can concave lens be used to make hand lens .why?​

This question is not complete, the complete question is;

An electron remains suspended between the surface of the Earth (assumed neutral) and a fixed positive point charge, at a distance of 5.3 m from the point charge. Determine the charge required for this to happen.  The acceleration due to gravity is 9.8 m/s² and the Coulomb constant is 8.98755 x 10⁹ N.m²/C².  Answer in units of C.

Answer: the charge required for this to happen is 1.7415 × 10¹⁹ C

Explanation:

Given the data in the question;

we know that gravitational force on electro = M×g

mass of electron m = 9.10938356 × 10⁻³¹ kilograms

charge of electron e = 1.60217662 × 10⁻¹⁹ coulombs

given that distance r = 5.3m and the Coulomb constant = 8.98755 x 10⁹ N.m²/C²

g = 9.8 m/s²

Now for the electron to be suspended, This will happen only if the electrostatic force is equal to weight of electron;

[ (1/4πε0) × q × e] / r²   =   m × g

so we substitute

8.98755 x 10⁹ × q × 1.60217662 × 10⁻¹⁹/[5.3]² = 9.10938356 × 10⁻³¹ × 9.8

q =  8.9271 × 10⁻³⁰ / 5.1262 × 10⁻¹¹

q = 1.7415 × 10¹⁹ C

Therefore the charge required for this to happen is 1.7415 × 10¹⁹ C

[1.43996 × 10⁹ × q] / 29.09 =  8.92719 x 10⁻³⁰

1.43996 × 10⁹ × q  = 2.5969 × 10⁻²⁶

q = 2.5969 × 10⁻²⁶ / 1.43996 × 10⁹

q =  

Answer:

[tex]y = - 2.7876 * 10^{28}[/tex]

[tex]x= 3.0199 * 10^{28}[/tex]

Explanation:

Given

[tex]12x+13y=12.01[/tex]

[tex]x+y=2.323 * 10^{27}[/tex]

Required:

Solve

Make x the subject in [tex]x+y=2.323 * 10^{27}[/tex]

[tex]x=2.323 * 10^{27} - y[/tex]

Substitute the above expression for y in [tex]12x+13y=12.01[/tex]

[tex]12(2.323 * 10^{27} - y) + 13y = 12.01[/tex]

Open brackets

[tex]12*2.323 * 10^{27} - 12y + 13y = 12.01[/tex]

[tex]12*2.323 * 10^{27} + y = 12.01[/tex]

Collect Like Terms

[tex]y = 12.01 - 12*2.323 * 10^{27}[/tex]

[tex]y = 12.01 - 2.7876 * 10^{28}[/tex]

12.01 is negligible compared to [tex]2.7876 * 10^{28}[/tex]

So:

[tex]y = - 2.7876 * 10^{28}[/tex]

Substitute the above expression for y in [tex]x=2.323 * 10^{27} - y[/tex]

[tex]x=2.323 * 10^{27} - (- 2.7876 * 10^{28})[/tex]

[tex]x=2.323 * 10^{27} + 2.7876 * 10^{28}[/tex]

[tex]x= 0.2323 * 10^{28} + 2.7876 * 10^{28}[/tex]

[tex]x= 3.0199 * 10^{28}[/tex]

Answer:

F =  73.7 N = 74 N (rounding off)

Explanation:

In order to get the box to start moving, Mr. Ames must push it with a force equal to the frictional force acting on it. Therefore, this force can be calculated through the following formula:

[tex]F = frictional force = \mu R[/tex]

where,

μ = coefficient of friction = 0.55

R = Normal Force on Box = Weight of Box with books = 134 N

Therefore,

[tex]F = (0.55)(134\ N)\\[/tex]

F =  73.7 N = 74 N (rounding off)

Answer:

This doesn't seem to really be a physics problem:

In physics stress is usually defined as Young's Modulus or Bulk Modulus

In the case of Young's Modulus Y would be defined as

Y = Stress / Strain or  Force / Area

So the stress would be the force acting on some particular area: in the case of a wire the area is merely the area of the wire where the force is applied.

So maybe, they mean that stress would be an increase in blood pressure or some other physiological reaction due  to an externally applied force.

Given that,

Number of turns, N = 25

Magnetic field, B = 1.5 T

The coil has a crosssectional area of 0.80 m2

The coil exits the field in 1.0 s.

To find,

Induced emf in the coil.

Solution,

The induced emf in the coil is given by :

[tex]\epsilon=\dfrac{-d\phi}{dt}\\\\=\dfrac{dB}{dt}\\\\=\dfrac{NBA}{t}\\\\=\dfrac{25\times 1.5\times 0.8}{1}\\\\=30\ V[/tex]

So, the induced emf in the coil is 30 V.

Answer:

Electromechanical transducer,

Explanation:

this is the answer I hope u got it

Answer:

yes it is a correct answer

Answer:

B) 0.3Hz

Explanation:

I just took the test i hope i helped and i hope you pass the test

Answer:.5

Explanation:

I took the quiz

Answer:

Lateral inversion is a phenomenon in which left appears to be right and vice versa. It is due to direction that light follows when it strikes a reflecting surface, generally a mirror.

Answer:

the impulse imparted to the ball is 4.158 kg.m/s

Explanation:

Please find attached image for diagram.

Given;

initial speed of the ball from point A, u = 54km/h = 15 m/s

angle of deflection of the ball along BOP, θ = 45⁰/2 = 22.5⁰

mass of the ball, m = 0.15 kg

the final speed of the ball along B,  = u (in reverse direction)

The initial momentum of the ball, P₁ = mucosθ

The final momentum of the ball is P₂ in reverse direction to P₁.

the impulse imparted to the ball = change in momentum of the ball

J = ΔP = P₂ - P₁

J = mucosθ - (-mucosθ)

J = mucosθ + mucosθ

J = 2mucosθ

J = 2(0.15)15cos(22.5⁰)

J = 4.158 kg.m/s

Thus, the impulse imparted to the ball is 4.158 kg.m/s

Answer:

Total Mass = 18 kg 900 gram

Explanation:

Given:

Mass of sugar buy = 6 kg 500 gram

Mass of rice buy = 12 kg 400 gram

Find:

Total Mass

Computation:

Total Mass = Mass of sugar buy + Mass of rice buy

Total Mass = 6 kg 500 gram + 12 kg 400 gram

Total Mass = 18 kg 900 gram

Answer:

the volume that has 1.0m^2 of water from the surface of the lake is 4.3

Explanation:

The computation of the volume is as follows;

The Bulk modulus is

= K = 2.3 × 10^9 Pa

K = - V dP ÷ dV

dV = - V dP ÷ K

dV = - (1 × 101.3 × 1000) ÷  2.3 × 10^9

= - 4.3 × 10^-3 m^3

So the volume that has 1.0m^2 of water from the surface of the lake is 4.3

Hence the same is relevant and considered

Answer:

they are closer!!

Explanation:

Hope this helped!! :D

Answer:

6.1 × 10^9 Nm-1

Explanation:

The electric field is given by

E= Kq/d^2

Where;

K= Coulombs constant = 9.0 × 10^9 C

q = magnitude of charge = 1.62×10−6 C

d = distance of separation = 1.53 mm = 1.55 × 10^-3 m

E= 9.0 × 10^9 × 1.62×10−6/(1.55 × 10^-3 )^2

E= 14.58 × 10^3/2.4 × 10^-6

E= 6.1 × 10^9 Nm-1

Answer:

A. Air

Explanation:

Answer : The weight of the car is 9800 N

Explanation :

It is given that,

The mass of the car, m = 1000 kg

We have to find the weight of the car. The weight of an object is defined as the force acting on it under the action of gravity. The mass of an object is the amount of matter present in it.

Using second law of motion :

W = m g

Where

m is the mass of the car

g is the acceleration due to gravity g = 9.8 N/kg

W = 1000 kg × 9.8 N/kg

W = 9800 N

So, the weight of the car is 9800 N.

Hence, this is the required solution.

Answer: The weight of the car in newtons is 9800N/kg

Explanation:

Answer:

volume = 683.53 [tex]m^{3}[/tex]

Explanation:

From the given question,

area  = 2420 [tex]ft^{2}[/tex]

height = 10 ft = 3.048 m

But,

1 [tex]ft^{2}[/tex] = 0.092903 [tex]m^{2}[/tex]

So that,

2420 [tex]ft^{2}[/tex] = 224.8254 [tex]m^{2}[/tex]

Volume = area x distance

             = 224.8254 x 3.048

             =  683.5262

volume = 683.53 [tex]m^{3}[/tex]

Answer:

9.836 ms^-2

Explanation:

If

r= 3re

m= 9me

But

g= Gm/r^2

G= 6.67 × 10^-11

me= 6 × 10^24 Kg

re= 6.38 × 10^6 m

g= 6.67 × 10^-11 × 9×6 × 10^24/(3 ×6.38 × 10^6)^2

g= 9.836 ms^-2

Answer:

Someone might think the answer is 30 m when the person cannot distinguish between absolute pressure and gauge pressure.

Explanation:

Given absolute pressure at a depth of 20 m = 3 atm.

When you drive down 30 m in water, the gauge pressure experienced is calculated as;

P = ρgh

Where;

ρ is density of water = 1000 kg/m³

g is acceleration due to gravity, = 9.8 m/s²

h is the depth of water = 30 m

P = (1000)(9.8)(30)

P = 294000 Pa

in atm = [tex]\frac{294000}{101325} = 2.9 \ atm[/tex] ≅ 3 atm.

Thus, someone might think the answer is 30 m when the person cannot distinguish between absolute pressure and gauge pressure.

Someone  might think the height (depth) is 30 meters, if he or she is unable to distinguish between gauge pressure and absolute pressure.

Given the following data:

Scientific data:

To calculate the gauge pressure at a depth below the surface of a water:

Mathematically, gauge pressure is given by this formula:

[tex]P = \rho gh[/tex]

Where:

Substituting the given parameters into the formula, we have;

[tex]P = 1000 \times 9.8 \times 30[/tex]

Gauge pressure = 294000 Pa

Next, we would convert the value in Pascals to atmosphere.

Conversion:

1 atm = 101325 Pa

X atm = 294000 Pa

Cross-multiplying, we have:

[tex]X = \frac{294000}{101325}[/tex]

X = 2.90 ≈ 3.0 atm.

Read more on absolute pressure here: https://brainly.com/question/10013312

Answer:

C. Horizontal component of velocity

Explanation:

Object in motion stays in motion,

nothing works against its motion in the horizontal direction, unlike in the vertical direction, gravity pulls object down.

Answer:

Same charge, positive.

Please see below as the answer is self-explanatory.

Explanation:

Answer:

2239

Explanation: Stack addition

Answer: 2,239

Explanation: do 2OOO + 1OO + 5O + 89, that will give you 2,239.

Answer:

Explanation:

F = 0.000000000042716 or 4.2688e-11

G = 6.67 × 10−11 Nm2 /kg2

m1 = 2kg

m2 = 2kg

R = 2.5 m ⇒ R^2 = 6.25

F =  6.67 × 10^−11 ( 2 * 2) / 6.25

⇒ F = 6.67 × 10^−11 (4) / 6.25

⇒ F = 2.668e-10 / 6.25

∴ F = 4.2688e-11

Answer:

no distance is moved as w=f×d

Answer: conductors are substances that allow heat or electricity to pass through . It deals with only the flow of electrons.

Eg. water, copper wire, iron rod, some ceramic materials, metallic nail.

Insulators are materials that do not allow heat or electricity to pass through.

Eg. Book, plastic, rubber, glass, paper

Explanation:

This question is incomplete, the complete question is;

A parallel-plate capacitor is made from two aluminum-foil sheets, each 3.0 cm wide and 5.00 m long. Between the sheets is a mica strip of the same width and length that is 0.0225 mm thick. What is the maximum charge?

(The dielectric constant of mica is 5.4, and its dielectric strength is 1.00×10⁸ V/m)

Answer: the maximum charge q is 716.85 μF

Explanation:

Given data;

with = 3.0 cm = 0.03

breathe = 5.0 m

Area = 0.03 × 5 = 0.15 m²

dielectric strength E = 1.00 × 10⁸

∈₀ = 8.85 × 10⁻¹²

constant K = 5.4

maximum charge = ?

the capacitor C = KA∈₀ / d

q = cv so c = q/v

now

q/v = KA∈₀ / d

q =  vKA∈₀/d = EKA∈₀

we substitute

q = (1.00 × 10⁸) × 5.4 × 0.15 ×  8.85 × 10⁻¹²    

q = 716.85 × 10⁻⁶ F

q = 716.85 μF

the maximum charge q is 716.85 μF

Answer:

8

10th classpepar2021

Answer:

y ≤ 1x-1

Explanation:

line is not dotted = ___ than or equal to

shaded area below line = less than

so: ≤

--

y=mx+b

y intercept -1 (line intersects y line on -1)

y=mx-1

points (1,0) (0, -1)

find slope

---

in conclusion, y ≤ 1x - 1

hope this helped ya :-)

Answer

plutonium

Explanation:

brainliest please

Answer:

A.

Explanation:

Answer:

B) the number of cycles per second perceived by the human ear

Explanation:

The best expression that describes pitch is that it is the number of cycles per second perceived by the human ear.

For a wave train, the number of cycles per second is frequency. Whereas the period is the amount of time taken for a longitudinal wave to produce one cycle.

The distance between two corresponding parts of a transverse wave is its wavelength.