Consider these pictures in answering the question below.
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Which diagram might represent the initial vertical component of the velocity of a ball thrown upward at an angle?
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The wavelength of a 2.4 ghz sine wave is 0.5 inches.

In physical science, the frequency is the spatial time of an occasional wave the distance over which the wave's shape rehashes. Albeit X-beams have numerous advantageous applications, utilizing them requires alert since openness can cause visual deficiency, malignant growth and different wounds. Frequency and recurrence are conversely related so that more drawn out waves have lower frequencies, and more limited waves have higher frequencies. Frequency addresses the distance between two successive recurrence wave tops and is normally used to portray the electromagnetic range.

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The torque acting on the loop will be zero .

The diagram is given below.

From the diagram ,  vector of the loop and therefore the force field  are parallel to every different which suggests sin 180 ° whose worth is zero.

On putting the value of sin180 in equation (1) , we get

[tex]T=NIAB\times0\\T=0[/tex]

Torque acting on the loop will be zero .

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75km=75000m

35min=2100 seconds

Velocity=Displacement/Time

=75000/2100

=750/21

=35.71 m/s

The statements about the skateboarder's energy is true option C which is  if friction is present, mechanical energy will be conserved. the pe is the greatest at the bottom of the ramp.

Energy is the ability to perform a task or do work. Energy can be potential or kinetic energy. Potential energy is the energy posses by a body in a state of rest while kinetic energy is the energy in motion.

As the skateboarder travels  the ramp, potential energy turn to kinetic energy and if  friction is present some of the energy in the system is converted to heat energy.

Therefore, The statements about the skateboarder's energy is true option C which is  if friction is present, mechanical energy will be conserved. the pe is the greatest at the bottom of the ramp.

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The magnitude of Magnetic field is 37.7 x [tex]10^{-4}[/tex] Tesla.

We have Hall Probe to measure an unknown Magnetic field.

We have to determine the Magnitude of the unknown Magnetic field.

A  Hall probe is a device that can be used to measure magnetic fields. They work on the principle of Hall effect.

According to the question, we have -

I = 120 mA = 120 x 0.001 = 0.12 Ampere.

B = 0.08 Tesla

V(H) = 0.7 [tex]\mu[/tex]V = 7 x [tex]10^{-7}[/tex]

The formula relating the above quantities is -

V(H) =  [tex]A_{H} \frac{IB}{d}[/tex]

[tex]$\frac{d}{A_{H} } =\frac{IB}{V_{H} }= \frac{0.12 \times 0.08}{7\times 10^{-7} }[/tex] = 13.71 x [tex]10^{3}[/tex]

Now -

For → V = 0.33 [tex]\mu[/tex]V =  0.33 x [tex]10^{-7}[/tex]

[tex]B=\frac{Vd}{A_{H}I }[/tex] = [tex]13.71\times 10^{3} \times\frac{0.33\times 10^{-7} }{0.12}[/tex] = 37.7 x [tex]10^{-4}[/tex] Tesla

Hence, the magnitude of Magnetic field is 37.7 x [tex]10^{-4}[/tex] Tesla.

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The annual cost for electricity to power a lamppost for 7.00 h per day with a 100 W incandescent light bulb versus an energy efficient 25 W fluorescent bulb is $25.55 and $6.3875 respectively.

The Power is the amount of Energy produced per unit time.

The general formula for the annual cost can be written as:

[tex]Cost = P\cdot t\cdot d[/tex]

where. P is power, t is time in hours per day, and d is the total days.

Using the formula:

The cost of a 100 W incandescent light bulb:

[tex]Cost=(0.1)(7)(365)(0.10)=\$25.5[/tex]

Similarly,

The cost of a 25 W fluorescent light bulb:

[tex]Cost=(0.025)(7)(365)(0.10)=\$6.3875[/tex]

Hence, the annual cost is $25.55 and $6.3875 respectively.

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The kinetic energy of the muon is 4.08 MeV

Given that:

A pion (mπ = 273 me)

muon (mµ= 207me)

Neutrino (mv=0)

(Let’s assume that c =1, and that me= 0.511MeV)

Since the pion is at rest conversation of momentum dictates that the momenta of the muon and the neutrino be equal in magnitude,

P_μ=P_v      (1)

Since the pion is at rest its energy equals its mass, E_π=m_π. Since the neutrino is massless its energy equals its momentum E_v=P_v . By conservation of energy,

E_π=E_μ+E_v, so

E_μ=m_π-P_v     (2)

Substituting the right sides of (1) and (2) into the left side of the fundamental kinematic equation for the muon E_μ^2-P_μ^2=m_μ^2 yields

〖(m_π-P_v)〗^2-P_μ^2=m_μ^2

Solving for P_v gives (the magnitudes of) the momenta of the decay particles and the kinetic energy (equal to the total energy) of the massless neutrino,

P_v (〖=P〗_u=E_v )=((m_π^2-m_μ^2))/(2m_π )

P_v=(〖273〗^2-〖207〗^2)/(2× 273)=29.65 MeV  

The kinetic energy of the muon equals its total energy minus its mass which, using (2), is

〖(m〗_π-P_v)-m_μ=4.08 MeV

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The statement that best explains why the system looses energy is; the Collison of the molecules of hydrogen with the wall of the can carries off energy to the environment.

We know that energy is defined as the rate of doing work. Now the temperature of a gas is measure of the kinetic energy of the molecules of the body. In this case, the temperature of the hydrogen in the cannister has to do with how fast the molecules of the hydrogen are moving.

The higher the temperature, the faster the molecules of the hydrogen move. The lower the temperature, the slower the molecules of the hydrogen moves.

As such, the molecules collide with the walls of the canister, causing the canister molecules to vibrate and carry energy from the canister to the canister’s surroundings.

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B = μ₀i/2πr

i = 2πrB/μ₀

∵ 16.50 nano Tesla = 1.65×10⁻⁸ Tesla

∵8.10Km = 8100 m

i = 2(3.14)(8100)(1.65×10⁻⁸)/4×3.14×10⁻⁷

i = 668.25 A

So the current carried up or down the funnel of the tornado is 668.25 A.

A tornado is a fast spinning column of air that occasionally strikes the base of a cumulonimbus cloud as well as the Earth's surface.

A tornado is a narrow, violently rotating column of air that extends from the ground to a thunderstorm.

Tornadoes are difficult to notice since wind is invisible unless they build a condensation funnel of water droplets, dust, and debris.

Some tornadoes increase and become powerful or destructive. Strong tornadoes can last for twenty minutes or more and have winds of up to 200 miles per hour, whereas severe tornadoes can persist for more than an hour and have winds of 200 to 300 miles per hour!

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The acceleration of the proton that is  projected in the positive x direction into a region of a uniform electric field is  5.76×〖10〗^13 m/s^2

The product of the field's strength and the charge's strength yields the magnitude of the electric force acting on a charge traveling in a magnetic field region.

The electric force magnitude acting on the charge is expressed in the equation below.

F=|→E|×|q|

F=|-6.00×〖10〗^5 N/C|×||+1.602×〖10〗^(-19) C|

F=9.612×〖10〗^(-14) N

Newton's second law of motion states that the magnitude of a force is equal to the product of a proton's mass and its acceleration. Where the magnitude of the acceleration of the proton is ;

a=F/m  

Where  F is the force and m is the mass;

Inserting the values into the equation,

a=(9.612×〖10〗^(-14) N)/(1.67×〖10〗^(-27) kg)

a=5.76×〖10〗^13 m/s^2

Therefore, the acceleration of proton is 5.76×〖10〗^13 m/s^2 #SPJ4

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Answer:

well....to every direction the body moves towards the force exerted is conducted in the opposite direction of motion.....when it turns around force exerted is not opposite but rather non directional...

The speed of sound used in water is 5408 Hz.

(d) The frequency that submarine B is able to detect is   [tex]fo = fs (V -V_O/ v +V_s).[/tex]

                  [tex]=53.273[/tex] × [tex]10 3hz) (1533 m/s + 11 m/s / (45 m/s - 1533 m/s))[/tex]

Frequency [tex]= 5408 HZ[/tex]

Hence, the speed of sound used in water is [tex]5408Hz[/tex].

Submarine, any naval vessel capable of propulsion both below and above the surface of the ocean. Submarines are very distinct from surface ships in terms of appearance and design, making this a unique capacity among warships.

When Germany used them to attack surface merchant ships during World War I (1914–18), submarines initially played a significant role in naval warfare. Torpedo's, a type of self-propelled underwater missile used by submarines, were used as their main armament in such attacks. In World War II (1939–1955), submarines participated in similar operations on a bigger scale, in both the Atlantic (by Germany) and Pacific (by the United States).

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The Kinetic energy of the pupil with mass of 55kg swinging back on a chair and falling off at a speed of 0.6 m/s is "9.9 J".

Kinetic energy is defined as the energy possessed by a body due to the virtue of velocity.

the S.I. unit of Kinetic energy is joule .

Kinetic energy is conserved.

velocity is defined as the displacement per unit time.

S.I unit of velocity is m/s.

given:

Mass (m) = 55 kg

velocity (v) = 0.6 m/s

Kinetic energy(K)=1/2×mv²

Kinetic energy (K)=1/2×55×0.36

Kinetic energy (K)= 9.9 joule

therefore,

The Kinetic energy of the pupil with mass of 55kg swinging back on a chair and falling off at a speed of 0.6 m/s is "9.9 J".

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A family ice show is held at an enclosed arena. The skaters perform to music with level 80.0 db. This level is too loud for your baby, who yells at 75.0 db. 155 db. is the combined sound level.

In physical science, the force or motion of brilliant energy is the power moved per unit region, where the region is estimated on the plane opposite to the heading of spread of the energy. Light force assumes an essential part. With expanded light the fish' s vision improves, and they will turn out to be more careful about hunters.

The formula for intensity is given by, I = P A. Where I am the intensity, P is the power and A is the area of cross section.

The sun' s point decides how much light entering the water. As would be normal, the most elevated measure of sun-based force happens on the globe right where the sun is above and as the point of the sun brings down, the sun-oriented power declines.

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The mass of the air in the cylinder will be 0.811 Kg.

The ideal gas law also referred to as the generic gas equation, is the equation of state for a hypothetical perfect gas. It is a good approximation of the behavior of several gases under diverse conditions, despite significant limitations.

Given that a vertical cylinder with a heavy piston contains air at 300 K . The initial pressure is 2.00 ×10⁵Pa, and the initial volume is 0.350m³. Take the molar mass of air as 28.9 g/mol.

The mass of the air in the cylinder will be calculated as below:-

P₁V₁ = nRT₁

n = ( P₁V₁  / RT₁ )

( m / M ) =  ( P₁V₁  / RT₁ )

m = ( P₁V₁ M / RT₁ )

m = ( P₁V₁ M / RT₁ ) = ( 2 x 10⁵ x 0.35 x 0.0289 ) / ( 8.314 x 300 )

m = 0.811 Kg

Therefore, the mass of the air in the cylinder will be 0.811 Kg.

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The height at which the seagull was flying is 82.45 m.

The height of motion or maximum height in projectile motion occurs when the object reaches a vertical velocity of zero magnitudes.

The height at which the seagull was flying is calculated as follows;

v² = u² - 2gh

where;

0 = u² - 2gh

2gh = u²

h =  u²/2g

h = (40.2²) / (2 x 9.8)

h = 82.45 m

Thus, the height at which the seagull was flying is 82.45 m.

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The velocity of the car will be 36.8 m/s when it has traveled a distance of 70 cm.

The velocity at any moment in time during a particle's motion is given by instantaneous velocity, a continuous function of time. By calculating the derivative of the position function, which gives us the functional form of instantaneous velocity v, we may determine the instantaneous velocity at a certain time (t).

Velocity is a vector quantity.

SI unit is m/s.

According to the question, the Given values are :

Distance =40 cm

=0.4 meter

Velocity, v =2105.3 cm/s

=21.053 m/s

21.053=0.4/t

⇒t=0.4/21.053

t=0.019 seconds

Now, the distance is 70 cm

=0.70 meters

v=0.7/0.019

v=36.8 m/sec

Hence, the velocity will be 36.8 m/sec when it has traveled a distance of 70 cm.

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the average acceleration of the bullet through the board   -55657×10⁵ m/s²

acceleration-  Rate of change of velocity with respect to time.

S = 0.10 mm = 10⁻⁵ m  ( distance)          [∵ 1mm = 10⁻³]

u =  480 m/s (initial velocity)

v = 345 m/s (final velocity)

As we know the 3rd equation of motion.  

v² = u² + 2aS

a = ? ( acceleration)

using these values in equation we get

(345)² = (480)² + 2×a× 10⁻⁵

a = (345)² -  (480)² / 2× 10⁻⁵

a =  -55657×10⁵ m/s²

The negative sign shows that the direction of acceleration is opposite of velocity thus bullet is slowing down.

the average acceleration of the bullet through the board  -55657×10⁵ m/s²

The given question is incomplete. The complete question is.

a bullet fired straight through a board 0.10 mm thick strikes the board with a speed of 480 m/sm/s, has constant acceleration through the board, and emerges with a speed of 345 m/sm/s.

What is the average acceleration of the bullet through the board/?

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By using uniform motion, the average force is 3106.89 N.

We need to know about the uniform motion to solve this problem. The uniform motion is an object's motion under acceleration. It should follow the rule

vt = vo + a . t

vt² = vo² + 2a . s

s = vo . t + 1/2 . a . t²

where vt is final velocity, vo is initial velocity, a is acceleration, t is time and s is displacement.

From the question above, we know that

vo = 0 m/s

vt = 10.6 m/s

m = 0.85 kg

t = 2.9 ms = 2.9 x 10¯³ second

Find the acceleration by using the first equation

vt = vo + a . t

10.6 = 0 + a. 2.9 x 10¯³

a = 3655.17 m/s²

Find the average force

F = m . a

F = 0.85 . 3655.17

F = 3106.89 N

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The average speed of driving the 10 miles would be lower than 35 mph.

The average speed of an object is the ratio of the total distance to the total time of motion of an object.

Mathematically, average speed of an object is given as;

v(average) = total distance / total time

The average speed of a car decreases with increase in the total time of motion.

Due to the many stop lights along the drive, the total of motion of the car will increase will the total distance traveled by the car (10 miles) will be constant.

Also, since the speed limit is 35 mph, the average speed of the car will lower than the 35 mph speed limit.

Thus, the average speed of driving the 10 miles would be lower than 35 mph.

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False, because in a rear tire skid when the rear wheel is in line with the front wheel, you want to release the rear brake to quickly straighten the motorcycle.

Understanding the rationale behind each correct response on the motorcycle written test is crucial for passing your motorbike permit examinations and developing into a safe rider.

When riding a motorcycle, a rear wheel skid can be a risky circumstance to encounter.

When the rear wheel locks up as a result of excessive braking, rear wheel skids happen.

You won't be able to turn around if the rear wheel locks up and starts to slide.

You must relieve the pressure on the rear brakes to stop the skidding of the rear wheels. However, the bike might quickly straighten out and knock you off in a high-side crash if the front and rear wheels are not in line when you remove the rear brake.

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Answer:

A?

Explanation:

i don't know correct me if i'm wrong

The given equations of motion are rearranged for the said variables.

In the given equations of motion, the variables used represents:

[tex]v_{f}[/tex] = Final velocity

[tex]v_{i}[/tex] = Initial velocity

Δx = Displacement

a = Acceleration

t = Time

The given equations that are rearranged for said variables are as follows.

Therefore, the given equations of motion are rearranged above for the said variables.

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Photon move at the speed of light which is option (b)

As electrons and protons are particles of the atoms and posses mass so they do not move at the speed of light even in vaccum.

Photon is a light energy so it moves with the speed of light .

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Several narrow tree rings in a row tell us that it was formed in the warm season.

Trees are those plants that grow very tall. We can see that ancient trees play an important role in the determination of the age of some fossils. The patterns of the rings that could be found in these trees also help us to know how old the particular tree is and especially the whether condition of the place around the time that the tree was formed.

This has been corroborated by a lot of biological evidences that show to tat effect. It can also tell us about the weather condition in a place at a particular time.

As such,  several narrow tree rings in a row tell us that it was formed in the warm season.

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The Position-Time graph for the given Velocity-Time graph is drawn in the image attached.

From the Velocity-Time graph we can take the information needed.

[tex]t_{1}[/tex] = 1 s

[tex]t_{2}[/tex] = 2 s

[tex]t_{3}[/tex] = 3 s

[tex]t_{4}[/tex] = 4 s

[tex]t_{5}[/tex] = 5 s

[tex]v_{1}[/tex] = 10 m / s

[tex]v_{2}[/tex] = 20 m / s

[tex]v_{3}[/tex] = 30 m / s

[tex]v_{4}[/tex] = 40 m / s

[tex]v_{5}[/tex] = 50 m / s

v = d / t

d = v * t

[tex]d_{1}[/tex] = 10 * 1 = 10 m

[tex]d_{2}[/tex] = 20 * 2 = 40 m

[tex]d_{3}[/tex] = 30 * 3 = 90 m

[tex]d_{4}[/tex] = 40 * 4 = 160 m

[tex]d_{5}[/tex] = 50 * 5 = 250 m

Therefore, the Position-Time graph is drawn in the image attached.

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The direction of electric field at any point of z axis is always positive because of the symmetry property.

ELECTRIC FIELD - It is a force that fills the space around  every charge in space.

It is a physical quantity. It represents the vector field that is generated by a charge in the area around that charge. It is defined as the electric force per unit test charge that placed at distance from the charged that generate the electric field.

the electric field is outward from the positive charge and inward  negative point charge.

The direction of electric field at any point of z axis is always positive because of the symmetry property.

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