Calculate the Molarity when a 6.11 mL solution of 0.1 H2SO4 is diluted with 105.12 mL of water

Answers

Answer 1

Molarity after dilution : 0.0058 M

Further explanation

The number of moles before and after dilution is the same  

The dilution formula

 M₁V₁=M₂V₂

M₁ = Molarity of the solution before dilution  

V₁ = volume of the solution before dilution  

M₂ = Molarity of the solution after dilution  

V₂ = Molarity volume of the solution after dilution

M₁=0.1 M

V₁=6.11

V₂=105.12

[tex]\tt M_2=\dfrac{M_1.V_1}{V_2}=\dfrac{0.1\times 6.11}{105.12}=0.0058~M[/tex]


Related Questions

The molarity (M) of an aqueous solution containing 22.5 g of sucrose (C12H22O11) in 35.5 mL of solution is ________.

Answers

Answer:

1.86 M

Explanation:

From the question given above, the following data were obtained:

Mass of sucrose (C12H22O11) = 22.5 g

Volume of solution = 35.5 mL

Molarity of solution =?

Next, we shall determine the number of mole in 22.5 g of sucrose (C12H22O11). This can be obtained as follow:

Mass of sucrose (C12H22O11) = 22.5 g

Molar mass of C12H22O11 = (12×12) + (22×1) + (16×11)

= 144 + 22 + 176

= 342 g/mol

Mole of C12H22O11 =?

Mole = mass /Molar mass

Mole of C12H22O11 = 22.5 /342

Mole of sucrose (C12H22O11) = 0.066 mole

Next, we shall convert 35.5 mL to litres (L). This can be obtained as follow:

1000 mL = 1 L

Therefore,

35.5 mL = 35.5 mL × 1 L / 1000 mL

35.5 mL = 0.0355 L

Thus, 35.5 mL is equivalent to 0.0355 L.

Finally, we shall determine the molarity of the solution as follow:

Mole of sucrose (C12H22O11) = 0.066 mole

Volume of solution = 0.0355 L.

Molarity of solution =?

Molarity = mole /Volume

Molarity of solution = 0.066/0.0355

Molarity of solution = 1.86 M

Therefore, the molarity of the solution is 1.86 M.

Suppose in an experiment to determine the amount of sodium hypochlorite in bleach, 0.0000538 mo KIO3 were titrated with an unknown solution of Na2S2O3 and the endpoint was reached after 17.80 mL. How many moles of Na2S2O3 did this require?

Answers

Answer:

3.228x10⁻⁴ moles of Na2S2O3 are required

Explanation:

In iodometry, the reaction of KIO3 with Na2S2O3 is:

KIO3 + 6 Na2S2O3 + 6H⁺ → KI + 3Na2S4O6 + 3H2O + 6Na⁺

Where 6 moles of Na2S2O3 reacts per moles of KIO3.

The moles of Na2S2O3 required to reach endpoint when 0.0000538 moles of KIO3 are:

0.0000538 moles of KIO3 * (6 moles Na2S2O3 / 1 mol KIO3) =

3.228x10⁻⁴ moles of Na2S2O3 are required

Would you want to build the wire for a cell phone charger out of nitrogen (N)? Why or why not? Be sure to explain how the properties and structure of nitrogen influence your decision.

Answers

Answer:

No

Explanation:

Nitrogen cannot be used to build the wire for a cell phone charger.

What are the elements used to build charger ?

Inside phone chargers is aluminum. Aluminum is used in phone chargers because it does a better job of conducting electricity than copper does. Bauxite is used to make aluminum. The crust of the earth contains aluminum.A phone charger is also made of tungsten. The wire's resistance is provided by tungsten. Wolframite make up tungsten. The crust of the Earth contains tungsten.Additionally, phone chargers contain gold. Because it is a conductor, gold is used in phone chargers. However, gold is also resistant to oxidation. Copper ores are used to make gold. Gold can be found everywhere on Earth and in its oceans.Silver is within your mobile charger. Silver conducts electricity. Silver is comprised of various minerals. Silver can be found free in nature at times, but it can also be found in copper, gold, and nickel.Phone chargers contain copper. Copper is also used to carry electric current.Chalcopyrite make up copper. Copper ore deposits can be found all over the world.Copper windings in a transformer are used to convert a 220 V input voltage into a 5 V operating output voltage in mobile phone chargers. The output voltage is greater than the input voltage if the secondary coil has more turns than the primary coil.Nitrogen (N), a nonmetallic element in the periodic table's Group 15 [Va] group. It is the most abundant element in Earth's atmosphere and a component of all living matter. It is a colorless, tasteless, and odorless gas. Nitrogen is used to shield motors, prevent oxidation and other chemical reactions, pressurize cable jackets, and more in the electrical industry.

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During bromination using NBS, the addition product is not observed because the rate of addition is _______than the rate of the chain propagation steps.

Answers

Answer:

slower

Explanation:

NBS is used in place of Br2 during bromination because the use of Br2 tends to result in the formation of a large concentration of the addition product.  This is because, the Br2 interacts with the double bond to yield only the dibromide (addition product).

The usefulness of NBS lies in the fact that it provides a lower concentration of Br2, and such that the rate addition is slower than the chain propagation steps. Only the monobromination product is observed

The low concentration of Br2 allows the free-radical reaction to out-compete the alkene addition reaction.

the difference in energy between the n=1 and n=2 energy levels in a hydrogen atom is 1.64x10^-18 J. what happens when an electron in a hydrogen atom transitions from n=2 to n=1?

Answers

Answer:

It emits 1.64 x 10⁻¹⁸J of energy

Explanation:

The n = 1 is a lower quantum level compared to n = 2.

When a hydrogen atom moves from a higher level to a lower one, it simply emits the energy difference between the two levels.

If a hydrogen atom moves from a lower energy level to a higher one such as from 1 to 2, they absorb the energy difference to attain the new excited state. So, for an electron in the hydrogen atom to move from a higher energy level to a lower one, it must emit 1.64 x 10⁻¹⁸J of energy.

how does mass and volume affect sinking and floating? Please don't plagiarize.... ​

Answers

Answer:

If an object has a higher density than the fluid it is in (fluid can mean liquid or gas), it will sink. If it has a lower density, it will float. Density is determined by an object's mass and volume. If two objects take up the same volume, but have one has more mass, then it also has a higher density.

Explanation:

When 4.58 g of a nonelectrolyte solute is dissolved in water to make 725 mL of solution at 25 °C, the solution exerts an osmotic pressure of 875 torr.

Required:
a. What is the molar concentration of the solution?
b. How many moles of solute are in the solution?
c. What is the molar mass of the solute?

Answers

Answer:

a. 0.047 M

b. 0.6778 moles

c. 6.76 g/mol

Explanation:

The formula for osmotic pressure is:

π = i*M*R*T

Where:

i is the van't Hoff's factor (in this case is 1, because it is a non electrolyte solute)M is the molar concentrationR is the ideal gas constantT is the temperature in Kelvin

a.) So we solve for M:

875 torr ⇒ 785/760 = 1.15 atm25 °C ⇒ 25+273.16 = 298.16 K1.15 atm = 1 * M * 0.082 atm·L·mol⁻¹·K⁻¹ * 298.16 KM = 0.047 M

b.) We calculate the moles of solute, using the volume and molar concentration:

725 mL / 1000 = 0.725 L0.047 M * 0.725 L = 0.6778 moles

c.) We calculate the molar mass, using the mass and the number of moles:

4.58 g / 0.6778 moles = 6.76 g/mol

A. The molar concentration of the solution is 0.047 M

B. The mole of the solute in the solution is 0.034 mole

C. The molar mass of the solute is 134.7 g/mol

A. Determination of the molar concentration of the solution.

Osmotic pressure (π) = 875 torr = 875 / 760 = 1.15 atm

Temperature (T) = 25 °C = 25 + 273 = 298 K

Van't Hoff's factor (i) = 1 (non-electrolyte)

Gas constant (R) = 0.0821 atm.L/Kmol

Molarity (M) =?

π = iMRT

1.15 = 1 × M × 0.0821 × 298

1.15 = M × 24.4658

Divide both side by 24.4658

M = 1.15 / 24.4658

M = 0.047 M

B. Determination of the mole of the solute.

Molarity = 0.047 M

Volume = 725 mL = 725 / 1000 = 0.725 L

Mole of solute =?

Mole = Molarity x Volume

Mole of solute = 0.047 × 0.725

Mole of solute = 0.034 mole

C. Determination of the molar mass of the solute

Mole of solute = 0.034 mole

Mass of solute = 4.58 g

Molar mass of solute =?

Molar mass = mass / mole

Molar mass of solute = 4.58 / 0.034

Molar mass of solute = 134.7 g/mol

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For a 0.300 mol sample of helium gas in a 0.200 L container at 248K, will the pressure be greater if calculated with the ideal gas law or the van der Waals equation, and by roughly how much? (For He,a=0.0342L2atmmol2,b=0.0237 Lmol)

Answers

Answer:

It changes by roughly 1 atm.

Explanation:

Hello!

In this case, since the ideal gas equation differs from the van der Waals' one by the presence of the a and b parameters which correct the assumption of no interactions into the container, they are written as:

[tex]P=\frac{nRT}{V}\\\\P=\frac{RT}{v_m-b}-\frac{a}{v_m^2}[/tex]

Thus, the pressure via the ideal gas equation is:

[tex]P=\frac{0.300mol*0.082\frac{atm*L}{mol*K}*248K}{0.200L}=30.5atm[/tex]

And the pressure via the van der Waals equation, considering the molar volume (vm=0.200L/0.300L=0.667L/mol) is:

[tex]P=\frac{0.082\frac{atm*L}{mol*K}*248K}{0.667L/mol-0.0237L/mol}-\frac{0.0342atm*L^2/mol^2}{(0.667L/mol)^2}\\\\P=31.6atm-0.0769atm\\\\P=31.5atm[/tex]

It means that the pressure change by 1 atm, which is not a significant difference for helium.

The difference in pressure calculated by the two methods is 84 atm.

The ideal gas equation is given by

PV =nRT

From the data given in the question;

P = ?

V = 0.200 L

n =  0.300 mol

T = 248K

R = 0.082 atmLK-1Mol-1

P = nRT/V

P =  0.300 mol × 0.082 atmLK-1Mol-1  × 248K/0.200 L

P = 30.5 atm

From Van der Waals equation;

P = RT/V - b - a/V^2

P =  (0.082 × 248/0.200 - 0.0237)  - (0.0342/ 0.200^2)

P = 114.5 atm

The difference in pressure calculated by the two methods is;

114.5 atm -  30.5 atm = 84 atm

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The equation for the reaction of magnesium ribbon and hydrochloric acid is
Mg(s) + 2 HCl(aq) → MgCl2(aq) + H2(g)
If 1.53 g magnesium reacted, how many moles of hydrogen gas was produced?
Report your answer to three significant figures.
Mg = 24.3 g/mol

Answers

Answer: .063

Explanation:

1.53g Mg * (1 mol Mg/ 24.3 g Mg) * (1 mol H2/1 mol Mg) = .063 mol H2

The mole of hydrogen gas that will be produced from the reaction would be 0.0630 moles.

From the equation of the reaction:

[tex]Mg(s) + 2 HCl(aq) ---> MgCl_2(aq) + H_2(g)[/tex]

The mole ratio of Mg to H2 gas is 1:1. Thus, for every one mole of Mg consumed by the reaction, 1 mole of H2 is produced, all other things being equal.

Recall that: mole = mass/molar mass

1.53 g of magnesium = 1.53/24.3

                                     = 0.0630 mole (to 3 significant figures)

Since the mole ratio of Mg to H2 is 1:1, it means that the number of moles of hydrogen gas produced would also be 0.0630 moles.

More on calculating moles can be found here: https://brainly.com/question/21085277

An ideal gas had a mass of 0.0218g and occupied a volume of 1.111L at 0oC and 0.0100atm. What is the molar mass of this gas?

Answers

Answer:

Explanation:

we shall use gas law formula to solve the problem .

P = .01 atm

V = 1.111 L

T = 273 K

mass of gas = .0218

molar mass = M

no of moles n = .0218 / M

PV = n RT

.01 x 1.111 = (.0218 / M)  x .082 x 273

.0218 / M = .000496

M = .0218 / .000496

= 43.95

How do you think energy flows in and out of the earth's atmosphere ?

Answers

As air is heated by surfaces or solar radiation, it triggers convection currents, sometimes called thermals. Other absorbed solar radiation is emitted from surfaces as infrared radiation and then eventually moves back out into space via the atmosphere.

At equilibrium, the value of [H ] in a 0.240M solution of an unknown acid is 0.00417M . Determine the degree of ionization and the Ka of this acid.

Answers

Answer:

[tex]ionization=1.74\%[/tex]

Explanation:

Hello!

In this case, since the degree of ionization of an acid is computed in terms of the concentration of hydrogen ions and the initial concentration of the acid:

[tex]ionization=\frac{[H^+]}{[HA]} *100\%[/tex]

Because the ionization reaction is represented by:

[tex]HA\rightleftharpoons H^++A^-[/tex]

Therefore, the degree or percent ionization turns out:

[tex]ionization=\frac{0.00417M}{0.240M} *100\%\\\\ionization=1.74\%[/tex]

Best regards!

In a coffee-cup calorimeter, 1.60 g of NH4NO3 was mixed with 75.0 g of water at an initial temperature of 25.008C. After dissolution of the salt, the final temperature of the calorimeter contents was 23.348C.

Required:
a. Assuming the solution has a heat capacity of 4.18 J 8C21 g21, and assuming no heat loss to the calorimeter, calculate the enthalpy of solution (DHsoln) for the dissolution of NH4NO3 in units of kJ/mol.
b. If the enthalpy of hydration for NH4NO3 is 2630. kJ/mol, calculate the lattice energy of NH4NO3.

Answers

Answer:

Explanation:

mass of the solution m = 1.6 + 75 = 76.6 g

fall in temperature = 25 - 23.34 = 1.66°C

heat absorbed = mass x specific heat x fall in temperature

= 76.6 x 1.66 x 4.18

= 531.5 J .

= .5315 kJ .

mol weight of ammonium nitrate = 80 g

heat absorbed by 1.6 g = .5315 kJ

heat absorbed by 80 g or one mole = 26.575 kJ

enthalpy change ΔH = +26.575 kJ

b )

enthalpy of hydration = 2630 kJ / mol

lattice energy = enthalpy of hydration + enthalpy change

= 2630 + 26.575

= 2656.575 kJ  .

How is thermal energy transferred during conduction? Check all that apply.
Thermal energy is transferred hetween particles that are not touching each other.
Thermal energy is transferred between particles that are in direct contact with each other.
Thermal energy is transferred between objects of different temperatures.
Thermal energy is transferred between objects of the same temperature.
Thermal energy is transferred from slow-moving particles to fast-moving particles.
Thermal energy is transferred from fast-moving particles to slow-moving particles.

Answers

Answer:energy

Explanation:needed points sorry

Explain some of the uses of metals based on their properties.

Answers

Answer:

Explain some of the uses of metals based on their properties.

Explanation:

Metals have a shiny or metallic luster and are good conductors of heat and electricity, they can be bent and pounded in various shapes, so they can be used on cars, coins, some pipes, keys, and and a flag.

Explain why a buffer can be prepared from a mixture of NH4CL and NaOH but not from NH3 and NaOH .​

Answers

A buffer solution is often referred to as a mixture of an aqueous solution of a weak acid and its conjugate base or weak base and its conjugate acid.

NH4CL is a weak base and NaOH is a strong base and when both it gives you a basic buffer and the result will give you an acid/base needed for the buffer.

NH 3 is a weak base, but NaOH is a strong base and therefore the combination of these solutes would not make a buffer solution because both will give you a base and no acid.

Conclusively we can say that an acid or base needed for making buffer solutions and not base alone

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Of the following, which is NOT a component of the circulatory system?
A. Heart
B. Veins
ws
C. Arteries
D. Brain

Answers

Answer:

D. Brain

~PumpkinSpice1

D. Brain Bec that belongs to nervous system?

In acid solution, water can add to the double bond of 2‑butenedioic acid to form 2‑hydroxysuccinic acid.
HOOCCH=CHCOOH+H2O <== H2SO4 ==> HOOCCH2CH(OH)COOH
This reaction is also an important reaction of the tricarboxylic acid cycle in cells, wherein the reaction occurs in neutral solution, so the acid groups are both ionized to the carboxylate form. The reaction is catalyzed by the stereospecific enzyme fumarase that utilizes only the trans form of 2‑butenedioate ion, also known as fumarate, and produces only the (S)‑2‑hydroxysuccinate enantiomer,also known as (s)-malate). Draw the correct stereochemical structures of these two compounds of the fumarase-catalyzed reaction.
fumarate (s)-malate
(trans-2-butenedioate) ((s)-2-hydroxysuccinate)
Fumarase
+ H2O <===========>

Answers

Answer:

Explanation:

The stereochemical structures of the two compounds of the fumarase-catalyzed reaction are in the attachment below. The reaction been referred to is illustrated in the equation below

HOOCCH=CHCOOH + H₂O ==> HOOCCH₂CH(OH)COOH

The compounds attached are trans-2-butenedioate (which is one of the reactants) and (s)-2-hydroxysuccinate (which is the product formed)

Note that stereoisomers are isomers that differ in spatial orientation, thus there are other isomers that could contain the same atoms and have slightly but different spatial orientation such as cis-2-butenedioate and (r)-2-hydroxysuccinate

Help in history class please Thnks

Answers

Answer:

C) Foreign relations and war powers

Weathering is the process that takes place as rocks, and other parts of the geosphere, are??

Answers

Breaking down that’s why they make land slides

PLEASE HELP!!!!

what happens when the ocean reaches it’s saturation level of carbon dioxide?

Answers

Hi!

When the ocean reaches its saturation level of carbon dioxide, a couple of things will happen:

First, more carbon dioxide will remain in the atmosphere, and second, the ocean's pH will drop.

Carbonate and bicarbonate ions in seawater act as a buffer system which keeps the ocean's pH levels stable. When CO2 dissolves in seawater, it reacts with the ocean's buffer system in such a way that it produces two hydrogen ions, which lowers the pH. As more and more CO2 reacts with the ocean's buffer system and the system becomes saturated, less atmospheric carbon dioxide will cross over into the ocean. This excess CO2 will remain in the atmosphere and contribute to global climate change.

Hope this helped!

When the ocean reaches it's saturation level of carbon dioxide  more amount of carbon dioxide remains in the atmosphere and  pH of the ocean drops.

What is saturation level?

It is defined as the level or extent up-to which a substance is soluble in a particular solvent. Due to global warming ,there is an excessive release of carbon dioxide in atmosphere. The excessive amount cannot be soluble in the ocean water which leads to ocean acidification.

As a result of ocean acidification the pH of water in the ocean drops thus there is less amount of oxygen present for aquatic organisms which is needed to survive. When carbon dioxide dissolves in water it yields carbonic acid which further reduces the pH of water  and thus making it unfit for aquatic environment.

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Is adding food coloring to frosting a chemical reaction?

Answers

Answer:

no

Explanation:

Answer:

Yes

Explanation:

Adding food coloring to batter or to your icing involves a chemical reaction of the two products bonding together. This bonding process starts when you add the color and mix it in, but it doesn't end straight away as the color needs some time to fully integrate and settle.

what is the molecular geometry of c atom in ch3nh2

Answers

Answer:

compound is sp3.

Explanation:

Sp3 it is because it is trust me

name the intermolecular force between Ne in liquid​

Answers

Answer:

Intermolecular forces in liquid are

Intermolecular forces are electrostatic in nature and include van der Waals forces and hydrogen bonds. Molecules in liquids are held to other molecules by intermolecular interactions, which are weaker than the intramolecular interactions that hold the atoms together within molecules and polyatomic ions.

Answer:

it is found in the halogen ,the no le gases and in other non polar molecules such as co2 and methane. Landon dispersion force are part of the Vander waals force or weak intermolecular attraction

1) If a bottle of olive oil contains 1.3 kg of olive oil, what is the volume, in milliliters, of the olive oil? Express your answer to two significant figures and include the appropriate units. 2) A cannon ball made of iron has a volume of 116 cm^3. What is the mass, in kilograms, of the cannon ball? Express your answer to three significant figures and include the appropriate units. 3) A balloon filled with helium has a volume of 6.1 L. What is the mass, in grams, of helium in the balloon? Express your answer to two significant figures and include the appropriate units.

Answers

Answer:

1) 1.4 × 10³ mL

2) 0.913 kg

3) 1.1 g

Explanation:

1)

Step 1: Calculate the volume of 1.3 kg of olive oil

The density of olive oil is 0.917 kg/L.

1.3 kg × (1 L/0.917 kg) = 1.4 L

Step 2: Convert the volume to mL

We will use the relationship 1 L = 10³ mL.

1.4 L × (10³ mL/1 L) = 1.4 × 10³ mL

2)

Step 1: Calculate the mass of the cannon ball

The density of iron is 7.87 g/cm³.

116 cm³ × 7.87 g/cm³ = 913 g

Step 2: Convert the mass to kg

We will use the relationship 1 kg = 10³ g.

913 g × (1 kg / 10³ g) = 0.913 kg

3)

Step 1: Calculate the mass of the helium in the balloon

The density of balloon is 0.18 g/L.

6.1 L × 0.18 g/L = 1.1 g

Which reason best explains why metals are malleable

Because they have delocalized electrons

Because they have localized electrons

Because they have ionic bonds

Because they have rigid bonds

Answers

Answer:

A.) because they have delocalized electrons

Explanation:

This is right on edg. 2020

Answer:

Bruzaaubrey is 100% correct

Explanation:

the proper answer is: "Because they have delocalized electrons(A)"

Make sure to mark bruzaaubrey brainliest :)

Lake Michigan holds 13 billion gallons of water. If just Chicago removed water from the lake and it never rained again, how many decades would the water last?

Answers

Answer:

Check explanation section.

Explanation:

In order to be able to answer this question accurately,there is need to follow the formula below for the calculation;

Numbers of decades = total volume/ volume per decade. ----------------------(1).

So, we are given from the Question above that the volume of water in Lake Michigan = 13 billion gallons of water.

And if chicago uses 5 million gallons of water every decade.

Therefore, using the formula (1) above, we have;

Numbers of decades = 13 × 10^9/ 5 × 10^6 = 2.6 × 10^15 decades.

what processes add methane (CH4) to the atmosphere

Answers

Answer:

Cultivated rice paddies

Drilling of natural deposits

Fossil fuel use

Burning of biomass

Landfills

Explanation:

The bulk of the methane released into the atmosphere are as a result of various human activities.

Cultivated rice paddies are a known source of methaneThe drilling of natural deposits and their exploration can release some methane into the atmosphereBurning of fossil fuel and biomass is a source of methane Landfills produces methane as organic materials begins to decay.

How much work (in JJ) is required to expand the volume of a pump from 0.0 LL to 2.5 LL against an external pressure of 1.1 atmatm

Answers

Answer:

- 278.85 J  

Explanation:

Given that:

Pressure = 1.1 atm

The initial volume V₁ = 0.0 L

The final volume V₂ = 2.5 L

The work that takes place in a reaction at constant pressure can be expressed by using the equation:

W = P(V₂ - V₁ )

Since the volume of the gas is expanded from 0 to 2.5 L when 1.1 atm pressure is applied. Then, the work can be given by the expression:

W = - P(V₂ - V₁ )

W = -1.1 atm ( 2.5 - 0.0) L

W = -1.1 atm (2.5 L)

W = -2.75 atm L

Recall that:

1 atm L = 101.4 J

Therefore;

-2.75 atm L = ( -2.75 × 101.4 )J

= -278.85 J  

Thus, the work required at the chemical reaction when the pressure applied is 1.1 atm  = - 278.85 J  

is a salt water solution saturated when there is undissolved salt at the bottom of the bottle?​

Answers

Answer:

Yes

Explanation:

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