

= C3H3O

(The atomic weights of C, H, O are 12,1,16)

Answer:

ether group

Explanation: I looked it up

Answer:

its B

Explanation:

Because its can only go cold to hot. -hope this help :)

Answer:

See explanation

Explanation:

a. I can conclusively tell if the crown was made of gold by measuring its density. First the mass of the crown is measured on a weighing balance. The crown is now put into a given volume of water and the volume of water displaced is accurately measured. The density of the crown is computed as mass/volume of fluid displaced. If the density of the crown is 19.3 g/mL, then it is made of solid gold.

b) When less valuable metals such as bronze or copper is mixed with gold in the crown, the density of the crown decreases and the crown becomes more brittle.

c) An object will float in a liquid when the density of the object is less than the density of the liquid. Hence the tendency of an object to float in a liquid depends on the density of the object and the density of the liquid.

d) Even though i do not know the results from your experiment but as regards the decision as to whether the object will float in the given liquid or not, reference must be made to the measured density of the object as well as the given density of the liquid. If the object is less dense (from values of density obtained from the experiment)  than the liquid, then the object will float in the liquid and vice versa.

Answer:

[tex]k=8.63x10^{-8}\frac{1}{M*s}[/tex]

Explanation:

Hello!

In this case, since the differential rate law of a second-order reaction is:

[tex]\frac{dC_A}{dt}=-kC_A^2[/tex]

Whereas A stands for NOCl and the corresponding integrated rate law is:

[tex]\frac{1}{C_A} =kt+\frac{1}{C_A_0}[/tex]

Thus, since we know the concentrations and the elapsed time, we compute the rate constant as shown below:

[tex]k=( \frac{1}{C_A}-\frac{1}{C_A_0} )/t\\\\k=( \frac{1}{0.83M}-\frac{1}{0.878M} )/763,200s\\\\k=8.63x10^{-8}\frac{1}{M*s}[/tex]

Best regards!

Answer:

0.548 moles of HBr are required

Explanation:

Given data:

Number of moles of  hydrobromic acid = ?

Moles of bromine formed = 0.274 mol

Solution:

Chemical equation:

2HBr     →   H₂  + Br₂

Now we will compare the moles of HBr with Br₂.

               Br₂           :           HBr

               1               :            2

               0.274       :           2×0.274=0.548

Thus, 0.548 moles of HBr are required.

Answer:

silicon tetrachloride or tetrachlorosilane

Answer:

See Explanation

Explanation:

Pb2O3 is better formulated as PbO.PbO2. It is actually a mixture of the two oxides of lead, lead II oxide and lead IV oxide.

This implies that this compound Pb2O3  (sometimes called lead sesquioxide) is a mixture of the oxides of lead in its two known oxidation states +II and +IV.

Hence Pb2O3  contains PbO and PbO2 units.

Answer:Because the Earth is round and not flat, the Sun's rays don't fall evenly on the land and oceans. The Sun shines more directly near the equator bringing these areas more warmth. However, the polar regions are at such an angle to the Sun that they get little or no sunlight during the winter, causing colder temperatures.

Explanation:

Answer:

Answer: Tin (II) nitride

Answer:

A. [H₃O⁺] = 0.900 M

B. pH = 0.0 to one decimal place

C. [H₃O⁺] = 0.620 M

D. pH = 0.21 to two decimal places

Explanation:

A. Equation for the complete dissociation of H₃PO₄ is given below:

H₃PO₄(s) + 3H₂O(l) -----> PO₄³⁻(aq) + 3H₃O⁺(aq)

From the equation of reaction, one mole of H₃PO₄ produces 3 moles of H₃O⁺

Therefore, [H₃O⁺] = 3 * 0.300M = 0.900 M

B. pH = -log[H₃O⁺]

pH = - log(0.900)

pH = -log (9 * 10⁻¹)

pH = 0.0 to one decimal place

C. Equation for the complete dissociation of H₂C₂O₄ is given below:

H₂C₂O₄(s) + 2H₂O(l) ----> C₂O₄⁻(aq) + 2H₃O⁺

From the equation of reaction, one mole of H₂C₂O₄ produces 3 moles of H₃O⁺

Therefore, [H₃O⁺] = 2 * 0.310 M = 0.620 M

D. pH = -log[H₃O⁺]

pH = -log(0.620)

pH = -log(0.62 * 10⁻¹)

pH = 0.21 to two decimal places

The concentration of [[tex]\rm H_3O^+[/tex]] has been 0.9 M, and the pH has been 0.045.

The polyprotic acid has been able to donate more than one proton in an acid-base reaction.

The balanced chemical reaction can be:

[tex]\rm H_3PO_4\;+\;3\;H_2O\;\rightarrow\;PO_4^3^-\;+\;3\;H_3O^+[/tex]

(a) According to the equation, 1 mole of [tex]\rm H_3PO_4[/tex] gives 3 moles of hydronium ions. The molarity has been defined as moles per liter. Assuming the volume of reaction to be 1 liter.

1 mole [tex]\rm H_3PO_4[/tex] = 1 M [tex]\rm H_3PO_4[/tex]

1 mole [tex]\rm H_3PO_4[/tex] = 3 moles [[tex]\rm H_3O^+[/tex]]

0.3 mole [tex]\rm H_3PO_4[/tex] = 3 [tex]\times[/tex] 0.3 moles [[tex]\rm H_3O^+[/tex]].

0.3 mole [tex]\rm H_3PO_4[/tex] = 0.9 moles [[tex]\rm H_3O^+[/tex]]

The concentration of [[tex]\rm H_3O^+[/tex]] has been 0.9 mole/L, or 0.9 M.

(b) pH of the solution can be defined as:

pH = -log [[tex]\rm H_3O^+[/tex]]

pH = -log (0.9)

pH = 0.045

The pH of the solution has been 0.045.

(c) The polyprotic acid have the balanced equation:

[tex]\rm H_2C_2O_4\;+\;2\;H_2O\;\rightarrow\;C_2O_4^-\;+\;2\;H_3O^+[/tex]

According to the equation, 1 M [tex]\rm H_2C_2O_4[/tex] gives 2 M [tex]\rm H_3O^+[/tex].

The concentration of hydronium ions from 0.310 M [tex]\rm H_2C_2O_4[/tex] has been:

1 M [tex]\rm H_2C_2O_4[/tex] = 3 M [tex]\rm H_3O^+[/tex]

0.310 M [tex]\rm H_2C_2O_4[/tex] =  2 [tex]\times[/tex] 0.310 moles [[tex]\rm H_3O^+[/tex]]

0.310 M [tex]\rm H_2C_2O_4[/tex] = 0.62 M  [[tex]\rm H_3O^+[/tex]].

The  [[tex]\rm H_3O^+[/tex]] concentration of the solution has been 0.62 M.

(d) pH of the solution can be defined as:

pH = -log  [[tex]\rm H_3O^+[/tex]]

pH = -log (0.62)

pH = 0.20

The pH of the solution has been 0.20.

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Answer:

c) H2O and HSO4-

Explanation:

The dehydration of 2-methylcyclohexanol occurs in the presence of H2SO4. Recall that acids are proton donors in solution; the equilibrium shown below is then set up,

H2SO4(aq)  +  H2O(l) ⇄H3O^+(aq) + HSO4^-(aq)

The species H2O and HSO4- are two proton acceptors in the system. According to the Brownstead- Lowry definition, a base is a proton acceptor in solution.

Hence H2O and HSO4- are bases present in the dehydration of 2-methylcyclohexanol.