Consider function h.
h(x) = 2x-6/x+3
Which statements are true or false about the graph of function h?
The graph crosses the y-axis at (0,3).
The graph crosses the x-axis at (-2,0)
The graph has a vertical asymptote at r = -3.
The graph has a hole at (3,0).
The graph has a horizontal asymptote at y = 2
The domain of the function does not include the values x= -3 and x= 3.

Answer:

a

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

I took the test and got 100%.

Answer:

150

Step-by-step explanation:

The question is unclear. Do they want an angle that is under 180 (to your left) or over 180 (to your right)? I'm guessing that it is just under 180.

Each hour on a clock takes up 30 degrees. Each 5 minutes hand sweep out out 5/60 * 360 = 30 degrees as well. This angle looks like it is 5 minutes to seven if it was on a clock.

So the large angle from 12 oclock would sweep out 210 degrees and that would mean that the left angle would be 150. But the time is not quite 7 o,clock.

My guess would be 150. Remember, this is an estimate. You can't use a protractor on the question.

Answer:

x = -30

Step-by-step explanation:

[tex]0.7x+0.6x=1x-9\\=>1.3x=1x-9\\=>1.3x-1x=9\\=>0.3x=-9\\=>\frac{3}{10}x =-9\\=>x=\frac{-9*10}{3} =-30[/tex]

Answer:

[tex]\frac{7}{3}-\frac{2}{3}+\sqrt{3}-3\sqrt{3}=\frac{5}{3}-2\sqrt{3}[/tex]    

Step-by-step explanation:

Given the expression

[tex]\frac{7}{3}\:-\:\frac{2}{3}\:+\:v^3\:-\:3v^3[/tex]

solving the expression

[tex]\frac{7}{3}\:-\:\frac{2}{3}\:+\:\sqrt{3}-3\sqrt{3}[/tex]

combine the fractions i.e [tex]\frac{7}{3}-\frac{2}{3}=\frac{5}{3}[/tex]

[tex]\frac{7}{3}\:-\:\frac{2}{3}\:+\:\sqrt{3}-3\sqrt{3}=\frac{5}{3}+\sqrt{3}-3\sqrt{3}[/tex]

add similar elements  i.e [tex]\sqrt{3}-3\sqrt{3}=-2\sqrt{3}[/tex]

                                 [tex]=\frac{5}{3}-2\sqrt{3}[/tex]      

Thus,

[tex]\frac{7}{3}-\frac{2}{3}+\sqrt{3}-3\sqrt{3}=\frac{5}{3}-2\sqrt{3}[/tex]                        

The value of the logarithmic expression log(10³ x) is 3 + log(x).

The opposite of exponential functions is logarithmic functions. The exponential function y = aˣ has the inverse, [tex]x=a^{y}[/tex]. The exponential equation [tex]x=a^{y}[/tex] is defined as being identical to the logarithmic function y = logₐ x.

The properties of logarithm are:

Product rule: logₐ (mn) = logₐ m + logₐ n

Quotient rule: logₐ (m/n) = logₐ m – logₐ n

Power rule: logₐ (mn) = n( logₐ m )

Consider the logarithmic expression,

a = log ( 10³ x )

Using the property of logarithm:

logₐ ( mn ) = logₐ m + logₐ n

Then,

a = log( 10³ x )

a = log( 10³ × x)

a = log( 10³ ) + log( x )

By using the property of logarithm:

logₐ mⁿ = n(  logₐ m )

So,

a = 3( log 10 ) + log( x )

a = 3 + log ( x )

Therefore, log( 10³ x ) = 3 + log ( x ).

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Answer:

D

Step-by-step explanation:

The Triangle Sum theorem states the angles of all triangles will add up to 180.

70 + 50 + 70 = 190. Therefore, this cannot be a triangle.

Answer

The slope-intercept form of the equation of the line with a slope of 1/4 and y-intercept at the origin:

[tex]y=\frac{1}{4}x[/tex]

Step-by-step explanation:

Given

We know that the slope-intercept form of the line equation is

[tex]y=mx+b[/tex]

where m is the slope and b is the y-intercept.

substituting the values m=1/4 and the y-intercept b=0 to determine the equation in slope-intercept form

[tex]y=mx+b[/tex]

[tex]y=\frac{1}{4}x+0[/tex]

[tex]y=\frac{1}{4}x[/tex]

Thus, the slope-intercept form of the equation of the line with a slope of 1/4 and y-intercept at the origin:

[tex]y=\frac{1}{4}x[/tex]

Answer:

I cant answer, but I can help, divide 100 by 16, than multiply what you get from that with 24, it'll look like this:

(100÷16)x24=A

The solution to the equation given as 4(3x + 4) = 4x + 8 is x =-1

Expressions are mathematical statements that are represented by variables, coefficients and operators

The equation is given as

4(3x + 4) = 4x + 8

Open the bracket in the above equation

So, we have

12x + 16 = 4x + 8

Collect the like terms in the above equation

12x - 4x = 8 - 16

Evaluate the like terms in the above equation

8x = -8

Divide both sides by 8 in the above equation

x =-1

Hence, the solution to the equation given as 4(3x + 4) = 4x + 8 is x =-1

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where are the answer choices

Answer: = a^2 + 2ab + 2(ac+ b^2 + 2bc)

Step-by-step explanation:

^starigjt line equation (SLE)^

how to find slope of line (m)

=y2 - y1/x2 - x1

7. there, (16,2) occupies the x1 (16) and y1 (2) positions.

and, (32,4) occupies the x2 (32) and y2 (4) positions.

ok, enter:

m = y2 - y1/ x2 - x1

=4 - 2 / 32 - 16

=2/16

8. there, (-2,17) occupies the x1 (-2) and y1 (17) positions.

and, (-1,5) occupies the x2 (-1) and y2 (5) positions.

ok, enter:

m= y2 - y1/ x2 - x1

=5 - 17/ -1 - (-2)

=5 - 17 / -1 + 2

= -12 / 1

Answer:

you can calculate it like two rectangle volume

Answer: 48

Step-by-step explanation:

yes

Answer:

hakdog keep it up po11828282882827272++--yyyxxxxxx

Answer:

trapezoid

Step-by-step explanation:

Answer:

B.(0,-1)

Step-by-step explanation:

Answer:

B.(0,-1)

Step-by-step explanation:

i just got it right

Answer:

The answer would be 2/3

Step-by-step explanation:

There are 36 total problems and 24 division problems.

So take 24 over 36 and simplify and you get 2/3

Answer: 550t + 150c ≥ 8500

Step-by-step explanation: the store makes 550 for each table sold, so for t tables, the store will make 550t dollars. The store makes 150 for each chair sold, so for c chairs, the store will make 150c dollars. Therefore, the total revenue 550t + 150c must be greater than or equal to 8500

The correct option is B) 5 minutes.

The width of each class /(class width) is 5 minutes.

The term "class interval" refers to the numerical width of a class in such a frequency distribution.

Some key features regarding the class width/class interval are-

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The complete question is -

The following are the duration in minutes of a sample of long-distance phone calls made within the continental United States reported by one long-distance carrier.

RelativeTime (in Minutes)/

Frequency

0 but less than 5/0.37

5 but less than 10/0.22

10 but less than 15/0.15

15 but less than 20/0.10

20 but less than 25/0.07

25 but less than 30/0.07

30 or more/0.02

What is the width of each class?

A) 1 minute

B) 5 minutes

c) 2%

d) 100%

Answer:

The solution of this system of linear equations is [tex](x,y) = (-3,-2)[/tex].

Step-by-step explanation:

Let be the following system of linear equations:

[tex]2\cdot x - 7\cdot y = 8[/tex] (1)

[tex]-3\cdot x + 2\cdot y = 5[/tex] (2)

From (1) we clear [tex]y[/tex]:

[tex]2\cdot x -8 = 7\cdot y[/tex]

[tex]y = \frac{2\cdot x - 8}{7}[/tex]

And we apply this variable in (2):

[tex]-3\cdot x+2\cdot \left(\frac{2\cdot x -8}{7} \right)= 5[/tex]

[tex]-3\cdot x +\frac{4}{7} \cdot x -\frac{16}{7} = 5[/tex]

[tex]-\frac{17}{7}\cdot x = \frac{51}{7}[/tex]

[tex]x = -\frac{51}{17}[/tex]

[tex]x = -3[/tex]

And the value of [tex]y[/tex] is:

[tex]y = \frac{2\cdot (-3)-8}{7}[/tex]

[tex]y = -\frac{14}{7}[/tex]

[tex]y = -2[/tex]

The solution of this system of linear equations is [tex](x,y) = (-3,-2)[/tex].

Answer:

[tex]y\ge \:-1+x,\:y<\frac{4-x}{2}\quad :\quad \begin{bmatrix}y\ge \:-1+x\\ y<\frac{4-x}{2}\end{bmatrix}\quad \mathrm{Unbounded}[/tex]

The graph is attached below.

Step-by-step explanation:

Given the system of inequalities.

[tex]\begin{bmatrix}x-y\le \:1\\ x+2y<4\end{bmatrix}[/tex]

Isolate y for [tex]x-y\le \:1[/tex]

[tex]x-y\le \:1[/tex]

subtract x from both sides

[tex]x-y-x\le \:1-x[/tex]

simplify

[tex]-y\le \:1-x[/tex]

Multiply both sides by -1 (reverse the inequality)

[tex]\left(-y\right)\left(-1\right)\ge \:1\cdot \left(-1\right)-x\left(-1\right)[/tex]

simplify

[tex]y\ge \:-1+x[/tex]

now solving

[tex]x+2y < 4[/tex]

isolate y for [tex]x+2y < 4[/tex]

[tex]x+2y < 4[/tex]

subtract x from both sides

[tex]x+2y-x<4-x[/tex]

simplify

[tex]2y<4-x[/tex]

Divide both sides by 2

[tex]\frac{2y}{2}<\frac{4}{2}-\frac{x}{2}[/tex]

Simplify

[tex]y<\frac{4-x}{2}[/tex]

Graphing Method:

1. Graph each inequality separately

2. Choose a test point to determine which side of the line needs to be shaded

3. The solution to the system will be the area where the shadings from each inequality overlap one another.

Thus,

[tex]y\ge \:-1+x,\:y<\frac{4-x}{2}\quad :\quad \begin{bmatrix}y\ge \:-1+x\\ y<\frac{4-x}{2}\end{bmatrix}\quad \mathrm{Unbounded}[/tex]

The graph is attached below.

Answer:

first one = greater than or equal to 1 and less than 10

Step-by-step explanation:

it's a method of writing numbers as the product of two factors where the first factor is a number whose absolute value is greater than or equal to 1 but less than 10 while the second factor is a power of 10

Answer:

Step-by-step explanation:

100/30=3  1/3hrs to go

3  1/3*3/4=  

10/3*3/4=30

30/12=2  1/5hrs return

100/2  1/2=

100/(5/2)=

100*2/5=200/5=40

100/2.5=40mph return

Answer:

$7.17

Step-by-step explanation: hope it helped

Answer:

No

Step-by-step explanation:

Any number multiplied by 0 is 0

4 × 0 = 0 , n × 0 = 0