Can u help me figure this out

Answer:  20

Step-by-step explanation:

Answer:

Therefore (x,y)=(3,7)

Step-by-step explanation:

put the second equation into the first

x+4=3x-2

x-3x=-2-4

-2x=-6

x=3

plug x=3 into the second equation

y=3+4=7

Answer:

(2, 2) or (2, 3)

Step-by-step explanation:

two of the same number in x place means it is not a function. elimination on of these will make it a function.

Answer:

P = a + b + c

Step-by-step explanation:

A triangle has 3 sides. Perimeter is the measurement of the length around a shape. If you add sides A, B, and C, you will get the perimeter. You can also find a missing side by subtracting two known sides of the triangle if you know the perimeter.

Answer:

Domain:  0  ≤  x ≤ 25

Range:  0 ≤ y ≤ 50 where y = f(x)

Step-by-step explanation:

Domain is the set of all x values. Here x is the number of minutes spent painting and we can see its minimum value is y=0, maximum value is y=25 os domain of function is 0  ≤  x ≤ 25

Range of a function is the set of values of the function ie the outputs produced the function.

Let y = f(x) Then the y values range from minimum of y = 0 to maximum of y = 50. So range is 0 ≤ y ≤ 50 which is 0 ≤ y ≤ 50

Answer:

No solution, or empty set.

Step-by-step explanation:

If you solve this for p you will get 4 = 5, which is false.  Therefore there is no solution to this equation.

Time taken by 3 boys to clean a house is 8 hours.

What is Division method?

Division method is used to distributing a group of things into equal parts.

Now, Time taken by 4 teenagers to clean a house = 6 hours

So, Time taken by 1 boy to clean a house = 4 * 6 = 24 hours

Hence, Time taken by 3 boys to clean a house = 24 ÷ 3

                                                                         = 8 hours.

Therefore, Time taken by 3 boys to clean a house is 8 hours.

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Answer: 8 hours

Step-by-step explanation:

I also do rsm

Answer:

[tex]x = 2[/tex]

Step-by-step explanation:

Using the pythagorean theorem in the right triangle:

[tex]1^2 + 2^2 = c^2\\1 + 4 = c^2\\c = \sqrt5[/tex]

Using the pythagorean theorem in the left triangle:

[tex]x^2 + (\sqrt5)^2 = 3^2\\x^2 + 5 = 9\\x^2 = 4\\x = 2[/tex]

Answer:

2

Step-by-step explanation:

6(6) ÷ ( 2 x 9)

= 36 ÷ 18

=2

Tip:

Use BODMAS whenever order of operations question is there

Bracket

Orders (power, roots, indices)

Division

Multiplication

Addition

Subtraction

Answer:

x=4

Step-by-step explanation:

=5x-50=30-15x.

=20x=80.

x=4

The mass of the triangle from the hanger diagram is found as 5 grams.

For the given question;

Let the mass of each triangle be 'T'.

The mass of each circle be 'C'.

The mass of circle is 6 grams; C = 6 grams.

Let the mass of each square be 'S'.

The mass of each square is given as 3 grams; S = 3 grams.

As, the hanger is in equilibrium.

Mass of the left side = mass of the right side;

Put the values;

2T + 6S + 3C = 2C + 3S + 5T

Simplify the equation;

6S + 3C - 2C - 3S  = 5T - 2T

3S + C = 3T

Or

3T = 3S + C

Put the values

3T = 3×3 + 6

3T = 15

T = 5

Thus, the mass of each triangle is 5 grams.

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Greetings from Brasil...

Observing the attached figure we conclude that we have a square of side 4 and 4 triangles of base 4 and height 6. With this information we can conclude that:

Looking at the attached figure, we conclude that we have a square of side 4 and 4 triangles of base 4 and height 6. Let At be the area of the triangle and As be the area of the square. With this information we can conclude that:

Atotal = 4At + As

Atotal = 4(4.6/2) + 4²

Check the picture below.

The simplest form of the expression [tex](\frac{x^{\frac{1}{3} }}{y^{\frac{-3}{3} }} )^{9}[/tex] is yx³.

The simplest form of a fraction is one with a reasonably prime denominator and numerator. It indicates that, except for 1, there is no common factor between the fraction's numerator (upper portion or top) and denominator (lower part or bottom).

A fraction is a number that has been expressed as a quotient by dividing the numerator by the denominator. Both are integers in a simple fraction. In a complex fraction, a fraction can be found in either the numerator or the denominator.

An expression is made up of a number, a variable, or a combination of a number, a variable, and operation symbols. Two expressions joined by an equal sign form an equation.

Consider the expression,

[tex](\frac{x^{\frac{1}{3} }}{y^{\frac{-3}{3} }} )^{9}[/tex]

[tex](\frac{x^{\frac{1}{3} }}{y^{\frac{-3}{3} }} )^{9}=\frac{x^{\frac{1}{3} }}{y^{-1}}[/tex]

We know, x⁻¹ = 1/x

[tex](\frac{x^{\frac{1}{3} }}{y^{\frac{-3}{3} }} )^{9}=(yx^{\frac{1}{3} })^{9}[/tex]

[tex](\frac{x^{\frac{1}{3} }}{y^{\frac{-3}{3} }} )^{9}=(y^{9})(x^{\frac{1}{3}\times 9})[/tex]

[tex](\frac{x^{\frac{1}{3} }}{y^{\frac{-3}{3} }} )^{9}=(yx^{3})[/tex]

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The least integer greater than each number for log₃38 = 4

All whole numbers and negative numbers are considered integers. This means that if we combine negative numbers with whole numbers, a collection of integers results.

Let y = log₃38

We know, logₐ x = y, only if  [tex]a^{y}[/tex]= x

Therefore, [tex]3^{y}[/tex] = 38

So, we must find an integer y such that [tex]3^{y}[/tex] = 38

[tex]3^{y}[/tex] = 38

(As, 3³ = 27; 3⁴ = 81)

(Since, 3³ = 27 and 3⁴ = 81, the answer will be 3⁴ as 3⁴ > log₃38)

In this case, y = 4 will be the least integer greater than each number to satisfy this equation.

Therefore, the ultimate answer to the equation is log₃38 = 4

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Answer:

A =3960 as the surface area. B=309 books.

Step-by-step explanation:

SA=

[tex]2\pirh + \pir \times r[/tex]

so 2*22/7*7*90+22/7*7*7.

=

[tex]3960cm {}^{2} [/tex]

B.get the volume of the box - volume of the book

Answer: The answers are ll and lll.

Answer:

[tex]\begin{aligned} \textsf{a)} \quad & \textsf{Position function}: \quad s(t) = -16t^2+1362 \\ & \textsf{Velocity function}: \quad v(t) = -32t\end{aligned}[/tex]

[tex]\textsf{b)} \quad \overline{v}=-48\:\: \sf ft/s[/tex]

[tex]\begin{aligned}\textsf{c)} \quad v(1) & = -32\:\: \sf ft/s\\ v(2) & = -64\:\: \sf ft/s\end{aligned}[/tex]

[tex]\textsf{d)} \quad t = 9.226\:\: \sf s \:\: (3\: d.p.)[/tex]

[tex]\textsf{e)} \quad v = -292.242\:\: \sf ft/s \:\: (3\: d.p.)[/tex]

Step-by-step explanation:

Given:

[tex]s(t)=-16t^2+v_0t+s_0[/tex]

If v₀ is the initial velocity, and s₀ is the initial position:

[tex]\implies v_0=0[/tex]

[tex]\implies s_0=1362[/tex]

Therefore:

[tex]\begin{aligned}\textsf{Position function}: \quad s(t) & =-16t^2+0+1362\\ \implies s(t) & = -16t^2+1362 \end{aligned}[/tex]

[tex]\begin{aligned}\textsf{Velocity function}: \quad v(t)&=s\:'(t)\\ \implies v(t) &=-32t\end{aligned}[/tex]

Average velocity is the change in displacement divided by the change in time:

[tex]\overline{v}=\dfrac{s(t_2)-s(t_1)}{t_2-t_1}[/tex]

Given interval: 1 ≤ t ≤ 2

[tex]\implies t_1=1[/tex]

[tex]\implies t_2=2[/tex]

Find the values of s(t) at t = 1 and t = 2:

[tex]\implies s(1)=-16(1)^2+1362=1346[/tex]

[tex]\implies s(2)=-16(2)^2+1362=1298[/tex]

Substitute the values into the formula:

[tex]\overline{v}=\dfrac{s(2)-s(1)}{2-1}=\dfrac{1298-1346}{2-1}=-48\:\: \sf ft/s[/tex]

To find the velocity at t = 1 and t = 2, substitute these values into the velocity function found in part (a):

[tex]\implies v(1)=-32(1)=-32\:\: \sf ft/s[/tex]

[tex]\implies v(2)=-32(2)=-64\:\: \sf ft/s[/tex]

The time required for the coin to reach ground level is when s(t) = 0:

[tex]\begin{aligned}s(t) & = 0\\-16t^2+1362 & = 0\\16t^2 & = 1362\\t^2 & = 85.125\\t & = \sqrt{85.125}\\t & = 9.226\: \sf s\:\:(3\:d.p.)\end{aligned}[/tex]

To find the velocity of the coin at impact with the ground, substitute the found value of t from part (d) into the equation for velocity found in part (a):

[tex]\begin{aligned}v(t) & = -32t\\\implies v(\sqrt{85.125}) & = -32(\sqrt{85.125})\\ v & =-295.242\:\: \sf ft/s\:\:(3\:d.p.)\end{aligned}[/tex]

Note: I have used the non-rounded value of t from part (d) for accuracy.

The line of best fit of a data set will be a data point is 1.3 units above the line of best fit. Option A is correct.

The line of the greatest fit is a mathematical concept that links points scattered throughout a graph.

It's a sort of linear regression that makes use of scatter data to determine the best approach to characterize the relationship between the dots.

The line of best fit of a data set will be a data point is 1.3 units above the line of best fit.

Hence, option A is correct.

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Answer:

A

Step-by-step explanation:

Answer:

316 km

Step-by-step explanation:

multiply 79 x 4

Answer: 1040 sequences

Step-by-step explanation:

a die has 6 faces, 6x6x6x6 = 1296 possible sequences in whole
you have to get rid of the sequences that don't work, 4x4x4x4 = 256 (these will fail because you need at least one number that is bigger than 4)

1296 (whole)-256 (failed) = 1040 sequences that could work

Answer:

this is not an answer please help me how to ask another question in brainly

Answer:

X=7

Step-by-step explanation:

use concept of similarity proportion between big and small triangle enclosed into it

The bigger measurement is 2 mm and the smaller measurement is

2 μm.

Given, the measurements  are :

2 μm

we know that to convert from micro meter to meter, we use:

1 μm = 0.01 meter.

2 μm = 2 × 0.01 m

2 μm = 0.02 m

2 μm = 2/100

2 μm = 2 × 10⁻² m

for 2 nm

we know that to convert from nano meter to meter, we use:

1 nm = 10⁻⁹ meters.

2 nm = 2 × 10⁻⁹ meters.

for 2 mm

we know that to convert from milli meter to meter, we use:

1 mm = 0.001 meters.

2 mm = 2 × 0.001 m

2 mm = 0.002 m

2 mm = 2/1000 m

2 mm = 2 × 10⁻³ m

therefore , 2 × 10⁻² m > 2 × 10⁻³ m > 2 × 10⁻⁹ m

we can notice that millimeter is the greatest and nanometer is the smallest.

Hence we get the greater and smaller measurements.

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Jacob is playing miniature golf, then the ball is can not reach the hole in one shot, so Jacob is correct.

Jacob is playing miniature golf.

He states that he cannot hit the ball from the start.

Bounce it off the back wall once

And reach the hole in one shot.

So, we can write,

The ball is need to bounce off the back wall once.

The ball is can not reach the hole in one shot.

Jacob is correct.

It is not possible to hit the ball from the start,

Bounce it off the back wall once,

And reach the hole in one shot.

Therefore, Jacob is playing miniature golf, Then the Jacob is correct.

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