can someone help me with this

Answer:

Step-by-step explanation:

The sum of three angles is 180 degrees.

Show this as equation and solve for x:

Angle one is:

Answer:

-1

Step-by-step explanation:

[tex]m= \frac{y2 - y1}{x2 - x1} [/tex]

put the values you will get your answer.

The range of values for the expressions are given by these following compound inequalities:

A compound inequality is a combination of multiple inequalities, at least two, involving operations such as and and or, explained below.

Hence one example of a compound inequality is:

a ≤ x ≤ b.

Which is read as follows:

x is greater or equal than a and less or equal than b.

The smallest possible value is when both a and b are at their lower bounds, hence:

a + b = 2 + 1 = 3.

The greatest possible value is when both a and b are at their upper bounds, hence:

5 + 2 = 7.

Then the range is:

3 < a + b < 7.

Since the ranges of a and b are open intervals, the ranges of the operations will also be composed by open intervals.

The smallest possible value is when both a and b are at their lower bounds, hence:

a x b = 2 x 1 = 2.

The greatest possible value is when both a and b are at their upper bounds, hence:

a x b = 5 x 2 = 10

Then the range is:

2 < ab < 10.

The smallest possible value is when a is at it's lower bound and b is at it's upper bound, hence:

2 - 2 = 0

The greatest possible value is when a is at it's upper bound and b is at it's lower bound, hence:

5 - 1 = 4.

Hence the range is:

0 < a - b < 4.

The smallest possible value is when a is at it's lower bound and b is at it's upper bound, hence:

2/2 = 1.

The greatest possible value is when a is at it's upper bound and b is at it's lower bound, hence:

5/1 = 5.

Hence the range is:

1 < a/b < 5.

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Answer:

8

Step-by-step explanation:

-5 is 5 units left of zero.

3 is 3 units right of zero.

The difference is 8.

Answer:

Option 3

Step-by-step explanation:

[tex]|6t-7|-8 \geq 3 \\ \\ |6t-7| \geq 11 \\ \\ 6t-7 \leq -11, 6t-7 \geq 11 \\ \\ 6t \leq -4, 6t \geq 18 \\ \\ t \leq -2/3, t \geq 3[/tex]

Answer:

Point J

Step-by-step explanation:

Collinear means in a line

Point J is on the same line with E and H

The number is -4

[tex]x \times[/tex]4+4= 2[tex]x[/tex]-4

[tex]$$x \times 4+4=2 x-4$$[/tex]

Subtract 4 from both sides[tex]$x \times 4+4-4=2 x-4-4$[/tex]

Simplify

[tex]$$x \times 4=2 x-8$$[/tex]

Subtract [tex]$2 x$[/tex] from both sides [tex]$x \times 4-2 x=2 x-8-2 x$[/tex]

Simplify

[tex]$$2 x=-8$$[/tex]

Divide both sides by 2

[tex]\frac{2 x}{2}=\frac{-8}{2}$$[/tex]

Simplify

[tex]$$x=-4$$[/tex]

A strategy for teaching division is by repeated subtraction. It involves repeatedly subtracting the same integer from a big number until the result is zero. It is a fantastic approach to teach kids about division. A technique called repeated subtraction, commonly referred to as division, removes an equal amount of items from a group.

Multiplication is the opposite of division. If 3 groups of 4 add up to 12, then 12 divided into 3 groups of equal size results in 4 in each group. Creating equal groups or determining how many people are in each group after a fair distribution is the basic objective of division.

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The difference between 4 and the sum of a number and is equal to twice that number. The number is -4.

Given that,

The difference between 4 and the sum of a number and is equal to twice that number.

Repeated subtraction is a method for teaching division. Until the result is zero, the same integer must be repeatedly subtracted from a large number. Repeated subtraction, sometimes known as division, is a method that takes an equal number of elements out of a group.

Division's opposite is multiplication. If 3 groups of 4 total up to 12, then 4 are in each group when 12 is divided into 3 equal groups. The fundamental goal of division is to produce equal groups or to determine how many individuals are in each group following a fair distribution.

x×4+4=2x-4

Subtracting 4 on both sides

4x+4-4=2x-4-4

4x=2x-8

Now, substracting 2x from both sides

4x-2x=2x-8-2x

2x=-8

x=-4

Therefore, The number is -4.

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Answer: Domain: [-1, 1]

Range: [-2, 3]

Step-by-step explanation:

Domain: The x-values go from -1 to 1 with x=-1 and x=1 included.

Range: The range starts at the vertex of the function which is y=-2 and goes up to y=3 where the graph is cut off by 2 points on y=3.

what of disibility rules?

The equation in the form y = mx + b is as follows:

y = 1 / 5 x + 32

The customer uses 500 minutes, the monthly cost will be $132. If the customer uses 700 minutes, the monthly cost will be $172.

Using linear equation in slope intercept form,

y = mx + b

where

Hence,

x = the number of monthly minutes used

y = the total monthly of the Ringular plan

Therefore, the equation in slope intercept form can be represented as follows:

(500, 132)(700, 172)

let's find the slope,

m = 172 - 132 / 700 - 500

m = 40 / 200

m = 4 / 20

m = 1 / 5

Hence,

y = 1 / 5x + b

using (500, 132) let's find the y-intercept

132 = 1 / 5 (500) + b

132 = 100 + b

b = 132 - 100

b = 32

Therefore, the equation in the form y = mx + b is as follows:

y = 1 / 5 x + 32

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Answer:

50

Step-by-step explanation:

The answer is 50 because f(6) basically means to substitute 6 for x.

8(6)+2

48+2

50

So the evaluation of f(6) is 50

The reasonable domain of the given situation is 0≤ x ≤2 that is 0 to 2 hours.

We see that x is represented as the number of phone hours used, therefore it has to be a number larger or equal to zero, but not a negative number. So, on one end we have that the number of phone hours used (x) must be larger or equal to zero. On the other hand, when the battery goes to zero, there are no more phone hours to use. We can find what is that other limit by making the battery percent (y variable) equal to zero, and solve the equation for x, thus giving us the upper limit of usable phone hours:

=> y = 0 = 100 - 50x

=> 100 = 50x

=> x = 100/50

=> x = 2

Therefore, the phone can be used for a maximum of 2 hours and the situation may be written as 0≤ x ≤2.

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Answer:

[tex] \sf \large{m=−3}[/tex]

Step-by-step explanation:

Let's solve your equation step-by-step.

10=7−m

Step 1: Simplify both sides of the equation.

10=7−m

10=7+−m

10=−m+7

Step 2: Flip the equation.

−m+7=10

Step 3: Subtract 7 from both sides.

−m+7−7=10−7

−m=3

Step 4: Divide both sides by -1.

−m/−1= 3/−1

m=−3

The speed of the car at the bottom of the loop is approximately 31.3 m/s

The given parameters are;

Mass of the car = 500 kg

Radius of the loop = 20 meters

Velocity of the car at the top of the loop = 14 m/s

The kinetic energy at the top of the loop is therefore;

K E. = 0.5×500×14² = 49,000

The potential energy gained = 500×9.81×40 = 196200

Total energy = 49,000 + 196,200 = 245,200

The velocity at the bottom is therefore;

0.5×500×v² = 245,200

v² = 245,200 ÷ (0.5×500) = 980.8

v = √(980.8) ≈ 31.3

The velocity at the bottom of the loop is therefore;

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Answer: 1/3 and 3/5

Step-by-step explanation:

Answer:

[tex]3^{-9}[/tex]or [tex]\frac{1}{3^{9} }[/tex]

Step-by-step explanation:

3^3/3^12 = 3^3 * 3^(-12) = 3 ^(3-12) = 3^(-9) or 1/3^9

Answer:

  95°

Step-by-step explanation:

You want the measure of angle TVZ, when adjacent angle (2x+5)° and its supplement (2x+15)° are given. The larger of these is a vertical angle with respect to TVZ.

The angles marked (2x+15)° and (2x+5)° are a linear pair, hence supplementary.

  ((2x+15)° +(2x+5)° = 180°

  4x +20 = 180 . . . . simplify

  x +5 = 45 . . . . . . . divide by 4

  x = 40 . . . . . subtract 5

Angle TVZ is a vertical angle with respect to the one marked (2x+15)°, so has the same measure:

  ∠TVZ = (2(40)+15)°

  ∠TVZ = 95°

__

Alternate solution

The two angles RVW (2x+15)° and ZVW (2x+5)° obviously differ by 10°. They are a linear pair, so their sum is 180°. Finding these angles is then a "sum and difference" problem. The larger of the solutions is the one we want, as (2x+15)° is a vertical angle to TVZ. We know the larger of the solutions to the sum and difference problem will be (180° +10°)/2 = 95°, the measure of TVZ.

More about sum and difference problems:

When a+b = s, and a-b = d, the larger value (a) can be found by adding these equations: (a+b) +(a-b) = s+d, or 2a = s+d, or a = (s+d)/2. This is the expression we used above to find the larger of the two angles. (You notice it is not necessary to solve for x.)

Answer:

12/25

Step-by-step explanation:

you have to start by reducing it by the lowest divisible numbers gradually till you get a fraction that cannot be divisible again.

start with two

48/100 = 24/50 = 12/ 25

12/25 cant be divided by any other number ahain therefore that's your final answer.

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Answer:

-40

Step-by-step explanation:

It states with g(-2) that x = -2, so we can plug -2 for x.

g(x) = 3x^3 - 2x^2 + 4x
g(x) = 3(-2)^3 - 2(-2)^2 + 4(-2)
g(x) = 3(-8) - 2(4) + 4(-2)
g(x) = -24 - 8 - 8
g(x) = -40

Answer:

Step-by-step explanation:

divide 14 by 11

which is 0.36

The numbers 7, 22, 11, 34, 17, 52, 26, 13 and so on represent hailstone sequence.

These patterns are referred to as hailstone sequences because the values frequently rise and fall, resembling a hailstone inside a cloud.

It should be noted that such numbers can either rise or fall.

Therefore, the numbers 7, 22, 11, 34, 17, 52, 26, 13 and so ob represent hailstone sequence.

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The type of market in which  all employee can take orders, sell flowers, make arrangements, and commit the store to large orders for weddings, banquets, and special events is Oligopoly.

An oligopoly is a market characterized by a small number of firms who realize they are interdependent in their pricing and output policies. The number of firms is small enough to give each firm some market power.

Given situation:

All employee can take orders, sell flowers, make arrangements, and commit the store to large orders for weddings, banquets, and special events.

As, A market structure known as an oligopoly occurs when a few large sellers or manufacturers control a sizable portion of a market or an entire sector.

Oligopolies are frequently the outcome of corporate collaboration as a way to increase profits.

Some examples of oligopolies include the car industry, petrol retail, pharmaceutical industry, coffee shop retail, and airlines.

So, as discussed in the given case employee can take orders, sell flowers, make arrangements, and commit the store to large orders for weddings, banquets, and special events to make some profit.

Hence, The type of market is Oligopoly.

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The correct solution of division fractions is 18/4.

Multiplication is the opposite of division. If 3 groups of 4 add up to 12, then 12 divided into 3 groups of equal size results in 4 in each group. The primary objective of division is to count the number of equal groups that are created or the number of individuals in each group after a fair distribution.

When describing how much of anything is left over, a fraction is used. It represents the appropriate parts of the totality. A fraction is made up of two parts: the numerator and the denominator

Given that,

The division fraction is 6× 3/4

So, the fraction is 6/1×3/4

Therefore, the division fraction is  4×2/4 or 18/4

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Answer:

Step-by-step explanation:

Step 1: We must locate the slope, by using the slope formula, which is:

[tex]\frac{y2-y1}{x2-x1}[/tex]

When we plug it in we get:

[tex]\frac{-2-10}{9-3}[/tex]

Which simplifies to a -2

Step 2: We must plug in our values in the point-slope formula which is:

[tex]y-y1=m(x-x1)[/tex]

We can plug in (3,10) or (9,-2). It doesn't matter which one, we'll end up with the same answer. For this example, we'll use (3,10)

When we plug in our values we will get:

[tex]y-10=-2(x-3)[/tex]

Step 3: Now we just need to put our equation in slope-intercept form

[tex]y-10=-2(x-3)[/tex]

[tex]y-10=-2x+6\\y=-2x+16[/tex]

Therefore, our answer is [tex]y=-2x+16[/tex]

Hope this helps!!!

the balance in the account at the 10th day will be equal to - $ 57.5.

Late fee for 1 day = $ 5.75

Number of days = 10

We will calculate the late fees for 10 days by using the operation of multiplication.

So, late fee will be:

Late fees = 10 × $ 5.75

Late fees = $ 57.5

Balance in the account at the 10th day = 0 - Late fees

Balance in the account at the 10th day = 0 - $ 57.5

Balance in the account at the 10th day = - $ 57.5

Therefore, the balance in the account at the 10th day will be equal to - $ 57.5.

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