The number line which represents the solution of the given absolute value inequality is |2x – 5| ≥ 3 is graph B : Points are at 1 and 4. Everything to the left of 1 and to the right of 4 is shaded.
What are absolute value inequalities?An absolute value inequality is an equation of the form |p| ≥ a or |p| ≤ a
where p and are mathematical expressions.
Absolute rule for solving inequality: if |p| ≥ a then solution is p ≤ (-a ) or
p ≥ a
Now for the given inequality |2x – 5| ≥ 3 , applying above absolute rule we get :
(2x-5) ≤ -3 and (2x-5) ≥ 3
For 2x-5 ≤ -3
Adding 5 on sides we get: 2x-5+5 ≤-3+5
2x ≤ 2
On dividing both sides by 2: (2x/2) ≤ (2/2)
x ≤ 1
which means that x are all number less than or equal to 1
On the number line, everything to left of 1 and point 1 on the number line
Now, For 2x-5 ≥ 3
Adding 5 on sides we get: 2x-5+5 ≥ 3+5
2x ≥ 8
On dividing both sides by 2: (2x/2) ≤ (8/2)
x ≥ 4
which means that x are all numbers greater than or equal to 4
On the number line, everything to right of 4 and point 4 on the number line
Therefore, Graph B is the right answer which says that points are at 1 and 4 ,everything to the left of 1 and to the right of 4 is shaded.
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Last month the online price was $250. This month the online price is $330. What is the increase for the price
Answer:
Step-by-step explanation:
330-250 =80
angelina determined that her father’s age is 4 less than 3 times her age. If x represents angelina’s age, write an expression for her father’s age
Answer:
4 - 3x
Step-by-step explanation:
please mark me as brainliest
Answer:
3x-4= Y
Y= her dad's age.
(a) Determine the net change between the indicated points on the graph.
b) determine the average rate of change between the indicated points on the graph.
The function which passes from (1,4) and (5,1) is y= -7/20x² + 27/20x +3
and the net change between the indicated points is -3, whereas the average rate change is -3/4.
Given, from the graph, the function passes (1,4) and (5,1).
Let y = ax² + bx + 3
from point 1.
the equation is: a + b+ 3 = 4 eq(1)
from point 2.
the equation is 25a + 5b + 3 = 1 eq(2)
solving equation 1 and equation 2.
we get, 20b = 99-72
20b = 27
b = 27/20
substitute b value in equation 1.
a + 27/20 + 3 = 4
20a = -7
a = -7/20
hence y = -7/20x² + 27/20x +3
(a) net change = change in y coordinates.
net change = y₂ - y₁
net change = 1 - 4
= -3
(b) Average rate = change in y coordinates / change in x coordinates
= 1 - 4/5-1
= -3/4
hence we get the required answers.
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what is the equation for the line with slope (rate of change) 2/3 and y-intercept 9
Answer:
y = 2/3x + 9
Step-by-step explanation:
The equation of a line is defined as y = mx + b
with m being the slope, and b being he intercept.
So to figure out the equation for the line with a slope of 2/3 and an intercept of 9, we can just plug those values into our line equation!
So take y = (slope)*x + *(intercept)
and plug your values in and you get...
y = 2/3 * x + 9
Answer: the answers for the quiz are
1. What is the slope (rate of change) of the line in the graph show below? Answer is A. -2
2. Find the slope (rate of change) of a line that passes through (-2, -3) and (1, 1). Answer is D. 4/3
3. constant of variation of -4y=8x answer is B. -2
4 the value of y when x=10 answer is B. 30
5. the equation for the line with slope 2/3 and y-intercept 9 answer is C. y=2/3x+9
6 is the equation in slope intercept form for the line that passes through the points (1, -3) and (3, 1) answer is D. y=2x-5
Step-by-step explanation:
On a spring day the temperature outside is 68 degrees F. What is this in Celsius? (Write your answer
as a whole number.)
lim
T-44
√x+5-7
x - 44
[tex]\displaystyle \lim_{x\to 44}~\cfrac{\sqrt{x+5}-7}{x-44}\hspace{5em}\stackrel{\textit{L'Hopital's rule}}{\lim_{x\to 44}~\cfrac{ ~~ \frac{d}{dx}[\sqrt{x+5}-7] ~~ }{\frac{d}{dx}[x-44]}} \\\\[-0.35em] ~\dotfill[/tex]
[tex]\cfrac{d}{dx}[\sqrt{x+5}-7]\implies \cfrac{1}{2}(x+5)^{-\frac{1}{2}}(1)\implies \cfrac{1}{2\sqrt{x+5}} \\\\\\ \cfrac{d}{dx}[x-44]\implies 1 \\\\[-0.35em] ~\dotfill\\\\ \displaystyle \lim_{x\to 44}~\cfrac{\sqrt{x+5}-7}{x-44}\implies \lim_{x\to 44}~\cfrac{ ~~ \frac{1}{2\sqrt{x+5}} ~~ }{1}\implies \lim_{x\to 44}~\cfrac{1}{2\sqrt{x+5}}\implies \cfrac{1}{2\sqrt{44+5}} \\\\\\ \cfrac{1}{2\sqrt{49}}\implies \cfrac{1}{2(7)}\implies \cfrac{1}{14}[/tex]
√80 in the number line
√80 on the number line would be marked at (8.94, 0) on the number line.
Hope this graph helps!
Find the first order differential eqn of y
dy/dx = y(x² + 1)
Answer:
[tex]\large\text{$y=ke^{\frac{1}{3}x^3+x}$}[/tex]
Step-by-step explanation:
Given differential equation:
[tex]\large\text{$\dfrac{\text{d}y}{\text{d}x}=y(x^2+1)$}[/tex]
Rearrange the equation so that all the terms containing y are on the left side, and all the terms containing x are on the right side:
[tex]\large\text{$\implies \dfrac{1}{y}\;\text{d}y=(x^2+1)\;\text{d}x$}[/tex]
Integrate both sides, remembering to add the constant of integration (C):
[tex]\large\begin{aligned}\implies \displaystyle \int\dfrac{1}{y}\;\text{d}y & =\int(x^2+1)\;\text{d}x\\\ln y & = \dfrac{1}{3}x^3+x+\text{C}\end{aligned}[/tex]
Rewrite C as ln k:
[tex]\large\text{$\implies \ln y = \dfrac{1}{3}x^3+x+\ln k$}[/tex]
Solve for y, applying:
[tex]\textsf{Log rule}: \quad e^{\ln a}=a[/tex][tex]\textsf{Exponent rule}: \quad \:a^{b+c}=a^ba^c[/tex][tex]\large\text{$ \implies e^{\ln y} =e^{\frac{1}{3}x^3+x+\ln k}$}[/tex]
[tex]\large\text{$ \implies y=e^{\ln k} \cdot e^{\frac{1}{3}x^3+x}$}[/tex]
[tex]\large\text{$\implies y=ke^{\frac{1}{3}x^3+x}$}[/tex]
Integration rules
[tex]\boxed{\begin{minipage}{3.6 cm}\underline{Integrating $\frac{1}{x}$}\\\\$\displaystyle \int \dfrac{1}{x}\:\text{d}x=\ln |x|+\text{C}$\end{minipage}}[/tex]
[tex]\boxed{\begin{minipage}{3.6 cm}\underline{Integrating $x^n$}\\\\$\displaystyle \int x^n\:\text{d}x=\dfrac{x^{n+1}}{n+1}+\text{C}$\end{minipage}}[/tex]
[tex]\boxed{\begin{minipage}{5.1 cm}\underline{Integrating a constant}\\\\$\displaystyle \int n\:\text{d}x=nx+\text{C}$\\\\(where $n$ is any constant value) \end{minipage}}[/tex]
Answer:
[tex]{ \tt{ \frac{dy}{dx} = y( {x}^{2} + 1) }} \\ [/tex]
- Simplify by collecting each term according to its corresponding d
[tex]{ \tt{ \frac{dy}{y} = ( {x}^{2} + 1) \: dx}} \\ [/tex]
- Integrate both sides;
[tex]{ \tt{ \int \frac{1}{y} \: dy = \int ( {x}^{2} + 1) \: dx }} \\ \\ { \tt{ ln(y) = \frac{1}{3} {x}^{3} + x + c }}[/tex]
- To make y the subject, you must remove the natural log;
[tex]{ \tt{ log_{e}(y) = \frac{1}{3} {x}^{3} + x + c }} \\ \\ { \tt{y = {e}^{( \frac{1}{3} {x}^{3} + x + c) } }} \\ [/tex]
slove please and thanks
60 divided by the sum of 5 and 2
Answer: 8 Remainder 4
Step-by-step explanation: Sum is the answer to addition so 5 plus 2 is 7 and 60 divided by 7 is 8 with a Remainder of 4
How much of an 80% salt solution must
be mixed with 50 gallons of a 13% salt
solution to obtain a solution that is
70% salt?
By means of weighted averages, we conclude that an amount of 285 gallons are needed to prepare a 70 % salt solution.
What quantities of two solutions with different concentrations are needed to obtain a new solution with a expected concentration?
In this problem we find two salt solutions with distinct concentrations, one with 80 % and another with 13 %, the latter in a quantity of 50 gallons. The required quantity of 80 % salt solution is determined by using weighted averages:
(80 / 100) · x + (13 / 100) · 50 = (70 / 100) · (x + 50)
0.8 · x + 13 / 2 = 0.7 · x + 35
0.1 · x = 57 / 2
0.2 · x = 57
x = 285
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URGENT ! HELPPPP
Evaluate (f+2) (g+8), when f = 4 and g = 2
Evaluate 2Tu, when T = 5 and u = 9
Answer:
1) 60
2) 90
Step-by-step explanation:
Evaluate (f+2) (g+8), when f = 4 and g = 2
Solution
(f+2) (g+8)
Evaluate for f=4,g=2
(4+2)(2+8)
(4+2)(2+8)
=60
Evaluate 2Tu, when T = 5 and u = 9
Solution
2tu
Evaluate for t=5,u=9
(2)(5)(9)
(2)(5)(9)
=90
Answer:
Step-by-step explanation:
replace f and g for their values
(4+2)(2+8)
= 6*10
= 60
replace t and u for their values
2*5*9
= 10*9
= 90
Which of the functions below could have created this graph?
+
OA. F(x)=x2
OB. F(x)=-¹-4
O C. F(x)=x²+2x-2
OD. F(x)=3x³ +2x²
Answer:
only D is negative on the leading term
Step-by-step explanation:
even roots bounce at (0,0)
negative leading coefficient: initial graph descending to right, curve up
4 local extremes means remaining 5 degree of the function
F(x)=x-5 and g(x)=x2 - 1 find
The value of the given functions are:
(i) f + g = x² + x - 6
(ii) f - g = -x² + x - 4
(iii) f . g = x³ - 5x² - x + 5
(iv) f/g = ( x - 5)/(x +1)(x - 1)
(v) g(f(x)) = x² - 10x + 24
The two functions are given that
f(x) = x - 5
g(x) = x² - 1
We have to find
(i) f + g
f(x) + g(x) = ( x-5) + (x² - 1)
= x² + x -5 -1
= x² + x -6
(ii) f - g
f(x) - g(x) = (x-5)- (x² - 1)
= -x² + x -5 +1
= -x² + x -4
(iii) f . g
f(x) . g(x) = (x-5)(x²-1)
=x(x² - 1) -5(x² - 1)
= x³ - x - 5x² + 5
= x³ - 5x² - x + 5
(iv) f/g
f(x) / g(x) = (x-5) / ( x² - 1)
= (x - 5) / (x+1)(x-1)
(v) g(f(x)) = - 1 + ( -5 + x )²
= -1 + 25 + x² - 10x
= x² - 10x + 24
Therefore we get the value of the function, (i) f + g = x² + x - 6, (ii) f - g = -x² + x - 4,(iii) f . g = x³ - 5x² - x + 5, (iv)f/g = ( x - 5)/(x +1)(x - 1), (v) g(f(x)) = x² - 10x + 24.
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The complete question is:
F(x)=x-5 and g(x)=x2 - 1 find (i) f + g , (ii) f-g, (iii) f. g (iv) f/g (v) g(f(x)).
Express the inequality using interval notation.
161 6.)
Interval Notation:
-7 < x < -4
8
The inequality using interval notation are (-7, -4).
What is defined as the interval notation?An interval is represented on a number line using interval notation.
In those other sayings, it is a method of writing real number line subsets. An interval is made up of numbers that fall between two specific data set.For instance, the set of digits x satisfying 0 ≤ x ≤ 8 is an interval containing 0, 8, as well as all numbers between 0 and 8.Open intervals: The endpoints of a inequality are not included in this type of interval. This is written in open interval notation: (-3, 1).closed intervals: The endpoints of a inequality are included in this type of interval. This is written in closed interval notation as [-3,1].For the given expression;
-7 < x < -4
As, x > -7; x is not equal to -7.
x < -4; here also x is not equal to -4.
So, the is a condition of open interval where both vales are not taken.
Thus, the intervals are written as; (-7, -4).
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What is the slope of the line?
Answer:
Slope = (-7/4)
Step-by-step explanation:
Point 1: (-3, 4); Point 2: (1, -3)
(x₁, y₁) (x₂, y₂)
y₂ - y₁ -3 - 4 -7 -7
m = ----------- = ----------- = ----------- = ------
x₂ - x₁ 1 - (-3) 1 + 3 4
I hope this helps!
I need help with geometry
A car salesman sells cars with prices ranging from $5,000 to $45,000. The histogram shows the distribution of the numbers of cars he expects to sell over the next 10 years.
The salesman has observed that many students are looking for cars that cost less than $5,000. If he decides to also deal in cars that cost less than $5,000 and projects selling 200 of them over the next 10 years, how will the distribution be affected?
Answer:
The mean will move to the left as more affordable vehicles are introduced.
Step-by-step explanation:
It is given that a car salesman sells cars with prices ranging from $5,000 to $45,000. The histogram shows the distribution of the numbers of cars he expects to sell over the next 10 years.
We need to find how will the distribution be affected if he decides to also deal in cars that cost less than $5,000 and projects selling 200 of them over the next 10 years.
Now, let us understand what is meant by mean;
What is the Mean ?
The mean of a set of data is its average value.
Further, It is given that the car salesman sells cars with prices ranging from $5,000 to $45,000.
Additionally, the salesperson has noticed that a lot of students are searching for vehicles around $5,000.
If he chooses to sell vehicles as well and anticipates selling 200 of them over the following ten years,
The histogram will deviate from its mean if cards with values less than $5,000 are also included in the data set.
The mean will move to the left as more affordable vehicles are introduced.
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Question
Find the rate if a principal of $5,875 earned $1,645 interest in 4 years. Round to the nearest whole percent.
The yearly interest rate percentage is 7%
The rate of interest can be found dividing the interest and the product of the principal and time period which can be written as
R = I / PT
where R is the Rate of interest
I is the Interest
P is the Principal amount
T is the time period.
Given values are
P = $5,875
I = $1,675
T = 4 years
Then,
R = I/PT
= 1,645/(5,875 x 4)
= 1645 / 23500
= 0.07
The Yearly interest rate percentage is
=0.07 x 100
= 7%
Therefore, the yearly rate percentage is 7%
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what amount of a 60% acid solution must be mixed with a 35% solution to produce 600 mL of a 55% solution? Algebra
2400mL is the amount of 60%acid solution to mix.
Let the amount of acid be mixed be x.
From the question, we get an equation that,
60%x + 35% × 600/ x + 600 = 55%
(Here x ≠ -600, as the denominator can never be 0.)
60%× x + 35% ×600 = 55%(x + 600)
Now we have to find the value of x to know the amount of acid that is mixed in a solution.
0.60x + 0.35 × 600 = 0.55(x+600)
0.60x + 210 = 0.55 + 330
0.05x = 120
x = 120/0.05
= 2400
Therefore we get an amount of acid to be mixed is 2400mL.
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NO LINKS!!
Please help me with this graphs
Answer:
triangle: 18.81 unitsparallelogram: 17.21 unitsStep-by-step explanation:
You want the perimeter of each of the figures defined by the coordinates of their vertices. You are told to use the distance formula as necessary.
TriangleThe first attachment shows the graph of the triangle. The distance formula is needed only for the length of the diagonal segment:
d = √((x2 -x1)² +(y2 -y1)²)
d = √((3 -(-2))² +(-3 -3)²) = √(5² +(-6)²) = √61 ≈ 7.81
The lengths of the horizontal and vertical legs of the triangle are the difference of their x- and y-coordinates, respectively.
CB = 3 -(-2) = 5
CA = 3 -(-3) = 6
The perimeter is the sum of the side lengths:
P = CA +CB +AB = 6 +5 +7.81 = 18.81
The perimeter of the triangle is 18.81 units.
ParallelogramThe second attachment shows the graph of the parallelogram. As with the triangle, we only need to use the distance formula for the length of the diagonal side. Here is the length of ML.
d = √((4 -2)² +(1 -(-2))²) = √(2² +3²) = √13 ≈ 3.606
The length of the horizontal legs is the difference of their x-coordinates.
KL = 4 -(-1) = 5
Opposite sides are congruent, so the perimeter is double the length of two adjacent sides.
P = 2(3.606 +5) ≈ 17.21
The perimeter of the parallelogram is about 17.21 units.
Answer:
1. 18.81 units
2. 17.21 units
Step-by-step explanation:
[tex]\boxed{\begin{minipage}{7.3 cm}\underline{Distance between two points}\\\\$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$\\\\where $(x_1,y_1)$ and $(x_2,y_2)$ are the two points.\\\end{minipage}}[/tex]
Question 1Given vertices of ΔABC:
A = (-2, 3)B = (3, -3)C = (-2, -3)Plot the vertices on the given graph paper and join with line segments to create the triangle.
As points B and C share the same y-coordinate:
[tex]\implies BC = |x_B-x_C|=|3-(-2)|=5\:\: \sf units[/tex]
As points A and C share the same x-coordinate:
[tex]\implies AC = |y_A-y_C|=|3-(-3)|=6\:\: \sf units[/tex]
Use the distance formula to find the length AB:
[tex]\begin{aligned}AB & =\sqrt{(x_B-x_A)^2+(y_B-y_A)^2}\\& =\sqrt{(3-(-2))^2+(-3-3)^2}\\& =\sqrt{(5)^2+(-6)^2}\\& =\sqrt{25+36}\\& =\sqrt{61}\\\end{aligned}[/tex]
The perimeter of a two-dimensional shape is the distance all the way around the outside.
[tex]\begin{aligned}\textsf{Perimeter of $ABC$} & = AB + BC + AC\\& = \sqrt{61}+5+6\\& = 11+\sqrt{61}\\& = 18.81\:\: \sf units\:(nearest\:hundredth)\end{aligned}[/tex]
Question 2Given vertices of polygon KLMN:
K = (-1, 1)L = (4, 1)M = (2, -2)N = (-3, -2)Plot the vertices on the given graph paper and join with line segments to create the polygon.
As the y-coordinate of points K and L, and M and N are the same, KL and MN are parallel line segments.
As the difference between the x-coordinates of K and N, and L and M is 2 units, KN and LM are parallel line segments.
Therefore, the polygon is a parallelogram.
A parallelogram has two pairs of opposite sides that are equal in length.
Therefore, KL = NM and KN = LM.
As points K and L share the same y-coordinate:
[tex]\implies KL = |x_K-x_L|=|-1-4|=5\:\: \sf units[/tex]
Use the distance formula to find the length KN:
[tex]\begin{aligned}KN & =\sqrt{(x_N-x_K)^2+(y_N-y_K)^2}\\& =\sqrt{(-3-(-1))^2+(-2-1)^2}\\& =\sqrt{(-2)^2+(-3)^2}\\& =\sqrt{4+9}\\& =\sqrt{13}\\\end{aligned}[/tex]
The perimeter of a two-dimensional shape is the distance all the way around the outside.
[tex]\begin{aligned}\textsf{Perimeter of $KLMN$} & = 2\:KL + 2 \:KN\\& = 2 \cdot 5 + 2\cdot \sqrt{13}\\& =10 + 2\sqrt{13}\\& = 17.21\:\: \sf units\:(nearest\:hundredth)\end{aligned}[/tex]
I need help with this exercise on Simplifying Logarithms.
Evaluate the following showing steps. Round the answer to three significant digits.
e^(4x-2) when x = 2
Answer:
e^6 ≈ 403
Step-by-step explanation:
You want the value of e^(4x-2) when x = 2.
EvaluationPut 2 where x is in the expression and do the arithmetic.
e^(4·2 -2) = e^6 ≈ 403.429
The value of the expression is about 403.
6.139 rounded to the nearest hundredth?
Answer:
Step-by-step explanation: 6.140
Study these equations:
f(x) = 2x – 8
g(x) = –5x
What is h(x) = f(x)g(x)?
h(x) = 10x2 – 40x
h(x) = –10x2 + 40x
h(x) = –10x + 40
h(x) = 10x – 40
The equation of the composite function h(x) is h(x) = -10x^2 + 40x
How to determine the equation of the composite function?The functions are given as
f(x) = 2x – 8
g(x) = –5x
The equation of the composite function is given as
h(x) = f(x)g(x)
Substitute f(x) = 2x – 8 and g(x) = –5x in the equation h(x) = f(x)g(x)
So, we have
h(x) = (2x - 8) x (-5x)
Evaluate the product
h(x) = -10x^2 + 40x
Hence, the equation of the composite function h(x) is h(x) = -10x^2 + 40x
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Find the square root of 1000 000 base two
Answer: Here's the answer step by step
Step-by-step explanation: First, find the square root of 1000000 base to and leave your answer in base two
find the square root of 111 in base 2
simplify 342+134-233 in base 5
divide 100001 by 11 in base 2
convert 123.12 in base 3 to a number in base 10 and make sure you leave your answer in base 2
Last step: convert 3.875 in base 10 to a number in base 2
Choose the symbol that makes the statement true
A. >
B. <
C. =
PLEASE HELP THANK YOU :)))
Answer:
C. =
Step-by-step explanation:
This is because 18% is 18/100. You could find the answer one of two ways. Divide by two or multiply by 2.
Can someone please help me this is geometry
Answer:
Step-by-step explanation:
[tex]\displaystyle\\\boxed {M_{AB}=(\frac{x_A+x_B}{2},\frac{y_A+y_B}{2} ) }[/tex]
1) E(-5,-3) F(3,7) M(x,y)=?
[tex]\displaystyle\\M(x,y)=(\frac{-5+3}{2} ),\frac{-3+7}{2})\\\\ M(x,y)=(\frac{-2}{2},\frac{4}{2} )\\\\ M(x,y)=(-1,2)\\\\Thus, \ M(-1,2)[/tex]
2) L(-8,11) N(-3,12) M(x,y)=?
[tex]\displaystyle\\M(x,y)=(\frac{-8+(-3)}{2} ,\frac{11+12}{2} )\\\\M(x,y)=(\frac{-11}{2},\frac{23}{2})\\\\ M(x,y)= (-5.5,11.5)\\\\Thus, M(-5.5,11.5)[/tex]
3) A(-4,6) B(2,4) M(x,y)=?
[tex]\displaystyle\\M(x,y)=(\frac{-4+2}{2},\frac{6+4}{2})\\\\ M(x,y)=(\frac{-2}{2},\frac{10}{2})\\\\ M(x,y)=(-1,5)\\\\ Thus,\ M(-1,5)[/tex]
Need help ASAP!!
Samuel is taking a multiple choice test with a total of 100 points available. Each question is worth exactly 5 points. What would be Samuel's test score (out of 100) if he got 9 questions wrong? What would be his score if he got x questions wrong?
Samuel's test score if he got 9 questions wrong=55
Samuel's test score if he got x questions wrong=45
What is mean scale score?Mean score: A mean scale score is the average performance of a group of students on an assessment. Specifically, a mean scale score is calculated by adding all individual student scores and dividing by the number of total scores. It can also be referred to as an average.
let y equal the number of questions
let's find how many total questions are there,
100=5y
divide by the coefficient of y which in the case is 5
20=y
so we have total of 20 questions each are worth 5 points
now, Samuel got 9 questions wrong and if we know they are 20 total questions
20-9=11
so, we know Samuel got 11 questions correct
let's use an expression to figure out his score
let x be the number of questions
5x
substitute
5(11)=55
his score if he got x questions wrong
20-11=9
9(5)=45
Samuel's test score if he got 9 questions wrong=55
Samuel's test score if he got x questions wrong=45
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How do you break apart the factor 56 using place
values
Answer:
Step-by-step explanation:
go
I just want someone to check this, Im finding X and I finda forgot how to do this, so if someone can correct me and tell how to do it, that would be nice, 50 points btw
The value of x is 13
How to determine the valueFrom the diagram shown, we have that the line segments as;
NK = NM + ML + LK
Where;
NK = 23NM = x - 6ML = 9LK = 2x - 19Substitute the values into the equation
(x - 6) + 9 + 2x - 19 = 23
collect like terms
x + 2x -6 + 9 - 19 = 23
Add like terms
3x - 16 = 23
3x = 23 + 16
3x = 39
Divide both sides by 3
x = 39/ 3
x = 13
Thus, the value of x is 13
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