Can gravity be considered a force even though the objects are not in contact?

Answer:

d) C₂H₅O₂

Explanation:

Molecular formula is a whole-number ratio of atoms presents in a molecule. The percentage given is in mass. Thus, we need to convert this percentage to moles using atomic mass of each atom and, in this way, we can solve for the ratio of atoms and molecular formula as follows:

C = 39.33g * (1mol / 12.01g) = 3.275mol

H = 8.269g * (1mol / 1.005g) = 8.228mol

O = 52.40g * (1mol / 16g) = 3.275mol

To obtain the ratio we must divide each amount of moles in the low number of moles (Moles of O or C):

C = 3.275mol / 3.275mol = 1

H = 8.229mol / 3.275mol = 2.5

O = 3.275mol / 3.275mol = 1

Multiplying this ratio in 2 (To obtain the whole-number ratio):

C = 1*2 = 2

H = 2.5*2 = 5

O = 1*2 = 2

The molecular formula is:

C₂H₅O₂

And right answer is:

London Dispersion force or Van de Waals force is a temporary attractive force which are the weakest and occur between nonpolar noble gases and same charges. This force is weaker because they have more electrons that are farther from the nucleus and are able to move around easier.

Example: [tex]N_2[/tex], [tex]F_2, \ I_2[/tex]

[tex]\huge\textbf{Dipole - Dipole Forces}[/tex]

Dipole force is present between the polar molecules. Polar molecules are those molecules which have slightly negative and slightly positive charge. Dipole-dipole forces are attractive forces between the positive end of one polar molecule and the negative end of another polar molecule.

Example: HCl, HF, [tex]CHCl_3[/tex]

[tex]\huge\textbf{Hydrogen Bonding}[/tex]

It is a special type of dipole force present between polar molecules, it is formed between Hydrogen atom which forms positive ion, and the other negative ion. It results from the attractive force between a hydrogen atom covalently bonded to a very electronegative atom such as a N, O, or F atom. The hydrogen bond is one of the strongest intermolecular attractions, but weaker than a covalent or an ionic bond.

Example: Every polar molecule which has hydrogen has hydrogen bonding i.e. [tex]H_2O, NH_3[/tex]

The energy of the waves is 6.5 * 10^-19 J.

The energy of the wave could be obtained from the wavelength of the wave by by the use of the formula shown below;

E = hc/λ

h = Plank's constant

c = speed of light

λ = wavelength

Now we have;

h = 6.6 * 10^-34 Js

c = 3 * 10^8 m/s

λ =  305 * 10^-9

E =  6.6 * 10^-34 Js * 3 * 10^8 m/s/ 305 * 10^-9

E = 6.5 * 10^-19 J

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A. The period of a pendulum can b defined as the time it takes the pendulum to make one full back-and-forth swing.

The period of a pendulum is defined as the time taken by the pendulum to finish one full oscillation and is denoted by letter "T".

The period of oscillation of a pendulum is calculated as follows;

T = 2π√(L/g)

where;

The period of a pendulum does not depend on the mass of the ball, but only on the length of the string.

Thus, we can conclude that, the period of a pendulum can b defined as the time it takes the pendulum to make one full back-and-forth swing.

A full back ad forth swing makes one complete oscillation.

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Answer: calcium

Explanation: a periodic table can tell you how many protons have, and from this we can see that the answer is calcium

Answer:

0.45 grams of hydrogen and 3.53 grams of oxygen will be formed, when 4.05 grams of water is used.

Explanation:

The given reaction is [tex]2H_20 \rightarrow 2H_2 + O_2[/tex]

2 moles of [tex]H_2O[/tex] is used to form 2 moles of [tex]H_2[/tex] and 1 mole of [tex]O_2[/tex]

As 1 mole of [tex]H_2O=18 g[/tex], 1 mole of [tex]H_2=2 g[/tex], and 1 mole of [tex]O_2=32 g[/tex].

So, 36 grams of [tex]H_2O[/tex] is used to form 4 grams of [tex]H_2[/tex] and 32 grams of [tex]O_2[/tex]

Therefore, 1 gram of [tex]H_2O[/tex] is used to form 4/36 grams of [tex]H_2[/tex] and 32/36 grams of [tex]O_2[/tex]

Therefore, 4.05 gram of [tex]H_2O[/tex] is used to form (1/9)4.09=0.45 grams of [tex]H_2[/tex] and (8/9)4.05=3.53 grams of [tex]O_2[/tex].

Hence, 0.45 grams of hydrogen and 3.53 grams of oxygen will be formed, when 4.05 grams of water is used.

The length of lead wire in meters is 2.48 m.

The mass of lead in the wire is calculated as follows:

moles of lead = 0.0236 moles

molar mass of lead = 207

mass of lead = 0.0236 * 207

mass of lead = 4.8852 g

The length of the is determined as follows:

volume of wire = 4.8852/11.3

volume of wire = 0.432 cm³

diameter of lead wire = 0.470 mm = 0.047 cm

radius of the lead wire = 0.047 cm * 0.5 = 0.0235 cm

Assuming the lead wire is in the shape of a cylinder:

volume of the cylindrical lead wire = πr²l

l = volume/πr²

length of lead wire = 0.432/3.142 * 0.0235²

length of lead wire = 248.967 cm

length of lead wire in meters = 2.48 m

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Answer: 39.948 grams

Explanation:

The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles Ar, or 39.948 grams

Answer:

3x10 16hz 16 small above 10

Explanation:the frequency of any wave is (wave speed)/(wavelength)

The speed of light is 3x10 m/s. that's 30 million quartz

Answer:

Barium chloride + Sodium phosphate    →   barium phosphate + sodium chloride

Explanation:

Double replacement:

It is the reaction in which two compound exchange their ions and form new compounds.

AB + CD → AC +BD

Chemical equation:

BaCl₂ + Na₃PO₄         →     Ba₃(PO₄)₂ + NaCl

Balanced chemical equation:

3BaCl₂ + 2Na₃PO₄         →     Ba₃(PO₄)₂ + 6NaCl

The cation and anion of both reactants are exchanged with each other.

Ba²⁺ react with PO₄³⁻ and form Ba₃(PO₄)₂ while Cl⁻ react with Na⁺ and form sodium chloride.  

Molecular equation:

Barium chloride + Sodium phosphate    →   barium phosphate + sodium chloride

Answer:

droughts in California have become more common in California

Explanation:

Climate is weather over time which means that the first and the third one are just isolated incidents and the last answer choice shows climate but it doesn't show a change in climate

The density : 21.63 g/L

The gas equation can be written  

[tex]\large {\boxed {\bold {PV = nRT}}}[/tex]

where  

P = pressure, atm  

V = volume, liter  

n = number of moles  

R = gas constant = 0.08206 L.atm / mol K  

T = temperature, Kelvin  

T = 65+273=338 K

P=2.36 atm

MW Iodine gas (I₂)=254

The density :

[tex]\tt \rho=\dfrac{P\times MW}{RT}\\\\\rho=\dfrac{2.36\times 254}{0.082\times 338}=21.63~g/L[/tex]

Answer:

The correct answer is - 1. oxaloacetate.

Explanation:

During the electron transport chain, the oxaloacetate is converted to aspartate by the reduction of NADH and accepting electrons in the mitochondria. Aspartate is then moved through the inner membrane to the cytosol.

This is the reaction also known as the synthesis of the aspartate. Aspartate either again converted to OAA (oxaloacetate) or move to the biosynthesis of proteins and biosynthesis of purine and pyrimidines.

The element from which it is easier to remove an electron between Argon and Bromine is Bromine.

This can be explained by electron affinity.

Electron affinity is defined as amount of the energy released when one mole of electron is added to one mole of atom or to the outermost or valence shell to form anion. It is the measure of attraction existing between atom and electron.

Electron affinity of Bromine is 324.537 kJ/mol and electron affinity of Argon is -96 kJ/mol. A higher electron affinity indicates that an atom accepts or removes the electrons more easily and low electron affinity means that an atom do not accept or remove electrons as easily.

Bromine has atomic number 35, which means it has 35 protons in nucleus. It has 35 electrons and for a bromine atom to become a 1- bromide ion, it will have to gain an electron. If it loses electrons, it receives a positive charge because it has more protons than electrons.

Argon is a noble gas element. It means argon is highly stable because it has full outer shell of electrons. Argon has low affinity. Therefre, it does not lose or gain electrons because it is already stable.

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Answer:

Before I answer I feel that I should provide some scientific background as to how you would go about determining the answer.

First point that’s important for you to understand is the following formula

F =  G∗(M1∗M2)/d2

Where G is your gravitational constant, which means that comparing the two weights it won’t change and we don’t really have to worry ourselves too much about it.

Secondly we have the masses of the two individual objects, M1 and M2, in this case M1 is going to be 120 pounds.

Then you have d which is the distance between the centres of the two objects.

The second thing you need to understand is the fine print in the question. You asked how much you would weigh given that you weigh 120 pounds on Earth. The question from a pure science view is flawed as you don’t infact weigh 120 pounds, rather you have a mass of 120 pounds which will remain a constant. Your weight on Earth is actually 530 Newtons

(120lb=54,4311kg)

(54,4311kg*9.8) = approximately 530N

Now assuming you are right and the moon has a sixth of the earths mass, that would mean that you would weigh a sixth of it.

But wait theres more, because the radius of the moon is smaller it will have an impact. the radius of the moon infact is a sixth of the earths, which means that you will be multiplying by 36(because you are making the divisor a sixth smaller, but also squaring it)

this would mean that you would weigh six times as much on the moon as on Earth, which we know is not true. This implies you made a mistake with the mass of the moon compared to that of the Earth. So upon googling it.

Mass of Earth

5.972 × 10^24 kg

Mass of Moon

7.34767309 × 10^22

kilograms

Just looking at it the difference is about 200 times, which means that you probably misinterpreted the data, the gravitational attraction of the moon is a sixth of the Earths, which means you would weigh about 530/6N or to the casual viewer about 88 N

Note : I rounded and abstracted a lot because I feel its the gist of the answer and the understanding that’s important, you are welcome to contact me if you feel anything is incomplete or unclear. I did most of the math quickly and am liable to mistakes but the science is right(unless ofc you feel like bringing relativity in, but that’s a whole other can of worms

Explanation:

Yess

Answer:

19.92 pounds :)

Answer:

Explanation:

Answer:

[Al³⁺] = 1.62 M

[SO₄²⁻] = 2.43 M

Explanation:

Step 1: Given data

Molar concentration of Al₂(SO₄)₃: 0.811 M

Step 2: Write the reaction for the ionization of Al₂(SO₄)₃

Al₂(SO₄)₃(aq) ⇒ 2 Al³⁺(aq) + 3 SO₄²⁻(aq)

Step 3: Calculate the molar concentration of Al³⁺

The molar ratio of Al₂(SO₄)₃ to Al³⁺ is 1:2. The molarity of Al³⁺ is 2/1 × 0.811 M = 1.62 M.

Step 4: Calculate the molar concentration of SO₄²⁻

The molar ratio of Al₂(SO₄)₃ to SO₄²⁻ is 1:3. The molarity of SO₄²⁻ is 3/1 × 0.811 M = 2.43 M

The concentration of the aluminium ion is 0.4055 M while the concentration of the sulfate ion is 0.270  M.

We know that the following reaction occurs for the dissolution of Al2(SO4)3 in water;

Al2(SO4)3(s) ----> 2Al^3+(aq) + 3SO4^2-(aq)

To find the concentration of each of the ions;

So using the square bracket notation to indicate concentration;

[Al^3+] = 0.4055 M

So using the square bracket notation to indicate concentration;

[SO4^2−] =0.270  M

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Answer:

See explanation

Explanation:

The mole refers to the amount of substance contained in 12 g of carbon-12. It was arbitrarily related to the number of elementary entities in 12 g of carbon -12 by Prof. Avogadro.

The number of moles of a substance is obtained as the mass of the substance divided by the mass of one mole of the substance (molar mass). Hence when the number of moles is known, the mass is now;

number of moles * molar mass

Answer:

1.18 × 10²⁴ particles Mg

General Formulas and Concepts:

Chemistry - Atomic Structure

Explanation:

Step 1: Define

47.7 g Mg

Step 2: Identify Conversions

Avogadro's Number

Molar Mass of Mg - 24.31 g/mol

Step 3: Convert

[tex]47.7 \ g \ Mg(\frac{1 \ mol \ Mg}{24.31 \ g \ Mg} )(\frac{6.022 \cdot 10^{23} \ particles \ Mg}{1 \ mol \ Mg} )[/tex] = 1.18161 × 10²⁴ particles Mg

Step 4: Check

We are given 3 sig figs. Follow sig fig rules and round.

1.18161 × 10²⁴ particles Mg ≈ 1.18 × 10²⁴ particles Mg

Answer:

A. Bar graph

Explanation:

Bar graphs are used to compare things between different groups or to track changes over time. 

Answer:

option a, bar graph

Explanation:

- a graphic means of quantitative comparison by rectangles with lengths proportional to the measure of the data or things being compared

Answer:

Explanation:

What occurs here (the description in the question) is condensation. Condensation is the process in which water changes from it's gaseous state (steam) to it's liquid state. When the hot air leaves the oven, and it touches/ passes through the glasses of John (that is of a lower thermal energy), the hot air would lose some of it's thermal energy (due to the lower thermal energy of the glasses) and then transits back to liquid forming the visible fog steam on the glasses.

Answer:

0.491 atm

Explanation:

Initial volume V1 = 571.5 mL = 0.5715 L

Initial Pressure P1 = 0.944 atm

Initial Temperature T1 = 10 oC + 273 = 283 K (Converting to kelvin units)

Final Temperature T2 = 32 oC + 273 = 305K (Converting to kelvin units)

Final volume V2 = 1.183 L

Final Pressure P2 = ?

These parameters related by the combined gas law;

P1V1 / T1   = P2V2 / T2

Mke P2 subject of formular;

P2 = P1 V1 T2 / V2 T1

P2 = 0.944 * 0.5715 * 305  /  1.183 * 283

P2 = 0.491 atm

Answer:

c

Explanation:

energy does not have volume

Answer:

Explanation:

Moles of potassium permanganate = 0.0008

Titration is a procedure for determining the concentration of a solution by reacting with another solution which is known to be concentrated (usually a standard solution). Determination of the endpoint/equivalence point of the reaction can use indicators according to the appropriate pH range  

Reaction

5Na2C2O4(aq) + 2KMnO4(aq) + 8H2SO4(aq) ---> 2MnSO4(aq) + K2SO4(aq) + 5Na2SO4(aq) +  10CO2(g) + 8H2O(1)

The end point ⇒titrant and analyte moles equal

titrant : potassium  permanganate-KMnO4

analyte : sodium oxalate - Na2C2O4

so moles of KMnO4 = moles of Na2C2O4

moles of Na2C2O4(mass = 0.2640 g, MW=134 g/mol) :

[tex]\tt mol=\dfrac{mass}{MW}\\\\mol=\dfrac{0.264}{134 g/mol}\\\\mol=0.002[/tex]

From equation, mol ratio  Na2C2O4 : KMnO4 = 5 : 2, so mol KMnO4 :

[tex]\tt \dfrac{2}{5}\times 0.002=0.0008[/tex]

Answer:

you didn't show the options

Explanation: